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  • drop down box php

    - by DAFFODIL
    I have stored 6 records in mysql db,when i use this code each of the 6 records getting displayed in seprate drop down box,i want them to be displayed in a single drop down box.Where am i going wrong? Any help ii be appreciated. Thnx in advance. http://dpaste.com/hold/180077/

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  • PHP PDO - Num Rows

    - by Ian
    PDO apparently has no means to count the number of rows returned from a select query (mysqli has the num_rows variable). Is there a way to do this, short of using count($results->fetchAll()) ?

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  • PHP: SimpleXML and Arrays

    - by acemasta
    When I run this code: foreach($xml->movie as $movie) { if(isset($movie->photos)) { foreach ($movie->photos as $photo) { echo $photo."&nbsp;"; } echo "<hr/>"; } } I get nice output of the actual data, e.g. a row looks like 06397001.jpg 06397002.jpg 06397003.jpg 06397004.jpg 06397005.jpg But when I throw it in an array, it includes all the SimpleXML wrapper tags and the jpgs are not at the root of the array. code: foreach($xml->movie as $movie) { if(isset($movie->photos)) { $photos = array(); foreach ($movie->photos as $photo) { $photos[] = $photo; } } else $photos = ""; var_dump($photos); echo "<hr />"; } e.g. same row looks like array(5) { [0]= object(SimpleXMLElement)#11 (1) { [0]= string(12) "06397001.jpg" } [1]= object(SimpleXMLElement)#12 (1) { [0]= string(12) "06397002.jpg" } [2]= object(SimpleXMLElement)#13 (1) { [0]= string(12) "06397003.jpg" } [3]= object(SimpleXMLElement)#14 (1) { [0]= string(12) "06397004.jpg" } [4]= object(SimpleXMLElement)#15 (1) { [0]= string(12) "06397005.jpg" } } Why is this happening/how can I remove this so I just get an array of the photos at root level like when I echo it? Thanks, sorry for the single line code formatting; was messing up when I tried to paste directly with line breaks.

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  • MySQL access classes in PHP

    - by Mike
    I have a connection class for MySQL that looks like this: class MySQLConnect { private $connection; private static $instances = 0; function __construct() { if(MySQLConnect::$instances == 0) { //Connect to MySQL server $this->connection = mysql_connect(MySQLConfig::HOST, MySQLConfig::USER, MySQLConfig::PASS) or die("Error: Unable to connect to the MySQL Server."); MySQLConnect::$instances = 1; } else { $msg = "Close the existing instance of the MySQLConnector class."; die($msg); } } public function singleQuery($query, $databasename) { mysql_select_db(MySQLConfig::DB, $this->connection) or die("Error: Could not select database " . MySQLConfig::DB . " from the server."); $result = mysql_query($query) or die('Query failed.'); return $result; } public function createResultSet($query, $databasename) { $rs = new MySQLResultSet($query, MySQLConfig::DB, $this->connection ) ; return $rs; } public function close() { MySQLConnect::$instances = 0; if(isset($this->connection) ) { mysql_close($this->connection) ; unset($this->connection) ; } } public function __destruct() { $this->close(); } } The MySQLResultSet class looks like this: class MySQLResultSet implements Iterator { private $query; private $databasename; private $connection; private $result; private $currentRow; private $key = 0; private $valid; public function __construct($query, $databasename, $connection) { $this->query = $query; //Select the database $selectedDatabase = mysql_select_db($databasename, $connection) or die("Error: Could not select database " . $this->dbname . " from the server."); $this->result = mysql_query($this->query) or die('Query failed.'); $this->rewind(); } public function getResult() { return $this->result; } // public function getRow() // { // return mysql_fetch_row($this->result); // } public function getNumberRows() { return mysql_num_rows($this->result); } //current() returns the current row public function current() { return $this->currentRow; } //key() returns the current index public function key() { return $this->key; } //next() moves forward one index public function next() { if($this->currentRow = mysql_fetch_array($this->result) ) { $this->valid = true; $this->key++; }else{ $this->valid = false; } } //rewind() moves to the starting index public function rewind() { $this->key = 0; if(mysql_num_rows($this->result) > 0) { if(mysql_data_seek($this->result, 0) ) { $this->valid = true; $this->key = 0; $this->currentRow = mysql_fetch_array($this->result); } } else { $this->valid = false; } } //valid returns 1 if the current position is a valid array index //and 0 if it is not valid public function valid() { return $this->valid; } } The following class is an example of how I am accessing the database: class ImageCount { public function getCount() { $mysqlConnector = new MySQLConnect(); $query = "SELECT * FROM images;"; $resultSet = $mysqlConnector->createResultSet($query, MySQLConfig::DB); $mysqlConnector->close(); return $resultSet->getNumberRows(); } } I use the ImageCount class like this: if(!ImageCount::getCount()) { //Do something } Question: Is this an okay way to access the database? Could anybody recommend an alternative method if it is bad? Thank-you.

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  • PHP: OOP and methods

    - by Pirkka
    Hello I`ve been wondering how to implement methods in a class. Could someone explain me what means if one does OOP in procedural style? Here is an example: class Fld extends Model { private $file; private $properties = array(); public function init($file) { $this->file = $file; $this->parseFile(); } private function parseFile() { // parses the file foreach($this->file as $line)...... .................. $this->properties = $result; } } I mean is it a good thing to have methods like these that do operations for the class properties like that. Or should I pass the class property as method parameter... I mean this would cause error if the file property wouldnt be declared.

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  • PHP, is_array() generating an "Undefined property: stdClass::$crit " error

    - by Brook Julias
    is_array($src2->crit) is generating an "Undefined property: stdClass::$crit" error. The line throwing the error is: if(is_array($src2->crit) && count($src->crit) > 0){ $src2->crit is initialized here. $src2->crit = array(); $src2->crit[0] = new dataSet(); $src2->crit[0]->tblName = $tbl2; $src2->crit[0]->colName = "ID"; $src2->crit[0]->val = $elm->editID; When testing $src2->crit with this code. print("\$src->crit is a ".$src->crit."<br />"); print_r($src->crit); print("<br />"); This is returned. $src2->crit is a Array Array ( [0] => dataSet Object ( [tblName] => sExam [colName] => ID [val] => 10 ) ) What am I not seeing/understanding correctly? If print("\$src2->crit is a ".$src->crit."<br />") returns that it is an array then why is is_array($src2->$crit) generating an error?

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  • How to extract keywords from a body of text in PHP

    - by Akeem
    Currently I'm leveraging http://developer.yahoo.com/search/content/V1/termExtraction.html which isn't ideal for performance and quality reasons. Before I embark on spending time on writing a system I wanted to see if there are any other available options that can do the trick.

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  • function and class to show image not working in php

    - by Gully
    i am trying to get get the following working nothing is happen when i use the function i am trying to get it to display images class ItemRes { //items DB var $img=""; } function ShowItemImage($index,$res_a){ if(sizeof($res_a) > $index){ if($res_a[$index] != NULL) { $cimg = $res_a[$index]->img; return "<img src='$cimg' width='70' height='70' style='cursor:pointer'></img>"; } }else{ return "<center class='whitetxt'><strong>Empty</strong></center>"; } } $res_array = array(); $idx=0; $result21 = mysql_query("SELECT * FROM photos WHERE eid='$eid' ORDER BY id DESC") or die (mysql_error()); while ($row21 = mysql_fetch_array($result21)) { $img_path = $row21['path']; $obj = new ItemRes(); $obj->img = $img_path; $res_array[$idx] = $obj; $idx++; } ShowItemImage(0,$res_array) ShowItemImage(1,$res_array)

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  • Capitalize Words in PHP with custom delimitor

    - by Paulie
    Hey guys, i need a method to capitalize every first letter of a word. This is what i got so far and it is working for almost every string...but it fails on this one "WELLNESS & RENOMME". // method in stringModify Class function capitalizeWords($words, $charList) { $capitalizeNext = true; for ($i = 0, $max = strlen($words); $i < $max; $i++) { if (strpos($charList, $words[$i]) !== false) { $`capitalizeNext` = true; } else if ($capitalizeNext) { $capitalizeNext = false; $words[$i] = strtoupper($words[$i]); } } return $words; } // Calling method $stringModify->capitalizeWords("WELLNESS & RENOMME", " -&"); I hope someone can help me out...i tried for 1,5 hours now and don't have a clue. Thanks in advance for any tips or hints. Greetz Paulie

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  • PHP mySQL - replace some string inside string

    - by apis17
    i want to replace ALL comma , into ,<space> in all address table in my mysql table. For example, +----------------+----------------+ | Name | Address | +----------------+----------------+ | Someone name | A1,Street Name | +----------------+----------------+ Into +----------------+----------------+ | Name | Address | +----------------+----------------+ | Someone name | A1, Street Name| +----------------+----------------+ Thanks in advance.

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  • Get the index value of an array in php

    - by Aakash Chakravarthy
    Hello, I have array $list = array('string1', 'string2', 'string3'); Now i want to get the index of the value string2 i.e 1 and 2 for string3 All i want is the position of the strings in the array string1 in 0 string2 in 1 string3 in 2 positions How to get this ? i used array_search but it is no use ! please help !

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  • php - arrange array to display in score order

    - by Phil Jackson
    hi, i have wrote a script to produce an array of data but now want to display in order of score. The array outputs as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user1_design [2] => user2_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 6 [2] => 15 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) so in a nutshell I am wanting it to be converted as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user2_design [2] => user1_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 15 [2] => 6 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) I have been looking at asort() but cant get anything to work. any help would be much appreciated.

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  • How to code a 'Next in Results' within search results in PHP

    - by thebluefox
    Right, bit of a head scratcher, although I've got a feeling there's an obvious answer and I'm just not seeing the wood for the trees. Baiscally, using Solr as a search engine for my site, bringing back 15 results per page. When you click on a result, you get a detail page, that has a "Next in Results" link on it, which obviously forwards you on to the next result. Whats the best way of doing this? I've come up with a few solutions but they're either too inpractical or just don't work. I could store all the ids in a session array, then grab the one after the current one and put that in the link. But with possibly hundreds/thousands of results, the memory that array would need, and the performance hit of dealing with it isn't practical. I could take the same approach and put it into the db, but I'll still have to deal with a potentially huge array when I grab them out of the db. Or; I could do the search again, only returning the id's, and grab the one after the one we're currently looking at. I think this could be the best option? Although it does seem kind of messy, namely because of when I have to select the id thats on a different 'page' (ie the 16th, 31st etc result). Unless I pass through where it was in the results, and select from there, but that still doesn't seem like the right way to do it. I'm really sorry if this is just complete nonsense, any help is massively appreciated as always, Cheers guys!

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  • PHP Date Manipulations

    - by Ajith
    I need to get previous 30 days from a specific date which is available from database(eg: 2010-05-23 12:36:29).I am try it by using date('d', strtotime("-30 days")) Which is getting the currect answer what i looking for but it is not help me to enter date from database.Please help me to solve the issue.

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  • PHP & AJAX SEO - For users with javascript and non javascript

    - by RussellHarrower
    So I understand this may come across as a open question, but I need away to solve this issue. I can either make the site do ajax request that load the body content, or I can have links that re-loads the whole page. I need the site to be SEO compliant, and I would really like the header to not re-load when the content changes, the reason is that we have a media player that plays live audio. Is there away that if Google BOT or someone without ajax enabled it does the site like normal href but if ajax or javascript allowed do it the ajax way.

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  • Implode error for PHP

    - by Pete Herbert Penito
    Hi Everyone! I have a form where I've got three checkboxes like this: <td>Wireless <input type="checkbox" name="services[]" value="wireless" /></td> </tr> <tr> <td>Cellular <input type="checkbox" name="services[]" value="cellular" /></td> </tr> <tr> <td>Security <input type="checkbox" name="services[]" value="Security" /></td> <input type="submit" name="submit"> and then I extract($_POST), and have this code $comServices = implode(",", $services); but I get an error: Warning: implode() [function.implode]: Invalid arguments passed in .. does anyone know why Im getting this error?

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  • PHP - Get dates of next 5 weekdays?

    - by Dan
    I'm trying to create an array of the next 5 working week days (Monday - Friday, excluding today). I know the working week varies around the world but this is not important for what I am trying to do. So, for example, if today is a Wednesday, I want the dates for Thursday and Friday of the current week and Monday, Tuesday and Wednesday of the following week. I thought this would work: $dates = array(); for ($i = 1; $ < 6; $i ++) { $dates[] = date('Y-m-d', strtotime('+ '.$i.' weekday')); } But for today, it is giving me: Monday 1st Tuesday 2nd Wednesday 3rd Thursday 4th Sunday 7th! Any advice appreciated. Thanks

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  • string function workout in php

    - by Karthik
    I have the string like this, $inp1 = "3 doses at 0[0,0], 1-2 and 6 Month[6,1] [3,2])"; in this internally, going to take the values of square bracket. How can i take this values in the square bracket? any function is there to return the string like this [0,0] [6,1] [3,2] Thanks in advance for help.

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  • Best way to stop SQL Injection in PHP

    - by Andrew G. Johnson
    So specifically in a mysql database. Take the following code and tell me what to do. // connect to the mysql database $unsafe_variable = $_POST["user-input"]; mysql_query("INSERT INTO table (column) VALUES ('" . $unsafe_variable . "')"); // disconnect from the mysql database

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  • INSERT INTO error MYSQL/PHP

    - by bat
    I get this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (total, addy, cc) VALUES ('798' , '123 sadf' , '12124123')' at line 1 $total = addslashes(($_SESSION['total'])); $addy = addslashes(($_POST['addy'])); $cc = addslashes(($_POST['cc'])); echo "$total"; echo "$addy"; echo "$cc"; mysql_query("INSERT INTO order (total, addy, cc) VALUES ('$total' , '$addy' , '$cc')") or die(mysql_error()); help plz =]

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  • image merging using php in GD

    - by vipinsahu
    hi i want to merge to images but the problem is one image is .PNG format and second one is .JPG format and after merging the output should be .PNG format but the transparency is not appearing .plz help Thanks

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  • php push 2d array into mysql

    - by john
    Hay All, I cant seem to get my head around this dispite the number to examples i read. Basically I have a 2d array and want to insert it into MySQL. The array contains a few strings. I cant get the following to work... $value = addslashes(serialize($temp3));//temp3 is my 2d array, do i need to use keys? (i am not at the moment) $query = "INSERT INTO table sip (id,keyword,data,flags) VALUES(\"$value\")"; mysql_query($query) or die("Failed Query"); Thanks Guys,

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  • PHP Scale image and then create image of specific size

    - by Ronny vdb
    The result I am trying to achieve is that the user can upload an image of any size, and the server side script will convert it to an image that has the dimension 1024x512. To save the aspect ratio of the image I first scale the image down by either the width or height to match the wanted dimensions. to do this I am using imagecopyresampled(): imagecopyresampled( $new_img, $src_img, $dst_x, $dst_y, 0, 0, $new_width, $new_height, $img_width, $img_height ) && $write_image($new_img, $new_file_path, $image_quality); If we take an image that is 1920x1200 as an example, the outputted image will be 819x512. However I still need a final result of 1024x512 so I want to add white borders to the image to will the width to 1024. How can I correct my imagecopyresampled function to acheive this?

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