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  • PHP & MySQL Image deletion problem?

    - by IMAGE
    I have this script that deletes a users avatar image that is stored in a folder name thumbs and another named images and the image name is stored in a mysql database. But for some reason the script deletes all the users info for example if the users id is 3 all of the users info like first name last name age and so are deleted as well, basically everything is deleted including the user how do I fix this so only the images and image name is deleted? Here is the code. $user_id = '3'; if (isset($_POST['delete_image'])) { $a = "SELECT * FROM users WHERE avatar = '". $avatar ."' AND user_id = '". $user_id ."'"; $r = mysqli_query ($mysqli, $a) or trigger_error("Query: $a\n<br />MySQL Error: " . mysqli_error($mysqli)); if ($r == TRUE) { unlink("../members/" . $user_id . "/images/" . $avatar); unlink("../members/" . $user_id . "/images/thumbs/" . $avatar); $a = "DELETE FROM users WHERE avatar = '". $avatar ."' AND user_id = '". $user_id ."'"; $r = mysqli_query ($mysqli, $a) or trigger_error("Query: $a\n<br />MySQL Error: " . mysqli_error($mysqli)); } }

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  • Add links to specific words within span tag in PHP

    - by dazhall
    I have a list of words that I'd like to add a link to, I can do this fairly easily using preg_match_all and preg_replace: $str = "<span class=\"cz\">Dám si jedno pivo prosím.</span> = I'll have a beer please."; preg_match_all('/[a-ztúuýžácdéeínórš]+/i',$str,$matches); $matches = array_unique($matches[0]); foreach ($matches as $match) { if(!empty($words[$match])) { $str = preg_replace("/(^|[^\w]){1}(".preg_quote($match,"/").")($|[^\w]){1}/i", '\\1<a href="#">\\2</a>\\3', $str); } } echo $str; What I'd like to do is restrict the linking to only within the span tag. My brain is all regex-ed out, so any help would be appreciated! Thanks! Darren.

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  • PHP Array To Class Static Public Values.

    - by what
    I want to make a class that has all the values of an array as a static object in that class. For example: $vars=array(... );//some array with actual values $Class_code='class MyClass{'; for($i=0; $i<count($vars); $i++){ $Class_code.='static public $'.strval($vars[i]).';'; } eval($Class_code.'}'); /* When I echo the line above it says that the vars for MyClass (MyClass::vars) are missing even with strval(). */ So, how can I get $vars[i] to be a string if strval didn't work?

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  • php, sql selection

    - by cosy
    I have a stupid question, I have this table : id_product name value 1 price 10-20 1 type computer 2 price 20-30 3 price 100-200 and I want to select from this table GROUP BY id_product and ORDER BY value WHERE name='price' how can i do this? Thanks a lot

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  • PHP SQL Form Insert

    - by Prateek Sachan
    I've developed a form that inserts many things into the database. But somehow, when the page is filled up; it inserts only the user_password that too of the database admin. here is the code. Any help would be great. Invalid Name: We want names with more than 3 letters. Invalid E-mail: Type a valid e-mail please. Passwords are invalid: Passwords doesnt match or are invalid! Please enter your contact number. Please enter your age Congratulations! All fields are OK ;)

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  • Strange problem with PHP and sessions

    - by Jhorra
    So the basis of this page is I set a session value when the page loads, and clear it on any other page they visit. Then the page can make an ajax call to download a file. If the session value matches the value I pass through the URL I allow them to download the file. If not I return a 404 error. I was having some weird issues, so I removed the 404 and set it to echo out the values instead to see what I was getting. Here is the top of the code on the page: $code = $this->_request->getParam('code'); $confirm = $_SESSION['mp3_code']; echo $code."-1-".$confirm; if($code != $confirm) echo $code."-2-".$confirm;//header("HTTP/1.1 404 Not Found"); else { Here is what displays on the page from the ajax call 12723430-1-12723430-2- As you can see when it echos out the first time they exist, then somehow after I compare them and it fails you see that it echos out blank values like they suddenly ceased to exist. Any ideas?

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  • PHP Transferring Photos From One Oracle Database Table to Another

    - by Jonathan Swift
    I am attempting to transfer a set of photos (blobs) from one table to another across databases. I'm nearly there, except for binding the photo parameter. I have the following code: $conn_db1 = oci_pconnect('username', 'password', 'db1'); $conn_db2 = oci_pconnect('username', 'password', 'db2'); $parse_db1_select = oci_parse($conn_db1, "SELECT REF PID, BINARY_OBJECT PHOTOGRAPH FROM BLOBS"); $parse_db2_insert = oci_parse($conn_db2, "INSERT INTO PHOTOGRAPHS (PID, PHOTOGRAPH) VALUES (:pid, :photo)"); oci_execute($parse_db1_select); while ($row = oci_fetch_assoc($parse_db1_select)) { $pid = $row['PID']; $photo = $row['PHOTOGRAPH']; oci_bind_by_name($parse_db2_insert, ':pid', $pid, -1, OCI_B_INT); // This line causes an error oci_bind_by_name($parse_db_insert, ':photo', $photo, -1, OCI_B_BLOB); oci_execute($parse_db2_insert); } oci_close($db1); oci_close($db2); But I get the following error, on the error line commented above: Warning: oci_execute() [function.oci-execute]: ORA-03113: end-of-file on communication channel Process ID: 0 Session ID: 790 Serial number: 118 Does anyone know the right way to do this?

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  • PHP problem with die()

    - by ThinkingInBits
    So, I have this code: } else { $photograph_moderation = new PhotographModeration($this->photograph_id); $photograph_moderation->purgePhotograph(); //eventually take to an error page die('image is not big enough to upload'); } the purgePhotograph() function gets called properly when this condition is met, but the script never appears to die. Is there a reason why die wouldn't get called here? purgePhotograph() has no script killing commands either.

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  • php count rss entries since a specific date/time

    - by Steven
    can anyone tell me why this code don't work: $q = $_GET['q']; // Load and parse the XML document $rss = simplexml_load_file("http://search.twitter.com/search.atom?lang=en&q=$q&rpp=100&page=1"); $Count1 = 0; while(strtotime($rss->entry->published)>1270833600){ foreach ($rss->entry as $item) { $Count1++; } } print "Total Record: ".$Count1;

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  • PHP XML encoding

    - by Jeremey
    I need a function that will convert € or chr(0x20AC) or chr(8364) to € without having a static map. I tried using htmlentities(), but it only seems to work for the symbol itself and it converts to €

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  • PHP: json_decode dumping NULL, BOM not found

    - by SerEnder
    I've been trying to find out why this 'json_encode'd string isn't parsing out correctly, and came across previously answered questions that had the UTF BOM sequence that was throwing the error, but didn't help me here. Here's the code that isn't currently working: //Decode the notes attached to the sig $aNotes = json_decode($rule->getNotes(),true); $bom = pack("CCC",0xef,0xbb,0xbf); if(0 == strncmp($rule->getNotes(),$bom,3)) { print('BOM detected - json encoding in UTF-8<br/>'); } else { print('BOM NOT detected - json encoding correctly<br/>'); } print('rule->getNotes:<br/>' . $rule->getNotes() .'<br/>'); var_dump($aNotes); Which generates this result: BOM NOT detected - json encoding correctly rule->getNotes: [{"lDate":"Unknown","sAuthor":"Unknown","sNote":"This is a general purpose Russian spam rule that matches anything starting with 2, 3 or 4 hex digits followed by a domain name ending with .ru -RSK 2010-05-10"},{"lDate":"1295031463082","sAuthor":"Drew Thorstenson","sNote":"this is Ryan's ru rule"}] NULL I've run it through JSON Lint, which said it was valid, and An Online JSON Parser which parsed it correctly too. Any insight would be greatly appreciated.

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  • How to build unlimited level of menu through PHP and mysql

    - by Starx
    Well, to build my menu my menu I use a db similar structure like this To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field. parent 0 means top menu now there is not problem while creating submenu inside another submenu now this is way I fetch the submenu for the top menu <ul class="topmenu"> <? $list = $obj -> childmenu($parentid); //this list contains the array of submenu under $parendid foreach($list as $menu) { extract($menu); echo '<li><a href="#">'.$name.'</a></li>'; } ?> </ul> What I want to do is. I want to check if a new menu has other child menu and I want to keep on checking until it searches every child menu that is available and I want to display its child menu inside its particular list item like this Home ........

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  • Transform RSS-Feed into another "standard" XML-Format with PHP

    - by ChrisBenyamin
    Hey friends, quick question: I need to transform a default RSS Structure into another XML-format. The RSS File is like.... Name des RSS Feed Feed Beschreibung de http://xml-rss.de Sat, 1 Jan 2000 00:00:00 GMT Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 Titel der Nachricht Die Nachricht an sich http://xml-rss.de/link-zur-nachricht.htm Sat, 1. Jan 2000 00:00:00 GMT 01012000-000000 ...and I want to extract only the item-elements (with childs and attributes) XML like: <?xml version="1.0" encoding="ISO-8859-1"?> <item> <title>Titel der Nachricht</title> <description>Die Nachricht an sich</description> <link>http://xml-rss.de/link-zur-nachricht.htm</link> <pubDate>Sat, 1. Jan 2000 00:00:00 GMT</pubDate> <guid>01012000-000000</guid> </item> ... It hasn't to be stored into a file. I need just the output. I tried different approaches with DOMNode, SimpleXML, XPath, ... but without success. Thanks chris

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  • change last key name from array in php

    - by robertdd
    i want to be able to change the last key from array i try with this function i made: function getlastimage($newkey){ $arr = $_SESSION['files']; $oldkey = array_pop(array_keys($arr)); $arr[$newkey] = $arr[$oldkey]; unset($arr[$oldkey]); $results = end($arr); //echo json_encode($results); print_r($arr); } if i call the function getlastimage('newkey') it change the key!but after if i print the $_SESSION the key is not changed? why this?

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  • PHP/WordPress Session CountDown

    - by Cameron
    I have the following code to show how long a user has left before their session will expire, I am using WordPress. How can I do this? Thanks <script> var obj_Span; var n_Seconds = 0; var n_Minutes = 0; var n_Hours = 0; function F_ConvertNumberToString ( n_Num ) { var str_Num = String(n_Num); if ( str_Num.length < 2 ) str_Num = "0" + str_Num; return str_Num; } function F_CountDown () { if ( n_Hours == 0 && n_Minutes == 0 && n_Seconds == 0 ) { obj_Span.innerHTML = "(Sorry, your session has expired.)"; } else { if ( n_Seconds >= 0 ) n_Seconds --; if ( n_Seconds < 0 ) { n_Minutes --; n_Seconds = 59; } if ( n_Minutes >= 0 ) { window.setTimeout ( "F_CountDown()", 1000 ); } if ( n_Minutes < 0 ) { n_Hours --; n_Minutes = 59; window.setTimeout ( "F_CountDown()", 1000 ); } F_UpdateDisplay (); } } function F_UpdateDisplay ( ) { if ( document.getElementById ) { if (n_Hours > 0 ) obj_Span.innerHTML = "(Remaining " + F_ConvertNumberToString(n_Hours) + ":" + F_ConvertNumberToString(n_Minutes) + ":" + F_ConvertNumberToString(n_Seconds) + ")"; else obj_Span.innerHTML = "(Remaining " + F_ConvertNumberToString(n_Minutes) + ":" + F_ConvertNumberToString(n_Seconds) + ")"; } } function F_StartCountDown ( n_Session ) { obj_Span = document.getElementById ( "CountDown" ); n_Minutes = n_Session; n_Hours = Math.floor(n_Minutes/60); n_Minutes = n_Minutes - (60*n_Hours); F_CountDown (); } </script> <script> F_StartCountDown ( " code here... " ); </script> <span id="CountDown"></span>

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  • Using preg_replace to replace all occurrences in php

    - by Greg-J
    Regex is absolutely my weak point and this one has me completely stumped. I am building a fairly basic search functionality and I need to be able to alter my user input based on the following pattern: Subject: %22first set%22 %22second set%22-drupal -wordpress Desired output: +"first set" +"second set" -drupal -wordpress I wish I could be more help as I normally like to at least post the solution I have so far, but on this one I'm at a loss. Any help is appreciated. Thank you.

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  • Organize array in PHP from mysql

    - by Matthew Carter
    Hi i have a social networking website. what i want it to do is pull out my friends status updates. basically what it does is i have a mysql query that pulls out all of my friends and in that while loop there is another mysql query that pulls out the status's from my friends. i want it to be in order of date but since its one while loop in another what it does is pull out all status's from friend 1 then 2 then 3 and not in order by date. i even tried ORDER BY DATE but that just ordered it by date within the friend.. my thought is that i could putt it all in an array and friends is one thing and the values is the stats. then just sort by values would this work and how could i do it. THANKS SO MUCH

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  • PHP/mySQL - using result from 'CONCAT' and 'AS' in 'LIKE' clause

    - by Phil Jackson
    Hi I have the following code; if( ! empty( $post['search-bar'] ) ) { $search_data = preg_replace("#\s\s#is", '', preg_replace("#[^\w\d\s+]#is", '', $post['search-bar'] ) ); $data_array = explode( " ", $search_data ); $data_array = "'%" . implode( "%' OR '%", $data_array ) . "%'"; $query = "SELECT CONCAT( PROFILE_PROFFESION, FIRST_NAME, LAST_NAME, DISPLAY_NAME) AS 'STRING' FROM `" . ACCOUNT_TABLE . "` WHERE STRING LIKE ( " . $data_array . " ) AND BUSINESS_POST_CODE LIKE '" . substr(P_BUSINESS_POST_CODE, 0, 4) . "%'"; $q = mysql_query( $query, $CON ) or die( "_error_" . mysql_error() ); if( mysql_num_rows( $q ) != 0 ) { die(); } } Problem is I want to use the temp col 'STRING' in the where clause but is returning 'unknown coloumn STRING Can any one point me in the right direction, regards Phil

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  • How to display MySQL Select statement results in PHP

    - by Vafello
    I have the following code and it should return just one value (id) from mysql table. The following code doesnt work. How can I output it without creating arrays and all this stuff, just a simple output of one value. $query = "SELECT id FROM users_entity WHERE username = 'Admin' "; $result = map_query($query); echo $result;

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  • PHP does not store all variables in session

    - by Flurin Juvalta
    Dear all I'm assigning session variables by filling the $_SESSION - Array throughout my script. My problem is, that for some reason not all variables are available in the session. here is a shortened version of my code for explaining this issue: session_start(); print_r($_SESSION); $_SESSION['lang'] = 'de'; $_SESSION['location_id'] = 11; $_SESSION['region_id'] = 1; $_SESSION['userid'] = 'eccbc87e4b5ce2fe28308fd9f2a7baf3'; $_SESSION['hash'] = 'dce57f1e3bc6fba32afab93b0c38b662'; print_r($_SESSION); first call prints something like this: Array ( ) Array ( [lang] => de [location_id] => 11 [region_id] => 1 [userid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [hash] => dce57f1e3bc6fba32afab93b0c38b662 ) the second call prints: Array ( [lang] => de [location_id] => 11 [region_id] => 1 ) Array ( [lang] => de [location_id] => 11 [region_id] => 1 [userid] => eccbc87e4b5ce2fe28308fd9f2a7baf3 [hash] => dce57f1e3bc6fba32afab93b0c38b662 ) As you can see, the important login information is not stored in the session. Does anybody has an idea what could be wrong with my session? Thanks for your answers!

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