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  • Can I pop up alert in javascript using php.

    - by Shantanu Gupta
    I want to trigger javascript alert using PHP. Is it possible I want to use it in head section, for displaying it at load time. <head> <?php $valid="valid"; if(!isset($valid)) echo "<script type=\"text/javascript\"> alert('Hi');</script>"; ?> </head> EDIT i want to display javascript alert() at load time after checking existance of session

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  • firefox object height ignored when data

    - by John Rygielski
    I have a flash video loading in a modal window. It works in others browsers but not Firefox. Firefox opens the modal window to the correct width of the object, but with no height. I have come to learn that Firefox does not recognize <param> and instead uses the data attribute. However, when I remove this attribute, the modal opens with correct height. What is going on? Here is the code the modal window loads: <object width="720" height="520" type="application/x-shockwave-flash" data="proxymovie.SWF?file=proxymovie.MP4"> <param name="movie" value="proxymovie.SWF?file=proxymovie.MP4" /> <img src="images/poster.png" width="720" height="480" alt="" title="Download the video below" /> </object>

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  • Scroll to bottom of div?

    - by dMix
    I am creating an ajax chat in rails and I am trying to get a div to scroll to the bottom without much luck. I am wrapping everything in this div: #scroll { height:400px; overflow:scroll; } Is there a way to keep it scrolled to the bottom by default using JS? is there a way to keep it scrolled to the bottom after an ajax request?

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  • Can one form have multiple actions?

    - by Brook Julias
    I am wanting to submit a form to different places based on selections made in the form. If the user wants to delete elements go to page 1. If the user wants to edit/update elements go to page 2. If the user wants to group/attach elements go to page 3.

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  • How do I get a div to float to the bottom of its container?

    - by Stephen Martin
    I have floated images and inset boxes at the top of a container using float:right (or left) many times. Recently I hit a need to float a div at the bottom right corner of another div with the normal text wrap that you get with float (text wrapped above and to the left only). I thought this must be relatively easy even though float has no bottom value but I haven't been able to do it using a number of techniques and searching the web hasn't come up with anything other than using absolute positioning but this doesn't give the correct word wrap behaviour. I had thought this would be a very common design but apparently it isn't. If nobody has a suggestion I'll have to break my text up into separate boxes and align the div manually but that is rather precarious and I'd hate to have to do it on every page that needs it.

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  • Lightbox scrolling issue with IE7 & 8

    - by BlazeK
    The lightbox that i am using works great with all browsers except for IE. In IE, its giving me triple scrolls. http://obliqueinteractive.com/demo/monster/ CSS code for the iframe: #wrap { float:left; width:800px; height:500px; overflow-x: hidden; overflow-y: scroll; } #content-wrap { float:left; width:700px; padding-left:50px; } Why is IE adding additional scrolls to the lightbox window? any suggestions?

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  • How do I use price data in one table for a calculation that is stored in another table?

    - by shane
    I'm still leanring PHP/MySQL but have learned quite a bit thanks to codies on StackOverflow. I'm trying to setup a sort of room reservations system using two tables: SETUP: Room price table: Has, prices for a type room a client may want to rent as well as the dates (day of week) they wish to use it. Pricing varies based on day of the week and per room. I've setup a different table for each room type as each room type carries different pricing for each day of the week. So, There is an Alpha room table, Bravo room, etc. Within Alpha table are headers for the days of the week with pricing pre-entered into the rows. Client info table: Has the name, address, date of room use, etc data for the specific client. EXAMPLE: Alpha-room price table: Sun = $100; Mon = $200; Tue=$300 and so on. Bravo-room price table: Sun = $100; Mon = $200; Tue=$300 and so on. Client data table: ClientName; date-of-room-use; address; day_subtotal; grand_total. QUESTION: I'm trying to find PHP code that will: look at the date of room use in the client data table, look up the associated cost for that date in the specific room pricing table, record that unit cost in the day subtotal of the client data table and sum a grand total in the grand total row of the client data table (assuming the room may be used more than one day by the customer). I know there's something to do with join but I'm finding it difficult to grasp the concept and, if someone can demonstrate using this example, I think I will have a better understanding of how to work this sort of transaction. Thank you ALL in advance for your suggestions or alternatvie approaches.

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  • In the following list, how do I prevent jQuery from interacting with part of it.

    - by kylex
    I have the following list structure: <ul> <li>One</li> <li class="topActive">Two <ul> <li class="active">Two-1 <ul> <li>Two-1-1</li> </ul> </li> <li>Two-2</li> </ul> </li> <li>Three <ul> <li>Three-1</li> </ul> </li> </ul> with the following jQuery: $("ul>li>ul").hide(); $("ul>li>ul>li>ul").hide(); $("ul>li>ul>li>ul>ul>li").hide(); $('.active').parents().show();????????? $("ul>li").hoverIntent( function(){ $(this).children('ul').slideDown('fast'); }, function(){ $(this).children('ul').slideUp('fast'); } ); $("ul>li>ul>li").hoverIntent( function(){ $(this).children('ul').slideDown('fast'); }, function(){ $(this).children('ul').slideUp('fast'); } ); What I would like is this: When an li class is topActive, everything within that class down to the current class can not be affected by the jQuery that causes the list to slide up and down. so in the case provided the following would show, along with the top level: One Two Two-1 Two-2 Three And when I mouse over either, Two, or Two-1 or Two-2 nothing happens, but if I mouse over Three, the jQuery will cause it to slide up or slide down. In this example: <ul> <li>One</li> <li class="topActive">Two <ul> <li class="active">Two-1 <ul> <li>Two-1-1</li> </ul> </li> <li>Two-2</li> </ul> </li> <li>Three <ul> <li>Three-1</li> </ul> </li> </ul> When I mouseover Two-1, it will slide down, but when I mouse out Two-1 will remain. One Two Two-1 Two-2 Three Any suggestsions for either a CSS or jQuery implementation (or mixture of the two)?

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  • How to condense onclick code to be dynamic

    - by opbeta
    I am trying to get this onclick function code to be dynamic. I do not want to have 50 blocks of code for all the states. He is a quick snippet of the code var Ohio=function(){ document.getElementById('texas').style.display='none'; document.getElementById('florida').style.display='none'; document.getElementById('ohio').style.display='block'; } and so on and so forth..... How would I go about condensing this to make it smaller and dynamic?

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  • refresh page after form download submit

    - by solomongaby
    Hello, I have a form that as an action returns a download. The problem is that the page will pop-out the download, and you can save it, but it will not allow another form submit. i was thinking of doing a page refresh after the submit. But i cant figure out how to do that and not stop the download. Do you have any ideas. Thanks

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  • PHP/MySQL allowing current user to edit there account information

    - by user1837896
    i have created 2 pages update.php edit.php we start on edit.php so here is edit.php's script <?php session_start(); $id = $_SESSION["id"]; $username = $_POST["username"]; $fname = $_POST["fname"]; $password = $_POST["password"]; $email = $_POST["email"]; mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); echo "MySQL Connection Established! <br>"; mysql_select_db("a2670376_Pass") or die(mysql_error()); echo "Database Found! <br>"; $query = "UPDATE members SET username = '$username', fname = '$fname', password = '$password' WHERE id = '$id'"; $res = mysql_query($query); if ($res) echo "<p>Record Updated<p>"; else echo "Problem updating record. MySQL Error: " . mysql_error(); ?> <form action="update.php" method="post"> <input type="hidden" name="id" value="<?=$id;?>"> ScreenName:<br> <input type='text' name='username' id='username' maxlength='25' style='width:247px' name="username" value="<?=$username;?>"/><br> FullName:<br> <input type='text' name='fname' id='fname' maxlength='20' style='width:248px' name="ud_img" value="<?=$fname;?>"/><br> Email:<br> <input type='text' name='email' id='email' maxlength='50' style='width:250px' name="ud_img" value="<?=$email;?>"/><br> Password:<br> <input type='text' name='password' id='password' maxlength='25' style='width:251px' value="<?=$password;?>"/><br> <input type="Submit"> </form> now here is the update.php page where i am having the MAJOR problem <?php session_start(); mysql_connect('mysql13.000webhost.com', 'a2670376_Users', 'Password') or die(mysql_error()); mysql_select_db("a2670376_Pass") or die(mysql_error()); $id = (int)$_SESSION["id"]; $username = mysql_real_escape_string($_POST["username"]); $fname = mysql_real_escape_string($_POST["fname"]); $email = mysql_real_escape_string($_POST["email"]); $password = mysql_real_escape_string($_POST["password"]); $query="UPDATE members SET username = '$username', fname = '$fname', email = '$email', password = '$password' WHERE id='$id'"; mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ echo "<p>($id) Record Updated<p>"; }else{ echo "<p>($id) Not Updated<p>"; } ?> now on edit.php i fill out the form to edit the account "test" while i am logged into it now once the form if filled out i click on |Submit!| button and it takes me to update.php and it returns this (0) Not Updated (0) <= id of user logged in Not Updated <= MySql Error from mysql_query($query)or die(mysql_error()); if(mysql_affected_rows()>=1){ i want it to update the user logged in and if i am not mistaken in this script it says $id = (int)$_SESSION["id"]; witch updates the user with the id of the person who is logged in but it isnt updating its saying that no tables were effected if it helps heres my MySql Database picture just click here http://i50.tinypic.com/21juqfq.png if this could possibly be any help to find the solution i have 2 more files delete.php and delete_ac.php they have can remove users from my sql database and they show the user id and it works there are no bugs in this script at all PLEASE DO NOT MAKE SUGGESTIONS FOR THE SCRIPTS BELOW delete.php first <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="PASSWORD"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // select record from mysql $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql); ?> <table border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" style="bgcolor: #FFFFFF"><strong><img src="http://i47.tinypic.com/u6ihk.png" height="30" widht="30">Delete data in mysql</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"><strong>Id</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>UserName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>FullName</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Password</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Email</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Date</strong></td> <td align="center" bgcolor="#FFFFFF"><strong>Ip</strong></td> <td align="center" bgcolor="#FFFFFF">&nbsp;</td> </tr> <?php while($rows=mysql_fetch_array($result)){ ?> <tr> <td bgcolor="#FFFFFF"><? echo $rows['id']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['username']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['fname']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['password']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['email']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['date']; ?></td> <td bgcolor="#FFFFFF"><? echo $rows['ip']; ?></td> <td bgcolor="#FFFFFF"><a href="delete_ac.php?id=<? echo $rows['id']; ?>">delete</a></td> </tr> <?php // close while loop } ?> </table> <?php // close connection; sql_close(); ?> and now delete_ac.php <table width="500" border="0" cellpadding="3" cellspacing="1" bgcolor="#CCCCCC"> <tr> <td colspan="8" bgcolor="#FFFFFF"><strong><img src="http://t2.gstatic.com/images? q=tbn:ANd9GcS_kwpNSSt3UuBHxq5zhkJQAlPnaXyePaw07R652f4StmvIQAAf6g" height="30" widht="30">Removal Of Account</strong> </td> </tr> <tr> <td align="center" bgcolor="#FFFFFF"> <?php $host="mysql13.000webhost.com"; // Host name $username="a2670376_Users"; // Mysql username $password="javascript00"; // Mysql password $db_name="a2670376_Pass"; // Database name $tbl_name="members"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id']; // Delete data in mysql from row that has this id $sql="DELETE FROM $tbl_name WHERE id='$id'"; $result=mysql_query($sql); // if successfully deleted if($result){ echo "Deleted Successfully"; echo "<BR>"; echo "<a href='delete.php'>Back to main page</a>"; } else { echo "ERROR"; } ?> <?php // close connection mysql_close(); ?> </td> </tr> </table>

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  • How to change the number of columns in a table dynamically but still keep the table layout intact?

    - by gurupriyan.e
    I have a 'n' column table , the first column is a drop down box , on selecting the options from the drop down, the other columns change. For eg: first drop down might need to display a text box and a button , the second drop down 3 text boxes and a button and so on. There is only one row in the table. What is the best solution to achieve this. with Sincere thanks,

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  • ORDER BY column_name help (via link in HTML table view) (PHP MySQL

    - by Derek
    My output for my table in HTML has several columns such as userid, name, age, dob. The table heading is simply the title of the column name, I want this to be a link, and when clicked, the selected column is sorted in order, ASC, and then DESC (on next click). I thought this was pretty straight forward but I'm having some difficulty. So far, I have produced this, and no output is taken, apart from the URL works by displaying 'users.php?orderby=userid' <?php if(isset($_GET['orderby'])){ $orderby = $_GET['orderby']; $query_sv = "SELECT * FROM users BY ".mysql_real_escape_string($orderby)." ASC"; } //default query else{ $query_sv = "SELECT * FROM users BY user_id DESC"; } ?> <tr> <th><a href="<?php echo $_SERVER['php_SELF']."?orderby=userid";?>">User ID</a></th> Hoefully if I get this working, I can sort the users by D.O.B. next also using the same principles. Does anyone have any ideas?

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  • DIV tags not being properly nested.

    - by chustar
    I have created some <div> tags and am setting it to contain two <div> tags that are floated to both sides of the <div>. I noticed when I tried to set a background color that the containing <div> was not properly wrapping around the <div>s that its supposed to contain. I would like to know why this happens. I have seen a similar question here http://stackoverflow.com/questions/611220/why-are-these-div-tags-not-nesting-properly but no one has explained why this happens in any of the answers.

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  • Browser back button broken between hidden div's

    - by Linda
    First of all, these pages will never be on the web but will be in internal memory. They are a group of linked documents---an ebook. http://www.anmldr.com/testdivs When I click on the link in the first div, the second div becomes visible and the first div is hidden. The problem is with the browser's back button. If you then click on the back button, the URL updates but the first div does not show again. How can I correct the back button so that the first div shows? The link from the second div to the first div works fine but it is the browser back button that I do not know how to work with. Thanks, Linda P.S. These are using CSS3 so it is better to use a WebKit based browser.

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  • how to send a POST value to a server with a PHP script waiting for it from iPhone app

    - by Sam Jarman
    Hi In my iPhone app - I am trying to get what the user types in a box emailed to me. I am going to use a PHP script sitting on my server, and try send the data to it for it to be processed. Promblem is... how do i do this? Im using the ASIHTTPRequest wrapper and have some code like this ASIFormDataRequest *request = [[[ASIFormDataRequest alloc] initWithURL:url] autorelease]; [request setPostValue:@"[email protected]" forKey:@"address"]; [request setPostValue:@"mymessagehere" forKey:@"message"]; and have this simple php script which i plan to use here http://www.w3schools.com/PHP/php_mail.asp How do I go about joining these up? Any tutorial links/blog post/ideas appreciated

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