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  • Is running multiple databases on login going to make my Mac really slow?

    - by Walrus the Cat
    Sometime ago, I installed Postgres, and the Launch agent that causes it to run when I log in. Just now, I did the same thing for Mongo. I was just about to do it for Couch. I don't remember if I ever did it for MySQL, but I probably did. Mongo and Couch are just 'when I have time to look into it' sort of things, but I don't want to have to remember to start them when I do. I have a 2.4 Ghz processor and 8 GB ram. Is this sort of behavior going to significantly impact my computer's performance? Should I be scrambling to uninstall all but the database I'm currently using, or can I install all the things and run them all the time? Thanks

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  • What does SQL Server do if you select more than 1 full backup when doing a restore?

    - by Rob Sobers
    I have a backup file that contains 2 backup sets. Both backup sets are full backups. When I open SQL Server Management Studio and choose "Restore..." and pick the file as my device, it lets me pick both backup sets. The restore operation completes without error, but I'm not sure exactly what SQL server did. Did it restore the first one, drop the database, and then restore the second one? Will it always let the most recent full backup prevail? It doesn't seem to make sense for SQL server to even allow you to select more than one full backup.

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  • What would cause SQL 2008 Log Reader Agent to fail with "This process could not execute 'sp_replcmds' "?

    - by Rick
    I've seen this error message in other posts. They didn't seem to help resolving our issue. We are trying this with two SQL Server 2008 servers. I backed up my database from the source server and then restored it on our destination server. We setup basic Transaction Replication. The Snapshot Agent is working fine. The Log Reader Agent fails with the error above. Is it most likely a login issue for this job or QueryTimeout?

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  • Apache deny access to images folder, but still able to display via <img> on site

    - by jeffery_the_wind
    I have an images folder on my site, let's call it /images/ where I keep a lot of images. I don't want anyone to have direct access to the images via the web, so I put a new directive in my Apache config that achieves this: <Directory "/var/www/images/"> Options Includes AllowOverride All Order allow,deny Deny from All </Directory> This is working, but it is blocking out ALL ACCESS, and I can't show the images anymore through my web pages. I guess this makes sense. So how do I selectively control access to these images? Basically I only want to display certain images through certain webpages and to certain users. What is best way to do this? Do I need to save the images to the database? Tim

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  • SQL 2008 R2 Mirroring Issue

    - by CWL
    Windows 2008 R2 with SQL 2008 R2 - Using Mirroring of a Database across the WAN in a HA setup with one witness. One issue I am having is during a failure (ever so often) the system fails over or tries, but leaves both databases in a Restoring State. My guess is the failover issue happens when there is a WAN bouncing and the systems get confused. The usual fix is to reboot the sql servers. Has anyone seen this type of failure? While this does not happen often it does causes an issue and concern with HA not being trusted fully.

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  • How can i simulate the production servers in my home for linux VMs [closed]

    - by user31
    I am thinking of making the small simulation of how the big companies run their system in my home environment to get the feeling. I have the server with 8GB ram , quad core processor. I am thinking of following setup if thats [possible because i have not worked with biger companies , so i want to know how can i do that I am thinking of creating 5 virtual machines VM1 will be database server and will have all databases like MySQL , postgreSQL , sqlite , mongodb and Oracle VM2 will be the web server and will have Apache and Tomcat installed VM3 will be the Filse server where i will have all the web sites file VM4 , i am thinking of as main box where i can install ptyon php java j2ee sites but not sure VM5 will have the server 22008 for c# .net applications my main idea is to be able to host the sites in php, python , java j2ee with spring Is my setup ok or i am missing few things. Please guide me with correct setup so that i can learn stuff

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  • db2 tablespace size and performance impact

    - by jrhickey
    Originally when we began moving to db2 LUW we ran into some issues where our tables were too big to fit into the default 4K table space. As a result of "pressure" to get it done we just went with a 32K default table space and put ALL of our tables there. What impact would that have if any? I talked to one person who said that it would possible make out database MUCH larger than it needed to be. Is that true? What about memory? Would there be any benefit to moving the smaller tables back to a 4K table space? I have looked around in forums and what not but cannot seem to find a good answer.

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  • Examples of 2D side-scrollers that achieve open non-linear feel?

    - by Milosz Falinski
    I'm working on a 2.5D platformer prototype that aims for an open feel while maintaining familiar core mechanics. Now, there's some obvious challenges with creating a non constricted feel in a spatially constricted environment. What I'm interested in, is examples of how game designers deal with the "here's a level, beat the bad guys/puzzles to get to the next level" design that seems so natural to most platformers (eg. Mario/Braid/Pid/Meat Boy to name a few). Some ideas for achieving openness I've come across include: One obvious successful example is Terraria, which achieves openness simply through complexity and flexibility of the game-system Another example that comes to mind is Cave Story. Game is non-linear, offers multiple choices and side-stories Mario, Rayman and some other 'classics' with a top-down level selection. I actually really dislike this as it never did anything for me emotionally and just seems like a bit of a lazy way to do things. Note: I've not actually had much experience with most of the 'classical' console platformers, apart from the obvious Marios/Zeldas/Metroids, since I've grown up on adventure games. By that I mean, it's entirely possible that I simply missed some games that solve the problem really well and are by some considered obvious 'classics'.

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  • Can JSON be made easily and safely editable by the non-technical Excel crowd?

    - by glitch
    I'm looking for a data storage format that's very intuitive and easy to edit. It should be ideally targeted towards the same crowd as Excel. At the same time I would like the data structure to be a tree. Ideally this would be JSON, since it offers both the tree aspect and allows for more interesting constructs like arrays. That and parsing libraries for JSON are ubiquitous, so I don't have to reinvent the wheel. The problem is that, at least with a non-specialized text editor, JSON is a giant pain to edit for a non-technical user. I'm thinking along the lines of someone who might have used Excel in the past, but never a real text editor. Someone who might not be comfortable with the idea of preserving JSON syntax by hand. Are there data formats out there that would fit this profile? I'd very much prefer this to be a JSON actually, but then it would require a solid editing tool that would hide the underlying implementation from the user. Think Excel and how it abstracts CSV syntax from the user. The reason I'm looking for something like this is because the team has been working with pretty hierarchical data for a while now and we've hit the limits of how easy it is to represent in simple CSVs without having to create complex rules for how represent hierarchy semantics from each row. Any suggestions?

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  • Are small amounts of functional programming understandable by non-FP people?

    - by kd35a
    Case: I'm working at a company, writing an application in Python that is handling a lot of data in arrays. I'm the only developer of this program at the moment, but it will probably be used/modified/extended in the future (1-3 years) by some other programmer, at this moment unknown to me. I will probably not be there directly to help then, but maybe give some support via email if I have time for it. So, as a developer who has learned functional programming (Haskell), I tend to solve, for example, filtering like this: filtered = filter(lambda item: included(item.time, dur), measures) The rest of the code is OO, it's just some small cases where I want to solve it like this, because it is much simpler and more beautiful according to me. Question: Is it OK today to write code like this? How does a developer that hasn't written/learned FP react to code like this? Is it readable? Modifiable? Should I write documentation like explaining to a child what the line does? # Filter out the items from measures for which included(item.time, dur) != True I have asked my boss, and he just says "FP is black magic, but if it works and is the most efficient solution, then it's OK to use it." What is your opinion on this? As a non-FP programmer, how do you react to the code? Is the code "googable" so you can understand what it does? I would love feedback on this :) Edit: I marked phant0m's post as answer, because he gives good advice on how to write the code in a more readable way, and still keep the advantages. But I would also like to recommend superM's post because of his viewpoint as a non-FP programmer.

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  • Migrate from MySQL to PostgreSQL on Linux (Kubuntu)

    - by Dave Jarvis
    A long time ago in a galaxy far, far away... Trying to migrate a database from MySQL to PostgreSQL. All the documentation I have read covers, in great detail, how to migrate the structure. I have found very little documentation on migrating the data. The schema has 13 tables (which have been migrated successfully) and 9 GB of data. MySQL version: 5.1.x PostgreSQL version: 8.4.x I want to use the R programming language to analyze the data using SQL select statements; PostgreSQL has PL/R, but MySQL has nothing (as far as I can tell). A New Hope Create the database location (/var has insufficient space; also dislike having the PostgreSQL version number everywhere -- upgrading would break scripts!): sudo mkdir -p /home/postgres/main sudo cp -Rp /var/lib/postgresql/8.4/main /home/postgres sudo chown -R postgres.postgres /home/postgres sudo chmod -R 700 /home/postgres sudo usermod -d /home/postgres/ postgres All good to here. Next, restart the server and configure the database using these installation instructions: sudo apt-get install postgresql pgadmin3 sudo /etc/init.d/postgresql-8.4 stop sudo vi /etc/postgresql/8.4/main/postgresql.conf Change data_directory to /home/postgres/main sudo /etc/init.d/postgresql-8.4 start sudo -u postgres psql postgres \password postgres sudo -u postgres createdb climate pgadmin3 Use pgadmin3 to configure the database and create a schema. The episode continues in a remote shell known as bash, with both databases running, and the installation of a set of tools with a rather unusual logo: SQL Fairy. perl Makefile.PL sudo make install sudo apt-get install perl-doc (strangely, it is not called perldoc) perldoc SQL::Translator::Manual Extract a PostgreSQL-friendly DDL and all the MySQL data: sqlt -f DBI --dsn dbi:mysql:climate --db-user user --db-password password -t PostgreSQL > climate-pg-ddl.sql mysqldump --skip-add-locks --complete-insert --no-create-db --no-create-info --quick --result-file="climate-my.sql" --databases climate --skip-comments -u root -p The Database Strikes Back Recreate the structure in PostgreSQL as follows: pgadmin3 (switch to it) Click the Execute arbitrary SQL queries icon Open climate-pg-ddl.sql Search for TABLE " replace with TABLE climate." (insert the schema name climate) Search for on " replace with on climate." (insert the schema name climate) Press F5 to execute This results in: Query returned successfully with no result in 122 ms. Replies of the Jedi At this point I am stumped. Where do I go from here (what are the steps) to convert climate-my.sql to climate-pg.sql so that they can be executed against PostgreSQL? How to I make sure the indexes are copied over correctly (to maintain referential integrity; I don't have constraints at the moment to ease the transition)? How do I ensure that adding new rows in PostgreSQL will start enumerating from the index of the last row inserted (and not conflict with an existing primary key from the sequence)? How do you ensure the schema name comes through when transforming the data from MySQL to PostgreSQL inserts? Resources A fair bit of information was needed to get this far: https://help.ubuntu.com/community/PostgreSQL http://articles.sitepoint.com/article/site-mysql-postgresql-1 http://wiki.postgresql.org/wiki/Converting_from_other_Databases_to_PostgreSQL#MySQL http://pgfoundry.org/frs/shownotes.php?release_id=810 http://sqlfairy.sourceforge.net/ Thank you!

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  • Doctrine Build-All Task fails in NetBeans - Class not found! Fatal Error: call to evictAll()

    - by Prasad
    When I build my model with the symfony doctrine:build --all --and-load command I have made no major changes to the model/schema, this is something new. I also tried sub-commands like build-model, build-tables, but they all hang.. I'm trying this in net beans. Any clue what this is? This command will remove all data in the following "dev" connection(s): - doctrine Are you sure you want to proceed? (y/N) y >> doctrine Dropping "doctrine" database >> doctrine Creating "dev" environment "doctrine" database >> doctrine generating model classes >> file+ C:\Documents and Settings\Gupte...\Temp/doctrine_schema_69845.yml >> tokens D:/projects/cim/lib/model/doctrine/base/BaseAffiliate.class.php >> tokens D:/projects/cim/lib/model/doctrine/base/BaseContact.class.php >> tokens D:/projects/cim/lib/model/doctr...e/BaseContactLocation.class.php >> tokens D:/projects/cim/lib/model/doctr...se/BaseGroupAffiliate.class.php >> tokens D:/projects/cim/lib/model/doctrine/base/BaseGrouping.class.php >> tokens D:/projects/cim/lib/model/doctrine/base/BaseLocation.class.php >> tokens D:/projects/cim/lib/model/doctr.../base/BasePhonenumber.class.php >> tokens D:/projects/cim/lib/model/doctrine/base/BaseTenant.class.php >> tokens D:/projects/cim/lib/model/doctr...base/BasesfGuardGroup.class.php >> tokens D:/projects/cim/lib/model/doctr...fGuardGroupPermission.class.php >> tokens D:/projects/cim/lib/model/doctr...BasesfGuardPermission.class.php >> tokens D:/projects/cim/lib/model/doctr...asesfGuardRememberKey.class.php >> tokens D:/projects/cim/lib/model/doctr.../base/BasesfGuardUser.class.php >> tokens D:/projects/cim/lib/model/doctr.../BasesfGuardUserGroup.class.php >> tokens D:/projects/cim/lib/model/doctr...sfGuardUserPermission.class.php >> autoload Resetting application autoloaders >> file- D:/projects/cim/cache/frontend/.../config/config_autoload.yml.php >> file- D:/projects/cim/cache/backend/dev/config/config_autoload.yml.php >> doctrine generating form classes [?php /** * Contact form base class. * * @method Contact getObject() Returns the current form's model object * * @package ##PROJECT_NAME## * @subpackage form * @author ##AUTHOR_NAME## * @version SVN: $Id: sfDoctrineFormGeneratedTemplate.php 24171 2009-11-19 16:37:50Z Kris.Wallsmith $ */ abstract class BaseContactForm extends BaseFormDoctrine { public function setup() { $this->setWidgets(array( 'id' Fatal error: Call to a member function evictAll() on a non-object in D:\projects\cim\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib\vendor\doctrine\Doctrine\Connection.php on line 1239 Call Stack: 0.9552 322760 1. {main}() D:\projects\cim\symfony:0 0.9594 587208 2. include('D:\projects\cim\lib\vendor\symfony\lib\command\cli.php') D:\projects\cim\symfony:14 11.9775 17118936 3. sfDatabaseManager->shutdown() D:\projects\cim\lib\vendor\symfony\lib\database\sfDatabaseManager.class.php:0 11.9775 17118936 4. sfDoctrineDatabase->shutdown() D:\projects\cim\lib\vendor\symfony\lib\database\sfDatabaseManager.class.php:134 11.9775 17118936 5. Doctrine_Manager->closeConnection() D:\projects\cim\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib\database\sfDoctrineDatabase.class.php:165 11.9775 17118936 6. Doctrine_Connection->close() D:\projects\cim\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib\vendor\doctrine\Doctrine\Manager.php:579 11.9776 17120160 7. Doctrine_Connection->clear() D:\projects\cim\lib\vendor\symfony\lib\plugins\sfDoctrinePlugin\lib\vendor\doctrine\Doctrine\Connection.php:1268 Couldn't find class Similar thing is mentioned here: http://osdir.com/ml/symfony-users/2010-01/msg00642.html

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  • MySQL access classes in PHP

    - by Mike
    I have a connection class for MySQL that looks like this: class MySQLConnect { private $connection; private static $instances = 0; function __construct() { if(MySQLConnect::$instances == 0) { //Connect to MySQL server $this->connection = mysql_connect(MySQLConfig::HOST, MySQLConfig::USER, MySQLConfig::PASS) or die("Error: Unable to connect to the MySQL Server."); MySQLConnect::$instances = 1; } else { $msg = "Close the existing instance of the MySQLConnector class."; die($msg); } } public function singleQuery($query, $databasename) { mysql_select_db(MySQLConfig::DB, $this->connection) or die("Error: Could not select database " . MySQLConfig::DB . " from the server."); $result = mysql_query($query) or die('Query failed.'); return $result; } public function createResultSet($query, $databasename) { $rs = new MySQLResultSet($query, MySQLConfig::DB, $this->connection ) ; return $rs; } public function close() { MySQLConnect::$instances = 0; if(isset($this->connection) ) { mysql_close($this->connection) ; unset($this->connection) ; } } public function __destruct() { $this->close(); } } The MySQLResultSet class looks like this: class MySQLResultSet implements Iterator { private $query; private $databasename; private $connection; private $result; private $currentRow; private $key = 0; private $valid; public function __construct($query, $databasename, $connection) { $this->query = $query; //Select the database $selectedDatabase = mysql_select_db($databasename, $connection) or die("Error: Could not select database " . $this->dbname . " from the server."); $this->result = mysql_query($this->query) or die('Query failed.'); $this->rewind(); } public function getResult() { return $this->result; } // public function getRow() // { // return mysql_fetch_row($this->result); // } public function getNumberRows() { return mysql_num_rows($this->result); } //current() returns the current row public function current() { return $this->currentRow; } //key() returns the current index public function key() { return $this->key; } //next() moves forward one index public function next() { if($this->currentRow = mysql_fetch_array($this->result) ) { $this->valid = true; $this->key++; }else{ $this->valid = false; } } //rewind() moves to the starting index public function rewind() { $this->key = 0; if(mysql_num_rows($this->result) > 0) { if(mysql_data_seek($this->result, 0) ) { $this->valid = true; $this->key = 0; $this->currentRow = mysql_fetch_array($this->result); } } else { $this->valid = false; } } //valid returns 1 if the current position is a valid array index //and 0 if it is not valid public function valid() { return $this->valid; } } The following class is an example of how I am accessing the database: class ImageCount { public function getCount() { $mysqlConnector = new MySQLConnect(); $query = "SELECT * FROM images;"; $resultSet = $mysqlConnector->createResultSet($query, MySQLConfig::DB); $mysqlConnector->close(); return $resultSet->getNumberRows(); } } I use the ImageCount class like this: if(!ImageCount::getCount()) { //Do something } Question: Is this an okay way to access the database? Could anybody recommend an alternative method if it is bad? Thank-you.

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  • sp_send_dbmail attach files stored as varbinary in database

    - by Mindstorm Interactive
    I have a two part question relating to sending query results as attachments using sp_send_dbmail. Problem 1: Only basic .txt files will open. Any other format like .pdf or .jpg are corrupted. Problem 2: When attempting to send multiple attachments, I receive one file with all file names glued together. I'm running SQL Server 2005 and I have a table storing uploaded documents: CREATE TABLE [dbo].[EmailAttachment]( [EmailAttachmentID] [int] IDENTITY(1,1) NOT NULL, [MassEmailID] [int] NULL, -- foreign key [FileData] [varbinary](max) NOT NULL, [FileName] [varchar](100) NOT NULL, [MimeType] [varchar](100) NOT NULL I also have a MassEmail table with standard email stuff. Here is the SQL Send Mail script. For brevity, I've excluded declare statements. while ( (select count(MassEmailID) from MassEmail where status = 20 )>0) begin select @MassEmailID = Min(MassEmailID) from MassEmail where status = 20 select @Subject = [Subject] from MassEmail where MassEmailID = @MassEmailID select @Body = Body from MassEmail where MassEmailID = @MassEmailID set @query = 'set nocount on; select cast(FileData as varchar(max)) from Mydatabase.dbo.EmailAttachment where MassEmailID = '+ CAST(@MassEmailID as varchar(100)) select @filename = '' select @filename = COALESCE(@filename+ ',', '') +FileName from EmailAttachment where MassEmailID = @MassEmailID exec msdb.dbo.sp_send_dbmail @profile_name = 'MASS_EMAIL', @recipients = '[email protected]', @subject = @Subject, @body =@Body, @body_format ='HTML', @query = @query, @query_attachment_filename = @filename, @attach_query_result_as_file = 1, @query_result_separator = '; ', @query_no_truncate = 1, @query_result_header = 0; update MassEmailset status= 30,SendDate = GetDate() where MassEmailID = @MassEmailID end I am able to successfully read files from the database so I know the binary data is not corrupted. .txt files only read when I cast FilaData to varchar. But clearly original headers are lost. It's also worth noting that attachment file sizes are different than the original files. That is most likely due to improper encoding as well. So I'm hoping there's a way to create file headers using the stored mimetype, or some way to include file headers in the binary data? I'm also not confident in the values of the last few parameters, and I know coalesce is not quite right, because it prepends the first file name with a comma. But good documentation is nearly impossible to find. Please help!

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  • Refresh RadGridview when Insert,Update and Delete Operation done on Database in WPF

    - by patelriki13
    WPF and C#: Problem: 1. How to Refresh Radgridview when i Insert,update and Delete Record in database anrecord. 2.when i am Insert or Update Record than in radgridview that row is selected. i am useing sql server 2005. i am use to set data source of radgridview like " radgridview1.ItemsSource = ds; " == ds is dataset. i am beginner so if possible than tel me by code it is easy to understand....... can u help me as early as possible .... i give some code which i am useing for update RadGridview con.ConnectionString = @"Data Source=(local);Initial Catalog=DigiDms;Integrated Security=True"; cmd1.Connection = con; con.Open(); cmd1.CommandType = CommandType.StoredProcedure; cmd1.CommandText = "Pro_Insurance_Master_Select"; da1.SelectCommand = cmd1; da1.Fill(ds1); con.Close(); //dataGrid.clear(); //dsGrid.Reset(); //dsGrid = dataGrid.GetData("Pro_Insurance_Master_Select"); //set datasource of gridview gridShowData.ItemsSource = null; gridShowData.ItemsSource = ds1; doing this , when i am delete or update record than folloning error generated... Error: "Object reference not set to an object" when i am doing the "gridShowData.ItemsSource = null;" and when i am doing insert operation than this error is not generated and RadGridview also updated..... so pls help me as early as possible.... i am beginer ........ my email address is [email protected]

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  • Display image from database with p:graphicImage

    - by minhltnt
    I'm trying to display image type byte which saved in database to return StreamedContent to the p:graphicImage, as follows: private StreamedContent content; // getter and setter public StreamedContent getImageF() { if (student.getImage() != null) { InputStream is = new ByteArrayInputStream(student.getImage()); System.out.println("Byte :"+student.getImage()); content = new DefaultStreamedContent(is, "", student.getStuID()); System.out.println("ddd ------------------------------- " + content); return content; } return content; } This return blank image. Can Someone explain why? <p:graphicImage value="#{item.imageF}" width="50" id="grpImage" height="80"/> When i try to print the ouput : INFO: Byte :[B@a2fb48 INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@b0887b INFO: Byte :[B@a2fb48 INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@1d06a92 INFO: Byte :[B@d52f0b INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@39a60 INFO: Byte :[B@d52f0b INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@8c3daa INFO: Byte :[B@124728a INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@1dbe05b INFO: Byte :[B@124728a INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@66a266 INFO: Byte :[B@a2fb48 INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@1293976 INFO: Byte :[B@a2fb48 INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@17b7399 INFO: Byte :[B@d52f0b INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@1e245a5 INFO: Byte :[B@d52f0b INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@4a7153 INFO: Byte :[B@124728a INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@1561bfd INFO: Byte :[B@124728a INFO: ddd ------------------------------- org.primefaces.model.DefaultStreamedContent@47a8c2<br/> I don't know the reason why p:grpalicImage return blank.Help me,please

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  • SQL Server database with clustered GUID PKs - switch clustered index or switch to sequential (comb)

    - by Eyvind
    We have a database in which all the PKs are GUIDs, and most of the PKs are also the clustered index for the table. We know that this is bad (due to the random nature of GUIDs). So, it seems there are basically two options here (short of throwing out GUIDs as PKs altogether, which we cannot do (at least not at this time)). We could change the GUID generation algorithm to e.g. the one that NHibernate uses, as detailed in this post, or we could, for the tables that are under the heaviest use, change to a different clustered index, e.g. an IDENTITY column, and keep the "random" GUIDs as PKs. Is it possible to give any general recommendations in such a scenario? The application in question has 500+ tables, the largest one presently at about 1,5 million rows, a few tables around 500 000 rows, and the rest significantly lower (most of them well below 10K). Furthermore, the application is installed at several customer sites already, so we have to take any possible negative effects for existing customer into consideration. Thanks!

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  • MS SQL Database with clustered GUID PKs - switch clustered index or switch to sequential (comb) GUID

    - by Eyvind
    We have a database in which all the PKs are GUIDs, and most of the PKs are also the clustered index for the table. We know that this is bad (due to the random nature of GUIDs). So, it seems there are basically two options here (short of throwing out GUIDs as PKs altogether, which we cannot do (at least not at this time)). We could change the GUID generation algorithm to e.g. the one that NHibernate uses, as detailed in this post, or we could, for the tables that are under the heaviest use, change to a different clustered index, e.g. an IDENTITY column, and keep the "random" GUIDs as PKs. Is it possible to give any general recommendations in such a scenario? The application in question has 500+ tables, the largest one presently at about 1,5 million rows, a few tables around 500 000 rows, and the rest significantly lower (most of them well below 10K). Furthermore, the application is installed at several customer sites already, so we have to take any possible negative effects for existing customer into consideration. Thanks!

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  • can't get data from database to dropdownlist in loginview

    - by Thomas Bøg Petersen
    I have this code on an aspx page. <asp:DropDownList runat="server" ID="ddlSize" CssClass="textbox" Width="100px"> <asp:ListItem Value="" Text="" /> <asp:ListItem Value="11" Text="11. Mands" /> <asp:ListItem Value="7" Text="7. Mands" /> <asp:ListItem Value="" Text="Ikke Kamp"/> </asp:DropDownList> <asp:DropDownList runat="server" ID="ddlType" CssClass="textbox" Width="100px"> <asp:ListItem Value="" Text="" /> <asp:ListItem Value="K" Text="Kamp" /> <asp:ListItem Value="T" Text="Træning" /> <asp:ListItem Value="E" Text="Aktivitet"/> </asp:DropDownList> ts inside a loginview with some other fields (textbox) Im trying to get a record id into the page so i can edit it, I have fix it with the Textbox and its working 100%, but i cant get the value from the database into the dropdownlist so it show that value as selected. I have tryed these 3 codes, but nothing is working fore the dropdownlist. // DataValueField Dim drop_obj As DropDownList = TryCast(LoginView2.FindControl("ddlSize"), DropDownList) drop_obj.DataValueField = dtEvents.Rows(0)("EventEventSize") Dim drop_obj2 As DropDownList = TryCast(LoginView2.FindControl("ddlType"), DropDownList) drop_obj2.DataValueField = dtEvents.Rows(0)("EventType") // SelectedIndex Dim drop_obj As DropDownList = TryCast(LoginView2.FindControl("ddlSize"), DropDownList) drop_obj.SelectedIndex = dtEvents.Rows(0)("EventEventSize") Dim drop_obj2 As DropDownList = TryCast(LoginView2.FindControl("ddlType"), DropDownList) drop_obj2.SelectedIndex = dtEvents.Rows(0)("EventType") // SelectedValue Dim drop_obj As DropDownList = TryCast(LoginView2.FindControl("ddlSize"), DropDownList) drop_obj.SelectedValue = dtEvents.Rows(0)("EventEventSize") Dim drop_obj2 As DropDownList = TryCast(LoginView2.FindControl("ddlType"), DropDownList) drop_obj2.SelectedValue = dtEvents.Rows(0)("EventType") Can someone plz. help !? I have values in the 2 dtEvents.Rows(0) i have checked that, with a debug and then step-into. and i get values like 7 or 11 and T or K.

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  • Adapt beginner C# SQL Server INSERT example to work with my database

    - by Mike Bertelsen
    I have read TONS of tutorials, articles and whatever regarding my issue and honestly, due to my lack of experience I can't twist my fingers around this one so I hope some of you guys can help me out :) I am working on a project (simply to learn how to program so it's probably very basic), but I have this "News" page where I can update and delete data using a GridView. Now I would like to INSERT something into my database using 3 textboxes and 1 submit button. I have 3 rows that has to be inserted: Headline Date Content/the news itself. Which are stored under NyhedTB from the connectionstring: BoligStjernenConnectionString My query looks like this: INSERT INTO [NyhedTB] ([NyhedDato], [NyhedTitel], [NyhedTekst]) VALUES (@NyhedDato, @NyhedTitel, @NyhedTekst) I read on the internet that this code should do the magic for me (I will have to insert my own values ofc.): static void Insert() { try { string connectionString = "server=.;" + "initial catalog=employee;" + "user id=sa;" + "password=sa123"; using (SqlConnection conn = new SqlConnection(connectionString)) { conn.Open(); using (SqlCommand cmd = new SqlCommand("INSERT INTO EmployeeDetails VALUES(" + "@Id, @Name, @Address)", conn)) { cmd.Parameters.AddWithValue("@Id", 1); cmd.Parameters.AddWithValue("@Name", "Amal Hashim"); cmd.Parameters.AddWithValue("@Address", "Bangalore"); int rows = cmd.ExecuteNonQuery(); //rows number of record got inserted } } } catch (SqlException ex) { //Log exception //Display Error message } } I looked at this code and thought it should be easy enough but really, I can't figure it out.

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  • php edit database entery script not working.

    - by Jacksta
    I have two files which show all contats in a database, then edits them. The second script keeps directing the browser back due to this part. I cant work out how to make it work! :) <?php if (!$_POST[id]) { header( "Location: pick_modcontact.php"); exit; } else { session_start(); } if ($_SESSION[valid] != "yes") { header( "Location: pick_modcontact.php"); exit; } This script shows all contacts in a database which is an "address book" this part works fine. please see below. Name:pick_modcontact.php if ($_SESSION[valid] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "user") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$f_name, $l_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html> This script is for modifying the contact: named show_modcontact.php <?php if (!$_POST[id]) { header( "Location: pick_modcontact.php"); exit; } else { session_start(); } if ($_SESSION[valid] != "yes") { header( "Location: pick_modcontact.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin_cantsayno", "cantsayno") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT f_name, l_name, address1, address2, address3, postcode, prim_tel, sec_tel, email, birthday FROM $table_name WHERE id = '$_POST[id]'"; $result = @mysql_query($sql, $connection) or die(mysql_error()); while ($row = mysql_fetch_array($result)) { $f_name = $row['f_name']; $l_name = $row['l_name']; $address1 = $row['address1']; $address2 = $row['address2']; $address3 = $row['address3']; $country = $row['country']; $prim_tel = $row['prim_tel']; $sec_tel = $row['sec_tel']; $email = $row['email']; $birthday = $row['birthday']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <form action="do_modcontact.php" method="post"> <input type="id" value="<? echo "$_POST[id]"; ?>" /> <table cellpadding="5" cellspacing="3"> <tr> <th>Name & Address Information</th> <th> Other Contact / Personal Information</th> </tr> <tr> <td align="top"> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name" ?>" size="35" maxlength="75" /></p> <p><strong>Last Name:</strong><br /> <input type="text" name="l_name" value="<? echo "$l_name" ?>" size="35" maxlength="75" /></p> <p><strong>Address1:</strong><br /> <input type="text" name="f_name" value="<? echo "$address1" ?>" size="35" maxlength="75" /></p> <p><strong>Address2:</strong><br /> <input type="text" name="f_name" value="<? echo "$address2" ?>" size="35" maxlength="75" /></p> <p><strong>Address3:</strong><br /> <input type="text" name="f_name" value="<? echo "$address3" ?>" size="35" maxlength="75" /> </p> <p><strong>Postcode:</strong><br /> <input type="text" name="f_name" value="<? echo "$postcode" ?>" size="35" maxlength="75" /></p> <p><strong>Country:</strong><br /> <input type="text" name="f_name" value="<? echo "$country" ?>" size="35" maxlength="75" /> </p> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name" ?>" size="35" maxlength="75" /></p> </td> <td align="top"> <p><strong>Prim Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$prim_tel" ?>" size="35" maxlength="75" /></p> <p><strong>Sec Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$sec_tel" ?>" size="35" maxlength="75" /></p> <p><strong>Email:</strong><br /> <input type="text" name="f_name" value="<? echo "$email" ?>" size="35" maxlength="75" /> </p> <p><strong>Birthday:</strong><br /> <input type="text" name="f_name" value="<? echo "$birthday" ?>" size="35" maxlength="75" /> </p> </td> </tr> <tr> <td align="center"> <p><input type="submit" name="submit" value="Update Contact" /></p> <br /> <p><a href="contact_menu.php">Retuen To Menu</a></p> </td> </tr> </table> </form> </body> </html>

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  • Displaying Many-To-Many Database relationship in VB.NET 2008 with DataGrid, MS SQL 2008

    - by user337501
    Computer bombed while posting this, couldnt find a duplicate question but if there is one, forgive me. So, I've run into a wall. And rather than use a ladder to avoid it, I'd like go through it. I'm setting up what I can best describe as a many-to-many relationship in a database. To examplify, imagine I have three primary tables: Items, Categories, Sections(nevermind the potential redundancy) Then I have another table, Properties. Items, Categories, and Sections can be associated with many properties. A single property can be associated with one, all, or none of the other tables. The best way I can figure to do this is to have join tables make the relationship. i.e. tblItems----(Foreign Key)----tblItems_To_Properties----(Foreign Key)----tblProperties In this example, tblItems simply has an "ItemID" Primary Key. tblItems_To_Properties has its own Primary Key(tblItems_To_PropertiesID), a Foreign Key to the Item(ItemID) and a Foreign key to the Property(PropertyID). The Properties table simply has its primary key(PropertyID) I hope this example isnt too confusing...if I have to I can find a way to put a diagram up or something. My problem is, I want to display this in a DataGrid using the Master-Detail method(DevExpress GridControl). I use the tblItems as a test, and I can see the Items in the parent view, but in the child view I see(understandably) the join table and that is it. My goal is to make it so the Grid ignores the join table and shows the Properties table as the only child. Any help on this method or insight into another solution would be muuuuuuuch appreciat

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  • choosing row (from group) with max value in a SQL Server Database

    - by sriehl
    I have a large database and am putting together a report of the data. I have aggregated and summed the data from many tables to get two tables that look like the following. id | code | value id | code | value 13 | AA | 0.5 13 | AC | 2.0 13 | AB | 1.0 14 | AB | 1.5 14 | AA | 2.0 13 | AA | 0.5 15 | AB | 0.5 15 | AB | 3.0 15 | AD | 1.5 15 | AA | 1.0 I need to get a list of id's, with the code (sumed from both tables) with the largest value. 13 | AC 14 | AA 15 | AB There are 4-6 thousand records and it is not possible to change the original tables. I'm not too worried about performance as I only need to run it a few times a year. edit: Let me see if I can explain a bit more clearly, imagine the id is the customer id, the code is who they ordered from and the value is how much they spent there. I need a list of the all the customer id's and the store that customer spent the most money at (and if they spent the same at two different stores, put a value such as 'ZZ' in for the store name).

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  • Crystal Reports Failed Database Login

    - by Marlon
    Hello, After spending a good 3 to 4 hours on google trying to find any solution to my problem I haven't had much luck. Basically, we use crystal reports for our .NET applications with a sql server back end, we have many clients each with their own server and so our reports need to have their connections dynamically set. Up until a week ago this worked fine. However a few days ago a client reported they were getting a database login prompt for a report (only one report, the rest worked fine). We were quite stumped but we managed to reproduce it on a netbook which didn't have visual studio or sql server installed. In the end the dev decided to reproduce the report in the hope it was just an oddity in that particular report. Unfortunately a new client today also experienced the same problem, but this time for every crystal report they had - and also they worked on the netbook, so we are really quite lost here. Below is a screenshot of what our clients get presented with - and here is the code that I use to set the connection information in the report cI.ServerName = (string)builder["Data Source"]; cI.DatabaseName = (string)builder["Initial Catalog"]; cI.UserID = (string)builder["User ID"]; cI.Password = (string)builder["Password"]; foreach (IConnectionInfo info in cryRpt.DataSourceConnections) { info.SetConnection(cI.ServerName, cI.DatabaseName, cI.UserID, cI.Password); } foreach (ReportDocument sub in cryRpt.Subreports) { foreach (IConnectionInfo info in sub.DataSourceConnections) { info.SetConnection(cI.ServerName, cI.DatabaseName, cI.UserID, cI.Password); } } As always, any help much appreciated.

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  • Symfony file upload - "Array" stored in database instead of the actual filename

    - by Guillaume Flandre
    I'm using Symfony 1.4.4 and Doctrine and I need to upload an image on the server. I've done that hundreds of times without any problem but this time something weird happens : instead of the filename being stored in the database, I find the string "Array". Here's what I'm doing: In my Form: $this->useFields(array('filename')); $this->embedI18n(sfConfig::get('app_cultures')); $this->widgetSchema['filename'] = new sfWidgetFormInputFileEditable(array( 'file_src' => '/uploads/flash/'.$this->getObject()->getFilename(), 'is_image' => true, 'edit_mode' => !$this->isNew(), 'template' => '<div id="">%file%</div><div id=""><h3 class="">change picture</h3>%input%</div>', )); $this->setValidator['filename'] = new sfValidatorFile(array( 'mime_types' => 'web_images', 'path' => sfConfig::get('sf_upload_dir').'/flash', )); In my action: public function executeIndex( sfWebRequest $request ) { $this->flashContents = $this->page->getFlashContents(); $flash = new FlashContent(); $this->flashForm = new FlashContentForm($flash); $this->processFlashContentForm($request, $this->flashForm); } protected function processFlashContentForm($request, $form) { if ( $form->isSubmitted( $request ) ) { $form->bind( $request->getParameter( $form->getName() ), $request->getFiles( $form->getName() ) ); if ( $form->isValid() ) { $form->save(); $this->getUser()->setFlash( 'notice', $form->isNew() ? 'Added.' : 'Updated.' ); $this->redirect( '@home' ); } } } Before binding my parameters, everything's fine, $request->getFiles($form->getName()) returns my files. But afterwards, $form->getValue('filename') returns the string "Array". Did it happen to any of you guys or do you see anything wrong with my code? Edit: I added the fact that I'm embedding another form, which may be the problem (see Form code above).

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