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  • php, sql selection

    - by cosy
    I have a stupid question, I have this table : id_product name value 1 price 10-20 1 type computer 2 price 20-30 3 price 100-200 and I want to select from this table GROUP BY id_product and ORDER BY value WHERE name='price' how can i do this? Thanks a lot

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  • Writing a new line to file in PHP

    - by James P
    My code: $i = 0; $file = fopen('ids.txt', 'w'); foreach ($gemList as $gem) { fwrite($file, $gem->getAttribute('id') . '\n'); $gemIDs[$i] = $gem->getAttribute('id'); $i++; } fclose($file); For some reason, it's writing \n as a string, so the file looks like this: 40119\n40122\n40120\n42155\n36925\n45881\n42145\n45880 From Google'ing it tells me to use \r\n, but \r is a carriage return which doesn't seem to be what I want to do. I just want the file to look like this: 40119 40122 40120 42155 36925 45881 42145 45880 Thanks.

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  • Using preg_replace to replace all occurrences in php

    - by Greg-J
    Regex is absolutely my weak point and this one has me completely stumped. I am building a fairly basic search functionality and I need to be able to alter my user input based on the following pattern: Subject: %22first set%22 %22second set%22-drupal -wordpress Desired output: +"first set" +"second set" -drupal -wordpress I wish I could be more help as I normally like to at least post the solution I have so far, but on this one I'm at a loss. Any help is appreciated. Thank you.

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  • How to build unlimited level of menu through PHP and mysql

    - by Starx
    Well, to build my menu my menu I use a db similar structure like this To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field. parent 0 means top menu now there is not problem while creating submenu inside another submenu now this is way I fetch the submenu for the top menu <ul class="topmenu"> <? $list = $obj -> childmenu($parentid); //this list contains the array of submenu under $parendid foreach($list as $menu) { extract($menu); echo '<li><a href="#">'.$name.'</a></li>'; } ?> </ul> What I want to do is. I want to check if a new menu has other child menu and I want to keep on checking until it searches every child menu that is available and I want to display its child menu inside its particular list item like this Home ........

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  • PHP SQL Form Insert

    - by Prateek Sachan
    I've developed a form that inserts many things into the database. But somehow, when the page is filled up; it inserts only the user_password that too of the database admin. here is the code. Any help would be great. Invalid Name: We want names with more than 3 letters. Invalid E-mail: Type a valid e-mail please. Passwords are invalid: Passwords doesnt match or are invalid! Please enter your contact number. Please enter your age Congratulations! All fields are OK ;)

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  • PHP/WordPress Session CountDown

    - by Cameron
    I have the following code to show how long a user has left before their session will expire, I am using WordPress. How can I do this? Thanks <script> var obj_Span; var n_Seconds = 0; var n_Minutes = 0; var n_Hours = 0; function F_ConvertNumberToString ( n_Num ) { var str_Num = String(n_Num); if ( str_Num.length < 2 ) str_Num = "0" + str_Num; return str_Num; } function F_CountDown () { if ( n_Hours == 0 && n_Minutes == 0 && n_Seconds == 0 ) { obj_Span.innerHTML = "(Sorry, your session has expired.)"; } else { if ( n_Seconds >= 0 ) n_Seconds --; if ( n_Seconds < 0 ) { n_Minutes --; n_Seconds = 59; } if ( n_Minutes >= 0 ) { window.setTimeout ( "F_CountDown()", 1000 ); } if ( n_Minutes < 0 ) { n_Hours --; n_Minutes = 59; window.setTimeout ( "F_CountDown()", 1000 ); } F_UpdateDisplay (); } } function F_UpdateDisplay ( ) { if ( document.getElementById ) { if (n_Hours > 0 ) obj_Span.innerHTML = "(Remaining " + F_ConvertNumberToString(n_Hours) + ":" + F_ConvertNumberToString(n_Minutes) + ":" + F_ConvertNumberToString(n_Seconds) + ")"; else obj_Span.innerHTML = "(Remaining " + F_ConvertNumberToString(n_Minutes) + ":" + F_ConvertNumberToString(n_Seconds) + ")"; } } function F_StartCountDown ( n_Session ) { obj_Span = document.getElementById ( "CountDown" ); n_Minutes = n_Session; n_Hours = Math.floor(n_Minutes/60); n_Minutes = n_Minutes - (60*n_Hours); F_CountDown (); } </script> <script> F_StartCountDown ( " code here... " ); </script> <span id="CountDown"></span>

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  • PHP: json_decode dumping NULL, BOM not found

    - by SerEnder
    I've been trying to find out why this 'json_encode'd string isn't parsing out correctly, and came across previously answered questions that had the UTF BOM sequence that was throwing the error, but didn't help me here. Here's the code that isn't currently working: //Decode the notes attached to the sig $aNotes = json_decode($rule->getNotes(),true); $bom = pack("CCC",0xef,0xbb,0xbf); if(0 == strncmp($rule->getNotes(),$bom,3)) { print('BOM detected - json encoding in UTF-8<br/>'); } else { print('BOM NOT detected - json encoding correctly<br/>'); } print('rule->getNotes:<br/>' . $rule->getNotes() .'<br/>'); var_dump($aNotes); Which generates this result: BOM NOT detected - json encoding correctly rule->getNotes: [{"lDate":"Unknown","sAuthor":"Unknown","sNote":"This is a general purpose Russian spam rule that matches anything starting with 2, 3 or 4 hex digits followed by a domain name ending with .ru -RSK 2010-05-10"},{"lDate":"1295031463082","sAuthor":"Drew Thorstenson","sNote":"this is Ryan's ru rule"}] NULL I've run it through JSON Lint, which said it was valid, and An Online JSON Parser which parsed it correctly too. Any insight would be greatly appreciated.

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  • Basic security, PHP mySQl

    - by yuudachi
    So I am making a basic log-in page. I have a good idea of what to do, but I'm still unsure of some things. I have a database full of students and a password column of course. I know I'm going to use md5 encryption in that column. The student enters their e-mail and student ID, and they get e-mailed a password if correct. But, where do I create the password? Do I have to manually add the password (which is just a randomly generated string) in mySQL to all the students? And I am suppose to send the password to the student; how will I know what to send the student if the password is encrypted? I was thinking about generating the password when the student first enters their e-mail and student ID. They get an e-mail of the random string, and at the same time, I add the same random string to the database, encrypted. Is that how it's suppose to work though? And it feels unsafe doing that all on the same page. Sorry for the long-winded, newbish question. I find this all facisnating at the same time as well (AES and RSA encryption :O)

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  • PHP XML encoding

    - by Jeremey
    I need a function that will convert € or chr(0x20AC) or chr(8364) to € without having a static map. I tried using htmlentities(), but it only seems to work for the symbol itself and it converts to €

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  • PHP search multidimensional array for value, then place that element at start of array

    - by BobFlemming
    I need to search this array: cars - [0] -make : Ford -model: Escort -year: 1991 [1] -make: Honda -model: Civic -year: 1996 [2] -make: Vauxhall -model: Astra -year: 1972 And if (for example) the model is "Civic" , place that 'car' at position 0. So the end array would be like: cars - [0] -make: Honda -model: Civic -year: 1996 [1] -make : Ford -model: Escort -year: 1991 [2] -make: Vauxhall -model: Astra -year: 1972 I've tried some usort variations: function typeSort($a, $b) { if ($a['model'] == 'Civic' ) { return 0; } return ($a['model'] < $b['model']) ? -1 : 1; } but this is just returning 1

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  • Need help with PHP URL encoding/decoding

    - by Kenan
    On one page I'm "masking"/encoding URL which is passed to another page, there I decode URL and start file delivering to user. I found some function for encoding/decoding URL's, but sometime encoded URL contains "+" or "/" and decoded link is broken. I must use "folder structure" for link, can not use QueryString! Here is encoding function: $urll = 'SomeUrl.zip'; $key = '123'; $result = ''; for($i=0; $i<strlen($urll); $i++) { $char = substr($urll, $i, 1); $keychar = substr($key, ($i % strlen($key))-1, 1); $char = chr(ord($char)+ord($keychar)); $result.=$char; } $result = urlencode(base64_encode($result)); echo '<a href="/user/download/'.$result.'/">PC</a>'; Here is decoding: $urll = 'segment_3'; //Don't worry for this one its CMS retrieving 3rd "folder" $key = '123'; $resultt = ''; $string = ''; $string = base64_decode(urldecode($urll)); for($i=0; $i<strlen($string); $i++) { $char = substr($string, $i, 1); $keychar = substr($key, ($i % strlen($key))-1, 1); $char = chr(ord($char)-ord($keychar)); $resultt.=$char; } echo '<br />DEC: '. $resultt; So how to encode and decode url. Thanks

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  • PHP Getting XPath of a DOMNode

    - by user256007
    I am creating an XML document on the fly. and I need to know the XPath of the Node I've just created. I don't see any such function like DOMNode::calculateXPath(void):string and I am not willing to write one by my own. is there any known lite 3rd party Solution ??

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  • PHP MySQLi and MySQLi_STMT: Which insert_id to use?

    - by Carvell Fenton
    Hello all, Both the MySQLi and MySQLi_STMT classes have an $insert_id property. If I am connected to my database using a MySQLi object (say $db), and then I perform an INSERT with a MySQLi_STMT object (say $stmt), to get the id of the last INSERT, should I use: $last_id = $db->insert_id; or $last_id = $stmt->insert_id; Or would they be the same, in which case it doesn't matter? I thought this might be a quick answer for someone, and save me the time of writing the test code to check it. Thanks in advance as always.

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  • How to display MySQL Select statement results in PHP

    - by Vafello
    I have the following code and it should return just one value (id) from mysql table. The following code doesnt work. How can I output it without creating arrays and all this stuff, just a simple output of one value. $query = "SELECT id FROM users_entity WHERE username = 'Admin' "; $result = map_query($query); echo $result;

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  • Get only new RSS entries with PHP Script ?

    - by ArneRie
    What im trying to do: Fetch X numbers of RSS Feeds from my Blogs and echo only new entries. My Problem is, how to know wich items are already parsed? Solution so far: Fetch the Feed every 5 hours, store all titles inside an Database table or flat file. Next run check if the title is already in database if not print it and save it inside the database. But iam not sure if this is best practise to do this? If someone knows a fast way, it would be great. Sorry for my poor english.

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  • PHP/mySQL - using result from 'CONCAT' and 'AS' in 'LIKE' clause

    - by Phil Jackson
    Hi I have the following code; if( ! empty( $post['search-bar'] ) ) { $search_data = preg_replace("#\s\s#is", '', preg_replace("#[^\w\d\s+]#is", '', $post['search-bar'] ) ); $data_array = explode( " ", $search_data ); $data_array = "'%" . implode( "%' OR '%", $data_array ) . "%'"; $query = "SELECT CONCAT( PROFILE_PROFFESION, FIRST_NAME, LAST_NAME, DISPLAY_NAME) AS 'STRING' FROM `" . ACCOUNT_TABLE . "` WHERE STRING LIKE ( " . $data_array . " ) AND BUSINESS_POST_CODE LIKE '" . substr(P_BUSINESS_POST_CODE, 0, 4) . "%'"; $q = mysql_query( $query, $CON ) or die( "_error_" . mysql_error() ); if( mysql_num_rows( $q ) != 0 ) { die(); } } Problem is I want to use the temp col 'STRING' in the where clause but is returning 'unknown coloumn STRING Can any one point me in the right direction, regards Phil

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  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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  • PHP does not store all variables in session

    - by Flurin Juvalta
    Dear all I'm assigning session variables by filling the $_SESSION - Array throughout my script. My problem is, that for some reason not all variables are available in the session. here is a shortened version of my code for explaining this issue: session_start(); print_r($_SESSION); $_SESSION['lang'] = 'de'; $_SESSION['location_id'] = 11; $_SESSION['region_id'] = 1; $_SESSION['userid'] = 'eccbc87e4b5ce2fe28308fd9f2a7baf3'; $_SESSION['hash'] = 'dce57f1e3bc6fba32afab93b0c38b662'; print_r($_SESSION); first call prints something like this: Array ( ) Array ( [lang] => de [location_id] => 11 [region_id] => 1 [userid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [hash] => dce57f1e3bc6fba32afab93b0c38b662 ) the second call prints: Array ( [lang] => de [location_id] => 11 [region_id] => 1 ) Array ( [lang] => de [location_id] => 11 [region_id] => 1 [userid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [hash] => dce57f1e3bc6fba32afab93b0c38b662 ) As you can see, the important login information is not stored in the session. Does anybody has an idea what could be wrong with my session? Thanks for your answers!

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  • How can get autosuggest in cake php

    - by rajesh
    i hav entered my code in controller like below function keyup(){ $this-Note-simple(); if(strlen($searchq)0){ while ($row = mysql_fetch_array($getRecord)) { echo $row['name']; echo $row['department']; } return $row; } } as soon as i entered this one it doesn't display any info .... what correction should require.......

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  • PHP problem with die()

    - by ThinkingInBits
    So, I have this code: } else { $photograph_moderation = new PhotographModeration($this->photograph_id); $photograph_moderation->purgePhotograph(); //eventually take to an error page die('image is not big enough to upload'); } the purgePhotograph() function gets called properly when this condition is met, but the script never appears to die. Is there a reason why die wouldn't get called here? purgePhotograph() has no script killing commands either.

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