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  • problem with twitter api friends_timeline

    - by siznax
    i can get my user_timeline fine: curl -u user:pwd http://www.twitter.com/statuses/user_timeline/user.json {blob of tweets} but when i try to get the friends_timeline, i get an auth error: curl -u user:pwd http://www.twitter.com/statuses/friends_timeline.json {"request":"\/statuses\/friends_timeline.json", "error":"Could not authenticate you."} do i just not understand the documentation? http://apiwiki.twitter.com/REST+API+Documentation#friendstimeline

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  • ADO.NET connection string and password with "=" in it

    - by Philippe Leybaert
    How do I build a connection string which includes a passsword having a "=" in it? (I'm connecting to MySql 5.1) For example, let's say the password is "Ge5f8z=6", what would the connection string look like? I tried: Server=DBSERV;Database=mydb;UID=myuser;PWD="Ge5f8z=6"; and Server=DBSERV;Database=mydb;UID=myuser;PWD=Ge5f8z=6;" Both don't work.

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  • InsertOnSubmit - NullReferenceException

    - by Jackie Chou
    I have 2 Model AccountEntity [Table(Name = "Account")] public class AccountEntity { [Column(IsPrimaryKey = true, IsDbGenerated = true, AutoSync = AutoSync.OnInsert)] public int id { get; set; } [Column(CanBeNull = false, Name = "email")] public string email { get; set; } [Column(CanBeNull = false, Name = "pwd")] public string pwd { get; set; } [Column(CanBeNull = false, Name = "row_guid")] public Guid guid { get; set; } private EntitySet<DetailsEntity> details_id { get; set; } [Association(Storage = "details_id", OtherKey = "id", ThisKey = "id")] public ICollection<DetailsEntity> detailsCollection { get; set; } } DetailsEntity [Table(Name = "Details")] public class DetailsEntity { public DetailsEntity(AccountEntity a) { this.Account = a; } [Column(IsPrimaryKey = true, IsDbGenerated = true, DbType = "int")] public int id { get; set; } private EntityRef<AccountEntity> _account = new EntityRef<AccountEntity>(); [Association(IsForeignKey = true, Storage = "_account", ThisKey = "id")] public AccountEntity Account { get; set; } } Main using (Database db = new Database()) { AccountEntity a = new AccountEntity(); a.email = "hahaha"; a.pwd = "13212312"; a.guid = Guid.NewGuid(); db.Account.InsertOnSubmit(a); db.SubmitChanges(); } that has relationhip AccountEntity <- DetailsEntity (1-n) when i'm trying to insert a record exception throws NullReferenceException cause: by EntitySet null please help me make it insert

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  • sql 2008 sqldmo alternative

    - by alexdelpiero
    Hi! I previously was using sqldmo to automatically generate scripts from the databse. Now I upgraded to sql server 2008 and I don’t want to use this feature anymore since Microsoft will be dropping this feature off. Is there any other alternative I can use to connect to a server and generate scripts automatically from a database? Any answer is welcome. Thanks in advance. This is the procedure i was previously using: CREATE PROC GenerateSP ( @server varchar(30) = null, @uname varchar(30) = null, @pwd varchar(30) = null, @dbname varchar(30) = null, @filename varchar(200) = 'c:\script.sql' ) AS DECLARE @object int DECLARE @hr int DECLARE @return varchar(200) DECLARE @exec_str varchar(2000) DECLARE @spname sysname SET NOCOUNT ON -- Sets the server to the local server IF @server is NULL SELECT @server = @@servername -- Sets the database to the current database IF @dbname is NULL SELECT @dbname = db_name() -- Sets the username to the current user name IF @uname is NULL SELECT @uname = SYSTEM_USER -- Create an object that points to the SQL Server EXEC @hr = sp_OACreate 'SQLDMO.SQLServer', @object OUT IF @hr < 0 BEGIN PRINT 'error create SQLOLE.SQLServer' RETURN END -- Connect to the SQL Server IF @pwd is NULL BEGIN EXEC @hr = sp_OAMethod @object, 'Connect', NULL, @server, @uname IF @hr < 0 BEGIN PRINT 'error Connect' RETURN END END ELSE BEGIN EXEC @hr = sp_OAMethod @object, 'Connect', NULL, @server, @uname, @pwd IF @hr < 0 BEGIN PRINT 'error Connect' RETURN END END --Verify the connection EXEC @hr = sp_OAMethod @object, 'VerifyConnection', @return OUT IF @hr < 0 BEGIN PRINT 'error VerifyConnection' RETURN END SET @exec_str = 'DECLARE script_cursor CURSOR FOR SELECT name FROM ' + @dbname + '..sysobjects WHERE type = ''P'' ORDER BY Name' EXEC (@exec_str) OPEN script_cursor FETCH NEXT FROM script_cursor INTO @spname WHILE (@@fetch_status < -1) BEGIN SET @exec_str = 'Databases("'+ @dbname +'").StoredProcedures("'+RTRIM(UPPER(@spname))+'").Script(74077,"'+ @filename +'")' EXEC @hr = sp_OAMethod @object, @exec_str, @return OUT IF @hr < 0 BEGIN PRINT 'error Script' RETURN END FETCH NEXT FROM script_cursor INTO @spname END CLOSE script_cursor DEALLOCATE script_cursor -- Destroy the object EXEC @hr = sp_OADestroy @object IF @hr < 0 BEGIN PRINT 'error destroy object' RETURN END GO

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  • SQL Server 2008 alternative for SQL-DMO

    - by alexdelpiero
    Hi! I previously was using SQL-DMO to automatically generate scripts from the database. Now I upgraded to SQL Server 2008 and I don’t want to use this feature anymore since Microsoft will be dropping this feature off. Is there any other alternative I can use to connect to a server and generate scripts automatically from a database? Any answer is welcome. Thanks in advance. This is the procedure i was previously using: CREATE PROC GenerateSP ( @server varchar(30) = null, @uname varchar(30) = null, @pwd varchar(30) = null, @dbname varchar(30) = null, @filename varchar(200) = 'c:\script.sql' ) AS DECLARE @object int DECLARE @hr int DECLARE @return varchar(200) DECLARE @exec_str varchar(2000) DECLARE @spname sysname SET NOCOUNT ON -- Sets the server to the local server IF @server is NULL SELECT @server = @@servername -- Sets the database to the current database IF @dbname is NULL SELECT @dbname = db_name() -- Sets the username to the current user name IF @uname is NULL SELECT @uname = SYSTEM_USER -- Create an object that points to the SQL Server EXEC @hr = sp_OACreate 'SQLDMO.SQLServer', @object OUT IF @hr <> 0 BEGIN PRINT 'error create SQLOLE.SQLServer' RETURN END -- Connect to the SQL Server IF @pwd is NULL BEGIN EXEC @hr = sp_OAMethod @object, 'Connect', NULL, @server, @uname IF @hr <> 0 BEGIN PRINT 'error Connect' RETURN END END ELSE BEGIN EXEC @hr = sp_OAMethod @object, 'Connect', NULL, @server, @uname, @pwd IF @hr <> 0 BEGIN PRINT 'error Connect' RETURN END END --Verify the connection EXEC @hr = sp_OAMethod @object, 'VerifyConnection', @return OUT IF @hr <> 0 BEGIN PRINT 'error VerifyConnection' RETURN END SET @exec_str = 'DECLARE script_cursor CURSOR FOR SELECT name FROM ' + @dbname + '..sysobjects WHERE type = ''P'' ORDER BY Name' EXEC (@exec_str) OPEN script_cursor FETCH NEXT FROM script_cursor INTO @spname WHILE (@@fetch_status <> -1) BEGIN SET @exec_str = 'Databases("'+ @dbname +'").StoredProcedures("'+RTRIM(UPPER(@spname))+'").Script(74077,"'+ @filename +'")' EXEC @hr = sp_OAMethod @object, @exec_str, @return OUT IF @hr <> 0 BEGIN PRINT 'error Script' RETURN END FETCH NEXT FROM script_cursor INTO @spname END CLOSE script_cursor DEALLOCATE script_cursor -- Destroy the object EXEC @hr = sp_OADestroy @object IF @hr <> 0 BEGIN PRINT 'error destroy object' RETURN END GO

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  • use exec for dsadd

    - by Daryl Gill
    I'm Programming on a Windows Server 2008 and I wish to have a WebUI to interact with the domains active directory. One of my main problems is this that i'm using dsadd from a HTML form but this is no succeeding. I know my command is correct, I have tested it out on the Servers Command line My Code is As Below: if (isset($_POST['Submit'])) { $DesiredUsername = $_POST['DesiredUsername']; $DesiredPassword = $_POST['DesiredPassword']; $DU = "{$DesiredUsername}"; // Desired Username $OU = "PHPCreatedUsers"; // Domain OU $DC1 = "slayerserv"; // Domain Part one $DC2 = "local"; // Domain Part Two $PWD = "{$DesiredPassword}"; // Password $ExecScript = 'dsadd user cn=$DesiredUsername,cn=PHPCreatedUsers,dc=slayerserv,dc=local -disabled no -pwd $DesiredPassword -mustchpwd yes'; exec($ExecScript, $output); mysql_query("INSERT INTO addedusers (`ID`, `DU`, `OU`, `DC1`, `DC2, `PWD`) VALUES ('', '$DU', '$OU', '$DC1', '$DC2', '$PWD')"); echo "<br><br>"; print_r($output); # echo "User: $DesiredUsername Has been Created"; } When I print_r($output); it Returns a blank array: Array ( ) Could anyone provide me with a solution or point me in the right direction? ++++ Below is a working example of my usage of exec $Script = 'ping 127.0.0.1 -n 1'; exec($Script, $Output); print_r($Output); print_r($Output); Gives: Array ( [0] = [1] = Pinging 127.0.0.1 with 32 bytes of data: [2] = Reply from 127.0.0.1: bytes=32 time<1ms TTL=128 [3] = [4] = Ping statistics for 127.0.0.1: [5] = Packets: Sent = 1, Received = 1, Lost = 0 (0% loss), [6] = Approximate round trip times in milli-seconds: [7] = Minimum = 0ms, Maximum = 0ms, Average = 0ms )

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  • 401 Unauthorized returned on GET request (https) with correct credentials

    - by Johnny Grass
    I am trying to login to my web app using HttpWebRequest but I keep getting the following error: System.Net.WebException: The remote server returned an error: (401) Unauthorized. Fiddler has the following output: Result Protocol Host URL 200 HTTP CONNECT mysite.com:443 302 HTTPS mysite.com /auth 401 HTTP mysite.com /auth This is what I'm doing: // to ignore SSL certificate errors public bool AcceptAllCertifications(object sender, System.Security.Cryptography.X509Certificates.X509Certificate certification, System.Security.Cryptography.X509Certificates.X509Chain chain, System.Net.Security.SslPolicyErrors sslPolicyErrors) { return true; } try { // request Uri uri = new Uri("https://mysite.com/auth"); HttpWebRequest request = (HttpWebRequest)WebRequest.Create(uri) as HttpWebRequest; request.Accept = "application/xml"; // authentication string user = "user"; string pwd = "secret"; string auth = "Basic " + Convert.ToBase64String(System.Text.Encoding.Default.GetBytes(user + ":" + pwd)); request.Headers.Add("Authorization", auth); ServicePointManager.ServerCertificateValidationCallback = new System.Net.Security.RemoteCertificateValidationCallback(AcceptAllCertifications); // response. HttpWebResponse response = (HttpWebResponse)request.GetResponse(); // Display Stream dataStream = response.GetResponseStream(); StreamReader reader = new StreamReader(dataStream); string responseFromServer = reader.ReadToEnd(); Console.WriteLine(responseFromServer); // Cleanup reader.Close(); dataStream.Close(); response.Close(); } catch (WebException webEx) { Console.Write(webEx.ToString()); } I am able to log in to the same site with no problem using ASIHTTPRequest in a Mac app like this: NSURL *login_url = [NSURL URLWithString:@"https://mysite.com/auth"]; ASIHTTPRequest *request = [ASIHTTPRequest requestWithURL:login_url]; [request setDelegate:self]; [request setUsername:name]; [request setPassword:pwd]; [request setRequestMethod:@"GET"]; [request addRequestHeader:@"Accept" value:@"application/xml"]; [request startAsynchronous];

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  • Submit form with POST data in Android app

    - by datguywhowanders
    I've been searching the web for a way to do this for about a week now, and I just can't seem to figure it out. I'm trying to implement an app that my college can use to allow users to log in to various services on the campus with ease. The way it works currently is they go to an online portal, select which service they want, fill in their user name and pwd, and click login. The form data is sent via post (it includes several hidden values as well as just the user name and pwd) to the corresponding login script which then signs them in and loads the service. I've been trying to come at the problem in two ways. I first tried a WebView, but it doesn't seem to want to support all of the html that normally makes this form work. I get all of the elements I need, fields for user and pwd as well as a login button, but clicking the button doesn't do anything. I wondered if I needed to add an onclick handler for it, but I can't see how as the button is implemented in the html of the webview not using a separate android element. The other possibility was using the xml widgets to create the form in a nice relative layout, which seems to load faster and looks better on the android screen. I used EditText fields for the input, a spinner widget for the service select, and the button widget for the login. I know how to make the onclick and item select handlers for the button and spinner, respectively, but I can't figure out how to send that data via POST in an intent that would then launch a browser. I can do an intent with the action url, but can't get the POST data to feed into it. Anyone have any suggestions?

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  • Display HttpResponse (string from Handler) in new WebView

    - by datguywhowanders
    I have the following code in a form's submit button onClickListener: String action, user, pwd, user_field, pwd_field; action = "theURL"; user_field = "id"; pwd_field = "pw"; user = "username"; pwd = "password!!"; List<NameValuePair> myList = new ArrayList<NameValuePair>(); myList.add(new BasicNameValuePair(user_field, user)); myList.add(new BasicNameValuePair(pwd_field, pwd)); HttpParams params = new BasicHttpParams(); HttpClient client = new DefaultHttpClient(params); HttpPost post = new HttpPost(action); HttpResponse end = null; String endResult = null; try { post.setEntity(new UrlEncodedFormEntity(myList)); } catch (UnsupportedEncodingException e) { // TODO Auto-generated catch block e.printStackTrace(); } try { HttpResponse response = client.execute(post); end = response; } catch (ClientProtocolException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } BasicResponseHandler myHandler = new BasicResponseHandler(); try { endResult = myHandler.handleResponse(end); } catch (HttpResponseException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } How can I take the resulting string (endResult) and start a new activity using an intent that will open webview and load the html?

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  • Am I encrypting my passwords correctly in ASP.NET

    - by Nick
    I have a security class: public class security { private static string createSalt(int size) { //Generate a random cryptographic number RNGCryptoServiceProvider rng = new RNGCryptoServiceProvider(); byte[] b = new byte[size]; rng.GetBytes(b); //Convert to Base64 return Convert.ToBase64String(b); } /// <summary> /// Generate a hashed password for comparison or create a new one /// </summary> /// <param name="pwd">Users password</param> /// <returns></returns> public static string createPasswordHash(string pwd) { string salt = "(removed)"; string saltAndPwd = string.Concat(pwd, salt); string hashedPwd = FormsAuthentication.HashPasswordForStoringInConfigFile( saltAndPwd, "sha1"); return hashedPwd; } } This works fine, but I am wondering if it is sufficient enough. Also, is this next block of code better? Overkill? static byte[] encrInitVector = new byte[] { 0x12, 0x34, 0x56, 0x78, 0x90, 0xAB, 0xCD, 0xEF }; static string encrKey = "(removed)"; public static string EncryptString(string s) { byte[] key; try { key = Encoding.UTF8.GetBytes(encrKey.Substring(0, 8)); DESCryptoServiceProvider des = new DESCryptoServiceProvider(); byte[] inputByteArray = Encoding.UTF8.GetBytes(s); MemoryStream ms = new MemoryStream(); CryptoStream cs = new CryptoStream(ms, des.CreateEncryptor(key, encrInitVector), CryptoStreamMode.Write); cs.Write(inputByteArray, 0, inputByteArray.Length); cs.FlushFinalBlock(); return Convert.ToBase64String(ms.ToArray()); } catch (Exception e) { throw e; }

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  • Who needs singletons?

    - by sexyprout
    Imagine you access your MySQL database via PDO. You got some functions, and in these functions, you need to access the database. The first thing I thought of is global, like: $db = new PDO('mysql:host=127.0.0.1;dbname=toto', 'root', 'pwd'); function some_function() { global $db; $db->query('...'); } But it's considered as a bad practice. So, after a little search, I ended up with the Singleton pattern, which "applies to situations in which there needs to be a single instance of a class." According to the example of the manual, we should do this: class Database { private static $instance, $db; private function __construct(){} static function singleton() { if(!isset(self::$instance)) self::$instance = new __CLASS__; return self:$instance; } function get() { if(!isset(self::$db)) self::$db = new PDO('mysql:host=127.0.0.1;dbname=toto', 'user', 'pwd') return self::$db; } } function some_function() { $db = Database::singleton(); $db->get()->query('...'); } some_function(); But I just can't understand why you need that big class when you can do it merely with: class Database { private static $db; private function __construct(){} static function get() { if(!isset(self::$rand)) self::$db = new PDO('mysql:host=127.0.0.1;dbname=toto', 'user', 'pwd'); return self::$db; } } function some_function() { Database::get()->query('...'); } some_function(); This last one works perfectly and I don't need to worry about $db anymore. But maybe I'm forgetting something. So, who's wrong, who's right?

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  • Unable to plot graph using matplotlib

    - by Aman Deep Gautam
    I have the following code which searches all the directory in the current directory and then takes data from those files to plot the graph. The data is read correctly as verified by printing but there are no points plotted on graph. import argparse import os import matplotlib.pyplot as plt #find the present working directory pwd=os.path.dirname(os.path.abspath(__file__)) #find all the folders in the present working directory. dirs = [f for f in os.listdir('.') if os.path.isdir(f)] plt.figure() plt.xlim(0, 20000) plt.ylim(0, 1) for directory in dirs: os.chdir(os.path.join(pwd, directory)); chd_dir = os.path.dirname(os.path.abspath(__file__)) files = [ fl for fl in os.listdir('.') if os.path.isfile(fl) ] print files for f in files: f_obj = open(os.path.join(chd_dir, f), 'r') list_x = [] list_y = [] for i in xrange(0,4): f_obj.next() for line in f_obj: temp_list = line.split() print temp_list list_y.append(temp_list[0]) list_x.append(temp_list[1]) print 'final_lsit' print list_x print list_y plt.plot(list_x, list_y, 'r.') f_obj.close() os.chdir(pwd) plt.savefig("test.jpg") The input files look like the following: 5 865 14709 15573 14709 1.32667e-06 664 0.815601 14719 1.55333e-06 674 0.813277 14729 1.82667e-06 684 0.810185 14739 1.4e-06 694 0.808459 Can anybody help me with why this is happening? Being new I would like to know some tutorial where I can get help with kind of plotting as the tutorial I was following made me end up here. Any help appreciated.

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  • Why Backbone.js isn't binding my event

    - by Saif Bechan
    I have a router like this, as main entry point: window.AppRouter = Backbone.Router.extend({ routes: { '': 'login' }, login: function(){ userLoginView = new UserLoginView(); } }); var appRouter = new AppRouter; Backbone.history.start({pushState: true}); I have a model/collection/view like this: window.User = Backbone.Model.extend({}); window.Users = Backbone.Collection.extend({ model: User }); window.UserLoginView = Backbone.View.extend({ events: { 'click #login-button': 'loginAction' }, initialize: function(){ _.bindAll(this, 'render', 'loginAction'); }, loginAction: function(){ var uid = $("#login-username").val(); var pwd = $("#login-password").val(); var user = new User({uid:uid, pwd:pwd}); } }); And body of my HTML looks like this: <form action="#" method="POST" id="login-form"> <p> <label for="login-username">username</label> <input type="text" id="login-username" autofocus /> </p> <p> <label for="login-password">password</label> <input type="password" id="login-password" /> </p> <a id="login-button" href="#">Inloggen</a> </form> Note: The HTML comes from Node.js using express.js, should I maybe wait for a document ready event somewhere? Edit: I have tried this, create the view when ready, did not solve the problem. $(function(){ userLoginView = new UserLoginView(); });

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  • Recommended approach for error handling with PHP and MYSQL

    - by iama
    I am trying to capture database (MYSQL) errors in my PHP web application. Currently, I see that there are functions like mysqli_error(), mysqli_errno() for capturing the last occurred error. However, this still requires me to check for error occurrence using repeated if/else statements in my php code. You may check my code below to see what I mean. Is there a better approach to doing this? (or) Should I write my own code to raise exceptions and catch them in one single place? What is the recommended approach? Also, does PDO raise exceptions? Thanks. function db_userexists($name, $pwd, &$dbErr) { $bUserExists = false; $uid = 0; $dbErr = ''; $db = new mysqli(SERVER, USER, PASSWORD, DB); if (!mysqli_connect_errno()) { $query = "select uid from user where uname = ? and pwd = ?"; $stmt = $db->prepare($query); if ($stmt) { if ($stmt->bind_param("ss", $name, $pwd)) { if ($stmt->bind_result($uid)) { if ($stmt->execute()) { if ($stmt->fetch()) { if ($uid) $bUserExists = true; } } } } if (!$bUserExists) $dbErr = $db->error(); $stmt->close(); } if (!$bUserExists) $dbErr = $db->error(); $db->close(); } else { $dbErr = mysqli_connect_error(); } return $bUserExists; }

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  • Agile web development with rails

    - by Steve
    Hi.. This code is from the agile web development with rails book.. I don't understand this part of the code... User is a model which has name,hashed_password,salt as its fields. But in the code they are mentioning about password and password confirmation, while there are no such fields in the model. Model has only hashed_password. I am sure mistake is with me. Please clear this for me :) User Model has name,hashed_password,salt. All the fields are strings require 'digest/sha1' class User < ActiveRecord::Base validates_presence_of :name validates_uniqueness_of :name attr_accessor :password_confirmation validates_confirmation_of :password validate :password_non_blank def self.authenticate(name, password) user = self.find_by_name(name) if user expected_password = encrypted_password(password, user.salt) if user.hashed_password != expected_password user = nil end end user end def password @password end def password=(pwd) @password = pwd return if pwd.blank? create_new_salt self.hashed_password = User.encrypted_password(self.password, self.salt) end private def password_non_blank errors.add(:password,"Missing password")if hashed_password.blank? end def create_new_salt self.salt = self.object_id.to_s + rand.to_s end def self.encrypted_password(password, salt) string_to_hash = password + "wibble" + salt Digest::SHA1.hexdigest(string_to_hash) end end

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  • get random password with puppet function

    - by ninja-2
    I have a function that allow me to generate random password. My function is working well without a puppetmaster. When i tried with a master an error appear when I called the function : Error 400 on SERVER: bad value for range Here is my function module Puppet::Parser::Functions newfunction(:get_random_password, :type => :rvalue, :doc => <<-EOS Returns a random password. EOS ) do |args| raise(Puppet::ParseError, "get_random_password(): Wrong number of arguments " + "given (#{args.size} for 1)") if args.size != 1 specials = ((33..33).to_a + (35..38).to_a + (40..47).to_a + (58..64).to_a + (91..93).to_a + (95..96).to_a + (123..125).to_a).pack('U*').chars.to_a numbers = (0..9).to_a alphal = ('a'..'z').to_a alphau = ('A'..'Z').to_a length = args[0] CHARS = (alphal + specials + numbers + alphau) pwd = CHARS.sort_by { rand }.join[0...length] return pwd end end The function is called in both case with $pwd = get_random_password(10). When I specified the length directly in the function to 10 for example. the password is well generated in master mode. Have you any idea why i can't specify the lentgth value ? Thanks for any help.

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  • FTP connection is aborted

    - by Conrad C
    I want to connect using FTP to my webpage hosted on ipages.com , but I always get this error on filezilla.: Status: Server does not support non-ASCII characters. Status: Connected Status: Retrieving directory listing... Command: PWD Response: 550 PWD: Permission denied Error: Failed to retrieve directory listing Error: Disconnected from server: ECONNABORTED - Connection aborted It looks like the connection is established but then disconnects. Is it an issue with the host? I use the default port 21. The user-pass is working. And the ftp adress is ftp.mysite.com I tested the port 21 using netstat and I get 220 Ipage FTP Server Ready

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  • Unix list absolute file name

    - by Matthew Adams
    Given an arbitrary single argument representing a file (or directory, device, etc), how do I get the absolute path of the argument? I've seen many answers to this question involving find/ls/stat/readlink and $PWD, but none that suits my need. It looks like the closest answer is ksh's "whence" command, but I need it to work in sh/bash. Assume a file, foo.txt, is located in my home directory, /Users/matthew/foo.txt. I need the following behavior, despite what my current working directory is (I'm calling the command "abs"): (PWD is ~) $ abs foo.txt /Users/matthew/foo.txt $ abs ~/foo.txt /Users/matthew/foo.txt $ abs ./foo.txt /Users/matthew/foo.txt $ abs /Users/matthew/foo.txt /Users/matthew/foo.txt What would "abs" really be? TIA, Matthew

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  • Ubuntu - Ruby Daemon script creates two processes - sh and ruby - PID file points at sh, not ruby

    - by Jonathan Scoles
    The PID file for a ruby process I have running as a daemon is getting the wrong PID. It appears that running /etc/init.d/sinatra start creates two processes - sh and ruby, and the PID that ends up in the PID file is that of the sh process. This means that when I then run /etc/init.d/sinatra stop or /etc/init.d/sinatra restart, it is killing sh and leaving the ruby process still running. I'd like to know a) why is my script launching two processes - sh and ruby, and not just ruby, and b) how do I fix it to just launch ruby? Details of the setup: I have a small Sinatra server set up on an ubuntu server, running as a daemon. It is set to automatically at server startup run a script named sinatra in /etc/init.d that launches the a control script control.rb, which then runs a ruby daemon command to start the server. The script is run under the 'sinatrauser' account, which has permissions for the directories the script needs. contents of /etc/init.d/sinatra #!/bin/bash # sinatra Startup script for Sinatra server. sudo -u sinatrauser ruby /var/www/sinatra/control.rb $1 RETVAL=$? exit $RETVAL To install this script, I simply copied it to /etc/init.d/ and ran sudo update-rc.d sinatra defaults contents of /var/www/sinatra/control.rb require 'rubygems' require 'daemons' pwd = Dir.pwd Daemons.run_proc('sinatraserver.rb', {:dir_mode => :normal, :dir => "/opt/pids/sinatra"}) do Dir.chdir(pwd) exec 'ruby /var/www/sinatra/sintraserver.rb >> /var/log/sinatra/sinatraOutput.log 2>&1' end portion of output from ps -A 6967 ? 00:00:00 apache2 10181 ? 00:00:00 sh <--- PID file gets this PID 10182 ? 00:00:02 ruby <--- Actual ruby process running Sinatra 12172 ? 00:00:00 sshd The PID file gets created in /opt/pids/sinatra/sinatraserver.rb.pid, and always contains the PID of the sh instance, which is always one less than the PID of the ruby process EDIT: I tried micke's solution, but it had no effect on the behavior I am seeing. This is the output from ps -A f. This output looks the same whether I use sudo -u sinatrauser ... or su sinatrauser -c ... in the service start script in /etc/init.d. 1146 ? S 0:00 sh -c ruby /var/www/sinatra/sinatraserver.rb >> /var/log/sinatra/sinatraOutput.log 2>&1 1147 ? S 0:00 \_ ruby /var/www/sinatra/sinatraserver.rb

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  • gnome-terminal. New tab opening

    - by thillai-selvan
    I am launching the gnome-terminal and I am working in a specific path For example: /home/user/programs/c/. Now I am opening another tab. When I am opening the new tab it is also in the same path. i.e. the new tab's pwd will be /home/user/programs/c/ But what I want is when I am opening a new tab its pwd should be /home/user. How can I achieve this? Any help much appreciated. Thanks in Advance!

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  • How to avoid tilde ~ in Bash prompt?

    - by Jirka
    Hello! I have set my prompt in bash in a such way that I can use it directly in scp command: My current PS1 string: PS1="\h:\w\n$" And the prompt looks like this: lnx-hladky:/tmp/plugtmp $ What I don't like at all is the fact that $HOME directory is displayed as tilde. Can this be avoided? It's causing problems when switching between different users. Example: lnx-hladky:~/DOC $ Documentation says: \w : the current working directory, with $HOME abbreviated with a tilde \W: the basename of the current working directory, with $HOME abbreviated with a tilde Is there any possibility to avoid $HOME being abbreviated with a tilde? I have found one way around but I feel like it's overcomplicated: PROMPT_COMMAND='echo -ne "\e[4;35m$(date +%T)\e[24m$(whoami)@$(hostname):$(pwd)\e[m\n"' PS1=$ Can anyone propose a better solution? I have a feeling it's not quite OK to run so many commands just to get prompt. (date,whoami,hostname,pwd). Thanks a lot! Jirka

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  • vmware linux headers not found for ubuntu 10.10 ?

    - by Tumbleweed
    I've installed Vmware 6.5 on Ubuntu 10.10... when I start vmware player/workstation its asking for linux kernel header for some compilation but I'm not able to find the appropriate package, see the Image below.... Update after running following commands sudo -s cd /lib/modules/$(uname -r)/build/include/linux ln -s ../generated/utsrelease.h ln -s ../generated/autoconf.h Error has been changed like below.... ERROR: modinfo: could not find module vmmon ERROR: modinfo: could not find module vmnet ERROR: modinfo: could not find module vmblock ERROR: modinfo: could not find module vmci ERROR: modinfo: could not find module vsock Using 2.6.x kernel build system. make: Entering directory /tmp/vmware-root/modules/vmmon-only' make -C /lib/modules/2.6.35-22-generic/build/include/.. SUBDIRS=$PWD SRCROOT=$PWD/. modules make[1]: Entering directory/usr/src/linux-headers-2.6.35-22-generic' CC [M] /tmp/vmware-root/modules/vmmon-only/linux/driver.o In file included from /tmp/vmware-root/modules/vmmon-only/linux/driver.c:31: /tmp/vmware-root/modules/vmmon-only/./include/compat_wait.h:78: error: conflicting types for ‘poll_initwait’ include/linux/poll.h:72: note: previous declaration of ‘poll_initwait’ was here

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  • 550 operation not permitted using FTP

    - by monkey_boys
    I'm using FTP to manage some files on a site I run but keep seeing this (truncated) error log: Command: DELE calendarpermission.php Response: 550 calendarpermission.php: Operation not permitted [...] Command: DELE button_down.gif Response: 550 button_down.gif: Operation not permitted Command: CWD /domains/example.com/public_html/admincp Response: 250 CWD command successful Command: PWD Response: 257 "/domains/example.com/public_html/admincp" is the current directory Command: RMD control_examples Response: 550 control_examples: Operation not permitted Command: CWD /domains/example.com/public_html Response: 250 CWD command successful Command: PWD Response: 257 "/domains/example.com/public_html" is the current directory Command: RMD admincp Response: 550 admincp: Operation not permitted Status: Retrieving directory listing... Command: PASV Response: 227 Entering Passive Mode (122,155,5,50,138,244). Command: MLSD Response: 150 Opening ASCII mode data connection for MLSD Response: 226 Transfer complete Status: Directory listing successful Status: Set permissions of '/domains/example.com/public_html/admincp' to '777' Command: SITE CHMOD 777 admincp Response: 550 CHMOD 777 admincp: Operation not permitted What do I do to solve this?

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  • Windows CMD, show the current folder name at prompt dynamically like Bash

    - by guneysus
    I am trying to modify my CMD, to show only current dir name dynamically like: Desktop $ When i switched the folder, it must be updated. It is not required to be code in purely batch file, it may depend any external commands, cygwin bash, etc. @echo off set a=bash -c "pwd | sed 's,^\(.*/\)\?\([^/]*\),\2,'" %a% cmd outputs _test-et Microsoft Windows [Version 6.3.9600] (c) 2013 Microsoft Corporation. Tüm haklari saklidir. >> But >> prompt %a% gives bash -c "pwd | sed 's,^\(.*/\)\?\([^/]*\),\2,'"

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  • On windows commandline, how do I get a dynamic prompt that tells me where in the filesystem I am?

    - by guneysus
    I am trying to modify my CMD, to show only current dir name dynamically like: Desktop $ When i switched the folder, it must be updated. It is not required to be code in purely batch file, it may depend any external commands, cygwin bash, etc. @echo off set a=bash -c "pwd | sed 's,^\(.*/\)\?\([^/]*\),\2,'" %a% cmd outputs _test-et Microsoft Windows [Version 6.3.9600] (c) 2013 Microsoft Corporation. Tüm haklari saklidir. >> But >> prompt %a% gives bash -c "pwd | sed 's,^\(.*/\)\?\([^/]*\),\2,'"

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