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  • What does the R function `poly` really do?

    - by merlin2011
    I have read through the manual page ?poly (which I admit I did not completely comphrehend) and also read the description of the function in book Introduction to Statistical Learning. My current understanding is that a call to poly(horsepower, 2) should be equivalent to writing horsepower + I(horsepower^2). However, this seems to be contradicted by the output of the following code. library(ISLR) summary(lm(mpg~poly(horsepower,2), data=Auto))$coef summary(lm(mpg~horsepower+I(horsepower^2), data=Auto))$coef Output: Estimate Std. Error t value Pr(>|t|) (Intercept) 23.44592 0.2209163 106.13030 2.752212e-289 poly(horsepower, 2)1 -120.13774 4.3739206 -27.46683 4.169400e-93 poly(horsepower, 2)2 44.08953 4.3739206 10.08009 2.196340e-21 Estimate Std. Error t value Pr(>|t|) (Intercept) 56.900099702 1.8004268063 31.60367 1.740911e-109 horsepower -0.466189630 0.0311246171 -14.97816 2.289429e-40 I(horsepower^2) 0.001230536 0.0001220759 10.08009 2.196340e-21 My question is, why does the output not match, and what is poly really doing?

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  • running jar file with multiple arguments in perl

    - by compiler9999
    Hi All, Im trying to run a jar file. this jar file will output multiple question in console manner, i want to eliminate the console and i need to input a value in order to proceed. e.g : A. Choose value 1 : [1] Windows [2] Unix Input : 2 B. Choose value 2 : [1] Oracle [2] DB2 Input : 1 Im trying : "java -jar program.jar < abc.txt" where abc.txt has a value of : 2 1 3 etc. but its not working its only getting the first value. please help. thanks. btw, ive also try : OPEN PIPE, "| java -jar program.jar"; open (FH, /abc.txt) print PIPE "$res"; close FH; close PIPE; Regards

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  • JavaScript to enable "submit" button (doesn't work)

    - by Halst
    I need the button "submit" to be disabled unless JavaScript is on. I tried: 1. <input onLoad="this.disabled=false" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> 2. <input onLoad="this.removeAttribute("disabled");" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> 3. <input onLoad="document.getElementById("post-comment").removeAttribute("disabled");" id="post-comment" type="submit" value="Post Your Comment" disabled="disabled"/> Doesn't work. I'm new to JavaScript, but can't find answer on the net.

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  • Executing in java code an external program that takes arguments

    - by rmaster
    Process p; String line; String path; String[] params = new String [3]; params[0] = "D:\\prog.exe"; params[1] = picA+".jpg"; params[2] = picB+".jpg"; try { p = Runtime.getRuntime().exec(params); BufferedReader input = new BufferedReader (new InputStreamReader(p.getInputStream())); while ((line = input.readLine()) != null) System.out.println(line); input.close(); } catch (IOException e) {System.out.println(" procccess not read"+e);} i don't get any error, just nothing in cmd.exe prog.exe is working fine What to improve in order to make this code working?

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  • How to tell MATLAB to open and save specific files in the same directory

    - by its-me
    I have to run an image processing algorithm on numerous images in a directory. An image is saved as name_typeX.tif, so there are X different type of images for a given name. The image processing algorithm takes an input image and outputs an image result. I need to save this result as name_typeX_number.tif, where 'number' is also an output from the algorithm for a given image. Now.. How do I tell MATLAB to open a specific 'typeX' file? Also note that there are other non-tif files in the same directory. How to save the result as name_typeX_number.tif? The results have to be saved in the same directory where the input images are present. How do I tell MATLAB NOT to treat the results that have been saved as an input images? I have to run this as background code on a server... so no user inputs allowed Thanks

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  • C Different answers for a variable when running 'Debug' and 'Start without debug'

    - by Craz
    I keep getting this weird output from my code everytime I use the 'start without degugging' (ctrl-F5) as opposed to normal 'debug' (F5). When I try to find the following value of norm_differnece in debug (pressing F5) mode, it gives me the correct answer for norm_difference normdifference = 1.000000 but in 'start without debugging' (pressing ctrl-f5) the wrong output normdifference = 1456816083547664100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000.000000 The following is a segment of code which is gives the output Note: X[] = is a array of stored DOUBLE values for(i=0;i<n;i++){ sum_difference += (pow((X[i*n]-X[i]),2)); } norm_difference = sqrt(norm_difference); for(i=0;i<n;i++){ sum_norm_1 += pow(X[i],2); } norm_1 = sqrt(norm_1); //Take square root of the sum of squares for the row printf("normdifference = %f \n norm_1 = %f \n",norm_difference,norm_1);

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  • C++ Boost bind value type {solved}

    - by aaa
    hello. I look in documentation and source code but cannot figure out how to get return value type of boost bind functor. I am trying to accomplish following: 35 template<typename T,size_t N, class F> 36 boost::array<typename F::value_type, N> make_array(T (&input)[N], F unary) { 37 boost::array<typename F::value_type, N> array; 38 std::transform(input, input + N, array.begin(), unary); 39 return array; 40 } where F can be bind functor. the above does not work because functor does not have value_type. for that matter, is there standard interface for unary/binary functor as far as return value. solution: it should be result_type. also equivalent defined are argument_type and first/second_argument_type for binary functions Thanks

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  • jQuery .click() .toggle() - change display and swap character

    - by danit
    Here is my jQuery: $('.ask').click(function() { $('.addtitle').slideToggle('fast', function() { // Animation complete. }); }); And my HTML: <p class="ask">+</p> <div class="addtitle"> <p>Give your Idea a great title</p> <form name="input" action="#" method="get"> <input id="title" type="text" name="title" /> <input id="go" type="submit" value="Go" /> </form> </div> I have multiple .ask div's on the page and I only want it to effect the .next() div named .ask rather than all div's named .ask. I also want to .toggle() the '+' character to '-' Can anyone assist?

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  • Selecting radiobuttons populated within asp.net RadioButtonList with jQuery

    - by user194881
    Hello and thanks in advance for the communal help I always find here. I have been tinkering around with what should seem a pretty straight forward task even for a jQuery newb as myself. I have a radiobuttonlist control bound to a collection: <asp:RadioButtonList ID="radBtnLstPackageSelector" runat="server" CssClass="PackageS"> </asp:RadioButtonList> My form does have several other controls of the same type; Now, the challenge is to select and wire up a on Click event for every radiobutton from the radBtnLstPackageSelector. I have tried several approaches such as: var results1 = $(".PackageS").children("input"); var results1 = $(".PackageS").children("input[type=radiobutton"); var results1 = $("table.PackageS > input[type=radiobutton"); with no luck... Your help would be great right now! ~m

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  • How do i get my search bar to actually work?

    - by Sam
    Hey guys, I've got a search bar and it looks fine, but i don't really know how to make it search the whole of my site... Here's my html code so far: <form class="search2" method="get" action="default.html" /> <input class="search2" type="text" name="serach_bar" size="31" maxlength="255" value="" style="left: 396px; top: 153px; width: 293px; height: 26px;" /> <input class="search1" type="submit" name="submition" value="Search" style=" padding- bottom:20px; left: 691px; top: 153px; height: 23px" /> <input class="search2" type="hidden" name="sitesearch" value="default.html" /> Thanks in advance guys!

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  • php exec and shell_exec not working

    - by chris
    I want to run an exe file on my server and return the output to the browser screen. The exe file takes a input file and then returns data on the screen. Why is this code not working? $output = shell_exec('myprogram < INP.DAT'); echo "<pre>" . var_export($output, TRUE) ."</pre>\\n"; It displays "NULL" on the browser screen. I have also tried exec(). There it returns "Array()".

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  • $_FILES empty on image upload

    - by zvir
    i need help, i'm programing some kind of catalogue and i have a page where clients can upload their logo or images. every page i make is included in index.php and my url looks like something like this www.url.com/index.php?s=upload where "upload" is name of upload.php file. when i create form on that upload.php file and submit it, $_FILES array is empty. echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php\" />\n"; echo "<input type=\"file\" name=\"image\">\n"; echo "<input type=\"hidden\" name=\"s\" value=\"upload\">\n"; echo "<input type=\"submit\" name=\"submit\" value=\"Spremi\">\n"; echo "</form>\n"; i tried everything and nothing works. $_POST items are returned but $_FILES are empty...

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  • Makefile won't copy .o to obj/ and target to bin/ folders

    - by about blank
    I'm trying to write a Makefile which will copy its target and objects to bin/ and obj/ directories, respectively. Yet, when I try to run it I get the following error: nasm -f elf64 -g -F stabs main.asm -l spacelander.lst ld -o spacelander obj/main.o ld: cannot find obj/main.o: No such file or directory make: *** [spacelander] Error 1 Why is this happening? Update I noticed when I posted the error that it was due to white spacing errors. After taking care of those, I still get the new error I replaced with the old one I mentioned prior. What is this?? Update 2 Posted -d flag output below Makefile source. Source ASM := nasm ARGS := -f FMT := elf64 OPT := -g -F stabs SRC := main.asm OBJDIR := obj TARGETDIR := bin OBJ := $(addprefix $(OBJDIR)/,$(patsubst %.asm, %.o, $(wildcard *.asm))) TARGET := spacelander .PHONY: all clean all: $(OBJDIR) $(TARGET) $(OBJDIR): mkdir $(OBJDIR) $(OBJDIR)/%.o: $(SRC) $(ASM) $(ARGS) $(FMT) $(OPT) $(SRC) -l $(TARGET).lst $(TARGET): $(OBJ) ld -o $(TARGET) $(OBJ) clean: @rm -f $(TARGET) $(wildcard *.o) @rm -rf $(OBJDIR) make -d Output - NOTE: output is too many characters for body, thus is pastebinned http://pastebin.com/3bctGJxs

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  • Simple bind not working in IE for Radiobutton in jQuery

    - by Jonathan
    Hi this works fine in Firefox, but not IE. What am I doing wrong? Thanks for the help in advance! $(document).ready(function(){ $("#radiodiv").buttonset(); $('#radio1').bind("click", function() { alert('Hello'); }); } <form> <div id="radiodiv"> <input type="radio" id="radio1" name="radio" checked="checked" /><label for="radio1">WaveHeight</label> <input type="radio" id="radio2" name="radio" /><label for="radio2">Current</label> <input type="radio" id="radio3" name="radio" /><label for="radio3">WaveHeightDir</label> </div> </form>

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  • Why this script is not validating the form

    - by danishjan
    This is registration form code. i wrote script in one i have accessed every element by Id and in One by name but both donot validation it. <div id="form"> <form action="" method="get" id="formdata" > <p> <label for="firstName" class="labels">&nbsp; &nbsp;First Name </label> <input type="text" name="firstName" id="firstName" placeholder="First Name" /> <label for="firstName" id="errorfirstName" style="color:red; font- size:14px; visibility:hidden;"> Please Enter First Name </label> </p> <p> <label for="lastName" class="labels">&nbsp; &nbsp;Last Name </label> <input type="text" name="lastName" id="lastName" placeholder="Last Name" /> <label for="lastName" id="errorlastName" style="color:red; font-size:14px; visibility:hidden;"> Please Enter Last Name</label> </p> <p> <label for="fatherName" class="labels">Father Name</label> <input type="text" name="fatherName" id="fatherName" placeholder="Father Name" /> <label for="fatherName" id="errorfatherName" style="color:red; font- size:14px; visibility:hidden;"> Please Enter Father Name </label> </p> <p> <label for="classNo" class="labels">&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;Class </label> <input type="text" name="classNo" id="classNo" placeholder="Class" /> <label for="classNo" id="errorclassNo" style="color:red; font-size:14px; visibility:hidden;"> Please Enter Class </label> </p> <p> <label for="address" class="labels">&nbsp; &nbsp; &nbsp; &nbsp;Address </label> <input type="text" name="address" id="address" placeholder="Address" /> <label for="address" id="erroraddress" style="color:red; font-size:14px; visibility:hidden;"> Please Enter Address </label> </p> <p> <input type="submit" value="Submit" onSubmit="return validate()" /> </p> </form> And the JavaScript Code is here. What is wrong with this code. This code is through accessing by Element Id. <script type="text\javascript"> function validate(){ var valid=true; var fname=document.getElementById("firstName"); var lname=document.getElementById("lastName"); var fathname=document.getElementById("fatherName"); var classno=document.getElementById("classNo"); var address=document.getElementById("address"); var errfname=document.getElementById("errorfirstName"); var errlname=document.getElementById("errorlastName"); var errfathname=document.getElementById("errorfatherName"); var errclass=document.getElementById("errorclass"); var erraddress=document.getElementById("erroraddress"); if(fname.value == ""){ errfname.style.visibility="visible"; valid=false; } if(lname.value == ""){ errlname.style.visibility="visible"; valid=false; } if(fathname.value == ""){ errfathname.style.visibility="visible"; valid=false; } if(classno.value == ""){ errclass.style.visibility="visible"; valid=false; } if(address.value == ""){ erraddress.style.visibility="visible"; valid=false; } return valid; } </script>

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  • simple question: Difficulty in declaring and using variable

    - by user281180
    What is wrong with the following code: I`m having the error message Error 1 ; expected <%if (Model.ReferenceFields != null) {%> <%int count = 1; %> <%foreach (var referenceName in Model.ReferenceFields) {%> <%var value = "value"; %> <%count++; %> <%value = value + count.ToString(); %> <tr> <td><input type="hidden" name="Tests.Index" value='<%value%>' /></td> <td><input type="text" name="Tests['<%value%>'].Value"/></td> <td><input type="button" value= "Add" /></td></tr> <%} %> <%} %>

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  • Use of 'standalone parentheses'

    - by zaf
    I just answered a question where I advised removing parentheses around a statement and was asked why, to which I had no answer when I realised that it caused no errors/warnings. I could only cite bad practice. But maybe I'm the one missing something... I did my own tests: (print('!')); // Outputs '!' ((print('!!'))); // Outputs '!!' (1); // No output (qwerty); // No output (1==2); // No output (1=2); // Syntax error // etc... Can someone shed some light on whats going on and of what use are 'standalone parentheses'?

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  • Understanding behaviour of read() and write()

    - by neo730
    hi i am a student and just start learning low level c programming.i tried to understand read() and write() methods with this program. #include <unistd.h> #include <stdlib.h> main() { char *st; st=calloc(sizeof(char),2);//allocate memory for 2 char read(0,st,2); write(1,st,2); } i was expecting that it would give segmentation fault when i would try to input more than 2 input characters.but when i execute program and enter " asdf " after giving " as " as output it executes "df" command. i want to know why it doesn't give segmentation fault when we assign more than 2 char to a string of size 2.and why is it executing rest(after 2 char)of input as command instead of giving it as output only? also reading man page of read() i found read() should give EFAULT error,but it doesn't. I am using linux.

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  • Submit form without page reloading

    - by Camran
    I have a classifieds website, and on the page where ads are showed, I am creating a "Send a tip to a friend" form... So anybody who wants can send a tip of the ad to some friends email-adress. I am guessing the form must be submitted to a php page right? <form name='tip' method='post' action='tip.php'> Tip somebody: <input name="tip_email" type="text" size="30" onfocus="tip_div(1);" onblur="tip_div(2);"/> <input type="submit" value="Skicka Tips"/> <input type="hidden" name="ad_id" /> </form> When submitting the form, the page gets reloaded... I don't want that... Is there any way to make it not reload and still send the mail? Preferrably without ajax or jquery... Thanks

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  • jquery problem where the returned data from an XML file seems inaccessible

    - by squeaker
    Hi all, I'm using an xml file to generate some links which i would like to then be able to click on to populate an input box: $(xmlResponse).find('types').each(function(){ var id = $(this).attr('id'); var type = $(this).find('type').text(); $('<span title=\"'+type+'\" class=\"type\">'+type+'</span>').appendTo('#types'); }); $('span.type').click(function() { var title = $(this).attr('title'); $("input[name='type']").val(title); }); But for some reason clicking on the liks does not populate the input box. It does work if the span is hard coded into the page for example: <span title="text to populate" class="type">test</span> I'm guessing that the XML is not getting loaded into the DOM in the right way (or something like that) Any Ideas?

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  • Parent element selection problem?

    - by Starx
    My HTML is something like this <div id="mydiv" class="common"> <input type="text" id="text1" value="" /> <input type="text" id="text2" value="" /> </div> I am assigning a function on the onclick event of the textbox like this $(document).ready(function() { $(".common input").click(function() { //////// What I am trying to do is access the id of its parent // in this case it is "mydiv" alert($(this:parent).attr('id')); }); But it is not working

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  • Adding form inputs in javascript (jquery)

    - by matthewsteiner
    I understand that you do something like: $('form').append('<input type="text" name="color-1" value="Hello" />'); But I have two questions about it. First off, I don't want it added to the end of the form, but after the last input in the "color" section. Secondly, where "name=color-1", I need the one to increment if they want to add more than one input, you know? So that I can process it on the server. Any ideas?

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  • Is there a way to redirect ONLY stderr to stdout (not combine the two) so it can be piped to other programs

    - by James K
    I'm working in a Windows CMD.EXE environment and would like to change the output of stdout to match that of stderr so that I can pipe error messages to other programs without the intermediary of a file. I'm aware of the 2>&1 notation, but that combines stdout and stderr into a single stream. What I'm thinking of would be something like this: program.exe 2>&1 | find " " But that combines stdout and stderr just like: program.exe | find " " 2>&1 I realize that I could do... program 2>file type file | find " " del file But this does not have the flexibility and power of a program | find " " sort of notation. Doing this requires that program has finished with it's output before that output can be processed.

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  • use printf("text %d", number) type format to assign value to variable

    - by rksprst
    I would like to use the syntax that printf uses, using the %d, %s and adding values after to assign a value to a char[]. Is this possible? e.g. Given an output of: printf("now: %d-%d-%d %d:%d:%d\n", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec); I'd like to assign that to char[] output; How can this be done? I tried: sprintf(output, "now: %d-%d-%d %d:%d:%d\n", tm.tm_year + 1900, tm.tm_mon + 1, tm.tm_mday, tm.tm_hour, tm.tm_min, tm.tm_sec); but that didn't seem to work. Is sprintf used differently... or is that not what I should be using? Thanks!

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  • [ruby] How to convert STDIN contents to an array?

    - by miketaylr
    I've got a file INPUT that has the following contents: 123\n 456\n 789 I want to run my script like so: script.rb < INPUT and have it convert the contents of the INPUT file to an array, splitting on the new line character. So, I'd having something like myArray = [123,456,789]. Here's what I've tried to do and am not having much luck: myArray = STDIN.to_s myArray.split(/\n/) puts field.size I'm expecting this to print 3, but I'm getting 15. I'm really confused here. Any pointers?

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