How to loop an array with strings as indexes in PHP
- by Axel Lambregts
I had to make an array with as indexes A-Z (the alphabet). Each index had to have a value 0.
So i made this array:
$alfabet = array(
'A' => 0,
'B' => 0,
'C' => 0,
'D' => 0,
'E' => 0,
'F' => 0,
'G' => 0,
'H' => 0,
'I' => 0,
'J' => 0,
'K' => 0,
'L' => 0,
'M' => 0,
'N' => 0,
'O' => 0,
'P' => 0,
'Q' => 0,
'R' => 0,
'S' => 0,
'T' => 0,
'U' => 0,
'V' => 0,
'W' => 0,
'X' => 0,
'Y' => 0,
'Z' => 0
);
I also have got text from a file ($text = file_get_contents('tekst15.txt');)
I have putted the chars in that file to an array: $textChars = str_split ($text);
and sorted it from A-Z: sort($textChars);
What i want is that (with a for loop) when he finds an A in the textChars array, the value of the other array with index A, goes up by one (so like: $alfabet[A]++;
Can anyone help me with this loop? I have this atm:
for($i = 0; $i <= count($textChars); $i++){
while($textChars[$i] == $alfabet[A]){
$alfabet[A]++;
}
}
echo $alfabet[A];
Problem 1: i want to loop the alfabet array to, so now i only check for A but i want to check all indexes.
Problem2: this now returns 7 for each alphabet index i try so its totally wrong :)
I'm sorry about my english but thanks for your time.
