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  • what is the accepted naming convention for int, string, array, list, object, etc...

    - by RJ
    The company I work for now uses a set naming convention for their C# variables such as iSomeName for int, sSomeName for string, aSomeName for arrays, bSomeName for boolean, dSomeName for datetime and so on. My previous employer did not use the i, s, a, b and d prefixes and just named the variables a good understandable name. My impression is that these prefixes lost favor a while ago and from what I read it is not the current trend. It seems fine to me either way as long as the variable is descriptive enough to understand what it is doing but I was wondering what the now-a-day accepted practice is for naming variables?

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  • Why use one dimensional array instead of a two dimensional arrray?

    - by user3869145
    I was doing some work handling a lot of information and my partner told me that I was using too many matrices to manipulate the variables of the problem. The idea was to use one dimension arrays int a[] instead of the 2 dimensional arrays int b[][], to save memory and processing speed of the algorithm. How certain is that this change will accelerate the speed of execution or compilation of my code in c ++?

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  • Is object clearing/array deallocation really necessary in VB6/VBA (Pros/Cons?)

    - by Oorang
    Hello, A lot of what I have learned about VB I learned from using Static Code Analysis (Particularly Aivosto's Project Analyzer). And one one of things it checks for is whether or not you cleared all objects and arrays. I used to just do this blindly because PA said so. But now that I know a little bit more about the way VB releases resources, it seems to me that these things should be happening automatically. Is this a legacy feature from pre VB6, or is there a reason why you should explicitly set objects back to nothing and use Erase on arrays?

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  • Better variant of getting the output dinamically-allocated array from the function?

    - by Raigomaru
    Here is to variants. First: int n = 42; int* some_function(int* input) { int* result = new int[n]; // some code return result; } void main() { int* input = new int[n]; int* output = some_function(input); delete[] input; delete[] output; } Here the function returns the memory, allocated inside the function. Second variant: int n = 42; void some_function(int* input, int* output) { // some code } void main() { int* input = new int[n]; int* output = new int[n]; some_function(input, output); delete[] input; delete[] output; } Here the memory is allocated outside the function. Now I use the first variant. But I now that many built-in c++ functions use the second variant. The first variant is more comfortable (in my opinion). But the second one also has some advantages (you allocate and delete memory in the same block). Maybe it's a silly question but what variant is better and why?

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  • Is this the best way to grab common elements from a Hash of arrays?

    - by Hulihan Applications
    I'm trying to get a common element from a group of arrays in Ruby. Normally, you can use the & operator to compare two arrays, which returns elements that are present or common in both arrays. This is all good, except when you're trying to get common elements from more than two arrays. However, I want to get common elements from an unknown, dynamic number of arrays, which are stored in a hash. I had to resort to using the eval() method in ruby, which executes a string as actual code. Here's the function I wrote: def get_common_elements_for_hash_of_arrays(hash) # get an array of common elements contained in a hash of arrays, for every array in the hash. # ["1","2","3"] & ["2","4","5"] & ["2","5","6"] # => ["2"] # eval("[\"1\",\"2\",\"3\"] & [\"2\",\"4\",\"5\"] & [\"2\",\"5\",\"6\"]") # => ["2"] eval_string_array = Array.new # an array to store strings of Arrays, ie: "[\"2\",\"5\",\"6\"]", which we will join with & to get all common elements hash.each do |key, array| eval_string_array << array.inspect end eval_string = eval_string_array.join(" & ") # create eval string delimited with a & so we can get common values return eval(eval_string) end example_hash = {:item_0 => ["1","2","3"], :item_1 => ["2","4","5"], :item_2 => ["2","5","6"] } puts get_common_elements_for_hash_of_arrays(example_hash) # => 2 This works and is great, but I'm wondering...eval, really? Is this the best way to do it? Are there even any other ways to accomplish this(besides a recursive function, of course). If anyone has any suggestions, I'm all ears. Otherwise, Feel free to use this code if you need to grab a common item or element from a group or hash of arrays, this code can also easily be adapted to search an array of arrays.

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  • Drupal 7 - I can't pass post data in module function

    - by user2603290
    I can't pass post data in my custom module. filenames: mymodule.info mymodule.mod .info name = My Module description = My custom module. package = DEV version = 1.0 core = 7.x .module <?php function mymodule_menu() { $items = array(); $items['getcountries'] = array( 'title' => 'Get Countries', 'page callback' => 'getcountries', 'access arguments' => array('access content'), 'type' => MENU_CALLBACK, ); $items['getstates'] = array( 'title' => 'Get States', 'page callback' => 'getstates', 'access arguments' => array('access content'), 'type' => MENU_CALLBACK, ); return $items; } function getcountries() { $result = db_query("select distinct(country) from region"); $jsonarray = Array(); foreach ($result as $record) { $jsonarray[] = array( 'item' => $record->country, 'value' => $record->country ); } $json = json_encode($jsonarray); echo $json; } function getstates() { echo $_POST["test"]; } Ajax call $(document).ready(function(){ $.ajax({ url: '/getstates', type: 'POST', data: '{"test":"1"}', success : function () { alert('ok'); }, error : function (jqXHR, textStatus, errorThrown) { alert('error'); } }); }); The first item "getcountries" is working fine however the second one is not. I can browse to http://mysite.com/getstates ok but when I call this function using ajax it is not passing the value of "test" which is "1" to $_POST["test"]. I am new to Drupal so I am positive that I miss something here. I thought I need a new set of eyes.

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  • Is this the best way to grab Common element from a Hash of arrays?

    - by Hulihan Applications
    I'm trying to get a common element from a group of arrays in Ruby. Normally, you can use the & operator to compare two arrays, which returns elements that are present or common in both arrays. This is all good, except when you're trying to get common elements from more than two arrays. However, I want to get common elements from an unknown, dynamic number of arrays, which are stored in a hash. I had to resort to using the eval() method in ruby, which executes a string as actual code. Here's the function I wrote: def get_common_elements_for_hash_of_arrays(hash) # get an array of common elements contained in a hash of arrays, for every array in the hash. # ["1","2","3"] & ["2","4","5"] & ["2","5","6"] # => ["2"] # eval("[\"1\",\"2\",\"3\"] & [\"2\",\"4\",\"5\"] & [\"2\",\"5\",\"6\"]") # => ["2"] eval_string_array = Array.new # an array to store strings of Arrays, ie: "[\"2\",\"5\",\"6\"]", which we will join with & to get all common elements hash.each do |key, array| eval_string_array << array.inspect end eval_string = eval_string_array.join(" & ") # create eval string delimited with a & so we can get common values return eval(eval_string) end example_hash = {:item_0 => ["1","2","3"], :item_1 => ["2","4","5"], :item_2 => ["2","5","6"] } puts get_common_elements_for_hash_of_arrays(example_hash) # => 2 This works and is great, but I'm wondering...eval, really? Is this the best way to do it? Are there even any other ways to accomplish this(besides a recursive function, of course). If anyone has any suggestions, I'm all ears. Otherwise, Feel free to use this code if you need to grab a common item or element from a group or hash of arrays, this code can also easily be adapted to search an array of arrays.

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  • For Loop not advancing

    - by shizishan
    I'm trying to read in a large number of jpg files using a for loop. But for some reason, the k index is not advancing. I just get A as a 460x520x3 uint8. Am I missing something? My goal with this code is to convert all the jpg images to the same size. Since I haven't been able to advance through the images, I can't quite tell if I'm doing it right. nFrames = length(date); % Number of frames. for k = 1:nFrames-1 % Number of days % Set file under consideration A = imread(['map_EUS_' datestr(cell2mat(date_O3(k)),'yyyy_mm_dd') '_O3_MDA8.jpg']); % Size of existing image A. [rowsA, colsA, numberOfColorChannelsA] = size(A); % Read in and get size of existing image B (the next image). B = imread(['map_EUS_' datestr(cell2mat(date_O3(k+1)),'yyyy_mm_dd') '_O3_MDA8.jpg']); [rowsB, colsB, numberOfColorChannelsB] = size(B); % Size of B does not match A, so resize B to match A's size. B = imresize(B, [rowsA colsA]); eval(['print -djpeg map_EUS_' datestr(cell2mat(date_O3(k)),'yyyy_mm_dd') '_O3_MDA8_test.jpg']); end end

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  • Use DivX settings to encode to mp4 with ffmpeg

    - by sjngm
    I'm used to use VirtualDub to encode a video to AVI container with DivX-codec (and MP3 for audio). Now I'm planning to use ffmpeg to encode videos to MP4 container with h264-codec. What I've figured out is that I need to use libx264 and one of those presets to make anything work. However, I'm amazed about the video bitrate ffmpeg uses for encoding. What I currently have is this little batch file: @ECHO OFF SETLOCAL SET IN=source.avs SET FFMPEG_PATH=C:\Program Files (x86)\ffmpeg SET PRESET=-fpre "%FFMPEG_PATH%\presets\libx264-lossless_slow.ffpreset" SET AUDIO=-acodec libmp3lame -ab 128000 SET VIDEO=-vcodec libx264 -vb 1978000 "%FFMPEG_PATH%\ffmpeg.exe" -i %IN% %AUDIO% %VIDEO% %PRESET% test.mp4 ENDLOCAL With this I tell ffmpeg to use 1978k as the bitrate, but ffmpeg uses 15000k+! I tried other presets, but they don't use my specified bitrate. Here are the presets I have: libx264-baseline.ffpreset libx264-ipod320.ffpreset libx264-ipod640.ffpreset libx264-lossless_fast.ffpreset libx264-lossless_max.ffpreset libx264-lossless_medium.ffpreset libx264-lossless_slow.ffpreset libx264-lossless_slower.ffpreset libx264-lossless_ultrafast.ffpreset ffmpeg version: FFmpeg git-N-29181-ga304071 libavutil 50. 40. 1 / 50. 40. 1 libavcodec 52.120. 0 / 52.120. 0 libavformat 52.108. 0 / 52.108. 0 libavdevice 52. 4. 0 / 52. 4. 0 libavfilter 1. 79. 0 / 1. 79. 0 libswscale 0. 13. 0 / 0. 13. 0 Note that I don't use the latest version as it has problems with spaces in filenames. Here's what seems to be the full parameter list DivX 6.9.2 uses: -bvnn 1978000 -vbv 218691200,100663296,100663296 -dir "C:\Users\sjngm\AppData\Roaming\DivX\DivX Codec" -w -b 1 -use_presets=1 -preset=10 -windowed_fullsearch=2 -thread_delay=1 What command line parameters would that be for ffmpeg? EDIT: Going with slhck's suggestion I tried a new 32-bit version. I have no idea if that is 0.9 or newer, I can't find that info. ffmpeg version N-36890-g67f5650 libavutil 51. 34.100 / 51. 34.100 libavcodec 53. 56.105 / 53. 56.105 libavformat 53. 30.100 / 53. 30.100 libavdevice 53. 4.100 / 53. 4.100 libavfilter 2. 59.100 / 2. 59.100 libswscale 2. 1.100 / 2. 1.100 libswresample 0. 6.100 / 0. 6.100 libpostproc 51. 2.100 / 51. 2.100 I reworked my batch file to look like this (interestingly enough I can't find parameter -vprofile in the documentation): @ECHO OFF SETLOCAL SET IN=VTS_01_1.avs SET FFMPEG_PATH=C:\Program Files (x86)\ffmpeg SET PRESET=-vprofile high -preset veryslow SET AUDIO=-acodec libmp3lame -ab 128000 SET VIDEO=-vcodec libx264 -vb 1978000 "%FFMPEG_PATH%\ffmpeg.exe" -i %IN% %AUDIO% %PRESET% %VIDEO% test.mp4 ENDLOCAL I see that it now uses the bitrate properly (thanks to LongNeckbeard for pointing out that the lossless-stuff ignores the bitrate!). Just in case you wonder how I came up with the 1978000, I'm using this formula which I found valid for DivX-files (I'm guessing the bitrate won't change that much for h264): width * height * 25 * 0.22 / 1000 I'm not sure if the 0.22 correlates with the CRF somehow. Overall I forgot to say the I will use a two-pass scenario, which is why I don't use the CRF here. I will try to read more about this. Currently I'm just trying to get something running that shows me that I'm doing something right (ffmpeg isn't the easiest tool to understand ;)). C:\Program Files (x86)\ffmpeg\ffmpeg.exe" -i VTS_01_1.avs -acodec libmp3lame -ab 128000 -vcodec libx264 -vb 1978000 -vprofile high -preset veryslow test.mp4 The output is now: ffmpeg version N-36890-g67f5650 Copyright (c) 2000-2012 the FFmpeg developers built on Jan 16 2012 21:57:13 with gcc 4.6.2 configuration: --enable-gpl --enable-version3 --disable-w32threads --enable-runtime-cpudetect --enable-avisynth --enable-bzlib --enable-frei0r --enable-libopencore-amrnb --enable-libopencore-amrwb --enable-libfreetype --enable-libgsm --enable-libmp3lame --enable-libopenjpeg --enable-librtmp --enable-libschroedinger --enable-libspeex --enable-libtheora --enable-libvo-aacenc --enable-libvo-amrwbenc --enable-libvorbis --enable-libvpx --enable-libx264 --enable-libxavs --enable-libxvid --enable-zlib libavutil 51. 34.100 / 51. 34.100 libavcodec 53. 56.105 / 53. 56.105 libavformat 53. 30.100 / 53. 30.100 libavdevice 53. 4.100 / 53. 4.100 libavfilter 2. 59.100 / 2. 59.100 libswscale 2. 1.100 / 2. 1.100 libswresample 0. 6.100 / 0. 6.100 libpostproc 51. 2.100 / 51. 2.100 Input #0, avs, from 'VTS_01_1.avs': Duration: 00:58:46.12, start: 0.000000, bitrate: 0 kb/s Stream #0:0: Video: rawvideo (YV12 / 0x32315659), yuv420p, 576x448, 77414 kb/s, 25 tbr, 25 tbn, 25 tbc Stream #0:1: Audio: pcm_s16le ([1][0][0][0] / 0x0001), 48000 Hz, 2 channels, s16, 1536 kb/s File 'test.mp4' already exists. Overwrite ? [y/N] y w:576 h:448 pixfmt:yuv420p tb:1/1000000 sar:0/1 sws_param: [libx264 @ 05A2C400] using cpu capabilities: MMX2 SSE2Fast FastShuffle SSEMisalign LZCNT [libx264 @ 05A2C400] profile High, level 3.1 [libx264 @ 05A2C400] 264 - core 120 r2120 0c7dab9 - H.264/MPEG-4 AVC codec - Copyleft 2003-2011 - http://www.videolan.org/x264.html - options: cabac=1 ref=16 deblock=1:0:0 analyse=0x3:0x133 me=umh subme=10 psy=1 psy_rd=1.00:0.00 mixed_ref=1 me_range=24 chroma_me=1 trellis=2 8x8dct=1 cqm=0 deadzone=21,11 fast_pskip=1 chroma_qp_offset=-2 threads=3 sliced_threads=0 nr=0 decimate=1 interlaced=0 bluray_compat=0 constrained_intra=0 bframes=8 b_pyramid=2 b_adapt=2 b_bias=0 direct=3 weightb=1 open_gop=0 weightp=2 keyint=250 keyint_min=25 scenecut=40 intra_refresh=0 rc_lookahead=60 rc=abr mbtree=1 bitrate=1978 ratetol=1.0 qcomp=0.60 qpmin=0 qpmax=69 qpstep=4 ip_ratio=1.40 aq=1:1.00 Output #0, mp4, to 'test.mp4': Metadata: encoder : Lavf53.30.100 Stream #0:0: Video: h264 (![0][0][0] / 0x0021), yuv420p, 576x448, q=-1--1, 1978 kb/s, 25 tbn, 25 tbc Stream #0:1: Audio: mp3 (i[0][0][0] / 0x0069), 48000 Hz, 2 channels, s16, 128 kb/s Stream mapping: Stream #0:0 -> #0:0 (rawvideo -> libx264) Stream #0:1 -> #0:1 (pcm_s16le -> libmp3lame) Press [q] to stop, [?] for help frame= 0 fps= 0 q=0.0 size= 0kB time=00:00:00.00 bitrate= 0.0kbits/s frame= 0 fps= 0 q=0.0 size= 0kB time=00:00:00.00 bitrate= 0.0kbits/s frame= 0 fps= 0 q=0.0 size= 0kB time=00:00:00.00 bitrate= 0.0kbits/s frame= 3 fps= 1 q=22.0 size= 39kB time=00:00:00.04 bitrate=8063.8kbits/ frame= 8 fps= 2 q=22.0 size= 82kB time=00:00:00.24 bitrate=2801.3kbits/ frame= 13 fps= 3 q=23.0 size= 120kB time=00:00:00.44 bitrate=2229.5kbits/ frame= 16 fps= 4 q=23.0 size= 147kB time=00:00:00.56 bitrate=2156.7kbits/ frame= 20 fps= 4 q=22.0 size= 175kB time=00:00:00.72 bitrate=1987.4kbits/ : video:4387kB audio:273kB global headers:0kB muxing overhead 0.260038% [libx264 @ 05A2C400] frame I:2 Avg QP:19.53 size: 29850 [libx264 @ 05A2C400] frame P:76 Avg QP:22.24 size: 19541 [libx264 @ 05A2C400] frame B:359 Avg QP:25.93 size: 8210 [libx264 @ 05A2C400] consecutive B-frames: 0.5% 0.5% 0.0% 8.2% 17.2% 52.2% 16.0% 5.5% 0.0% [libx264 @ 05A2C400] mb I I16..4: 5.4% 75.3% 19.3% [libx264 @ 05A2C400] mb P I16..4: 1.3% 16.5% 2.2% P16..4: 36.3% 28.6% 12.7% 1.8% 0.2% skip: 0.4% [libx264 @ 05A2C400] mb B I16..4: 0.4% 3.8% 0.3% B16..8: 40.0% 18.4% 4.7% direct:18.5% skip:13.9% L0:45.4% L1:38.1% BI:16.5% [libx264 @ 05A2C400] final ratefactor: 20.35 [libx264 @ 05A2C400] 8x8 transform intra:83.1% inter:68.5% [libx264 @ 05A2C400] direct mvs spatial:99.2% temporal:0.8% [libx264 @ 05A2C400] coded y,uvDC,uvAC intra: 64.9% 83.4% 49.2% inter: 49.0% 50.4% 4.4% [libx264 @ 05A2C400] i16 v,h,dc,p: 25% 22% 27% 26% [libx264 @ 05A2C400] i8 v,h,dc,ddl,ddr,vr,hd,vl,hu: 10% 7% 23% 9% 10% 10% 10%10% 13% [libx264 @ 05A2C400] i4 v,h,dc,ddl,ddr,vr,hd,vl,hu: 12% 11% 13% 9% 12% 11% 10% 9% 12% [libx264 @ 05A2C400] i8c dc,h,v,p: 42% 28% 16% 14% [libx264 @ 05A2C400] Weighted P-Frames: Y:18.4% UV:7.9% [libx264 @ 05A2C400] ref P L0: 29.1% 11.3% 15.7% 7.3% 6.9% 4.9% 5.1% 3.4%3.9% 2.7% 2.8% 1.8% 1.7% 1.2% 1.4% 0.9% [libx264 @ 05A2C400] ref B L0: 68.8% 11.4% 5.5% 2.9% 2.3% 1.9% 1.5% 1.1%1.1% 1.0% 0.9% 0.7% 0.5% 0.3% 0.1% [libx264 @ 05A2C400] ref B L1: 91.9% 8.1% [libx264 @ 05A2C400] kb/s:2055.88 As far as I'm concerned it doesn't look that bad to me.

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  • Hi i have a c programming doubt in the implementation of hash table?

    - by aks
    Hi i have a c programming doubt in the implementation of hash table? I have implemented the hash table for storing some strings? I am having problem while dealing with hash collisons. I am following chaining link-list approach to overcome the same? But, somehow my code is behaving differently. I am not able to debug the same? Can somebody help? This is what i am facing: Say first time, i insert a string called gaur. My hash map calculates the index as 0 and inserts the string successfully. However, when another string whose hash map also when calculates turns out to be 0, my previous value gets overrridden i.e. gaur will be replaced by new string. This is my code: struct list { char *string; struct list *next; }; struct hash_table { int size; /* the size of the table */ struct list **table; /* the table elements */ }; struct hash_table *create_hash_table(int size) { struct hash_table *new_table; int i; if (size<1) return NULL; /* invalid size for table */ /* Attempt to allocate memory for the table structure */ if ((new_table = malloc(sizeof(struct hash_table))) == NULL) { return NULL; } /* Attempt to allocate memory for the table itself */ if ((new_table->table = malloc(sizeof(struct list *) * size)) == NULL) { return NULL; } /* Initialize the elements of the table */ for(i=0; i<size; i++) new_table->table[i] = '\0'; /* Set the table's size */ new_table->size = size; return new_table; } unsigned int hash(struct hash_table *hashtable, char *str) { unsigned int hashval = 0; int i = 0; for(; *str != '\0'; str++) { hashval += str[i]; i++; } return (hashval % hashtable->size); } struct list *lookup_string(struct hash_table *hashtable, char *str) { printf("\n enters in lookup_string \n"); struct list * new_list; unsigned int hashval = hash(hashtable, str); /* Go to the correct list based on the hash value and see if str is * in the list. If it is, return return a pointer to the list element. * If it isn't, the item isn't in the table, so return NULL. */ for(new_list = hashtable->table[hashval]; new_list != NULL;new_list = new_list->next) { if (strcmp(str, new_list->string) == 0) return new_list; } printf("\n returns NULL in lookup_string \n"); return NULL; } int add_string(struct hash_table *hashtable, char *str) { printf("\n enters in add_string \n"); struct list *new_list; struct list *current_list; unsigned int hashval = hash(hashtable, str); printf("\n hashval = %d", hashval); /* Attempt to allocate memory for list */ if ((new_list = malloc(sizeof(struct list))) == NULL) { printf("\n enters here \n"); return 1; } /* Does item already exist? */ current_list = lookup_string(hashtable, str); if (current_list == NULL) { printf("\n DEBUG Purpose \n"); printf("\n NULL \n"); } /* item already exists, don't insert it again. */ if (current_list != NULL) { printf("\n Item already present...\n"); return 2; } /* Insert into list */ printf("\n Inserting...\n"); new_list->string = strdup(str); new_list->next = NULL; //new_list->next = hashtable->table[hashval]; if(hashtable->table[hashval] == NULL) { hashtable->table[hashval] = new_list; } else { struct list * temp_list = hashtable->table[hashval]; while(temp_list->next!=NULL) temp_list = temp_list->next; temp_list->next = new_list; hashtable->table[hashval] = new_list; } return 0; }

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  • Error In centos6 while compiling java classes,in tomcat6

    - by AJIT RANA
    I am newbie to Linux and Centos6. I bought server just now and want to deploy my web app in it. I am getting error while I am compiling my servlet classes. It showing me bash: javac: command not found when I try to compile my classes. But when I checked my class in '/usr/lib/jvm/java-1.6.0/bin .'I found my javac there. Then I checked javac with the help of command ./javac i got ERROR.. [root:ip_address.com]# ./javac There is insufficient memory for the Java Runtime Environment to continue. pthread_getattr_np Error occurred during initialization of VM java.lang.OutOfMemoryError: unable to create new native thread I followed the step as shown in "" Java outofmemoryerror when creating <100 threads "" which shows me command to get limits.. '[root:ipaddress.com]# ulimit -a core file size (blocks, -c) unlimited data seg size (kbytes, -d) unlimited scheduling priority (-e) 0 file size (blocks, -f) unlimited pending signals (-i) 278528 max locked memory (kbytes, -l) 32 max memory size (kbytes, -m) unlimited open files (-n) 1024 pipe size (512 bytes, -p) 8 POSIX message queues (bytes, -q) 819200 real-time priority (-r) 0 stack size (kbytes, -s) 10240 cpu time (seconds, -t) unlimited max user processes (-u) 1024 virtual memory (kbytes, -v) unlimited file locks (-x) unlimited' [root:ipaddress.com]# top bash: top: command not found link :- http://stackoverflow.com/q/12913857/1746764

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  • mdadm superblock hiding/shadowing partition

    - by Kjell Andreassen
    Short version: Is it safe to do mdadm --zero-superblock /dev/sdd on a disk with a partition (dev/sdd1), filesystem and data? Will the partition be mountable and the data still there? Longer version: I used to have a raid6 array but decided to dismantle it. The disks from the array are now used as non-raid disks. The superblocks were cleared: sudo mdadm --zero-superblock /dev/sdd The disks were repartitioned with fdisk and filesystems created with mfks.ext4. All disks where mounted and everything worked fine. Today, a couple of weeks later, one of the disks is failing to be recognized when trying to mount it, or rather the single partition on it. sudo mount /dev/sdd1 /mnt/tmp mount: special device /dev/sdd1 does not exist fdisk claims there to be a partition on it: sudo fdisk -l /dev/sdd Disk /dev/sdd: 2000.4 GB, 2000398934016 bytes 255 heads, 63 sectors/track, 243201 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0xb06f6341 Device Boot Start End Blocks Id System /dev/sdd1 1 243201 1953512001 83 Linux Of course mount is right, the device /dev/sdd1 is not there, I'm guessing udev did not create it because of the mdadm data still on it: sudo mdadm --examine /dev/sdd /dev/sdd: Magic : a92b4efc Version : 1.2 Feature Map : 0x0 Array UUID : b164e513:c0584be1:3cc53326:48691084 Name : pringle:0 (local to host pringle) Creation Time : Sat Jun 16 21:37:14 2012 Raid Level : raid6 Raid Devices : 6 Avail Dev Size : 3907027120 (1863.02 GiB 2000.40 GB) Array Size : 15628107776 (7452.06 GiB 8001.59 GB) Used Dev Size : 3907026944 (1863.02 GiB 2000.40 GB) Data Offset : 2048 sectors Super Offset : 8 sectors State : clean Device UUID : 3ccaeb5b:843531e4:87bf1224:382c16e2 Update Time : Sun Aug 12 22:20:39 2012 Checksum : 4c329db0 - correct Events : 1238535 Layout : left-symmetric Chunk Size : 512K Device Role : Active device 3 Array State : AA.AAA ('A' == active, '.' == missing) My mdadm --zero-superblock apparently didn't work. Can I safely try it again without losing data? If not, are there any suggestion on what do to? Not starting mdadm at all on boot might be a (somewhat unsatisfactory) solution.

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  • Resizing a LUKS encrypted volume

    - by mgorven
    I have a 500GiB ext4 filesystem on top of LUKS on top of an LVM LV. I want to resize the LV to 100GiB. I know how to resize ext4 on top of an LVM LV, but how do I deal with the LUKS volume? mgorven@moab:~% sudo lvdisplay /dev/moab/backup --- Logical volume --- LV Name /dev/moab/backup VG Name moab LV UUID nQ3z1J-Pemd-uTEB-fazN-yEux-nOxP-QQair5 LV Write Access read/write LV Status available # open 1 LV Size 500.00 GiB Current LE 128000 Segments 1 Allocation inherit Read ahead sectors auto - currently set to 2048 Block device 252:3 mgorven@moab:~% sudo cryptsetup status backup /dev/mapper/backup is active and is in use. type: LUKS1 cipher: aes-cbc-essiv:sha256 keysize: 256 bits device: /dev/mapper/moab-backup offset: 3072 sectors size: 1048572928 sectors mode: read/write mgorven@moab:~% sudo tune2fs -l /dev/mapper/backup tune2fs 1.42 (29-Nov-2011) Filesystem volume name: backup Last mounted on: /srv/backup Filesystem UUID: 63877e0e-0549-4c73-8535-b7a81eb363ed Filesystem magic number: 0xEF53 Filesystem revision #: 1 (dynamic) Filesystem features: has_journal ext_attr resize_inode dir_index filetype extent flex_bg sparse_super large_file huge_file uninit_bg dir_nlink extra_isize Filesystem flags: signed_directory_hash Default mount options: (none) Filesystem state: clean with errors Errors behavior: Continue Filesystem OS type: Linux Inode count: 32768000 Block count: 131071616 Reserved block count: 0 Free blocks: 112894078 Free inodes: 32044830 First block: 0 Block size: 4096 Fragment size: 4096 Reserved GDT blocks: 992 Blocks per group: 32768 Fragments per group: 32768 Inodes per group: 8192 Inode blocks per group: 512 RAID stride: 128 RAID stripe width: 128 Flex block group size: 16 Filesystem created: Sun Mar 11 19:24:53 2012 Last mount time: Sat May 19 13:29:27 2012 Last write time: Fri Jun 1 11:07:22 2012 Mount count: 0 Maximum mount count: 100 Last checked: Fri Jun 1 11:03:50 2012 Check interval: 31104000 (12 months) Next check after: Mon May 27 11:03:50 2013 Lifetime writes: 118 GB Reserved blocks uid: 0 (user root) Reserved blocks gid: 0 (group root) First inode: 11 Inode size: 256 Required extra isize: 28 Desired extra isize: 28 Journal inode: 8 Default directory hash: half_md4 Directory Hash Seed: 383bcbc5-fde9-4720-b98e-2d6224713ecf Journal backup: inode blocks

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  • Cannot upload files bigger than 8GB to Amazon S3 by multi-part upload due to broken pipe

    - by spencerho
    I implemented S3 multi-part upload, both high level and low level version, based on the sample code from http://docs.amazonwebservices.com/AmazonS3/latest/dev/index.html?HLuploadFileJava.html and http://docs.amazonwebservices.com/AmazonS3/latest/dev/index.html?llJavaUploadFile.html When I uploaded files of size less than 4 GB, the upload processes completed without any problem. When I uploaded a file of size 13 GB, the code started to show IO exception, broken pipes. After retries, it still failed. Here is the way to repeat the scenario. Take 1.1.7.1 release, create a new bucket in US standard region create a large EC2 instance as the client to upload file create a file of 13GB in size on the EC2 instance. run the sample code on either one of the high-level or low-level API S3 documentation pages from the EC2 instance test either one of the three part size: default part size (5 MB) or set the part size to 100,000,000 or 200,000,000 bytes. So far the problem shows up consistently. I attached here a tcpdump file for you to compare. In there, the host on the S3 side kept resetting the socket.

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  • 613 threads limit on debian

    - by Joel
    When running this program thread-limit.c on my dedicated debian server, the output says that my system can't create more than around 600 threads. I need to create more threads, and fix my system misconfiguration. Here are a few informations about my dedicated server: de801:/# uname -a Linux de801.ispfr.net 2.6.18-028stab085.5 #1 SMP Thu Apr 14 15:06:33 MSD 2011 x86_64 GNU/Linux de801:/# java -version java version "1.6.0_26" Java(TM) SE Runtime Environment (build 1.6.0_26-b03) Java HotSpot(TM) 64-Bit Server VM (build 20.1-b02, mixed mode) de801:/# ldd $(which java) linux-vdso.so.1 => (0x00007fffbc3fd000) libpthread.so.0 => /lib/libpthread.so.0 (0x00002af013225000) libjli.so => /usr/lib/jvm/java-6-sun-1.6.0.26/jre/bin/../lib/amd64/jli/libjli.so (0x00002af013441000) libdl.so.2 => /lib/libdl.so.2 (0x00002af01354b000) libc.so.6 => /lib/libc.so.6 (0x00002af013750000) /lib64/ld-linux-x86-64.so.2 (0x00002af013008000) de801:/# cat /proc/sys/kernel/threads-max 1589248 de801:/# ulimit -a core file size (blocks, -c) 0 data seg size (kbytes, -d) unlimited scheduling priority (-e) 0 file size (blocks, -f) unlimited pending signals (-i) 794624 max locked memory (kbytes, -l) 32 max memory size (kbytes, -m) unlimited open files (-n) 10240 pipe size (512 bytes, -p) 8 POSIX message queues (bytes, -q) 819200 real-time priority (-r) 0 stack size (kbytes, -s) 128 cpu time (seconds, -t) unlimited max user processes (-u) unlimited virtual memory (kbytes, -v) unlimited file locks (-x) unlimited Here is the output of the C program de801:/test# ./thread-limit Creating threads ... Address of c = 1061520 KB Address of c = 1081300 KB Address of c = 1080904 KB Address of c = 1081168 KB Address of c = 1080508 KB Address of c = 1080640 KB Address of c = 1081432 KB Address of c = 1081036 KB Address of c = 1080772 KB 100 threads so far ... 200 threads so far ... 300 threads so far ... 400 threads so far ... 500 threads so far ... 600 threads so far ... Failed with return code 12 creating thread 637. Any ideas how to fix this please ?

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  • Why does cpuinfo report that my frequency is slower?

    - by Avery Chan
    My machine is running off of a AMD Sempron(tm) X2 190 Processor. According the marketing copy, it should be running at around 2.5 Ghz. Why is the cpu speed being reported as something lower? Spec description (in Chinese) $ cat /proc/cpuinfo processor : 0 vendor_id : AuthenticAMD cpu family : 16 model : 6 model name : AMD Sempron(tm) X2 190 Processor stepping : 3 microcode : 0x10000c8 cpu MHz : 800.000 cache size : 512 KB physical id : 0 siblings : 2 core id : 0 cpu cores : 2 apicid : 0 initial apicid : 0 fpu : yes fpu_exception : yes cpuid level : 5 wp : yes flags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush mmx fxsr sse sse2 ht syscall nx mmxext fxsr_opt pdpe1gb rdtscp lm 3dnowext 3dnow constant_tsc rep_good nopl nonstop_tsc extd_apicid pni monitor cx16 popcnt lahf_lm cmp_legacy svm extapic cr8_legacy abm sse4a misalignsse 3dnowprefetch osvw ibs skinit wdt npt lbrv svm_lock nrip_save bogomips : 5022.89 TLB size : 1024 4K pages clflush size : 64 cache_alignment : 64 address sizes : 48 bits physical, 48 bits virtual power management: ts ttp tm stc 100mhzsteps hwpstate processor : 1 vendor_id : AuthenticAMD cpu family : 16 model : 6 model name : AMD Sempron(tm) X2 190 Processor stepping : 3 microcode : 0x10000c8 cpu MHz : 800.000 cache size : 512 KB physical id : 0 siblings : 2 core id : 1 cpu cores : 2 apicid : 1 initial apicid : 1 fpu : yes fpu_exception : yes cpuid level : 5 wp : yes flags : fpu vme de pse tsc msr pae mce cx8 apic sep mtrr pge mca cmov pat pse36 clflush mmx fxsr sse sse2 ht syscall nx mmxext fxsr_opt pdpe1gb rdtscp lm 3dnowext 3dnow constant_tsc rep_good nopl nonstop_tsc extd_apicid pni monitor cx16 popcnt lahf_lm cmp_legacy svm extapic cr8_legacy abm sse4a misalignsse 3dnowprefetch osvw ibs skinit wdt npt lbrv svm_lock nrip_save bogomips : 5022.82 TLB size : 1024 4K pages clflush size : 64 cache_alignment : 64 address sizes : 48 bits physical, 48 bits virtual power management: ts ttp tm stc 100mhzsteps hwpstate

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  • Different versions of iperf for windows give totally different results

    - by Albert Mata
    Measuring TCP output from a Windows client to Solaris server: WXP SP3 with iperf 1.7.0 -- returns an average around 90Mbit Same client, same server but iperf 2.0.5 for windows -- returns an average of 8.5 Mbit Similar discrepancies have been observed connecting to other servers (W2008, W2003) It's difficult to get to some conclusions when different versions of the same tool provide vastly different results. Example below: C:\tempiperf -v (from iperf.fr) iperf version 2.0.5 (08 Jul 2010) pthreads C:\tempiperf -c solaris10 Client connecting to solaris10, TCP port 5001 TCP window size: 64.0 KByte (default) [ 3] local 10.172.181.159 port 2124 connected with 10.172.180.209 port 5001 [ ID] Interval Transfer Bandwidth [ 3] 0.0-10.2 sec 10.6 MBytes 8.74 Mbits/sec Abysmal perfomance, but now I test from the same host (Windows XP SP3 32bit and 100Mbit) to the same server (Solaris 10/sparc 64bit and 1Gbit running iperf 2.0.5 with default window of 48k) with the old iperf C:\temp1iperf -v iperf version 1.7.0 (13 Mar 2003) win32 threads C:\temp1iperf.exe -c solaris10 -w64k Client connecting to solaris10, TCP port 5001 TCP window size: 64.0 KByte [1208] local 10.172.181.159 port 2128 connected with 10.172.180.209 port 5001 [ ID] Interval Transfer Bandwidth [1208] 0.0-10.0 sec 112 MBytes 94.0 Mbits/sec So one iperf with a 64k window says 8.75Mbit and the old iperf with the same window size says 94.0Mbit. These results are constant through repeated tests. From my testing launching iperf(old) with window size "x" and iperf(new) with window size "x" instead of producing the same or very close results produce totally different results. The only difference I see is the old compiled as win32 threads vs. pthreads but parallelism (-P 10) appears to work in both. Anyone has a clue or can recommend a tool that gives results I can trust?? EDIT: Looking at traces from (old) iperf it sets the TCP Window Scale flag to 3 in the SYN packet, when I run the (new) iperf this is set to 0 in the initial packet. A quick analysis of the window size through the exchange shows the (old) iperf moving back and forth but mostly at 32k while the (new) iperf mostly keeps at 64k. Maybe it will help somebody to connect the dots.

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  • Creating RAID1 on Windows Server causes not enough disk space error

    - by northpole
    I have three disks. Disk0 (boot), Disk1 and Disk2. Disk 1 and 2 are both unformatted and unallocated drives. I am trying to mirror Disk0 to Disk1. They are both Dynamic and are both the same size (1TB). When I select Disk1 to be the mirror I get the error "There is not enough space available on the disk(s) to complete this operation". I have spent several hours searching for a solution but have not found one. Why do I get this error when they are both the same size? EDIT: Shrinking the volume size on the boot disk by 100MB allowed me to get past this error. From what I read the mirror drive needs to be the same size or larger than the boot drive. So I am confused why that change worked. However, I now get the error " all disks holding extents for a given volume must have the same sector size and the sector size must be valid". I believe this is because the drives are different and one has 512B and the other is the Advanced Drive that is 4KB. What the different sector sizes cause both problems? If I got the same disks would both issues go away?

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  • Git fails to push with error 'out of memory'

    - by jwir3
    I'm using gitosis on a server that has a low amount of memory, specifically around 512 MB. When I try to push a large folder (happens to be a backup from an android phone), I get: me@corellia:~/Configs/$ git push origin master Counting objects: 18, done. Delta compression using up to 8 threads. Compressing objects: 100% (14/14), done. fatal: Out of memory, malloc failed MiB | 685 KiB/s error: pack-objects died of signal 13 error: failed to push some refs to 'git@dagobah:Configs' I've been searching the web, and notably found: http://www.mail-archive.com/[email protected]/msg01747.html as well as http://git.661346.n2.nabble.com/Out-of-memory-error-during-git-push-td5443705.html but these don't seem to help me for two reasons: 1) I am not actually out of memory when I push. When I run 'top' during the push, I get: 24262 git 18 0 16204 6084 1096 S 2 1.2 0:00.12 git-unpack-obje Also, during the push if I run /head/meminfo, I get: MemTotal: 524288 kB MemFree: 289408 kB Buffers: 0 kB Cached: 0 kB SwapCached: 0 kB Active: 0 kB Inactive: 0 kB HighTotal: 0 kB HighFree: 0 kB LowTotal: 524288 kB So, it seems that I have enough memory free, but it's actually still failing, and I'm not enough of a git guru to figure out what is happening. I would appreciate it if someone could give me a hand here and tell me what could be causing this problem, and what I can do to solve it. Thanks! EDIT: The output of running the ulimit -a command: scottj@dagobah:~$ ulimit -a core file size (blocks, -c) 0 data seg size (kbytes, -d) unlimited scheduling priority (-e) 0 file size (blocks, -f) unlimited pending signals (-i) 204800 max locked memory (kbytes, -l) 32 max memory size (kbytes, -m) unlimited open files (-n) 1024 pipe size (512 bytes, -p) 8 POSIX message queues (bytes, -q) 819200 real-time priority (-r) 0 stack size (kbytes, -s) 10240 cpu time (seconds, -t) unlimited max user processes (-u) 204800 virtual memory (kbytes, -v) unlimited file locks (-x) unlimited

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