Search Results

Search found 31719 results on 1269 pages for 'php apc'.

Page 293/1269 | < Previous Page | 289 290 291 292 293 294 295 296 297 298 299 300  | Next Page >

  • function and class to show image not working in php

    - by Gully
    i am trying to get get the following working nothing is happen when i use the function i am trying to get it to display images class ItemRes { //items DB var $img=""; } function ShowItemImage($index,$res_a){ if(sizeof($res_a) > $index){ if($res_a[$index] != NULL) { $cimg = $res_a[$index]->img; return "<img src='$cimg' width='70' height='70' style='cursor:pointer'></img>"; } }else{ return "<center class='whitetxt'><strong>Empty</strong></center>"; } } $res_array = array(); $idx=0; $result21 = mysql_query("SELECT * FROM photos WHERE eid='$eid' ORDER BY id DESC") or die (mysql_error()); while ($row21 = mysql_fetch_array($result21)) { $img_path = $row21['path']; $obj = new ItemRes(); $obj->img = $img_path; $res_array[$idx] = $obj; $idx++; } ShowItemImage(0,$res_array) ShowItemImage(1,$res_array)

    Read the article

  • Reading large excel file with PHP

    - by Itamar Bar-Lev
    I'm trying to read a 17MB excel file (2003) with PHPExcel1.7.3c, but it crushes already while loading the file, after exceeding the 120 seconds limit I have. Is there another library that can do it more efficiently? I have no need in styling, I only need it to support UTF8. Thanks for your help

    Read the article

  • PHP - stop calling on refresh

    - by Ross
    I need my class to create a new blank record when the page opens up the problem I am having is when the page refreshes it keeps incrementing by 1, if I write a session to keep the variable the next time I go back it does not increment. Any ideas? if(!isset($_POST['record_no'])) { echo $_POST['record_no'] = $projects->insert__blank_project(); } else { print "already Set"; }

    Read the article

  • php regex - can't find the error

    - by peirix
    Just one simple, specific question: I've got the string {var1}12345{var2}, and I want to get the variable names used. if (preg_match("/{([a-zA-Z0-9]*)}/g", $url, $matches)) { print_r($matches); } If I remove the global flag, it works, but I only get the first variable, as expected. Why isn't it working with a global flag? It works when I'm testing it with the Regex Tester

    Read the article

  • PHP - Get dates of next 5 weekdays?

    - by Dan
    I'm trying to create an array of the next 5 working week days (Monday - Friday, excluding today). I know the working week varies around the world but this is not important for what I am trying to do. So, for example, if today is a Wednesday, I want the dates for Thursday and Friday of the current week and Monday, Tuesday and Wednesday of the following week. I thought this would work: $dates = array(); for ($i = 1; $ < 6; $i ++) { $dates[] = date('Y-m-d', strtotime('+ '.$i.' weekday')); } But for today, it is giving me: Monday 1st Tuesday 2nd Wednesday 3rd Thursday 4th Sunday 7th! Any advice appreciated. Thanks

    Read the article

  • php domDocument variables

    - by geoffs3310
    Hi, I have the following code at the moment: $ip = '195.72.186.157'; $xmlDoc = new DOMDocument(); $xmlDoc->loadXML(file_get_contents('http://www.geoffmeierhans.com/services/geo-locator/locate/?ip='.$ip.'&output=xml')); foreach($xmlDoc->getElementsByTagName('city') as $link) { $links = array('text' => $link->nodeValue); } $city = $links['text']; echo $city; Is there a better way to get the city variable? Since there is only one tag called city a loop isn't really needed but I can't get it to work any other way

    Read the article

  • Php wrapper class for XML

    - by gms8994
    I'm working on a new class to wrap XML handling. I want my class to use simplexml if it's installed, and the built in XML functions if it's not. Can anyone give me some suggestions on a skeleton class to do this? It seems "wrong" to litter each method with a bunch of if statements, and that also seems like it would make it nearly impossible to correctly test. Any upfront suggestions would be great! EDIT: I'm talking about these built-in xml functions.

    Read the article

  • PHP form processing - how to capture text from field that has variable Name/ID

    - by user80151
    I have a form that has a field pulled from the database as a dropdown. I need to get the text selected in the dropdown but I don't know in advance what the field ID will be. This is basically just a form that has already been generated. I don't need to pull anything from the database, it's already on this page. All I need to do is get the form information and email it, no writing to the database. I know how to do the _Request for the other fields based on the ID but I'm not sure how to do this one. The ID changes. It can be ID=1, ID-2, etc. I need to do something like: _REQUEST form element where ID is LIKE "ID[*]" or something similar. Any suggestions or links to tutorials? Here are a couple samples of what the dropdown renders on the page: <div class="wrapperAttribsOptions"> <h4 class="optionName back"><label class="attribsSelect" for="attrib- 1">Model</label></h4> <div class="back"> <select name="id[1]" id="attrib-1"> <option value="45">VC3-4C</option> <option value="1">VC3-4PG</option> <option value="3">VC3-4SG</option> <div class="wrapperAttribsOptions"> <h4 class="optionName back"><label class="attribsSelect" for="attrib-14">SPK Model</label></h4> <div class="back"> <select name="id[14]" id="attrib-14"> <option value="43">SPK-4</option> <option value="44">SPK-8</option> </select> TIA

    Read the article

  • How to pass array element one by one in text box in php

    - by trainee
    i am Reading the file contents and passed it in explod function("=",$string) ,it gives me two array parts[0].parts[1] seprated by = .parts[1] array displays all the values of the variable .now how can i use these values one by one to pass in the text box .The variable value comes in this way (value1 value2 value3 value4...) my code also throws the undefined offset :1 notice when i prints the parts[1]arrray

    Read the article

  • drop down box php

    - by DAFFODIL
    I have stored 6 records in mysql db,when i use this code each of the 6 records getting displayed in seprate drop down box,i want them to be displayed in a single drop down box.Where am i going wrong? Any help ii be appreciated. Thnx in advance. http://dpaste.com/hold/180077/

    Read the article

  • [PHP] Kohana-v3 ORM parent relationship

    - by VDVLeon
    Hi all, I just started with the version 3 of the Kohana Framework. I have worked a little with the $_has_many etc. Now I have the table pages. The primary key is pageID. The table has a column called parentPageID. Now I want to make a ORM model who, when accesed like this $page->parent->find() returns the page identified by parentPageID. I have the following already: // Settings protected $_table_name = 'pages'; protected $_primary_key = 'pageID'; protected $_has_one = array( 'parent' => array( 'model' => 'page', 'foreign_key' => 'parentPageID', ), ); But that does not work, it simply returns the first page from the table. Last query says this: SELECT `pages`.* FROM `pages` ORDER BY `pages`.`pageID` ASC LIMIT 1 Does somebody know how to solve this? I know this can: $parent = $page->parent->find($page->parentPageID); but it must be and can be cleaner (I think).

    Read the article

  • Errors checking and opening a URL using PHP

    - by Jean
    Hello Here is one script with out any errors $url="http://yahoo.com"; $file1 = fopen($url, "r"); $content = file_get_contents($url); $t_beg = explode('<title>',$content); $t_end = explode('</title>',$t_beg[1]); echo $t_end[0]; And here is the same script using a look to check multiple urls and getting errors for ($j=1;$j<=$i;$j++) { if ($x[$j]!=''){ $t_u = "http:".$x[$j]; $file2 = fopen($t_u, "r"); $content2 = file_get_contents($t_u); $t_beg = explode('<title>',$content); $t_end = explode('</title>',$t_beg[1]); echo $t_end[0]; } } The error is Warning: fopen() [function.fopen]: php_network_getaddresses: getaddrinfo failed: No such host is known. in g:/ What exactly is wrong here?

    Read the article

  • Are Dynamic Prepared Statements Bad? (with php + mysqli)

    - by John
    I like the flexibility of Dynamic SQL and I like the security + improved performance of Prepared Statements. So what I really want is Dynamic Prepared Statements, which is troublesome to make because bind_param and bind_result accept "fixed" number of arguments. So I made use of an eval() statement to get around this problem. But I get the feeling this is a bad idea. Here's example code of what I mean // array of WHERE conditions $param = array('customer_id'=>1, 'qty'=>'2'); $stmt = $mysqli->stmt_init(); $types = ''; $bindParam = array(); $where = ''; $count = 0; // build the dynamic sql and param bind conditions foreach($param as $key=>$val) { $types .= 'i'; $bindParam[] = '$p'.$count.'=$param["'.$key.'"]'; $where .= "$key = ? AND "; $count++; } // prepare the query -- SELECT * FROM t1 WHERE customer_id = ? AND qty = ? $sql = "SELECT * FROM t1 WHERE ".substr($where, 0, strlen($where)-4); $stmt->prepare($sql); // assemble the bind_param command $command = '$stmt->bind_param($types, '.implode(', ', $bindParam).');'; // evaluate the command -- $stmt->bind_param($types,$p0=$param["customer_id"],$p1=$param["qty"]); eval($command); Is that last eval() statement a bad idea? I tried to avoid code injection by encapsulating values behind the variable name $param. Does anyone have an opinion or other suggestions? Are there issues I need to be aware of?

    Read the article

  • php - arrange array to display in score order

    - by Phil Jackson
    hi, i have wrote a script to produce an array of data but now want to display in order of score. The array outputs as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user1_design [2] => user2_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 6 [2] => 15 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) so in a nutshell I am wanting it to be converted as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user2_design [2] => user1_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 15 [2] => 6 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) I have been looking at asort() but cant get anything to work. any help would be much appreciated.

    Read the article

  • php shuffle() returns one item

    - by mike
    Anyone have any idea why shuffle() would only return 1 item? when using: $array2 = shuffle($array1); with the following array($array1): Array ( [0] => 1 [1] => 5 [2] => 6 [3] => 7 [4] => 8 [5] => 10 [6] => 11 [7] => 12 [8] => 13 [9] => 14 ) The output of: print_r($array2); is simply: 1 Any idea as to why it would not only not shuffle the array, but knock off the remaining 9 items in the array? thanks!

    Read the article

  • problem creating jpg thumb with php

    - by Ross
    Hi, I am having problems creating a thumbnail from an uploaded image, my problem is (i) the quality (ii) the crop http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/large.jpg http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/thumb.jpg If you look the quality is very poor and the crop is taken from the top and is not a resize of the original image although the dimesions mean it is in proportion. The original is 1600px wide by 1100px high. Any help would be appreciated. $thumb = $targetPath."Thumbs/".$fileName; $imgsize = getimagesize($targetFile); $image = imagecreatefromjpeg($targetFile); $width = 200; //New width of image $height = 138; //This maintains proportions $src_w = $imgsize[0]; $src_h = $imgsize[1]; $thumbWidth = 200; $thumbHeight = 138; // Intended dimension of thumb // Beyond this point is simply code. $sourceImage = imagecreatefromjpeg($targetFile); $sourceWidth = imagesx($sourceImage); $sourceHeight = imagesy($sourceImage); $targetImage = imagecreate($thumbWidth,$thumbHeight); imagecopyresized($targetImage,$sourceImage,0,0,0,0,$thumbWidth,$thumbWidth,imagesx($sourceImage),imagesy($sourceImage)); //imagejpeg($targetImage, "$thumbPath/$thumbName"); imagejpeg($targetImage, $thumb); chmod($thumb, 0755);

    Read the article

  • INSERT INTO error MYSQL/PHP

    - by bat
    I get this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (total, addy, cc) VALUES ('798' , '123 sadf' , '12124123')' at line 1 $total = addslashes(($_SESSION['total'])); $addy = addslashes(($_POST['addy'])); $cc = addslashes(($_POST['cc'])); echo "$total"; echo "$addy"; echo "$cc"; mysql_query("INSERT INTO order (total, addy, cc) VALUES ('$total' , '$addy' , '$cc')") or die(mysql_error()); help plz =]

    Read the article

  • Implode error for PHP

    - by Pete Herbert Penito
    Hi Everyone! I have a form where I've got three checkboxes like this: <td>Wireless <input type="checkbox" name="services[]" value="wireless" /></td> </tr> <tr> <td>Cellular <input type="checkbox" name="services[]" value="cellular" /></td> </tr> <tr> <td>Security <input type="checkbox" name="services[]" value="Security" /></td> <input type="submit" name="submit"> and then I extract($_POST), and have this code $comServices = implode(",", $services); but I get an error: Warning: implode() [function.implode]: Invalid arguments passed in .. does anyone know why Im getting this error?

    Read the article

  • GZIP .htaccess and php session problem

    - by Suresh
    Hi, I am trying to implement GZIP compression for my website. I copied the below code in my .htaccess file: ExpiresActive On ExpiresDefault A604800 Header append Cache-Control "public" <IfModule mod_deflate.c> <FilesMatch "\.(js|css)$"> SetOutputFilter DEFLATE </FilesMatch> </IfModule> what happens is when I type username and password the page reloads but still the login form is displayed but session is set. When I refresh the page using ctrl + R the login form goes and the username is displayed. what will be the problem. wwaiting for ur reply.

    Read the article

  • change font in sharedbook api in php

    - by ashish
    I m using Sharedbook api to generate a memory book, although it's working perfect, but font of the memory book is unchangeable ...means i can't change the font family of that book. I tried to change the font then it display error. please suggest me how to change Font of that memory book.. Thank is advance

    Read the article

  • PHP PDO - Num Rows

    - by Ian
    PDO apparently has no means to count the number of rows returned from a select query (mysqli has the num_rows variable). Is there a way to do this, short of using count($results->fetchAll()) ?

    Read the article

  • PHP mySQL - replace some string inside string

    - by apis17
    i want to replace ALL comma , into ,<space> in all address table in my mysql table. For example, +----------------+----------------+ | Name | Address | +----------------+----------------+ | Someone name | A1,Street Name | +----------------+----------------+ Into +----------------+----------------+ | Name | Address | +----------------+----------------+ | Someone name | A1, Street Name| +----------------+----------------+ Thanks in advance.

    Read the article

< Previous Page | 289 290 291 292 293 294 295 296 297 298 299 300  | Next Page >