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  • help with regex pattern

    - by noname
    i have multiple strings containing a link like: <A HREF="http://www.testings2">testings2</A> <A HREF="http://www.blabla">blabla</A> <A HREF="http://www.gowick">gowick</A> i want to use a regex pattern that gets the uri within the href. i could do like: /".*?"/ but then the "" will come along. is there a way to just get the uri within the HREF="" without using preg_replace function? thanks!

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  • Javascript Regex to convert dot notation to bracket notation

    - by Tauren
    Consider this javascript: var joe = { name: "Joe Smith", location: { city: "Los Angeles", state: "California" } } var string = "{name} is currently in {location.city}, {location.state}"; var out = string.replace(/{([\w\.]+)}/g, function(wholematch,firstmatch) { return typeof values[firstmatch] !== 'undefined' ? values[firstmatch] : wholematch; }); This will output the following: Joe Smith is currently in {location.city}, {location.state} But I want to output the following: Joe Smith is currently in Los Angeles, California I'm looking for a good way to convert multiple levels of dot notation found between braces in the string into multiple parameters to be used with bracket notation, like this: values[first][second][third][etc] Essentially, for this example, I'm trying to figure out what regex string and function I would need to end up with the equivalent of: out = values[name] + " is currently in " + values["location"]["city"] + values["location"]["state"];

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  • How to improve my Python regex syntax?

    - by FarmBoy
    I very new to Python, and fairly new to regex. (I have no Perl experience.) I am able to use regular expressions in a way that works, but I'm not sure that my code is particularly Pythonic or consise. For example, If I wanted to read in a text file and print out text that appears directly between the words 'foo' and 'bar' in each line (presuming this occurred one or zero times a line) I would write the following: fileList = open(inFile, 'r') pattern = re.compile(r'(foo)(.*)(bar)') for line in fileList: result = pattern.search(line) if (result != None): print result.groups()[1] Is there a better way? The if is necessary to avoid calling groups() on None. But I suspect there is a more concise way to obtain the matching String when there is one, without throwing errors when there isn't. I'm not hoping for Perl-like unreadability. I just want to accomplish this common task in the commonest and simplest way.

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  • Add / remove a port number to/from a URL with REGEX in PHP

    - by SuperDuck
    Hello guys, I've searched but was unable to find an existing regex function. Has anybody done this before? I wish to add a port number, or remove a potantially existing one from a url in php. To use in some functions which translate a given url to the secure one, unsecure one, etc. Now I need a second SSL secured site on the server so I need to dynamically add a port number while converting http to https, and remove any port number while converting from https to http. Thanks, Duck

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  • Regex to match 2 things in 1 HTML file

    - by CyberK
    Hi, I have a HTML file which contains the following: <img src="MATCH1" bla="blabla"> <something:else bla="blabla" bla="bla"><something:else2 something="something"> <something image="MATCH2" bla="abc"> Now I need a regex to match both MATCH1 and MATCH2 Also the HTML contains multiple parts like this, so it can be in the HTML 1, 2, 3 of x times.. When I say: <img\s*src="(.*?)".*?<something\s*image="(.*?)" It doesn't match it. What am I missing here? Thanks in advance!

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  • replacing strings with regex in javascript

    - by koko
    Hi, regex is bugging me right now. I simply want to replace the range=100 in a string like var string = '...commonstringblabla&range=100&stringandsoon...'; with ...commonstringblabla&range=400&stringandsoon... I successfully matched the "range=100"-part with alert( string.match(/range=100/) ); But when I try to replace it string.replace(/range=100/, 'range=400'); nothing happens, the string still has the range=100 in it... I don't get it, please help.

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  • RegEx to extract all HTML tag attributes including inline JavaScript

    - by Mike
    I found this useful regex code here while looking to parse HTML tag attributes: (\S+)=["']?((?:.(?!["']?\s+(?:\S+)=|[>"']))+.)["']? It works great, but it's missing one key element that I need. Some attributes are event triggers that have inline Javascript code in them like this: onclick="doSomething(this, 'foo', 'bar');return false;" Or: onclick='doSomething(this, "foo", "bar");return false;' I can't figure out how to get the original expression to not count the quotes from the JS (single or double) while it's nested inside the set of quotes that contain the attribute's value.

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  • how to match all group and subgroup in pcre

    - by mono
    a ip or other string, like "11.22.33.44" or "aa.bb.cc.dd". basically, I think it is very easy, (([\d\w]+)+\.)+[\d\w]+ but the problem is which group these submatches are in. not like ip, some string is consist of lots of words+separate in pcre, I don't know how to extract it all words -- "aa bb cc dd ..."

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  • Regex & BBCode - Perfecting Nested Quote

    - by Moe
    Hey there, I'm working on some BBcode for my website. I've managed to get most of the codes working perfectly, however the [QUOTE] tag is giving me some grief. When I get something like this: [QUOTE=1] [QUOTE=2] This is a quote from someone else [/QUOTE] This is someone else quoting someone else [/QUOTE] It will return: > 1 said: [QUOTE=2]This is a quote from > someone else This is someone else quoting someone else[/QUOTE] So what is happening is the [/quote] from the nested quote is closing the quote block. The Regex I am using is: "[quote=(.*?)\](.*?)\[/quote\]'is" How can I make it so nested Quotes will appear properly? Thank you.

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  • RegEx for a date format

    - by Ivan
    Say I have a string like this: 07-MAY-07 Hello World 07-MAY-07 Hello Again So the pattern is, DD-MMM-YY, where MMM is the three letter format for a month. What Regular Expression will break up this string into: 07-MAY-07 Hello World 07-MAY-07 Hello Again Using Jason's code below modified for C#, string input = @"07-MAY-07 Hello World 07-MAY-07 Hello Again"; string pattern = @"(\d{2}-[A-Z]{3}-\d{2}\s)(\D*|\s)"; string[] results = Regex.Split(input, pattern); results.Dump(); Console.WriteLine("Length = {0}", results.Count()); foreach (string split in results) { Console.WriteLine("'{0}'", split); Console.WriteLine(); } I get embedded blank lines? Length = 7 '' '07-MAY-07 ' 'Hello World ' '' '07-MAY-07 ' 'Hello Again' '' I don't even understand why I am getting the blank lines...?

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  • RegEx - Match optional groups

    - by Maurizio
    I know RE is not the best way to scrape HTMLs, but this is it... I have some something like: <td> Writing: <a href="creator.php?c=CCh">Carlo Chendi</a> Art: <a href="creator.php?c=LBo">Luciano Bottaro</a> </td> And I need to match the Writing and Art parts. But it is not said they're there and there could be other parts like Ink and Pencils... How do i do this ? I need to use pure Regex, no additional Python libs... Thanks !

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  • Using a regex to determine domain using JavaScript

    - by jerome
    Hi All, If, as here at work, we have test, staging and production environments, such as: http://test.my-happy-work.com http://staging.my-happy-work.com http://www.my-happy-work.com I am writing some javascript that will redirect the browser to a url such as: http://[environment].my-happy-work.com/my-happy-video I need to be able to determine the current environment that we are in. There is the possibility that I will currently be at a url such as: http://[environment].my-happy-work.com/my-happy-path/my-happy-resource I want to be able to grab the window.location but strip it of everything but: http://[environment].my-happy-work.com And then append to that string + "/" + "my-happy-video". I am not skilled with regex, but I suppose there would be a way to parse the window.location up to the ".com" Thoughts? Thanks!

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  • Regex to detect a proper permalink?

    - by Fedor
    These permalinks above are rerouted to my page: page.php?permalink=events/foo page.php?permalink=events/foo/ page.php?permalink=ru/events/foo page.php?permalink=ru/events/foo/ The events is dynamic, it could be specials or packages. My dilemma is basically; I need to detect an empty link in order so I can feed a robots no index meta tag in the case of: page.php?permalink=events page.php?permalink=events/ page.php?permalink=ru/events/ page.php?permalink=ru/events I can't use a simple pattern such as [a-zA-Z]+\/?(.+)/ since it won't work on the i18n permalinks. What regex could I use which would detect this, using $_GET['permalink'] as the reference to the permalinks? And avoid false positives? Update: Empty link means there's no fragment after the "events/" part. These are empty: page.php?permalink=events page.php?permalink=events/ page.php?permalink=ru/events/ page.php?permalink=ru/events

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  • regex for shortforms

    - by Sourabh
    I need a regex (JavaScript) which will extract shortforms from a string for example from below string Hibbs' essays in progress include "Anselm's Sacramental Imagination," "W.E.B. DuBois and Socratic Questioning," and "Everything That Rises Must Converge: Aquinas's Theological Re-formation of the Cardinal Virtues." it will match "W.E.B." so the condition is it should have DOTs to seperate the letters or from Marcih J. Robert II. Distinguished Professor of Electrical & Computer Engineering. Ph.D. (1977) Texas Tech University, B.S./M.S. Rose-Hulman Institute of Technology (1972/1973). Ph.D. B.S. M.S. will match Thanks

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  • A regex for version number parsing

    - by ajborley
    Hi, I have a version number of the following form: version.release.modification where version, release and modification are either a set of digits or the '*' wildcard character. Additionally, any of these numbers (and any preceding .) may be missing. So the following are valid and parse as: 1.23.456 = version 1, release 23, modification 456 1.23 = version 1, release 23, any modification 1.23.* = version 1, release 23, any modification 1.* = version 1, any release, any modification 1 = version 1, any release, any modification * = any version, any release, any modification But these are not valid: *.12 *123.1 12* 12.*.34 Can anyone provide me a not-too-complex regex to validate and retrieve the release, version and modification numbers? Many thanks! Thanks for all the responses! This is ace :) Based on OneByOne's answer (which looked the simplest to me), I added some non-capturing groups (the '(?:' parts - thanks to VonC for introducing me to non-capturing groups!), so the groups that do capture only contain the digits or * character. ^(?:(\d+)\.)?(?:(\d+)\.)?(\*|\d+)$ Many thanks to everyone!

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  • Regex - Ignore lines with matching text

    - by codem
    I need the RegEx command to get all the lines which DO NOT have the job name containing "filewatch". Any help will be greatly appreciated! Thanks. STATUS: FAILURE JOB: i3-imds-dcp-pd-bo1-05-ftpfilewatcher STATUS: FAILURE JOB: i3-cur-atmrec-pd-TD_FTP_Forecast_File_Del_M_Su ALARM: JOBFAILURE JOB: i3-cur-atmrec-pd-TD_FTP_Forecast_File_Del_M_Su STATUS: FAILURE JOB: i3-sss-system-heartbeat ALARM: JOBFAILURE JOB: i3-sss-system-heartbeat STATUS: FAILURE JOB: i3-chq-cspo-pd-batch-daily-renametable-fileok STATUS: FAILURE JOB: i3-chq-cspo-pd-batch-daily-renametable-file ALARM: JOBFAILURE JOB: i3-chq-cspo-pd-batch-daily-renametable-fileok ALARM: JOBFAILURE JOB: i3-chq-cspo-pd-batch-daily-renametable-file STATUS: FAILURE JOB: i3-imds-dcp-pd-bo1-35-filewatcher STATUS: FAILURE JOB: i3-imds-dcp-pd-bo1-05-ftpfilewatcher STATUS: FAILURE JOB: i3-imds-dcp-pd-bo1-35-filewatcher STATUS: FAILURE JOB: i3-imds-dcp-pd-bo1-05-ftpfilewatcher

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  • Java String.replaceAll regex

    - by atomsfat
    I want to replace the first context of web/style/clients.html with the java String.replaceFirst method so I can get: ${pageContext.request.contextPath}/style/clients.html I tried String test = "web/style/clients.html".replaceFirst("^.*?/", "hello/"); And this give me: hello/style/clients.html but when I do String test = "web/style/clients.html".replaceFirst("^.*?/", "${pageContext.request.contextPath}/"); gives me java.lang.IllegalArgumentException: Illegal group reference

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  • java.util.regex.* Recursive matching

    - by amit.bhayani
    Hi Guys, I have been using the java.util.regex.* classes for Regular Expression in Java and all good so far. But today I have a different requirement. For example consider the pattern to be "aabb". Now if the input String is aa it will definitely not match, however there is still possibility that if I append bb it becomes aabb and it matches. However if I would have started with cc, no matter what I append it will never match. I have explored the Pattern and Matcher class but didn't find any way of achieving this. The input will come from user and system have to wait till pattern matches or it will never match irrespective of any input further. Any clue? Thanks.

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  • Ignore duplicates in regex pattern

    - by gAMBOOKa
    I have a regex pattern that searches for words in a text file. How do I ignore duplicates? For instance, take a look at this code $pattern = '/(lorem|ipsum|daboom|pahwal|ababaga)/i'; $num_found = preg_match_all( $pattern, $string, $matches ); echo "$num_found match(es) found!"; echo "Matched words: " . implode( ',', $matches[0] ); If I have more than one say lorem in the article, the output will be something like this 5 matches found! Matched words: daboom,lorem,lorem,lorem,lorem I want the pattern to only find the first occurrence, and ignore the rest, so the output should be: 2 matches found! Matched words: daboom,lorem

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  • [C#, Regex] EOL Special Char not matching

    - by Aurélien Ribon
    Hello, I am trying to find every "a - b, c, d" pattern in an input string. The pattern I am using is the following : "^[ \t]*(\\w+)[ \t]*->[ \t]*(\\w+)(,[ \t]*\\w+)*$" The input is : a -> b b -> c c -> d The function is : private void ParseAndBuildGraph(String input) { MatchCollection mc = Regex.Matches(input, "^[ \t]*(\\w+)[ \t]*->[ \t]*(\\w+)(,[ \t]*\\w+)*$", RegexOptions.Multiline); foreach (Match m in mc) { Debug.WriteLine(m.Value); } } The output is : c -> d Actually, there is a problem with the line ending "$" special char. If I insert a "\r" before "$", it works, but I thought "$" would match any line termination (with the Multiline option), especially a \r\n in a Windows environment. Is it not the case ?

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  • Boost Regex throwing an error

    - by Srinivasa Varadan
    Hi ALL, I have the following error when I try to compile my code in g+ compiler using eclipse In function `ZSt19__iterator_categoryIPKSsENSt15iterator_traitsIT_E17iterator_categoryERKS3_': C:/Program Files (x86)/mingw/bin/../lib/gcc/mingw32/3.4.5/../../../../include/c++/3.4.5/bits/stl_algobase.h:(.text$_ZN5boost11basic_regexIcNS_12regex_traitsIcNS_16cpp_regex_traitsIcEEEEE6assignEPKcS7_j[boost::basic_regex<char, boost::regex_traits<char, boost::cpp_regex_traits<char> > >::assign(char const*, char const*, unsigned int)]+0x22): undefined reference to `boost::basic_regex<char, boost::regex_traits<char, boost::cpp_regex_traits<char> > >::do_assign(char const*, char const*, unsigned int)' collect2: ld returned 1 exit status Build error occurred, build is stopped All I have done is this statement boost::regex re("\s+"); along with the header #inlucde Could you kindly tell me how to proceed ?

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  • RegEx for the <li></li> tags

    - by Abu
    Hi All, i am working on the C# WinForm application. In that application, i have snippet like this: <ul> <li>abc <li>bbc <li>xyz <li>pqr </li></li></li></li> </ul> but, i want to get output like.. <ul> <li>abc</li> <li>bbc</li> <li>xyz</li> <li>pqr</li> </ul> Is there any method using which this thing can be done? Can anybody suggest me any RegEx for this problem? Thanks. Regards.

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  • Regex Searching in Emacs

    - by Inaimathi
    I'm trying to write some Elisp code to format a bunch of legacy files. The idea is that if a file contains a section like "<meta name=\"keywords\" content=\"\\(.*?\\)\" />", then I want to insert a section that contains existing keywords. If that section is not found, I want to insert my own default keywords into the same section. I've got the following function: (defun get-keywords () (re-search-forward "<meta name=\"keywords\" content=\"\\(.*?\\)\" />") (goto-char 0) ;The section I'm inserting will be at the beginning of the file (or (march-string 1) "Rubber duckies and cute ponies")) ;;or whatever the default keywords are When the function fails to find its target, it returns Search failed: "[regex here]" and prevents the rest of evaluation. Is there a way to have it return the default string, and ignore the error?

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  • standardize international phone no. code using only regex

    - by DarkFox
    Sipdroid on Android has a search & replace method, that uses regex. I'm trying to use it to make sure all outgoing calls has a country code in the format 00XX I also want it to put 0045 in front of the number, if no country code is present. The first one, I have solved, but I can't figure out how to do the second thing. Search: \A(((\+)(\d{2})?)|(00(\d{2})?)|)((\d|\s)+)\Z Replace: 00$4$6$7 I'm using http://www.regexplanet.com/simple/index.html to test it, with the test strings: "12345678", "+4512345678" and "004512345678" They should all return "004512345678".

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  • Regex browser version match

    - by Matic
    I have a string: Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.9.1.2) Gecko/20090729 Firefox/3.5.2 (.NET CLR 3.5.30729) I want to know what version of Firefox is in the string (3.5.2). My current regex is: Firefox\/[0-9]\.[0-9]\.[0-9] and it returns Firefox/3.5.2 I only want it to return 3.5.2 from the Firefox version, not the other versions in the string. I already know the browser is Firefox.

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