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Search found 13051 results on 523 pages for 'remove from staging'.

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  • jquery: remove table row while iterating through table rows

    - by deostroll
    #exceptions is a html table. I try to run the code below, but it doesn't remove the table row. $('#exceptions').find('tr').each(function(){ var flag=false; var val = 'excalibur'; $(this).find('td').each(function(){ if($(this).text().toLowerCase() == val) flag = true; }); if(flag) $(this).parent().remove($(this)); }); What is the correct way to do it?

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  • jquery: How to completely remove a dialog on close

    - by Svish
    When an ajax operation fails, I create a new div with the errors and then show it as a dialog. When the dialog is closed I would like to completely destroy and remove the div again. How can I do this? My code looks something like this at the moment: $('<div>We failed</div>') .dialog( { title: 'Error', close: function(event, ui) { $(this).destroy().remove(); } }); When I run this the dialog box shows up correctly, but when I close it the dialog is still visible in the html (using FireBug). What am I missing here? Something I have forgotten? Update: Just noticed my code gives me an error in the firebug console. $(this).destroy is not a function Anyone able to help me out? Update: If I do just $(this).remove() instead, the item is removed from the html. But is it completely removed from the DOM? Or do I somehow need to call that destroy function first as well?

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  • Javascript - remove part of cookie with a split('|') like array

    - by MgS
    I'm abit stuck. I'm using jQuery. I have a cookie which has the value such as : 1,something|2,somethingg|1,something We are treating it as [0] as id and [1] as name. I need to remove ONE where the id == '1' for example, this will leave the cookie like this: 1,something|2,somethingg How do I go about this, it will probally be in a loop, but not sure how to remove one of them. I have this so far: function removeItem(id){ var cookieName = 'myCookie'; var cookie = $.cookie(cookieName); if(cookie){ var cookie = cookie.split('|'); $(cookie).each(function(index){ var thisCookieData = this.split(','); if(thisCookieData[0] == id ){ } }); }

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  • JQuery: Remove duplicate elements?

    - by Keith Donegan
    Say I have a list of links with duplicate values as below: <a href="#">Book</a> <a href="#">Magazine</a> <a href="#">Book</a> <a href="#">Book</a> <a href="#">DVD</a> <a href="#">DVD</a> <a href="#">DVD</a> <a href="#">Book</a> How would I, using JQuery, remove the dups and be left with the following for example: <a href="#">Book</a> <a href="#">Magazine</a> <a href="#">DVD</a> Basically I am looking for a way to remove any duplicate values found and show 1 of each link.

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  • jQuery.remove() - Is there a way to get the object back after you remove it?

    - by Jack Marchetti
    I basically have the same problem in this questions: Flash Video still playing in hidden div I've used the .remove jquery call and this works. However, I have previous/next buttons when a user scrolls through hidden/non-hidden divs. What I need to know is, once I remove the flash object, is there a way to get it back other than refreshing the page? Basically, can this be handled client side or am I going to need to implement some server side handling. detach() won't work because the flash video continues to play. I can't just hide it because the video continues to play as well.

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  • data replication from a production web server back to the staging web server

    - by Dennis Smith
    Have two web servers, development/staging and production. Code and some documentation is moved from the staging area to production either through on-demand jobs or nightly via a global replication job. The production server of course sits isolated in a DMZ. There is some content that gets uploaded to the live server that needs to be replicated back to staging. Our security team is locking the network down (and they should) and restricting access to the live server. Best suggestions for replication of "live" data back to "stage" and backing up the live server also.

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  • Can you have a staging and production slot in Azure Websites

    - by Barry King
    I'm looking at hosting 3 Websites (there will all use the same linked database resource but I think I have to use 3 websites within Azure for this); www.website.com, provider.website.com and admin.website.com. Using Windows Azure Websites, can you have a Staging, Production slot? I think this feature is only available to Azure Cloud Services but there is little documentation on this. If its not possible, other than spinning up 3 more sites to act as the staging sites is there another way? I want the ability to "swap" from staging to production.

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  • jquery remove selected element and append to another

    - by KnockKnockWhosThere
    I'm trying to re-append a "removed option" to the appropriate select option menu. I have three select boxes: "Categories", "Variables", and "Target". "Categories" is a chained select, so when the user selects an option from it, the "Variables" select box is populated with options specific to the selected categories option. When the user chooses an option from the "Variables" select box, it's appended to the "Target" select box. I have a "remove selected" feature so that if a user "removes" a selected element from the "Target" select box, it's removed from "Target" and put back into the pool of "Variables" options. The problem I'm having is that it appends the option to the "Variables" items indiscriminately. That is, if the selected category is "Age" the "Variables" options all have a class of "age". But, if the removed option is an "income" item, it will display in the "Age Variables" option list. Here's the HTML markup: <select multiple="" id="categories" name="categories[]"> <option class="category" value="income">income</option> <option class="category" value="gender">gender</option> <option class="category" value="age">age</option> </select> <select multiple="multiple" id="variables" name="variables[]"> <option class="income" value="10">$90,000 - $99,999</option> <option class="income" value="11">$100,000 - $124,999</option> <option class="income" value="12">$125,000 - $149,999</option> <option class="income" value="13">Greater than $149,999</option> <option class="gender" value="14">Male</option> <option class="gender" value="15">Female</option> <option class="gender" value="16">Ungendered</option> <option class="age" value="17">Ages 18-24</option> <option class="age" value="18">Ages 25-34</option> <option class="age" value="19">Ages 35-44</option> </select> <select height="60" multiple="multiple" id="target" name="target[]"> </select> And, here's the js: /* This determines what options are display in the "Variables" select box */ var cat = $('#categories'); var el = $('#variables'); $('#categories option').click(function() { var class = $(this).val(); $('#variables option').each(function() { if($(this).hasClass(class)) { $(this).show(); } else { $(this).hide(); } }); }); /* This adds the option to the target select box if the user clicks "add" */ $('#add').click(function() { return !$('#variables option:selected').appendTo('#target'); }); /* This is the remove function in its current form, but doesn't append correctly */ $('#remove').click(function() { $('#target option:selected').each(function() { var class = $(this).attr('class'); if($('#variables option').hasClass(class)) { $(this).appendTo('#variables'); sortList('variables'); } }); });

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  • Git: Remove specific commit

    - by Joshua Cheek
    I was working with a friend on a project, and he edited a bunch of files that shouldn't have been edited. Somehow I merged his work into mine, either when I pulled it, or when I tried to just pick the specific files out that I wanted. I've been looking and playing for a long time, trying to figure out how to remove the commits that contain the edits to those files, it seems to be a toss up between revert and rebase, and there are no straightforward examples, and the docs assume I know more than I do. So here is a simplified version of the question: Given the following scenario, how do I remove commit 2? $ mkdir git_revert_test && cd git_revert_test $ git init Initialized empty Git repository in /Users/josh/deleteme/git_revert_test/.git/ $ echo "line 1" > myfile $ git add -A $ git commit -m "commit 1" [master (root-commit) 8230fa3] commit 1 1 files changed, 1 insertions(+), 0 deletions(-) create mode 100644 myfile $ echo "line 2" >> myfile $ git commit -am "commit 2" [master 342f9bb] commit 2 1 files changed, 1 insertions(+), 0 deletions(-) $ echo "line 3" >> myfile $ git commit -am "commit 3" [master 1bcb872] commit 3 1 files changed, 1 insertions(+), 0 deletions(-) The expected result is $ cat myfile line 1 line 3 Here is an example of how I have been trying to revert $ git revert 342f9bb Automatic revert failed. After resolving the conflicts, mark the corrected paths with 'git add <paths>' or 'git rm <paths>' and commit the result.

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  • jquery disable/remove option on select?

    - by SoulieBaby
    Hi all, I have two select lists, I would like jquery to either remove or disable a select option, depending on what is selected from the first select list: <select name="booking" id="booking"> <option value="3">Group Bookings</option> <option value="2" selected="selected">Port Phillip Bay Snapper Charters</option> <option value="6">Portland Tuna Fishing</option> <option value="1">Sport Fishing</option> </select> Here's the second list (which will only ever have two values): <select name="charterType" id="charterType"> <option value="1">Individual Booking</option> <option value="2">Group Booking</option> </select> If Group Bookings or Port Phillip Bay Snapper Charters are selected, I need only "Group Booking" to be displayed. (To basically hide "Individual Booking") but I can't seem to get it to work.. If someone could help me that'd be great!! :) I've also tried using a switch, but that doesnt work either.. /* select list */ switch (jQuery('#booking :selected').text()) { case 'Sport Fishing': alert('AA'); break; case 'Port Phillip Bay Snapper Charters': jQuery("#charterType option[value=1]").remove(); alert('BB'); break; case 'Portland Tuna Fishing': alert('CC'); break; case 'Group Bookings': alert('DD'); break; }; It alerts, but doesn't do anything else..

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  • UIViewController remove subview

    - by ghiboz
    Hi all! I add a view as subview of my uiviewcontroller like this: // into my ViewController: UIImageView *imView =[[UIImageView alloc] initWithImage:[UIImage imageNamed:@"img.jpg"]]; imView.frame = CGRectMake(2, 46, 1020, 720); [self.view addSubview:imView]; now, with another button I wish remove the imView from the subview chain.. how can I do to do this?? thanks

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  • How to remove commas etc form a matrix in python

    - by robert
    say ive got a matrix that looks like: [[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]] how can i make it on seperate lines: [[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]] and then remove commas etc: 0 0 0 0 0 And also to make it blank instead of 0's, so that numbers can be put in later, so in the end it will be like: _ 1 2 _ 1 _ 1 (spaces not underscores) thanks

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  • PHP: Remove Simple Session with Get-Method

    - by elmaso
    Hello, I want to Remove the Sessions from this php code, actually if someone searches i get this url search.php?searchquery=test but if I reload the page, the results are cleaned. how can I remove the Sessions to get the Results still, if someone reloads the page? this are the codes: search.php <?php session_start(); ?> <form method="get" action="querygoogle.php"> <label for="searchquery"><span class="caption">Search this site</span> <input type="text" size="20" maxlength="255" title="Enter your keywords and click the search button" name="searchquery" /></label> <input type="submit" value="Search" /> </form> <?php if(!empty($_SESSION['googleresults'])) { echo $_SESSION['googleresults']; unset($_SESSION['googleresults']); } ?> querygoogle.php <?php session_start(); $url = 'http://www.example.com'; $handle = fopen($url, 'rb'); $body = ''; while (!feof($handle)) { $body .= fread($handle, 8192); } fclose($handle); $json = json_decode($body); foreach($json->responseData->results as $searchresult) { if($searchresult->GsearchResultClass == 'GwebSearch') { $formattedresults .= ' <div class="searchresult"> <h3><a href="' . $searchresult->unescapedUrl . '">' . $searchresult->titleNoFormatting . '</a></h3> <p class="resultdesc">' . $searchresult->content . '</p> <p class="resulturl">' . $searchresult->visibleUrl . '</p> </div>'; } } $_SESSION['googleresults'] = $formattedresults; header("Location: search.php?searchquery=" . $_GET['searchquery']); exit; ?> thank you for your help!!

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  • Cannot remove git repository completely

    - by Aleyna
    I have been using git on windows-msysgit. Whenever I try to remove a repository completely either using explorer or using $ git rm -rf ptp/ fatal: Not a git repository (or any of the parent directories): .git it errors out "The data present in the reparse point buffer is invalid" or the fatal error above. What's wrong with me/git? Thanks in advance

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  • Amazon WebStore hide/disable/remove

    - by Paul
    Hey guys, I'm new to template editting. I'm trying to remove a table from the Amazon's WebStore template so i can start designing my own. Anyone out there know how I can go about hiding/disabling/removing/bypassing it?

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  • How to remove commas etc from a matrix in python

    - by robert
    say ive got a matrix that looks like: [[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]] how can i make it on seperate lines: [[0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0]] and then remove commas etc: 0 0 0 0 0 And also to make it blank instead of 0's, so that numbers can be put in later, so in the end it will be like: _ 1 2 _ 1 _ 1 (spaces not underscores) thanks

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  • Hot to remove text from variable? (php)

    - by Glister
    I have a variable $link_item, it's used with echo and gives the strings like <span class="name">Google</span>http://google.com How to remove "<span class="name">Google</span>" from string? It should give just "http://google.com". Heard it can be done with regex(), please help.

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  • How to remove the selected element during a clone() operation

    - by Slinky
    Hi All, I have a select box that gets cloned. I want to remove the user's previous selection from each cloned select box. Here is the method that does the clone() : function addselect(s){ $('#product_categories > .category_block:last').after( $('#product_categories > .category_block:last').clone() ); set_add_delete_links(); return false; } What's the best way to do this?

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  • Remove all styles from dynamic label in asp.net

    - by kad1r
    I have a label and I got some text from database. text format like: Windows Server 2008 ...etc But sometimes there are different fonts or something like style. How can I remove all of them quickly? I know I can make it with replace command. But is there any quick way for it?

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