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  • Knight movement.... " how to output all possible moves. "

    - by josh kant
    hi tried the following code and is still not working. it is having problem on backtracking. it just fills the squares of a board with numbers but not in expected order. The code is as follows : include include using namespace std; int i=0; int permuteno = 0; bool move(int *p[], int *used[] ,int x, int y,int n, int count); bool knights (int *p[], int *used[],int x,int y,int n, int count); void output(int *p[],int n); int main(char argc, char *argv[]) { int count = 1; int n; //for size of board int x,y; // starting pos int **p; // to hold no. of combinations int **used; // to keep track of used squares on the board if ( argc != 5) { cout << "Very few arguments. Please try again."; cout << endl; return 0; } n = atoi(argv[2]); if( argv[1] <= 0 ) { cout << " Invalid board size. "; return 0; } x = atoi(argv[4]); y = atoi(argv[4]); cout << "board size: " << n << ", "<< n << endl; cout << "starting pos: " << x << ", " << y << endl; //dynamic allocation of arrays to hold permutation p = new int *[n]; for (int i = 0; i < n; i++) p[i] = new int [n]; //dynamic allocation of used arrays used = new int*[n]; for (int i = 0; i < n; i++) used[i] = new int [n]; //initializing board int i, j; for (i=0; i output(p,n); if (knights(p,used,x, y, n, count)) { cout << "solution found: " << endl < int i, j; for (i=0; i else { cout << "Solution not found" << endl; output (p, n); } knights (p,used, x, y, n, 1); //knights (p,used,x, y, n, count); cout << "no. perm " << permuteno << endl; return 0; } void output(int *p[],int n) { int i = 0,j; while ( i !=n) { for ( j=0; j bool move(int *p[], int *used[] ,int x, int y,int n,int count) { if (x < 0 || x = n) { return false; } if ( y < 0 || y = n) { return false; } if( used[x][y] != 0) { return false; } if( p[x][y] != 0) { return false; } count++; return true; } bool knights (int *p[], int *used[], int x,int y,int n ,int count) { //used[x][y] = 1; if (!move(p,used,x,y,n, count)) { return false; } if (move(p,used,x,y,n, count)) { i++; } p[x][y] = count; used[x][y] = 1; cout << "knight moved " << x << ", " << y << " " << count << endl; if(n*n == count) { return true; } //move 1 if (!knights (p,used, x-1, y-2, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 2 if (!knights (p,used, x+1, y-2, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 3 if (!knights (p,used, x+2, y-1, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 4 if (!knights (p,used, x+2, y+1, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 5 if (!knights (p,used, x+1, y+2, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 6 if (!knights (p,used, x-1, y+2, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 7 if (!knights (p,used, x-2, y+1, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } //move 8 if (!knights (p,used, x-2, y-1, n, count+1)) { used[x][y] = 0; //p[x][y] = 0; } permuteno++; //return true; //}while ( x*y != n*n ); return false; } I has to output all the possible combinations of the knight in a nXn board.. any help would be appreciated...

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