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• GET and POST on the same page?

  - by Phil

  I am creating a commenting script and I came across a problem. I am having to use $_POST and $_GET on the same page, which I don't think makes sense. I am very new to php and am training myself. I have a page named viewVerses.php - this has a lists of verses. When someone follows the reply link, echo '<br /><a href="reply.php?verseid='.$verseid.'">Reply</a>'; I'm passing the verseid (commenting on bible verses) into the reply.php, so that a query may be made with that verseid. (This is so that the user can still see the verse he/she is commenting on). Now reply.php has the form in it for posting a reply. The form goes to postReply.php This is in postReply.php $title = $_POST['title']; $body = $_POST['body']; $verseid = $_GET[verseid]; Can I get the verseid from the url and the POST the values from the form in the same page? If not, is there a way I can do this better? Remember, I am new at php and probably won't implement a solution that is super hard. I have to get it for my to put it in my site. I hope this is clear

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• Using struts 2 with no tags

  - by WannaAsk

  Hi everyone, I wonder if you could guide me on this struts issue - I feel hopeless on this... I am working on migrating our web application to a Struts 2 portlet (I'm using Struts 2.1.8). The thing is, I am forced to avoid struts tags because our application relies on Dijit widgets, which are omitted when using struts tags. So now I should implement the <s:form tag using scriptlets. My question is: how you would suggest I imitate the way struts handles the "action" attribute? Right now it appears I should: Create a regular html form in my jsp. Get/create the ActionConfig object during onsubmit and set on it values which match my desired destination: class+method+result jsp. Execute the action I set in 2. Would you recommend this? If so - is ActionConfig obtained from the session? Can I initiate an action execution from ActionConfig? (Aletrnatively... generating an action url using struts' form.vm file - what do you say?) I would appreciate any help on this - Thanks a lot in advance!!!

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• User welcome message in php

  - by user225269

  How do I create a user welcome message in php. So that the user who has been logged on will be able to see his username. I have this code, but it doesn't seem to work. <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM users WHERE Username='$username'"); while($row = mysql_fetch_array($result)) { echo $row['Username']; echo "<br />"; } ?> I'm trying to make use of the data that is inputted in this login form: <form name="form1" method="post" action="verifylogin.php"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="myusername" type="text" id="idnum" maxlength="5"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="mypassword" type="password" id="lname" maxlength="15"></td> </tr> <td align="right" width="30"><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td align="right" width="30"><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> But this, verifylogin.php, seems to be in the way. <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $myusername=$_POST['myusername']; $mypassword=$_POST['mypassword']; $myusername = stripslashes($myusername); $mypassword = stripslashes($mypassword); $myusername = mysql_real_escape_string($myusername); $mypassword = mysql_real_escape_string($mypassword); $sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'"; $result=mysql_query($sql); $count=mysql_num_rows($result); if($count==1){ session_register("myusername"); session_register("mypassword"); header("location:userpage.php"); } else { echo "Wrong Username or Password"; } ?> How do I do it? I always get this error when I run it: Notice: Undefined variable: username in C:\wamp\www\exp\userpage.php on line 53 Can you recommend of an easier on how I can achieve the same thing?

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• How can I measure the time it takes a file to upload to a PHP script?

  - by Gustav Bertram

  I am trying to measure the time a script takes to upload a file to a PHP script, inside the receiving script. Here's a short example: <form action="#" enctype="multipart/form-data" method="post"> Upload: <input type="file" name="datafile" size="40"> <input type="submit" value="Send"> </form> <?php $upload_time = time() - $_SERVER['REQUEST_TIME']; echo $upload_time . " seconds."; I've submitted 4MB, 25MB, 100MB and 1.4GB files. They took anything from a fraction of a second, to almost a minute, yet the script above always yielded 0 seconds. NOTE: I know that this is a duplicate question, but the accepted answer on the other question did not work for me (at least, initially): Detect how long it takes for a file to upload (PHP) I've tried it using PHP 5.3.3 with Apache 2.2.16 on Ubuntu 10.4. UPDATE: I've discovered that both the Apache header and Ajax solutions work. In fact, the solution on the duplicate question also works. The critical element to making these solutions work is to ensure that the following values in the php.ini are sufficiently high: memory_limit = 1000M upload_max_filesize = 1000M post_max_size = 1000M I am accepting the Apache header solution, since it only uses PHP.

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• wordpress add post validation

  - by dskanth

  This is embarrassing, but yet i am surprised to see that there is no validation by default while adding a new post in wordpress. When i don't enter a title and even content, and just hit Publish, it says that the post is published, and when i view the front end, there is no new post. How could wordpress skip the simple validation for adding a post? Atleast i expected a server side validation (if not client side). Don't know why the validation is skipped. It is upto wordpress, whether they incorporate it in the new versions. But i want to know how can i add a javascript (or jquery) validation for adding a post in wordpress. I know it must not at all be difficult. But being new to wordpress, i would like to get some hint. From Firebug, i could see the form is rendering like: <form id="post" method="post" action="post.php" name="post"> ... </form> Where shall i put my javascript validation code?

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• Fasted way to develop data entry screens for a .NET backend ?

  - by jay23

  I am a .NET / C# back end guy. I am working on a app that will have about 200 different data entry screens. For me exposing DTO as a collection for CRUD (IUpdatable and IQueryable) is the easy part, can do it in sleep :-). What I am trying to decide is what type of front end technology will allow me to develop these data entry screens fast. They don't have to be fancy but they are not just plain grid either and on average they have about 15 form fields and some client side data validation (no db look up) Options I am looking at are Use ExtJS on the front and REST / JSON on the back. ASP.NET RIA but I do not know SL (Well XAML) Plain ASP.NET / MVC One idea I had was the DTO will contain the meta data about the form (As Attributes) and the form can be dynamically generated, but i do not want to reinvent the wheel if their is an easy way. I have looked at RAD software but all of them look at the DB and generate screens. I rather want some thing that can look at my DTO and generate screens. Jay

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• How can I spot subtle Lisp syntax mistakes?

  - by Marius Andersen

  I'm a newbie playing around with Lisp (actually, Emacs Lisp). It's a lot of fun, except when I seem to run into the same syntax mistakes again and again. For instance, here's something I've encountered several times. I have some cond form, like (cond ((foo bar) (qux quux)) ((or corge (grault warg)) (fred) (t xyzzy))) and the default clause, which returns xyzzy, is never carried out, because it's actually nested inside the previous clause: (cond ((foo bar) (qux quux)) ((or corge (grault warg)) (fred)) (t xyzzy)) It's difficult for me to see such errors when the difference in indentation is only one space. Does this get easier with time? I also have problems when there's a large distance between the (mal-)indented line and the line it should be indented against. let forms with a lot of complex bindings, for example, or an unless form with a long conditional: (defun test () (unless (foo bar (qux quux) (or corge (grault warg) (fred)))) xyzzy) It turns out xyzzy was never inside the unless form at all: (defun test () (unless (foo bar (qux quux) (or corge (grault warg) (fred))) xyzzy)) I auto-indent habitually and use parenthesis highlighting to avoid counting parentheses. For the most part it works like a breeze, but occasionally, I discover my syntax mistakes only by debugging. What can I do?

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• VB.net/Excel- "Backwards" tab index For Each iteration with textboxes.

  - by MSD

  Hi there, I have a form with 3 textboxes and 1 button. textbox1 has tab index 0, and it's text = 1 textbox2 has tab index 1, and it's text = 2 textbox3 has tab index 2, and it's text = 3 I want to iterate thru the textboxes and place their values into cells so that... range("A1").value = txtbox1.text (ie: A1 = "1") range("A2").value = txtbox2.text (ie: A2 = "2") range("A3").value = txtbox3.text (ie: A3 = "3") but what I am getting is... range("A1").value = txtbox1.text (ie: A1 = "3") range("A2").value = txtbox2.text (ie: A2 = "2") range("A3").value = txtbox3.text (ie: A3 = "1") I have tried reversing the tab index for the text boxes, but it doesn't change the "backwards iteration". Is there something I can do to change this so that the loop runs from lowest tab index to highest? Thanks! Public Class Form1 Private Sub Button1_Click_1(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click Dim objExcel As New Microsoft.Office.Interop.Excel.Application 'Declaring the object. objExcel.Visible = True 'Setting Excel to visible. Dim cntrl As Control With objExcel .Workbooks.Add() 'Adding a workbook. .Range("A1").Select() 'Selecting cell A1. End With 'Form contains 3 text boxes, with one number in each (1,2,3), and one button to fire the code in this sub. For Each cntrl In Me.Controls 'For every control on the form... If TypeOf (cntrl) Is TextBox Then 'If the control is a textbox, then... With objExcel .ActiveCell.Value = cntrl.Text 'place the control's text in the active cell and... .ActiveCell.Offset(1, 0).Activate() 'offset down one row. End With End If 'If the control is not a textbox (if it's the button), do nothing. Next 'Go to the next control. objExcel = Nothing 'Release the object. GC.Collect() 'Clean up. End Sub End Class

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• Why does this sql statement keep saying it is a boolean and not a paramter? (php/Mysql)

  - by ggfan

  In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

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• How to use multiple identity numbers in one table?

  - by vincer

  I have an web application that creates printable forms, these forms have a unique number on them, the problem is I have 2 forms that separate numbers need to be created for them. ie) Form1- Numbered 2000000-2999999 Form2- Numbered 3000000-3999999 dbo.test2 - is my form information table Tsel - is my autoinc table for the 3000000 series numbers Tadv - is my autoinc table for the 2000000 series numbers What I have done is create 2 tables with just autoinc row (one for 2000000 series numbers and one for 3000000 series numbers), I then created a trigger to add a record to the coresponding table, read back the autoinc number and add it to my table that stores the form information including the just created autoinc number for the right series of forms. Although it does work, I'm concerned that the numbers will get messed up under load. I'm not sure the @@IDENTITY will always return the right value when many people are using the system. (I cannot have duplicates and I need to use the numbering form show above. See code below. ** TRIGGER ** CREATE TRIGGER MAKEANID2 ON dbo.test2 AFTER INSERT AS SET NOCOUNT ON declare @someid int declare @someid2 int declare @startfrom int declare @test1 varchar(10) select @someid=@@IDENTITY select @test1 = (Select name1 from test2 where sysid = @someid ) if @test1 = 'select' begin insert into Tsel Default values select @someid2 = @@IDENTITY end if @test1 = 'adv' begin insert into Tadv Default values select @someid2 = @@IDENTITY end update test2 set name2=(@someid2) where sysid = @someid SET NOCOUNT OFF

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• Codeigniter PHP - loading a view at an anchor point

  - by James Billings

  I have a form at the bottom of a long page, if a user fills out the form but it doesn't validate the page is reloaded in the typical codeigniter fashion: $this->load->view('template',$data); however because the form is way down at the bottom of the page I need the page to load down there like you do with HTML anchors. Does anyone know how to do this in codeigniter? I can't use the codeigniter redirect(); function because it loses the object and the validation errors are gone. Other frameworks I've used like Yii you can call the redirect function like: $this->redirect(); which solves the problem because you keep the object. I've tried using: $this->index() within the controller which works fine as a redirect but the validation errors are in another method which is where the current page is loaded from: $this->item($labs) but when I use this it get stuck in a loop Any ideas? I've seen this question a lot on the net but no clear answers. I'm researching using codeigniter "flash data" but think it's a bit overkill. cheers.

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• Textarea (asp:Textbox TextMode="Multiline") overlapping buttons

  - by Gogster

  Hi all, I'm having this problem with form buttons overlapping an asp:Texbox with TextMode set to multi-line: Here is the code: <asp:Panel ID="pnlGiftStep" Visible="false" runat="server"> <img src="/images/shopping-cart/form-separator.png" alt="separator" /> <div class="form-title">GIFT OPTIONS</div> <div class="row"> <asp:TextBox ID="txtGiftName" Height="31" Width="323" BorderStyle="None" Font-Names="Arial" Font-Size="116.7%" runat="server"></asp:TextBox> <cc1:TextBoxWatermarkExtender ID="wmeGiftName" TargetControlID="txtGiftName" WatermarkText="Gift Name" WatermarkCssClass="watermark" runat="server"></cc1:TextBoxWatermarkExtender> </div> <br class="clear" /> <div class="row"> <asp:TextBox ID="txtGiftMessage" Rows="5" Width="323" BorderStyle="None" Font-Names="Arial" TextMode="MultiLine" Font-Size="116.7%" runat="server"></asp:TextBox> <cc1:TextBoxWatermarkExtender ID="wmeGiftMessage" TargetControlID="txtGiftMessage" WatermarkText="Gift Message" WatermarkCssClass="watermark" runat="server"></cc1:TextBoxWatermarkExtender> </div> <br class="clear" /> <div class="button-row"> <asp:ImageButton ID="imbShippingDetails" ImageUrl="/images/shopping-cart/ship-details-btn.png" OnClick="ReturnToShipping" ValidationGroup="shipping" runat="server" /> <asp:ImageButton ID="imbPayDetails" ImageUrl="/images/shopping-cart/pay-details-btn.png" ValidationGroup="pay" runat="server" /> </div> <br class="clear" /> </asp:Panel> Here is the CSS: .row { float:left; height:40px; } .button-row { float:left; width:323px; text-align:right; } Any ideas how I can stop this? Thanks.

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• Asp.net MVC - Model binding image button

  - by big dave

  I've got a very complex form and i'm using the MVC model binding to capture all the information I've got it set up to capture all the different submissions that can happen as there are about 10 different submit buttons on the form, and there are also 2 image buttons I tried to get a bit clever (or so i thought) with capturing the image button submissions, and have created a child class so that i can capture the x value that's returned public class ImageButtonViewData { public int x { get; set; } public string Value { get; set; } } The parent class looks something like this public class ViewDataObject { public ImageButtonViewData ImageButton { get; set; } public ViewDataObject(){ this.ImageButton = new ImageButton(); } } The html for the image button then looks like <input type="image" id="ViewDataObject_ImageButton" name="ViewDataObject.ImageButton" /> This works fine in all browsers except for Chrome. When i debug it in chrome, the Request.Form object contains the values that i would expect, but after the model binding has occurred, the ImageButton property on the ViewDataObject has been set to null The only difference that i can see between the submission values is that Chrome passes the x as lower case (ViewDataObject.ImageButton.x) and IE passes it as upper case (ViewDataObject.ImageButton.X) but i didn't think that model binding took any notice of casing on property names Does anyone have any ideas ?

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• saveall not saving associated data

  - by junior29101

  I'm having a problem trying to save (update) some associated data. I've read about a million google returns, but nothing seems to be the solution. I'm at my wit's end and hope some kind soul here can help. I'm using 1.3.0-RC4, my database is in InnoDB. Course has many course_tees CourseTee belongs to course My controller function is pretty simple (I've made it as simple as possible): if(!empty($this-data)) $this-Course-saveAll($this-data); I've tried a lot of different variations of that $this-data['Course'], save($this-data), etc without luck. It saves the Course info, but not the CourseTee stuff. I don't get an error message. Since I don't know how many tees any given course will have, I generate the form inputs dynamically in a loop. $form-input('CourseTee.'.$i.'.teeName', array('error' = false, 'label' = false, 'value'=$data['course_tees'][$i]['teeName'])) The course inputs are simpler: $form-input('Course.hcp'.$j, array('error' = false, 'label' = false, 'class' = 'form_small_w', 'value'=$data['Course']['hcp'.$j])) And this is how my data is formatted: Array ( [Course] = Array ( [id] = 1028476 ... ) [CourseTee] = Array ( [0] = Array ( [key] = 636 [courseid] = 1028476 ... ) [1] = Array ( [key] = 637 [courseid] = 1028476 ... ) ... ) )

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• Filling a region draws it off canvas

  - by Xanyx

  Hi Using the following code in Delphi 2007: procedure TfrmTest.PaintBox1Paint(Sender: TObject); const Rect_Size = 10; begin PaintBox1.Canvas.Brush.Color := clYellow; PaintBox1.Canvas.FillRect(Rect(0, 0, PaintBox1.width, PaintBox1.height)); PaintBox1.Canvas.Brush.Color := clRed; DrawARect(PaintBox1.Canvas, 0, 0, Rect_Size, Rect_Size); end; procedure TfrmTest.DrawARect(ACanvas: TCanvas; iLeft, iTop, iWidth, iHeight: Integer); var rgnMain: HRGN; begin rgnMain := CreateRectRgn(iLeft, iTop, iLeft + iWidth, iTop + iHeight); try SelectClipRgn(ACanvas.handle, rgnMain); ACanvas.FillRect(ACanvas.ClipRect); SelectClipRgn(ACanvas.handle, 0); finally DeleteObject(rgnMain); end; end; I get this: (Yellow area shows boundaries of PaintBox1). HMMM, NOT ALLOWED TO POST IMAGE Please go to: http://www.freeimagehosting.net/uploads/62cf687d29.jpg (Linked image shows a form with a yellow box [PaintBox1] in the center. However my red rectange [rgnMain] has been drawn at pos 0,0 on the form) My expectation was that the red rectangle would be at the top left of the PaintBox1 canvas, not the form's canvas. Why is it not? Can regions only be used with controls that have a Windows handle? Thanks

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• Django ModelForm Imagefield Upload

  - by Wei Xu

  I am pretty new to Django and I met a problem in handling image upload using ModelForm. My model is as following: class Project(models.Model): name = models.CharField(max_length=100) description = models.CharField(max_length=2000) startDate = models.DateField(auto_now_add=True) photo = models.ImageField(upload_to="projectimg/", null=True, blank=True) And the modelform is as following: class AddProjectForm(ModelForm): class Meta: model = Project widgets = { 'description': Textarea(attrs={'cols': 80, 'rows': 50}), } fields = ['name', 'description', 'photo'] And the View function is: def addProject(request, template_name): if request.method == 'POST': addprojectform = AddProjectForm(request.POST,request.FILES) print addprojectform if addprojectform.is_valid(): newproject = addprojectform.save(commit=False) print newproject print request.FILES newproject.photo = request.FILES['photo'] newproject.save() print newproject.photo else: addprojectform = AddProjectForm() newProposalNum = projectProposal.objects.filter(solved=False).count() return render(request, template_name, {'addprojectform':addprojectform, 'newProposalNum':newProposalNum}) the template is: <form class="bs-example form-horizontal" method="post" action="">{% csrf_token %} <h2>Project Name</h2><br> {{ addprojectform.name }}<br> <h2>Project Description</h2> {{ addprojectform.description }}<br> <h2>Image Upload</h2><br> {{ addprojectform.photo }}<br> <input type="submit" class="btn btn-success" value="Add Project"> </form> Can anyone help me or could you give an example of image uploading? Thank you!

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• PHP checking/refreashing functions

  - by user1284360

  ok i have a main document that displays a chatbox, what i want is for the chatbox to refreash on everyone who is logged in's screen whenever someone posts a new message... ive tried many methods including sleep timers and new functions that call then sleep and get recalled but this just generates an endless line of the same or little diffrent data making the form unusable until error... this is my code <?php // set error reporting level if (version_compare(phpversion(), "5.3.0", ">=") == 1) error_reporting(E_ALL & ~E_NOTICE & ~E_DEPRECATED); else error_reporting(E_ALL & ~E_NOTICE); require_once('inc/login.inc.php'); require_once('inc/chat.inc.php'); // initialization of login system and generation code $oSimpleLoginSystem = new SimpleLoginSystem(); $oSimpleChat = new SimpleChat(); // draw login box echo $oSimpleLoginSystem->getLoginBox(); // draw chat application $sChatResult = '<font color="0x99000"> <a href="Register_form.html">New Account</a><br> login to send a message<br> or register for a new account</font>'; if ($_COOKIE['member_name'] && $_COOKIE['member_pass']) { if ($oSimpleLoginSystem->check_login($_COOKIE['member_name'], $_COOKIE['member_pass'])) { $sChatResult = ""; if($oSimpleLoginSystem->check_privledges($_COOKIE['member_name']) >= 2) { $sChatResult .= "<br>privledge check Working<br>"; } $sChatResult .= "<form action=$_SERVER[PHP_SELF] method='post'> <input type='hidden' name='foo' value='<?= $foo ?>' /> <input type='submit' name='submit' value='Refresh Messages' /> </form>"; $sChatResult .= $oSimpleChat->acceptMessages(); $sChatResult .= "<br><br>"; $sChatResult .= $oSimpleChat->getMessages(); } } echo $sChatResult; ?>

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• How to change name attribut value from twig

  - by taieb baccouch

  I am using Symfony version 2.3 and twig version 1.0. and I'm trying to change the name attribut value. Here is my code : <div class="control-group"> {{ form_label(form.menuTitle, null, {'label_attr': {'class': 'control-label'}}) }} {{ form_errors(form.menuTitle)}} <div class="controls"> <div class="span12"> {{ form_widget(form.menuTitle, {'attr': {'class': 'span6'}}) }} </div> </div> </div> The rendering code : <div class="control-group"> <label class="control-label required" for="smart_contactbundle_contact_menuTitle">Menu title</label> <div class="controls"> <div class="span12"> <input type="text" id="smart_contactbundle_contact_menuTitle" name="smart_contactbundle_contact[menuTitle]" required="required" maxlength="255" class="span6"> </div> </div> </div> I want to change name="smart_contactbundle_contact[menuTitle]" to name="menuTitle"

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• Handling large datasets with PHP/Drupal

  - by jo

  Hi all, I have a report page that deals with ~700k records from a database table. I can display this on a webpage using paging to break up the results. However, my export to PDF/CSV functions rely on processing the entire data set at once and I'm hitting my 256MB memory limit at around 250k rows. I don't feel comfortable increasing the memory limit and I haven't got the ability to use MySQL's save into outfile to just serve a pre-generated CSV. However, I can't really see a way of serving up large data sets with Drupal using something like: $form = array(); $table_headers = array(); $table_rows = array(); $data = db_query("a query to get the whole dataset"); while ($row = db_fetch_object($data)) { $table_rows[] = $row->some attribute; } $form['report'] = array('#value' => theme('table', $table_headers, $table_rows); return $form; Is there a way of getting around what is essentially appending to a giant array of arrays? At the moment I don't see how I can offer any meaningful report pages with Drupal due to this. Thanks

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• DRY jQuery for RESTful PUT/DELETE links

  - by Aupajo

  I'm putting together PUT/DELETE links, a la Rails, which when clicked create a POST form with an hidden input labelled _method that sends the intended request type. I want to make it DRYer, but my jQuery knowledge isn't up to it. HTML: <a href="/articles/1" class="delete">Destroy Article 1</a> <a href="/articles/1/publish" class="put">Publish Article 1</a> jQuery: $(document).ready(function() { $('.delete').click(function() { if(confirm('Are you sure?')) { var f = document.createElement('form'); $(this).after($(f).attr({ method: 'post', action: $(this).attr('href') }).append('<input type="hidden" name="_method" value="DELETE" />')); $(f).submit(); } return false; }); $('.put').click(function() { var f = document.createElement('form'); $(this).after($(f).attr({ method: 'post', action: $(this).attr('href') }).append('<input type="hidden" name="_method" value="PUT" />')); $(f).submit(); return false; }); });

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• ThickBox - update inside without redirect

  - by Alex Maslakov

  ASP.NET MVC and jQuery ThickBox. I show some content in ThickBox. It includes file upload form The view multi-media.apsx (it's strange, the this editor doesn't allow start the line with "<" in the code) form action="/upload/multi-media" method="post" enctype="multipart/form-data" label for="file"File name: input type="file" name="file" id="file" / input type="submit" value="Upload" / <% if (Model.Count > 0) { foreach (FileInfo mediaFile in Model) { <img width="100px" height="100px" src="<%: ResolveUrl("~/audio.png") %>" border="0" alt="<%: mediaFile.Name %>" / //................ After file upload I redirect to /upload/multi-media action and content shows in normal window, not in ThickBox. [ActionName("multi-media"), HttpPost] public ActionResult MultiMedia(HttpPostedFileBase file) { if (file.ContentLength > 0) { file.SaveAs(GenerateNewFileName(fullFileName)); return View("multi-media", model); } } How can I stay into ThickBox after file upload? I need show content in ThickBox all the time, even after the file upload.

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• PHP $_GET and $_POST are returning empty arrays--trying to paginate SQL data

  - by George88

  I have set up the following: Database class ($db) Pagination class ($paginator) I am attempting to write a basic system to let me administrate pages. I have a page "page_manager.php" in which I include both my database class (database.php) and my pagination class (paginate.php). In my pagination class I have a function which echoes my SQL data. I've come up with a way to echo an HTML < select element with the necessary IDs, which allows me to successfully echo the corresponding results (10 per page), based on the value of the < select element. So, "1" will echo the first 10 results in the database, "2" will echo from 11-20, "3" will echo from 21-30, etc., etc.. I have added an onChange event to the < select element which will copy its value (using "this.value") to a hidden form field. I then submit this form using document.getElementById().submit(); This will then add the $_GET variable to the URL, so the URL becomes ".../?pagenumber_form=X". However, when I try to grab this value back from the URL, the $_GET['pagenumber_form'] is empty. Some code: <span style='font-family: tahoma; font-size: 10pt;'>Page #</span> <select id="page_number_selection" onchange='javascript: document.getElementById("pagenumber_form").value = this.value; document.getElementById("pagenumber").submit();'> <?php for($i = 1; $i <= $this->num_pages; $i++) echo"<option id='" . $i . "'>" . $i . "</option>"; ?> </select> <form name="pagenumber" id="pagenumber" action="" method="get"> <input type="text" name="pagenumber_form" id="pagenumber_form" /> </form> So, I've tried using $_POST as well, but the same thing happens. I want to use $_GET, for a couple of reasons: it's easier to see what is happening with my values and the data I'm using doesn't need to be secure. To recap: the $_GET variable is being added to the URL when I change the < select element, and the corresponding value gets added to the URL as: ".../?pagenumber_form=X", but when I try to use the value in PHP, for example... $page_number = $_GET['pagenumber_form']; ... I get a NULL value. :-( Can anybody help me out please? Thank you. EDIT: I've just made a discovery. If I move my print_r($_GET) to my main index page, then the superglobals are returning as expected. My site structure is like this: index.php - JavaScript buttons use AJAX HTTP requests to include the "responseText" as the .innerHTML of my main < div . The "responseText" is the contents the page itself, in this case page_manager.php, which in turn includes pagination.php. So in other words, my site is built from PHP includes, which doesn't seem to be compatible with HTTP superglobals. Any idea how I can get around this problem? Thank you :-).

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• Disabling Text field with Javascript when value in drop down box is from mysql

  - by SteveJ313

  Hi I have a simple script in HTML, using a dropdown menu. When the value 1 is selected, the user can write in the text field, if value 2 is selected, it disables the text field. However, i changed the values of the dropdown menu, so that one value was from a mysql table(using PHP) and the other remained 'option value='1''. Yet now neither text field is disabled. Below is the code. `<script type="text/javascript"> function findselected() { if (document.form.selmenu.value == <?php echo $id; ?>) { document.form.txtField.disabled=true; // return false; // not sure this line is needed } else { document.form.txtField.disabled=false; // return false; // not sure this line is needed } } ` And the PHP section if(mysql_num_rows($SQL) == 1) { echo "<select name='selmenu' onChange='findselected()'>"; echo "<label>TCA_Subject</label>"; while ($row=mysql_fetch_array($SQL)) { echo "<option value='$id'>$thing</option>"; echo "<option value='2'>Choice 2</option>"; } } echo "<option value=$userid>'Choice 1'</option>"; ?> <option value='2'>Choice 2</option>"; </select> I have tried taking the second option value out of the loop, putting it into html, editing the variable in the javascript function. There is not a fault with the PHP as it is retrieving the right results and displaying it, yet the text field doesnt become disabled. Does anyone know of a possible solution? Thanks

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• conditional selects with jQuery and the Validation plugin

  - by dbonomo

  Hi, I've got a form that I am validating with the jQuery validation plugin. I would like to add a conditional select box (a selection box that is populated/shown depending on the selection of another) and have it validate as well. Here is what I have so far: $(document).ready(function(){ $("#customer_information").validate({ //disable the submit button after it is clicked to prevent multiple submissions submitHandler: function(form){ if(!this.wasSent){ this.wasSent = true; $(':submit', form).val('Please wait...') .attr('disabled', 'disabled') .addClass('disabled'); form.submit(); } else { return false; } }, //Customizes error placement errorPlacement: function(error, element) { error.insertAfter(element) error.wrap("<div class=\"form_error\">") } }); $(".courses").hide(); $("#course_select").change(function() { switch($(this).val()){ case "Certificates": $(".courses").hide().parent().find("#Certificates").show(); $(".filler").hide(); break; case "Associates": $(".courses").hide().parent().find("#Associates").show(); $(".filler").hide(); break; case "": $(".filler").show(); $(".courses").hide(); } }); }); And the HTML: <select id="course_select"> <option value="">Please Select</option> <option value="Certificates">Certificates</option> <option value="Associates">Associates</option> </select> <div id="Form0" class="filler"><select name="filler_select"><option value="">Please Select Course Type</option></select></div> <div id="Associates" class="courses"> <select name="lead_source_id" id="Requested Program" class="required"> <option value="">Please Select</option> <option value="01">Health Information Technology</option> <option value="02">Human Resources </option> <option value="03">Marketing </option> </select> </div> <div id="Certificates" class="courses"> <select name="lead_source_id" id="Requested Program" class="required"> <option value="">Please Select</option> <option value="04">Accounting Services</option> <option value="05">Bookkeeping</option> <option value="06">Child Day Care</option> </select> </div> So far, the select is working for me, but validation thinks that the field is empty even when a value is selected. It looks like there are a ton of ways to do conditional selects in jQuery. This was the best way I managed to work out (I'm new to jQuery), but I'd love to hear what you folks feel is the "best" way, especially if it works well with the validation plugin. Thanks!

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• Upload to a PHP Server, using Ajax ( XMLHttp POST)

  - by Krishnanunni

  Right now i'm using the below method to Upload a file to PHP <form enctype="multipart/form-data" action="http://sserver.com/fileupload.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="30000000" /> <input type="hidden" name="filename" value="file_uploaded.gif" /> <input type="hidden" name="username" value="foobar"/> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> I read the $_POST and $_FILE in php to complete upload like this. $target = $_SERVER['DOCUMENT_ROOT']."/test/upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; echo $target; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } My questions is , can i change the above said code (HTML) to an Ajax XMLHttpRequest without changes in PHP.

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