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  • turning text into image - PHP/GD - save image

    - by Phil Jackson
    Hi, I'm using this script to simply create an image from text. What I would like to know is how to save the image instead of printing straight to browser; // an email address in a string $string = $post[$key]; // some variables to set $font = 4; $width = ImageFontWidth($font) * strlen($string); $height = ImageFontHeight($font); // lets begin by creating an image $im = @imagecreatetruecolor ($width,$height); //white background $background_color = imagecolorallocate ($im, 255, 255, 255); //black text $text_color = imagecolorallocate ($im, 0, 0, 0); // put it all together $image = imagestring ($im, $font, 0, 0, $string, $text_color); I know its probably just one line of code at the end but im not sure which GD function to use. Any help would be much appreciated, Regards, Phil.

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  • PHP cURL error: "Empty reply from server"

    - by ABach
    All, I have a class function to interface with the RESTful API for Last.FM - its purpose is to grab the most recent tracks for my user. Here it is: private static $base_url = 'http://ws.audioscrobbler.com/2.0/'; public static function getTopTracks($options = array()) { $options = array_merge(array( 'user' => 'bachya', 'period' => NULL, 'api_key' => 'xxxxx...', // obfuscated, obviously ), $options); $options['method'] = 'user.getTopTracks'; // Initialize cURL request and set parameters $ch = curl_init(); curl_setopt_array($ch, array( CURLOPT_URL => self::$base_url, CURLOPT_POST => TRUE, CURLOPT_POSTFIELDS => $options, CURLOPT_RETURNTRANSFER => TRUE, CURLOPT_TIMEOUT => 30, CURLOPT_USERAGENT => 'Mozilla/4.0 (compatible; MSIE 5.01; Windows NT 5.0)' )); $results = curl_exec($ch); return $results; } This returns "Empty reply from server". I know that some have suggested that this error comes from some fault in network infrastructure; I do not believe this to be true in my case. If I run a cURL request through the command line, I get my data; the Last.FM service is up and accessible. Before I go to those folks and see if anything has changed, I wanted to check with you fine folks and see if there's some issue in my code that would be causing this. Thanks!

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  • Remove the Parent tag in xml using php

    - by Wasim
    I am facing a problem in editing a xml file. <?xml version="1.0" encoding="UTF-8"?> <urlset> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> </urlset> I want to add one more set of records starting with <url> with its other tags, (i.e) "loc,lastmod,changefreq,priority" and than save the xml file.For adding the new record i need to remove the parent closing tag that is </urlset> and than add the rest of the records and close the main tag. Can anyone please help me solving my problem.Thanks

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  • PHP Round function

    - by Steve
    Is it possible to round a number where if it's 5 , just leave it , anything below 5 round down , anything above 5 round up? EX: 5 * 1.35 = 6.75 .... leave it 5.2 * 1.35 = 7.02 .... 7.00 5.5 * 1.35 = 7.56 .... 8.00 I've formatted with round($n,0, PHP_ROUND_HALF_UP) where $n is the product from the above calc , which leaves 6.75 but returns 7.02 for the next one. I also tried round($n,-1, PHP_ROUND_HALF_UP) which gives me the 7.00 on the second calc but then of course won't return a 6.75 for the first, instead it returns 680. This is a ticket markup calculation where the user enters the first number and is multiplied by the second. I actually remove the decimal because they don't want to see it, and they want this sort of customized rounding on the result. Thanks, Steve

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  • How can get autosuggest in cake php

    - by rajesh
    i hav entered my code in controller like below function keyup(){ $this-Note-simple(); if(strlen($searchq)0){ while ($row = mysql_fetch_array($getRecord)) { echo $row['name']; echo $row['department']; } return $row; } } as soon as i entered this one it doesn't display any info .... what correction should require.......

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  • PHP: SimpleXML and Arrays

    - by acemasta
    When I run this code: foreach($xml->movie as $movie) { if(isset($movie->photos)) { foreach ($movie->photos as $photo) { echo $photo."&nbsp;"; } echo "<hr/>"; } } I get nice output of the actual data, e.g. a row looks like 06397001.jpg 06397002.jpg 06397003.jpg 06397004.jpg 06397005.jpg But when I throw it in an array, it includes all the SimpleXML wrapper tags and the jpgs are not at the root of the array. code: foreach($xml->movie as $movie) { if(isset($movie->photos)) { $photos = array(); foreach ($movie->photos as $photo) { $photos[] = $photo; } } else $photos = ""; var_dump($photos); echo "<hr />"; } e.g. same row looks like array(5) { [0]= object(SimpleXMLElement)#11 (1) { [0]= string(12) "06397001.jpg" } [1]= object(SimpleXMLElement)#12 (1) { [0]= string(12) "06397002.jpg" } [2]= object(SimpleXMLElement)#13 (1) { [0]= string(12) "06397003.jpg" } [3]= object(SimpleXMLElement)#14 (1) { [0]= string(12) "06397004.jpg" } [4]= object(SimpleXMLElement)#15 (1) { [0]= string(12) "06397005.jpg" } } Why is this happening/how can I remove this so I just get an array of the photos at root level like when I echo it? Thanks, sorry for the single line code formatting; was messing up when I tried to paste directly with line breaks.

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  • PHP form processing - how to capture text from field that has variable Name/ID

    - by user80151
    I have a form that has a field pulled from the database as a dropdown. I need to get the text selected in the dropdown but I don't know in advance what the field ID will be. This is basically just a form that has already been generated. I don't need to pull anything from the database, it's already on this page. All I need to do is get the form information and email it, no writing to the database. I know how to do the _Request for the other fields based on the ID but I'm not sure how to do this one. The ID changes. It can be ID=1, ID-2, etc. I need to do something like: _REQUEST form element where ID is LIKE "ID[*]" or something similar. Any suggestions or links to tutorials? Here are a couple samples of what the dropdown renders on the page: <div class="wrapperAttribsOptions"> <h4 class="optionName back"><label class="attribsSelect" for="attrib- 1">Model</label></h4> <div class="back"> <select name="id[1]" id="attrib-1"> <option value="45">VC3-4C</option> <option value="1">VC3-4PG</option> <option value="3">VC3-4SG</option> <div class="wrapperAttribsOptions"> <h4 class="optionName back"><label class="attribsSelect" for="attrib-14">SPK Model</label></h4> <div class="back"> <select name="id[14]" id="attrib-14"> <option value="43">SPK-4</option> <option value="44">SPK-8</option> </select> TIA

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  • php extract data from mysql

    - by florin
    I have this mysql table with the following rows: id_cont suma_lun month year -------------------------------------------- FL28 2133 March 2012 FL28 2144 April 2012 FL28 2155 May 2012 FL28 2166 June 2012 How can i extract suma_lun, month and year foreach id_cont? so that i get an output like this: ID: Month: Monthly Sum: Year: ---------------------------------------------- FL28 March 2133 2012 April 2144 2012 May 2155 2012 June 2166 2012 This is my current code: $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) die ('Could not connect to database: '.mysql_error()); mysql_select_db(DB_DATABASE,$link); $sql="SELECT * FROM test WHERE id_cont = '$cur'"; $result=mysql_query($sql); while ($row=mysql_fetch_array($result)) { $a=$row["id_cont"]; $b=$row["suma_lun"]; $c=$row["month"]; $d=$row["year"]; } I echo the data in a table Thanks!

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  • PHP file_get_contents() does not work after uploading to the webserver

    - by Ethan
    Sample code: $html = file_get_contents('http://www.google.com'); echo $html; It works on localhost. But after uploading to the webserver, it gives me a warning: file_get_contents(): php_network_getaddresses: getaddrinfo failed: Temporary failure in name resolution. If I replace the domain name with google's IP address, it gives a warning: failed to open stream: Connection timed out. And ini_get("allow_url_fopen") return 1.

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  • problem creating jpg thumb with php

    - by Ross
    Hi, I am having problems creating a thumbnail from an uploaded image, my problem is (i) the quality (ii) the crop http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/large.jpg http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/thumb.jpg If you look the quality is very poor and the crop is taken from the top and is not a resize of the original image although the dimesions mean it is in proportion. The original is 1600px wide by 1100px high. Any help would be appreciated. $thumb = $targetPath."Thumbs/".$fileName; $imgsize = getimagesize($targetFile); $image = imagecreatefromjpeg($targetFile); $width = 200; //New width of image $height = 138; //This maintains proportions $src_w = $imgsize[0]; $src_h = $imgsize[1]; $thumbWidth = 200; $thumbHeight = 138; // Intended dimension of thumb // Beyond this point is simply code. $sourceImage = imagecreatefromjpeg($targetFile); $sourceWidth = imagesx($sourceImage); $sourceHeight = imagesy($sourceImage); $targetImage = imagecreate($thumbWidth,$thumbHeight); imagecopyresized($targetImage,$sourceImage,0,0,0,0,$thumbWidth,$thumbWidth,imagesx($sourceImage),imagesy($sourceImage)); //imagejpeg($targetImage, "$thumbPath/$thumbName"); imagejpeg($targetImage, $thumb); chmod($thumb, 0755);

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  • php / mysql - select id from one table excepting ids which are in second table

    - by John
    hello. for example i have 2 tables: 1 . users: id Name 1 Mike 2 Adam 3 Tom 4 John 5 Andy 6 Ray 2 . visits: userID date 1 ... 3 ... 6 ... i want to make a page which can be visited once in 12 hours, when user visits that page his id is included in database ( visits ), how i can select all users ( from database users) excepting users who visited page in <= 12 hours ( users from database visits )?

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  • PHP: saving multiple tuples to the same table

    - by Binaryrespawn
    Hi all, I am trying to save data into the same table several times from the same $_POST array. You see, on my registration form a family is allowed to specify the names, gender and age of all members they wish to bring along. This data is being stored in a database table called aditional_member. Based on family size, I am dynamically generating html table rows where each row has the number of input fields required. <tr id="additionalmember_3"> <td><input type="text" name="first_name1" maxlength="50" value="" /></td> <td><input type="text" name="last_name1" maxlength="50" value="" /></td> td><select name="gender1" value="" ><option value='Male'>Male</option><option value='Female'>Female</option></select></td> <td><select name="age_group"value="" ><option value='18 to 30'>18 to 30</option><option value='31 to 60'>31 to 60</option></select></td> </tr> When I POST, let us say I have three sets of input(3 table rows as above), Is there a simple way to insert into the addional_member table the data from row one, then row two, and so on. I tried looping the insert statement, which failed. I am basically open to suggestions, I do not need to use a table. Any ideas, Thank you.

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  • PHP MVC correct usage

    - by Ratt
    What is the correct (recommended method) for passing information to a view in a MVC environment. Currently we use Zend Framework, where we write classes to handle specific things EG a Book class with a save and load method to retrieve info from the DB, which is called from a particular nameAction(). What I would like to know is what is the best way to pass this information to the view, in some cases we do $this-view-book_name = $book-getBookName(); and in other cases we do the following $this-view-book = $book; OR $this-view-books = Book_Manager::getAllBooks(); and then access the object(s) properties in the view. Information on-line suggests we try limit what access a view has to information, i.e pass them only what they need and in some cases people say its ok to pass stuff through as long as nothing is done to that information. Regards

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  • How to pass array element one by one in text box in php

    - by trainee
    i am Reading the file contents and passed it in explod function("=",$string) ,it gives me two array parts[0].parts[1] seprated by = .parts[1] array displays all the values of the variable .now how can i use these values one by one to pass in the text box .The variable value comes in this way (value1 value2 value3 value4...) my code also throws the undefined offset :1 notice when i prints the parts[1]arrray

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  • Validating Login / Changing User settings / Php Mysql

    - by Marcelo
    Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

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  • PHP XML encoding

    - by Jeremey
    I need a function that will convert € or chr(0x20AC) or chr(8364) to € without having a static map. I tried using htmlentities(), but it only seems to work for the symbol itself and it converts to €

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  • php regex replace slashes and spaces and hyphens

    - by Muhammad Shahzad
    I have fews combinations of strings that I need to bring in to one pattern, that is multiple spaces should be removed, double hyphens should be replaced with single hypen, and single space should be replaced with single hyphen. I have already tried this expression. $output = preg_replace( "/[^[:space:]a-z0-9]/e", "", $output ); $output = trim( $output ); $output = preg_replace( '/\s+/', '-', $output ); But this fails in few combinations. I need help in making all of these combinations to work perfectly: steel-black steel- black steel black I should also remove any of these as well "\r\n\t".

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  • count and fetch rows in php

    - by Mac Taylor
    hey guys i have a table in my mysql database named (names) now everyone can save their real names now i want to query this table and find out how many times these names used forexample the output should be : Jakob (20) Jenny (17) now this is my own code : list($usernames) =mysql_fetch_row(mysql_query('SELECT name FROM table_user GROUP BY name ORDER BY COUNT(name) DESC LIMIT 50 ')); list($c) =mysql_num_rows(mysql_query('SELECT COUNT(name) FROM table_user GROUP BY name ')); print $usernames.'('.$c.')' is this a correct approach ?!

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  • php function to make slug (url string)

    - by andufo
    function gen_slug($str){ # special accents $a = array('À','Á','Â','Ã','Ä','Å','Æ','Ç','È','É','Ê','Ë','Ì','Í','Î','Ï','Ð','Ñ','Ò','Ó','Ô','Õ','Ö','Ø','Ù','Ú','Û','Ü','Ý','ß','à','á','â','ã','ä','å','æ','ç','è','é','ê','ë','ì','í','î','ï','ñ','ò','ó','ô','õ','ö','ø','ù','ú','û','ü','ý','ÿ','A','a','A','a','A','a','C','c','C','c','C','c','C','c','D','d','Ð','d','E','e','E','e','E','e','E','e','E','e','G','g','G','g','G','g','G','g','H','h','H','h','I','i','I','i','I','i','I','i','I','i','?','?','J','j','K','k','L','l','L','l','L','l','?','?','L','l','N','n','N','n','N','n','?','O','o','O','o','O','o','Œ','œ','R','r','R','r','R','r','S','s','S','s','S','s','Š','š','T','t','T','t','T','t','U','u','U','u','U','u','U','u','U','u','U','u','W','w','Y','y','Ÿ','Z','z','Z','z','Ž','ž','?','ƒ','O','o','U','u','A','a','I','i','O','o','U','u','U','u','U','u','U','u','U','u','?','?','?','?','?','?'); $b = array('A','A','A','A','A','A','AE','C','E','E','E','E','I','I','I','I','D','N','O','O','O','O','O','O','U','U','U','U','Y','s','a','a','a','a','a','a','ae','c','e','e','e','e','i','i','i','i','n','o','o','o','o','o','o','u','u','u','u','y','y','A','a','A','a','A','a','C','c','C','c','C','c','C','c','D','d','D','d','E','e','E','e','E','e','E','e','E','e','G','g','G','g','G','g','G','g','H','h','H','h','I','i','I','i','I','i','I','i','I','i','IJ','ij','J','j','K','k','L','l','L','l','L','l','L','l','l','l','N','n','N','n','N','n','n','O','o','O','o','O','o','OE','oe','R','r','R','r','R','r','S','s','S','s','S','s','S','s','T','t','T','t','T','t','U','u','U','u','U','u','U','u','U','u','U','u','W','w','Y','y','Y','Z','z','Z','z','Z','z','s','f','O','o','U','u','A','a','I','i','O','o','U','u','U','u','U','u','U','u','U','u','A','a','AE','ae','O','o'); return strtolower(preg_replace(array('/[^a-zA-Z0-9 -]/','/[ -]+/','/^-|-$/'),array('','-',''),str_replace($a,$b,$str))); } Works great, but i've found some cases in which it fails: echo gen_slug('andrés'); returns andras instead of andres why? any ideas on the preg_replace parameters?

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  • How to get parameter after "/" in URL in PHP

    - by Lucifer
    I need to let my users type anything at the end of my url, like this: http://mysite.com/?somethingorother or http://mysite.com/somethingorother And then I would like to get that last bit that they added to the end of the url like so: $var = $_POST['']; But I'm not sure how to go about this, and I can't find anything, because I'm not quite sure how to search for it. Any help is appreciated, thanks!

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  • Display Yearly Report When Data Not Available (CI, PHP, MySQL)

    - by tegaralaga
    First of all, i do apologize for my bad english, cos english isn't my native language. I want to display yearly report based on month, let say i got order on January, August, December, but the rest there's no order. So in MySQL database only have 3 order (Jan,Aug,Dec). When i query use CI ( select month(order_date) as month_name , count(order_id) as amount from order where year(order_date)=2011 group by month(order_date) ) there's only 3 data let say the 3 data is (use $query-result_array()) Array ( [0] => Array ( [month_num] => 1 [amount] => 4 ) [1] => Array ( [month_num] => 8 [amount] => 1 ) [2] => Array ( [month_num] => 12 [amount] => 19 ) ) how to make it to 12 data (12 Month) the array become like this (when data not available the amount is 0) Array ( [0] => Array ( [month_num] => 1 [amount] => 4 ) [1] => Array ( [month_num] => 2 [amount] => 0 ) [2] => Array ( [month_num] => 3 [amount] => 0 ) etc ) Thanks in advance :)

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  • PHP/MYSQL Trouble Selecting by Primary Key

    - by djs22
    Hi all, So I have a primary key column called key. I'm trying to select the row with key = 1 via this code: $query ="SELECT * FROM Bowlers WHERE key = '1'"; $result = mysql_query($query) or die(mysql_error()); For some reason, I'm getting this result: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key = '1'' at line 1 The mysql statement works for using other keys, ie WHERE name = 'djs22'. Any ideas?

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  • PHP + MySQL - Match first letter of directory

    - by user1822825
    Let's say I have a class table. In the class table, there are many students with their pictures. In the first registration, I've registered the class and students with pictures. The pictures were put into a directory like classid_classname. Then, I change the class name. Now, I'm adding the student's picture. Now, the new picture can't be recognized because the class name has changed. The pic url will be set as classid_class(new)name. How can I match the first letter of the directory? This is my update code : $classID= $_POST["classID"]; $className= $_POST["className"]; $p1 = $_FILES['p1']['name']; $p2 = $_FILES['p2']['name']; $p3 = $_FILES['p3']['name']; $direct = $_POST["className"]; $direct = strtolower($direct); $direct = str_replace(' ', '_', $direct); $tfish = $classID."_".$direct; //the directory variable will have new name because it can't be fetched if the directory has been changed many times// $file = "slider_imagesClass/".$tfish."/"; $url = "/".$tfish."/"; How can I make the variable to match the first letter of the directory because the classID will not change? Thank you. Really appreciate your help :D

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