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• Having an issue with Onejar-Maven-Plugin

  - by reverendgreen

  I am trying to package a simple maven java project (uses javax.persistence api) into a single jar using the onejar-maven-plugin. I can run the program fine in eclipse; however when execute the onejar I get the exception below. If someone could provide some insight, that would be appreciated. Thanks, RG Exception in thread "main" java.lang.reflect.InvocationTargetException at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at com.simontuffs.onejar.Boot.run(Boot.java:306) at com.simontuffs.onejar.Boot.main(Boot.java:159) Caused by: Exception [EclipseLink-30005] (Eclipse Persistence Services - 2.0.0.v20091127-r5931): org.eclipse.persistence.exceptions.PersistenceUnitLoadingExcept Exception Description: An exception was thrown while searching for persistence archives with ClassLoader: com.simontuffs.onejar.JarClassLoader@190d11 Internal Exception: java.lang.ClassCastException: sun.misc.Launcher$AppClassLoader cannot be cast to com.simontuffs.onejar.JarClassLoader at org.eclipse.persistence.exceptions.PersistenceUnitLoadingException.exceptionSearchingForPersistenceResources(PersistenceUnitLoadingException.java:126 at org.eclipse.persistence.jpa.PersistenceProvider.createEntityManagerFactory(PersistenceProvider.java:133) at org.eclipse.persistence.jpa.PersistenceProvider.createEntityManagerFactory(PersistenceProvider.java:65) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:78) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:54) at com.test.onejartest.App.main(App.java:19) ... 6 more Caused by: java.lang.ClassCastException: sun.misc.Launcher$AppClassLoader cannot be cast to com.simontuffs.onejar.JarClassLoader at com.simontuffs.onejar.JarClassLoader.getByteStream(JarClassLoader.java:753) at com.simontuffs.onejar.Handler$1.getInputStream(Handler.java:50) at java.net.URL.openStream(Unknown Source) at org.eclipse.persistence.internal.jpa.deployment.ArchiveFactoryImpl.isJarInputStream(ArchiveFactoryImpl.java:124) at org.eclipse.persistence.internal.jpa.deployment.ArchiveFactoryImpl.createArchive(ArchiveFactoryImpl.java:106) at org.eclipse.persistence.internal.jpa.deployment.PersistenceUnitProcessor.findPersistenceArchives(PersistenceUnitProcessor.java:213) at org.eclipse.persistence.internal.jpa.deployment.JPAInitializer.findPersistenceUnitInfoInArchives(JPAInitializer.java:134) at org.eclipse.persistence.internal.jpa.deployment.JPAInitializer.findPersistenceUnitInfo(JPAInitializer.java:125) at org.eclipse.persistence.jpa.PersistenceProvider.createEntityManagerFactory(PersistenceProvider.java:98) ... 10 more pom.xml: ... <pluginRepositories> <pluginRepository> <id>onejar-maven-plugin.googlecode.com</id> <url>http://onejar-maven-plugin.googlecode.com/svn/mavenrepo</url> </pluginRepository> </pluginRepositories> ... <build> <plugins> <plugin> <groupId>org.dstovall</groupId> <artifactId>onejar-maven-plugin</artifactId> <version>1.3.0</version> <executions> <execution> <configuration> <mainClass>com.test.onejartest.App</mainClass> </configuration> <goals> <goal>one-jar</goal> </goals> </execution> </executions> </plugin> <plugin> <artifactId>maven-compiler-plugin</artifactId> <version>2.3.1</version> <configuration> <target>1.6</target> <source>1.6</source> </configuration> </plugin> </plugins> </build> ... <dependencies> <dependency> <groupId>javax.persistence</groupId> <artifactId>persistence-api</artifactId> <version>2.0.0</version> </dependency> <dependency> <groupId>org.eclipse.persistence</groupId> <artifactId>eclipselink</artifactId> <version>2.0.0</version> </dependency> <dependency> <groupId>com.microsoft.sqlserver.jdbc</groupId> <artifactId>sqljdbc</artifactId> <version>4.0.0</version> </dependency> </dependencies>

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• Integrating GWT, Spring and JPA (Eclipse-link) in Weblogic 10

  - by MVK

  Hi, My application architecture looks like this. GWT in the UI layer - Calls GWT RPC service (servlets) - Looksup Spring Beans - Calls the DAO layer which is implemented in JPA (EclipseLink). I have successfully tested the application with GWT rpc services directly calling the JPA layer. But I am having trouble integrating spring into the mix. (Primary usage of Spring is transaction management). I tried googling, but could not find any good article on the topic. (Most of the articles refers to using Spring MVC within GWT, which is not what I am looking for) Could you please point me to some article/tutorial? Thanks in advance! Manoj

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• JPA association table is not deletable

  - by Marcel

  Hi I have a problem with JPA (EclipseLink). I am not able to delete a association table. This is the situation: Product 1:n to ProductResource Resource 1:n to ProductResource I first set the product and resource attributes of ProductResource. If I then try to delete the ProductResource object nothing happens (no sql is generated - no exception). If I comment out both OneToMany annotations in ProductResource I can delete the object. I can also delete the object when product and resource attributes are not set. If I comment out only the annotation above the ressource attribut the ProductResource object gets deleted upon the deletion of the product object (cascade=CascadeType.ALL). I hope someone could give me a hint. Thank you. Product Resource: public class ProductResource implements Serializable { @ManyToOne(fetch=FetchType.EAGER, cascade=CascadeType.MERGE) private Product product; @ManyToOne(fetch=FetchType.EAGER, cascade=CascadeType.MERGE) private Resource resource; Product: public class Product implements Serializable { @OneToMany(mappedBy="product", fetch=FetchType.EAGER, cascade=CascadeType.ALL) private List<ProductResource> productResources = new ArrayList<ProductResource>(); Resource: public class Resource implements Serializable { @OneToMany(mappedBy="resource", fetch=FetchType.EAGER, cascade=CascadeType.ALL) private List<ProductResource> productResources = new ArrayList<ProductResource>(); Greetings Marcel

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• JPA - Setting entity class property from calculated column?

  - by growse

  I'm just getting to grips with JPA in a simple Java web app running on Glassfish 3 (Persistence provider is EclipseLink). So far, I'm really liking it (bugs in netbeans/glassfish interaction aside) but there's a thing that I want to be able to do that I'm not sure how to do. I've got an entity class (Article) that's mapped to a database table (article). I'm trying to do a query on the database that returns a calculated column, but I can't figure out how to set up a property of the Article class so that the property gets filled by the column value when I call the query. If I do a regular "select id,title,body from article" query, I get a list of Article objects fine, with the id, title and body properties filled. This works fine. However, if I do the below: Query q = em.createNativeQuery("select id,title,shorttitle,datestamp,body,true as published, ts_headline(body,q,'ShortWord=0') as headline, type from articles,to_tsquery('english',?) as q where idxfti @@ q order by ts_rank(idxfti,q) desc",Article.class); (this is a fulltext search using tsearch2 on Postgres - it's a db-specific function, so I'm using a NativeQuery) You can see I'm fetching a calculated column, called headline. How do I add a headline property to my Article class so that it gets populated by this query? So far, I've tried setting it to be @Transient, but that just ends up with it being null all the time.

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• Ability to switch Persistence Unit dynamically within the application (JPA)

  - by MVK

  My application data access layer is built using Spring and EclipseLink and I am currently trying to implement the following feature - Ability to switch the current/active persistence unit dynamically for a user. I tried various options and finally ended up doing the following. In the persistence.xml, declare multiple PUs. Create a class with as many EntityManagerFactory attributes as there are PUs defined. This will act as a factory and return the appropriate EntityManager based on my logic public class MyEntityManagerFactory { @PersistenceUnit(unitName="PU_1") private EntityManagerFactory emf1; @PersistenceUnit(unitName="PU_2") private EntityManagerFactory emf2; public EntityManager getEntityManager(int releaseId) { // Logic goes here to return the appropriate entityManeger } } My spring-beans xml looks like this.. <!-- First persistence unit --> <bean class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean" id="emFactory1"> <property name="persistenceUnitName" value="PU_1" /> </bean> <bean class="org.springframework.orm.jpa.JpaTransactionManager" id="transactionManager1"> <property name="entityManagerFactory" ref="emFactory1"/> </bean> <tx:annotation-driven transaction-manager="transactionManager1"/> The above section is repeated for the second PU (with names like emFactory2, transactionManager2 etc). I am a JPA newbie and I know that this is not the best solution. I appreciate any assistance in implementing this requirement in a better/elegant way! Thanks!

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• JPA Inheritance and Relations - Clarification question

  - by Michael

  Here the scenario: I have a unidirectional 1:N Relation from Person Entity to Address Entity. And a bidirectional 1:N Relation from User Entity to Vehicle Entity. Here is the Address class: @Entity public class Address implements Serializable { private static final long serialVersionUID = 1L; @Id @GeneratedValue(strategy = GenerationType.AUTO) privat Long int ... The Vehicles Class: @Entity public class Vehicle implements Serializable { @Id @GeneratedValue(strategy = GenerationType.AUTO) private Long id; @ManyToOne private User owner; ... @PreRemove protected void preRemove() { //this.owner.removeVehicle(this); } public Vehicle(User owner) { this.owner = owner; ... The Person Class: @Entity @Inheritance(strategy = InheritanceType.JOINED) @DiscriminatorColumn(name="PERSON_TYP") public class Person implements Serializable { @Id protected String username; @OneToMany(cascade = CascadeType.ALL, orphanRemoval=true) @JoinTable(name = "USER_ADDRESS", joinColumns = @JoinColumn(name = "USERNAME"), inverseJoinColumns = @JoinColumn(name = "ADDRESS_ID")) protected List<Address> addresses; ... @PreRemove protected void prePersonRemove(){ this.addresses = null; } ... The User Class which is inherited from the Person class: @Entity @Table(name = "Users") @DiscriminatorValue("USER") public class User extends Person { @OneToMany(mappedBy = "owner", cascade = {CascadeType.PERSIST, CascadeType.REMOVE}) private List<Vehicle> vehicles; ... When I try to delete a User who has an address I have to use orphanremoval=true on the corresponding relation (see above) and the preRemove function where the address List is set to null. Otherwise (no orphanremoval and adress list not set to null) a foreign key contraint fails. When i try to delete a user who has an vehicle a concurrent Acces Exception is thrown when do not uncomment the "this.owner.removeVehicle(this);" in the preRemove Function of the vehicle. The thing i do not understand is that before i used this inheritance there was only a User class which had all relations: @Entity @Table(name = "Users") public class User implements Serializable { @Id protected String username; @OneToMany(mappedBy = "owner", cascade = {CascadeType.PERSIST, CascadeType.REMOVE}) private List<Vehicle> vehicles; @OneToMany(cascade = CascadeType.ALL) @JoinTable(name = "USER_ADDRESS", joinColumns = @JoinColumn(name = "USERNAME") inverseJoinColumns = @JoinColumn(name = "ADDRESS_ID")) ptivate List<Address> addresses; ... No orphanremoval, and the vehicle class has used the uncommented statement above in its preRemove function. And - I could delte a user who has an address and i could delte a user who has a vehicle. So why doesn't everything work without changes when i use inheritance? I use JPA 2.0, EclipseLink 2.0.2, MySQL 5.1.x and Netbeans 6.8

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• GlassFish v2.1 -- getting Application Client and Eclipselink to work together?

  - by Nick

  We are trying to use Eclipselink 1.1 with Glassfish v2.1. Following the instructions on: http://wiki.glassfish.java.net/Wiki.jsp?page=FaqEclipseLinkGlassFishV2 I adapted the instructions for the appclient script on linux by adding the lines: APPCPATH=$APPCPATH:$AS_INSTALL/lib/eclipselink-1.1.1.jar export APPCPATH to the appclient shell script. This however is not working. On running the application client (using Glassfish's webstart), I get the error: WARNING: "IOP00810257: (MARSHAL) Could not load class org.eclipse.persistence.indirection.IndirectList" Anyone else succeed in getting GF v 2.1 to work with eclipselink? or any ideas on what I might be doing wrong? I found this bug report: http s://glassfish.dev.java.net/issues/show_bug.cgi?id=8204 (New users can't post more than 1 link, so remove the space between 'http' and 's'.) Where Tim Quinn (tjquinn) said: App client container support for persistence is not yet in place I think this refers only to Glassfish v3, and it should be working in Glassfish v2. Is this correct? I'm working on the assumption that this will work once the ACC knows where to find the eclipselinks jar. Thanks in advance, Nick.

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• Foreign Key constraint violation when persisting a many-to-one class

  - by tieTYT

  I'm getting an error when trying to persist a many to one entity: Internal Exception: org.postgresql.util.PSQLException: ERROR: insert or update on table "concept" violates foreign key constraint "concept_concept_class_fk" Detail: Key (concept_class_id)=(Concept) is not present in table "concept_class". Error Code: 0 Call: INSERT INTO concept (concept_key, description, label, code, concept_class_id) VALUES (?, ?, ?, ?, ?) bind = [27, description_1, label_1, code_1, Concept] Query: InsertObjectQuery(com.mirth.results.entities.Concept[conceptKey=27]) at com.sun.ejb.containers.BaseContainer.checkExceptionClientTx(BaseContainer.java:3728) at com.sun.ejb.containers.BaseContainer.postInvokeTx(BaseContainer.java:3576) at com.sun.ejb.containers.BaseContainer.postInvoke(BaseContainer.java:1354) ... 101 more Here is the method that tries to persist it. I've put a comment where the line is: @Override public void loadConcept(String metaDataFilePath, String dataFilePath) throws Exception { try { ConceptClassMetaData conceptClassMetaData = (ConceptClassMetaData) ModelSerializer.getInstance().fromXML(FileUtils.readFileToString(new File(metaDataFilePath), "UTF8")); em.executeNativeQuery(conceptClassMetaData.getCreateStatement()); ConceptClassRow conceptClassRow = conceptClassMetaData.getConceptClassRow(); ConceptClass conceptClass = em.findByPrimaryKey(ConceptClass.class, conceptClassRow.getId()); if (conceptClass == null) { conceptClass = new ConceptClass(conceptClassRow.getId()); } conceptClass.setLabel(conceptClassRow.getLabel()); conceptClass.setOid(conceptClassRow.getOid()); conceptClass.setDescription(conceptClassRow.getDescription()); conceptClass = em.merge(conceptClass); DataParser dataParser = new DataParser(conceptClassMetaData, dataFilePath); for (ConceptModel conceptModel : dataParser.getConceptRows()) { ConceptFilter<Concept> filter = new ConceptFilter<Concept>(Concept.class); filter.setCode(conceptModel.getCode()); filter.setConceptClass(conceptClass.getLabel()); List<Concept> concepts = em.findAllByFilter(filter); Concept concept = new Concept(); if (concepts != null && !concepts.isEmpty()) { concept = concepts.get(0); } concept.setCode(conceptModel.getCode()); concept.setDescription(conceptModel.getDescription()); concept.setLabel(conceptModel.getLabel()); concept.setConceptClass(conceptClass); concept = em.merge(concept); //THIS LINE CAUSES THE ERROR! } } catch (Exception e) { e.printStackTrace(); throw e; } } ... Here are how the two entities are defined: @Entity @Table(name = "concept") @Inheritance(strategy=InheritanceType.JOINED) @DiscriminatorColumn(name="concept_class_id", discriminatorType=DiscriminatorType.STRING) public class Concept extends KanaEntity { @Id @Basic(optional = false) @Column(name = "concept_key") protected Integer conceptKey; @Basic(optional = false) @Column(name = "code") private String code; @Basic(optional = false) @Column(name = "label") private String label; @Column(name = "description") private String description; @JoinColumn(name = "concept_class_id", referencedColumnName = "id") @ManyToOne private ConceptClass conceptClass; ... @Entity @Table(name = "concept_class") public class ConceptClass extends KanaEntity { @Id @Basic(optional = false) @Column(name = "id") private String id; @Basic(optional = false) @Column(name = "label") private String label; @Column(name = "oid") private String oid; @Column(name = "description") private String description; .... And also, what's important is the sql that's being generated: INSERT INTO concept_class (id, oid, description, label) VALUES (?, ?, ?, ?) bind = [LOINC_TEST, 2.16.212.31.231.54, This is a meta data file for LOINC_TEST, loinc_test] INSERT INTO concept (concept_key, description, label, code, concept_class_id) VALUES (?, ?, ?, ?, ?) bind = [27, description_1, label_1, code_1, Concept] The reason this is failing is obvious: It's inserting the word Concept for the concept_class_id. It should be inserting the word LOINC_TEST. I can't figure out why it's using this word. I've used the debugger to look at the Concept and the ConceptClass instance and neither of them contain this word. I'm using eclipselink. Does anyone know why this is happening?

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• Foreign Key constraint when persisting a many-to-one class

  - by tieTYT

  I'm getting an error when trying to persist a many to one entity: Internal Exception: org.postgresql.util.PSQLException: ERROR: insert or update on table "concept" violates foreign key constraint "concept_concept_class_fk" Detail: Key (concept_class_id)=(Concept) is not present in table "concept_class". Error Code: 0 Call: INSERT INTO concept (concept_key, description, label, code, concept_class_id) VALUES (?, ?, ?, ?, ?) bind = [27, description_1, label_1, code_1, Concept] Query: InsertObjectQuery(com.mirth.results.entities.Concept[conceptKey=27]) at com.sun.ejb.containers.BaseContainer.checkExceptionClientTx(BaseContainer.java:3728) at com.sun.ejb.containers.BaseContainer.postInvokeTx(BaseContainer.java:3576) at com.sun.ejb.containers.BaseContainer.postInvoke(BaseContainer.java:1354) ... 101 more Here is the method that tries to persist it. I've put a comment where the line is: @Override public void loadConcept(String metaDataFilePath, String dataFilePath) throws Exception { try { ConceptClassMetaData conceptClassMetaData = (ConceptClassMetaData) ModelSerializer.getInstance().fromXML(FileUtils.readFileToString(new File(metaDataFilePath), "UTF8")); em.executeNativeQuery(conceptClassMetaData.getCreateStatement()); ConceptClassRow conceptClassRow = conceptClassMetaData.getConceptClassRow(); ConceptClass conceptClass = em.findByPrimaryKey(ConceptClass.class, conceptClassRow.getId()); if (conceptClass == null) { conceptClass = new ConceptClass(conceptClassRow.getId()); } conceptClass.setLabel(conceptClassRow.getLabel()); conceptClass.setOid(conceptClassRow.getOid()); conceptClass.setDescription(conceptClassRow.getDescription()); conceptClass = em.merge(conceptClass); DataParser dataParser = new DataParser(conceptClassMetaData, dataFilePath); for (ConceptModel conceptModel : dataParser.getConceptRows()) { ConceptFilter<Concept> filter = new ConceptFilter<Concept>(Concept.class); filter.setCode(conceptModel.getCode()); filter.setConceptClass(conceptClass.getLabel()); List<Concept> concepts = em.findAllByFilter(filter); Concept concept = new Concept(); if (concepts != null && !concepts.isEmpty()) { concept = concepts.get(0); } concept.setCode(conceptModel.getCode()); concept.setDescription(conceptModel.getDescription()); concept.setLabel(conceptModel.getLabel()); concept.setConceptClass(conceptClass); concept = em.merge(concept); //THIS LINE CAUSES THE ERROR! } } catch (Exception e) { e.printStackTrace(); throw e; } } ... Here are how the two entities are defined: @Entity @Table(name = "concept") @Inheritance(strategy=InheritanceType.JOINED) @DiscriminatorColumn(name="concept_class_id", discriminatorType=DiscriminatorType.STRING) public class Concept extends KanaEntity { @Id @Basic(optional = false) @Column(name = "concept_key") protected Integer conceptKey; @Basic(optional = false) @Column(name = "code") private String code; @Basic(optional = false) @Column(name = "label") private String label; @Column(name = "description") private String description; @JoinColumn(name = "concept_class_id", referencedColumnName = "id") @ManyToOne private ConceptClass conceptClass; ... @Entity @Table(name = "concept_class") public class ConceptClass extends KanaEntity { @Id @Basic(optional = false) @Column(name = "id") private String id; @Basic(optional = false) @Column(name = "label") private String label; @Column(name = "oid") private String oid; @Column(name = "description") private String description; .... And also, what's important is the sql that's being generated: INSERT INTO concept_class (id, oid, description, label) VALUES (?, ?, ?, ?) bind = [LOINC_TEST, 2.16.212.31.231.54, This is a meta data file for LOINC_TEST, loinc_test] INSERT INTO concept (concept_key, description, label, code, concept_class_id) VALUES (?, ?, ?, ?, ?) bind = [27, description_1, label_1, code_1, Concept] The reason this is failing is obvious: It's inserting the word Concept for the concept_class_id. It should be inserting the word LOINC_TEST. I can't figure out why it's using this word. I've used the debugger to look at the Concept and the ConceptClass instance and neither of them contain this word. I'm using eclipselink. Does anyone know why this is happening?

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• JPA ManyToMany problem...

  - by Parhs

  Hello i have an Entity Exam @Id @GeneratedValue(strategy=GenerationType.TABLE) private Long id; ..... ...... @ManyToMany private List<Exam> exams; @ManyToMany(mappedBy="id") private List<Exam> parentExams; The problem is that @ManyToMany private List<Exam> exams; is ok works great... but this doesnt validate?! @ManyToMany(mappedBy="id") private List<Exam> parentExams; Any idea what to do ? I just want to get the exams that are parents of the current exam. ??e???? ??µ?sµat??? ?aµe??

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• use of EntityManagerFactory causing duplicate primary key exceptions

  - by bradd

  Hey guys, my goal is create an EntityManager using properties dependent on which database is in use. I've seen something like this done in all my Google searches(I made the code more basic for the purpose of this question): @PersistenceUnit private EntityManagerFactory emf; private EntityManager em; private Properties props; @PostConstruct public void createEntityManager(){ //if oracle set oracle properties else set postgres properties emf = Persistence.createEntityManagerFactory("app-x"); em = emf.createEntityManager(props); } This works and I can load Oracle or Postgres properties successfully and I can Select from either database. HOWEVER, I am running into issues when doing INSERT statements. Whenever an INSERT is done I get a duplicate primary key exception.. every time! Can anyone shed some light on why this may be happening? Thanks -Brad

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• JPA behaviour...

  - by Marcel

  Hi I have some trouble understanding a JPA behaviour. Mabye someone could give me a hint. Situation: Product entity: @Entity public class Product implements Serializable { ... @OneToMany(mappedBy="product", fetch=FetchType.EAGER) private List<ProductResource> productResources = new ArrayList<ProductResource>(); .... public List<ProductResource> getProductResources() { return productResources; } public boolean equals(Object obj) { if (obj == this) return true; if (obj == null) return false; if (!(obj instanceof Product)) return false; Product p = (Product) obj; return p.productId == productId; } } Resource entity: @Entity public class Resource implements Serializable { ... @OneToMany(mappedBy="resource", fetch=FetchType.EAGER) private List<ProductResource> productResources = new ArrayList<ProductResource>(); ... public void setProductResource(List<ProductResource> productResource) { this.productResources = productResource; } public List<ProductResource> getProductResources() { return productResources; } public boolean equals(Object obj) { if (obj == this) return true; if (obj == null) return false; if (!(obj instanceof Resource)) return false; Resource r = (Resource) obj; return (long)resourceId==(long)r.resourceId; } } ProductResource Entity: This is a JoinTable (association class) with additional properties (amount). It maps Product and Resources. @Entity public class ProductResource implements Serializable { ... @JoinColumn(nullable=false, updatable=false) @ManyToOne(fetch=FetchType.EAGER, cascade=CascadeType.PERSIST) private Product product; @JoinColumn(nullable=false, updatable=false) @ManyToOne(fetch=FetchType.EAGER, cascade=CascadeType.PERSIST) private Resource resource; private int amount; public void setProduct(Product product) { this.product = product; if(!product.getProductResources().contains((this))){ product.getProductResources().add(this); } } public Product getProduct() { return product; } public void setResource(Resource resource) { this.resource = resource; if(!resource.getProductResources().contains((this))){ resource.getProductResources().add(this); } } public Resource getResource() { return resource; } ... public boolean equals(Object obj) { if (obj == this) return true; if (obj == null) return false; if (!(obj instanceof ProductResource)) return false; ProductResource pr = (ProductResource) obj; return (long)pr.productResourceId == (long)productResourceId; } } This is the Session Bean (running on glassfish). @Stateless(mappedName="PersistenceManager") public class PersistenceManagerBean implements PersistenceManager { @PersistenceContext(unitName = "local_mysql") private EntityManager em; public Object create(Object entity) { em.persist(entity); return entity; } public void delete(Object entity) { em.remove(em.merge(entity)); } public Object retrieve(Class entityClass, Long id) { Object entity = em.find(entityClass, id); return entity; } public void update(Object entity) { em.merge(entity); } } I call the session Bean from a java client: public class Start { public static void main(String[] args) throws NamingException { PersistenceManager pm = (PersistenceManager) new InitialContext().lookup("java:global/BackITServer/PersistenceManagerBean"); ProductResource pr = new ProductResource(); Product p = new Product(); Resource r = new Resource(); pr.setProduct(p); pr.setResource(r); ProductResource pr_stored = (ProductResource) pm.create(pr); pm.delete(pr_stored); Product p_ret = (Product) pm.retrieve(Product.class, pr_stored.getProduct().getProductId()); // prints out true ???????????????????????????????????? System.out.println(p_ret.getProductResources().contains(pr_stored)); } } So here comes my problem. Why is the ProductResource entity still in the List productResources(see code above). The productResource tuple in the db is gone after the deletion and I do newly retrieve the Product entity. If I understood right every method call of the client happens in a new persistence context, but here i obviously get back the non-refreshed product object!? Any help is appreciated Thanks Marcel

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• Pitfalls and practical Use-Cases: Toplink, Hibernate, Eclipse Link, Ibatis ...

  - by Martin K.

  I worked a lot with Hibernate as my JPA implementation. In most cases it works fine! But I have also seen a lot of pitfalls: Remoting with persisted Objects is difficult, because Hibernate replaces the Java collections with its own collection implementation. So the every client must have the Hibernate .jar libraries. You have to take care on LazyLoading exceptions etc. One way to get around this problem is the use of webservices. Dirty checking is done against the Database without any lock. "Delayed SQL", causes that the data access isn't ACID compliant. (Lost data...) Implict Updates So we don't know if an object is modified or not (commit causes updates). Are there similar issues with Toplink, Eclipse Link and Ibatis? When should I use them? Have they a similar performance? Are there reasons to choose Eclipse Link/Toplink... over Hibernate?

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• Match entities fulfilling filter (strict superset of search)

  - by Jon

  I have an entity (let's say Person) with a set of arbitrary attributes with a known subset of values. I need to search for all of these entities that match all my filter conditions. That is, given a set of Attributes A, I need to find all people that have a set of Attributes that are a superset of A. For example, my table structures look like this: Person: id | name 1 | John Doe 2 | Jane Roe 3 | John Smith Attribute: id | attr_name 1 | Sex 2 | Eye Color ValidValue: id | attr_id | value_name 1 | 1 | Male 2 | 1 | Female 3 | 2 | Blue 4 | 2 | Green 5 | 2 | Brown PersonAttributes id | person_id | attr_id | value_id 1 | 1 | 1 | 1 2 | 1 | 2 | 3 3 | 2 | 1 | 2 4 | 2 | 2 | 4 5 | 3 | 1 | 1 6 | 3 | 2 | 4 In JPA, I have entities built for all of these tables. What I'd like to do is perform a search for all entities matching a given set of attribute-value pairs. For instance, I'd like to be able to find all males (John Doe and John Smith), all people with green eyes (Jane Roe or John Smith), or all females with green eyes (Jane Roe). I see that I can already take advantage of the fact that I only really need to match on value_id, since that's already unique and tied to the attr_id. But where can I go from there? I've been trying to do something like the following, given that the ValidValue is unique in all cases: select distinct p from Person p join p.personAttributes a where a.value IN (:values) Then I've tried putting my set of required values in as "values", but that gives me errors no matter how I try to structure that. I also have to get a little more complicated, as follows, but at this point I'd be happy with solving the first problem cleanly. However, if it's possible, the Attribute table actually has a field for default value: id | attr_name | default_value 1 | Sex | 1 2 | Eye Color | 5 If the value you're searching on happens to be the default value, I want it to return any people that have no explicit value set for that attribute, because in the application logic, that means they inherit the default value. Again, I'm more concerned about the primary question, but if someone who can help with that also has some idea of how to do this one, I'd be extremely grateful.

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• Removing associated entity JPA

  - by Marcel

  Hi I have a question regarding JPA persistence in Glassfish. Situation: I have a Supplier class that has a 1:n bidirectional relation to SupplierAddress. I would like to have the following behaviour: If I remove the SupplierAddress object from the List in the Supplier object and update it via the merge(supplierobject), the SupplierAddress tupel/object should be deleted. Is there an annotation do configure it like this or do I have to delete it manually. Any help would be very appreciated. Greetings Marcel

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• Can a List<> be casted to a DataModel

  - by Ignacio

  I'm trying to do the following: public String createByMarcas() { items = (DataModel) ejbFacade.findByMarcas(current.getIdMarca().getId()); updateCurrentItem(); return "List"; } public List<Modelos> findByMarcas(int idMarca){ return em.createQuery("SELECT id, descripcion FROM Modelos WHERE id_marca ="+idMarca+"").getResultList(); } But I keep getting this expection: Caused by: javax.ejb.EJBException at com.sun.ejb.containers.BaseContainer.processSystemException(BaseContainer.java:5070) at com.sun.ejb.containers.BaseContainer.completeNewTx(BaseContainer.java:4968) at com.sun.ejb.containers.BaseContainer.postInvokeTx(BaseContainer.java:4756) at com.sun.ejb.containers.BaseContainer.postInvoke(BaseContainer.java:1955) at com.sun.ejb.containers.BaseContainer.postInvoke(BaseContainer.java:1906) at com.sun.ejb.containers.EJBLocalObjectInvocationHandler.invoke(EJBLocalObjectInvocationHandler.java:198) at com.sun.ejb.containers.EJBLocalObjectInvocationHandlerDelegate.invoke(EJBLocalObjectInvocationHandlerDelegate.java:84) at $Proxy347.findByMarcas(Unknown Source) at controladores.EJB31_Generated_ModelosFacade_Intf_Bean_.findByMarcas(Unknown Source) Can anyone give a hand please? Thank you very much

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• Extending an entity

  - by Kim L

  I have class named AbstractUser, which is annotated with @MappedSuperclass. Then I have a class named User (@Entity) which extends AbstractUser. Both of these exist in a package named foo.bar.framework. When I use these two classes, everything works just fine. But now I've imported a jar containing these files to another project. I'd like to reuse the User class and expand it with a few additional fields. I thought that @Entity public class User extends foo.bar.framework.User would do the trick, but I found out that this implementation of the User only inherits the fields from AbstractUser, but nothing from foo.bar.framework.User. The question is, how can I get my second User class to inherit all the fields from the first User entity class? Both User class implementation have different table names defined with @Table(name = "name").

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• EJB failure to update datamodel

  - by Ignacio

  Here my EJB @Entity @Table(name = "modelos") @NamedQueries({ @NamedQuery(name = "Modelos.findAll", query = "SELECT m FROM Modelos m"), @NamedQuery(name = "Modelos.findById", query = "SELECT m FROM Modelos m WHERE m.id = :id"), @NamedQuery(name = "Modelos.findByDescripcion", query = "SELECT m FROM Modelos m WHERE m.descripcion = :descripcion")}) public class Modelos implements Serializable { private static final long serialVersionUID = 1L; @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Basic(optional = false) @Column(name = "id") private Integer id; @Basic(optional = false) @Column(name = "descripcion") private String descripcion; @OneToMany(cascade = CascadeType.ALL, mappedBy = "idModelo") private Collection produtosCollection; @JoinColumn(name = "id_marca", referencedColumnName = "id") @ManyToOne(optional = false) private Marcas idMarca; public Modelos() { } public Modelos(Integer id) { this.id = id; } public Modelos(Integer id, String descripcion) { this.id = id; this.descripcion = descripcion; } public Modelos(Integer id, Marcas idMarca) { this.id = id; this.idMarca = idMarca; } public Integer getId() { return id; } public void setId(Integer id) { this.id = id; } public String getDescripcion() { return descripcion; } public void setDescripcion(String descripcion) { this.descripcion = descripcion; } public Collection<Produtos> getProdutosCollection() { return produtosCollection; } public void setProdutosCollection(Collection<Produtos> produtosCollection) { this.produtosCollection = produtosCollection; } public Marcas getIdMarca() { return idMarca; } public void setIdMarca(Marcas idMarca) { this.idMarca = idMarca; } @Override public int hashCode() { int hash = 0; hash += (id != null ? id.hashCode() : 0); return hash; } @Override public boolean equals(Object object) { // TODO: Warning - this method won't work in the case the id fields are not set if (!(object instanceof Modelos)) { return false; } Modelos other = (Modelos) object; if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) { return false; } return true; } @Override public String toString() { return "" + descripcion + ""; } } And the method accesing from the Modelosfacade public List findByMarcas(Marcas idMarca){ return em.createQuery("SELECT id, descripcion FROM Modelos WHERE idMarca = "+idMarca.getId()+"").getResultList(); } And the calling method from the controller public String createByMarcas() { //recreateModel(); items = new ListDataModel(ejbFacade.findByMarcas(current.getIdMarca())); updateCurrentItem(); System.out.println(current.getIdMarca()); return "List"; } I do not understand why I keep falling in an EJB exception.

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• How do I write JPA QL statements that hints to the runtime to use the DEFAULT value ?

  - by Jacques René Mesrine

  I have a table like so: mysql> show create table foo; CREATE TABLE foo ( network bigint NOT NULL, activeDate datetime NULL default '0000-00-00 00:00:00', ... ) In the domain object, FooVO the activeDate member is annotated as Temporal. If I don't set activeDate to a valid Date instance, a new record is inserted with NULLs. I want the default value to take effect if I don't set the activeDate member. Thanks.

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• how to query an embedded entity by using a query builder

  - by user577719

  I've searched quite a time for an answer to this question. Following Codesmell: @Entity public class Person { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) protected Integer id; @Column(nullable = true, length = 50) @Size(max = 50) private String name; @Embedded @Valid protected Adress adress; public void setId(Integer id) { this.id = id; } public Integer getId() { return this.id; } public void setName(String name) { this.name = name; } public void getName() { return this.name; } public void setAdress(Adress adress) { this.adress = adress; } public void getAdress() { return this.adress; } } @Embeddable public class Adress { @Column(nullable = false, length = 50) @Size(max = 50) @NotNull private String place; public void setPlace(String place) { this.place = place; } public void getPlace() { return this.place; } } public class PersonDaoJpa { public List<Ort> findByPerson(final Person person) { CriteriaBuilder builder = this.entityManager.getCriteriaBuilder(); CriteriaQuery<Person> query = builder.createQuery(Person.class); Root<Person> rootPerson = query.from(Person.class); List<Predicate> wherePredicates = new ArrayList<Predicate>(); if (person.getName() != null) { wherePredicates.add( builder.like(builder.lower(rootPerson.<String>get("name")), ort.getName().toLowerCase()) ); } Adresse adresse = ort.getAdresse(); if (adresse != null) { if(adresse.getPlace() != null) { // this won't work wherePredicates.add( builder.like(builder.lower(rootPerson.<String>get("person.adress.place")), adresse.getPlace().toLowerCase()) ); } } Predicate whereClause = builder.and(wherePredicates.toArray(new Predicate[0])); query.where(whereClause); return this.entityManager.createQuery(query).getResultList(); } } How can I access the Adress.place through rootPerson? rootPerson.get("place"), or rootPerson.get("adress.place") won't work...

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• Jsf validation error (shown by h:message) while updating Model, why?

  - by Ignacio

  List.xhtml: <h:selectOneMenu value="#{produtosController.selected.codigo}"> <f:selectItems value="#{produtosController.itemsAvailableSelectOne}"/> </h:selectOneMenu> <h:commandButton action="#{produtosController.createByCodigos}" value="Buscar" /> Controller Class method: public String createByCodigos(){ items = new ListDataModel(ejbFacade.findByCodigos(current.getCodigo())); updateCurrentItem(); return "List"; } Facade Class method: public List<Produtos> findByCodigos(Integer codigo){ Query q = em.createNamedQuery("Produtos.findByCodigo"); q.setParameter("codigo", codigo); return q.getResultList(); } Bean Class query: @NamedQuery(name = "Produtos.findByCodigo", query = "SELECT p FROM Produtos p WHERE p.codigo = :codigo") @Column(name = "codigo") private Integer codigo;

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• Is there any advantage for using a library other than Hibernate for JPA?

  - by Jeduan Cornejo

  Hi, I've been using JPA for some time now and been in projects where we've used both Hibernate Annotations and Toplink Essentials. AFAIK the project leader chose Toplink because Netbeans had it integrated and seemed to be the easy thing to do. However when looking for help, most of the literature seemed to assume that you are using Hibernate as the JPA provider, so, the question is, is have you found any advantage, performance or otherwise for not using the de-facto standard for JPA, Hibernate?

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• Mysql maven jpa skeleton

  - by coubeatczech

  Hi, is there a skeleton for a project using mysql, some eclipse/top link with RESOURCE_LOCAL as connection type? Preferably using maven. I'm searching for it for hours and can't get running even the sipmlest exaple. So if you had it ready and running, please, post :-). Even something as simple as these two classes only. @Entity public class Message implements Serializable{ public Message() {} public Message(String s){ this.s = s; } @Id String s; public String getS(){ return s; } } public class App { static private EntityManagerFactory emf; static private EntityManager em; public static void main( String[] args ) { emf = Persistence.createEntityManagerFactory("persistence"); em = emf.createEntityManager(); Message m = new Message("abc"); em.persist(m); } }

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• Eclipse Multitenancy. Now with a screencast.

  - by alexismp

  As a follow-up to the previous EclipseLink's mutitenancy blog post and the recent Eclipse Indigo release train and the recent GlassFish Podcast interview on EclipseLink, we now have a short screencast showing it all in action. You can also find it on the GlassFish YouTube Channel. The scenario is pretty simple with two simple and identical web applications deployed with different tenant identifiers via persistence.xml customization (just one of the means of identifying tenants with EclipseLink). Hopefully this'll help people understand what Java EE 7 multitenancy might look like.

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• Using JPA 2.0 with WebLogic Server 10.3.4 and Eclipse

  - by greg.stachnick

  Beginning in Oracle Enterprise Pack for Eclipse (OEPE) 11.1.1.6.1, we introduced a new feature for WebLogic Server configuration called Server Extensions. Similar in concept to project facets, Server Extensions allow us to install additional technologies, libraries, configurations, etc into an existing server runtime. WebLogic Server 10.3.4 introduces new support for Java Persistence 2.0, the new JEE 6 standard entity access. In order to start developing JPA 2.0 applications with WebLogic Server 10.3.4, a SmartUpdate patch must be applied to add and configure the EclipseLink libraries. More information on the manual EclipseLink installation and configuration can be found here. OEPE provides a Server Extension for JPA 2.0, making the addition and configuration of JPA 2.0 and EclipseLink much easier. When defining a new WebLogic Server 10.3.4 configuration, simply click the Install link for Java Persistence 2.0 and OEPE will take care of the WebLogic Server enablement for JPA 2.0.  

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