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  • Sessions in asp.net

    - by Indranil Mutsuddy
    Hello i have a login page so once the user enters the correct details he enters into the home page. Now i want to implement 3 things once he clicks the button 'log out' he must be redirected to a page saying" logged out successfully " n even if clicks the back button in the browser, he should not be able to access. if the user leaves the homepage idle for a specific amount of time say 10minutes and then he tries to navigate after 10 mins a msg should display saying "Your Session has been expired login again" if given the url of homepage he shouldnt be able to access unless logged in. I am not sure about what exactly i need to do and how to do. Plz Help Regards Indranil Mutsuddy

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  • use more then one sound in my iphone application using cocos2d

    - by Rana
    avc = [[MPAVController sharedInstance] avController]; //avc is AVController NSString *path = [[NSBundle mainBundle] pathForResource:@"Sound" ofType:@"wav"]; id feeder = [[MPArrayQueueFeeder alloc] initWithPaths:[NSArray arrayWithObject:path]]; [avc setQueueFeeder:feeder]; [avc play:nil]; [feeder release]; NSTimer *sound = [NSTimer scheduledTimerWithTimeInterval:(9.0) target:self selector:@selector(Gamesoundplay) userInfo:nil repeats:YES]; Hear i use tow framework for playing sound. 1. MediaPlayer.framework 2. AudioToolbox.framework I success to play the background sound with repeat after lodding the game. I also want to play sound after clicking some button action without stop the previous background sound.But when i click the other button that time background sound is stop and start again after time intereval ( 9.0 sec ) which i mention for repeated the sound time line. If anyone do this work then help me to complete my application.

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  • MacX DVD Ripper Pro is Free for How-To Geek Readers (Time Limited!)

    - by The Geek
    Want to rip a DVD to your hard drive, but don’t have a software package to do it? How-To Geek readers can get the normally non-free MacX DVD Ripper Pro for free, but only if you download your copy and install it before Saturday. Here’s how to get it. This time-limited offer is available to anybody for the next couple of days—just head to the download site, install the software package, and use the key provided. It’s as simple as that. Note: despite the confusion of the name, it’s available for both Mac and Windows. Latest Features How-To Geek ETC MacX DVD Ripper Pro is Free for How-To Geek Readers (Time Limited!) HTG Explains: What’s a Solid State Drive and What Do I Need to Know? How to Get Amazing Color from Photos in Photoshop, GIMP, and Paint.NET Learn To Adjust Contrast Like a Pro in Photoshop, GIMP, and Paint.NET Have You Ever Wondered How Your Operating System Got Its Name? Should You Delete Windows 7 Service Pack Backup Files to Save Space? Save Files Directly from Your Browser to the Cloud in Chrome and Iron The Steve Jobs Chronicles – Charlie and the Apple Factory [Video] Google Chrome Updates; Faster, Cleaner Menus, Encrypted Password Syncing, and More Glowing Chess Set Combines LEDs, Chess, and DIY Electronics Fun Peaceful Alpine River on a Sunny Day [Wallpaper] Fast Society Creates Mini and Mobile Temporary Social Networks

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  • SelectedIndex of combobox not updating correctly using databinding.

    - by Matthijs Wessels
    I have a ComboBox: <ComboBox Name="iComponentFieldComboBox" SelectedIndex="{Binding ComponentFieldSelectedIndex, Mode=TwoWay}" Height="23" Margin="132,0,280,38" VerticalAlignment="Bottom"> <ComboBoxItem Name="item1">item1</ComboBoxItem> <ComboBoxItem Name="item2">item2</ComboBoxItem> <ComboBoxItem Name="item3">item3</ComboBoxItem> </ComboBox> When I start my WPF and set the ComponentFieldSelectedIndex property of my ViewModel in my code, nothing happens. But after I have selected an item in the combobox, then suddenly setting ComponentFieldSelectedIndex does work. for example: start app. click button that sets ComponentFieldSelectedIndex to 1. selected item doesn't change to item2. select item3 in combo box. click button that sets ComponentFieldSelectedIndex to 1. selected item does change to item2. Does anyone have an idea what could be causing this?

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  • How do I use SLIDE instead of FADE in a YUI Menu animation?

    - by Avry
    I'm using the following configuration for a menu that is attached to a button: var srchTypeMenuConfig = { shadow: false, effect: { effect: YAHOO.widget.ContainerEffect.FADE, duration: .25 } }; I get a nice fade in and out for my menu when I click on the button; I'd rather have it slide in and out though. I replace YAHOO.widget.ContainerEffect.FADE with YAHOO.widget.ContainerEffect.SLIDE and the menu doesn't appear. Is there a way for me to get YUI to give me the slide effect? Here's what I've done so far: 1) Looked at the examples. 2) Looked at some effects examples from DavGlass' blog. 3) Searched the forums for 'ContainerEffect.SLIDE'. 4) Searched SO for 'ContainerEffect.SLIDE [YUI]'. I haven't found any helpful information. I suspect that I need to add something to my configuration, but I don't understand why fade would work but slide doesn't.

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  • How to automatically fix MISSING reference in a dll when a referenced library is broken in VB6?

    - by systempuntoout
    What do you do when you break compatibility on a common library used by many other libraries? What i usually do is: For every dll that reference the broken one Checkout dll Checkout vbp project Open vpb project with VB6 Ide Click on References button Uncheck MISSING reference and OK Click on References button Check references and OK Click on Make dll Close project This can be a pita activity, when you have many Dll to recompile and it can be error prone because you could miss some Dll (anyway we have continuous integration that alert this cases). What's your best practice to handle this scenario?

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  • Have problems designing input and output for a calculator app

    - by zoul
    Hello! I am writing a button calculator. I have the code split into model, view and a controller. The model knows nothing about formatting, it is only concerned with numbers. All formatting is done in the view. The model gets its input as keypresses, each keypress is a part of an enum: typedef enum { kButtonUnknown = 0, kButtonMemoryClear = 100, kButtonMemoryPlus = 112, kButtonMemoryMinus = 109, kButtonMemoryRecall = 114, kButtonClear = 99, … }; When the user presses a button (say 1), the model receives a button code (kButtonNum1), adds the corresponding number to a string input buffer ("1") and updates the numeric output value (1.0). The controller then passes the numeric output value to the view that formats it (1). This is all plain, simple and clean, but does not really work. The problem is that when user enters a part of a number (say 0.00, going to enter 0.001), the input does not survive the way through model to view and the display says 0 instead of 0.00. I know why this happens ("0.00"::string parses to 0::double and that gets formatted as 0). What I don’t know is how to design the calculator so that the code stays clean and simple and the numbers will show up on screen exactly as the user types them. I’ve already come with some kind of solution, but that’s essentially a hack and breaks the beautiful and simple flow from the calculator model to the display. Ideas? Current solution keeps track of the calculator state. If the calculator is building a number, I take the calculator input buffer (a string) and directly set the display contents (also a string). Otherwise I take the proper path, ie. take the numeric calculator output, pass it to the view as a double and the view uses its internal formatter to create a string for the display. Example input: input | display | mode ------+---------+------------ 0 | 0 | from string 0. | 0. | from string 0.0 | 0.0 | from string 0.0+ | 0 | from number This is ugly. (1) The calculator has to expose its input buffer and state. (2) The view has to expose its display and allow setting its contents directly using a string. (3) I have to duplicate some of the formatting code to format the string I got from the calculator input buffer. If user enters 12345.000, I have to display 12,345.000 and therefore I’ve got to have a commification code for strings. Yuck.

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  • Check if value of textbox extended with MaskedEditExtender is valid?

    - by Ismail S
    Below is my code: <asp:TextBox ID="FromDateTextBox" runat="server" /> <asp:ImageButton ID="FromDateImageButton" runat="server" ImageUrl="~/images/calander.png" /> <ajaxkit:CalendarExtender ID="FromDate" runat="server" TargetControlID="FromDateTextBox" CssClass="CalanderControl" PopupButtonID="FromDateImageButton" Enabled="True" /> <ajaxkit:MaskedEditExtender id="FromDateMaskedEditExtender" runat="server" targetcontrolid="FromDateTextBox" Mask="99/99/9999" messagevalidatortip="true" onfocuscssclass="MaskedEditFocus" oninvalidcssclass="MaskedEditError" masktype="Date" displaymoney="Left" acceptnegative="Left" errortooltipenabled="True" /> <ajaxkit:MaskedEditValidator id="FromDateMaskedEditValidator" runat="server" controlextender="FromDateMaskedEditExtender" controltovalidate="FromDateTextBox" emptyvaluemessage="Date is required" invalidvaluemessage="Date is invalid" display="Dynamic" tooltipmessage="Input a date" emptyvalueblurredtext="*" invalidvalueblurredmessage="*" validationgroup="MKE" /> I've set Culture="auto" UICulture="auto" in @Page directive and EnableScriptGlobalization="true" EnableScriptLocalization="true" in script manager to have client culture specific date format in my textbox. I also have a Go button on my page on which I will do a partial post back. So, I want to validate the FromDateTextBox in javascript when the Go button is clicked.

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  • eBook editions of programming books

    - by Jon Hopkins
    (I'll get my justification for why this is on topic in early: programming books tend to have fairly specific formatting needs - code samples, tables, images and graphs - which are not common to all book types and are not necessarily well handled by eBook readers. Similarly they're used in different ways - you often dip in and out rather than read cover to cover.) I've just noticed that Don't Make Me Think by Steve Krug is available as an eBook edition for the Kindle (and presumably also for other readers) which set me thinking. There are certain advantages to eBook readers for tech books - primarily that you can carry a massive library of what would be heavy physical books around very easily. The downside is that certain eBook readers allegedly aren't particularly well equipped to cope with tables, code samples and so on and a book like Don't Make Me Think presumably makes extensive use of these sorts of things. So, the question, what are your experiences of reading and using programming books on an eBook reader and would you recommend it? I'm specifically interested in the latest generation Kindle but happy to hear about all devices - might be useful to state which one you use in the answer.

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  • add ms ajax accordion pane at runtime loses previous pane issue

    - by Chris Conway
    I have an AjaxControlToolkit accordion control that i'm trying to load panes at runtime. When I click a button inside a listview, it should add a new pane to the accordion control. Here is the code that adds the pane in the onitemcommand event within the listview var pane = new AccordionPane { ID = key }; pane.HeaderContainer.Controls.Add(new LiteralControl(label.Text)); pane.ContentContainer.Controls.Add(LoadControl("~/UserControls/Covers/" + e.CommandArgument + ".ascx")); accordion.Panes.Add(pane); And this will successfully show a webcontrol inside the accordion control. But when I click on another button in the listview, the accordion is reset and it only shows the new pane instead of appending a new pane. Is there any way to keep the previous pane visible across postbacks like this? By the way, each of the webcontrols that are loaded in the accordion have input fields that will need to be persisted across postbacks as well. thanks!

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  • javascript return function's data as a file

    - by Dennis
    I have a function in javascript called "dumpData" which I call from a button on an html page as **onlick="dumpData(dbControl);"* What it does is return an xml file of the settings (to an alert box right now). I want to return it to the user as a file download. Is there a way to create a button when click will open a file download box and ask the user to save or open it? (sorta of like right-clicking and save target as)... Or can it be sent to a php file and use export();? Not sure how I would send a long string like that to php and have it simple send it back as a file download. Dennis

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  • Apple Co-founder Wozniak: Windows Phone is more beautiful and intuitive than Android

    - by Gopinath
    It’s a great day for Microsoft and Nokia who are working hard to resurrect Windows Phone. Steve Wozniak, the co-founder of Apple and gadget lover, has all praise for Windows Phone after using Nokia Lumia 900 for a while. He shared his experience of using Lumia powered by Windows Phone 7.5 in a interview and he is very impressed. Here are the few good quotes from the interview Just for looks and beauty, I definitely favor the Windows 7 Phone over Android. I’m kinda shocked how every screen is much more beautiful than the same apps on Android and iPhone. I’m just shocked, I haven’t seen anything yet that isn’t more beautiful than the other platforms. It’s more intuitive and beautiful. This is going to change the perception of Windows Phone  which is seen  as “not-so good” operating system for mobiles.  Along with these high profile endorsements, if Microsoft can manage to attract developers in building good apps then Windows Phone is going to be a fitting competitor to iOS and Android. via aNewDomain

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  • Django models avaoid duplicates

    - by Hulk
    In models, class Getdata(models.Model): title = models.CharField(max_length=255) state = models.CharField(max_length=2, choices=STATE, default="0") name = models.ForeignKey(School) created_by = models.ForeignKey(profile) def __unicode__(self): return self.id() In templates <form> <input type="submit" save the data/> </form> If the user clicks on the save button and the above data is saved in the table how to avoid the duplicates,i.e, if the user again clicks on the same submit button there should not be another entry for the same values.Or is it some this that has to be handeled in views Thanks..

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  • Android popup style activity which sits on top of any other apps

    - by RenegadeAndy
    What I want to create is a popup style application. I have a service in the background - something arrives on the queue and i want an activity to start to inform the user - very very similar to the functionality of SMSPopup app. So I have the code where something arrives on the queue and it calls my activity. However for some reason the activity always shows on top of the originally started activity instead of just appearing on the main desktop of the android device. As an example: I have the main activity which is shown when the application is run I have the service which checks queue I have a popup activity. When i start the main activity it starts the service - I can now close this. I then have something on the queue and it creates the popup activity which launches the main activity with the popup on top of it :S How do I stop this and have it behave as i want... The popup class is : package com.andy.tabletsms.work; import com.andy.tabletsms.tablet.R; import android.app.Activity; import android.content.Context; import android.content.Intent; import android.os.Bundle; import android.view.Gravity; import android.view.LayoutInflater; import android.view.View; import android.view.View.OnClickListener; import android.view.ViewGroup; import android.widget.Button; import android.widget.PopupWindow; import android.widget.TextView; import android.widget.Toast; public class SMSPopup extends Activity implements OnClickListener{ public static String msg; @Override public void onCreate(Bundle bundle){ super.onCreate(bundle); // Toast.makeText(getApplicationContext(), msg, Toast.LENGTH_LONG).show(); this.setContentView(R.layout.popup); TextView tv = (TextView)findViewById(R.id.txtLbl); Intent intent = getIntent(); if (intent != null){ Bundle bb = intent.getExtras(); if (bb != null){ msg = bb.getString("com.andy.tabletsms.message"); } } if(msg == null){ msg = "LOLOLOL"; } tv.setText(msg); Button b = (Button)findViewById(R.id.closeBtn); b.setOnClickListener(this); } @Override public void onClick(View v) { this.finish(); } } and I call the activity from a broadcast receiver which checks the queue every 30 seconds or so : if(main.msgs.size()0){ Intent testActivityIntent = new Intent(context.getApplicationContext(), com.andy.tabletsms.work.SMSPopup.class); testActivityIntent.putExtra("com.andy.tabletsms.message", main.msgs.get(0)); testActivityIntent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK); context.startActivity(testActivityIntent); } The layout is here : http://pastebin.com/F25u6wdM

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  • Programmer + Drugs =? [closed]

    - by sytycs
    I just read this quote from Steve Jobs: "Doing LSD was one of the two or three most important things I have done in my life." Now I'm wondering: Has there ever been a study where programmers have been given drugs to see if they could produce "better" code? Is there a programming concept, which originated from people who where drug-users? Do you know of a piece of code, which was written by someone under the influence? EDIT So I did a little more research and it turns out Dennis R. Wier actually documented how he took LSD to wrap his head around a coding project: "At one point in the project I could not get an overall viewpoint for the operation of the entire system. It really was too much for my brain to keep all the subtle aspects and processing nuances clear so I could get a processing and design overview. After struggling with this problem for a few weeks, I decided to use a little acid to see if it would enable a breakthrough, because otherwise, I would not be able to complete the project and be certain of a consistent overall design"[1] There is also an interesting article on wired about Kevin Herbet, who used LSD to solve tough technical problems and chemist Kary Mullis even said "...that LSD had helped him develop the polymerase chain reaction that helps amplify specific DNA sequences." [2]

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  • Jpanel didn't show rest of it's component

    - by Ali Amiri
    I have jfarame with a button and a JPanel as I named panel, I want after I clicked the button add an inner JPanel to my panel. But this but there is a problem with this! because after adding second panel it didn't add any other panel. my code is: import java.awt.BorderLayout; import java.awt.Dimension; import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import javax.swing.AbstractButton; import javax.swing.ImageIcon; import javax.swing.JButton; import javax.swing.JFrame; import javax.swing.JLabel; import javax.swing.JPanel; import java.awt.GridBagLayout; import java.awt.GridBagConstraints; import java.awt.GridLayout; import javax.swing.JTextField; public class DrawImages extends JFrame{ int i; public DrawImages() { JButton btnNewButton = new JButton("New button"); i = 0; getContentPane().add(btnNewButton, BorderLayout.SOUTH); setMinimumSize(new Dimension(1000,150)); final JPanel panel = new JPanel(); panel.setSize(995, 145); getContentPane().add(panel, BorderLayout.CENTER); panel.setLayout(null); final JLabel lblNewLabel = new JLabel("New label"); lblNewLabel.setBounds(0, 0, 46, 14); panel.add(lblNewLabel); btnNewButton.addActionListener(new ActionListener() public void actionPerformed(ActionEvent paramActionEvent) { JPanel panel_1 = new JPanel(); //getContentPane().add(panel_1, BorderLayout.NORTH); panel_1.setLayout(null); JLabel imagelable = new JLabel(new ImageIcon("c:\\good.jpg")); imagelable.setBounds(70, 5, 105, 65); panel_1.add(imagelable); JLabel lblNewLabel_4 = new JLabel("Up Label"); lblNewLabel_4.setBounds(5, 5, 65, 35); panel_1.add(lblNewLabel_4); JLabel lblNewLabel_2 = new JLabel("Down Label"); lblNewLabel_2.setBounds(5, 25, 65, 65); panel_1.add(lblNewLabel_2); lblNewLabel.setText(""+i); panel_1.setBounds(5+170*i, 5, 170+170*i, 70); panel.add(panel_1); i++; } }); panel.setMinimumSize(new Dimension(995,150)); } public static void main(String[]args) { DrawImages drawImages = new DrawImages(); drawImages.setVisible(true); } }

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  • How to Detect Right Click on the Taskbar

    - by Zay
    I've got a Windows Forms application in C# that starts off with a loading dialog. As expected, a button for the app shows up in the Windows taskbar. I would like to detect right-clicks that might be done to that button. Ultimately, I hope to disable the right-click or simply have the loading dialog regain focus. I've seen that some people use custom libraries and packages (interop, for example) to achieve some Win32 functionality, but I'd personally like to avoid this. Is it impossible to do without such libraries/packages?

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  • How to scroll to the new added item in a ListView

    - by Thomas
    Hi all My application show a ListView with a button which allow user to add an element. When the user clicks on this button, another Activity is started to allow user to populate the new element. When the add is finished, we return to the previous Activity with the ListView and I would like to scroll to the new element. Note that this element is not necessarily at the end of the ListView because there is an "order by" when I retrieve the datas from the database. I know I need the cursor position of the new element to make the ListView scrool to it, but the only info I have about this element is its id, so how to convert this id to cursor position ? Do I have to loop on the cursor to find the position ? Thanks in advance

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  • How to make TWebBrowser ignore accelerator chars of others controls?

    - by douglaslise
    I have a TWebBrowser placed on a form with the designMode enabled. Bellow the browser I have a close button with the Caption set to 'Clos&e'. When I am editing the contents of a document inside the WebBrowser and I press the key E the button close is called. It appears that it is treating TWebBrowser like other controls that don't handle keys and/or don't accept chars (e.g. TButton). How can I solve this? Thanks in advance.

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  • Datatype to use for collection of QT buttons

    - by different
    Hi Everyone, I am brand new to QT and need to develop the Mancala game. Since I'm brand new to the QT environment, my plan it to keep things very simple. I will be using the "Push Button" widget as pieces on the game. Since two players play this game, my idea is to have to arrays of buttons. One array for player 1 and the other for player 2. My question is since I am using "Push Button" widgets, how can I group them to iterate through? I notice that QT has both the array and vector data types but I'm confused on how these data types can be used to "group" the buttons. Does anyone know of any sample code or tutorials to look at to learn more? Thanks for your time and any input provided.

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  • [MINI HOW-TO] Repair Missing External Hard Drive Database Error in WHS

    - by Mysticgeek
    If you’re using external hard drives with your Windows Home Server, they might get unplugged and create an error. Here we look at running the Repair Wizard to quickly fix the issue. If an external drive that is included in your drive pool becomes unplugged or loses power, you might see the following error under Home Network Health when opening the WHS Console. To fix the issue verify the drive has power and is plugged in correctly and click Repair. The wizard launches and you’ll need to agree that you may lose data during the repair of the backup database. In this example it was a simple problem where an external drive became unplugged from the server…so you can close out of the wizard. If you look under Server Storage you can see the drive is missing…To fix the issue verify the drive has power and is plugged in correctly. WHS will add the drive back into the pool and when finished you’ll see it listed as healthy and good to go. Using external drives that are part of your storage pool may not be the best way to have your home built WHS setup, but if you do, expect occasional errors such as this. Similar Articles Productive Geek Tips Find Your Missing USB Drive on Windows XPFixing "BOOTMGR is missing" Error While Trying to Boot Windows VistaSpeed up External USB Hard Drives in Windows VistaRebit Backup Software [Review]Troubleshoot Startup Problems with Startup Repair Tool in Windows 7 & Vista TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips HippoRemote Pro 2.2 Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Know if Someone Accessed Your Facebook Account Shop for Music with Windows Media Player 12 Access Free Documentaries at BBC Documentaries Rent Cameras In Bulk At CameraRenter Download Songs From MySpace Steve Jobs’ iPhone 4 Keynote Video

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  • Django models avoid duplicates

    - by Hulk
    In models, class Getdata(models.Model): title = models.CharField(max_length=255) state = models.CharField(max_length=2, choices=STATE, default="0") name = models.ForeignKey(School) created_by = models.ForeignKey(profile) def __unicode__(self): return self.id() In templates <form> <input type="submit" save the data/> </form> If the user clicks on the save button and the above data is saved in the table how to avoid the duplicates,i.e, if the user again clicks on the same submit button there should not be another entry for the same values.Or is it some this that has to be handeled in views Thanks..

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  • JQuery text display problem?

    - by SLAPme
    Kind of new to JQuery and I was wondering how can I state that the users submitted info was saved when they click the submit button by displaying the message Changes saved at the top of the form and then have it disappear when the user leaves the web page and return back to it? Right now my code only displays that changes were saved at the bottom of the form outside of the lists and will not disappear when the users leave the web page and return back to it. Here is the JQuery code. $(function() { $(".save-button").click(function() { $.post($("#contact-form").attr("action"), $("#contact-form").serialize(), function(html) { $("div.contact-info-form").html(html); $('#contact-form').append('<li>Changes saved!</li>'); }); return false; // prevent normal submit }); }); Here is the html code. <div id="contact-info-form" class="form-content"> <h2>Contact Information</h2> <form method="post" action="index.php" id="contact-form"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form> </div>

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