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  • Syntax error near unexpected token 'fi'

    - by Bill Sherwin
    I have created a very simple script (see below) but cannot get it to run properly. I always get messages saying line 5: syntax error near unexpected token 'fi' line 5: 'fi' when I try to execute this script. #!/bin/sh rm /opt/file_name if $? -ne 0 then echo 'error' fi exit I am running this on Red Hat Linux if that makes any difference. If any one can help identify what is wrong with the if statement I'd really appreciate it. Bill

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  • Linux Software RAID1: How to boot after (physically) removing /dev/sda? (LVM, mdadm, Grub2)

    - by flight
    A server set up with Debian 6.0/squeeze. During the squeeze installation, I configured the two 500GB SATA disks (/dev/sda and /dev/sdb) as a RAID1 (managed with mdadm). The RAID keeps a 500 GB LVM volume group (vg0). In the volume group, there's a single logical volume (lv0). vg0-lv0 is formatted with extfs3 and mounted as root partition (no dedicated /boot partition). The system boots using GRUB2. In normal use, the systems boots fine. Also, when I tried and removed the second SATA drive (/dev/sdb) after a shutdown, the system came up without problem, and after reconnecting the drive, I was able to --re-add /dev/sdb1 to the RAID array. But: After removing the first SATA drive (/dev/sda), the system won't boot any more! A GRUB welcome message shows up for a second, then the system reboots. I tried to install GRUB2 manually on /dev/sdb ("grub-install /dev/sdb"), but that doesn't help. Appearently squeeze fails to set up GRUB2 to launch from the second disk when the first disk is removed, which seems to be quite an essential feature when running this kind of Software RAID1, isn't it? At the moment, I'm lost whether this is a problem with GRUB2, with LVM or with the RAID setup. Any hints?

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  • Strange issue with 64 bit OS

    - by Sherwin Flight
    So I own two versions of Windows 7, one is 32 bit, the other is 64. The 64 bit version came with my new desktop, and the 32 bit version came with my Laptop. I was doing a clean install of my laptop, and the install went smooth, Windows is up and running! However, after installing it I realized that I accidentally used the 64 bit installation disk instead of the 32 bit version. I confirmed this in the System Information screen, it says: System type: 64-bit Operating System As far as I knew this laptop was only a 32 bit machine. My understanding is that a 64 bit OS would NOT run on 32 bit architecture. Am I correct with this assumption? If this was a 32 bit laptop is there any way a 64 bit OS would even run at all on it?

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  • Accessing server by dedicated IP address

    - by Sherwin Flight
    I'm having an issue with my hosting provider after migrating to a new account. It's taking some time to get the problem sorted out, so I am hoping someone here can shed some light on the situation. The server is running WHM/cPanel, and the site I am trying to access has a dedicated IP address. When I connect to the server like this http://IP.HERE instead of showing my the website the way I would expect, it is showing the contents of a subfolder. So, while I would expect it to load public_html/ it is loading public_html/somefolder/ instead. Any idea why this is happening instead of showing the sites homepage the way I would expect? EDIT It is not redirecting, so the url is just http://IP.ADDRESS/, but the files listed are from a subfolder. So, it LOOKS at though I went to http://IP.ADDRESS/subfolder, when the URL says it should be showing the main folder contents. When I access the site using the domain name, it works properly, so I assume the document root is set correctly.

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  • Apache's htcacheclean doesn't scale: How to tame a huge Apache disk_cache?

    - by flight
    We have an Apache setup with a huge disk_cache (500.000 entries, 50 GB disk space used). The cache grows by 16 GB every day. My problem is that the cache seems to be growing nearly as fast as it's possible to remove files and directories from the cache filesystem! The cache partition is an ext3 filesystem (100GB, "-t news") on an iSCSI storage. The Apache server (which acts as a caching proxy) is a VM. The disk_cache is configured with CacheDirLevels=2 and CacheDirLength=1, and includes variants. A typical file path is "/htcache/B/x/i_iGfmmHhxJRheg8NHcQ.header.vary/A/W/oGX3MAV3q0bWl30YmA_A.header". When I try to call htcacheclean to tame the cache (non-daemon mode, "htcacheclean-t -p/htcache -l15G"), IOwait is going through the roof for several hours. Without any visible action. Only after hours, htcacheclean starts to delete files from the cache partition, which takes a couple more hours. (A similar problem was brought up in the Apache mailing list in 2009, without a solution: http://www.mail-archive.com/[email protected]/msg42683.html) The high IOwait leads to problems with the stability of the web server (the bridge to the Tomcat backend server sometimes stalls). I came up with my own prune script, which removes files and directories from random subdirectories of the cache. Only to find that the deletion rate of the script is just slightly higher than the cache growth rate. The script takes ~10 seconds to read the a subdirectory (e.g. /htcache/B/x) and frees some 5 MB of disk space. In this 10 seconds, the cache has grown by another 2 MB. As with htcacheclean, IOwait goes up to 25% when running the prune script continuously. Any idea? Is this a problem specific to the (rather slow) iSCSI storage? Should I choose a different file system for a huge disk_cache? ext2? ext4? Are there any kernel parameter optimizations for this kind of scenario? (I already tried the deadline scheduler and a smaller read_ahead_kb, without effect).

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  • The Future of Air Travel: Intelligence and Automation

    - by BobEvans
    Remember those white-knuckle flights through stormy weather where unexpected plunges in altitude result in near-permanent relocations of major internal organs? Perhaps there’s a better way, according to a recent Wall Street Journal article: “Pilots of a Honeywell International Inc. test plane stayed on their initial flight path, relying on the company's latest onboard radar technology to steer through the worst of the weather. The specially outfitted Boeing 757 barely shuddered as it gingerly skirted some of the most ferocious storm cells over Fort Walton Beach and then climbed above the rest in zero visibility.” Or how about the multifaceted check-in process, which might not wreak havoc on liver location but nevertheless makes you wonder if you’ve been trapped in some sort of covert psychological-stress test? Another WSJ article, called “The Self-Service Airport,” says there’s reason for hope there as well: “Airlines are laying the groundwork for the next big step in the airport experience: a trip from the curb to the plane without interacting with a single airline employee. At the airport of the near future, ‘your first interaction could be with a flight attendant,’ said Ben Minicucci, chief operating officer of Alaska Airlines, a unit of Alaska Air Group Inc.” And in the topsy-turvy world of air travel, it’s not just the passengers who’ve been experiencing bumpy rides: the airlines themselves are grappling with a range of challenges—some beyond their control, some not—that make profitability increasingly elusive in spite of heavy demand for their services. A recent piece in The Economist illustrates one of the mega-challenges confronting the airline industry via a striking set of contrasting and very large numbers: while the airlines pay $7 billion per year to third-party computerized reservation services, the airlines themselves earn a collective profit of only $3 billion per year. In that context, the anecdotes above point unmistakably to the future that airlines must pursue if they hope to be able to manage some of the factors outside of their control (e.g., weather) as well as all of those within their control (operating expenses, end-to-end visibility, safety, load optimization, etc.): more intelligence, more automation, more interconnectedness, and more real-time awareness of every facet of their operations. Those moves will benefit both passengers and the air carriers, says the WSJ piece on The Self-Service Airport: “Airlines say the advanced technology will quicken the airport experience for seasoned travelers—shaving a minute or two from the checked-baggage process alone—while freeing airline employees to focus on fliers with questions. ‘It's more about throughput with the resources you have than getting rid of humans,’ said Andrew O'Connor, director of airport solutions at Geneva-based airline IT provider SITA.” Oracle’s attempting to help airlines gain control over these challenges by blending together a range of its technologies into a solution called the Oracle Airline Data Model, which suggests the following steps: • To retain and grow their customer base, airlines need to focus on the customer experience. • To personalize and differentiate the customer experience, airlines need to effectively manage their passenger data. • The Oracle Airline Data Model can help airlines jump-start their customer-experience initiatives by consolidating passenger data into a customer data hub that drives realtime business intelligence and strategic customer insight. • Oracle’s Airline Data Model brings together multiple types of data that can jumpstart your data-warehousing project with rich out-of-the-box functionality. • Oracle’s Intelligent Warehouse for Airlines brings together the powerful capabilities of Oracle Exadata and the Oracle Airline Data Model to give you real-time strategic insights into passenger demand, revenues, sales channels and your flight network. The airline industry aside, the bullet points above offer a broad strategic outline for just about any industry because the customer experience is becoming pre-eminent in each and there is simply no way to deliver world-class customer experiences unless a company can capture, manage, and analyze all of the relevant data in real-time. I’ll leave you with two thoughts from the WSJ article about the new in-flight radar system from Honeywell: first, studies show that a single episode of serious turbulence can wrack up $150,000 in additional costs for an airline—so, it certainly behooves the carriers to gain the intelligence to avoid turbulence as much as possible. And second, it’s back to that top-priority customer-experience thing and the value that ever-increasing levels of intelligence can deliver. As the article says: “In the cabin, reporters watched screens showing the most intense parts of the nearly 10-mile wide storm, which churned some 7,000 feet below, in vibrant red and other colors. The screens also were filled with tiny symbols depicting likely locations of lightning and hail, which can damage planes and wreak havoc on the nerves of white-knuckle flyers.”  (Bob Evans is senior vice-president, communications, for Oracle.)  

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  • Link List Problem,

    - by david
    OK i have a problem with a Link List program i'm trying to Do, the link List is working fine. Here is my code #include <iostream> using namespace std; struct record { string word; struct record * link; }; typedef struct record node; node * insert_Node( node * head, node * previous, string key ); node * search( node *head, string key, int *found); void displayList(node *head); node * delete_node( node *head, node * previous, string key); int main() { node * previous, * head = NULL; int found = 0; string node1Data,newNodeData, nextData,lastData; //set up first node cout <<"Depature"<<endl; cin >>node1Data; previous = search( head, node1Data, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, node1Data); cout <<"Depature inserted"<<endl; //insert node between first node and head cout <<"Destination"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Destinationinserted"<<endl; //insert node between second node and head cout <<"Cost"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Cost inserted"<<endl; cout <<"Number of Seats Required"<<endl; //place node between new node and first node cin >>nextData; previous = search( head, nextData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, nextData); cout <<"Number of Seats Required inserted"<<endl; //insert node between first node and head cout <<"Name"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Name inserted"<<endl; //insert node between node and head cout <<"Address "<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Address inserted"<<endl; //place node as very last node cin >>lastData; previous = search( head, lastData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, lastData); cout <<"C"<<endl; displayList(head); char Ans = 'y'; //Delete nodes do { cout <<"Enter Keyword to be delete"<<endl; cin >>nextData; previous = search( head, nextData, &found); if (found == 1) head = delete_node( head, previous,nextData); displayList(head); cout <<"Do you want to Delete more y /n "<<endl; cin >> Ans; } while( Ans =='y'); int choice, i=0, counter=0; int fclass[10]; int coach[10]; printf("Welcome to the booking program"); printf("\n-----------------"); do{ printf("\n Please pick one of the following option:"); printf("\n 1) Reserve a first class seat on Flight 101."); printf("\n 2) Reserve a coach seat on Flight 101."); printf("\n 3) Quit "); printf("\n ---------------------------------------------------------------------"); printf("\nYour choice?"); scanf("%d",&choice); switch(choice) { case 1: i++; if (i <10){ printf("Here is your seat: %d " , fclass[i]); } else if (i = 10) { printf("Sorry there is no more seats on First Class. Please wait for the next flight"); } break; case 2: if (i <10){ printf("Here is your Seat Coach: %d " , coach[i]); } else if ( i = 10) { printf("Sorry their is no more Seats on Coach. Please wait for the next flight"); } break; case 3: printf("Thank you and goodbye\n"); //exit(0); } } while (choice != 3); } /******************************************************* search function to return previous position of node ******************************************************/ node * search( node *head, string key, int *found) { node * previous, * current; current = head; previous = current; *found = 0;//not found //if (current->word < key) move through links until the next link //matches or current_word > key while( current !=NULL) { //compare exactly if (key ==current->word ) { *found = 1; break; } //if key is less than word else if ( key < current->word ) break; else { //previous stays one link behind current previous = current; current = previous -> link; } } return previous; } /******************************************************** display function as used with createList ******************************************************/ void displayList(node *head) { node * current; //current now contains the address held of the 1st node similar //to head current = head; cout << "\n\n"; if( current ==NULL) cout << "Empty List\n\n"; else { /*Keep going displaying the contents of the list and set current to the address of the next node. When set to null, there are no more nodes */ while(current !=NULL) { cout << current->word<<endl; current = current ->link; } } } /************************************************************ insert node used to position node (i) empty list head = NULL (ii) to position node before the first node key < head->word (iii) every other position including the end of the list This is done using the following steps (a) Pass in all the details to create the node either details or a whole record (b) Pass the details over to fill the node (C) Use the if statement to add the node to the list **********************************************************/ node * insert_Node( node * head, node * previous, string key ) { node * new_node, * temp; new_node = new node; //create the node new_node ->word = key; new_node -> link = NULL; if (head == NULL || key < head->word ) //empty list { //give address of head to temp temp = head; //head now points to the new_node head = new_node; //new_node now points to what head was pointing at new_node -> link = temp; } else { //pass address held in link to temp temp = previous-> link; //put address of new node to link of previous previous -> link = new_node; //pass address of temp to link of new node new_node -> link = temp; } return head; } node * delete_node( node *head, node * previous, string key) { /* this function will delete a node but will not return its contents */ node * temp; if(key == head->word) //delete node at head of list { temp = head; //point head at the next node head = head -> link; } else { //holds the address of the node after the one // to be deleted temp = previous-> link; /*assign the previous to the address of the present node to be deleted which holds the address of the next node */ previous-> link = previous-> link-> link; } delete temp; return head; }//end delete The problem i have is when i Enter in the Number 2 in the Node(Seats) i like to get a Counter Taken 2 off of 50, some thing like what i have here enter code here int choice, i=0, counter=0; int fclass[10]; int coach[10]; printf("Welcome to the booking program"); printf("\n-----------------"); do{ printf("\n Please pick one of the following option:"); printf("\n 1) Reserve a first class seat on Flight 101."); printf("\n 2) Reserve a coach seat on Flight 101."); printf("\n 3) Quit "); printf("\n ---------------------------------------------------------------------"); printf("\nYour choice?"); scanf("%d",&choice); switch(choice) { case 1: i++; if (i <10){ printf("Here is your seat: %d " , fclass[i]); } else if (i = 10) { printf("Sorry there is no more seats on First Class. Please wait for the next flight"); } break; case 2: if (i <10){ printf("Here is your Seat Coach: %d " , coach[i]); } else if ( i = 10) { printf("Sorry their is no more Seats on Coach. Please wait for the next flight"); } break; case 3: printf("Thank you and goodbye\n"); //exit(0); } } while (choice != 3); How can i get what the User enters into number of Seats into this function

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  • SQL server 2008 trigger not working correct with multiple inserts

    - by Rob
    I've got the following trigger; CREATE TRIGGER trFLightAndDestination ON checkin_flight AFTER INSERT,UPDATE AS BEGIN IF NOT EXISTS ( SELECT 1 FROM Flight v INNER JOIN Inserted AS i ON i.flightnumber = v.flightnumber INNER JOIN checkin_destination AS ib ON ib.airport = v.airport INNER JOIN checkin_company AS im ON im.company = v.company WHERE i.desk = ib.desk AND i.desk = im.desk ) BEGIN RAISERROR('This combination of of flight and check-in desk is not possible',16,1) ROLLBACK TRAN END END What i want the trigger to do is to check the tables Flight, checkin_destination and checkin_company when a new record for checkin_flight is added. Every record of checkin_flight contains a flightnumber and desknumber where passengers need to check in for this destination. The tables checkin_destination and checkin_company contain information about companies and destinations restricted to certain checkin desks. When adding a record to checkin_flight i need information from the flight table to get the destination and flightcompany with the inserted flightnumber. This information needs to be checked against the available checkin combinations for flights, destinations and companies. I'm using the trigger as stated above, but when i try to insert a wrong combination the trigger allows it. What am i missing here?

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  • Classical task-scheduling assignment

    - by Bruno
    I am working on a flight scheduling app (disclaimer: it's for a college project, so no code answers, please). Please read this question w/ a quantum of attention before answering as it has a lot of peculiarities :( First, some terminology issues: You have planes and flights, and you have to pair them up. For simplicity's sake, we'll assume that a plane is free as soon as the flight using it prior lands. Flights are seen as tasks: They have a duration They have dependencies They have an expected date/time for beginning Planes can be seen as resources to be used by tasks (or flights, in our terminology). Flights have a specific type of plane needed. e.g. flight 200 needs a plane of type B. Planes obviously are of one and only one specific type, e.g., Plane Airforce One is of type C. A "project" is the set of all the flights by an airline in a given time period. The functionality required is: Finding the shortest possible duration for a said project The earliest and latest possible start for a task (flight) The critical tasks, with basis on provided data, complete with identifiers of preceding tasks. Automatically pair up flights and planes, so as to get all flights paired up with a plane. (Note: the duration of flights is fixed) Get a Gantt diagram with the projects scheduling, in which all flights begin as early as possible, showing all previously referred data graphically (dependencies, time info, etc.) So the questions is: How in the world do I achieve this? Particularly: We are required to use a graph. What do the graph's edges and nodes respectively symbolise? Are we required to discard tasks to achieve the critical tasks set? If you could also recommend some algorithms for us to look up, that'd be great.

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  • SQL - Query to display average as either "longer than" or "shorter than"

    - by user1840801
    Here are the tables I've created: CREATE TABLE Plane_new (Pnum char(3), Feature varchar2(20), Ptype varchar2(15), primary key (Pnum)); CREATE TABLE Employee_new (eid char(3), ename varchar(10), salary number(7,2), mid char(3), PRIMARY KEY (eid), FOREIGN KEY (mid) REFERENCES Employee_new); CREATE TABLE Pilot_new (eid char(3), Licence char(9), primary key (eid), foreign key (eid) references Employee_new on delete cascade); CREATE TABLE FlightI_new (Fnum char(4), Fdate date, Duration number(2), Pid char(3), Pnum char(3), primary key (Fnum), foreign key (Pid) references Pilot_new (eid), foreign key (Pnum) references Plane_new); And here is the query I must complete: For each flight, display its number, the name of the pilot who implemented the flight and the words ‘Longer than average’ if the flight duration was longer than average or the words ‘Shorter than average’ if the flight duration was shorter than or equal to the average. For the column holding the words ‘Longer than average’ or ‘Shorter than average’ make a header Length. Here is what I've come up with - with no luck! SELECT F.Fnum, E.ename, CASE Length WHEN F.Duration>(SELECT AVG(F.Duration) FROM FlightI_new F) THEN "Longer than average" WHEN F.Duration<=(SELECT AVG(F.Duration) FROM FlightI_new F) THEN 'Shorter than average' END FROM FlightI_new F LEFT OUTER JOIN Employee_new E ON F.Pid=E.eid GROUP BY F.Fnum, E.ename; Where am I going wrong?

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  • Why It Is So Important to Know Your Customer

    - by Christie Flanagan
    Over the years, I endured enough delayed flights, air turbulence and misadventures in airport security clearance to watch my expectations for the air travel experience fall to abysmally low levels. The extent of my loyalty to any one carrier had more to do with the proximity of the airport parking garage to their particular gate than to any effort on the airline’s part to actually earn and retain my business. That all changed one day when I found myself at the airport hoping to catch a return flight home a few hours earlier than expected, using an airline I had flown with for the first time just that week.  When you travel regularly for business, being able to catch a return flight home that’s even an hour or two earlier than originally scheduled is a big deal. It can mean the difference between having a normal evening with your family and having to sneak in like a cat burglar after everyone is fast asleep. And so I found myself on this particular day hoping to catch an earlier flight home. I approached the gate agent and was told that I could go on standby for their next flight out. Then I asked how much it was going to cost to change the flight, knowing full well that I wouldn’t get reimbursed by my company for any change fees. “Oh, there’s no charge to fly on standby,” the gate agent told me. I made a funny look. I couldn’t believe what I was hearing. This airline was going to let my fly on standby, at no additional charge, even though I was a new customer with no status or points. It had been years since I’d seen an airline pass up a short term revenue generating opportunity in favor of a long term loyalty generating one.  At that moment, this particular airline gained my loyal business. Since then, this airline has had the opportunity to learn a lot about me. They know where I live, where I fly from, where I usually fly to, and where I like to sit on the plane. In general, I’ve found their customer service to be quite good whether at the airport, via call center and even through social channels. They email me occasionally, and when they do, they demonstrate that they know me by promoting deals for flights from where I live to places that I’d be interested in visiting. And that’s part of why I’m always so puzzled when I visit their website.Does this company with the great service, customer friendly policies, and clean planes demonstrate that they know me at all when I visit their website? The answer is no. Even when I log in using my loyalty program credentials, it’s pretty obvious that they’re presenting the same old home page and same old offers to every single one of their site visitors. I mean, those promotional offers that they’re featuring so prominently  -- they’re for flights that originate thousands of miles from where I live! There’s no way I’d ever book one of those flights and I’m sure I’m not the only one of their customers to feel that way.My reason for recounting this story is not to pick on the one customer experience flaw I've noticed with this particular airline, in fact, they do so many things right that I’ll continue to fly with them. But I did want to illustrate just how glaringly obvious it is to customers today when a touch point they have with a brand is impersonal, unconnected and out of sync. As someone who’s spent a number of years in the web experience management and online marketing space, it particularly peeves me when that out of sync touch point is a brand’s website, perhaps because I know how important it is to make a customer’s online experience relevant and how many powerful tools are available for making a relevant experience a reality. The fact is, delivering a one-size-fits-all online customer experience is no longer acceptable or particularly effective in today’s world. Today’s savvy customers expect you to know who they are and to understand their preferences, behavior and relationship with your brand. Not only do they expect you to know about them, but they also expect you to demonstrate this knowledge across all of their touch points with your brand in a consistent and compelling fashion, whether it be on your traditional website, your mobile web presence or through various social channels.Delivering the kind of personalized online experiences that customers want can have tremendous business benefits. This is not just about generating feelings of goodwill and higher customer satisfaction ratings either. More relevant and personalized online experiences boost the effectiveness of online marketing initiatives and the statistics prove this out. Personalized web experiences can help increase online conversion rates by 70% -- that’s a huge number.1  And more than three quarters of consumers indicate that they’ve made additional online purchases based on personalized product recommendations.2Now if only this airline would get on board with delivering a more personalized online customer experience. I’d certainly be happier and more likely to spring for one of their promotional offers. And by targeting relevant offers on their home page to appropriate segments of their site visitors, I bet they’d be happier and generating additional revenue too. Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}  ***** If you're interested in hearing more perspectives on the benefits of demonstrating that you know your customers by delivering a more personalized experience, check out this white paper on creating a successful and meaningful customer experience on the web.  Also catch the video below on the business value of CX in attracting new customers featuring Oracle's VP of Customer Experience Strategy, Brian Curran. 1 Search Engine Watch 2 Marketing Charts

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  • Difficulty screen scraping http://www.momondo.com using nokogiri

    - by Khai Kiong
    I have some difficulty to extract the total price (css selector = '.total') from the flight result. http://www.momondo.com/multicity/?Search=true&TripType=oneway&SegNo=1&SO0=KUL&SD0=KBR&SDP0=31-12-2012&AD=2&CA=0,0&DO=false&NA=false#Search=true&TripType=oneway&SegNo=1&SO0=KUL&SD0=KBR&SDP0=31-12-2012&AD=2&CA=0,0&DO=false&NA=false I get the error "undefined method `text' for nil:NilClass nokogiri ". My code desc "Fetch product prices" task :fetch_details => :environment do require 'nokogiri' require 'open-uri' include ERB::Util OneWayFlight.find_all_by_money(nil).each do |flight| url = "http://www.momondo.com/multicity/Search=true&TripType=oneway&SegNo=1&SO0=KUL&SD0=KBR&SDP0=31-12-2012&AD=2&CA=0,0&DO=false&NA=false#Search=true&TripType=oneway&SegNo=1&SO0=KUL&SD0=KBR&SDP0=31-12-2012&AD=2&CA=0,0&DO=false&NA=false" doc = Nokogiri::HTML(open(url)) price = doc.at_css(".total").text[/[0-9\.]+/] flight.update_attribute(:price, price) end end

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  • How to associate node with products in Drupal/Ubercart

    - by henrijs.seso
    I am looking for a way to allow users to add node reference to each product or whole cart @ checkout. I am making web site where users can buy items and then receive them on board flight. Products are fixed, but user needs to tell for which flight he is buying items. Flights are nodes and users has flagged these nodes so there is no problem making View with users flagged flight nodes. How would I associate one of these nodes with purchase? Nodereference from CCK would be cool, but checkout is probably not node. Any suggestions for approach?

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  • sql server 2008 multiple inserts over 2 tables

    - by Rob
    I got the following trigger on my sql server 2008 database CREATE TRIGGER tr_check_stoelen ON Passenger AFTER INSERT, UPDATE AS BEGIN IF EXISTS( SELECT 1 FROM Passenger p INNER JOIN Inserted i on i.flight= p.flight WHERE p.flight= i.flightAND p.seat= i.seat ) BEGIN RAISERROR('Seat taken!',16,1) ROLLBACK TRAN END END The trigger is throwing errors when i try to run the query below. This query i supposed to insert two different passengers in a database on two different flights. I'm sure both seats aren't taken, but i can't figure out why the trigger is giving me the error. Does it have to do something with correlation? INSERT INTO passagier VALUES (13392,5315,3,'Janssen Z','2A','October 30, 2006 10:43','M'), (13333,5316,2,'Janssen Q','2A','October 30, 2006 11:51','V')

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  • SQL returns non-array value in PHP

    - by DeadMG
    $request = 'SELECT * FROM flight WHERE Id = \''.$_SESSION['LFLightRadio'].'\''; $data = mysql_fetch_array(mysql_query($request, $SQL)); echo '<table class="table">'; foreach($data as $key => $value) { echo '<th class="head" align="center" height="19">'.$key.'</th>'; } echo '<tr>'; foreach($data as $key => $value) { echo '<td class="cell" align="center" height="19">'.$value.'</td>'; } echo '</tr></table>'; I know that the LFlightRadio value is set, and is a value returned by the Id value of a previously returned row from the flight database. So within "flight", a record definitely exists with this Id. But, this still gives me a non-array result, so that when I try to use foreach on it, it errors out. Suggestions?

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  • Passing Control's Value to Modal Popup

    - by Sherwin Valdez
    Hello, Just would like know how to pass textbox value to a modal popup after clicking a button using ModalPopUpExtender in ASP.NET, I've tried these codes but seems that I have no luck :( <script runat="server"> protected void Page_Load(object sender, EventArgs e) { Button1.Attributes.Add("onclick", "showModalPopup(); return false;"); } </script> <asp:ScriptManager ID="ScriptManager1" runat="server"> </asp:ScriptManager> <asp:TextBox ID="TextBox1" runat="server"></asp:TextBox> <asp:Button ID="Button1" runat="server" Text="Button" OnClick='showModalPopup(); return false;' /> <cc1:ModalPopupExtender ID="ModalPopupExtender1" runat="server" TargetControlID="Button1" PopupControlID="Panel1" CancelControlID="btnCancel" OkControlID="btnOkay" BackgroundCssClass="ModalPopupBG"> </cc1:ModalPopupExtender> <asp:Panel ID="Panel1" Style="display: none" runat="server"> <div class="HellowWorldPopup"> <div class="PopupHeader" id="PopupHeader"> Header</div> <div class="PopupBody"> <asp:Label ID="Label1" runat="server"></asp:Label> </div> <div class="Controls"> <input id="btnOkay" type="button" value="Done" /> <input id="btnCancel" type="button" value="Cancel" /> </div> </div> </asp:Panel> javascript function showModalPopup() { //show the ModalPopupExtender var value; value = document.getElementById("TextBox1").value; $get("<%=Label1.ClientID %>").value = value; $find("<%=ModalPopupExtender1.ClientID %>").show(); } I wonder what I miss out :(, Thanks and I hope someone could help me :)

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  • Python objects as userdata in ctypes callback functions

    - by flight
    The C function myfunc operates on a larger chunk of data. The results are returned in chunks to a callback function: int myfunc(const char *data, int (*callback)(char *result, void *userdata), void *userdata); Using ctypes, it's no big deal to call myfunc from Python code, and to have the results being returned to a Python callback function. This callback work fine. myfunc = mylib.myfunc myfunc.restype = c_int myfuncFUNCTYPE = CFUNCTYPE(STRING, c_void_p) myfunc.argtypes = [POINTER(c_char), callbackFUNCTYPE, c_void_p] def mycb(result, userdata): print result return True input="A large chunk of data." myfunc(input, myfuncFUNCTYPE(mycb), 0) But, is there any way to give a Python object (say a list) as userdata to the callback function? In order to store away the result chunks, I'd like to do e.g.: def mycb(result, userdata): userdata.append(result) userdata=[] But I have no idea how to cast the Python list to a c_void_p, so that it can be used in the call to myfunc. My current workaround is to implement a linked list as a ctypes structure, which is quite cumbersome.

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  • How do I *really* justify a horizontal menu in HTML+CSS?

    - by flight
    You find plenty of tutorials on menu bars in HTML, but for this specific (though IMHO generic) case, I haven't found any decent solution: # THE MENU ITEMS SHOULD BE JUSTIFIED JUST AS PLAIN TEXT WOULD BE # # ^ ^ # # There's an varying number of text-only menu items and the page layout is fluid. # # The first menu item should be left-aligned, the last menu item should be right- # # aligned. The remaining items should be spread optimal on the menu bar. # # # # The number is varying,so there's no chance to pre-calculate the optimal widths. # # # # Note that a TABLE won't work here as well: # # - If you center all TDs, the first and the last item aren't aligned correctly. # # - If you left-align and right-align the first resp. the last items, the spacing # # will be sub-optimal. # Isn't it strange that there is no obvious way to implement this in a clean way by using HTML+CSS?

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  • SpaceX’s Dragon Spacecraft Docks with the ISS [Video]

    - by Jason Fitzpatrick
    This weekend was the first time a commercial space craft successfully rendezvoused with the International Space Station. Check out this video to see the opening of the hatch. From the notes on NASA’s video release: Aboard the International Space Station, Expedition 31 Flight Engineer Don Pettit and Joe Acaba of NASA and European Space Agency Flight Engineer Andre Kuipers opened the hatch to SpaceX’s Dragon cargo craft and entered the vehicle May 26, one day after the world’s first commercial cargo spacecraft was berthed to the Earth-facing port of the Harmony module. Dragon will remain berthed to Harmony until May 31, enabling the crew to unload supplies for the station’s residents before it is re-grappled and released to return to Earth for a parachute-assisted splashdown in the Pacific Ocean off the coast of southern California. If you’re interested in learning more about the SpaceX program, hit up the link below. SpaceX How To Customize Your Wallpaper with Google Image Searches, RSS Feeds, and More 47 Keyboard Shortcuts That Work in All Web Browsers How To Hide Passwords in an Encrypted Drive Even the FBI Can’t Get Into

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  • Looking Back at MIX10

    Its the sad truth of my life that even though Im fascinated by airplanes and flight in general since my childhood days, my body doesnt like flying. Even the ridiculously short flights inside Germany are taking their toll on me each time. Now combine this with sitting in the cramped space of economy class for many hours on a transatlantic flight from Germany to Las Vegas and back, and factor in some heavy dose of jet lag (especially on my way eastwards), and you get an idea why after coming back...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Workshop in Denver canceled - thanks to hurricane Isaac

    - by Mike Dietrich
    Yesterday Roy did start his journey on time to travel to Denver, CO for today's Upgrade and Migration Workshop.  But unfortunately due to the remnants of  hurricane Issac moving up the East Coast and scrambling up flight schedules Roy's flight from NYC to Denver got canceled after a 3 hour delay leaving Manchester, NH, and there was no option to arrive in Denver this morning on time. So we apologize for canceling that workshop. The local marketing department will contact you regarding an alternative date. Sorry for any inconvenience!

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  • WebCenter Customer Spotlight: Azul Brazilian Airlines

    - by me
    Author: Peter Reiser - Social Business Evangelist, Oracle WebCenter  Solution SummaryAzul Linhas Aéreas Brasileiras (Azul Brazilian Airlines) is the third-largest airline in Brazil serving  42 destinations with a fleet of 49 aircraft and employs 4,500 crew members. The company wanted to offer an innovative site with a simple purchasing process for customers to search for and buy tickets and for the company’s marketing team to more effectively conduct its campaigns. To this end, Azul implemented Oracle WebCenter Sites, succeeding in gathering all of the site’s key information onto a single platform. Azul can now complete the Web site content updating process—which used to take approximately 48 hours—in less than five minutes. Company OverviewAzul Linhas Aéreas Brasileiras (Azul Brazilian Airlines) has established itself as the third-largest airline in Brazil, based on a business model that combines low prices with a high level of service. Azul serves 42 destinations with a fleet of 49 aircraft. It operates 350 daily flights with a team of 4,500 crew members. Last year, the company transported 15 million passengers, achieving a 10% share of the Brazilian market, according to the Agência Nacional de Aviação Civil (ANAC, or the National Civil Aviation Agency). Business ChallengesThe company wanted to offer an innovative site with a simple purchasing process for customers to search for and buy tickets and for the company’s marketing team to more effectively conduct its campaigns. Provide customers with an  innovative Web site with a simple process for purchasing flight tickets Bring dynamism to the Web site’s content updating process to provide autonomy to the airline’s strategic departments, such as marketing and product development Facilitate integration among the site’s different application providers, such as ticket availability and payment process, on which ticket sales depend Solution DeployedAzul worked with the  Oracle partner TQI to implement Oracle WebCenter Sites, succeeding in gathering all of the site’s key information onto a single platform. Previously, at least three servers and corporate information environments had directed data to the portal. The single Oracle-based platform now facilitates site updates, which are daily and constant. Business Results Gained development freedom in all processes—from implementation to content editing Gathered all of the Web site’s key information onto a single platform, facilitating its daily and constant updating, whereas the information was previously spread among at least three IT environments and had to go through a complex process to be made available online to customers Reduced time needed to update banners and other Web site content from an average of 48 hours to less than five minutes Simplified the flight ticket sales process thanks to tool flexibility that enabled the company to improve Website usability “Oracle WebCenter Sites provides an easy-to-use platform that enables our marketing department to spend less time updating content and more time on innovative activities. Previously, it would take 48 hours to update content on our Web site; now it takes less than five minutes. We have shown the market that we are innovators, enabling customer convenience through an improved flight ticket purchase process.” Kleber Linhares, Information Technology and E-Commerce Director, Azul Linhas Aéreas Brasileiras Additional Information Azul Brazilian Airlines Case Study Oracle WebCenter Sites Oracle WebCenter Sites Satellite Server

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  • Synchronization requirements for FileStream.(Begin/End)(Read/Write)

    - by Doug McClean
    Is the following pattern of multi-threaded calls acceptable to a .Net FileStream? Several threads calling a method like this: ulong offset = whatever; // different for each thread byte[] buffer = new byte[8192]; object state = someState; // unique for each call, hence also for each thread lock(theFile) { theFile.Seek(whatever, SeekOrigin.Begin); IAsyncResult result = theFile.BeginRead(buffer, 0, 8192, AcceptResults, state); } if(result.CompletedSynchronously) { // is it required for us to call AcceptResults ourselves in this case? // or did BeginRead already call it for us, on this thread or another? } Where AcceptResults is: void AcceptResults(IAsyncResult result) { lock(theFile) { int bytesRead = theFile.EndRead(result); // if we guarantee that the offset of the original call was at least 8192 bytes from // the end of the file, and thus all 8192 bytes exist, can the FileStream read still // actually read fewer bytes than that? // either: if(bytesRead != 8192) { Panic("Page read borked"); } // or: // issue a new call to begin read, moving the offsets into the FileStream and // the buffer, and decreasing the requested size of the read to whatever remains of the buffer } } I'm confused because the documentation seems unclear to me. For example, the FileStream class says: Any public static members of this type are thread safe. Any instance members are not guaranteed to be thread safe. But the documentation for BeginRead seems to contemplate having multiple read requests in flight: Multiple simultaneous asynchronous requests render the request completion order uncertain. Are multiple reads permitted to be in flight or not? Writes? Is this the appropriate way to secure the location of the Position of the stream between the call to Seek and the call to BeginRead? Or does that lock need to be held all the way to EndRead, hence only one read or write in flight at a time? I understand that the callback will occur on a different thread, and my handling of state, buffer handle that in a way that would permit multiple in flight reads. Further, does anyone know where in the documentation to find the answers to these questions? Or an article written by someone in the know? I've been searching and can't find anything. Relevant documentation: FileStream class Seek method BeginRead method EndRead IAsyncResult interface

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  • Use multiple inheritance to discriminate useage roles?

    - by Arne
    Hi fellows, it's my flight simulation application again. I am leaving the mere prototyping phase now and start fleshing out the software design now. At least I try.. Each of the aircraft in the simulation have got a flight plan associated to them, the exact nature of which is of no interest for this question. Sufficient to say that the operator way edit the flight plan while the simulation is running. The aircraft model most of the time only needs to read-acess the flight plan object which at first thought calls for simply passing a const reference. But ocassionally the aircraft will need to call AdvanceActiveWayPoint() to indicate a way point has been reached. This will affect the Iterator returned by function ActiveWayPoint(). This implies that the aircraft model indeed needs a non-const reference which in turn would also expose functions like AppendWayPoint() to the aircraft model. I would like to avoid this because I would like to enforce the useage rule described above at compile time. Note that class WayPointIter is equivalent to a STL const iterator, that is the way point can not be mutated by the iterator. class FlightPlan { public: void AppendWayPoint(const WayPointIter& at, WayPoint new_wp); void ReplaceWayPoint(const WayPointIter& ar, WayPoint new_wp); void RemoveWayPoint(WayPointIter at); (...) WayPointIter First() const; WayPointIter Last() const; WayPointIter Active() const; void AdvanceActiveWayPoint() const; (...) }; My idea to overcome the issue is this: define an abstract interface class for each usage role and inherit FlightPlan from both. Each user then only gets passed a reference of the appropriate useage role. class IFlightPlanActiveWayPoint { public: WayPointIter Active() const =0; void AdvanceActiveWayPoint() const =0; }; class IFlightPlanEditable { public: void AppendWayPoint(const WayPointIter& at, WayPoint new_wp); void ReplaceWayPoint(const WayPointIter& ar, WayPoint new_wp); void RemoveWayPoint(WayPointIter at); (...) }; Thus the declaration of FlightPlan would only need to be changed to: class FlightPlan : public IFlightPlanActiveWayPoint, IFlightPlanEditable { (...) }; What do you think? Are there any cavecats I might be missing? Is this design clear or should I come up with somethink different for the sake of clarity? Alternatively I could also define a special ActiveWayPoint class which would contain the function AdvanceActiveWayPoint() but feel that this might be unnecessary. Thanks in advance!

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