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  • How to query two tables based on whether or not record exists in a third?

    - by Katherine
    I have three tables, the first two fairly standard: 1) PRODUCTS table: pid pname, etc 2) CART table: cart_id cart_pid cart_orderid etc The third is designed to let people save products they buy and keep notes on them. 3) MYPRODUCTS table: myprod_id myprod_pid PRODUCTS.prod_id = CART.cart_prodid = MYPRODUCTS.myprod_pid When a user orders, they are presented with a list of products on their order, and can optionally add that product to myproducts. I am getting the info necessary for them to do this, with a query something like this for each order: SELECT cart.pid, products.pname, products.pid FROM products, cart WHERE products.pid = cart_prodid AND cart_orderid=orderid This is fine the first time they order. However, if they subsequently reorder a product which they have already added to myproducts, then it should NOT be possible for them to add it to myproducts again - basically instead of 'Add to MyProducts' they need to see 'View in MyProducts'. I am thinking I can separate the products using two queries: Products never added to MyProducts By somehow identifying whether the user has the product in MyProducts already, and if so excluding it from the query above. Products already in MyProducts By reversing the process above. I need some pointers on how to do this though.

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  • How can I use Hibernate Criteria's to query nested tables?

    - by cbmeeks
    I've looked all over SO and Google but I guess I'm not using the right search terms or something. Anyway, say I have three tables: Companies ----------------------------------------- id name user_id Users ----------------------------------------- id username usertype_id UserTypes ----------------------------------------- id typeofuser So ACME would be a company, it would have a user Moe and Moe would be a usertype of Stooge. In SQL, I would do something like: select * from companies c join users u on (u.id = c.user_id) join usertypes ut on (ut.id = u.usertype_id) where ut.typeofuser = 'Stooge' But I can't seem to figure out how to do that in a Criteria. I have tried: Criteria crit = io.getSession().createCriteria(Company.class); List<Company> list = crit.createCriteria("users") .createCriteria("usertypes") .add(Restriction.eq("typeofuser", "Stooge").list(); But I get back way too many records. And the results don't even come close to being accurate. I've also tried: Criteria crit = io.getSession().createCriteria(Company.class); List<Company> list = crit.createAlias("users", "u") .createAlias("u.usertypes", "ut") .add(Restriction.eq("ut.typeofuser", "Stooge").list(); Seems to bring back the exact same result set. I actually have read the user manual. And when I nest only one level deep (ie, searching by users is fine) but when I get two layers deep, I can't quite get it. And the manual is no help. I just can't relate cats and kittens to business objects. Maybe they should use cats, kittens and fleas? :-/ Thanks for any suggestions.

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  • How do I left join tables in unidirectional many-to-one in Hibernate?

    - by jbarz
    I'm piggy-backing off of http://stackoverflow.com/questions/2368195/how-to-join-tables-in-unidirectional-many-to-one-condition. If you have two classes: class A { @Id public Long id; } class B { @Id public Long id; @ManyToOne @JoinColumn(name = "parent_id", referencedColumnName = "id") public A parent; } B - A is a many to one relationship. I understand that I could add a Collection of Bs to A however I do not want that association. So my actual question is, Is there an HQL or Criteria way of creating the SQL query: select * from A left join B on (b.parent_id = a.id) This will retrieve all A records with a Cartesian product of each B record that references A and will include A records that have no B referencing them. If you use: from A a, B b where b.a = a then it is an inner join and you do not receive the A records that do not have a B referencing them. I have not found a good way of doing this without two queries so anything less than that would be great. Thanks.

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  • Beginner Ques::How to delete records permanently in case of linked tables?

    - by Serenity
    Let's say I have these 2 tables QuesType and Ques:- QuesType QuestypeID|QuesType |Active ------------------------------------ 101 |QuesType1 |True 102 |QuesType2 |True 103 |XXInActiveXX |False Ques QuesID|Ques|Answer|QUesTypeID|Active ------------------------------------ 1 |Ques1|Ans1 |101 |True 2 |Ques2|Ans2 |102 |True 3 |Ques3|Ans3 |101 |True In the QuesType Table:- QuesTypeID is a Primary key In the Ques Table:- QuesID is a Primary key and QuesType ID is the Foreign Key that refernces QuesTypeID from QuesType Table Now I am unable to delete records from QuesType Table, I can only make QuesType inactive by setting Active=False. I am unable to delete QuesTypes permanently because of the Foreign key relation it has with Ques Table. So , I just set the column Active=false and those Questypes then don't show on my grid wen its binded. What I want to do is be able to delete any QuesType permamnently. Now it can only be deleted if its not being used anywhere in the Ques table, right? So to delete any QuesType permanently I thot this is what I could do:- In the grid that displays QuesTypes, I have this check box for Active and a button for delete.What I thot was, when a user makes some QuesType inactive then OnCheckChanged() event will run and that will have the code to delete all the Questions in Ques table that are using that QuesTypeID. Then on the QuesType grid, that QuesType would show as Deactivated and only then can a user delete it permanently. Am I thinking correctly? Currently in my DeleteQuesType Stored Procedure what I am doing is:- Setting the Active=false and Setting QuesTye= some string like XXInactiveXX Is there any other way?

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  • Where to start to create an HTML website with 2 tables read from csv files using anything but php

    - by CodingIsAwesome
    I want to design a website which displays on loading two tables each with it's respective data from a csv file. Then every minute the website automatically refreshes. This problem seems so simple! But yet the solution eludes me. All of the files will be contained in 1 directory, not on a server but on a local machine. Such as sitting on the desktop. I understand if I use javascript I have to use ADO, and I'm still trying to work out how to use ASP. I am new with both languages. So far the only restriction is that I can't use PHP. So the jist so far as I can think right now is: 1. read the file 2. place the file into an array by splitting at the commas 3. write the array into td's ????? 4. then print all this out into a div ???? I have googled my heart out and can't seem to find what I'm looking for. or even piece together what I'm looking for. Everything with javascript and ADO's leads me to dead ends, I can't find anything on ASP that is helpful. Could someone please write up some sample code for a resource? Or have a better solution?

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  • how to compare two tables fields name with another value in mysql?

    - by I Like PHP
    I have two tables table_school school_open_time|school_close_time|school_day 8:00 AM | 9:00PM | Monday 10:00 AM | 7:00PM | Wednesday table_college college_open_time|college_close_time|college_day 10:00 AM | 8:00PM | Monday 10:00 AM | 9:00PM | Tuesday 10:00 AM | 5:00PM | Wednesday Now I want to select school_open_time school_close time, college_open_time and college_close_time according to today (means college_day=school_day=today), and also if there is no row for a specific day in any of one table then it display blank field ( LEFT JOIN , I think I can use). Please suggest me best and optimized query for this. UPDATE: if there is no open time and close time for school then college_open_time and college_close_time has to be returned( not to be filled in database,just return) as school_open_time and school_close_time. and there always must be college_open_time and college_close_time for a given day MORE UPDATE: i m using below query SELECT college_open_time,college_close_time ,school_open_time, school_close_time FROM tbl_college LEFT JOIN tbl_school ON school_owner_id=college_owner_id WHERE college_owner_id='".$_session['user_id']."' AND college_day='".date('l',time())."'"; it return single row (left hand having some value and right hand having blank value) when there is no row of a given day in table_school, BUT display seven rows with same value on left hand side(college_open_time, college_close_time) and 6 blank row on right hand side (school_open_time and school_close_time) i need only one row when both table have a row of a given day but using above query take only first row of corresponding table_school where school_owner_id is 50(let), it not see the condition that school_day name should be given day

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  • Why do I recieve multiple warnings of "No running instance of xfce4-panel was found" when logging into Xubuntu?

    - by Fredrik
    I'm running Xubuntu 11.04, the bootup-time is quite fast but when I log in it takes close to a minute before the desktop is displayed, meanwhile I see no activity on the hard drive. When I finally have the desktop I see this notification repeated 10 times: and then this one: In .config/autostart I have these entries $ ls xfce4-settings-helper-autostart.desktop xfce4-clipman-plugin-autostart.desktop xfce-panel.desktop $ cat xfce-panel.desktop [Desktop Entry] Encoding=UTF-8 Version=0.9.4 Type=Application Name=xfce4-panel Comment= Exec=xfce4-panel StartupNotify=false Terminal=false Hidden=false I need some assistance to locate the slow startup, which logs to look at etc. And then this annoying message about xfce-panel. Where do I look for from where it is started.

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  • Why does a user have to enter "Profile" data to enter data into other tables?

    - by Greg McNulty
    EDIT It appears the user has to enter some data for his profile, otherwise I get this error below. I guess if there is no profile data, the user can not continue to enter data in other tables by default? I do not want to make entering user profile data a requirement to use the rest of the sites functionality, how can I get around this? Currently I have been testing everything with the same user and everything has been working fine. However, when I created a new user for the very first time and tried to enter data into my custom table, I get the following error. The INSERT statement conflicted with the FOREIGN KEY constraint "FK_UserData_aspnet_Profile". The conflict occurred in database "C:\ISTATE\APP_DATA\ASPNETDB.MDF", table "dbo.aspnet_Profile", column 'UserId'. The statement has been terminated. Not sure why I am getting this error. I have the user controls set up in ASP.NET 3.5 however all I am using is my own table or at least that I am aware of. I have a custom UserData table that includes the columns: id, UserProfileID, CL, LL, SL, DateTime (id is the auto incremented int) The intent is that all users will add their data in this table and as I mentioned above it has been working fine for my original first user I created. However, when i created a new user I am getting this problem. Here is the code that updates the database. protected void Button1_Click(object sender, EventArgs e) { //connect to database MySqlConnection database = new MySqlConnection(); database.CreateConn(); //create command object Command = new SqlCommand(queryString, database.Connection); //add parameters. used to prevent sql injection Command.Parameters.Add("@UID", SqlDbType.UniqueIdentifier); Command.Parameters["@UID"].Value = Membership.GetUser().ProviderUserKey; Command.Parameters.Add("@CL", SqlDbType.Int); Command.Parameters["@CL"].Value = InCL.Text; Command.Parameters.Add("@LL", SqlDbType.Int); Command.Parameters["@LL"].Value = InLL.Text; Command.Parameters.Add("@SL", SqlDbType.Int); Command.Parameters["@SL"].Value = InSL.Text; Command.ExecuteNonQuery(); } Source Error: Line 84: Command.ExecuteNonQuery();

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  • Analiytics: Can I set a goal on multiple events?

    - by David Parks
    We have a popup dialogue that requests users email address or facebook login. The page behind the popup loads, so a page view is counted. We want to measure: How many users ignored the popup completely How many users engaged the popup, but don't complete the process (we trigger an event when the user performs actions defined as "engaging") How many users completed the popup Bounce rates aren't telling because some users won't receive the popup. We are basically triggering events "PopupDisplayed" "PopupEngaged" and "PopupComplete", with labels to differentiate between email and facebook. But I don't think I can set goals to count "Users who received 'PopupDisplayed' AND 'PopupComplete'" events, so I can count how many users both saw the popup and completed it.

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  • Ubuntu One Sync for multiple folders, not just the Ubuntu One folder.

    - by bisi
    Hello, I may have misunderstood Ubuntu One as a service, but this is how I had pictured it. At home, I tagged a few folders with the "Sync to Ubuntu One" tick and it started uploading. Now back at work, on Win7, I installed Ubuntu One and thought I was going to be able to tick which of the backed-up folders I could download/sync to this machine. From what I gather after a little research is that whatever I would like to synchronize would need to be in the Ubuntu One folder? There is no way to do this outside of that? Thanks for confirming, or informing me whether this will be introduced in the future as an option? Thank you very much for your help on this! bisi

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  • How should I log time spent on multiple tasks?

    - by xenoterracide
    In Joel's blog on evidence based scheduling he suggests making estimates based on the smallest unit of work and logging extra work back to the original task. The problem I'm now experiencing is that I'll have create object A with subtask method A which creates object B and test all of the above. I create tasks for each of these that seems to be resulting in ok-ish estimates (need practice), but when I go to log work I find that I worked on 4 tasks at once because I tweak method A and find a bug in the test and refactor object B all while coding it. How should I go about logging this work? should I say I spent, for example, 2 hours on each of the 4 tasks I worked on in the 8 hour day?

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  • Should I use the same AddThis tag on multiple sites?

    - by ripper234
    I have an AddThis for one site: <script type="text/javascript" src="http://s7.addthis.com/js/250/addthis_widget.js#pubid=ripper234"> </script> Now I logged into AddThis and wanted to get my tag again, I saw it changed: <script type="text/javascript" src="http://s7.addthis.com/js/300/addthis_widget.js#pubid=ripper234"> </script> Should I use the same tag I got before, or the new tag? What's the difference? Is 250/300 the internal version number?

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  • Is there a pattern or best practice for passing a reference type to multiple classes vs a static class?

    - by Dave
    My .NET application creates HTML files, and as such, the structure looks like variable myData BuildHomePage() variable graph = new BuildGraphPage(myData) variable table = BuildTablePage(myData) BuildGraphPage and BuildTablePage both require access data, the myData object. In the above example, I've passed the myData object to 2 constructors. This is what I'm doing now, in my current project. The myData object, and it's properties are all readonly. The problem is, the number of pages which will require this object has grown. In the real project, there are currently 4, but the new spec is to have about 20. Passing this object to the constructor of each new object and assigning it to a field is a little time consuming, but not a hardship! This poses the question whether it's better practice to continue as I have, or to refactor and create a new static class for myData which can be referenced from any where in my project. I guess my abilities to use Google are poor, because I did try and find an appropriate pattern as I am sure this type of design must be common place but my results returned nothing. Is there a pattern which is suited, or do best practices lean towards one implementation over another.

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  • To have multiple sites with similar content on the same server but different IPs?

    - by Eugene
    I have 7 different sites on the same dedicated server. Two major sites have different IPs, and 5 small share the same IP. About first 2 they have similar content, but not the same. Basically they have different: URLs Titles Meta Data But they both have the same niche. I was thinking about two strategies. One is to move one of the sites (from 2 first one) on different server or move 5 other sites on different server. But I'm not sure which way is better. My questions are: Wouldn't be better from SEO stand point, to move those 2 sites on different servers? Does it worth it to spend for additional server? Do you know if Google penalize sites for similar content on the same server with different IPs?

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  • Why do people have to use multiple versions of jQuery in the same page?

    - by reprogrammer
    I have noticed that sometimes people have to use multiple versions of jQuery in the same page (See question 1 and question 2). I assume people have to carry old versions of jQuery because some pieces of their code is based on an older version of jQuery. Obviously, this approach causes inefficiency. The ideal solution is to refactor the old code to use the newer jQuery API. I wonder if there are tools that automate the process of upgrading a piece of code to use a newer version of jQuery. I've never written programs in in either Javascript or jQuery. So, I'd like to hear from programmers experienced in these language about their opinion on this issue. In particular, I'd like to know the following. How much of problem it is to have to load multiple versions of jQuery? Have you ever had to load multiple versions of any other library in the same page? Do you know of any refactoring tools that helps you migrate your code to use the updated API? Do you think such a refactoring tool is useful? Are you willing to use it?

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  • Is there a Content Management System that allows multiple & independent blogs to be running on one domain?

    - by Ron
    Hello Webmasters, I am a Wordpress fan, and I'm now building a new site and I'm not sure which CMS can achieve what I'm trying to do. I am building a food blog network for a bunch of cities in the US, and I want to my city pages to be independently running blogs themselves. So basically... Home Page - Its own blog with its own users, talking about Food in general Dallas Page (child of home page) - Its own blog with its own users Chicago Page ..... so on and so forth. The web layout and design will be all the same, but just trying to achieve 25~50 independent blogs on one domain. How can I achieve this? I'm hoping that I don't have to install Wordpress into as many subdomains that I create... Thank you for your help in advance. -RP

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  • Business operates in multiple counties, will adding a listing in the Local Business sites harm our placement in SERPs?

    - by leeand00
    I work at a non-profit where we operate in more than two counties within our state. Our offices are located in two different towns, and that leaves a few counties of operation where we would also like to appear in their local SERPs or Local Business listings. Please note that these towns are not necessarily close to all the areas of operation. Since we don't have offices in all the counties of operation, how can we effectively post our business in the Local Business Listings and still show up in our counties of operation?

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  • How do I detect multiple sprite collisions when there are >10 sprites?

    - by yao jiang
    I making a small program to animate the astar algorithm. If you look at the image, there are lots of yellow cars moving around. Those can collide at any moment, could be just one or all of them could just stupidly crash into each other. How do I detect all of those collisions? How do I find out which specific car has crash into which other car? I understand that pygame has collision function, but it only detects one collision at a time and I'd have to specify which sprites. Right now I am just trying to iterate through each sprite to see if there is collision: for car1 in carlist: for car2 in carlist: collide(car1, car2); This can't be the proper way to do it, if the car list goes to a huge number, a double loop will be too slow.

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  • How can I screen clients that try to register multiple times?

    - by Aba Dov
    My company offers a bonus to every client that register. We would like to prevent people from abusing this by registering several times. we thought about filtering clients by ip (there is a problem with workplaces where all stations have the same ip) cookies (if cookies are not allowed we might lose a client) I would like your opinions on these two methods and will be glad to hear about new ones. thanks

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  • Why do people have to use multiple versions of jQuery on the same page?

    - by reprogrammer
    I have noticed that sometimes people have to use multiple versions of jQuery in the same page (See question 1 and question 2). I assume people have to carry old versions of jQuery because some pieces of their code is based on an older version of jQuery. Obviously, this approach causes inefficiency. The ideal solution is to refactor the old code to use the newer jQuery API. I wonder if there are tools that automate the process of upgrading a piece of code to use a newer version of jQuery. I've never written programs in in either Javascript or jQuery. So, I'd like to hear from programmers experienced in these language about their opinion on this issue. In particular, I'd like to know the following. How much of problem it is to have to load multiple versions of jQuery? Have you ever had to load multiple versions of any other library in the same page? Do you know of any refactoring tools that helps you migrate your code to use the updated API? Do you think such a refactoring tool is useful? Are you willing to use it?

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  • How do I link external style sheet to multiple pages and folders?

    - by user18681
    im building a pretty large website that will have many pages and folders. I have 1 stylesheet. How do I add the style sheet to "ALL" of these folders? I didnt have this problem before I started to put the pages in SEPERATE folders. Now that each page has its own folder it no longer reads my stylesheet unless its in the SAME folder Example, lets say I have a folder of pets, another of cars, and another of planes. I have to put my stylesheet in EACH and everyone of these folders so that I can see my site. How can I do it so that I do NOT have to put a stylesheet in each and every folder? In other words how can I get my stylesheets on the same page as my folders without having them in that folder? How can I get them to communicate while being in a different folder?

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  • How do you manage frequent software releases to multiple clients?

    - by meeech
    hi we have a cross-platform middleware product which we typically end up customizing/bug fixing on a per client basis. In some cases, providing updates as often as once/twice per week. We have a lot of trouble efficiently managing and releasing the updates to our clients. I've done some digging, but I can't find anything to specifically address this problem. Can anyone share their experiences - how do you deal with this scenario, or do you know of a good software delivery cms? thanks

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  • How to get multiple open-source projects to use a standard way of doing something.

    - by Marco
    Problem In the last couple weeks, I've used 3 different "repository" tools (listed in alphabetical order): gradle ivy maven I'm calling them "repository" tools because I've also used sbt -- which fortunately uses ivy to manage it's cache or local repository. Each of these tools will create it's own repository. The defaults are: ~/.m2/repository for maven ~/.gradle/cache ~/.ivy2/cache Why can't they all use the same cache? Goal I'd like to change the world so that all three build tools could use the same cache. I'm looking for advice about issues I'm likely to run into and smart ways to get around them. By "use the same cache", I do not mean "retrieve from another build tool's cache". I mean "retrieve from and store in another build tool's cache". While I could go ahead and submit issues to the three projects, I know from experience (as a developer on an open source project), that if you want something done, you're best off getting it done yourself. Also, it seems like I need to get all 3 communities on board to some degree. What is the recommended approach for getting this kind of thing done? How do I approach the different communities? Do I work on patches for the 3 different projects, or would it be better off to create my own "interface" project that deals with these issues and have the 3 tools interface with that? Is this a standards question that I need to address on that front? Lastly, if I'm missing something and this is possible (in an globally configurable fashion), then please let me know.

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  • How to handle possible duplicate content across multiple sites?

    - by ElHaix
    Let's say I have two sites that cover the same vertical/topic. one in the USA and one in Canada. Both sites have local-related content, which is obviously unique by location. However they will share common news or blog pages. How do I avoid getting hit with duplicate content on both sites for those news/blog pages? If the content is exactly the same, I'm guessing I would have to pick which site's content I want to noindex,nofollow, is that correct, and if so, is that all I have to add on the URL links to those pages, and the pages' meta tags?

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  • How do create an encrypted system with multiple Linux distributions?

    - by niels
    A few weeks ago I created a completely encrypted system on a notebook and must say I like the idea. It's a little bit annoying to enter the password on every boot, but it's nice to know even if I loose the computer I don't give my data to other people. With the alternate-cd it's easy to do. Now I have to setup a new system where I want to combine the new idea with my usual usage strategy. There I have more partitions: 3 system, Home, Different Data-Partitions for vm-data, photo-data and mp3-data. The background is that I prefer not to update a system. I prefer to install the new version parallel to the old system. So I can easily test it. Obviously the Data-Partitions are used for both systems. My questions is, how can I easily combine both my strategy and the crypto-approach? Or is it impossible. The way to do the crypted stuff by hand is in my eyes to complicated.

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