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  • web design question (php/ajax)

    - by tom smith
    Hi guys... Hope this isn't a waste of your time. I'm working on a project, and it occured to me that there's a chunk of code out there, that should allow me to see how others have implemented this. I've got a project where I'm going to have a page, with a sel box. the user will select an item from the selList, and based on the item selected, a separate section of the page (areaB) will change in terms of the content/tbls being displayed. i then want to allow the user to go through a series of subpages in areaB, where the user goes through a submit/cancel/confirm process, where the stuff in areaB changes, with the rest of the page remaining the same... i'm trying to figure out the best approach to implement the on both client/server side. i could just have an ugly "if block" where i have abunch of logic, and i completely regen the page each time the user selects an action.. i could have an approach that might involve divs/frames, where i then just regen the targeted frame/div area.. is this even possible?? i could have some form of ajaxy process, which would only alter the targeted section(s) of the page... so.. i'm trying to talk to anyone who has ideas on how to do this, or more ideally, if you know of a good code (client/server) side example of this... that i can examine. i'd really appreciate it!! i've got a more detailed overview but didn't know if it would be cool to post it here... thanks.. tom

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  • PHP: Strange Date Problem

    - by Me-and-Coding
    Hi, I have two users in my database whose birth date is set to: 1985-01-26 And then i have function which when provided the users' date, tells how many days are left in the birthday. Here is the function: function retage($iy,$im,$id) { if(!empty($iy)>0 && intval($im)>0 && intval($id)>0) { $tdo=$iy.'-'.$im.'-'.$id; $tdc=date('Y').'-'.$im.'-'.$id; /*echo "<br/>";*/ $cd=date('Y-n-j'); /*echo "<br/>";*/ if(strtotime($tdc)>strtotime($cd))//coming { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); $td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)); if($td==1) { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' day to go'; } else { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; } $ty='<font color="#C7C5C5">is turning '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'is turning '.$ty.' on '.$tdc; } elseif(strtotime($tdc)<strtotime($cd))//past { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); if($ty>0) { //$td='gone '.floor((strtotime($cd)-strtotime($tdc))/(24*3600)).' days ago'; $ndays=floor((strtotime($cd)-strtotime($tdc))/(24*3600)); if($ndays==1) $td=' gone '.round((strtotime($cd)-strtotime($tdc))/(24*3600)).' day ago'; else $td=' gone '.round((strtotime($cd)-strtotime($tdc))/(24*3600)).' days ago'; $ty='<font color="#C7C5C5">had turned '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'had turned '.$ty.' on '.$tdc; } else { $tdc=(date('Y')+1).'-'.$im.'-'.$id; $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); //$td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; $td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)); if($td==1) { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' day to go'; } else { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; } $ty='<font color="#C7C5C5">is turning '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'is turning '.$ty.' on '.$tdc; } } else//today { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); if($ty>0) { $td='today'; $ty='<font color="#C7C5C5">has turned <br>'.$ty.' on today </font>'; //return 'has turned '.$ty.' on today'; } else { $ty='<font color="#C7C5C5">today</font>';$td=''; //return ''; } } } else { $ty='';$td=''; //return ''; } $ta[0]=$ty; $ta[1]=$td ; return $ta; } I use below code to show the days remaining: while($rs=mysql_fetch_array($result)) { if (isset($rs['byear'],$rs['bmonth'],$rs['bdate'])) { $tmptxt = retage($rs['byear'],$rs['bmonth'],$rs['bdate']); echo $tmptxt[1]; } } The strange thing is that for one user, the days remaining is shown correctly eg: gone 120 days ago And for other user having same birth date, this is shown: Jan 1st 1970 -14755 days to go Strange: When I use the same function outside of the loop and test with date 1985-01-26, the correct result is shown. Note: You can check out the function for yourself. Could you please tell what could be wrong there, your help will be highly appreciated. Thanks.

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  • PHP IP Validation Help

    - by Zubair1
    Hello, I am using this IP Validation Function that i came across while browsing, it has been working well until today i ran into a problem. For some reason the function won't validate this IP as valid: 203.81.192.26 I'm not too great with regular expressions, so would appreciate any help on what could be wrong. If you have another function, i would appreciate if you could post that for me. |--------------------------------------------| The code for the function is below: |--------------------------------------------| public static function validateIpAddress($ip_addr) { global $errors; $preg = '#^(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}' . '(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)$#'; if(preg_match($preg, $ip_addr)) { //now all the intger values are separated $parts = explode(".", $ip_addr); //now we need to check each part can range from 0-255 foreach($parts as $ip_parts) { if(intval($ip_parts) > 255 || intval($ip_parts) < 0) { $errors[] = "ip address is not valid."; return false; } return true; } return true; } else { $errors[] = "please double check the ip address."; return false; } }

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  • [PHP] Invalid argument supplied for foreach()

    - by Roberto Aloi
    It often happens to me to handle data that can be either an array or a null variable and to feed some foreach with these data. $values = get_values(); foreach ($values as $value){ ... } When you feed a foreach with data that are not an array, you get a warning: Warning: Invalid argument supplied for foreach() in [...] Assuming it's not possible to refactor the get_values() function to always return an array (backward compatibility, not available source code, whatever other reason), I'm wondering which is the cleanest and most efficient way to avoid these warnings: Casting $values to array Initializing $values to array Wrapping the foreach with an if Other (please suggest)

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  • how to find the directory already is there or not in php

    - by zahir hussain
    hi i want know find the directory is already there or not... if not i would like to create the directory... my coding is below... $da = getdate(); $dat = $da["year"]."-".$da["mon"]."-".$da["mday"]; $m = md5($url)."xml"; if(is_dir($dat)) { chdir($dat); $fh = fopen($m, 'w'); fwrite($fh, $xml); fclose($fh); echo "yes"; } else { mkdir($dat,0777,true); chdir($dat); $fh = fopen($m, 'w'); fwrite($fh, $xml); fclose($fh); echo "not"; } thanks and advance

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  • PHP Associative Array Duplicate Key?

    - by Steven
    Hello, I have an associative array, however when I add values to it using the below function it seems to overwrite the same keys. Is there a way to have multiple of the same keys with different values? Or is there another form of array that has the same format? I want to have 42=56 42=86 42=97 51=64 51=52 etc etc function array_push_associative(&$arr) { $args = func_get_args(); foreach ($args as $arg) { if (is_array($arg)) { foreach ($arg as $key => $value) { $arr[$key] = $value; $ret++; } }else{ $arr[$arg] = ""; } } return $ret; }

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  • PHP Application check name is unique if not append

    - by user270797
    My application requires the user to enter their business name, which the application will automatically create into a unique identifier to be used in URLs, ie "Bob's Cafe" will become "bobs-cafe" But if there are duplicate names I would like the application to add a number so if there is already a "bobs-cafe" we will use "bobs-cafe-1" and likewise if there is already a "bobs-cafe-1" we will use "bobs-cafe-2" Ive used explode and also looked at a regular expressions but I dont know the best way to approach this. Im stuck in being able to grab the number and incrementing it and returning the string

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  • Multiple table relationships in Zend Help

    - by Zogi
    Hi Guys I have been doing some DB mapping to link two tables to no avail. Everytime I run the code I get the following error: Message: File "Role.php" does not exist or class "Role" was not found in the file Stack trace: #0 C:\wamp\www\zend\library\Zend\Db\Table\Row\Abstract.php(867): Zend_Db_Table_Row_Abstract->_getTableFromString('Role') #1 C:\wamp\www\uw\application\models\admin\User.php(56): Zend_Db_Table_Row_Abstract->findDependentRowset('Role') #2 C:\wamp\www\uw\application\controllers\AdminController.php(110): Application_Model_Admin_User->getUsers() #3 C:\wamp\www\zend\library\Zend\Controller\Action.php(513): AdminController->usersAction() #4 C:\wamp\www\zend\library\Zend\Controller\Dispatcher\Standard.php(289): Zend_Controller_Action->dispatch('usersAction') #5 C:\wamp\www\zend\library\Zend\Controller\Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #6 C:\wamp\www\zend\library\Zend\Application\Bootstrap\Bootstrap.php(97): Zend_Controller_Front->dispatch() #7 C:\wamp\www\zend\library\Zend\Application.php(366): Zend_Application_Bootstrap_Bootstrap->run() #8 C:\wamp\www\uwi\public\index.php(26): Zend_Application->run() #9 {main} Code & DB below: application/models/admin/User.php class Application_Model_Admin_User extends Zend_Db_Table_Abstract { protected $_name = 'user'; protected $_dependentTables = array('Role'); public function getUsers() { $rows = $this->fetchAll($this->select()->where('active = ?', 1)); $rows1 = $rows->current(); $rows2 = $rows1->findDependentRowset('Role'); return $rows2; } } application/models/admin/Role.php class Application_Model_Admin_Role extends Zend_Db_Table_Abstract { protected $_name = 'role'; protected $_referenceMap = array ( 'Role' => array( 'columns' => array('id'), 'refTableClass' => 'User', 'refColumns' => array('role_id') ); } DB tables CREATE TABLE role ( id integer auto_increment NOT NULL, name varchar(120), PRIMARY KEY(id) ); CREATE TABLE user ( id integer auto_increment NOT NULL, username varchar(120), PRIMARY KEY(id), FOREIGN KEY(role_id) REFERENCES role(id) );

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  • Order Multidimensional Arrays PHP

    - by ronsandova
    Hi everyone I have some problem to order an array by a field of this, here i leave the example foreach($xml as $site){ echo '<div><a href="'.$site->loc.'">'.$site->loc.'</a>' .$site->padre.'</div>'; } Some times the filed $site->padre is empty but i'd like to order by $site->padre alphabetical i saw example with usort but i don't understand how to work it. Thanks in advance. Cheers

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  • php: replacing double <br /> with </p><p>

    - by andufo
    i use nicEdit to write RTF data in my CMS. The problem is that it generates strings like this: hello first line<br><br />this is a second line<br />this is a 3rd line since this is for a news site, i much prefer the final html to be like this: <p>hello first line</p><p>this is a second line<br />this is a 3rd line</p> so my current solution is this: i need to trim the $data for <br /> at the start/end of the string replace <br /><br /> with </p><p> (one single <br /> is allowed). finally, add <p> at the start and </p> at the end i only have the 3rd step so far. can someone give me a hand with steps 1 and 2? function replace_br($data) { # step 3 $data = '<p>'.$data.'</p>'; return $data; } thanks! ps: it would be even better to avoid specific situations. example: "hello<br /><br /><br /><br /><br />too much space" -- those 5 breaklines should also be converted to just one "</p><p>"

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  • PHP MySQL join table

    - by Jordan Pagaduan
    $sql = "SELECT logs.full_name, logout.status FROM logs, logout WHERE logs.employee_id = logout.employee_id"; tables -- logs logout I'm having error on this. I search join tables in google. And that's what I got. What is wrong with this code?

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  • SimpleXMLElement to PHP Array

    - by Codex73
    Variable $d comes from file_get_contents function to a url. $answer = @new SimpleXMLElement($d); Below is output of the print_r($answer): SimpleXMLElement Object ( [Amount] = 2698 [Status] = OK [State] = FL [Country] = USA ) How can I retrieve value of each element and add to an array? can't figure it out.

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  • PHP count total files in directory AND subdirectory function

    - by Neoweiter
    I need to get a total count of JPG files within a specified directory, including ALL it's subdirectories. No sub-sub directories. Structure looks like this : dir1/ 2 files subdir 1/ 8 files total dir1 = 10 files dir2/ 5 files subdir 1/ 2 files subdir 2/ 8 files total dir2 = 15 files I have this function, which doesn't work fine as it only counts files in the last subdirectory, and total is 2x more than the actual amount of files. (will output 80 if I have 40 files in the last subdir) public function count_files($path) { global $file_count; $file_count = 0; $dir = opendir($path); if (!$dir) return -1; while ($file = readdir($dir)) : if ($file == '.' || $file == '..') continue; if (is_dir($path . $file)) : $file_count += $this->count_files($path . "/" . $file); else : $file_count++; endif; endwhile; closedir($dir); return $file_count; }

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  • mysql connect not working with PHP

    - by shikhar
    Any idea why the following code is not working mysql credentials are correct, have verified from command line. The second connection fails i.e., $conn1 . I am clueless !!! $conn = mysql_connect($hostname, $username, $password) or die("Connecting to MySQL failed" . mysql_error()); $conn1 = mysql_connect($hostname, $username1, $password1) or die("Connecting to MySQL failed" . mysql_error());

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  • Redefining PHP function?

    - by Michael
    If I have a function: function this($a){ return $a; } If I wanted to redefine the function, would it be as simple as rewriting it? function this($a, $b){ //New this function return $a * $b; }

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  • Foreach loop returning null values in PHP?

    - by Jascha
    Hello, I have a pretty simple problem. Basically I have an array called $list that is a list of titles. If I do a print_r($list) I get these results: Array ( [0] => Another New Title [1] => Awesome Movies and stuff [2] => Jascha's Title ) Now, I'm running a foreach loop to retrieve their values and format them in an <ul> like so... function get_film_list(){ global $categories; $list = $categories->get_film_list(); if(count($list)==0){ echo 'No films are in this category'; }else{ echo '<ul>'; foreach($list as $title){ echo '<li>' . $title . '<li>'; } echo '</ul>'; } } The problem I'm having is my loop is returning two values per value (is it the key value?) The result of the preceding function looks like this: Another New Title   Awesome Movies and stuff   Jascha's Title   I even tried: foreach($list as $key => $title){ echo '<li>' . $title . '<li>'; } With the same results: Another New Title   Awesome Movies and stuff   Jascha's Title   What am I missing here? Thanks in advance.

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  • PHP urlize function

    - by Maxime
    Hello guys, I'm using this function on my website to transform user input into acceptable URL: function urlize($url) { $search = array('/[^a-z0-9]/', '/--+/', '/^-+/', '/-+$/' ); $replace = array( '-', '-', '', ''); return preg_replace($search, $replace, utf2ascii($url)); } function utf2ascii($string) { $iso88591 = "\\xE0\\xE1\\xE2\\xE3\\xE4\\xE5\\xE6\\xE7"; $iso88591 .= "\\xE8\\xE9\\xEA\\xEB\\xEC\\xED\\xEE\\xEF"; $iso88591 .= "\\xF0\\xF1\\xF2\\xF3\\xF4\\xF5\\xF6\\xF7"; $iso88591 .= "\\xF8\\xF9\\xFA\\xFB\\xFC\\xFD\\xFE\\xFF"; $ascii = "aaaaaaaceeeeiiiidnooooooouuuuyyy"; return strtr(mb_strtolower(utf8_decode($string), 'ISO-8859-1'),$iso88591,$ascii); } I'm having a problem with it though, with numbers. For some reason when I try: echo urlize("test 23342"); I get "test-eiioe". Why is that and how can I fix it? Thank you very much!

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