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  • Java PropertyChangeListener

    - by Laphroaig
    Hi, i'm trying to figure out how to listen a property change on another class. this is my code: class with the property to listen: public class ClassWithProperty { private PropertyChangeSupport changes = new PropertyChangeSupport(this); private int usersOnline; public int getUsersOnline() { return usersOnline; } public ClassWithProperty() { usersOnline = 0; while (usersOnline<10) { changes.firePropertyChange("usersOnline", usersOnline, usersOnline++); } } public void addPropertyChangeListener( PropertyChangeListener l) { changes.addPropertyChangeListener(l); } public void removePropertyChangeListener( PropertyChangeListener l) { changes.removePropertyChangeListener(l); } } class where i need to know when the property change: public class Main { private static ClassWithProperty test; public static void main(String[] args) { test = new ClassWithProperty(); test.addPropertyChangeListener(listen()); } private static PropertyChangeListener listen() { System.out.println(test.getUsersOnline()); return null; } } I have the event fired only the last time (usersOnline=10). Sorry if it can be a stupid question, i'm learning now java and can't find a solution.

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  • Trouble understanding the semantics of volatile in Java

    - by HungryTux
    I've been reading up about the use of volatile variables in Java. I understand that they ensure instant visibility of their latest updates to all the threads running in the system on different cores/processors. However no atomicity of the operations that caused these updates is ensured. I see the following literature being used frequently A write to a volatile field happens-before every read of that same field . This is where I am a little confused. Here's a snippet of code which should help me better explain my query. volatile int x = 0; volatile int y = 0; Thread-0: | Thread-1: | if (x==1) { | if (y==1) { return false; | return false; } else { | } else { y=1; | x=1; return true; | return true; } | } Since x & y are both volatile, we have the following happens-before edges between the write of y in Thread-0 and read of y in Thread-1 between the write of x in Thread-1 and read of x in Thread-0 Does this imply that, at any point of time, only one of the threads can be in its 'else' block(since a write would happen before the read)? It may well be possible that Thread-0 starts, loads x, finds it value as 0 and right before it is about to write y in the else-block, there's a context switch to Thread-1 which loads y finds it value as 0 and thus enters the else-block too. Does volatile guard against such context switches (seems very unlikely)?

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  • How to identify end of InputStream in java

    - by Vardhaman
    I am trying to read bytes from server using Socket program, ie I am using InputStream to read the bytes. If I pass the length size I am able to read the bytes, but I am not sure what may be the length. So I am not able initialize the byte array. Also I tried while (in.read() !=-1), I observered it loop works fine when the data is sent , but the next line after the loop is not executable , I feel its still looking for the data in the stream but there is no ata. If I close the Server connection , then my client will execute the next line followed to the loop. I am not sure where I am going wrong? this.in = socket.getInputStream(); int dataInt = this.in.read(); while(dataInt != -1){ System.out.print(","+i+"--"+dataInt); i++; dataInt = this.in.read(); } System.out.print("End Of loop"); I get the output as:- ,1--0,2--62,3--96,4--131,5--142,6--1,7--133,8--2,9--16,10--48,11--56,12--1,13--0,14--14,15--128,16--0,17--0,18--0,19--48,20--0,21--0,22--0,23--0,24--0,25--1,26--0,27--0,28--38,29--114,30--23,31--20,32--70,33--3,34--20,35--1,36--133,37--48,38--51,39--49,40--52,41--49,42--55,43--49,44--52,45--52,46--54,47--55,48--50,49--51,50--52,51--48,52--53,53--56,54--51,55--48,56--48,57--57,58--57,59--57,60--57,61--57,62--57,63--57,64--56 But no output for :- End Of loop Please guide how shall I close the loop? Looking forward for you response. Thanking you all in advance.

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  • java:25: '.class' expected error while merging arrays

    - by user3677712
    Here is my code, it is asking me to call a class, I am confused as to do this. Noob to java, so any help would be greatly appreciated. line 25 is where the error occurs. This program is merging two arrays together into a new array. public class Merge{ public static void main(String[] args){ int[] a = {1, 1, 4, 5, 7}; int[] b = {2, 4, 6, 8}; int[] mergedArray = merge(a, b); for(int i = 0; i < mergedArray.length; i++){ System.out.print(mergedArray[i] + " "); } } public static int[] merge(int[] a, int[] b){ // WRITE CODE HERE int[] mergedArray = new int[a.length[] + b.length[]]; int i = 0, j = 0, k = 0; while (i < a.length() && j < b.length()) //error occurs at this line { if (a[i] < b[j]) { mergedArray[k] = a[i]; i++; } else { mergedArray[k] = b[j]; j++; } k++; } while (i < a.length()) { mergedArray[k] = a[i]; i++; k++; } while (j < b.length()) { mergedArray[k] = b[j]; j++; k++; } return mergedArray; } } This program is merging two arrays together into a new array.

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  • Timer in Java swing

    - by Yesha
    I'm trying to replace Thread.sleep with a java swing timer as I hear that is much better for graphics. Before, I had something set up like this, but it was interfering with the graphics. while(counter < array.size){ Thread.sleep(array.get(counter).startTime); //do first task Thread.sleep(array.get(counter).secondTime); //do second task Thread.sleep(array.get(counter).thirdTime); //do third task counter++ } Now, I'm trying to replace each Thread.sleep with one of these and then I have the actual events that happen after this, but it does not seem to be waiting at all. int test = array.get(counter).time; ActionListener taskPerformer = new ActionListener(){ public void actionPerformed(ActionEvent evt){ } }; Timer t = new Timer(test, taskPerformer); t.setRepeats(false); t.start(); Basically, how do I ensure that the program will wait without giving it any code to execute inside of the timer? Thank you!

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  • Learning Java Swing (GUI builder or not?)

    - by Paul
    Well I know basic Java and wanted to learn Swing so of course looked at the Sun website first, where this tutorial is. I was going to start it but realised it relied heavily on NetBeans, which I'm not sure about. I'm not sure because it's learning that I want to acheive, not a nice looking program. So I thought using NetBeans like this would be great once I know it, but I don't want to be building things without a clue what's going on underneath, and of course this could also cause problems later. My first question is is this the right way to do it, should I try not to rely on an IDE heavily? Looking through questions on the site most people recommend using the Sun tutorial, and I've only seen one answer that agrees with what I'm thinking, and they linked to this resource which looks promising. Or perhaps I'm getting the wrong idea of the Sun tutorial, perhaps it doesn't rely on the IDE, it just seemed like that. My second question is, if you agree with me, what resources (apart from the one above) would you recommend? Thanks for your answers.

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  • how to create following Java applicatin? [on hold]

    - by Tushar Bichwe
    Write a JAVA program which performs the following listed operations: A. Create a package named MyEmpPackage which consists of following classes A class named Employee which stores information like the Emp number, first name, middle name, last name, address, designation and salary. The class should also contain appropriate get and set methods. 05 A class named AddEmployeeFrame which displays a frame consisting of appropriate controls to enter the details of a Employee and store these details in the Employee class object. The frame should also have three buttons with the caption as “Add Record” and “Delete Record” and “Exit”. 10 A class named MyCustomListener which should work as a user – defined event listener to handle required events as mentioned in following points. 05 B When the “Add Record” button is clicked, the dialog box should be appeared with asking the user “Do you really want to add record in the file”. If the user selects Yes than the record should be saved in the file. 10 When the “Exit” button is clicked, the frame should be closed. 10 [Note: Use the MyCustomListener class only to handle the appropriate events] C The “Delete Record” button should open a new frame which should take input of delete criteria using a radio button. The radio button should provide facility to delete on basis of first name, middle name or last name. 10 The new frame should also have a text box to input the delete criteria value. 10 The record should be deleted from the file and a message dialog should appear with the message that “Record is successfully Deleted”. 10 [Note: Use the MyCustomListener class only to handle the appropriate events] D Provide proper error messages and perform appropriate exceptions where ever required in all the classes 10

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  • getting duplicate array output - java

    - by dowln
    Hello, Can someone could be kind and help me out here. Thanks in advance... My code below outputs the string as duplicates. I don't want to use Sets or ArrayList. I am using java.util.Random. I am trying to write a code that checks if string has already been randomly outputted and if it does, then it won't display. Where I am going wrong and how do I fix this. public class Worldcountries { private static Random nums = new Random(); private static String[] countries = { "America", "Candada", "Chile", "Argentina" }; public static int Dice() { return (generator.nums.nextInt(6) + 1); } public String randomCounties() { String aTemp = " "; int numOfTimes = Dice(); int dup = 0; for(int i=0 ; i<numOfTimes; i++) { // I think it's in the if statement where I am going wrong. if (!countries[i].equals(countries[i])) { i = i + 1; } else { dup--; } // and maybe here aTemp = aTemp + countries[nums.nextInt(countries.length)]; aTemp = aTemp + ","; } return aTemp; } } So the output I am getting (randomly) is, "America, America, Chile" when it should be "America, Chile".

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  • Java - Display % of upload done

    - by tr-raziel
    I have a java applet for uploading files to server. I want to display the % of data sent but when I use ObjectOutputStream.write() it just writes to the buffer, does not wait until the data has actually been sent. How can I achieve this. Perhaps I need to use thread synchronization or something. Any clues would be most helpful. This is the code I'm using right now: try{ for(File file : ficheiros){ FileInputStream stream = new FileInputStream (file); int bytesRead1 = 0;; int off1 = 0; int len1 = 100000; if(file.length() < 100000) len1 = new Long(file.length()).intValue(); byte[] bytes1 = new byte[len1]; while (off1 < file.length()) { bytes1 = new byte[len1]; if((file.length() - off1) < len1){ len1 = (new Long(file.length()).intValue() - off1); bytes1 = new byte[len1]; } if((bytesRead1 = stream.read(bytes1)) != -1){ //I want this to block until all data has been sent outputToServlet.write(bytes1, 0, bytesRead1 ); System.out.println("off1: " + off1); off1 = off1 + len1; outputToServlet.flush(); } sent += len1; if(sent>totalLength) sent = (int)totalLength; updateFeedback(sent,totalLength,false);//calls method to display % } updateFeedback(-1,-1,true); } }catch(Exception e){ e.printStackTrace(); } Thanks

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  • Javascript enabled but not enabled in Firefox browser

    - by k s subramanisn
    I had installed Java ii icedtea-6-jre-cacao 6b24-1.11.5-0ubuntu1~12.04.1 Alternative JVM for OpenJDK, using Cacao ii icedtea-6-jre-jamvm 6b24-1.11.5-0ubuntu1~12.04.1 Alternative JVM for OpenJDK, using JamVM ii openjdk-6-jre-headless 6b24-1.11.5-0ubuntu1~12.04.1 OpenJDK Java runtime, using Hotspot JIT (headless) ii openjdk-6-jre-lib 6b24-1.11.5-0ubuntu1~12.04.1 OpenJDK Java runtime (architecture and had installed addon in Firefox browser QuickJava 1.8.0. And still keep getting message Javascript enabled, but Java is not enabled in Firefox browser while trying to use on-line bill payment facility.

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  • Failed to create symbolic link to keytool

    - by mt0s
    Keytool is /usr/bin/keytool and points to /etc/alternatives/keytool which in turn points to /usr/lib/jvm/java-6-openjdk-i386/jre/bin/keytool. Now I have installed java version 1.7.0_45 so I need to change keytool to the new path : /usr/lib/jvm/jdk1.7.0_45/jre/bin/keytool I tried deleting the /usr/bin/keytool with rm -rf and then adding a new link like : sudo ln -s /usr/bin/keytool /usr/lib/jvm/jdk1.7.0_45/jre/bin/keytool but what I get is ln: failed to create symbolic link `/usr/lib/jvm/jdk1.7.0_45/jre/bin/keytool': File exists I also tried : sudo update-alternatives --config keytool There is only one alternative in link group keytool: /usr/lib/jvm/java-6-openjdk-i386/jre/bin/keytool Nothing to configure. update-alternatives: warning: forcing reinstallation of alternative /usr/lib/jvm/java-6-openjdk-i386/jre/bin/keytool because link group keytool is broken. but doesn't works too. Any suggestions ? Thank you

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  • Android “open for embedded”? Must-read Ars Technica article

    - by terrencebarr
    A few days ago ars technica published an article “Google’s iron grip on Android: Controlling open source by any means necessary”. If you are considering Android for embedded this article is a must-read to understand the severe ramifications of Google’s tight (and tightening) control on the Android technology and ecosystem. Some quotes from the ars technica article: “Android is open – except for all the good parts“ “Android actually falls into two categories: the open parts from the Android Open Source Project (AOSP) … and the closed source parts, which are all the Google-branded apps” “Android open source apps … turn into abandonware by moving all continuing development to a closed source model.” “Joining the OHA requires a company to sign its life away and promise to not build a device that runs a competing Android fork.” “Google Play Services is a closed source app owned by Google … to turn the “Android App Ecosystem” into the “Google Play Ecosystem” “You’re allowed to contribute to Android and allowed to use it for little hobbies, but in nearly every area, the deck is stacked against anyone trying to use Android without Google’s blessing“ Compare this with a recent Wired article “Oracle Makes Java More Relevant Than Ever”: “Oracle has actually opened up Java even more — getting rid of some of the closed-door machinations that used to be part of the Java standards-making process. Java has been raked over the coals for security problems over the past few years, but Oracle has kept regular updates coming. And it’s working on a major upgrade to Java, due early next year.” Cheers, – Terrence Filed under: Embedded, Mobile & Embedded Tagged: Android, embedded, Java Embedded, Open Source

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  • How to propagate http response code from back-end to client

    - by Manoj Neelapu
    Oracle service bus can be used as for pass through casses. Some use cases require propagating the http-response code back to the caller. http://forums.oracle.com/forums/thread.jspa?messageID=4326052&#4326052 is one such example we will try to accomplish in this tutorial.We will try to demonstrate this feature using Oracle Service Bus (11.1.1.3.0. We will also use commons-logging-1.1.1, httpcomponents-client-4.0.1, httpcomponents-core-4.0.1 for writing the client to demonstrate.First we create a simple JSP which will always set response code to 304.The JSP snippet will look like <%@ page language="java"     contentType="text/xml;     charset=UTF-8"        pageEncoding="UTF-8" %><%      System.out.println("Servlet setting Responsecode=304");    response.setStatus(304);    response.flushBuffer();%>We will now deploy this JSP on weblogic server with URI=http://localhost:7021/reponsecode/For this JSP we will create a simple Any XML BS We will also create proxy service as shown below Once the proxy is created we configure pipeline for the proxy to use route node, which invokes the BS(JSPCaller) created in the first place. So now we will create a error handler for route node and will add a stage. When a HTTP BS sends a request, the JSP sends the response back. If the response code is not 200, then the http BS will consider that as error and the above configured error handler is invoked. We will print $outbound to show the response code sent by the JSP. The next actions. To test this I had create a simple clientimport org.apache.http.Header;import org.apache.http.HttpEntity;import org.apache.http.HttpHost;import org.apache.http.HttpResponse;import org.apache.http.HttpVersion;import org.apache.http.client.methods.HttpGet;import org.apache.http.conn.ClientConnectionManager;import org.apache.http.conn.scheme.PlainSocketFactory;import org.apache.http.conn.scheme.Scheme;import org.apache.http.conn.scheme.SchemeRegistry;import org.apache.http.impl.client.DefaultHttpClient;import org.apache.http.impl.conn.tsccm.ThreadSafeClientConnManager;import org.apache.http.params.BasicHttpParams;import org.apache.http.params.HttpParams;import org.apache.http.params.HttpProtocolParams;import org.apache.http.util.EntityUtils;/** * @author MNEELAPU * */public class TestProxy304{    public static void main(String arg[]) throws Exception{     HttpHost target = new HttpHost("localhost", 7021, "http");     // general setup     SchemeRegistry supportedSchemes = new SchemeRegistry();     // Register the "http" protocol scheme, it is required     // by the default operator to look up socket factories.     supportedSchemes.register(new Scheme("http",              PlainSocketFactory.getSocketFactory(), 7021));     // prepare parameters     HttpParams params = new BasicHttpParams();     HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);     HttpProtocolParams.setContentCharset(params, "UTF-8");     HttpProtocolParams.setUseExpectContinue(params, true);     ClientConnectionManager connMgr = new ThreadSafeClientConnManager(params,              supportedSchemes);     DefaultHttpClient httpclient = new DefaultHttpClient(connMgr, params);     HttpGet req = new HttpGet("/HttpResponseCode/ProxyExposed");     System.out.println("executing request to " + target);     HttpResponse rsp = httpclient.execute(target, req);     HttpEntity entity = rsp.getEntity();     System.out.println("----------------------------------------");     System.out.println(rsp.getStatusLine());     Header[] headers = rsp.getAllHeaders();     for (int i = 0; i < headers.length; i++) {         System.out.println(headers[i]);     }     System.out.println("----------------------------------------");     if (entity != null) {         System.out.println(EntityUtils.toString(entity));     }     // When HttpClient instance is no longer needed,      // shut down the connection manager to ensure     // immediate deallocation of all system resources     httpclient.getConnectionManager().shutdown();     }}On compiling and executing this we see the below output in STDOUT which clearly indicates the response code was propagated from Business Service to Proxy serviceexecuting request to http://localhost:7021----------------------------------------HTTP/1.1 304 Not ModifiedDate: Tue, 08 Jun 2010 16:13:42 GMTContent-Type: text/xml; charset=UTF-8X-Powered-By: Servlet/2.5 JSP/2.1----------------------------------------  

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  • MVC 2 Client Side Model Validation with ExtJS

    One of the most exciting new features in MVC 2 is "Enhanced Model Validation support across both server and client"; this new enhanced support allows for client side validation to be dynamically generated into a view from DataAnnotations attributes on models. One minor complaint: Out of the box, it only supports the Microsoft AJAX libraries. Good news: It can use other frameworks, and we have done just that! Ext.ux.MvcFormValidator The MvcFormValidator is an alternative form validation...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Sync Your Windows Computer with Your Ubuntu One Account [Desktop Client]

    - by Asian Angel
    Do you have a Windows computer that needs to be synced with the Ubuntu systems connected to your Ubuntu One account? Not a problem. Just grab a copy of the Ubuntu One Desktop Client and in just a few minutes your Windows system will be feeling the Ubuntu love. Once you get the desktop client installed you will see a new System Tray Icon waiting for you. Access the Context Menu and select Add this computer to start the syncing process. Enter your account details into the login window that appears and click Connect to Ubuntu One. Go back to the System Tray Icon, access the Context Menu, and select Synchronize Now. You can monitor the progress as small desktop notification messages keep you updated during the synchronizing process. The newly synchronized files will be placed in an Ubuntu One Folder under Documents/My Documents. Here is a quick peek at the Preferences Window. The only odd thing (bug) that we noticed with the whole setup was “Disconnected” being displayed even though our system was freshly synchronized and logged in. Note: Works on Windows XP (with SP3 & Windows Installer 4.5), Vista, and Windows 7. You will need to have the .NET 4 Framework installed (links for both installer types provided below). Need to access your Ubuntu One account directly through your browser? Then see our article on Accessing and Managing Your Ubuntu One Account in Chrome and Iron. Links Download the Ubuntu One Desktop Client [Ubuntu One Wiki] *Click on the (https://one.ubuntu.com/windows/beta) link to start the download. Microsoft .NET Framework 4 (Standalone Installer) [Microsoft] Microsoft .NET Framework 4 (Web Installer) [Microsoft] Latest Features How-To Geek ETC Learn To Adjust Contrast Like a Pro in Photoshop, GIMP, and Paint.NET Have You Ever Wondered How Your Operating System Got Its Name? Should You Delete Windows 7 Service Pack Backup Files to Save Space? What Can Super Mario Teach Us About Graphics Technology? Windows 7 Service Pack 1 is Released: But Should You Install It? How To Make Hundreds of Complex Photo Edits in Seconds With Photoshop Actions Awesome 10 Meter Curved Touchscreen at the University of Groningen [Video] TV Antenna Helper Makes HDTV Antenna Calibration a Snap Turn a Green Laser into a Microscope Projector [Science] The Open Road Awaits [Wallpaper] N64oid Brings N64 Emulation to Android Devices Super-Charge GIMP’s Image Editing Capabilities with G’MIC [Cross-Platform]

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  • Why not Green Threads?

    - by redjamjar
    Whilst I know questions on this have been covered already (e.g. http://stackoverflow.com/questions/5713142/green-threads-vs-non-green-threads), I don't feel like I've got a satisfactory answer. The question is: why don't JVM's support green threads anymore? It says this on the code-style Java FAQ: A green thread refers to a mode of operation for the Java Virtual Machine (JVM) in which all code is executed in a single operating system thread. And this over on java.sun.com: The downside is that using green threads means system threads on Linux are not taken advantage of and so the Java virtual machine is not scalable when additional CPUs are added. It seems to me that the JVM could have a pool of system processes equal to the number of cores, and then run green threads on top of that. This could offer some big advantages when you have a very number large of threads which block often (mostly because current JVM's cap the number of threads). Thoughts?

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  • Bruxelles finance un client BitTorrent décentralisé dans le cadre d'une recherche sur l'amélioration des réseaux informatiques

    La Communauté Européenne finance un client BitTorrent entièrement décentralisé Dans le cadre d'une recherche sur l'amélioration des réseaux informatiques Il est déjà difficile d'expliquer au grand public la différence entre hacker et pirate. On souhaite donc beaucoup de patience et de courage au Professeur responsable du projet Tribler pour expliquer la différence entre BitTorrent et piratage. Il s'agit pourtant d'un projet intéressant à plus d'un titre. Technologiquement, Tribler est un client BitTorrent entièrement décentralisé. Autrement dit, un logiciel qui permet d'échanger des contenus de machine à machine, en gré à gré (ou ...

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  • JavaOne Latin America Underway

    - by Tori Wieldt
    JavaOne Latin America started officially today, but lots of networking has already happened. Last night some JUG leaders, Java Champions, and members of the Oracle Java development and marketing teams had dinner together. The conversation ranged from the new direction of JavaFX to how to improve JUG attendance. Maricio Leal shared the idea some Brazilian JUGs have of putting Java Evangelists and experts on a boat and having them visit JUGs on cities along the Amazon river.  We discussed ideas, and shared dessert pizza. It was the perfect community get together! If you see Brazilian Java Man Bruno Souza, ask him what he is bringing to the party.Today, at JavaOne Latin America, all the sessions were full, and developers were spilling into the hallways. Session content was selected with the help of 14 Java thought leaders from Latin America. JavaOne Program Committee Chair, Sharat Chander, said "I'm thrilled that at this JavaOne over half of the content is coming from the community." Between sessions, developers take advantage of the Oracle Technology Network lounge to grab a snack and use their laptops.  OTN LoungeIt promises to be a great JavaOne.

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  • What change in mindset are needed for a Jave/C# programmer when learning Swift?

    - by Ian
    Swift seem to fit into the same “space” as Java/C# as it was created to make it easier to create end user applications. It is also used to target smart phones like Java/C#. However reading it’s documentation it seems to come from anther universe, you could say it is from Jupiter while C#/Java is from Saturn. As a C# programmer I am finding myself making assumptions that are not true, so what are the conceptual “traps” that I should look out for while leaning about Swift?

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  • Explain Model View Controller

    - by Channel72
    My experience with developing dynamic websites is limited mostly to Java servlets. I've used Tomcat to develop various Java servlets, and I wouldn't hesitate to say that I'm reasonably proficient with this technology, as well as with client-side HTML/CSS/Javascript for the front-end. When I think "dynamic website", I think: user requests a URL with a query string, server receives the query, and then proceeds to output HTML dynamically in order to respond to the query. This often involves communication with a database in order to fetch requested data for display. This is basically the idea behind the doGet method of a Java HttpServlet. But these days, I'm hearing more and more about newer frameworks such as Django and Ruby on Rails, all of which take advantage of the "Model View Controller" architecture. I've read various articles which explain MVC, but I'm having trouble really understanding the benefits. I understand that the general idea is to separate business logic from UI logic, but I fail to see how this is anything really different from normal web programming. Web programming, by it's very nature, forces you to separate business logic (back-end server-side programming) from UI programming (client-side HTML or Javascript), because the two exist in entirely different spheres of programming. Question: What does MVC offer over something like a Java servlet, and more importantly, what exactly is MVC and how is it different from what you would normally do to develop a dynamic website using a more traditional approach such as a Java servlet (or even something older like CGI). If possible, when explaining MVC, please provide an example which illustrates how MVC is applied to the web development process, and how it is beneficial.

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