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  • zsh: command not found: ls

    - by ABach
    I'm having a rather strange problem with zsh. When I start up my shell, everything - functions, environment vars, aliases, etc. - all work fine. I've created the following function and sourced it in zsh: clean() { for i in /tmp/* do echo $i done } Running clean in the terminal works as expected, in that it prints out all the files in /tmp/. Afterward, however, trying any command - for example, ls - produces this: zsh: command not found: ls I have several other functions that work just fine, which leads me to believe that somehow, that loop is causing the problem. At any rate, this is very frustrating and I would sincerely appreciate the community's eyes. Thanks!

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  • the commands ls and get of ftp are not working in vmware

    - by mnish
    Hi, Iam using vmware player version 3.1 to boot a minix 3 os image. After booting the minix os I want to get some files from a server using ftp. the ftp connection to the server works but when i use the commands "ls" or "get" nothing happens except it says "200 PORT command successful" and it hanges in there. The only thing i can do after typing ls+enter or get+enter is to exit the ftp by using ctrl+c. If anyone knows a solution to this? please help. Thank you

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  • Unix list absolute file name

    - by Matthew Adams
    Given an arbitrary single argument representing a file (or directory, device, etc), how do I get the absolute path of the argument? I've seen many answers to this question involving find/ls/stat/readlink and $PWD, but none that suits my need. It looks like the closest answer is ksh's "whence" command, but I need it to work in sh/bash. Assume a file, foo.txt, is located in my home directory, /Users/matthew/foo.txt. I need the following behavior, despite what my current working directory is (I'm calling the command "abs"): (PWD is ~) $ abs foo.txt /Users/matthew/foo.txt $ abs ~/foo.txt /Users/matthew/foo.txt $ abs ./foo.txt /Users/matthew/foo.txt $ abs /Users/matthew/foo.txt /Users/matthew/foo.txt What would "abs" really be? TIA, Matthew

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  • directory listing on Mac OS X

    - by user27150
    I dumped a bunch of files (music and otherwise) onto my shiny new Macbook, and since I'm more comfortable with linux than Mac (at this point) I tend to use the terminal. I did a ls -al on the files I'd transfered, and some had an "@" at the end of the permissions string, and some did not. Something like: drwxrwxr--@ 93 user staff etc. drwxrwxr-- 107 user staff etc. The ones without "@" could be seen in Finder and accessed by other programs-- the "@" files and directories were invisible. Can anyone explain what the "@" means, and how to chmod (or whatever) so I can use these files? I assume it is some sort of system flag but I don't know how to unset it. Chmod 777 had no effect and I already own the files. Thanks

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  • LS command for torrent files

    - by amir-beygi
    Hi all I have a directory full of torrent files,and i have to download all of them; But the problem is i have disk limit in my remote server,and file sizes are vary(100MB~8GB) and if i add all of torrent files ,none of them would be download completely;So i need a command to list all my torrents and the size of them , to be selected and add to download list later . NOTE: REMOTE SERVER - LINUX_UBUNTU_9.10 // SSH So i need a command like torrentls That output somethings like: file1.torrent 1111MB file2.torrent 222MB file3.torrent 3333MB file4.torrent 444MB file5.torrent 5555MB

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  • ls, rm, cd commands not working in SUSE LINUX

    - by Jak
    Hi All, Iam newbi to SUSE, I installed java in my SUSE linux Server edition, So i want to set the path in linux,So i created .bash_profile in in /root path using touch and added the path as "JAVA_PATH". When restart my linux the above command is not working and it show unknown command "JAVA_PATH", I can't able to boot in GUI mode, I can boot only in terminal mode, How to delete the file (.bash_profile in /root) ? And how to add java path in SUSE Note: Before all the commands are working fine Thanks in Advance, Jak...

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  • All terminal commands (like ls, cd, edit, open) are returning errors on my Mac

    - by park
    From what I can tell from reading other questions/answers is that my .bash_profile file may be corrupt. If I type echo $PATH in terminal the result is: /usr/local/git/bin From what I've read, that's not what the result is supposed to be. But I also can't get any of the commands (like edit or subl, for Sublime Text 2) to open the .bash_profile file to edit it. I was able to open the file in TextEdit using "cmd-shift-.", and here's what's in the file: [[ -s "$HOME/.rvm/scripts/rvm" ]] && source "$HOME/.rvm/scripts/rvm" PATH=$PATH:~/bin export PATH export PATH=/usr/local/git/bin But the file is LOCKED, so I can't edit it there either. I'm very new to programming and in the middle of trying to install everything on my Mac to go through a Ruby on Rails tutorial. I can't even check my version of ruby, since even ruby -v returns -bash: ruby: command not found Any help would be greatly appreciated. Thanks.

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  • Linux ls[] command

    - by pedro
    ubuntu@ubuntu:/$ ls /dev/tty[15-24]* /dev/tty1 /dev/tty13 /dev/tty17 /dev/tty40 /dev/tty44 /dev/tty48 /dev/tty10 /dev/tty14 /dev/tty18 /dev/tty41 /dev/tty45 /dev/tty49 /dev/tty11 /dev/tty15 /dev/tty19 /dev/tty42 /dev/tty46 what is wrong?

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  • why the output of ls is like this

    - by dorelal
    I am using snow leopard and this is what I get in my terminal. By default I am using bash. > ls c* clock: PSD demo.html jquery.tzineClock script.js styles.css clock2: clojure-presentations: Clojure-1up.pdf ClojureInTheField-1up.pdf license.html Clojure-4up.pdf README ClojureForRubyists-1up.pdf keynote coffee-script: Cakefile README bin examples index.html package.json test LICENSE Rakefile documentation extras lib src vendor

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  • How to order a ls output by suffix?

    - by Luca Borrione
    Having a ls output like GGGG_3.0.3_98/ GGGG_3.0.3_d_100/ GGGG_3.0.3_d_101/ GGGG_3.0.3_d_99/ GGGG_3.0.4_104/ GGGG_3.0.4_105/ GGGG_3.0.4_106/ GGGG_3.0_87/ GGGG_3.0_89/ GGGG_3.0_90/ GGGG_3.0_91/ GGGG_3.0_92/ GGGG_3.0_93/ SSS_2.2.3_01/ SSS_2.2.3_02/ SSS_2.2.3_03/ TTT_2.8.3_29/ how to get the elements ordered by suffix? Also, is there any quick command I can use to know that 106 is the last suffix in this example? Sorry: it wasn't clear that "the suffix" in the given example is everything following the final underscore.

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  • Scripts help FIND command via atime output to multiple files

    - by sswagner
    here is a script I have wrote that I need help with. in the script I do a find for any file that has not been access for over 30 days, 60, 90, 180, 270 & 365 days. This works just fine. however, this takes a few days just to finish the 30 day portion. it is scanning a NAS. (millions and millions of files) as you see, the 30 day information really holds all the data need for the rest of the scripts. the 60, 90, etc. portion of the script are just redoing the same effort as the 30 day portion, except for an extended time frame. it would save in this case weeks worth of re-scanning if some how the 60, 90 180, etc.. portions could just get its data from the 30 day output. this is where I am asking for help. the output is just like an ls -l command. and you can also see from the output below, there are multiple years in this output. the script is attached and printed below. total 24 -rw-r--r-- 1 root bin 60 Apr 12 13:07 config_file -rw-r--r-- 1 root bin 9 Apr 12 13:07 config_file.InProgress -rw-r--r-- 1 root bin 0 Apr 12 13:07 config_file.sids -rw-r--r-- 1 root bin 1284 Apr 19 10:41 rpt_file -rw-r--r-- 1 16074 5003 20083 Apr 26 2002 /nas/quota/slot_2/CR_APP002/eb_ora_bin1/sun8/product/9.2s/oem_webstage/oracle/sysman/qtour/console/dat1_01.gif -rw-r--r-- 1 16074 5003 20088 Apr 26 2002 /nas/quota/slot_2/CR_APP002/eb_ora_bin1/sun8/product/9.2s/oem_webstage/oracle/sysman/qtour/console/set1_04.gif -rw-r--r-- 1 16074 5003 2008 Apr 26 2002 /nas/quota/slot_2/CR_APP002/eb_ora_bin1/sun8/product/9.2s/oem_webstage/oracle/sysman/qtour/oapps/get2_03.htm -rw-r--r-- 1 16074 5003 20083 Apr 26 2002 /nas/quota/slot_2/CR_APP002/eb_ora_bin1/sun8/product/9.2s/oem_webstage/oracle/sysman/qtour/oapps/per1_01.gif any help is appreciated. these are linux distro boxes, so I am sure perl is on there too if needed.. Thanks! !/bin/ksh # search shares for files that have not been accessed for a certain time. NOTE: $IN = input search $OUT = output directory for text file # TESTS Numeric arguments can be specified as # +n for greater than n, -n for less than n, n for exactly n. # -atime n File was last accessed n*24 hours ago. # # IN1=/nas/quota/slot_2/CR* IN2=/nas/quota/slot_3/CR* IN3=/nas/quota/slot_4/CR* IN4=/nas/quota/slot_5/CR* OUT=/nas/quota/slot_3/CR_PRJ144/steve mkdir ${OUT} for dir in ${IN1}; do find $dir -atime +30 -exec ls -l '{}' \; ${OUT}/30days.txt; done for dir in ${IN2}; do find $dir -atime +30 -exec ls -l '{}' \; ${OUT}/30days.txt; done for dir in ${IN3}; do find $dir -atime +30 -exec ls -l '{}' \; ${OUT}/30days.txt; done for dir in ${IN4}; do find $dir -atime +30 -exec ls -l '{}' \; ${OUT}/30days.txt; done for dir in ${IN1}; do find $dir -atime +60 -exec ls -l '{}' \; ${OUT}/60days.txt; done for dir in ${IN2}; do find $dir -atime +60 -exec ls -l '{}' \; ${OUT}/60days.txt; done for dir in ${IN3}; do find $dir -atime +60 -exec ls -l '{}' \; ${OUT}/60days.txt; done for dir in ${IN4}; do find $dir -atime +60 -exec ls -l '{}' \; ${OUT}/60days.txt; done for dir in ${IN1}; do find $dir -atime +90 -exec ls -l '{}' \; ${OUT}/90days.txt; done for dir in ${IN2}; do find $dir -atime +90 -exec ls -l '{}' \; ${OUT}/90days.txt; done for dir in ${IN3}; do find $dir -atime +90 -exec ls -l '{}' \; ${OUT}/90days.txt; done for dir in ${IN4}; do find $dir -atime +90 -exec ls -l '{}' \; ${OUT}/90days.txt; done for dir in ${IN1}; do find $dir -atime +180 -exec ls -l '{}' \; ${OUT}/180days.txt; done for dir in ${IN2}; do find $dir -atime +180 -exec ls -l '{}' \; ${OUT}/180days.txt; done for dir in ${IN3}; do find $dir -atime +180 -exec ls -l '{}' \; ${OUT}/180days.txt; done for dir in ${IN4}; do find $dir -atime +180 -exec ls -l '{}' \; ${OUT}/180days.txt; done for dir in ${IN1}; do find $dir -atime +270 -exec ls -l '{}' \; ${OUT}/270days.txt; done for dir in ${IN2}; do find $dir -atime +270 -exec ls -l '{}' \; ${OUT}/270days.txt; done for dir in ${IN3}; do find $dir -atime +270 -exec ls -l '{}' \; ${OUT}/270days.txt; done for dir in ${IN4}; do find $dir -atime +270 -exec ls -l '{}' \; ${OUT}/270days.txt; done for dir in ${IN1}; do find $dir -atime +365 -exec ls -l '{}' \; ${OUT}/365days.txt; done for dir in ${IN2}; do find $dir -atime +365 -exec ls -l '{}' \; ${OUT}/365days.txt; done for dir in ${IN3}; do find $dir -atime +365 -exec ls -l '{}' \; ${OUT}/365days.txt; done for dir in ${IN4}; do find $dir -atime +365 -exec ls -l '{}' \; ${OUT}/365days.txt; done

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  • Mercurial - Files nog showing on server (ls command)

    - by Bumbolt
    I'm trying to setup a java buildserver with jenkins,maven and mercurial. Now my mercurial server is working i can push, pull and commit. Running the command 'hg serve' on the server allows me to see commits from my clients. But when i go manually into the repository (cd in server-terminal) and do an 'ls' command i can't see any file. When i clone the repository onto a new client i DO recieve the files pushed by the other clients. This is somewhat strange behaviour. Does anyone recognize this? What should i do to fix this?

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  • Improved technique to store a filename in a variable?

    - by SDGuero
    Greetings, I need to store the filename of a log into a variable so my script can perform some checks on the daily log files. These logs always have a different name because they have a timestamp in the name. Currently I'm using a hodge podged method that pipes an ls command to sed, sort, cut, and tail in order to get the name out. CRON_LOG=$(ls -1 $LOGS_DIR/fetch_cron_{true,false}_$CRON_DATE*.log 2> /dev/null | sed 's/^[^0-9][^0-9]*\([0-9][0-9]*\).*/\1 &/' | sort -n | cut -d ' ' -f2- | tail -1 ) UPDATE: $CRON_DATE is supplied as an argument to the script. It is the date (to the day) that the log was created on. Sometimes multiple logs will exist for the same day so I want this to get the most recent one. A typical filename is fetch_cron_false_031810090452.log I'm pretty sure I kluged this together from some stuff I found google a few months ago. it works now but I'm not really happy with the technique. I have some ideas about how to do this better but I have had great success on this site before and thought it might be best to refer to the stackoverflow gods first. All answers are greatly appreciated. Thanks, Ryan

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  • What is user/owner 24561?

    - by ralphthemagician
    So, I just installed the node.js package from nodejs.org and I was poking around to see what it installed. Over in /usr/local/bin I saw this owner 24561. I see it in a few other places too. What is this? What does it mean? Should it be root like everything else? lrwxr-xr-x 1 root wheel 66 Jun 23 13:02 mate -> /Applications/TextMate.app/Contents/SharedSupport/Support/bin/mate -rwxr-xr-x 1 24561 wheel 18865984 Jun 29 09:32 node -rwxr-xr-x 1 24561 wheel 355 Jun 29 09:32 node-waf lrwxr-xr-x 1 root wheel 38 Jul 3 12:15 npm -> ../lib/node_modules/npm/bin/npm-cli.js What was curious is that I couldn't find any other information about this user by Googling. Using OS X Lion 10.7.4 with Xcode installed if that makes any difference.

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  • List files recursively in linux with path relative to the current directory

    - by Darryl Hein
    This is similar to this question, but I want to include the path relative to the current directory in unix. If can do the following: ls -LR | grep .txt But it doesn't include the full paths. For example, I have the follow dir structure: test1/file.txt test2/file1.txt test2/file2.txt The code above will return: file.txt file1.txt file2.txt How can I get it to include the paths relative to the current directory using standard nix commands?

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  • Maximum number of inodes in a directory?

    - by Dr. UNIX
    Is there a maximum number of inodes in a single directory? I have a directory of 2 million+ files and can't get an the ls command to work against that directory. So now I'm wondering if I've exceeded a limit on inodes in Linux. Is there a limit before a 2^64 numerical limit?

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  • Listing the content of a tar file or a directory only down to some level

    - by Tim
    I wonder how to list the content of a tar file only down to some level? I understand tar tvf mytar.tar will list all files, but sometimes I would like to only see directories down to some level. Similarly, for the command ls, how do I control the level of subdirectories that will be displayed? By default, it will only show the direct subdirectories, but not go further.

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  • a program similar to ls with some modifications

    - by Bond
    Hi, here is a simple puzzle I wanted to discuss. A C program to take directory name as command line argument and print last 3 directories and 3 files in all subdirectories without using api 'system' inside it. suppose directory bond0 contains bond1, di2, bond3, bond4, bond5 and my_file1, my_file2, my_file3, my_file4, my_file5, my_file6 and bond1 contains bond6 my_file7 my_file8 my_file9 my_file10 program should output - bond3, bond4, bond5, my_file4, my_file5, my_file6, bond6, my_file8, my_file9, my_file10 My code for the above problem is here #include<dirent.h> #include<unistd.h> #include<string.h> #include<sys/stat.h> #include<stdlib.h> #include<stdio.h> char *directs[20], *files[20]; int i = 0; int j = 0; int count = 0; void printdir(char *); int count_dirs(char *); int count_files(char *); int main() { char startdir[20]; printf("Scanning user directories\n"); scanf("%s", startdir); printdir(startdir); } void printdir(char *dir) { printf("printdir called %d directory is %s\n", ++count, dir); DIR *dp = opendir(dir); int nDirs, nFiles, nD, nF; nDirs = 0; nFiles = 0; nD = 0; nF = 0; if (dp) { struct dirent *entry = 0; struct stat statBuf; nDirs = count_dirs(dir); nFiles = count_files(dir); printf("The no of subdirectories in %s is %d \n", dir, nDirs); printf("The no of files in %s is %d \n", dir, nFiles); while ((entry = readdir(dp)) != 0) { if (strcmp(entry->d_name, ".") == 0 || strcmp(entry->d_name, "..") == 0) { continue; } char *filepath = malloc(strlen(dir) + strlen(entry->d_name) + 2); if (filepath) { sprintf(filepath, "%s/%s", dir, entry->d_name); if (lstat(filepath, &statBuf) != 0) { } if (S_ISDIR(statBuf.st_mode)) { nD++; if ((nDirs - nD) < 3) { printf("The directory is %s\n",entry->d_name); } } else { nF++; if ((nFiles - nF) < 3) { printf("The files are %s\n", entry->d_name); } //if } //else free(filepath); } //if(filepath) } //while while ((entry = readdir(dp)) != 0) { if (strcmp(entry->d_name, ".") == 0 || strcmp(entry->d_name, "..") == 0) { continue; } printf("In second while loop *entry=%s\n",entry->d_name); char *filepath = malloc(strlen(dir) + strlen(entry->d_name) + 2); if (filepath) { sprintf(filepath, "%s/%s", dir, entry->d_name); if (lstat(filepath, &statBuf) != 0) { } if (S_ISDIR(statBuf.st_mode)) { printdir(entry->d_name); } } //else free(filepath); } //2nd while closedir(dp); } else { fprintf(stderr, "Error, cannot open directory %s\n", dir); } } //printdir int count_dirs(char *dir) { DIR *dp = opendir(dir); int nD; nD = 0; if (dp) { struct dirent *entry = 0; struct stat statBuf; while ((entry = readdir(dp)) != 0) { if (strcmp(entry->d_name, ".") == 0 || strcmp(entry->d_name, "..") == 0) { continue; } char *filepath = malloc(strlen(dir) + strlen(entry->d_name) + 2); if (filepath) { sprintf(filepath, "%s/%s", dir, entry->d_name); if (lstat(filepath, &statBuf) != 0) { fprintf(stderr, "File Not found? %s\n", filepath); } if (S_ISDIR(statBuf.st_mode)) { nD++; } else { continue; } free(filepath); } } closedir(dp); } else { fprintf(stderr, "Error, cannot open directory %s\n", dir); } return nD; } int count_files(char *dir) { DIR *dp = opendir(dir); int nF; nF = 0; if (dp) { struct dirent *entry = 0; struct stat statBuf; while ((entry = readdir(dp)) != 0) { if (strcmp(entry->d_name, ".") == 0 || strcmp(entry->d_name, "..") == 0) { continue; } char *filepath = malloc(strlen(dir) + strlen(entry->d_name) + 2); if (filepath) { sprintf(filepath, "%s/%s", dir, entry->d_name); if (lstat(filepath, &statBuf) != 0) { fprintf(stderr, "File Not found? %s\n", filepath); } if (S_ISDIR(statBuf.st_mode)) { continue; } else { nF++; } free(filepath); } } closedir(dp); } else { fprintf(stderr, "Error, cannot open file %s\n", dir); } return nF; } The above code I wrote is a bit not functioning correctly can some one help me to understand the error which is coming.So that I improve it further.There seems to be some small glitch which is not clear to me right now.

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  • How to rename files in a folder using the ls command output as a pipe ?

    - by user1179459
    I am using GNU/Linux and BASH shell, What i wanted to do is in server is to i need to be able to download the files stating with B* and D* and then rename them to ~B* and ~D*(same file name just ~ in-front) i wrote following which works fine for the downloading part ideally i would like it to use ls command output as well but dont know how to do that. cd inbox get D* get B* ls B*|rename $0 ~B.* bye Any idea ? ideally what i would like to do is ls command to send the list of files one by one to the get command and then the once the get command is completed i want rename command executed renaming the server files

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  • No Alias's when sudo'ing

    - by Danny Roberts
    I was playing around with aliases today and I noticed that aliases don't seem to be available whilst using sudo: danny@kaon:~$ alias alias egrep='egrep --color=auto' alias fgrep='fgrep --color=auto' alias grep='grep --color=auto' alias l='ls -CF' alias la='ls -A' alias ll='ls -alF' alias ls='ls --color=auto' danny@kaon:~$ ll -d / drwxr-xr-x 23 root root 4096 2011-01-06 20:29 // danny@kaon:~$ sudo -i root@kaon:~# ll -d / drwxr-xr-x 23 root root 4096 2011-01-06 20:29 // root@kaon:~# exit logout danny@kaon:~$ sudo ll -d / sudo: ll: command not found Is there any reason why you cannot use aliases whilst using sudo?

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  • Aliases not available when using sudo

    - by Danny Roberts
    I was playing around with aliases today and I noticed that aliases don't seem to be available whilst using sudo: danny@kaon:~$ alias alias egrep='egrep --color=auto' alias fgrep='fgrep --color=auto' alias grep='grep --color=auto' alias l='ls -CF' alias la='ls -A' alias ll='ls -alF' alias ls='ls --color=auto' danny@kaon:~$ ll -d / drwxr-xr-x 23 root root 4096 2011-01-06 20:29 // danny@kaon:~$ sudo -i root@kaon:~# ll -d / drwxr-xr-x 23 root root 4096 2011-01-06 20:29 // root@kaon:~# exit logout danny@kaon:~$ sudo ll -d / sudo: ll: command not found Is there any reason why you cannot use aliases whilst using sudo?

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  • Why is this file hidden when you run ls?

    - by luckytaxi
    For a few weeks now I couldn't figure out why I wasn't able to delete this one particular file. As root I can, but my shell script runs as a different user. So I go run ls -la and it's not there. However, if I call it as a parameter, it shows up! Sure enough, the owner is root, hence I'm not able to delete. Notice, 6535 is missing ... [root@server]# ls -la 653* -rw-rw-r-- 1 svn svn 24002 Mar 26 01:00 653 -rw-rw-r-- 1 svn svn 7114 Mar 26 01:01 6530 -rw-rw-r-- 1 svn svn 8653 Mar 26 01:01 6531 -rw-rw-r-- 1 svn svn 6836 Mar 26 01:01 6532 -rw-rw-r-- 1 svn svn 3308 Mar 26 01:01 6533 -rw-rw-r-- 1 svn svn 3918 Mar 26 01:01 6534 -rw-rw-r-- 1 svn svn 3237 Mar 26 01:01 6536 -rw-rw-r-- 1 svn svn 3195 Mar 26 01:01 6537 -rw-rw-r-- 1 svn svn 27725 Mar 26 01:01 6538 -rw-rw-r-- 1 svn svn 263473 Mar 26 01:01 6539 Now it shows up if you call it directly. [root@server]# ls -la 6535 -rw-rw-r-- 1 root root 3486 Mar 26 01:01 6535

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