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  • perl xml parser get xml content within xml

    - by user391986
    How can I use XMLParser to get the item-@url, item-@replace and item-"value inside" for the content as a string of the node where item-@cone="one"? <cstep> <item cone="one" url="http://google.com/{ccc}/cthree" replace="{ccc}"> <itemsub conesub="conesub"> <itemsubsub conesubsub="conesubsub" /> </itemsub> </item> <item cone="two" url="http://google.com/{ccc}/cthree" replace="{ccc}"> <itemsub conesub="conesub"> <itemsubsub conesubsub="conesubsub" /> </itemsub> </item> </cstep>

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  • Parsing XML via jQuery, nested loops

    - by Coughlin
    I am using jQuery to parse XML on my page using $.ajax(). My code block is below and I can get this working to display say each result on the XML file, but I am having trouble because each section can have MORE THAN ONE and im trying to print ALL grades that belong to ONE STUDENT. Here is an example of the XML. <student num="505"> <name gender="male">Al Einstein</name> <course cid="1">60</course> <course cid="2">60</course> <course cid="3">40</course> <course cid="4">55</course> <comments>Lucky if he makes it to lab, hopeless.</comments> </student> Where you see the I am trying to get the results to print the grades for EACH student in each course. Any ideas on what I would do? Thanks, Ryan $.ajax({ type: "GET", url: "final_exam.xml", dataType: "xml", success: function(xml) { var student_list = $('#student-list'); $(xml).find('student').each(function(){ $(xml).find('course').each(function(){ gradeArray = $(this).text(); console.log(gradeArray); }); var name = $(this).find("name").text(); var grade = $(this).find("course").text(); var cid = $(this).find("course").attr("cid"); //console.log(cid); student_list.append("<tr><td>"+name+"</td><td>"+cid+"</td><td>"+grade+"</td></tr>"); }); } });

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  • Parsing xml files locally from assets folder using XmlPullParser

    - by Randolphg
    Im trying to parse a local xml file that I place in my assets folder. I've been trying to do this for almost a week now. Here is my test xml file Test1 Test2 Test3 Test4 Test5 I keep getting the same error: W/System.err(22458): org.xmlpull.v1.XmlPullParserException: unexpected type (position:TEXT Code: public void xmlParser() throws XmlPullParserException, IOException, ParserConfigurationException, SAXException { Log.d("tag", "xmlParsing...."); Arithmetic arthm = new Arithmetic(); XmlPullParserFactory xmlPF = XmlPullParserFactory.newInstance(); xmlPF.setValidating(false); XmlPullParser xml = xmlPF.newPullParser(); InputStream raw = getApplication().getAssets().open("menu.xml"); xml.setInput(raw, null); xml.nextTag(); Log.d("tag", "start parsing...."); String elementText = null; String elemName = null; int nofTags = 0; while (xml.getEventType() != XmlPullParser.END_DOCUMENT) { Log.d("tag", "while(xml.next)..."); switch (xml.getEventType()) { case XmlPullParser.START_DOCUMENT: Log.d("tag", "while (xml.getEventType() != XmlPullParser.END_DOCUMENT)"); break; case XmlPullParser.START_TAG: Log.d("tag", " case XmlPullParser.START_TAG"); elementText = xml.getName(); Log.d("tag", "elementText = " + elementText); if (xml.getEventType() != XmlPullParser.END_TAG) { xml.nextTag(); } break; case XmlPullParser.TEXT: Log.d("tag", "case TEXT"); if (elementText.equals("menu") && xml.isWhitespace()) { Log.d("tag", "<" + elementText + ">"); arthm.menu_name = xml.getText(); Log.d("tag", "value " + xml.getText() + " added"); } else if (elementText.equals("item")) { arthm.description = xml.getText(); Log.d("tag", "value " + xml.getText() + " added"); } else if (elementText.equals("SUBCATEGORY NAME")) { arthm.subcategoryDesc.add(xml.getText()); Log.d("tag", "value " + xml.getText() + " added"); } else if (elementText.equals("SUBCATEGORY DESC")) { arthm.subcategoryName.add(xml.getText()); Log.d("tag", "value " + xml.getText() + " added"); } break; case XmlPullParser.END_TAG: Log.d("tag", "case END_TAG"); nofTags += 1; String tags = Integer.toString(nofTags); Log.d("tags", elementText + " number of tags" + tags); if (xml.nextTag() != XmlPullParser.START_TAG) { xml.next(); } break; case XmlPullParser.END_DOCUMENT: Log.d("tag", "case END_DOCUMENT"); break; default: break; } } Log.d("tag", "Success!"); } Thanks in advance.

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  • Parsing WordPress XML, slash:comments syntax?

    - by user313653
    This is really just a syntax question. I have a PHP script that parses my WordPress feed and returns the latest posts. I also want my script to parse the # of comments, but the WordPress feed XML object for number of comments has a colon in it (slash:comments). It causes the following error: Parse error: syntax error, unexpected ':' in ... on line ... I have tried each of the following without luck: $xml->slash:comments $comments = 'slash:comments' $xml->$comments $xml->slash.':'.comments $xml->{slash:comments} $xml->{'slash:comments'} How do I parse an object with a colon?

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  • What is this XML Parse Error?

    - by Jake
    I am using the following script to generate a RSS feed for my site: <?php class RSS { public function RSS() { $root = $_SERVER['DOCUMENT_ROOT']; require_once ("../connect.php"); } public function GetFeed() { return $this->getDetails() . $this->getItems(); } private function dbConnect() { DEFINE ('LINK', mysql_connect (DB_HOST, DB_USER, DB_PASSWORD)); } private function getDetails() { $detailsTable = "rss_feed_details"; $this->dbConnect($detailsTable); $query = "SELECT * FROM ". $detailsTable ." WHERE feed_category = ''"; $result = mysql_db_query (DB_NAME, $query, LINK); while($row = mysql_fetch_array($result)) { $details = '<?xml version="1.0" encoding="ISO-8859-1" ?> <rss version="2.0"> <channel> <title>'. $row['title'] .'</title> <link>'. $row['link'] .'</link> <description>'. $row['description'] .'</description> <language>'. $row['language'] .'</language> <image> <title>'. $row['image_title'] .'</title> <url>'. $row['image_url'] .'</url> <link>'. $row['image_link'] .'</link> <width>'. $row['image_width'] .'</width> <height>'. $row['image_height'] .'</height> </image>'; } return $details; } private function getItems() { $itemsTable = "rss_posts"; $this->dbConnect($itemsTable); $query = "SELECT * FROM ". $itemsTable ." ORDER BY id DESC"; $result = mysql_db_query (DB_NAME, $query, LINK); $items = ''; while($row = mysql_fetch_array($result)) { $items .= '<item> <title>'. $row["title"] .'</title> <link>'. $row["link"] .'</link> <description><![CDATA['.$row["readable_date"]."<br /><br />".$row["description"]."<br /><br />".']]></description> </item>'; } $items .= '</channel> </rss>'; return $items; } } ?> The baffling thing is, the script works perfectly fine on my localhost but gives the following error on my remote server: XML Parsing Error: junk after document element Location: http://mysite.com/rss/main/ Line Number 2, Column 1:<b>Parse error</b>: syntax error, unexpected T_STRING in <b>/home/studentw/public_html/rss/global-reach/rssClass.php</b> on line <b>1</b><br /> ^

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  • Can we replace XML with JSON entirely?

    - by Saeed Neamati
    I'm sure lots of developers are familiar with XML and JSON, and they've used both of them. Thus no point in explaining what they are, and what is their purpose, even in brief. If we try to map their concepts, we can say (correct me if I'm wrong): XML tags are equivalent to JSON {} XML attributes are equivalent to JSON properties XML tag collection is equivalent to JSON [] The only thing I can think of, which doesn't exist in JSON, is XML Namespaces. The question is, considering this mapping, and considering that JSON is highly lighter in this mapping, can we see a world in future (or at least theoretically think of a world) without XML, but with JSON doing everything XML does? Can we use JSON everywhere XML is used? PS: Please note that I've seen this question. It's something entirely different from what I'm asking here. Thus please don't mention duplicate.

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  • Loading a new instance of a class through XML not working quite right

    - by Thegluestickman
    I'm having trouble with XML and XNA. I want to be able to load weapon settings through XML to make my weapons easier to make and to have less code in the actual project file. So I started out making a basic XML document, something to just assign variables with. But no matter what I changed it gave me a new error every time. The code below gives me a "XML element 'Tag' not found", I added and it started to say the variables weren't found. What I wanted to do in the XML file as well, was load a texture for the file too. So I created a static class to hold my texture values, then in the Texture tag of my XML document I would set it to that instance too. I think that's were the problems are occuring because that's where the "XML element 'Tag' not found" error is pointing me too. My XML document: <XnaContent> <Asset Type="ConversationEngine.Weapon"> <weaponStrength>0</weaponStrength> <damageModifiers>0</damageModifiers> <speed>0</speed> <magicDefense>0</magicDefense> <description>0</description> <identifier>0</identifier> <weaponTexture>LoadWeaponTextures.ironSword</weaponTexture> </Asset> </XnaContent> My Class to load the weapon XML: public static class LoadWeaponXML { static Weapon Weapons; public static Weapon WeaponLoad(ContentManager content, int id) { Weapons = content.Load<Weapon>(@"Weapons/" + id); return Weapons; } } public static class LoadWeaponTextures { public static Texture2D ironSword; public static void TextureLoad(ContentManager content) { ironSword = content.Load<Texture2D>("Sword"); } } I'm not entirely sure if you can load textures through XML, but any help would be greatly appreciated.

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  • Receive the Broadcast program with XML [on hold]

    - by bitmez4
    I have a channel publishing sites and I wanna get into the channel CNN broadcast program.. CNN broadcast the program here: (you can see in source - xml File) http://tvprofil.net/xmltv/data/cnn.info/weekly_cnn.info_tvprofil.net.xml How the data according to the time of withdrawal? For example: Now program: "bitmez's table" next program: "stack's table" in 30 minute Is this possible? UPDATE 1 // -I can take the XML data but to all of XML file- <?php if(!$xml=simplexml_load_file('http://tvprofil.net/xmltv/data/cnn.info/weekly_cnn.info_tvprofil.net.xml')){ trigger_error('XML file -- read error',E_USER_ERROR); } echo 'X-'; foreach($xml as $programme){ echo 'Now: '.$programme->title.' <br/>'; } ?>

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  • Unit Testing XML independent of physical XML file

    - by RAbraham
    Hi, My question is: In JUnit, How do I setup xml data for my System Under Test(SUT) without making the SUT read from an XML file physically stored on the file system Background: I am given a XML file which contains rules for creation of an invoice. My job is to convert these rules from XMl to Java Objects e.g. If there is a tag as below in my XML file which indicates that after a period of 30 days, the transaction cannot be invoiced <ExpirationDay>30</ExpirationDay> this converts to a Java class , say ExpirationDateInvoicingRule I have a class InvoiceConfiguration which should take the XML file and create the *InvoicingRule objects. I am thinking of using StAX to parse the XML document within InvoiceConfiguration Problem: I want to unit test InvoiceConfiguration. But I dont want InvoiceConfiguration to read from an xml file physically on the file system . I want my unit test to be independent of any physical stored xml file. I want to create a xml representation in memory. But a StAX parser only takes FileReader( or I can play with the File Object)

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  • XML deserialization doubling up on entities

    - by Nathan Loding
    I have an XML file that I am attempting to deserialize into it's respective objects. It works great on most of these objects, except for one item that is being doubled up on. Here's the relevant portion of the XML: <Clients> <Client Name="My Company" SiteID="1" GUID="xxx-xxx-xxx-xxx"> <Reports> <Report Name="First Report" Path="/Custom/FirstReport"> <Generate>true</Generate> </Report> </Reports> </Client> </Clients> "Clients" is a List<Client> object. Each Client object has a List<Report> object within it. The issue is that when this XML is deserialized, the List<Report> object has a count of 2 -- the "First Report" Report object is in there twice. Why? Here's the C#: public class Client { [System.Xml.Serialization.XmlArray("Reports"), System.Xml.Serialization.XmlArrayItem(typeof(Report))] public List<Report> Reports; } public class Report { [System.Xml.Serialization.XmlAttribute("Name")] public string Name; public bool Generate; [System.Xml.Serialization.XmlAttribute("Path")] public string Path; } class Program { static void Main(string[] args) { List<Client> _clients = new List<Client>(); string xmlFile = "myxmlfile.xml"; System.Xml.Serialization.XmlSerializer xmlSerializer = new System.Xml.Serialization.XmlSerializer(typeof(List<Client>), new System.Xml.Serialization.XmlRootAttribute("Clients")); using (FileStream stream = new FileStream(xmlFile, FileMode.Open)) { _clients = xmlSerializer.Deserialize(stream) as List<Client>; } foreach(Client _client in _clients) { Console.WriteLine("Count: " + _client.Reports.Count); // This write "2" foreach(Report _report in _client.Reports) { Console.WriteLine("Name: " + _report.Name); // Writes "First Report" twice } } } }

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  • Read XML Files using LINQ to XML and Extension Methods

    - by psheriff
    In previous blog posts I have discussed how to use XML files to store data in your applications. I showed you how to read those XML files from your project and get XML from a WCF service. One of the problems with reading XML files is when elements or attributes are missing. If you try to read that missing data, then a null value is returned. This can cause a problem if you are trying to load that data into an object and a null is read. This blog post will show you how to create extension methods to detect null values and return valid values to load into your object. The XML Data An XML data file called Product.xml is located in the \Xml folder of the Silverlight sample project for this blog post. This XML file contains several rows of product data that will be used in each of the samples for this post. Each row has 4 attributes; namely ProductId, ProductName, IntroductionDate and Price. <Products>  <Product ProductId="1"           ProductName="Haystack Code Generator for .NET"           IntroductionDate="07/01/2010"  Price="799" />  <Product ProductId="2"           ProductName="ASP.Net Jumpstart Samples"           IntroductionDate="05/24/2005"  Price="0" />  ...  ...</Products> The Product Class Just as you create an Entity class to map each column in a table to a property in a class, you should do the same for an XML file too. In this case you will create a Product class with properties for each of the attributes in each element of product data. The following code listing shows the Product class. public class Product : CommonBase{  public const string XmlFile = @"Xml/Product.xml";   private string _ProductName;  private int _ProductId;  private DateTime _IntroductionDate;  private decimal _Price;   public string ProductName  {    get { return _ProductName; }    set {      if (_ProductName != value) {        _ProductName = value;        RaisePropertyChanged("ProductName");      }    }  }   public int ProductId  {    get { return _ProductId; }    set {      if (_ProductId != value) {        _ProductId = value;        RaisePropertyChanged("ProductId");      }    }  }   public DateTime IntroductionDate  {    get { return _IntroductionDate; }    set {      if (_IntroductionDate != value) {        _IntroductionDate = value;        RaisePropertyChanged("IntroductionDate");      }    }  }   public decimal Price  {    get { return _Price; }    set {      if (_Price != value) {        _Price = value;        RaisePropertyChanged("Price");      }    }  }} NOTE: The CommonBase class that the Product class inherits from simply implements the INotifyPropertyChanged event in order to inform your XAML UI of any property changes. You can see this class in the sample you download for this blog post. Reading Data When using LINQ to XML you call the Load method of the XElement class to load the XML file. Once the XML file has been loaded, you write a LINQ query to iterate over the “Product” Descendants in the XML file. The “select” portion of the LINQ query creates a new Product object for each row in the XML file. You retrieve each attribute by passing each attribute name to the Attribute() method and retrieving the data from the “Value” property. The Value property will return a null if there is no data, or will return the string value of the attribute. The Convert class is used to convert the value retrieved into the appropriate data type required by the Product class. private void LoadProducts(){  XElement xElem = null;   try  {    xElem = XElement.Load(Product.XmlFile);     // The following will NOT work if you have missing attributes    var products =         from elem in xElem.Descendants("Product")        orderby elem.Attribute("ProductName").Value        select new Product        {          ProductId = Convert.ToInt32(            elem.Attribute("ProductId").Value),          ProductName = Convert.ToString(            elem.Attribute("ProductName").Value),          IntroductionDate = Convert.ToDateTime(            elem.Attribute("IntroductionDate").Value),          Price = Convert.ToDecimal(elem.Attribute("Price").Value)        };     lstData.DataContext = products;  }  catch (Exception ex)  {    MessageBox.Show(ex.Message);  }} This is where the problem comes in. If you have any missing attributes in any of the rows in the XML file, or if the data in the ProductId or IntroductionDate is not of the appropriate type, then this code will fail! The reason? There is no built-in check to ensure that the correct type of data is contained in the XML file. This is where extension methods can come in real handy. Using Extension Methods Instead of using the Convert class to perform type conversions as you just saw, create a set of extension methods attached to the XAttribute class. These extension methods will perform null-checking and ensure that a valid value is passed back instead of an exception being thrown if there is invalid data in your XML file. private void LoadProducts(){  var xElem = XElement.Load(Product.XmlFile);   var products =       from elem in xElem.Descendants("Product")      orderby elem.Attribute("ProductName").Value      select new Product      {        ProductId = elem.Attribute("ProductId").GetAsInteger(),        ProductName = elem.Attribute("ProductName").GetAsString(),        IntroductionDate =            elem.Attribute("IntroductionDate").GetAsDateTime(),        Price = elem.Attribute("Price").GetAsDecimal()      };   lstData.DataContext = products;} Writing Extension Methods To create an extension method you will create a class with any name you like. In the code listing below is a class named XmlExtensionMethods. This listing just shows a couple of the available methods such as GetAsString and GetAsInteger. These methods are just like any other method you would write except when you pass in the parameter you prefix the type with the keyword “this”. This lets the compiler know that it should add this method to the class specified in the parameter. public static class XmlExtensionMethods{  public static string GetAsString(this XAttribute attr)  {    string ret = string.Empty;     if (attr != null && !string.IsNullOrEmpty(attr.Value))    {      ret = attr.Value;    }     return ret;  }   public static int GetAsInteger(this XAttribute attr)  {    int ret = 0;    int value = 0;     if (attr != null && !string.IsNullOrEmpty(attr.Value))    {      if(int.TryParse(attr.Value, out value))        ret = value;    }     return ret;  }   ...  ...} Each of the methods in the XmlExtensionMethods class should inspect the XAttribute to ensure it is not null and that the value in the attribute is not null. If the value is null, then a default value will be returned such as an empty string or a 0 for a numeric value. Summary Extension methods are a great way to simplify your code and provide protection to ensure problems do not occur when reading data. You will probably want to create more extension methods to handle XElement objects as well for when you use element-based XML. Feel free to extend these extension methods to accept a parameter which would be the default value if a null value is detected, or any other parameters you wish. NOTE: You can download the complete sample code at my website. http://www.pdsa.com/downloads. Choose “Tips & Tricks”, then "Read XML Files using LINQ to XML and Extension Methods" from the drop-down. Good Luck with your Coding,Paul D. Sheriff  

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  • JBoss AS: use .xml files in the properties-service.xml

    - by fgysin
    The properties service (configured in properties-service.xml) in JBoss application server lets you specify external .properties files that are loaded and can then be accessed as system properties from the deployed applications. (See here http://community.jboss.org/wiki/PropertiesService for more info...) Is it also possible to load config files in the .xml format instead of .properties? I know it is possible for certain given configs like for example the mail-service.xml and the jboss-log4j.xml... But they are both loaded directly by JBoss, and not via the properties service.

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  • JBOSS Security: web.xml vs. jboss-web.xml

    - by sixtyfootersdude
    What is the relation between web.xml and jboss-web.xml? Seems like: Jboss-web.xml specifies the security domain (which can be found in login-config.xml) web.xml specifies what the security level is I don't understand what happens when jboss-web.xml specifies a weak security domain. Ie: one that cannot do what web.xml specifies. What happens then?

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  • Special characters in XHTML - Parse Error

    - by Rachel
    When there are special characters like & in the xhtml the DOM / SAX parser throws parse exception. The xhtml document is got as an input for my component. I want to ignore such special characters when i parse. How can i achieve it using DOM/SAX JAVA parser.

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  • Is xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" a special case in XML?

    - by Bytecode Ninja
    When we use a namespace, we should also indicate where its associated XSD is located at, as can be seen in the following example: <?xml version="1.0"?> <Artist BirthYear="1958" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://www.webucator.com/Artist" xsi:schemaLocation="http://www.webucator.com/Artist Artist.xsd"> <Name> <Title>Mr.</Title> <FirstName>Michael</FirstName> <LastName>Jackson</LastName> </Name> </Artist> Here, we have indicated that Artist.xsd should be used for validating the http://www.webucator.com/Artist namespace. However, we are also using the http://www.w3.org/2001/XMLSchema-instance namespace, but we have not specified where its XSD is located at. How do XML parsers know how to handle this namespace? Thanks in advance.

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  • Using XML as data storage

    - by Kian Mayne
    I was thinking about the XML format and the following quote: “XML is not a database. It was never meant to be a database. It is never going to be a database. Relational databases are proven technology with more than 20 years of implementation experience. They are solid, stable, useful products. They are not going away. XML is a very useful technology for moving data between different databases or between databases and other programs. However, it is not itself a database. Don't use it like one.“ -Effective XML: 50 Specific Ways to Improve Your XML by Elliotte Rusty Harold (page 230, Part 4, Item 41, 2nd paragraph) This seems to really stress that XML should not be used for data storage and should only be used for program to program interoperability. Personally, I disagree and .NET's app.config file that's used to store a program's settings is an example of data storage in an XML file. However for databases rather than configurations etc XML should not be used. To develop my point, I will use two examples: A) Data about customers with fields that are all on one level i.e. there are a number of fields all relating to one customer with no children B) Data about configuration of an application where nested fields and properties make a lot of sense So my question is, Is this still a valid statement and is it now acceptable to store data using XML? EDIT: I've sent an email to the author of that quote to ask for his input/extra context.

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  • XML + Xslt -> Xml with PHP

    - by rokdd
    Hi, I know that there are really a mass of XML XSLT php merging threads at SO. But php specific i could not found what might my problem: $xml = new DOMDocument; $xml-load("f.xml"); $xsl = new DOMDocument; $xsl-load('test.xsl'); // init and configure processor $proc = new XSLTProcessor; $proc-importStyleSheet($xsl); // import xsl document $xml2=$proc-transformToXML($xml); echo $xml2; My xslt file looks a bit empty.. However i tried ´output method="xml"´. but it doesnot help.. PHP returns always the data as text or html but not in XML.. what i am doing wrong. I only want to edit the XML with xslt and save back to XML (file). THanks for your help!

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  • Friendly way to parse XDocument

    - by Oli
    I have a class that various different XML schemes are created from. I create the various dynamic XDocuments via one (Very long) statement using conditional operators for optional elements and attributes. I now need to convert the XDocuments back to the class but as they are coming from different schemes many elements and sub elements may be optional. The only way I know of doing this is to use a lot of if statements. This approach doesn't seem very LINQ and uses a great deal more code than when I create the XDocument so I wondered if there is a better way to do this? An example would be to get <?xml version="1.0"?> <root xmlns="somenamespace"> <object attribute1="This is Optional" attribute2="This is required"> <element1>Required</element1> <element1>Optional</element1> <List1> Optional List Of Elements </List1> <List2> Required List Of Elements </List2> </object> </root> Into public class Object() { public string Attribute1; public string Attribute2; public string Element1; public string Element2; public List<ListItem1> List1; public List<ListItem2> List2; } In a more LINQ friendly way than this: public bool ParseXDocument(string xml) { XNamespace xn = "somenamespace"; XDocument document = XDocument.Parse(xml); XElement elementRoot = description.Element(xn + "root"); if (elementRoot != null) { //Get Object Element XElement elementObject = elementRoot.Element(xn + "object"); if(elementObject != null) { if(elementObject.Attribute(xn + "attribute1") != null) { Attribute1 = elementObject.Attribute(xn + "attribute1"); } if(elementObject.Attribute(xn + "attribute2") != null) { Attribute2 = elementObject.Attribute(xn + "attribute2"); } else { //This is a required Attribute so return false return false; } //If, If/Elses get deeper and deeper for the next elements and lists etc.... } else { //Object is a required element so return false return false; } } else { //Root is a required element so return false return false; } return true; } Update: Just to clarify the ParseXDocument method is inside the "Object" class. Every time an xml document is received the Object class instance has some or all of it's values updated.

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  • Perl XML SAX parser emulating XML::Simple record for record

    - by DVK
    Short Q summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog - due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. What I'm looking for is an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been. I don't care much what the interface of the new module is - e.g whether I need to call next_record() or give it a callback coderef accepting a record.

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  • Perl XML SAX parser emulating XML::Simple record for record

    - by DVK
    Short Q summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog - due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. What I'm looking for is an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been.

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  • parse Linq To Xml with attribute nodes

    - by Manoj
    I am having xml with following structure <ruleDefinition appId="3" customerId = "acf"> <node alias="element1" id="1" name="department"> <node alias="element2" id="101" name="mike" /> <node alias="element2" id="102" name="ricky" /> <node alias="element2" id="103" name="jim" /> </node> </ruleDefinition> Here nodes are differentiated using alias and not with node tag. As you can see top level node element1 has same node name "node" as element2. I want to parse this XML based on attribute alias. What should be the Linq-To-Xml code (using C#)to acheive this?

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  • Using Qt's XML library for simple operation

    - by David Powers
    I basically want to use the XML parser from Qt in my existing project. I have only used Qt once before, and that was with Qt Designer, and I am not having much luck finding anything on Google about how to just use the XML library. I have downloaded a web page that has one large list, and I want to parse it and add each list item to a c++ list. I found this sample code on Ubuntu forums... http://www.uluga.ubuntuforums.org/showpost.php?p=9112973&postcount=6 I want to use that except I need to know what exactly I need to add to the project to get access to it. One other small question is QDomDocument seems to be for files (makes sense) but I have the XML in a string. What part of the XML library works for contents of a string?

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  • How to display information contained in XML file from another website

    - by Tristan
    Hello, I have an XML file ( XML file I produce ) which contains information about my parteners. I want them to display on their website information relative to them by picking them into the XML file. I have no idea to do that, ecxept that i need to write a 'parser' in javascript to display information. could you please provide me examples to do that ? (how to write a parser, how to display only information for one partener ?) Thank you, Regards

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