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  • Selecting Date Range on a PHP form and displaying results from MySQL database

    - by Sarah HSL
    This may be something simple but I cant understand why this wouldn't work.. I have a php form where you can select a date range from drop downs. I've given the field names day, month year, and day1, month1, year1. When clicking submit it takes you to a second php form. Here is the code for second form: <?php $username="***"; $password="***"; $database="****"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td><b><font face="Arial, Helvetica, sans-serif">Product Description</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Master Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Barcode</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Status</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">TimeStamp</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">New Own</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Serial No.</font></b></td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f6; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f7; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f8; ?></font></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> Is there any reason this wouldn't work? I'm not sure where I am going wrong. It displays results when there is another option as well as the date such as 'status' but when this is taken out and I just want to display all the results between the date range it doesn't work.. This works: <?php $username="+++"; $password="+++"; $database="+++"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $status = $_GET['status']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE status = '$status' AND curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td><b><font face="Arial, Helvetica, sans-serif">Product Description</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Master Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Barcode</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Status</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">TimeStamp</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">New Own</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Serial No.</font></b></td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f6; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f7; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f8; ?></font></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> But when the 'status' field is taken out (and obviously the serial drop down in the first form) it stops working...

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  • Servlet Security question about j_security_check, j_username and j_password

    - by Nitesh Panchal
    Hello, I used jdbcRealm in my web application and it's working fine. I defined all constraints also in my web.xml. Like all pages of url pattern /Admin/* should be accessed by only admin. I have a login form with uses standard j_security_check, j_username and j_password. Now, when i type Admin/home.jsf it rightly redirects me login.jsf and there when i type the password i am redirected to home.jsf. This works alright but problem comes i directly go to login.jsf and then type password and username. This time it again redirects me to login.jsf. Is there any way through which i can specify which page to go when successful login is there? I need to specify different different pages for different roles. For Admin, it is /Admin/home.jsf for general users it is /General/home.jsf because login form is shared between different type of users. Where do i specify all these things? Secondly, i want to have a remember me checkbox at the end of login form. How do i do this? By default, it is submitted to j_security_check servlet and i have no control over its execution. Please help. This doesn't seem so hard but looks like i am missing something.

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  • Attempted to render a circle in opengl es 1.1, renders as oval

    - by eipxen
    Hi all, I attempted to render a circle in opengl es 1.1 as a test before building a larger program, but it renders as an oval. Here is the code I use to generate and render my vertices: static const int numVerts = 40; static GLfloat myFirstCircle[82]; myFirstCircle[0] = 0.0f; myFirstCircle[1] = 0.0f; for (int i = 2; i < (numVerts+1)*2; i+=2) { myFirstCircle[i] = .5 * cosf(i*2*3.14159/numVerts); myFirstCircle[i+1] = .5 * sinf(i*2*3.14159/numVerts); } glVertexPointer(2, GL_FLOAT, 0, myFirstCircle); glEnableClientState(GL_VERTEX_ARRAY); glDrawArrays(GL_TRIANGLE_FAN, 0, 22); I'm still somewhat new to this system, so I may have a silly error that I do not see, but it seems to me like this should generate 40 vertices on a circle of radius .5. When it renders, the shape on screen appears to be an oval, significantly taller than it is wide. My question is thus: why is my circle rendering this way, and what could I do to fix it? This is the first question on stackoverflow, so I'm not sure how to share an image of my output.

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  • Is there a FAST way to export and install an app on my phone, while signing it with my own keystore?

    - by Alexei Andreev
    So, I've downloaded my own application from the market and installed it on my phone. Now, I am trying to install a temporary new version from Eclipse, but here is the message I get: Re-installation failed due to different application signatures. You must perform a full uninstall of the application. WARNING: This will remove the application data! Please execute 'adb uninstall com.applicationName' in a shell. Launch canceled! Now, I really really don't want to uninstall the application, because I will lose all my data. One solution I found is to Export my application, creating new .apk, and then install it via HTC Sync (probably a different program based on what phone you have). The problem is this takes a long time to do, since I need to enter the password for the keystore each time and then wait for HTC Sync. It's a pain in the ass! So the question is: Is there a way to make Eclipse automatically use my keystore to sign the application (quickly and automatically)? Or perhaps to replace debug keystore with my own? Or perhaps just tell it to remember the password, so I don't have to enter it every time...? Or some other way to solve this problem?

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  • Javascript CS-PRNG - 64-bit random

    - by Jack
    Hi, I need to generate a cryptographically secure 64-bit unsigned random integer in Javascript. The first problem is that Javascript only allows 64-bit signed integers, so 9223372036854775808 is the biggest supported integer without going into floating point use I think? To fix this I can use a big number library, no problem. My Method: var randNum = SHA256( randBigInt(128, 0) ) % 2^64; Where SHA256() is a secure hash function and randBigInt() is defined below as a non-crypto PRNG, im giving it a 128bit seed so brute force shouldn't be a problem. randBigInt(n,s) //return an n-bit random BigInt (n>=1). If s=1, then the most significant of those n bits is set to 1. Is this a secure method to generate a cryptographically secure 64-bit random int? And importantly does taking the 2^64 mod guarantee 100% I have a 64-bit number? An abstract example, say this number is prime (it isn't i know), I will use it in the Galois Field [2^p], where p must be 64bits so that every possible 1-63bit number is a field element. In this query, my random int must be larger than any 63-bit number. And Im not sure im correct in taking the 2^64 mod of a 256bit hash output. Thanks (hope that makes sense)

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  • Accessing the value of an input element with XPath in an XSLT

    - by asymmetric
    Hi! I'm developing a web app that has a button that triggers an XSLT transformation of the document DOM, with a stylesheet fetched via AJAX. Here's a portion of the HTML: <html> <head> <title>Static Javascript-based XMR Form Creator</title> </head> <body> <h1 id="title">Static Javascript-based XMR Form Creator</h1> <div class="opt_block" id="main_opts"> Form name <input type="text" id="form_name" /> Form cols <input type="text" id="form_cols" size="3" maxlength="3" /> </div> <button id="generate">Generate source</button> <textarea rows="20" cols="50" id="xmr_source" ></textarea> </body> Inside the stylesheet, I want to access the value attribute of the first input field, the one with id form_name. The XSLT looks like this: <xsl:template match="/html/body/div[@id = 'main_opts']" > <form> <xsl:attribute name="fname"> <xsl:value-of select="input[@id = 'form_name']/@value" /> </xsl:attribute> </form> </xsl:template> The problem is that the XPath that should do the work: <xsl:value-of select="input[@id = 'form_name']/@value" /> returns nothing. Can anyone help?

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  • Ruby shortest/most efficient way to write rnd hex

    - by Whirlwin
    Hi. What I have is a method used to generate random hex values. E.g 666 or FF7 However, I don't think it is efficient at all.. What I want is to make it more efficient which perhaps will make my code shorter as well, but I don't know how. That is why I need tips or hints Here is my code so far: def random_values random_values = Array.new letters = ['A','B','C','D','E','F'] for i in 1..15 if i <= 9 random_values << i else random_values << letters[i-10] end end return random_values.shuffle[0].to_s + random_values.shuffle[0].to_s + random_values.shuffle[0].to_s end As you probably see, I do not generate random numbers. I just shuffle the array containing the values I want, meaning all the numbers in the array are unique, which is not needed, but was the easiest solution for me when I wrote the code. I am most concerned about the return line.. If only it was possible to write like: return 3.times { random_values.shuffle[0] } or return random_values.shuffle[0].to_s *3 Thanks in advance!

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  • How to get Tkinter to input text and submit with button

    - by Rob
    Hi I was wondering if anybody could help me submit code from the test fields to the login fields from Tkinter import * import tkMessageBox if ( __name__ == "__main__" ): import resources.lib.mechanize as mechanize mechanize # Start Browser br = mechanize.Browser(factory=mechanize.RobustFactory()) # User-Agent (Firefox) br.addheaders = [('User-agent', 'Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.0.6')] br.open('http://razetheworld.com/wp-login.php?redirect_to=http%3A%2F%2Frazetheworld.com') br.select_form(name="loginform") br['log'] = 'entryWidget_U must enter here' br['pwd'] = 'entryWidget_P must enter here' br.submit(name="wp-submit") print br.geturl() def displayText(): """ Display the Entry text value. """ global entryWidget_U global entryWidget_P if entryWidget_U.get().strip() == "": tkMessageBox.showerror("Tkinter Entry Widget", "Enter a Username") else: tkMessageBox.showinfo("Tkinter Entry Widget", "Text value =" + entryWidget_U.get().strip()) if entryWidget_P.get().strip() == "": tkMessageBox.showerror("Tkinter Entry Widget", "Enter a Password") else: tkMessageBox.showinfo("Tkinter Entry Widget", "Text value =" + entryWidget_P.get().strip()) if __name__ == "__main__": root = Tk() root.title("Tkinter Entry Widget") root["padx"] = 40 root["pady"] = 20 # Create a text frame to hold the text Label and the Entry widget textFrame_U = Frame(root) textFrame_P = Frame(root) #Create a Label in textFrame entryLabel = Label(textFrame_U) entryLabel["text"] = "Enter Username:" entryLabel.pack(side=LEFT) entryLabel = Label(textFrame_P) entryLabel["text"] = "Enter Password:" entryLabel.pack(side=LEFT) # Create an Entry Widget in textFrame entryWidget_U = Entry(textFrame_U) entryWidget_U["width"] = 50 entryWidget_U.pack(side=LEFT) entryWidget_P = Entry(textFrame_P) entryWidget_P["width"] = 50 entryWidget_P.pack(side=LEFT) textFrame_U.pack() textFrame_P.pack() button = Button(root, text="Login", command=#Run br.submit(name="wp-submit")) button.pack() root.mainloop()

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  • To OpenID or not to OpenID? Is it worth it?

    - by Eloff
    Does OpenID improve the user experience? Edit Not to detract from the other comments, but I got one really good reply below that outlined 3 advantages of OpenID in a rational bottom line kind of way. I've also heard some whisperings in other comments that you can get access to some details on the user through OpenID (name? email? what?) and that using that it might even be able to simplify the registration process by not needing to gather as much information. Things that definitely need to be gathered in a checkout process: Full name Email (I'm pretty sure I'll have to ask for these myself) Billing address Shipping address Credit card info There may be a few other things that are interesting from a marketing point of view, but I wouldn't ask the user to manually enter anything not absolutely required during the checkout process. So what's possible in this regard? /Edit (You may have noticed stackoverflow uses OpenID) It seems to me it is easier and faster for the user to simply enter a username and password in a signup form they have to go through anyway. I mean you don't avoid entering a username and password either with OpenID. But you avoid the confusion of choosing a OpenID provider, and the trip out to and back from and external site. With Microsoft making Live ID an OpenID provider (More Info), bringing on several hundred million additional accounts to those provided by Google, Yahoo, and others, this question is more important than ever. I have to require new customers to sign up during the checkout process, and it is absolutely critical that the experience be as easy and smooth as possible, every little bit harder it becomes translates into lost sales. No geek factor outweighs cold hard cash at the end of the day :) OpenID seems like a nice idea, but the implementation is of questionable value. What are the advantages of OpenID and is it really worth it in my scenario described above?

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  • What would be the best way to install (distribute) dynamic libraries in Mac OSX using CMake/Cpack ?

    - by YuppieNetworking
    Hello all, I have a project whose artifacts are two dynamic libraries, let's say libX.dylib and libY.dylib (or .so for linux distributions). There are no executables. Now I would like to distribute these libraries. Since I already use CMake to compile it, I looked at CPack and successfully generated .tgz and .deb packages for Linux. However, for Mac OSX I have no idea and the CPack Wiki about its generators did not help me much. I managed to generate a PackageMaker package, but as clearly stated at this packagemaker howto, there is no uninstall option when using this util. I then read a bit about Bundles, but I feel lost specially since I have no executable. Question: What is the correct way to generate a package for Mac OSX using CPack? My ideal scenario would be either something that installs as easily as a bundle or as a deb file in debian/ubuntu. Thanks for your help Edit One more detail: the code to one of these libraries is not open, so I can't expect the users to do a cmake; make; make install That's why I want a .deb, .tar.gz, bundle or whatsoever.

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  • how to let the parser print help message rather than error and exit

    - by fluter
    Hi, I am using argparse to handle cmd args, I wanna if there is no args specified, then print the help message, but now the parse will output a error, and then exit. my code is: def main(): print "in abing/start/main" parser = argparse.ArgumentParser(prog="abing")#, usage="%(prog)s <command> [args] [--help]") parser.add_argument("-v", "--verbose", action="store_true", default=False, help="show verbose output") subparsers = parser.add_subparsers(title="commands") bkr_subparser = subparsers.add_parser("beaker", help="beaker inspection") bkr_subparser.set_defaults(command=beaker_command) bkr_subparser.add_argument("-m", "--max", action="store", default=3, type=int, help="max resubmit count") bkr_subparser.add_argument("-g", "--grain", action="store", default="J", choices=["J", "RS", "R", "T", "job", "recipeset", "recipe", "task"], type=str, help="resubmit selection granularity") bkr_subparser.add_argument("job_ids", nargs=1, action="store", help="list of job id to be monitored") et_subparser = subparsers.add_parser("errata", help="errata inspection") et_subparser.set_defaults(command=errata_command) et_subparser.add_argument("-w", "--workflows", action="store_true", help="generate workflows for the erratum") et_subparser.add_argument("-r", "--run", action="store_true", help="generate workflows, and run for the erratum") et_subparser.add_argument("-s", "--start-monitor", action="store_true", help="start monitor the errata system") et_subparser.add_argument("-d", "--daemon", action="store_true", help="run monitor into daemon mode") et_subparser.add_argument("erratum", action="store", nargs=1, metavar="ERRATUM", help="erratum id") if len(sys.argv) == 1: parser.print_help() return args = parser.parse_args() args.command(args) return how can I do that? thanks.

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  • problem configure JBoss to work with JNDI(2)

    - by Spiderman
    in continuation to the question from last week: http://stackoverflow.com/questions/2828237/problem-configure-jboss-to-work-with-jndi I'm trying to bind datasource in JBoss and use it in my application. In my struggling, I already managed to avoid the javax.naming.NameNotFoundException by: 1. using in java new InitialContext().lookup(connection); instead of new JndiObjectFactoryBean().setJndiName(connection); 2. changing the connection name from: 'jndi-name' to 'java:jndi-name' Now the problem is that the datasouce that I get from the lookup is null. I created the datsource file: <datasources> <local-tx-datasource> <jndi-name>bilby</jndi-name> <connection-url>jdbc:oracle:myURL</connection-url> <driver-class>oracle.jdbc.OracleDriver </driver-class> <user-name>myUsername</user-name> <password>myPassword</password> <exception-sorter-class- name>org.jboss.resource.adapter.jdbc.vendor.OracleExceptionSorter</exception-sorter-class-name> <metadata> <type-mapping>Oracle9i</type-mapping> </metadata> </local-tx-datasource> </datasources> and put it under \server\default\deploy\oracle-ds.xml I get during runtime the line: 18:37:56,560 INFO [ConnectionFactoryBindingService] Bound ConnectionManager 'jb oss.jca:service=DataSourceBinding,name=bilby' to JNDI name 'java:bilby' So my question is - why do I get null as my datasource???

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  • PHP Transferring Photos From One Oracle Database Table to Another

    - by Jonathan Swift
    I am attempting to transfer a set of photos (blobs) from one table to another across databases. I'm nearly there, except for binding the photo parameter. I have the following code: $conn_db1 = oci_pconnect('username', 'password', 'db1'); $conn_db2 = oci_pconnect('username', 'password', 'db2'); $parse_db1_select = oci_parse($conn_db1, "SELECT REF PID, BINARY_OBJECT PHOTOGRAPH FROM BLOBS"); $parse_db2_insert = oci_parse($conn_db2, "INSERT INTO PHOTOGRAPHS (PID, PHOTOGRAPH) VALUES (:pid, :photo)"); oci_execute($parse_db1_select); while ($row = oci_fetch_assoc($parse_db1_select)) { $pid = $row['PID']; $photo = $row['PHOTOGRAPH']; oci_bind_by_name($parse_db2_insert, ':pid', $pid, -1, OCI_B_INT); // This line causes an error oci_bind_by_name($parse_db_insert, ':photo', $photo, -1, OCI_B_BLOB); oci_execute($parse_db2_insert); } oci_close($db1); oci_close($db2); But I get the following error, on the error line commented above: Warning: oci_execute() [function.oci-execute]: ORA-03113: end-of-file on communication channel Process ID: 0 Session ID: 790 Serial number: 118 Does anyone know the right way to do this?

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  • Five unique, random numbers from a subset

    - by tau
    I know similar questions come up a lot and there's probably no definitive answer, but I want to generate five unique random numbers from a subset of numbers that is potentially infinite (maybe 0-20, or 0-1,000,000). The only catch is that I don't want to have to run while loops or fill an array. My current method is to simply generate five random numbers from a subset minus the last five numbers. If any of the numbers match each other, then they go to their respective place at the end of the subset. So if the fourth number matches any other number, it will bet set to the 4th from the last number. Does anyone have a method that is "random enough" and doesn't involve costly loops or arrays? Please keep in mind this a curiosity, not some mission-critical problem. I would appreciate it if everyone didn't post "why are you having this problem?" answers. I am just looking for ideas. Thanks a lot!

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  • Cannot redeploy to remote tomcat 7 with using cargo-maven-plugin

    - by rottmanj
    I am attempting to build and redeploy to a remote tomcat 7 server using the cargo-maven plugin. I have been able to successfully deploy to the remote server, but all other actions fail. Here is the pluging settings in my pom.xml <plugin> <groupId>org.codehaus.cargo</groupId> <artifactId>cargo-maven2-plugin</artifactId> <version>1.1.1</version> <configuration> <!-- Container configuration --> <container> <containerId>tomcat7x</containerId> <type>remote</type> </container> <configuration> <type>runtime</type> <properties> <cargo.remote.username>tomcat</cargo.remote.username> <cargo.remote.password>tomcat</cargo.remote.password> <cargo.remote.uri>http://devserver:8080/manager/html</cargo.remote.uri> </properties> </configuration> </configuration> </plugin> This is the error I am seeing within eclipse, when I attempt to deploy. I posted it to pastebin so it is easier to read. Error link. Any help with this is greatly appreciated.

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  • Inserting variables into a query string - it won't work!

    - by Jonesy
    Basically i have a query string that when i hardcode in the catalogue value its fine. when I try adding it via a variable it just doesn't pick it up. This works: Dim WaspConnection As New SqlConnection("Data Source=JURA;Initial Catalog=WaspTrackAsset_NROI;User id=" & ConfigurationManager.AppSettings("WASPDBUserName") & ";Password='" & ConfigurationManager.AppSettings("WASPDBPassword").ToString & "';") This doesn't: Public Sub GetWASPAcr() connection.Open() Dim dt As New DataTable() Dim username As String = HttpContext.Current.User.Identity.Name Dim sqlCmd As New SqlCommand("SELECT WASPDatabase FROM dbo.aspnet_Users WHERE UserName = '" & username & "'", connection) Dim sqlDa As New SqlDataAdapter(sqlCmd) sqlDa.Fill(dt) If dt.Rows.Count > 0 Then For i As Integer = 0 To dt.Rows.Count - 1 If dt.Rows(i)("WASPDatabase") Is DBNull.Value Then WASP = "" Else WASP = "WaspTrackAsset_" + dt.Rows(i)("WASPDatabase") End If Next End If connection.Close() End Sub Dim WaspConnection As New SqlConnection("Data Source=JURA;Initial Catalog=" & WASP & ";User id=" & ConfigurationManager.AppSettings("WASPDBUserName") & ";Password='" & ConfigurationManager.AppSettings("WASPDBPassword").ToString & "';") When I debug the catalog is empty in the query string but the WASP variable holds the value "WaspTrackAsset_NROI" Any idea's why? Cheers, jonesy

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  • Why is this ajax call being made even though it shouldn't be

    - by user2921557
    i have this validation script im working on but cant see why im having an issue. You can see that i have a check = false / true, check before it runs the ajax call. However, even if a field is empty and check is set to false, it is still running the call. so: // JavaScript - Update Password AJAX $(document).ready(function () { // When the form is submitted $('.updatepasswordform').submit(function () { var check = true; // Get the values var password1 = $("input[name=password1]").val(); var password2 = $("input[name=password2]").val(); var newpassword = $("input[name=newpassword]").val(); /* Password Validation */ // If fields are empty if (password1 === '') { check = false; $("input[name=password1]").css('border', 'solid 2px red'); } // If fields are empty if (password2 === '') { check = false; $("input[name=password2]").css('border', 'solid 2px red'); } // If fields are empty if (newpassword === '') { check = false; $("input[name=newpassword]").css('border', 'solid 2px red'); } if (check = true) { $.ajax({ type: "POST", url: "process/updatepassword.php", data: $(".updatepasswordform").serialize(), dataType: "json", success: function (response) { /* Checks for database validation, removed for space saving */ } }); } return false; }); });

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  • Returning data from SQL Server reporting web service call

    - by user79339
    Hi, I am generating a report that contains the version number. The version number is stored in the DB and retrieved/incremented as part of the report generation. The only problem is, I am calling SSRS via a web service call, which returns the generated report as a byte array. Is there any way to get the version number out of this generated report? For example to display a dialog that says "You generated Status Report, Version number 3". I tried passing in an output parameter and setting it inside the storedproc. Its modified when i execute it in sql management studio, but not in the reporting studio. Or atleast i can't seem to bind to the modified, post execution value (using expression "=Parameters!ReportVersion.Value"). Of course, I could get/increment the version number from database myself before calling the SSRS webservice and pass it along as a parameter to the Report, but that might cause concurrancy problems. On the whole, it just seems neater for the storedproc to access/generate a version number and return it to the ReportingEngine, which will generate the report with the version number and return the updated version number to the WebService client. Any thoughts/Ideas?

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  • php code in FTP to backup db using URL

    - by Giom
    I fund and inserted this code in my FTP in a backup.php that works great but it copy the file into the root folder (homez/) 1- I would like to put these backup files in a homez/backupDB any idea where to put this path? 2- the db backup files (DB.sql.bz2) have always the same name, is it possible to name each one with the date of creation? (I launch this php with the URL link) <? echo "Votre base est en cours de sauvegarde....... "; $db="nom_de_ma_base"; $status=system("mysqldump --host=mysql5-1.perso --user=$_POST[login] --password=$_POST[password] $db > ../$db.sql"); echo $status; echo "Compression du fichier..... "; system("bzip2 -f ../$db.sql"); echo "C'est fini. Vous pouvez récupérer la base par FTP \n "; ?> Thanks!

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  • Finding a list of indices from master array using secondary array with non-unique entries

    - by fideli
    I have a master array of length n of id numbers that apply to other analogous arrays with corresponding data for elements in my simulation that belong to those id numbers (e.g. data[id]). Were I to generate a list of id numbers of length m separately and need the information in the data array for those ids, what is the best method of getting a list of indices idx of the original array of ids in order to extract data[idx]? That is, given: a=numpy.array([1,3,4,5,6]) # master array b=numpy.array([3,4,3,6,4,1,5]) # secondary array I would like to generate idx=numpy.array([1,2,1,4,2,0,3]) The array a is typically in sequential order but it's not a requirement. Also, array b will most definitely have repeats and will not be in any order. My current method of doing this is: idx=numpy.array([numpy.where(a==bi)[0][0] for bi in b]) I timed it using the following test: a=(numpy.random.uniform(100,size=100)).astype('int') b=numpy.repeat(a,100) timeit method1(a,b) 10 loops, best of 3: 53.1 ms per loop Is there a better way of doing this?

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  • Putting together CSV Cells in Excel with a macro

    - by Eric Kinch
    So, I have a macro to export data into CSV format and it's working great (Code at the bottom). The problem is the data I am putting into it. When I put the data in question in it comes out Firstname,Lastname,username,password,description I'd like to change it so I get Firstname Lastname,Firstname,Lastname,username,password,description What I'd like to do is manipulate my existing macro so to accomplish this. I'm not so good at VBS so any input or a shove in the right direction would be fantastic. Thanks! Sub Make_CSV() Dim sFile As String Dim sPath As String Dim sLine As String Dim r As Integer Dim c As Integer r = 1 'Starting row of data sPath = "C:\CSVout\" sFile = "MyText_" & Format(Now, "YYYYMMDD_HHMMSS") & ".CSV" Close #1 Open sPath & sFile For Output As #1 Do Until IsEmpty(Range("A" & r)) 'You can also Do Until r = 17 (get the first 16 cells) sLine = "" c = 1 Do Until IsEmpty(Cells(1, c)) 'Number of Columns - You could use a FOR / NEXT loop instead sLine = sLine & """" & Replace(Cells(r, c), ";", ":") & """" & "," c = c + 1 Loop Print #1, Left(sLine, Len(sLine) - 1) 'Remove the trailing comma r = r + 1 Loop Close #1 End Sub

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  • Building static (but complicated) lookup table using templates.

    - by MarkD
    I am currently in the process of optimizing a numerical analysis code. Within the code, there is a 200x150 element lookup table (currently a static std::vector < std::vector < double ) that is constructed at the beginning of every run. The construction of the lookup table is actually quite complex- the values in the lookup table are constructed using an iterative secant method on a complicated set of equations. Currently, for a simulation, the construction of the lookup table is 20% of the run time (run times are on the order of 25 second, lookup table construction takes 5 seconds). While 5-seconds might not seem to be a lot, when running our MC simulations, where we are running 50k+ simulations, it suddenly becomes a big chunk of time. Along with some other ideas, one thing that has been floated- can we construct this lookup table using templates at compile time? The table itself never changes. Hard-coding a large array isn't a maintainable solution (the equations that go into generating the table are constantly being tweaked), but it seems that if the table can be generated at compile time, it would give us the best of both worlds (easily maintainable, no overhead during runtime). So, I propose the following (much simplified) scenario. Lets say you wanted to generate a static array (use whatever container suits you best- 2D c array, vector of vectors, etc..) at compile time. You have a function defined- double f(int row, int col); where the return value is the entry in the table, row is the lookup table row, and col is the lookup table column. Is it possible to generate this static array at compile time using templates, and how?

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  • Trouble with building up a string in Clojure

    - by Aki Iskandar
    Hi gang - [this may seem like my problem is with Compojure, but it isn't - it's with Clojure] I've been pulling my hair out on this seemingly simple issue - but am getting nowhere. I am playing with Compojure (a light web framework for Clojure) and I would just like to generate a web page showing showing my list of todos that are in a PostgreSQL database. The code snippets are below (left out the database connection, query, etc - but that part isn't needed because specific issue is that the resulting HTML shows nothing between the <body> and </body> tags). As a test, I tried hard-coding the string in the call to main-layout, like this: (html (main-layout "Aki's Todos" "Haircut<br>Study Clojure<br>Answer a question on Stackoverfolw")) - and it works fine. So the real issue is that I do not believe I know how to build up a string in Clojure. Not the idiomatic way, and not by calling out to Java's StringBuilder either - as I have attempted to do in the code below. A virtual beer, and a big upvote to whoever can solve it! Many thanks! ============================================================= ;The master template (a very simple POC for now, but can expand on it later) (defn main-layout "This is one of the html layouts for the pages assets - just like a master page" [title body] (html [:html [:head [:title title] (include-js "todos.js") (include-css "todos.css")] [:body body]])) (defn show-all-todos "This function will generate the todos HTML table and call the layout function" [] (let [rs (select-all-todos) sbHTML (new StringBuilder)] (for [rec rs] (.append sbHTML (str rec "<br><br>"))) (html (main-layout "Aki's Todos" (.toString sbHTML))))) ============================================================= Again, the result is a web page but with nothing between the body tags. If I replace the code in the for loop with println statements, and direct the code to the repl - forgetting about the web page stuff (ie. the call to main-layout), the resultset gets printed - BUT - the issue is with building up the string. Thanks again. ~Aki

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  • Consume a JSON webservice and process data in Android

    - by user1783391
    I am trying to consume a the webservice below http://62.253.195.179/disaster/webservices/login.php?message=[{"email":"[email protected]","password":"welcome"}] This returns a JSON array [{"companyuserId":"2","name":"ben stein","superiorname":"Leon","departmentId":"26","departmentname":"Development","companyId":"23","UDID":"12345","isActive":"1","devicetoken":"12345","email":"[email protected]","phone":"5456465465654","userrole":"1","chngpwdStatus":"1"}] My code is below try{ String weblink = URLEncoder.encode("http://62.253.195.179/disaster/webservices/login.php?message=[{\"email\":\"[email protected]\",\"password\":\"welcome\"}]"); HttpParams httpParameters = new BasicHttpParams(); int timeoutConnection = 7500; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 7500; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); HttpClient client = new DefaultHttpClient(httpParameters); HttpGet request = new HttpGet(); URI link = new URI(weblink); request.setURI(link); HttpResponse response = client.execute(request); BufferedReader rd = new BufferedReader(new InputStreamReader( response.getEntity().getContent())); result = rd.readLine(); JSONObject myData = new JSONObject(result); JSONArray jArray = myData.getJSONArray(""); JSONObject steps = jArray.getJSONObject(0); String name = steps.getString("name"); } catch (JSONException e) { e.printStackTrace(); } But its not working and I am not 100% sure this is the best way to do it. 11-10 10:49:55.489: E/AndroidRuntime(392): java.lang.IllegalStateException: Target host must not be null, or set in parameters.

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  • jQuery Validate PHP Response

    - by Kurt
    Hello Everybody, my problem is, I want to validate an email adresse with jquery. Not only the syntax but rather if the email is already registrated. There are some tutorials but they are not working! At first the Jquery Code: <script id="demo" type="text/javascript"> $(document).ready(function() { // validate signup form on keyup and submit var validator = $("form#signupform").validate({ rules: { Vorname: { required: true, minlength: 3 }, Nachname:{ required: true, minlength: 4 }, password: { required: true, minlength: 5 }, password_confirm: { required: true, minlength: 5, equalTo: "#password" }, Email: { required: true, email: true, type: "POST", remote: "remotemail.php" }, dateformat: "required", ... </script> And now the PHP Code: <?php include('dbsettings.php'); $conn = mysql_connect($dbhost,$dbuser,$dbpw); mysql_select_db($dbdb,$conn); $auslesen1 = "SELECT Email FROM flo_user"; $auslesen2 = mysql_query($auslesen1,$conn); $registered_email = mysql_fetch_assoc($auslesen2); $requested_email = $_POST['Email']; if( in_array($requested_email, $registered_email) ){ echo "false"; } else{ echo "true"; } ?> I tried return TRUE/ return FALSE as well, but this displays "Email is registrated" all the time. json_encode didn't work as well. Thanks a lot!

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