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  • adding a toolbar to a pickerview

    - by devb0yax
    Hi, How I could able to add a toolbar to the picker? I want above the picker there is a toolbar with a "done" bar button item. clicking the "done" button will hide (animate) the picker offscreen (going to bottom like the keyboard) I'm still looking for this how-to... Hope you could help me. Thanks

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  • Javascript update before page loads in ASP.NET

    - by user204588
    Hello, I'm trying to update values from a xml file into textboxes. I have this javascript being called in the Page_Load event this.Page.ClientScript.RegisterStartupScript(this.GetType(), "Script", sb.ToString(), true); I click the continue button which does a post back but the values are not updated until I refresh the page again which makes me think the js isn't being run until after the page is returned. I'm wondering how to have the values updated when the page is refreshed after the button postback. thanks

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  • synchronously load html content in UIWebView

    - by mbg1987
    im using a UIWebView to show html content in my app, the app contains two arrows to navigate between topics just like a RSS reader app, but when the user hits up or down arrow, the next topic doesn't show up until the data come back and the user still able to interact with the UI which is a bit confusing, My question: how to block the UI when user moves to the next/back topic ? in other words how to make loadHTMLString:baseURL: works as a synchronous calling ? thanks !

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  • jquery animation problem using stop

    - by Flanders
    Hi! When running a Jquery animation like slideDown(), it looks like a number of element-specific css properties is set to be updated at a specific interval and when the animation is complete these properties are unset and the display property is simply set to auto or whatever. At least in firebug you can't see those temporary properties any more. The problem I've encountered is the scenario where we stop the slide down with stop(). The element is then left with the current temporary css values. Which is fine because it has to, but let us say that I stoped the slidedown because I have decided to slide it back up again a bit prematurely. It would look something like this: $(this).slideDown(2000) //The below events is not in queue but will rather start execute almost simultaneously as the above line. (dont remember the exact syntax) $(this).delay(1000).stop().slideUp(2000) The above code might not make much sense, but the point is: After 1 second of sliding down the animation is stopped and it starts to slide back up. Works like a charm. BUT!!! And here is the problem. Once it it has slid back up the elements css properties are reset to the exact values it had 1000ms into the slideDown() animation (when stop() was called). If we now try to run the following: $(this).slideDown(2000) It will slide down to the very point the prior slideDown was aborted and not further at half the speed (since it uses the same time for approximately half the height). This is because the css properties were saved as I see it. But it is not especially wished for. Of course I want it to slide all the way down this time. Due to UI interaction that is hard to predict everything might soon break. The longer animations we use increases the risk of something like this happening. Is this to be considered a bug, or am I doing something wrong? Or maybe it's just a feature that is not supported? I guess I can use a callback function to reset the css properties, but depending on the animation used, different css properties are used to render it, and covering your back would result in quite a not-so-fancy solution.

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  • Problem in understanding connectSlotsByName() in pyqt???

    - by Jebagnanadas
    Hi all, I couldn't understand the connectSlotsByName() method which is predominently used by pyuic4.. As far the class is single in a PyQt file it's ok since we can use self which will be associated with a single object throughout.. But when we try to use various classes from different files the problem and the need to use connectSlotsByName() arises.. Here's what i encountered which is weird.. I created a stacked widget.. I placed my first widget on it.. It has a button called "Next ". On clicking next it hides the current widget and adds another widget which has the "click me" button.. The problem here is the click event for "click me" button in second is not captured.. It's a minimal example that i can give for my original problem.. Please help me.. This is file No.1..(which has the parent stacked widget and it's first page). On clicking next it adds the second page which has "clickme" button in file2.. from PyQt4 import QtCore, QtGui import file2 class Ui_StackedWidget(QtGui.QStackedWidget): def __init__(self,parent=None): QtGui.QStackedWidget.__init__(self,parent) self.setObjectName("self") self.resize(484, 370) self.setWindowTitle(QtGui.QApplication.translate("self", "stacked widget", None, QtGui.QApplication.UnicodeUTF8)) self.createWidget1() def createWidget1(self): self.page=QtGui.QWidget() self.page.setObjectName("widget1") self.pushButton=QtGui.QPushButton(self.page) self.pushButton.setGeometry(QtCore.QRect(150, 230, 91, 31)) self.pushButton.setText(QtGui.QApplication.translate("self", "Next >", None, QtGui.QApplication.UnicodeUTF8)) self.addWidget(self.page) QtCore.QMetaObject.connectSlotsByName(self.page) QtCore.QObject.connect(self.pushButton,QtCore.SIGNAL('clicked()'),self.showWidget2) def showWidget2(self): self.page.hide() obj=file2.widget2() obj.createWidget2(self) if __name__ == "__main__": import sys app = QtGui.QApplication(sys.argv) ui = Ui_StackedWidget() ui.show() sys.exit(app.exec_()) Here's file2 from PyQt4 import QtGui,QtCore class widget2(): def createWidget2(self,parent): self.page = QtGui.QWidget() self.page.setObjectName("page") self.parent=parent self.groupBox = QtGui.QGroupBox(self.page) self.groupBox.setGeometry(QtCore.QRect(30, 20, 421, 311)) self.groupBox.setObjectName("groupBox") self.groupBox.setTitle(QtGui.QApplication.translate("self", "TestGroupBox", None, QtGui.QApplication.UnicodeUTF8)) self.pushButton = QtGui.QPushButton(self.groupBox) self.pushButton.setGeometry(QtCore.QRect(150, 120, 92, 28)) self.pushButton.setObjectName("pushButton") self.pushButton.setText(QtGui.QApplication.translate("self", "Click Me", None, QtGui.QApplication.UnicodeUTF8)) self.parent.addWidget(self.page) self.parent.setCurrentWidget(self.page) QtCore.QMetaObject.connectSlotsByName(self.page) QtCore.QObject.connect(self.pushButton,QtCore.SIGNAL('clicked()'),self.printMessage) def printMessage(self): print("Hai") Though in both the widgets(i mean pages) QtCore.QMetaObject.connectSlotsByName(self.page) the clicked signal in second dialog isn't getting processed. Thanks in advance.. Might be a beginner question..

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  • Onclick not added until after Postback

    - by Morph
    I have the following: <asp:Button id="SubmitButton" Text="Submit" runat="server" OnClientClick="Do();" OnClick="SubmitButton_Click"/> When the page is first rendered, I go to the view source in my browser and see that the onclick="Do();" is not added to my submit button tag. But when I do a post back, and do the view source again, the onclick is added to the submit. Why would the onclick not be there on the first request?

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  • how can I reset field after check it with php

    - by mjd
    Hi all, I have a html form that sends the data from 2 fields (memer no. , pw) via axaj (getElementById)to php file to check them with database info. . I did every thing well but I want to reset both fields if one of them is incorrect . How can I send reset order back to html form ? notice - I didn't use submit button just normal button to keep in same page. Thanks all

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  • Need help with text animation within UITableViewCell

    - by gdiphone
    I'm trying to implement a simple text animation in a custom UITableViewCell without having to go into editing mode which automatically brings up the delete button on the right. What I'm trying to accomplish is that when the label is updated by a button within the UITableviewcell, the text in the label is updated but with some smooth animation like sliding to the right since the updated text is prepended to the string. Any sample code would be great. thanks

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  • Accessing datagrid cell in ajavascript

    - by Anil
    Datagrid is in content,When trying to access client side function for the cells in the datagrid,its always showing at 0 position suppose i have 10 rows,for each row "Test button" i should invoke the client side java script. For each row "Test button" client side script is displaying message at first row only.

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  • Problem with File uplolad in javascript.

    - by Nikhil
    I have used javascript to upload more than one file. when user clicks on 'add more' javascript appends new object to older div using innerHTML. Now the problem is if I select a file and then click on "add more" then new file button exist but older selected file removes and two blank file buttons display. I want this old file must be selected when user add new file button. If anybody can, Help Plz!!! tnX.

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  • Pausing and restarting an Animation

    - by Sandeep
    I'm running a CAKeyframeAnimation in a subclass of UIViewController. I want to pause the animation on pressing a "Pause" button and start back from where it paused on pressing a "Resume" button. I've come across an answer to a similar question on this site, but it doesn't work for me. I would appreciate any help.

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  • problem in presentmodelviewcontroller?

    - by Bala
    i am using tabbarcontroller. In tabbar having one view.In that tab i call one function using Nstimer it open another viewcontroller. First * sVC = [[First alloc] initWithNibName:@"First" bundle:[NSBundle mainBundle]]; [self presentModalViewController:sVC animated:YES]; Opened viewcontrller having one button.when user click that button i want to close the view and call Nstimer. [self dismissModalViewControllerAnimated:NO] The problem is first the view opened and closed but second time view could not open.

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  • Validation is not working

    - by Joby Kurian
    hi...I have one asp content page.Its contain many controls like dropdownlist,textbox etc.All controls are inside a div tag.I gave required field validator for all my drop down list.i have one SAVE button that reside inside another div tag.I gave SAVE button cause validation true.But my problem is that, the validator is not working and the page.Isvalid property is true.What is the problem with my code?

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  • Keep Jquery dialog State after poseback

    - by shaahin
    Hi i have a dialog that made by jquery in this dialog i have asp button that save information in database but when i pust the button the page will be poseback and dialog will be close but i want to keep dialog state how can i do that cheers shaahin please give me an example

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  • Java ActionListener buttonPress() restriction

    - by Extinct23
    Is there a way to restrict this button to only being impressed once? The reason I ask is because for some reasons every time the button is pressed it disrupts the rest of my code. So in effort to save a massive amount of time debugging, it would be much easier to just somehow restrict the number of times it can be pressed. Thanks in advance. ActionListener pushButton = new buttonPress(); start.addActionListener(pushButton);

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  • write jquery plugin

    - by tazphoenix
    hi.i wrote a jquery function and now i want to use it as a plugin so i could use that more than 1 place.the code lookes like this: function loadTable(){ $.post("includes/action.php", {action: "gettable"}, function(html){ $("#tblstudents tbody").html(html); $("#tblstudents") .tablesorter({widthFixed: false, widgets: ['zebra'], sortList: [[0,0]]}) .tablesorterPager({container: $("#pager")}) .tablesorterFilter({filterContainer: $("#filter-box"), filterClearContainer: $("#filter-clear-button")}); }); } And I want it have functions for setting "includes/action.php" and "gettable" in $.post function and $("#pager") ,$("#filter-box") and $("#filter-clear-button") from $("#tblstudents").Can anyone help me?

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  • How to get password html helper to render password on failed validation

    - by Max Schmeling
    I have a form for creating a new account and it has a password field in it. I'm using view models to pass data to the controller action and back to the form view. When the user enters their details in, and clicks submit, if validation fails and it returns them to the same view passing back in the view model, it won't default the password to what they entered. How can I get it to do this? Or should I even try?

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  • Displaying validation control in a div tag

    - by JaiGanesh
    I have a div tag for which i have defined a border. i have given the validation control inside the div tag Now before clicking the "submit" i get to see the div tag and border. - how to avoid this Now after clicking the "submit" i get to see the div tag and border- which is exptected and correct. My question how to hide the border in the div tag before clicking the "submit" button or on the click of the "cancel" button

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  • Long numbers. Division.

    - by user577395
    Hello, world! I have a problem. Today I tried to create a code, which finds Catalan number. But in my program can be long numbers. I found numerator and denominator. But i can't div long numbers! Also, only standard libraries was must use in this program. Help me please. This is my code #include <vector> #include <iostream> using namespace std; int main(int argc, char *argv[]) { const int base = 1000*1000*1000; vector <int> a, b; int n, carry = 0; cin>>n; a.push_back(n); for (int ii=n+2; ii!=(2*n)+1;++ii) { carry = 0; for (size_t i=0; i<a.size() || carry; ++i) { if (i == a.size()) a.push_back (0); long long cur = carry + a[i] * 1ll * ii; a[i] = int (cur % base); carry = int (cur / base); } } while (a.size() > 1 && a.back() == 0) a.pop_back(); b.push_back(n); for (int ii=1; ii!=n+1;++ii) { carry = 0; for (size_t i=0; i<b.size() || carry; ++i) { if (i == b.size()) b.push_back (0); long long cur = carry + b[i] * 1ll * ii; b[i] = int (cur % base); carry = int (cur / base); } } while (b.size() > 1 && b.back() == 0) b.pop_back(); cout<<(a.empty() ? 0 : a.back()); for (int i=(int)a.size()-2; i>=0; --i) cout<<(a[i]); cout<<" "; cout<<(b.empty() ? 0 : b.back()); for (int i=(int)b.size()-2; i>=0; --i) cout<<(b[i]); //system("PAUSE"); cout<<endl; return 0; } P.S. Sorry for my bad english =)

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