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  • PHP: saving multiple tuples to the same table

    - by Binaryrespawn
    Hi all, I am trying to save data into the same table several times from the same $_POST array. You see, on my registration form a family is allowed to specify the names, gender and age of all members they wish to bring along. This data is being stored in a database table called aditional_member. Based on family size, I am dynamically generating html table rows where each row has the number of input fields required. <tr id="additionalmember_3"> <td><input type="text" name="first_name1" maxlength="50" value="" /></td> <td><input type="text" name="last_name1" maxlength="50" value="" /></td> td><select name="gender1" value="" ><option value='Male'>Male</option><option value='Female'>Female</option></select></td> <td><select name="age_group"value="" ><option value='18 to 30'>18 to 30</option><option value='31 to 60'>31 to 60</option></select></td> </tr> When I POST, let us say I have three sets of input(3 table rows as above), Is there a simple way to insert into the addional_member table the data from row one, then row two, and so on. I tried looping the insert statement, which failed. I am basically open to suggestions, I do not need to use a table. Any ideas, Thank you.

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  • PHP file_get_contents() does not work after uploading to the webserver

    - by Ethan
    Sample code: $html = file_get_contents('http://www.google.com'); echo $html; It works on localhost. But after uploading to the webserver, it gives me a warning: file_get_contents(): php_network_getaddresses: getaddrinfo failed: Temporary failure in name resolution. If I replace the domain name with google's IP address, it gives a warning: failed to open stream: Connection timed out. And ini_get("allow_url_fopen") return 1.

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  • php extract data from mysql

    - by florin
    I have this mysql table with the following rows: id_cont suma_lun month year -------------------------------------------- FL28 2133 March 2012 FL28 2144 April 2012 FL28 2155 May 2012 FL28 2166 June 2012 How can i extract suma_lun, month and year foreach id_cont? so that i get an output like this: ID: Month: Monthly Sum: Year: ---------------------------------------------- FL28 March 2133 2012 April 2144 2012 May 2155 2012 June 2166 2012 This is my current code: $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) die ('Could not connect to database: '.mysql_error()); mysql_select_db(DB_DATABASE,$link); $sql="SELECT * FROM test WHERE id_cont = '$cur'"; $result=mysql_query($sql); while ($row=mysql_fetch_array($result)) { $a=$row["id_cont"]; $b=$row["suma_lun"]; $c=$row["month"]; $d=$row["year"]; } I echo the data in a table Thanks!

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  • php function to make slug (url string)

    - by andufo
    function gen_slug($str){ # special accents $a = array('À','Á','Â','Ã','Ä','Å','Æ','Ç','È','É','Ê','Ë','Ì','Í','Î','Ï','Ð','Ñ','Ò','Ó','Ô','Õ','Ö','Ø','Ù','Ú','Û','Ü','Ý','ß','à','á','â','ã','ä','å','æ','ç','è','é','ê','ë','ì','í','î','ï','ñ','ò','ó','ô','õ','ö','ø','ù','ú','û','ü','ý','ÿ','A','a','A','a','A','a','C','c','C','c','C','c','C','c','D','d','Ð','d','E','e','E','e','E','e','E','e','E','e','G','g','G','g','G','g','G','g','H','h','H','h','I','i','I','i','I','i','I','i','I','i','?','?','J','j','K','k','L','l','L','l','L','l','?','?','L','l','N','n','N','n','N','n','?','O','o','O','o','O','o','Œ','œ','R','r','R','r','R','r','S','s','S','s','S','s','Š','š','T','t','T','t','T','t','U','u','U','u','U','u','U','u','U','u','U','u','W','w','Y','y','Ÿ','Z','z','Z','z','Ž','ž','?','ƒ','O','o','U','u','A','a','I','i','O','o','U','u','U','u','U','u','U','u','U','u','?','?','?','?','?','?'); $b = array('A','A','A','A','A','A','AE','C','E','E','E','E','I','I','I','I','D','N','O','O','O','O','O','O','U','U','U','U','Y','s','a','a','a','a','a','a','ae','c','e','e','e','e','i','i','i','i','n','o','o','o','o','o','o','u','u','u','u','y','y','A','a','A','a','A','a','C','c','C','c','C','c','C','c','D','d','D','d','E','e','E','e','E','e','E','e','E','e','G','g','G','g','G','g','G','g','H','h','H','h','I','i','I','i','I','i','I','i','I','i','IJ','ij','J','j','K','k','L','l','L','l','L','l','L','l','l','l','N','n','N','n','N','n','n','O','o','O','o','O','o','OE','oe','R','r','R','r','R','r','S','s','S','s','S','s','S','s','T','t','T','t','T','t','U','u','U','u','U','u','U','u','U','u','U','u','W','w','Y','y','Y','Z','z','Z','z','Z','z','s','f','O','o','U','u','A','a','I','i','O','o','U','u','U','u','U','u','U','u','U','u','A','a','AE','ae','O','o'); return strtolower(preg_replace(array('/[^a-zA-Z0-9 -]/','/[ -]+/','/^-|-$/'),array('','-',''),str_replace($a,$b,$str))); } Works great, but i've found some cases in which it fails: echo gen_slug('andrés'); returns andras instead of andres why? any ideas on the preg_replace parameters?

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  • How to get parameter after "/" in URL in PHP

    - by Lucifer
    I need to let my users type anything at the end of my url, like this: http://mysite.com/?somethingorother or http://mysite.com/somethingorother And then I would like to get that last bit that they added to the end of the url like so: $var = $_POST['']; But I'm not sure how to go about this, and I can't find anything, because I'm not quite sure how to search for it. Any help is appreciated, thanks!

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  • PHP XML encoding

    - by Jeremey
    I need a function that will convert € or chr(0x20AC) or chr(8364) to € without having a static map. I tried using htmlentities(), but it only seems to work for the symbol itself and it converts to €

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  • Declaring variable as PHP class

    - by iamdadude
    I have a variable called $theclass and it's a string "Home_class". How can I define a class out of that string? The reason I need to do this is that the variable will change and I want to be able to declare the class that the variable is equal to. Is this possible? Thanks for any help.

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  • PHP & MySQL Image deletion problem?

    - by IMAGE
    I have this script that deletes a users avatar image that is stored in a folder name thumbs and another named images and the image name is stored in a mysql database. But for some reason the script deletes all the users info for example if the users id is 3 all of the users info like first name last name age and so are deleted as well, basically everything is deleted including the user how do I fix this so only the images and image name is deleted? Here is the code. $user_id = '3'; if (isset($_POST['delete_image'])) { $a = "SELECT * FROM users WHERE avatar = '". $avatar ."' AND user_id = '". $user_id ."'"; $r = mysqli_query ($mysqli, $a) or trigger_error("Query: $a\n<br />MySQL Error: " . mysqli_error($mysqli)); if ($r == TRUE) { unlink("../members/" . $user_id . "/images/" . $avatar); unlink("../members/" . $user_id . "/images/thumbs/" . $avatar); $a = "DELETE FROM users WHERE avatar = '". $avatar ."' AND user_id = '". $user_id ."'"; $r = mysqli_query ($mysqli, $a) or trigger_error("Query: $a\n<br />MySQL Error: " . mysqli_error($mysqli)); } }

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  • Display Yearly Report When Data Not Available (CI, PHP, MySQL)

    - by tegaralaga
    First of all, i do apologize for my bad english, cos english isn't my native language. I want to display yearly report based on month, let say i got order on January, August, December, but the rest there's no order. So in MySQL database only have 3 order (Jan,Aug,Dec). When i query use CI ( select month(order_date) as month_name , count(order_id) as amount from order where year(order_date)=2011 group by month(order_date) ) there's only 3 data let say the 3 data is (use $query-result_array()) Array ( [0] => Array ( [month_num] => 1 [amount] => 4 ) [1] => Array ( [month_num] => 8 [amount] => 1 ) [2] => Array ( [month_num] => 12 [amount] => 19 ) ) how to make it to 12 data (12 Month) the array become like this (when data not available the amount is 0) Array ( [0] => Array ( [month_num] => 1 [amount] => 4 ) [1] => Array ( [month_num] => 2 [amount] => 0 ) [2] => Array ( [month_num] => 3 [amount] => 0 ) etc ) Thanks in advance :)

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  • count and fetch rows in php

    - by Mac Taylor
    hey guys i have a table in my mysql database named (names) now everyone can save their real names now i want to query this table and find out how many times these names used forexample the output should be : Jakob (20) Jenny (17) now this is my own code : list($usernames) =mysql_fetch_row(mysql_query('SELECT name FROM table_user GROUP BY name ORDER BY COUNT(name) DESC LIMIT 50 ')); list($c) =mysql_num_rows(mysql_query('SELECT COUNT(name) FROM table_user GROUP BY name ')); print $usernames.'('.$c.')' is this a correct approach ?!

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  • php regex replace slashes and spaces and hyphens

    - by Muhammad Shahzad
    I have fews combinations of strings that I need to bring in to one pattern, that is multiple spaces should be removed, double hyphens should be replaced with single hypen, and single space should be replaced with single hyphen. I have already tried this expression. $output = preg_replace( "/[^[:space:]a-z0-9]/e", "", $output ); $output = trim( $output ); $output = preg_replace( '/\s+/', '-', $output ); But this fails in few combinations. I need help in making all of these combinations to work perfectly: steel-black steel- black steel black I should also remove any of these as well "\r\n\t".

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  • Validating Login / Changing User settings / Php Mysql

    - by Marcelo
    Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

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  • Apply PHP regex replace on a multi-line repeated pattern

    - by Hussain
    Let's say I have this input: I can haz a listz0rs! # 42 # 126 I can haz another list plox? # Hello, world! # Welcome! I want to split it so that each set of hash-started lines becomes a list: I can haz a listz0rs! <ul> <li>42</li> <li>126</li> </ul> I can haz another list plox? <ul> <li>Hello, world!</li> <li>Welcome!</li> </ul> If I run the input against the regex "/(?:(?:(?<=^# )(.*)$)+)/m", I get the following result: Array ( [0] => Array ( [0] => 42 ) [1] => Array ( [0] => 126 ) [2] => Array ( [0] => Hello, world! ) [3] => Array ( [0] => Welcome! ) ) This is fine and dandy, but it doesn't distinguish between the two different lists. I need a way to either make the quantifier return a concatenated string of all the occurrences, or, ideally, an array of all the occurrences. Ideally, this should be my output: Array ( [0] => Array ( [0] => 42 [1] => 126 ) [1] => Array ( [0] => Hello, world! [1] => Welcome! ) ) Is there any way of achieving this, and if not, is there a close alternative? Thanks in advance!

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  • PHP, MySQL prepared statements - can you use results of execute more than once by calling data_seek(

    - by Carvell Fenton
    Hello, I have a case where I want to use the results of a prepared statement more than once in a nested loop. The outer loop processes the results of another query, and the inner loop is the results of the prepared statement query. So the code would be something like this (just "pseudoish" to demonstrate the concept): // not showing the outer query, it is just a basic SELECT, not prepared statement // we'll call it $outer_query $obj_array = array(); // going to save objects in this $ids = array(18,19,20); // just example id numbers $query = "SELECT field1, field2 FROM table1 WHERE id=?"; $stmt = $db->prepare($query); foreach ($ids as $id) { $stmt->bind_param("i", $id); $stmt->execute(); $stmt->bind_result($var1, $var2); $stmt->store_result(); // I think I need this for data_seek while ($q1 = $outer_query->fetch_object()) { while ($stmt->fetch()) { if ($q1->field1 == $var1) { // looking for a match $obj = new stdClass(); $obj->var1 = $var1; $obj->var2 = $var2; $obj_array[] = $obj; $stmt->data_seek(0); // reset for outer loop break; // found match, so leave inner } } } } The problem I seem to be experiencing is that the values are not getting bound in the variables as I would expect after the first time I use fetch in the inner loop. Specifically, in one example I ran with 3 ids for the foreach, the first id was processed correctly, the second was processed incorrectly (matches were not found in the inner loop even though they existed), and then the third was processed correctly. Is there something wrong with the prepared statment function calls in the sequence I am doing above, or is this an invalid way to use the results of the prepared statement? Thanks.

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  • PHP/MYSQL Trouble Selecting by Primary Key

    - by djs22
    Hi all, So I have a primary key column called key. I'm trying to select the row with key = 1 via this code: $query ="SELECT * FROM Bowlers WHERE key = '1'"; $result = mysql_query($query) or die(mysql_error()); For some reason, I'm getting this result: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'key = '1'' at line 1 The mysql statement works for using other keys, ie WHERE name = 'djs22'. Any ideas?

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  • PHP weirdness extending IMagick class

    - by Jamie Carl
    This is a really weird one. I have some code that is happily working on version 2.1.1RC1 of the php5-imagick module. It's basically just a class I wrote that extends the Imagick class and manages images stored in a database. Since upgrading to version 3.0.0RC1 (thankfully only on my dev box) things have gone to hell. It seems that object members are writeable but are NOT readable. Take the following sample code: class db_image extends IMagick { private $data; function __construct( $id = null ){ parent::__construct(); $this->data = 'some plain text'; echo $this->data; } This will output absolutely NOTHING. My debugger indicates that the contents of $this-data are the correct string value, but I am unable to read the value back out of the member variable. Seriously. WTF? Does anyone know what is causing this or has seen it before? I don't even know how to replicate this behaviour in my own classes.

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  • How to merge objects in php ?

    - by The Devil
    Hey everybody, I'm currently re-writing a class which handles xml files. Depending on the xml file and it's structure I sometimes need to merge objects. Lets say once I have this: <page name="a title"/> And another time I have this: <page name="a title"> <permission>administrator</permission> </page> Before, I needed only the attributes from the "page" element. That's why a lot of my code expects an object containing only the attributes ($loadedXml-attributes()). Now there are xml files in which the <permission> element is required. I did manage to merge the objects (though not as I wanted) but I can't get to access one of them (most probably it's something I'm missing). To merge my objects I used this code: (object) array_merge( (array) $loadedXml->attributes(), (array) $loadedXml->children() ); This is what I get from print_r(): stdClass Object ( [@attributes] => Array ( [name] => a title ) [permission] => Array ( [0] => administrator ) ) So now my question is how to access the @attributes method ? Thanks in advance, The Devil

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  • PHP + MySQL - Match first letter of directory

    - by user1822825
    Let's say I have a class table. In the class table, there are many students with their pictures. In the first registration, I've registered the class and students with pictures. The pictures were put into a directory like classid_classname. Then, I change the class name. Now, I'm adding the student's picture. Now, the new picture can't be recognized because the class name has changed. The pic url will be set as classid_class(new)name. How can I match the first letter of the directory? This is my update code : $classID= $_POST["classID"]; $className= $_POST["className"]; $p1 = $_FILES['p1']['name']; $p2 = $_FILES['p2']['name']; $p3 = $_FILES['p3']['name']; $direct = $_POST["className"]; $direct = strtolower($direct); $direct = str_replace(' ', '_', $direct); $tfish = $classID."_".$direct; //the directory variable will have new name because it can't be fetched if the directory has been changed many times// $file = "slider_imagesClass/".$tfish."/"; $url = "/".$tfish."/"; How can I make the variable to match the first letter of the directory because the classID will not change? Thank you. Really appreciate your help :D

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  • Errors checking and opening a URL using PHP

    - by Jean
    Hello Here is one script with out any errors $url="http://yahoo.com"; $file1 = fopen($url, "r"); $content = file_get_contents($url); $t_beg = explode('<title>',$content); $t_end = explode('</title>',$t_beg[1]); echo $t_end[0]; And here is the same script using a look to check multiple urls and getting errors for ($j=1;$j<=$i;$j++) { if ($x[$j]!=''){ $t_u = "http:".$x[$j]; $file2 = fopen($t_u, "r"); $content2 = file_get_contents($t_u); $t_beg = explode('<title>',$content); $t_end = explode('</title>',$t_beg[1]); echo $t_end[0]; } } The error is Warning: fopen() [function.fopen]: php_network_getaddresses: getaddrinfo failed: No such host is known. in g:/ What exactly is wrong here?

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  • PHP mysql_fetch_array

    - by rag
    $n=mysql_num_rows($rs); $i=0; while($n>0) { while(($row=mysql_fetch_array($rs))&&$i<=5) { echo $row['room_name']; $i=$i+1; //echo $n."<br>"; } echo "<br>"; //echo "n1=".$n; $n=$n-5; // $i=0; } Output:101102103104105106 108109110 The row for roomname 107 is missing.... anybody please tell me what is the problem while reentering the loop again...

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  • Math - Adding with PHP

    - by Wayne
    Basically I can't get it right. I need something like this: if($p == 1) { $start = 0; $limit = 16; } The numbers must add on depending on the value of the $p, e.g. if $p is 5 then the values of $start and $limit would be: if($p == 5) { $start = 64; $limit = 80; } The math is to add 16, depending on the value of $p. Thanks.

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  • How to code a 'Next in Results' within search results in PHP

    - by thebluefox
    Right, bit of a head scratcher, although I've got a feeling there's an obvious answer and I'm just not seeing the wood for the trees. Baiscally, using Solr as a search engine for my site, bringing back 15 results per page. When you click on a result, you get a detail page, that has a "Next in Results" link on it, which obviously forwards you on to the next result. Whats the best way of doing this? I've come up with a few solutions but they're either too inpractical or just don't work. I could store all the ids in a session array, then grab the one after the current one and put that in the link. But with possibly hundreds/thousands of results, the memory that array would need, and the performance hit of dealing with it isn't practical. I could take the same approach and put it into the db, but I'll still have to deal with a potentially huge array when I grab them out of the db. Or; I could do the search again, only returning the id's, and grab the one after the one we're currently looking at. I think this could be the best option? Although it does seem kind of messy, namely because of when I have to select the id thats on a different 'page' (ie the 16th, 31st etc result). Unless I pass through where it was in the results, and select from there, but that still doesn't seem like the right way to do it. I'm really sorry if this is just complete nonsense, any help is massively appreciated as always, Cheers guys!

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  • (PHP) Converting an array of arrays from one format into another

    - by Richard Carter
    Hi, I currently have an array, created from a database, an example of which looks like the following: Array( [0] => Array ( objectid => 2, name => title, value => apple ), [1] => Array ( objectid => 2, name => colour, value => red ), [2] => Array ( objectid => 3, name => title, value => pear ), [3] => Array ( objectid => 3, name => colour, value => green ) ) What I would like to do is group all the items in the array by their objectid, and convert the 'name' values into keys and 'value' values into values of an associative array....like below: Array ( [0] => Array ( objectid => 2, title => apple, colour => red ), [1] => Array ( objectid => 3, title => pear, colour => green ) ) I've tried a few things but haven't really got anywhere.. Any ideas? Thanks in advance

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