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• Cannot install wine on Ubuntu natty 64bit [broken dependency]

  - by MHK

  I've just installed Ubuntu natty 64bit. Now I'm trying to install wine and no matter how I do it (Software center/synaptic/terminal), it fails. Here's what I tried on terminal: sudo apt-get update sudo apt-get install wine It shows: Reading package lists... Done Building dependency tree Reading state information... Done Some packages could not be installed. This may mean that you have requested an impossible situation or if you are using the unstable distribution that some required packages have not yet been created or been moved out of Incoming. The following information may help to resolve the situation: The following packages have unmet dependencies: wine : Depends: wine1.3 but it is not going to be installed Depends: ia32-libs (>= 1.6) but it is not going to be installed Depends: lib32asound2 (> 1.0.14) but it is not going to be installed Depends: libc6-i386 (>= 2.6-1) but it is not going to be installed Depends: lib32nss-mdns (>= 0.10-3) but it is not going to be installed E: Broken packages Any body faced this? Is this a bug or something is broken on my end? Any hints on how to solve? Edit: I've tried with aptitude, it gives more clear message: sudo aptitude install wine Output: The following NEW packages will be installed: gnome-exe-thumbnailer{a} ia32-libs{a} icoutils{a} imagemagick{a} lib32asound2{ab} lib32bz2-1.0{a} lib32gcc1{ab} lib32ncurses5{a} lib32nss-mdns{a} lib32stdc++6{ab} lib32v4l-0{ab} lib32z1{a} libc6-i386{ab} libcdt4{a} libgraph4{a} libgvc5{a} libilmbase6{a} liblqr-1-0{a} libmagickcore3{a} libmagickcore3-extra{a} libmagickwand3{a} libnetpbm10{a} libopenexr6{a} libpathplan4{a} netpbm{a} ttf-droid{a} ttf-symbol-replacement-wine1.3{a} ttf-umefont{a} winbind{a} wine wine1.3{a} wine1.3-gecko{a} winetricks{a} 0 packages upgraded, 33 newly installed, 0 to remove and 0 not upgraded. Need to get 135 MB of archives. After unpacking 421 MB will be used. The following packages have unmet dependencies: libc6-i386: Depends: libc6 (= 2.12.1-0ubuntu16) but 2.13-0ubuntu13 is installed. lib32gcc1: Depends: gcc-4.5-base (= 4.5.2-2ubuntu3) but 4.5.2-8ubuntu4 is installed. lib32asound2: Depends: libasound2 (= 1.0.23-2.1ubuntu2) but 1.0.24.1-0ubuntu5 is installed. lib32stdc++6: Depends: gcc-4.5-base (= 4.5.2-2ubuntu3) but 4.5.2-8ubuntu4 is installed. lib32v4l-0: Depends: libv4l-0 (= 0.8.1-2) but 0.8.3-1 is installed. The following actions will resolve these dependencies: Keep the following packages at their current version: 1) ia32-libs [Not Installed] 2) lib32asound2 [Not Installed] 3) lib32bz2-1.0 [Not Installed] 4) lib32gcc1 [Not Installed] 5) lib32ncurses5 [Not Installed] 6) lib32nss-mdns [Not Installed] 7) lib32stdc++6 [Not Installed] 8) lib32v4l-0 [Not Installed] 9) lib32z1 [Not Installed] 10) libc6-i386 [Not Installed] 11) wine [Not Installed] 12) wine1.3 [Not Installed] Leave the following dependencies unresolved: 13) wine1.3-gecko recommends wine1.3 14) winetricks recommends wine1.2 | wine1.3 | cxoffice5 | cxgames5 It seems the wine package hasn't been updated in the repo. What should I do now?

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• TeamCity Scheduled Build not getting all files from VSS

  - by Kate

  Within TeamCity if I trigger a build it all works correctly, however if the Scheduler triggers a build it does not seem to get all the files from VSS. I have clean checkout directory turned on, so I am not sure how it determines the patch for the VSS root. Does anyone have any suggestions on how I can get it to always get all files, and create a new patch each time? I have put the start of two build logs below, as you can see the first one has the correct 249mb, whereas the second only transfers 2MB. The files it doesn't get from VSS seem sporadic and not in relation to what has changed. Manual Trigger [23:57:49]: Checking for changes [00:09:04]: Clean build enabled: removing old files from C:\Builds\Ab 2.0 [00:09:04]: Clearing temporary directory: C:\TeamCity\buildAgent\temp\buildTmp [00:09:05]: Checkout directory: C:\Builds\Ab 2.0 [00:09:05]: Updating sources: server side checkout... (24m:53s) [00:09:05]: [Updating sources: server side checkout...] Will perform clean checkout [00:09:05]: [Updating sources: server side checkout...] Clean checkout reasons [00:09:05]: [Clean checkout reasons] Checkout directory is empty or doesn't exist [00:09:05]: [Clean checkout reasons] "Clean all files before build" turned on [00:09:05]: [Updating sources: server side checkout...] Transferring cached clean patch for VCS root: Ab 2.0 [00:09:42]: [Updating sources: server side checkout...] Building incremental patch over the cached patch [00:31:50]: [Updating sources: server side checkout...] Transferring repository sources: 124.0Mb so far... [00:32:18]: [Updating sources: server side checkout...] Repository sources transferred: 249.46Mb total [00:32:18]: [Updating sources: server side checkout...] Average transfer speed: 183.40Kb per second Triggered by the Scheduler [07:45:01]: Checking for changes [07:55:09]: Clean build enabled: removing old files from C:\Builds\Ab 2.0 [07:55:22]: Clearing temporary directory: C:\TeamCity\buildAgent\temp\buildTmp [07:55:22]: Checkout directory: C:\Builds\Ab 2.0 [07:55:22]: Updating sources: server side checkout... (24m:24s) [07:55:22]: [Updating sources: server side checkout...] Will perform clean checkout [07:55:22]: [Updating sources: server side checkout...] Clean checkout reasons [07:55:22]: [Clean checkout reasons] Checkout directory is empty or doesn't exist [07:55:22]: [Clean checkout reasons] "Clean all files before build" turned on [07:55:22]: [Updating sources: server side checkout...] Building clean patch for VCS root: Ab 2.0 [08:19:46]: [Updating sources: server side checkout...] Transferring cached clean patch for VCS root: Ab 2.0 [08:19:47]: [Updating sources: server side checkout...] Repository sources transferred: 2.01Mb total

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• Type Mismatch using VBScript to create Pivot Table/Chart

  - by Rodricks

  I get Run time error:Type mismatch for the following code: Dim Field Field="Gen8" '''' ============================================================================== EXCEL Sheet '==============Errors -Stacked Chart by Year and Week --ALL WEEKS ''''=================================================== objExcel.ActiveWorkbook.Worksheets.Add SheetNumber = SheetNumber ' add adds in front so sheetnumber stays 1 objExcel.Sheets(SheetNumber).Select objExcel.Sheets(SheetNumber).Activate objExcel.Sheets(SheetNumber).Name = "YRWk" SheetName = "SYS_Product_YRWeeks" '============== strSQLCustomers = "select isnull(AB.Week,D.Week_Num) AS YRWk,ISNULL(AB.UnCorrectable,0) as UE," & _ "isnull(AB.Correctable,0) as CE, isnull(AB.SYS_Product,'" & Field & "'" & _ ") as SYS_Product from AHS_Dates D Left Join (select * from P_tot where " & _ "SYS_Product = '" & Field & "'" & _ " ) AB on AB.Year_=D.Year_ and AB.Week=D.Week_Num order by YRWk" FetchData2.Open strSQLCustomers, openConnection, adOpenStatic, adLockReadOnly If FetchData2.RecordCount > 0 Then **objExcel.ActiveWorkbook.Connections.Add SheetName, "", _ Array(Array( _ "ODBC;DRIVER=SQL Server Native Client 10.0;SERVER=" & sServerIP & ";TimeOut=5000000; Trusted_Connection=Yes;Integrated Security=SSPI;" _ ), Array("DATABASE=" & sDataBaseName & ";")), Array(strSQLCustomers), 2** objExcel.ActiveWorkbook.PivotCaches.Create(SourceType:=xlExternal, SourceData:= _ objExcel.ActiveWorkbook.Connections(SheetName), Version:= _ xlPivotTableVersion14).CreatePivotTable TableDestination:=objExcel.Sheets(SheetNumber).Name & "!R3C7", _ TableName:="PivotTable" & SheetNumber, DefaultVersion:=xlPivotTableVersion14 Set ws = objExcel.ActiveWorkbook.Worksheets(objExcel.Sheets(SheetNumber).Name) objExcel.Cells(3, 7).Select ws.Shapes.AddChart.Select objExcel.ActiveWorkbook.ActiveChart.ChartType = xlAreaStacked objExcel.ActiveWorkbook.ActiveChart.SetSourceData Source:=ws.Range(objExcel.Sheets(SheetNumber).Name & "!$G$3:$I$20") With ws.PivotTables("PivotTable1").PivotFields("SYS_PRoduct") .Orientation = xlColumnField .Position = 1 End With With ws.PivotTables("PivotTable1").PivotFields("YRWk") .Orientation = xlRowField .Position = 1 End With ' With ws.PivotTables("PivotTable1").PivotFields("Year_") ' .Orientation = xlRowField ' .Position = 2 ' End With objExcel.ActiveWorkbook.ActiveChart.ChartTitle.Text = " Errors by Week and Year -ALLWEEKS" ws.PivotTables("PivotTable1").AddDataField ws.PivotTables( _ "PivotTable1").PivotFields("UE"), "Sum of UnCorrectable", xlSum ws.PivotTables("PivotTable1").AddDataField ws.PivotTables( _ "PivotTable1").PivotFields("CE"), "Sum of Correctable", xlSum End If ''MsgBox (FetchData2.RecordCount) FetchData2.Close I have used the same pivot chart + table in other slides. The problem I think is the query length My question: 1.Is there a better way for me to access the query results. Would appreciate the steps if any. 2.If I can make it a procedure how do I modify the pivot chart/table creation. Thanks. The query results with all 52 weeks: Week UE CE SYS_Product(or Field) 1 0 0 Gen8 2 0 0 Gen8 3 0 0 Gen8 4 0 0 Gen8 5 0 0 Gen8 6 0 0 Gen8

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• Apache MaxClients reaching max and locking the server

  - by Rodrigo Sieiro

  Hi. I currently have an Apache2 server running with mpm-prefork and mod_php on a OpenVZ VPS with 512M real / 1024M burstable RAM (no swap). After running some tests, I found that the maximum process size Apache gets is 23M, so I've set MaxClients to 25 (23M x 25 = 575 MB, ok for me). I decided to run some load tests on my server, and the results left me puzzled. I'm using ab on my desktop machine requesting the main page from a wordpress blog. When I run ab with 24 concurrent connections, everything seems fine. Sure, CPU goes up, free RAM goes down, and the result is about 2-3s response time per request. But if I run ab with 25 concurrent connections (my server limit), Apache just hangs after a couple of seconds. It starts processing the requests, then it stops responding, CPU goes back to 100% idle and ab times out. Apache log says it reached MaxClients. When this happens, Apache keeps itself locked up with 25 running processes (they're all in "W" if I check server status) and only after the TimeOut setting the processes start to die and the server starts responding again (in my case it's set to 45). My question: is that expected behaviour? Why Apache just dies when it reaches MaxClients? If it works with 24 connections, shouldn't it work with 25, just taking maybe more time to respond each request and queueing up the rest? It sounds kinda strange to me that any kid running ab can alone kill a webserver just by setting the concurrent connections to the servers MaxClients.

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• Apache reaching MaxClients and locking the server

  - by Rodrigo Sieiro

  Hi. I currently have an Apache2 server running with mpm-prefork and mod_php on a OpenVZ VPS with 512M real / 1024M burstable RAM (no swap). After running some tests, I found that the maximum process size Apache gets is 23M, so I've set MaxClients to 25 (23M x 25 = 575 MB, ok for me). I decided to run some load tests on my server, and the results left me puzzled. I'm using ab on my desktop machine requesting the main page from a wordpress blog. When I run ab with 24 concurrent connections, everything seems fine. Sure, CPU goes up, free RAM goes down, and the result is about 2-3s response time per request. But if I run ab with 25 concurrent connections (my server limit), Apache just hangs after a couple of seconds. It starts processing the requests, then it stops responding, CPU goes back to 100% idle and ab times out. Apache log says it reached MaxClients. When this happens, Apache keeps itself locked up with 25 running processes (they're all in "W" if I check server status) and only after the TimeOut setting the processes start to die and the server starts responding again (in my case it's set to 45). My question: is that expected behaviour? Why Apache just dies when it reaches MaxClients? If it works with 24 connections, shouldn't it work with 25, just taking maybe more time to respond each request and queueing up the rest? It sounds kinda strange to me that any kid running ab can alone kill a webserver just by setting the concurrent connections to the servers MaxClients.

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• Add separate domain name to Wordpress admin area with htaccess

  - by Marc

  I have a Wordpress installation in a seperate folder on my server (meaning it is not in the root folder). I have a htaccess rewrite rule that maps Domain A to folder A. Inside folder A is the Wordpress admin folder, let's call it folder A.B. I tried mapping Domain B to folder A.B., but I can't get it to work properly. When you log in to Wordpress via /admin, you get redirected to /wp-login.php (so from folder A.B. to folder A), maybe that is where I get into trouble. So what I would like to do is this: Domain A folder A Domain B folder A.B Note that this is not for security purposes, I just like the idea of www.domainb.com instead of www.domaina.com/wp-admin. Can this be done with Wordpress?

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• Finetuning movement based on gradual rotation towards a target

  - by A.B.

  I have an object which moves towards a target destination by gradually adjusting its facing while moving forwards. If the target destination is in a "blind spot", then the object is incapable of reaching it. This problem is ilustrated in the picture below. When the arrow is ordered to move to point A, it will only end up circling around it (following the red circle) because it is not able to adjust its rotation quickly enough. I'm interested in a solution where the movement speed is multiplied by a number from 0.1 to 1 in proportion to necessity. The problem is, how do I calculate whether it is necessary in the first place? How do I calculate an appropriate multiplier that is neither too small nor too large? void moveToPoint(sf::Vector2f destination) { if (destination == position) return; auto movement_distance = distanceBetweenPoints(position, destination); desired_rotation = angleBetweenPoints(position, destination); /// Check whether rotation should be adjusted if (rotation != desired_rotation) { /// Check whether the object can achieve the desired rotation within the next adjustment of its rotation if (Radian::isWithinDistance(rotation, desired_rotation, rotation_speed)) { rotation = desired_rotation; } else { /// Determine whether to increment or decrement rotation in order to achieve desired rotation if (Radian::convert(desired_rotation - rotation) > 0) { /// Increment rotation rotation += rotation_speed; } else { /// Decrement rotation rotation -= rotation_speed; } } } if (movement_distance < movement_speed) { position = destination; } else { position.x = position.x + movement_speed*cos(rotation); position.y = position.y + movement_speed*sin(rotation); } updateGraphics(); }

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• Finding the shorter turning direction towards a target

  - by A.B.

  I'm trying to implement a type of movement where the object gradually faces the target. The problem I've run into is figuring out which turning direction is faster. The following code works until the object's orientation crosses the -PI or PI threshold, at which point it will start turning into the opposite direction void moveToPoint(sf::Vector2f destination) { if (destination == position) return; auto distance = distanceBetweenPoints(position, destination); auto direction = angleBetweenPoints(position, destination); /// Decides whether incrementing or decrementing orientation is faster /// the next line is the problem if (atan2(sin(direction - rotation), cos(direction - rotation)) > 0 ) { /// Increment rotation rotation += rotation_speed; } else { /// Decrement rotation rotation -= rotation_speed; } if (distance < movement_speed) { position = destination; } else { position.x = position.x + movement_speed*cos(rotation); position.y = position.y + movement_speed*sin(rotation); } updateGraphics(); } 'rotation' and 'rotation_speed' are implemented as custom data type for radians which cannot have values lower than -PI and greater than PI. Any excess or deficit "wraps around". For example, -3.2 becomes ~3.08.

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• Puppet's automatically generated certificates failing

  - by gparent

  I am running a default configuration of Puppet on Debian Squeeze 6.0.4. The server's FQDN is master.example.com. The client's FQDN is client.example.com. I am able to contact the puppet master and send a CSR. I sign it using puppetca -sa but the client will still not connect. Date of both machines is within 2 seconds of Tue Apr 3 20:59:00 UTC 2012 as I wrote this sentence. This is what appears in /var/log/syslog: Apr 3 17:03:52 localhost puppet-agent[18653]: Reopening log files Apr 3 17:03:52 localhost puppet-agent[18653]: Starting Puppet client version 2.6.2 Apr 3 17:03:53 localhost puppet-agent[18653]: Could not retrieve catalog from remote server: SSL_connect returned=1 errno=0 state=SSLv3 read server certificate B: certificate verify failed Apr 3 17:03:53 localhost puppet-agent[18653]: Using cached catalog Apr 3 17:03:53 localhost puppet-agent[18653]: Could not retrieve catalog; skipping run Here is some interesting output: OpenSSL client test: client:~# openssl s_client -host master.example.com -port 8140 -cert /var/lib/puppet/ssl/certs/client.example.com.pem -key /var/lib/puppet/ssl/private_keys/client.example.com.pem -CAfile /var/lib/puppet/ssl/certs/ca.pem CONNECTED(00000003) depth=1 /CN=Puppet CA: master.example.com verify return:1 depth=0 /CN=master.example.com verify error:num=7:certificate signature failure verify return:1 depth=0 /CN=master.example.com verify return:1 18509:error:1409441B:SSL routines:SSL3_READ_BYTES:tlsv1 alert decrypt error:s3_pkt.c:1102:SSL alert number 51 18509:error:140790E5:SSL routines:SSL23_WRITE:ssl handshake failure:s23_lib.c:188: client:~# master's certificate: root@master:/etc/puppet# openssl x509 -text -noout -in /etc/puppet/ssl/certs/master.example.com.pem Certificate: Data: Version: 3 (0x2) Serial Number: 2 (0x2) Signature Algorithm: sha1WithRSAEncryption Issuer: CN=Puppet CA: master.example.com Validity Not Before: Apr 2 20:01:28 2012 GMT Not After : Apr 2 20:01:28 2017 GMT Subject: CN=master.example.com Subject Public Key Info: Public Key Algorithm: rsaEncryption RSA Public Key: (1024 bit) Modulus (1024 bit): 00:a9:c1:f9:4c:cd:0f:68:84:7b:f4:93:16:20:44: 7a:2b:05:8e:57:31:05:8e:9c:c8:08:68:73:71:39: c1:86:6a:59:93:6e:53:aa:43:11:83:5b:2d:8c:7d: 54:05:65:c1:e1:0e:94:4a:f0:86:58:c3:3d:4f:f3: 7d:bd:8e:29:58:a6:36:f4:3e:b2:61:ec:53:b5:38: 8e:84:ac:5f:a3:e3:8c:39:bd:cf:4f:3c:ff:a9:65: 09:66:3c:ba:10:14:69:d5:07:57:06:28:02:37:be: 03:82:fb:90:8b:7d:b3:a5:33:7b:9b:3a:42:51:12: b3:ac:dd:d5:58:69:a9:8a:ed Exponent: 65537 (0x10001) X509v3 extensions: X509v3 Basic Constraints: critical CA:FALSE Netscape Comment: Puppet Ruby/OpenSSL Internal Certificate X509v3 Key Usage: critical Digital Signature, Key Encipherment X509v3 Subject Key Identifier: 8C:2F:14:84:B6:A1:B5:0C:11:52:36:AB:E5:3F:F2:B9:B3:25:F3:1C X509v3 Extended Key Usage: critical TLS Web Server Authentication, TLS Web Client Authentication Signature Algorithm: sha1WithRSAEncryption 7b:2c:4f:c2:76:38:ab:03:7f:c6:54:d9:78:1d:ab:6c:45:ab: 47:02:c7:fd:45:4e:ab:b5:b6:d9:a7:df:44:72:55:0c:a5:d0: 86:58:14:ae:5f:6f:ea:87:4d:78:e4:39:4d:20:7e:3d:6d:e9: e2:5e:d7:c9:3c:27:43:a4:29:44:85:a1:63:df:2f:55:a9:6a: 72:46:d8:fb:c7:cc:ca:43:e7:e1:2c:fe:55:2a:0d:17:76:d4: e5:49:8b:85:9f:fa:0e:f6:cc:e8:28:3e:8b:47:b0:e1:02:f0: 3d:73:3e:99:65:3b:91:32:c5:ce:e4:86:21:b2:e0:b4:15:b5: 22:63 root@master:/etc/puppet# CA's certificate: root@master:/etc/puppet# openssl x509 -text -noout -in /etc/puppet/ssl/certs/ca.pem Certificate: Data: Version: 3 (0x2) Serial Number: 1 (0x1) Signature Algorithm: sha1WithRSAEncryption Issuer: CN=Puppet CA: master.example.com Validity Not Before: Apr 2 20:01:05 2012 GMT Not After : Apr 2 20:01:05 2017 GMT Subject: CN=Puppet CA: master.example.com Subject Public Key Info: Public Key Algorithm: rsaEncryption RSA Public Key: (1024 bit) Modulus (1024 bit): 00:b5:2c:3e:26:a3:ae:43:b8:ed:1e:ef:4d:a1:1e: 82:77:78:c2:98:3f:e2:e0:05:57:f0:8d:80:09:36: 62:be:6c:1a:21:43:59:1d:e9:b9:4d:e0:9c:fa:09: aa:12:a1:82:58:fc:47:31:ed:ad:ad:73:01:26:97: ef:d2:d6:41:6b:85:3b:af:70:00:b9:63:e9:1b:c3: ce:57:6d:95:0e:a6:d2:64:bd:1f:2c:1f:5c:26:8e: 02:fd:d3:28:9e:e9:8f:bc:46:bb:dd:25:db:39:57: 81:ed:e5:c8:1f:3d:ca:39:cf:e7:f3:63:75:f6:15: 1f:d4:71:56:ed:84:50:fb:5d Exponent: 65537 (0x10001) X509v3 extensions: X509v3 Basic Constraints: critical CA:TRUE Netscape Comment: Puppet Ruby/OpenSSL Internal Certificate X509v3 Key Usage: critical Certificate Sign, CRL Sign X509v3 Subject Key Identifier: 8C:2F:14:84:B6:A1:B5:0C:11:52:36:AB:E5:3F:F2:B9:B3:25:F3:1C Signature Algorithm: sha1WithRSAEncryption 1d:cd:c6:65:32:42:a5:01:62:46:87:10:da:74:7e:8b:c8:c9: 86:32:9e:c2:2e:c1:fd:00:79:f0:ef:d8:73:dd:7e:1b:1a:3f: cc:64:da:a3:38:ad:49:4e:c8:4d:e3:09:ba:bc:66:f2:6f:63: 9a:48:19:2d:27:5b:1d:2a:69:bf:4f:f4:e0:67:5e:66:84:30: e5:85:f4:49:6e:d0:92:ae:66:77:50:cf:45:c0:29:b2:64:87: 12:09:d3:10:4d:91:b6:f3:63:c4:26:b3:fa:94:2b:96:18:1f: 9b:a9:53:74:de:9c:73:a4:3a:8d:bf:fa:9c:c0:42:9d:78:49: 4d:70 root@master:/etc/puppet# Client's certificate: client:~# openssl x509 -text -noout -in /var/lib/puppet/ssl/certs/client.example.com.pem Certificate: Data: Version: 3 (0x2) Serial Number: 3 (0x3) Signature Algorithm: sha1WithRSAEncryption Issuer: CN=Puppet CA: master.example.com Validity Not Before: Apr 2 20:01:36 2012 GMT Not After : Apr 2 20:01:36 2017 GMT Subject: CN=client.example.com Subject Public Key Info: Public Key Algorithm: rsaEncryption RSA Public Key: (1024 bit) Modulus (1024 bit): 00:ae:88:6d:9b:e3:b1:fc:47:07:d6:bf:ea:53:d1: 14:14:9b:35:e6:70:43:e0:58:35:76:ac:c5:9d:86: 02:fd:77:28:fc:93:34:65:9d:dd:0b:ea:21:14:4d: 8a:95:2e:28:c9:a5:8d:a2:2c:0e:1c:a0:4c:fa:03: e5:aa:d3:97:98:05:59:3c:82:a9:7c:0e:e9:df:fd: 48:81:dc:33:dc:88:e9:09:e4:19:d6:e4:7b:92:33: 31:73:e4:f2:9c:42:75:b2:e1:9f:d9:49:8c:a7:eb: fa:7d:cb:62:22:90:1c:37:3a:40:95:a7:a0:3b:ad: 8e:12:7c:6e:ad:04:94:ed:47 Exponent: 65537 (0x10001) X509v3 extensions: X509v3 Basic Constraints: critical CA:FALSE Netscape Comment: Puppet Ruby/OpenSSL Internal Certificate X509v3 Key Usage: critical Digital Signature, Key Encipherment X509v3 Subject Key Identifier: 8C:2F:14:84:B6:A1:B5:0C:11:52:36:AB:E5:3F:F2:B9:B3:25:F3:1C X509v3 Extended Key Usage: critical TLS Web Server Authentication, TLS Web Client Authentication Signature Algorithm: sha1WithRSAEncryption 33:1f:ec:3c:91:5a:eb:c6:03:5f:a1:58:60:c3:41:ed:1f:fe: cb:b2:40:11:63:4d:ba:18:8a:8b:62:ba:ab:61:f5:a0:6c:0e: 8a:20:56:7b:10:a1:f9:1d:51:49:af:70:3a:05:f9:27:4a:25: d4:e6:88:26:f7:26:e0:20:30:2a:20:1d:c4:d3:26:f1:99:cf: 47:2e:73:90:bd:9c:88:bf:67:9e:dd:7c:0e:3a:86:6b:0b:8d: 39:0f:db:66:c0:b6:20:c3:34:84:0e:d8:3b:fc:1c:a8:6c:6c: b1:19:76:65:e6:22:3c:bf:ff:1c:74:bb:62:a0:46:02:95:fa: 83:41 client:~#

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• The ':' character, hexadecimal value 0x3A, cannot be included in a name

  - by coure06

  I have an xml file that contains its element like <ab:test>Str</ab:test> When i am trying to access it using the code XElement tempElement = doc.Descendants(XName.Get("ab:test")).FirstOrDefault(); Its giving me error System.Web.Services.Protocols.SoapException: Server was unable to process request. --- System.Xml.XmlException: The ':' character, hexadecimal value 0x3A, cannot be included in a name. How shld i access it?

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• Compute average distance from point to line segment and line segment to line segment

  - by Fred

  Hi everyone, I'm searching for an algorithm to calculate the average distance between a point and a line segment in 3D. So given two points A(x1, y1, z1) and B(x2, y2, z2) that represent line segment AB, and a third point C(x3, y3, z3), what is the average distance between each point on AB to point C? I'm also interested in the average distance between two line segments. So given segment AB and CD, what is the average distance from each point on AB to the closest point on CD? I haven't had any luck with the web searches I've tried, so any suggestions would be appreciated. Thanks.

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• given two bits in a set of four, fine position of two other bits

  - by aaa

  hello I am working on a simple combinatorics part, and found that I need to recover position of two bits given position of other two bits in 4-bits srring. for example, (0,1) maps to (2,3), (0,2) to (1,3), etc. for a total of six combinations. My solution is to test bits using four nested ternary operators: ab is a four bit string, with two bits set. c = ((((ab & 1) ? (((ab & 2) ? ... ))) : 0) abc = ab | c recover the last bit in the same fashion from abc. can you think of a better way/more clever way? thanks

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• choosing row (from group) with max value in a SQL Server Database

  - by sriehl

  I have a large database and am putting together a report of the data. I have aggregated and summed the data from many tables to get two tables that look like the following. id | code | value id | code | value 13 | AA | 0.5 13 | AC | 2.0 13 | AB | 1.0 14 | AB | 1.5 14 | AA | 2.0 13 | AA | 0.5 15 | AB | 0.5 15 | AB | 3.0 15 | AD | 1.5 15 | AA | 1.0 I need to get a list of id's, with the code (sumed from both tables) with the largest value. 13 | AC 14 | AA 15 | AB There are 4-6 thousand records and it is not possible to change the original tables. I'm not too worried about performance as I only need to run it a few times a year. edit: Let me see if I can explain a bit more clearly, imagine the id is the customer id, the code is who they ordered from and the value is how much they spent there. I need a list of the all the customer id's and the store that customer spent the most money at (and if they spent the same at two different stores, put a value such as 'ZZ' in for the store name).

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• Practical Scheme Programming

  - by Ixmatus

  It's been a few months since I've touched Scheme and decided to implement a command line income partitioner using Scheme. My initial implementation used plain recursion over the continuation, but I figured a continuation would be more appropriate to this type of program. I would appreciate it if anyone (more skilled with Scheme than I) could take a look at this and suggest improvements. I'm that the multiple (display... lines is an ideal opportunity to use a macro as well (I just haven't gotten to macros yet). (define (ab-income) (call/cc (lambda (cc) (let ((out (display "Income: ")) (income (string->number (read-line)))) (cond ((<= income 600) (display (format "Please enter an amount greater than $600.00~n~n")) (cc (ab-income))) (else (let ((bills (* (/ 30 100) income)) (taxes (* (/ 20 100) income)) (savings (* (/ 10 100) income)) (checking (* (/ 40 100) income))) (display (format "~nDeduct for bills:---------------------- $~a~n" (real->decimal-string bills 2))) (display (format "Deduct for taxes:---------------------- $~a~n" (real->decimal-string taxes 2))) (display (format "Deduct for savings:-------------------- $~a~n" (real->decimal-string savings 2))) (display (format "Remainder for checking:---------------- $~a~n" (real->decimal-string checking 2)))))))))) Invoking (ab-income) asks for input and if anything below 600 is provided it (from my understanding) returns (ab-income) at the current-continuation. My first implementation (as I said earlier) used plain-jane recursion. It wasn't bad at all either but I figured every return call to (ab-income) if the value was below 600 kept expanding the function. (please correct me if that apprehension is incorrect!)

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• Hibernate - how to delete bidirectional many-to-many association

  - by slomir

  Problem: I have many-to-many association between two entities A and B. I set A entity as an owner of their relationship(inverse=true is on A's collection in b.hbm.xml). When i delete an A entity, corresponding records in join table are deleted. When i delete an B entity, corresponding records in join table are not deleted (integrity violation exception). -- Let's consider some very simple example: class A{ Set<B> bset=new HashSet<B>(); //... } class B{ Set<A> aset=new HashSet<A>(); //... } File a.hbm.xml [m-to-m mappings only]: <set name="bset" table="AB"> <key name="a_id"/> <many-to-many column="b_id" class="B"/> </set> File b.hbm.xml [m-to-m mappings only]: <set name="aset" table="AB" inverse="true"> <key name="b_id"/> <many-to-many column="a_id" class="A"/> </set> Database relations: A(id,...) B(id,...) AB(a_id,b_id) Suppose that we have some records in AB joint table. For example: AB = {(1,1),(1,2)} where AB= { (a_id , b_id) | ... ... } -- Situation 1 - works probably because A is owner of AB relationship: A a=aDao.read(1); //read A entity with id=1 aDao.delete(a); //delete 'a' entity and both relations with B-entities Situation 2 - doesn't work: B b=bDao.read(1); //read B entity with id=1 bDao.delete(b); //foreign key integrity violation On the one hand, this is somehow logical to me, because the A entity is responsible for his relation with B. But, on the other hand, it is not logical or at least it is not orm-like solution that I have to explicitly delete all records in join table where concrete B entity appears, and then to delete the B entity, as I show in situation 3: Situation 3 - works, but it is not 'elegant': B b=bDao.read(1); Set<A> aset=b.getA(); //get set with A entities Iterator i=aset.iterator(); //while removes 'b' from all related A entities //while breaks relationships on A-side of relation (A is owner) while(i.hasNext()){ A a=i.next(); a.bset.remove(b); //remove entity 'b' from related 'a' entity aDao.update(a); //key point!!! this line breaks relation in database } bDao.delete(b); //'b' is deleted because there is no related A-entities -- So, my question: is there any more convenient way to delete no-owner entity (B in my example) in bidirectional many-to-many association and all of his many-to-many relations from joint table?

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• Easy to follow LaTeX tutorial on layout?

  - by lexu

  I want to layout a page using LaTeX and distribute text snippets/blocks in predefined locations. Something like this +--------------------------------------------------------+ | +-------------+ | | |bla bla bla| | | |bla bl ab lab| +-------------+ | | |bla bla bla| |bla bla bla| | | |bla bl ab lab| |bla bl ab lab| | | +-------------+ |bla bla bla| | | |bla bl ab lab| | | +-------------+ +----+ | | |more| | | Ich und Du |text| | | Müllers Kuh +----+ | | | +--------------------------------------------------------+ My guess is that I should go about this using a minipage or using boxes like \begin{minipage}[b][2cm]{8cm} \mbox{more} \newline \mbox{text} \newline \end{minipage} Is there a tutorial or a 'how to' page that you know, that shows me how to do this - not a list all LaTeX idioms, I have some books for that. But my books are more focused on command lists, scientific publishing and math ..

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• Change SVN Path Entirely

  - by Tom

  Hi Guys, We have an SVN at http:/XX.XXX.XXX.XXX:1111/svn/AB/ - and the first two folders of the SVN are like http:/XX.XXX.XXX.XXX:1111/svn/AB/abc/filefolder/ The problem is we want to move the entire svn to get rid of /abc/filefolder/ - as the entire project sits under /abc/filefolder/ [created long ago and never bothered to change] (que stupid yes yes) How would we could about fixing this so we dont loose logs etc ? We dont want to have to export and create a new svn - since then we loose all our log files. But we want to "move" the svn root so for example it becomes From: http:/XX.XXX.XXX.XXX:1111/svn/AB/abc/filefolder/documents/ To: http:/XX.XXX.XXX.XXX:1111/svn/AB/documents/ Any help appreciated ? [ps - yes had to remove http:// due to link restriction]

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• Regular Expression to break row with comma separated values into distinct rows

  - by Nick

  I have a file with many rows. Each row has a column which may contain comma separated values. I need each row to be distinct (ie no comma separated values). Here is an example row: AB AB10,AB11,AB12,AB15,AB16,AB21,AB22,AB23,AB24,AB25,AB99 ABERDEEN Aberdeenshire The columns are comma separated (Postcode area, Postcode districts, Post town, Former postal county). So the above row would get turned into: AB AB10 ABERDEEN Aberdeenshire AB AB11 ABERDEEN Aberdeenshire AB AB12 ABERDEEN Aberdeenshire ... ... I tried the following but it didn't work... (.+)\t(([0-9A-Z]+),)+\t(.+)\t(.+)

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• problem with evolutionary algorithms degrading into simulated annealing: mutation too small?

  - by Schnalle

  i have a problem understanding evolutionary algorithms. i tried using this technique several times, but i always ran into the same problem: degeneration into simulated annealing. lets say my initial population, with fitness in brackets, is: A (7), B (9), C (14), D (19) after mating and mutation i have following children: AB (8.3), AC (12.2), AD (14.1), BC(11), BD (14.7), CD (17) after elimination of the weakest, we get A, AB, B, AC next turn, AB will mate again with a result around 8, pushing AC out. next turn, AB again, pushing B out (assuming mutation changes fitness mostly in the 1 range). now, after only a few turns the pool is populated with the originally fittest candidates (A, B) and mutations of those two (AB). this happens regardless of the size of the initial pool, it just takes a bit longer. say, with an initial population of 50 it takes 50 turns, then all others are eliminated, turning the whole setup in a more complicated simulated annealing. in the beginning i also mated canditates with themselves, worsening the problem. so, what do i miss? are my mutation rates simply too small and will it go away if i increase them? here's the project i'm using it for: http://stefan.schallerl.com/simuan-grid-grad/ yeah, the code is buggy and the interface sucks, but i'm too lazy to fix it right now - and be careful, it may lock up your browser. better use chrome, even thought firefox is not slower than chrome for once (probably the tracing for the image comparison pays off, yay!). if anyone is interested, the code can be found here. here i just dropped the ev-alg idea and went for simulated annealing. ps: i'm not even sure about simulated annealing - it is like evolutionary algorithms, just with a population size of one, right?

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• create program in c for permutation combination and showing frequency

  - by Vishal Oswal

  I have 2 strings where I have saved fixed 20 characters and these are “A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T” and same 20 char in string 2. so I will get 400 combinations of 2 character sets like AA,AB,AC,AD,AE,AF,……………AT BA,BB,BC,BD,BE,BF,…………..BT CA,CB,CC,CD,CE,CF……………CT This way we will get 400 combinations (Which program I have created successfully) but then user will put the value till 31 characters witch will be treated as 3rd string for E.g. “ABCDDAAAB” now I have to check the frequency of user input in the sequence of 12,23,34,45,56,67,78,89 (2 CHAR SET) means AB,BC,CD,DD,DA,AA,AA,AB and need to show the frequency of user input OUTPUT: AB=2 BC=1 CD=1 DD=1 DA=1 AA=2 please its urgent

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• How can I simplify this redundant code?

  - by Alix Axel

  Can someone please help me simpling this redundant piece of code? if (isset($to) === true) { if (is_string($to) === true) { $to = explode(',', $to); } $to = array_filter(filter_var_array(preg_replace('~[<>]|%0[ab]|[[:cntrl:]]~i', '', $to), FILTER_VALIDATE_EMAIL)); } if (isset($cc) === true) { if (is_string($cc) === true) { $cc = explode(',', $cc); } $cc = array_filter(filter_var_array(preg_replace('~[<>]|%0[ab]|[[:cntrl:]]~i', '', $cc), FILTER_VALIDATE_EMAIL)); } if (isset($bcc) === true) { if (is_string($bcc) === true) { $bcc = explode(',', $bcc); } $bcc = array_filter(filter_var_array(preg_replace('~[<>]|%0[ab]|[[:cntrl:]]~i', '', $bcc), FILTER_VALIDATE_EMAIL)); } if (isset($from) === true) { if (is_string($from) === true) { $from = explode(',', $from); } $from = array_filter(filter_var_array(preg_replace('~[<>]|%0[ab]|[[:cntrl:]]~i', '', $from), FILTER_VALIDATE_EMAIL)); } I tried using variable variables but without success (it's been a long time since I've used them).

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• explain interfaces in C#

  - by Ashish

  //inteface i11 public interface i11 { void m11(); } //interface i22 public interface i22 { void m11(); } //class ab implements interfaces i11 and i22 public class ab : i11, i22 { public void m11() { Console.WriteLine("class"); } } now when in Main() method we create an object of class ab which interface method will get called please explain all.

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• minimal cover for functional dependencies

  - by user2975836

  I have the following problem: AB -> CD H->B G ->DA CD-> EF A -> HJ J>G I understand the first step (break down right hand side) and get the following results: AB -> C AB -> D H -> B G -> D G -> A CD -> E CD -> F A -> H A -> J J -> G I understand that A - h and h - b, therefore I can remove the B from AB - c and ab - D, to get: A -> C A -> D H -> B G -> D G -> A CD -> E CD -> F A -> H A -> J J -> G The step that follows is what I can't compute (reduce the left hand side) Any help will be greatly appreciated.

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• Best algorithm for finding the combination of a word?

  - by hao

  so say you have ab you can have a,b,ab whats the best way of doing this?

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• Getting highest results in a JOIN

  - by Keithamus

  I've got three tables; Auctions, Auction Bids and Users. The table structure looks something like this: Auctions: id title -- ----- 1 Auction 1 2 Auction 2 Auction Bids: id user_id auction_id bid_amt -- ------- ---------- ------- 1 1 1 200.00 2 2 1 202.00 3 1 2 100.00 Users is just a standard table, with id and user name. My aim is to join these tables so I can get the highest values of these bids, as well as get the usernames related to those bids; so I have a result set like so: auction_id auction_title auctionbid_amt user_username ---------- ------------- -------------- ------------- 1 Auction 1 202.00 Bidder2 2 Auction 2 100.00 Bidder1 So far my query is as follows: SELECT a.id, a.title, ab.bid_points, u.display_name FROM auction a LEFT JOIN auctionbid ab ON a.id = ab.auction_id LEFT JOIN users u ON u.id = ab.user_id GROUP BY a.id This gets the single rows I am after, but it seems to display the lowest bid_amt, not the highest.

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