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  • SQL Server User Mapping - Limit view of databases for a user

    - by Jaime
    Hi there, I am adding a new Login with SQL Server Authentication. I set its Server Role as public and then went into User Mapping, selecting the only database this user should have access to. I then change the Default Schema to dbo and made this user the db_owner. I then connect to the instance using the new user's credentials and I can see not only the database he should have access to but all the other attached databases. How can I limit this user to just see the database he has access to? Thanks in advance!

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  • Icon on user account desktop before the user has logged in.

    - by JHamill
    Currently working on a Windows 7 deployment project and I have a requirement to place an RDP icon on a specific users desktop, lets call this user 'Guest'. The image itself will be completely vanilla and all user accounts will be created using commands in the Unattend file. The 'Guest' account will not be a local admin and so it will not be the account used for autologon during the application of the unattend file. As a result of this, the 'Guest' profile will not have been created so I'm unable to simply place the icon at C:\Users\Guest\Desktop. Is there a way to place an icon on this specific users desktop prior to logging in with it? I know there are ways around this i.e. include this account in the base image and log in with it in order to create the profile but I'd like to keep the base image as vanilla as possible. Any ideas or pointers would be greatly appreciated. Thanks in advance.

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  • User Interface Annoyances

    - by Jim McKeeth
    I am looking for some of the most annoying user interface features that are common and keep being repeated. The first one that comes to mind is the modal pop up message box that developers like to use to let you know you did something right, but gets frustrating the 1000th time you have to close it. I would rather see the annoyances that are common in many applications instead of the one really odd ones that are only in one or two applications. Please: One per answer.

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  • Managing user privileges, best practice.

    - by Loïc N.
    I'm am new to web development. I'm creating a website where different user can have different privileges, such as creating/editing/deleting a news, or adding/editing/deleting whatever kind of content on the website. I started by creating a "user type" that would indicate the user's privileges (such as "user", "newser", "moderator", "admin", and so on), but i quickly started noticing issues that made me think that this might be a naive approach to this issue. What if i want to give a regular user the right to edit a news (for whatever reason)? Then the user would be half "user", half "newser". But the system i use can only handle one user-type. So what would be the best practice here? I was thinking of removing the concept of roles (or "user-types" such as newser) and only have the concept of "privilege", where every user could have zero to many privileges. So, to re-use the above example, if i wanted a user to have the right to edit some news, i would only have to give him a "edit news" privilege. Is this the way to go?

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  • Managing user privileges, best practices [on hold]

    - by Loïc N.
    I'm am new to web development. I'm creating a website where different user can have different privileges, such as creating/editing/deleting a news, or adding/editing/deleting whatever kind of content on the website. I started by creating a "user type" that would indicate the user's privileges (such as "user", "newser", "moderator", "admin", and so on), but I quickly started noticing issues that made me think that this might be a naive approach to this issue. What if I want to give a regular user the right to edit a news (for whatever reason)? Then the user would be half "user", half "newser". But the system I use can only handle one user-type. So what would be the best practice here? I was thinking of removing the concept of roles (or "user-types" such as newser) and only have the concept of "privilege", where every user could have zero to many privileges. So, to re-use the above example, if I wanted a user to have the right to edit some news, I would only have to give him a "edit news" privilege. Is this the way to go?

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  • More efficent way to do this?

    - by Pez Cuckow
    I have a if function that works out how much of a users profile is completed however the way I include below was the best I could think of, however it seems really inefficient. What is the better way to do this? if($user['first_name']!==""&&$user['last_name']!==""&&$user['pemail']!==""&&$user['dob']!==""&&$user['ambitions']!==""&&$user['memories']!==""&&$user['thoughts']!==""&&$user['message_1']!=="0"&&$user['message_2']!=="0"&&$user['message_3']!=="0"&&$user['v1']!=="0"&&$user['v2']!=="0"&&$user['v3']!=="0"&&$user['v4']!=="0"&&$user['v5']!=="0"&&$user['v6']!=="0"&&$user['v7']!=="0"&&$user['v8']!=="0"&&$user['v9']!=="0"&&$user['image_1']!==""&&$user['image_2']!==""&&$user['image_3']!=="") { $completed = 4; } elseif($user['first_name']!==""&&$user['last_name']!==""&&$user['pemail']!==""&&$user['dob']!==""&&$user['ambitions']!==""&&$user['memories']!==""&&$user['thoughts']!==""&&$user['v1']!=="0"&&$user['v2']!=="0"&&$user['v3']!=="0"&&$user['v4']!=="0"&&$user['v5']!=="0"&&$user['v6']!=="0"&&$user['v7']!=="0"&&$user['v8']!=="0"&&$user['v9']!=="0"&&$user['image_1']!==""&&$user['image_2']!==""&&$user['image_3']!=="") { $completed = 3; } elseif($user['first_name']!==""&&$user['last_name']!==""&&$user['pemail']!==""&&$user['dob']!==""&&$user['ambitions']!==""&&$user['memories']!==""&&$user['thoughts']!==""&&$user['message_1']!=="0"&&$user['message_2']!=="0"&&$user['message_3']!=="0"&&$user['image_1']!==""&&$user['image_2']!==""&&$user['image_3']!=="") { $completed = 2; } elseif($user['first_name']!==""&&$user['last_name']!==""&&$user['pemail']!==""&&$user['dob']!==""&&$user['ambitions']!==""&&$user['memories']!==""&&$user['thoughts']!==""&&$user['image_1']!==""&&$user['image_2']!==""&&$user['image_3']!=="") { $completed = 1; } else { $completed = 0; }

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  • PHP If/Else - More efficent way to do this?

    - by Pez Cuckow
    I have a if function that works out how much of a users profile is completed however the way I include below was the best I could think of, however it seems really inefficient. What is the better way to do this? if($user['first_name']!==""&&$user['last_name']!==""&&$user['pemail']!==""&&$user['dob']!==""&&$user['ambitions']!==""&&$user['memories']!==""&&$user['thoughts']!==""&&$user['message_1']!=="0"&&$user['message_2']!=="0"&&$user['message_3']!=="0"&&$user['v1']!=="0"&&$user['v2']!=="0"&&$user['v3']!=="0"&&$user['v4']!=="0"&&$user['v5']!=="0"&&$user['v6']!=="0"&&$user['v7']!=="0"&&$user['v8']!=="0"&&$user['v9']!=="0"&&$user['image_1']!==""&&$user['image_2']!==""&&$user['image_3']!=="") { $completed = 4; } elseif($user['first_name']!==""&&$user['last_name']!==""&&$user['pemail']!==""&&$user['dob']!==""&&$user['ambitions']!==""&&$user['memories']!==""&&$user['thoughts']!==""&&$user['v1']!=="0"&&$user['v2']!=="0"&&$user['v3']!=="0"&&$user['v4']!=="0"&&$user['v5']!=="0"&&$user['v6']!=="0"&&$user['v7']!=="0"&&$user['v8']!=="0"&&$user['v9']!=="0"&&$user['image_1']!==""&&$user['image_2']!==""&&$user['image_3']!=="") { $completed = 3; } elseif($user['first_name']!==""&&$user['last_name']!==""&&$user['pemail']!==""&&$user['dob']!==""&&$user['ambitions']!==""&&$user['memories']!==""&&$user['thoughts']!==""&&$user['message_1']!=="0"&&$user['message_2']!=="0"&&$user['message_3']!=="0"&&$user['image_1']!==""&&$user['image_2']!==""&&$user['image_3']!=="") { $completed = 2; } elseif($user['first_name']!==""&&$user['last_name']!==""&&$user['pemail']!==""&&$user['dob']!==""&&$user['ambitions']!==""&&$user['memories']!==""&&$user['thoughts']!==""&&$user['image_1']!==""&&$user['image_2']!==""&&$user['image_3']!=="") { $completed = 1; } else { $completed = 0; }

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  • Project Euler #290 in python, hint please

    - by debragail
    This solution is grossly inefficient. What am I missing? #!/usr/bin/env python #coding: utf-8 import time from timestrings import * start = time.clock() maxpower = 18 count = 0 for i in range(0, 10 ** maxpower - 1): if i % 9 == 0: result1 = list(str(i)) result2 = list(str(137 * i)) sum1 = 0 for j in result1: sum1 += int(j) sum2 = 0 for j in result2: sum2 += int(j) if sum1 == sum2: print (i, sum1) count += 1 finish = time.clock() print ("Project Euler, Project 290") print () print ("Answer:", count) print ("Time:", stringifytime(finish - start))

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  • Is there a user-comfortable Unix-like OS?

    - by Rob Kam
    Apparently BSD is like this but only for the OS not for the third party applications: Is there a Unix or Unix-like operating system (but not OS X), where all the installed applications and drivers either all work smoothly/properly or are not included in the distribution? But not something that's been dumbed down.

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  • Local User & Local Admin User Server 2008

    - by Ammo
    Hi I had a test recently and one of the questions was to create a file and local user and give the local user write permission to that file. I created the local user successfully however when I went to add permission to the file it would not find the local user when name was entered correctly, and idea what could have prevented this. Secondly I was asked to create a local admin account and give full permissions to the file, to my knowledge server 2008 has a built in admin account, and neither was the server a domain controller. Could you tell me what you would do in this situation? Many Thanks!

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  • Design For Asynchronous User Interface

    - by Sohnee
    I have been working on a integration that has posed an interesting user interface conundrum that I would like suggestions for. The user interface is displayed within a third party product. The state of the interface is supplied by calls to a service I have written. There can be small delays between the actual state changing the the user interface changing due to the polling for state by the third party. When a user interacts with the user interface, requests are sent back to my application. This then affects the state and the next state poll request will update the user interface. The problem is that the delay between pressing a button and seeing the user interface update is perhaps 1 or 2 seconds and in usability testing I can see that people are clicking again before the user interface updates, thinking that they haven't properly clicked the first time. Given the constraints (we can only update the user interface via the polling mechanism - if we updated it when they clicked, the polling might return and overwrite the change causing unpredictable / undesirable results)... what can we do to make the user experience better. My current idea is to show a message for a couple of seconds so people know their click was accepted, the message would not be affected by the state polling, so wouldn't be prematurely removed / overwritten etc. I'm sure there are other ideas out there and I'm also confident someone has a better idea that I have!

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  • SQL SERVER – Detecting guest User Permissions – guest User Access Status

    - by pinaldave
    Earlier I wrote the blog post SQL SERVER – Disable Guest Account – Serious Security Issue, and I got many comments asking questions related to the guest user. Here are the comments of Manoj: 1) How do we know if the uest user is enabled or disabled? 2) What is the default for guest user in SQL Server? Default settings for guest user When SQL Server is installed by default, the guest user is disabled for security reasons. If the guest user is not properly configured, it can create a major security issue. You can read more about this here. Identify guest user status There are multiple ways to identify guest user status: Using SQL Server Management Studio (SSMS) You can expand the database node >> Security >> Users. If you see the RED arrow pointing downward, it means that the guest user is disabled. Using sys.sysusers Here is a simple script. If you notice column dbaccess as 1, it means that the guest user is enabled and has access to the database. SELECT name, hasdbaccess FROM sys.sysusers WHERE name = 'guest' Using sys.database_principals and sys.server_permissions This script is valid in SQL Server 2005 and a later version. This is my default method recently. SELECT name, permission_name, state_desc FROM sys.database_principals dp INNER JOIN sys.server_permissions sp ON dp.principal_id = sp.grantee_principal_id WHERE name = 'guest' AND permission_name = 'CONNECT' Using sp_helprotect Just run the following stored procedure which will give you all the permissions associated with the user. sp_helprotect @username = 'guest' Disable Guest Account REVOKE CONNECT FROM guest Additionally, the guest account cannot be disabled in master and tempdb; it is always enabled. There is a special need for this. Let me ask a question back at you: In which scenario do you think this will be useful to keep the guest, and what will the additional configuration go along with the scenario? Note: Special mention to Imran Mohammed for being always there when users need help. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Security, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Exchange accidentally forwards sent mails from one User to another User's Inbox

    - by Das Butterschnitzel
    Like the Topic says: Our Exchange Server accidentally forwards sent mails from one User to another User's Inbox. The sent mails are mostly to Outbound Adresses and they where successfully delivered but all those sent Mails are accidentally forwarded into our Info Mail account. There are no Outlook rules defined and the forward routing in exchange is not used, for such things. I really don´t know the cause of the problem and i don´t know where I have to look, because I´m new to exchange...

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  • Project Euler 79: what am I missing?

    - by Evert
    Hi Guys, I'm not interested in the answer, but I need to be pointed in the right direction Here's problem 79 I first try to analyze the file myself. I've noticed that the number 7 only ever appears as the first digit. This immediately implies that all the numbers containing 7 never overlaps with under numbers (on the left side). Since the questions in project euler always have 1 answer, I believe I'm misunderstanding the question. Do I not have to use all numbers? If I do have to use all numbers, there's many different possible numbers. Where am I going wrong?

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  • which euler rotations can i use ?

    - by melis
    i have two cartesian coordinates. There are xyz and BIG XYZ. I want to make these are paralel each other.forexample , x paralel to X ,y paralel to Y and z paralel to Z. I use rotation matris but I have a lot of different rotation matris . for example I have 3D point in xyz cartesien coordinates and its called A. and I want to change cartesien coordinate to BIG XYZ and find the same 3D point in this coordinates its called B.Until now it is okay. But when I used different rotational matris , points were changed.what can I do? Which Euler rotations can i use?

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  • more ruby way of doing project euler #2

    - by aharon
    I'm trying to learn Ruby, and am going through some of the Project Euler problems. I solved two as such: def fib(n) return n if n < 2 vals = [0, 1] n.times do vals.push(vals[-1]+vals[-2]) end return vals.last end i = 1 s = 0 while((v = fib(i)) < 4_000_000) s+=v if v%2==0 i+=1 end puts s While that works, it seems not very ruby-ish—I couldn't come up with any good purely Ruby answer like I could with the first one ( puts ( (0..999).inject{ |sum, n| n%3==0||n%5==0 ? sum : sum+n } )).

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  • Why can't get past the user info screen when installing 10.10?

    - by Faceless
    I have a Dell Inspiron 1318 (07-08?) with an Intel Cored 2 Duo Processor and 3 GB of RAM. I can run Ubuntu 10.10 from the disk, but I've tried to install it three times with no success. As the files are installing, the program asks me to enter my user information. I'm fine through the time zone screen, and fine through the keyboard screen. But when it asks me to set my used name and password, the "next" button stays ghosted out no matter what I enter. Eventually, the installation gets to the point where it says it's waiting for me, but no matter what I do I can't get the "next" button to click. I'm a complete newbie, and I've been stuck at the same spot three times. If anyone has any idea what's going wrong, I'd love to hear about it.

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  • Project Euler #163 understanding

    - by Paul
    I spent quite a long time searching for a solution to this problem. I drew tons of cross-hatched triangles, counted the triangles in simple cases, and searched for some sort of pattern. Unfortunately, I hit the wall. I'm pretty sure my programming/math skills did not meet the prereq for this problem. So I found a solution online in order to gain access to the forums. I didn't understand most of the methods at all, and some just seemed too complicated. Can anyone give me an understanding of this problem? One of the methods, found here: http://www.math.uni-bielefeld.de/~sillke/SEQUENCES/grid-triangles (Problem C) allowed for a single function to be used. How did they come up with that solution? At this point, I'd really just like to understand some of the concepts behind this interesting problem. I know looking up the solution was not part of the Euler spirit, but I'm fairly sure I would not have solved this problem anyhow.

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  • Why do some user agents have spam urls in them (and why are they always Opera/Presto User-Agents)?

    - by Erx_VB.NExT.Coder
    If you go to (say) the last 100 entries (visits) to the botsvsbrowsers.com website (exact link, feel free to take a look: http://www.botsvsbrowsers.com/recent/listings/index.html ), you'd notice that almost every User Agent that has the keywords "Opera" and "Presto" inside them, will almost certainly have a web link (URL/Web Address) inside it, and it won't just be a normal web address, but a HTML anchor tag/link to that address. Why is this so, I could not even find a single discussion about it on the internet, nowhere, I tried varying my search terms many times. If the user agent contains the words "Opera" and "Presto" it doesnt mean it will have this weblink, but it means there is about an 80% change that it will. A typical anchor tag/link inside a user agent will look like this: Mozilla/4.0 <a href="http://osis-uk.co.uk/disabled-equipment">disability equipment</a> (Windows NT 5.1; U; en) Presto/2.10.229 Version/11.60 If you check it out at the website, http://www.botsvsbrowsers.com/recent/listings/index.html you will notice that the back and forward arrows are in there unescaped format. This isn't just true for botsvsbrowsers, but several other user agent listing sites. I'm really confused and feel line I'm in a room full of 10,000 people and am the only one seeing this ghost :). If I'm doing statistical analysis, should I include or exclude this type of user agent from my listing (ie: are these just normal users who've set their user agents to attempt to drive some traffic to their sites as they browser the web), or is there something else going on? The fact that it is so consistent in terms of its format leads me to believe that it is an automated process (the setting or alteration of the user agent) so I cannot decide or understand the process by which this change is made (I know how to change a user agent), but unsure which program or facility is doing this, especially since it is exclusive to Opera (Presto) user agents that are beyond I think an 8 or 9 point something browser version. I've run some statistical tests, parsing entries from all over the place, writing custom programs, to get a better understanding of this. Keep in mind that I see normal URL's in user agents infrequently, they are just text such as +http://www.someSite.com appended to a user agent normally, especially if its a crawler or bot it provided its service URL, this is normal and isnt done with an embedded link (A HREF=) etc, so I'm not talking about "those".

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  • Project Euler: Programmatic Optimization for Problem 7?

    - by bmucklow
    So I would call myself a fairly novice programmer as I focused mostly on hardware in my schooling and not a lot of Computer Science courses. So I solved Problem 7 of Project Euler: By listing the first six prime numbers: 2, 3, 5, 7, 11, and 13, we can see that the 6th prime is 13. What is the 10001st prime number? I managed to solve this without problem in Java, but when I ran my solution it took 8 and change seconds to run. I was wondering how this could be optimized from a programming standpoint, not a mathematical standpoint. Is the array looping and while statements the main things eating up processing time? And how could this be optimized? Again not looking for a fancy mathematical equation..there are plenty of those in the solution thread. SPOILER My solution is listed below. public class PrimeNumberList { private ArrayList<BigInteger> primesList = new ArrayList<BigInteger>(); public void fillList(int numberOfPrimes) { primesList.add(new BigInteger("2")); primesList.add(new BigInteger("3")); while (primesList.size() < numberOfPrimes){ getNextPrime(); } } private void getNextPrime() { BigInteger lastPrime = primesList.get(primesList.size()-1); BigInteger currentTestNumber = lastPrime; BigInteger modulusResult; boolean prime = false; while(!prime){ prime = true; currentTestNumber = currentTestNumber.add(new BigInteger("2")); for (BigInteger bi : primesList){ modulusResult = currentTestNumber.mod(bi); if (modulusResult.equals(BigInteger.ZERO)){ prime = false; break; } } if(prime){ primesList.add(currentTestNumber); } } } public BigInteger get(int primeTerm) { return primesList.get(primeTerm - 1); } }

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  • Project Euler 7 Scala Problem

    - by Nishu
    I was trying to solve Project Euler problem number 7 using scala 2.8 First solution implemented by me takes ~8 seconds def problem_7:Int = { var num = 17; var primes = new ArrayBuffer[Int](); primes += 2 primes += 3 primes += 5 primes += 7 primes += 11 primes += 13 while (primes.size < 10001){ if (isPrime(num, primes)) primes += num if (isPrime(num+2, primes)) primes += num+2 num += 6 } return primes.last; } def isPrime(num:Int, primes:ArrayBuffer[Int]):Boolean = { // if n == 2 return false; // if n == 3 return false; var r = Math.sqrt(num) for (i <- primes){ if(i <= r ){ if (num % i == 0) return false; } } return true; } Later I tried the same problem without storing prime numbers in array buffer. This take .118 seconds. def problem_7_alt:Int = { var limit = 10001; var count = 6; var num:Int = 17; while(count < limit){ if (isPrime2(num)) count += 1; if (isPrime2(num+2)) count += 1; num += 6; } return num; } def isPrime2(n:Int):Boolean = { // if n == 2 return false; // if n == 3 return false; var r = Math.sqrt(n) var f = 5; while (f <= r){ if (n % f == 0) { return false; } else if (n % (f+2) == 0) { return false; } f += 6; } return true; } I tried using various mutable array/list implementations in Scala but was not able to make solution one faster. I do not think that storing Int in a array of size 10001 can make program slow. Is there some better way to use lists/arrays in scala?

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  • Project Euler (P14): recursion problems

    - by sean mcdaid
    Hi I'm doing the Collatz sequence problem in project Euler (problem 14). My code works with numbers below 100000 but with numbers bigger I get stack over-flow error. Is there a way I can re-factor the code to use tail recursion, or prevent the stack overflow. The code is below: import java.util.*; public class v4 { // use a HashMap to store computed number, and chain size static HashMap<Integer, Integer> hm = new HashMap<Integer, Integer>(); public static void main(String[] args) { hm.put(1, 1); final int CEILING_MAX=Integer.parseInt(args[0]); int len=1; int max_count=1; int max_seed=1; for(int i=2; i<CEILING_MAX; i++) { len = seqCount(i); if(len > max_count) { max_count = len; max_seed = i; } } System.out.println(max_seed+"\t"+max_count); } // find the size of the hailstone sequence for N public static int seqCount(int n) { if(hm.get(n) != null) { return hm.get(n); } if(n ==1) { return 1; } else { int length = 1 + seqCount(nextSeq(n)); hm.put(n, length); return length; } } // Find the next element in the sequence public static int nextSeq(int n) { if(n%2 == 0) { return n/2; } else { return n*3+1; } } }

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  • Lazy Sequences that "Look Ahead" for Project Euler Problem 14

    - by ivar
    I'm trying to solve Project Euler Problem 14 in a lazy way. Unfortunately, I may be trying to do the impossible: create a lazy sequence that is both lazy, yet also somehow 'looks ahead' for values it hasn't computed yet. The non-lazy version I wrote to test correctness was: (defn chain-length [num] (loop [len 1 n num] (cond (= n 1) len (odd? n) (recur (inc len) (+ 1 (* 3 n))) true (recur (inc len) (/ n 2))))) Which works, but is really slow. Of course I could memoize that: (def memoized-chain (memoize (fn [n] (cond (= n 1) 1 (odd? n) (+ 1 (memoized-chain (+ 1 (* 3 n)))) true (+ 1 (memoized-chain (/ n 2))))))) However, what I really wanted to do was scratch my itch for understanding the limits of lazy sequences, and write a function like this: (def lazy-chain (letfn [(chain [n] (lazy-seq (cons (if (odd? n) (+ 1 (nth lazy-chain (dec (+ 1 (* 3 n))))) (+ 1 (nth lazy-chain (dec (/ n 2))))) (chain (+ n 1)))))] (chain 1))) Pulling elements from this will cause a stack overflow for n2, which is understandable if you think about why it needs to look 'into the future' at n=3 to know the value of the tenth element in the lazy list because (+ 1 (* 3 n)) = 10. Since lazy lists have much less overhead than memoization, I would like to know if this kind of thing is possible somehow via even more delayed evaluation or queuing?

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  • Project Euler #14 and memoization in Clojure

    - by dbyrne
    As a neophyte clojurian, it was recommended to me that I go through the Project Euler problems as a way to learn the language. Its definitely a great way to improve your skills and gain confidence. I just finished up my answer to problem #14. It works fine, but to get it running efficiently I had to implement some memoization. I couldn't use the prepackaged memoize function because of the way my code was structured, and I think it was a good experience to roll my own anyways. My question is if there is a good way to encapsulate my cache within the function itself, or if I have to define an external cache like I have done. Also, any tips to make my code more idiomatic would be appreciated. (use 'clojure.test) (def mem (atom {})) (with-test (defn chain-length ([x] (chain-length x x 0)) ([start-val x c] (if-let [e (last(find @mem x))] (let [ret (+ c e)] (swap! mem assoc start-val ret) ret) (if (<= x 1) (let [ret (+ c 1)] (swap! mem assoc start-val ret) ret) (if (even? x) (recur start-val (/ x 2) (+ c 1)) (recur start-val (+ 1 (* x 3)) (+ c 1))))))) (is (= 10 (chain-length 13)))) (with-test (defn longest-chain ([] (longest-chain 2 0 0)) ([c max start-num] (if (>= c 1000000) start-num (let [l (chain-length c)] (if (> l max) (recur (+ 1 c) l c) (recur (+ 1 c) max start-num)))))) (is (= 837799 (longest-chain))))

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