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  • What is the right way to modify a wordpress query in a plugin?

    - by starepod
    Basically i am playing with a plugin that allows future-dated posts on archive pages. My question is broader than this specific functionality, but everyone likes some context. I have my head around many of the plugin development concepts, but must be missing something very basic. I can successfully rewrite a query that gives me the results i want like this: function modify_where( $where ) { global $wp_query; // define $year, $cat, etc if( is_archive() ) { $where = " AND YEAR(wp_posts.post_date)='".$year."' AND wp_term_taxonomy.taxonomy = 'category' AND wp_term_taxonomy.term_id IN ('".$cat."') AND wp_posts.post_type = 'post' AND (wp_posts.post_status = 'publish' OR wp_posts.post_status = 'future')"; } return $where; } add_filter('posts_where', 'catCal_where' ); However, if i attempt to create a new WP_Query('different_query_stuff') after the main loop the new query uses the same WHERE statement outlined above. The question is : What am I missing? Thanks.

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  • Can i query a List? Java

    - by Nitesh Panchal
    Hello, Say i have List<SomeObject> objList = new ArrayList<SomeObject>(); If someObject contains a field named id. Can we find it through some query like objList.filter('id=2'); wihout looping through the list? If not, then why? This can be so useful method and used as an alternative to write tedious for loop? Just a question that came to my mind so i thought i must clear it here :) Thanks in advance :)

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  • Cannot we use break statement in a lambda(C#3.0)

    - by Newbie
    Consider this List<int> intList = new List<int> { 1, 2, 3, 4, 5, 6 }; int j = 0; intList.ForEach(i => { if (i.Equals(1)) { j = i; break; } } ); Throwing error: No enclosing loop out of which to break or continue But the below works foreach(int i in intList) { j = i; break; } Why so. Am I making any mistake. Thanks

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  • Can I un-assign (clear) all fields of an instance?

    - by Roman
    Is there a simple way to clear all fields of an instance from a an instance? I mean, I would like to remove all values assigned to the fields of an instance. ADDED From the main thread I start a window and another thread which controls state of the window (the last thread, for example, display certain panels for a certain period of time). I have a class which contains state of the window (on which stage the user is, which buttons he already clicked). In the end, user may want to start the whole process from the beginning (it is a game). So, I decided. So, if everything is executed from the beginning, I would like to have all parameter to be clean (fresh, unassigned). ADDED The main thread, creates the new object which is executed in a new thread (and the old thread is finished). So, I cannot create a new object from the old thread. I just have a loop in the second thread.

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  • How to apply Seq map function?

    - by netmatrix01
    Hello All, I been recently playing with F# . I was wondering instead of using a for loop to generate a sequence to element which are multiplied with every other element in the list how can I use a Seq map function or something similar to generate something like below. So for e.g. I have a list [1..10] I would like to apply a fun which generates a result something like [(1*1); (1*2);(1*3); (1*4); (1*5)......(2*1);(2*2);(2*3).....(3*1);(3*2)...] How can i achieve this ?. Many thanks for all you help.

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  • JavaScript: String Concatenation slow performance? Array.join('')?

    - by NickNick
    I've read that if I have a for loop, I should not use string concation because it's slow. Such as: for (i=0;i<10000000;i++) { str += 'a'; } And instead, I should use Array.join(), since it's much faster: var tmp = []; for (i=0;i<10000000;i++) { tmp.push('a'); } var str = tmp.join(''); However, I have also read that string concatention is ONLY a problem for Internet Explorer and that browsers such as Safari/Chrome, which use Webkit, actually perform FASTER is using string concatention than Array.join(). I've attempting to find a performance comparison between all major browser of string concatenation vs Array.join() and haven't been able to find one. As such, what is faster and more efficient JavaScript code? Using string concatenation or Array.join()?

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  • writing a single line of a file in C++ into two different arrays

    - by mekasperasky
    suppose a text file has 11001100 11001101 and i open the text file and take the input from the file as pt[0]=11001100, pt[1]=11001101.. but if i take the input from file as inpt it wont put it in two different arrays which is obvious but it takes the whole line . Thus I have to take another for loop and traverse through the whole string and when I find a null character i start putting into the second array . But how can I do it without putting it into a variable and traversing .. I mean directly from the file itself ..

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  • Select photo while keep the order

    - by wong2
    I have a list of photo on the page, each have an unique id, user can click on them to toggle select the photo, when they click the submit button, I need to send the array of selected photo ids to the back end, in the order that the photo was selected. I think that the fastest way to track if a photo is selected is to use an object that use photo id as key, like: var selected = { "6272861": true, "6272888": true } when the user unselect a photo, I just need to delete selected["6272861"]. But this will ignore the order, if I use an array to keep the selected photos: var selected = ["6272861", "6272888"]; then when I need to unselect a photo, I have to loop through the array and delete the item. Is there better ways? thanks.

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  • Action(Of T) in Visual Basic in List(Of T).ForEach

    - by Jason
    I have searched high and low for documentation on how to use this feature. While the loop I could write would be simple and take no time, I really would like to learn how to use this. Basically I have a class, say, Widget, with a Save() sub that returns nothing. So: Dim w as New Widget() w.Save() basically saves the widget. Now let's say I have a generic collection List(Of Widget) name widgetList(Of Widget) and I want to run a Save() on each item in that list. It says I can do a widgetList.ForEach([enter Action(Of T) here]) ....but how in the F does this work??? There is no documentation anywhere on the intrablags. Help would be much much appreciated.

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  • Object still linked (referenced) after selecting it out of list?

    - by djerry
    Hey guys, I was wondering, and i'm not really sure, but help me out here. If you have a List items, and there's one object you need to change a property of it. Say myClass has a string property "status". I'm searching my list with a for-loop and i get my object so i do myClass item = items[i]; if i want to change the "status" property, i do this for example : item.Status = "new status"; My question/issue is this: is "item" still linked to the list item, so that if i execute the line above, it will be changed in the list as well without having to set this : items[i] = item; Hope this is clear. Thanks in advance.

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  • Parallel.For(): Different results for simple addition

    - by TSS
    I'm just looking in to the new .NET 4.0 features. With that, I'm attempting a simple calculation using Parallel.For and a normal for(x;x;x) loop. However, I'm getting different results about 50% of the time (no code change). long sum = 0; Parallel.For(1, 10000, y => { sum += y; }); Console.WriteLine(sum.ToString()); sum = 0; for (int y = 1; y < 10000; y++) { sum += y; } Console.WriteLine(sum.ToString()); Surely I'm missing something simple or do not completely understand the concept. My guess is that the threads are trying to update "sum" at the same time. If so, is there an obvious way around it?

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  • functionality of cin in c++

    - by wyatt
    I'm a bit confused by the results of the following function: int main() { string command; while(1) { cin >> command; if(command == "end") return 0; else cout << "Could you repeat the command?" << endl; } return 0; } First of all - the output line ("could you...") repeats once for each individual word in the input (stored in command). So far as I can see, it should only be possible for it to happen once for each instance of the loop. Also, when the line 'if(command == "end")' is changed to 'if(command == "that's all")' it never triggers. A little testing suggested that all of the whitespace was removed from the command. Could someone explain to me what's going on here? Thanks

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  • Add a multiple buttons to a view programatically, call the same method, determine which button it wa

    - by just_another_coder
    I want to programatically add multiple UIButtons to a view - the number of buttons is unknown at compile time. I can make one or more UIButton's like so (in a loop, but shorted for simplicity): UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect]; [button addTarget:self action:@selector(buttonClicked:) forControlEvents:UIControlEventTouchDown]; [button setTitle:@"Button x" forState:UIControlStateNormal]; button.frame = CGRectMake(100.0, 100.0, 120.0, 50.0); [view addSubview:button]; Copied/Edited from this link: http://stackoverflow.com/questions/1378765/how-do-i-create-a-basic-uibutton-programmatically But how do I determine in buttonClicked: which button was clicked? I'd like to pass tag data if possible to identify the button.

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  • Simple C++ classes question

    - by Without me Its just Aweso
    Its been a long time since i've done C++ and I'm running into some trouble with classes referencing eachother. right now I have something like: a.h class a { public: a(); bool skeletonfunc(b temp); } ==================== b.h class b { public: b(); bool skeletonfunc(a temp); } since each one needs a reference to the other i've found I cant do a #include of eachother at the top or i end up in a weird loop of sorts with the includes. So how can I make it so that a can use b and vice versa with out making a cyclical #include problem. thanks!

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  • How to retrieve CSS style object by CSS class name?

    - by Chir
    Hi, Is it possible to get all properties of a css class associated with an element? e.g. .hightligh { font-weight: bold; border: 1px solid red; padding-top:10px; } Lets say the css class "hightlight" is assigned to div element <div class='highlight'></div> Now using JavaScript, I need to iterate through all style properties of css class "highlight" associated with the div element. Basically, I want to treat it as a JavaScript object whose properties can be accessed using iterator or for loop. Thanks in advance

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  • DOMDocument::load in PHP 5

    - by Abs
    Hello all, I open a 10MB+ XML file several times in my script in different functions: $dom = DOMDocument::load( $file ) or die('couldnt open'); 1) Is the above the old style of loading a document? I am using PHP 5. Oppening it statically? 2) Do I need to close the loading of the XML file, if possible? I suspect its causing memory problems because I loop through the nodes of the XML file several thousand times and sometimes my script just ends abruptly. Thanks all for any help

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  • Include upper bound in range()

    - by Jull
    How can I include the upper bound in range() function? I can't add by 1 because my for-loop looks like: for x in range(1,math.floor(math.sqrt(x))): y = math.sqrt(n - x * x) But as I understand it will actually be 1 < x < M where I need 1 < x <= M Adding 1 will completely change the result. I am trying to rewrite my old program from C# to Python. That's how it looked in C#: for (int x = 1; x <= Math.Floor(Math.Sqrt(n)); x++) double y = Math.Sqrt(n - x * x);

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  • trying to work through a list in sections

    - by user1714887
    I have a list of lists sorted by the second value of the list (the groups). I now need to iterate through this to work on each "group" at a time. the data is [name, group, data1, data2, data3, data4]. I wasn't sure if I need a while or some other sort of loop, or maybe groupby but I've never used that. any help would be appreciated. for i in range (int(max_group)): x1 = [] x2 = [] x3 = [] x4 = [] if data[i][1] == i+1: x1.append(data[2]) x2.append(data[3]) x3.append(data[4]) x4.append(data[5]) print x1 print 'next' # these are just to test where we're at

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  • So my girlfriend wants to learn to program [closed]

    - by vanstee
    Possible Duplicate: What programming language should be taught in Computer Science 101? My girlfriend hates feeling completely out of the loop when my friends and I talk about anything related to computers, so she asked me to teach her how to program. I'm pretty happy she asked, but I want to be able to teach her enough to know the basics without her completely losing interest or getting too frustrated. She is a very smart girl, probably smarter than me, but her computer related skills are pretty minimal. What language should I teach her and why?

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  • Add periods in a string [closed]

    - by Garling Beard
    I'm unable to determine why I don't get my expected output, given this code: int periods = (location.Length / 2) - 1; for (int index = 2, i = 0; i < periods; index += 3, ++i ) { location = location.Insert(index, "."); } And a location of "C5032AC", I expect that location will equal "C.50.32.A.C" after my loop terminates; it is instead "C5.03.2AC". Can anyone explain what I'm missing here?

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  • Convert Java program to C

    - by imicrothinking
    I need a bit of guidance with writing a C program...a bit of quick background as to my level, I've programmed in Java previously, but this is my first time programming in C, and we've been tasked to translate a word count program from Java to C that consists of the following: Read a file from memory Count the words in the file For each occurrence of a unique word, keep a word counter variable Print out the top ten most frequent words and their corresponding occurrences Here's the source program in Java: package lab0; import java.io.File; import java.io.FileReader; import java.util.ArrayList; import java.util.Calendar; import java.util.Collections; public class WordCount { private ArrayList<WordCountNode> outputlist = null; public WordCount(){ this.outputlist = new ArrayList<WordCountNode>(); } /** * Read the file into memory. * * @param filename name of the file. * @return content of the file. * @throws Exception if the file is too large or other file related exception. */ public char[] readFile(String filename) throws Exception{ char [] result = null; File file = new File(filename); long size = file.length(); if (size > Integer.MAX_VALUE){ throw new Exception("File is too large"); } result = new char[(int)size]; FileReader reader = new FileReader(file); int len, offset = 0, size2read = (int)size; while(size2read > 0){ len = reader.read(result, offset, size2read); if(len == -1) break; size2read -= len; offset += len; } return result; } /** * Make article word by word. * * @param article the content of file to be counted. * @return string contains only letters and "'". */ private enum SPLIT_STATE {IN_WORD, NOT_IN_WORD}; /** * Go through article, find all the words and add to output list * with their count. * * @param article the content of the file to be counted. * @return words in the file and their counts. */ public ArrayList<WordCountNode> countWords(char[] article){ SPLIT_STATE state = SPLIT_STATE.NOT_IN_WORD; if(null == article) return null; char curr_ltr; int curr_start = 0; for(int i = 0; i < article.length; i++){ curr_ltr = Character.toUpperCase( article[i]); if(state == SPLIT_STATE.IN_WORD){ article[i] = curr_ltr; if ((curr_ltr < 'A' || curr_ltr > 'Z') && curr_ltr != '\'') { article[i] = ' '; //printf("\nthe word is %s\n\n",curr_start); if(i - curr_start < 0){ System.out.println("i = " + i + " curr_start = " + curr_start); } addWord(new String(article, curr_start, i-curr_start)); state = SPLIT_STATE.NOT_IN_WORD; } }else{ if (curr_ltr >= 'A' && curr_ltr <= 'Z') { curr_start = i; article[i] = curr_ltr; state = SPLIT_STATE.IN_WORD; } } } return outputlist; } /** * Add the word to output list. */ public void addWord(String word){ int pos = dobsearch(word); if(pos >= outputlist.size()){ outputlist.add(new WordCountNode(1L, word)); }else{ WordCountNode tmp = outputlist.get(pos); if(tmp.getWord().compareTo(word) == 0){ tmp.setCount(tmp.getCount() + 1); }else{ outputlist.add(pos, new WordCountNode(1L, word)); } } } /** * Search the output list and return the position to put word. * @param word is the word to be put into output list. * @return position in the output list to insert the word. */ public int dobsearch(String word){ int cmp, high = outputlist.size(), low = -1, next; // Binary search the array to find the key while (high - low > 1) { next = (high + low) / 2; // all in upper case cmp = word.compareTo((outputlist.get(next)).getWord()); if (cmp == 0) return next; else if (cmp < 0) high = next; else low = next; } return high; } public static void main(String args[]){ // handle input if (args.length == 0){ System.out.println("USAGE: WordCount <filename> [Top # of results to display]\n"); System.exit(1); } String filename = args[0]; int dispnum; try{ dispnum = Integer.parseInt(args[1]); }catch(Exception e){ dispnum = 10; } long start_time = Calendar.getInstance().getTimeInMillis(); WordCount wordcount = new WordCount(); System.out.println("Wordcount: Running..."); // read file char[] input = null; try { input = wordcount.readFile(filename); } catch (Exception e) { // TODO Auto-generated catch block e.printStackTrace(); System.exit(1); } // count all word ArrayList<WordCountNode> result = wordcount.countWords(input); long end_time = Calendar.getInstance().getTimeInMillis(); System.out.println("wordcount: completed " + (end_time - start_time)/1000000 + "." + (end_time - start_time)%1000000 + "(s)"); System.out.println("wordsort: running ..."); start_time = Calendar.getInstance().getTimeInMillis(); Collections.sort(result); end_time = Calendar.getInstance().getTimeInMillis(); System.out.println("wordsort: completed " + (end_time - start_time)/1000000 + "." + (end_time - start_time)%1000000 + "(s)"); Collections.reverse(result); System.out.println("\nresults (TOP "+ dispnum +" from "+ result.size() +"):\n" ); // print out result String str ; for (int i = 0; i < result.size() && i < dispnum; i++){ if(result.get(i).getWord().length() > 15) str = result.get(i).getWord().substring(0, 14); else str = result.get(i).getWord(); System.out.println(str + " - " + result.get(i).getCount()); } } public class WordCountNode implements Comparable{ private String word; private long count; public WordCountNode(long count, String word){ this.count = count; this.word = word; } public String getWord() { return word; } public void setWord(String word) { this.word = word; } public long getCount() { return count; } public void setCount(long count) { this.count = count; } public int compareTo(Object arg0) { // TODO Auto-generated method stub WordCountNode obj = (WordCountNode)arg0; if( count - obj.getCount() < 0) return -1; else if( count - obj.getCount() == 0) return 0; else return 1; } } } Here's my attempt (so far) in C: #include <stdio.h> #include <stdlib.h> #include <stdbool.h> #include <string.h> // Read in a file FILE *readFile (char filename[]) { FILE *inputFile; inputFile = fopen (filename, "r"); if (inputFile == NULL) { printf ("File could not be opened.\n"); exit (EXIT_FAILURE); } return inputFile; } // Return number of words in an array int wordCount (FILE *filePointer, char filename[]) {//, char *words[]) { // count words int count = 0; char temp; while ((temp = getc(filePointer)) != EOF) { //printf ("%c", temp); if ((temp == ' ' || temp == '\n') && (temp != '\'')) count++; } count += 1; // counting method uses space AFTER last character in word - the last space // of the last character isn't counted - off by one error // close file fclose (filePointer); return count; } // Print out the frequencies of the 10 most frequent words in the console int main (int argc, char *argv[]) { /* Step 1: Read in file and check for errors */ FILE *filePointer; filePointer = readFile (argv[1]); /* Step 2: Do a word count to prep for array size */ int count = wordCount (filePointer, argv[1]); printf ("Number of words is: %i\n", count); /* Step 3: Create a 2D array to store words in the file */ // open file to reset marker to beginning of file filePointer = fopen (argv[1], "r"); // store words in character array (each element in array = consecutive word) char allWords[count][100]; // 100 is an arbitrary size - max length of word int i,j; char temp; for (i = 0; i < count; i++) { for (j = 0; j < 100; j++) { // labels are used with goto statements, not loops in C temp = getc(filePointer); if ((temp == ' ' || temp == '\n' || temp == EOF) && (temp != '\'') ) { allWords[i][j] = '\0'; break; } else { allWords[i][j] = temp; } printf ("%c", allWords[i][j]); } printf ("\n"); } // close file fclose (filePointer); /* Step 4: Use a simple selection sort algorithm to sort 2D char array */ // PStep 1: Compare two char arrays, and if // (a) c1 > c2, return 2 // (b) c1 == c2, return 1 // (c) c1 < c2, return 0 qsort(allWords, count, sizeof(char[][]), pstrcmp); /* int k = 0, l = 0, m = 0; char currentMax, comparedElement; int max; // the largest element in the current 2D array int elementToSort = 0; // elementToSort determines the element to swap with starting from the left // Outer a iterates through number of swaps needed for (k = 0; k < count - 1; k++) { // times of swaps max = k; // max element set to k // Inner b iterates through successive elements to fish out the largest element for (m = k + 1; m < count - k; m++) { currentMax = allWords[k][l]; comparedElement = allWords[m][l]; // Inner c iterates through successive chars to set the max vars to the largest for (l = 0; (currentMax != '\0' || comparedElement != '\0'); l++) { if (currentMax > comparedElement) break; else if (currentMax < comparedElement) { max = m; currentMax = allWords[m][l]; break; } else if (currentMax == comparedElement) continue; } } // After max (count and string) is determined, perform swap with temp variable char swapTemp[1][20]; int y = 0; do { swapTemp[0][y] = allWords[elementToSort][y]; allWords[elementToSort][y] = allWords[max][y]; allWords[max][y] = swapTemp[0][y]; } while (swapTemp[0][y++] != '\0'); elementToSort++; } */ int a, b; for (a = 0; a < count; a++) { for (b = 0; (temp = allWords[a][b]) != '\0'; b++) { printf ("%c", temp); } printf ("\n"); } // Copy rows to different array and print results /* char arrayCopy [count][20]; int ac, ad; char tempa; for (ac = 0; ac < count; ac++) { for (ad = 0; (tempa = allWords[ac][ad]) != '\0'; ad++) { arrayCopy[ac][ad] = tempa; printf("%c", arrayCopy[ac][ad]); } printf("\n"); } */ /* Step 5: Create two additional arrays: (a) One in which each element contains unique words from char array (b) One which holds the count for the corresponding word in the other array */ /* Step 6: Sort the count array in decreasing order, and print the corresponding array element as well as word count in the console */ return 0; } // Perform housekeeping tasks like freeing up memory and closing file I'm really stuck on the selection sort algorithm. I'm currently using 2D arrays to represent strings, and that worked out fine, but when it came to sorting, using three level nested loops didn't seem to work, I tried to use qsort instead, but I don't fully understand that function as well. Constructive feedback and criticism greatly welcome (...and needed)!

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  • Adobe Photoshop Vs Lightroom Vs Aperture

    - by Aditi
    Adobe Photoshop is the standard choice for photographers, graphic artists and Web designers. Adobe Photoshop Lightroom  & Apple’s Aperture are also in the same league but the usage is vastly different. Although Photoshop is most popular & widely used by photographers, but in many ways it’s less relevant to photographers than ever before. As Lightroom & Aperture is aimed squarely at photographers for photo-processing. With this write up we are going to help you choose what is right for you and why. Adobe Photoshop Adobe Photoshop is the most liked tool for the detailed photo editing & designing work. Photoshop provides great features for rollover and Image slicing. Adobe Photoshop includes comprehensive optimization features for producing the highest quality Web graphics with the smallest possible file sizes. You can also create startling animations with it. Designers & Editors know how important precise masking is, PhotoShop lets you do that with various detailing tools. Art history brush, contact sheets, and history palette are some of the smart features, which add to its viability. Download Whether you’re producing printed pages or moving images, you can work more efficiently and produce better results because of its smooth integration across other adobe applications. Buy supporting layer effects, it allows you to quickly add drop shadows, inner and outer glows, bevels, and embossing to layers. It also provides Seamless Web Graphics Workflow. Photoshop is hands-down the BEST for editing. Photoshop Cons: • Slower, less precise editing features in Bridge • Processing lots of images requires actions and can be slower than exporting images from Lightroom • Much slower with editing and processing a large number of images Aperture Apple Aperture is aimed at the professional photographer who shoots predominantly raw files. It helps them to manage their workflow and perform their initial Raw conversion in a better way. Aperture provides adjustment tools such as Histogram to modify color and white balance, but most of the editing of photos is left for Photoshop. It gives users the option of seeing their photographs laid out like slides or negatives on a light table. It boasts of – stars, color-coding and easy techniques for filtering and picking images. Aperture has moved forward few steps than Photoshop, but most of the editing work has been left for Photoshop as it features seamless Photoshop integration. Aperture Pros: Aperture is a step up from the iPhoto software that comes with every Mac, and fairly easy to learn. Adjustments are made in a logical order from top to bottom of the menu. You can store the images in a library or any folder you choose. Aperture also works really well with direct Canon files. It is just $79 if you buy it through Apple’s App Store Moving forward, it will run on the iPad, and possibly the iPhone – Adobe products like Lightroom and Photoshop may never offer these options It is much nicer and simpler user interface. Lightroom Lightroom does a smashing job of basic fixing and editing. It is more advanced tool for photographers. They can use it to have a startling photography effect. Light room has many advanced features, which makes it one of the best tools for photographers and far ahead of the other two. They are Nondestructive editing. Nothing is actually changed in an image until the photo is exported. Better controls over organizing your photos. Lightroom helps to gather a group of photos to use in a slideshow. Lightroom has larger Compare and Survey views of images. Quickly customizable interface. Simple keystrokes allow you to perform different All Lightroom controls are kept available in panels right next to the photos. Always-available History palette, it doesn’t go when you close lightroom. You gain more colors to work with compared to Photoshop and with more precise control. Local control, or adjusting small parts of a photo without affecting anything else, has long been an important part of photography. In Lightroom 2, you can darken, lighten, and affect color and change sharpness and other aspects of specific areas in the photo simply by brushing your cursor across the areas. Photoshop has far more power in its Cloning and Healing Brush tools than Lightroom, but Lightroom offers simple cloning and healing that’s nondestructive. Lightroom supports the RAW formats of more cameras than Aperture. Lightroom provides the option of storing images outside the application in the file system. It costs less than photoshop. Download Why PhotoShop is advanced than Lightroom? There are countless image processing plug-ins on the market for doing specialized processing in Photoshop. For example, if your image needs sophisticated noise reduction, you can use the Noiseware plug-in with Photoshop to do a much better job or noise removal than Lightroom can do. Lightroom’s advantages over Aperture 3 Will always have better integration with Photoshop. Lightroom is backed by bigger and more active user community (So abundant availability for tutorials, etc.) Better noise reduction tool. Especially for photographers the Lens-distortion correction tool  is perfect Lightroom Cons: • Have to Import images to work on them • Slows down with over 10,000 images in the catalog • For processing just one or two images this is a slower workflow Photoshop Pros: • ACR has the same RAW processing controls as Lightroom • ACR Histogram is specialized to the chosen color space (Lightroom is locked into ProPhoto RGB color space with an sRGB tone curve) • Don’t have to Import images to open in Bridge or ACR • Ability to customize processing of RAW images with Photoshop Actions Pricing and Availability Get LightRoomGet PhotoShop Latest version Of Photoshop can be purchased from Adobe store and Adobe authorized reseller and it costs US$999. Latest version of Aperture can be bought for US$199 from Apple Online store or Mac App Store. You can buy latest version of LightRoom from Adobe Store or Adobe Authorized reseller for US$299. Related posts:Adobe Photoshop CS5 vs Photoshop CS5 extended Web based Alternatives to Photoshop 10 Free Alternatives for Adobe Photoshop Software

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  • Ternary operator in VB.NET

    - by Jalpesh P. Vadgama
    We all know about Ternary operator in C#.NET. I am a big fan of ternary operator and I like to use it instead of using IF..Else. Those who don’t know about ternary operator please go through below link. http://msdn.microsoft.com/en-us/library/ty67wk28(v=vs.80).aspx Here you can see ternary operator returns one of the two values based on the condition. See following example. bool value = false;string output=string.Empty;//using If conditionif (value==true) output ="True";else output="False";//using tenary operatoroutput = value == true ? "True" : "False"; In the above example you can see how we produce same output with the ternary operator without using If..Else statement. Recently in one of the project I was working with VB.NET language and I was eager to know if there is a ternary operator equivalent there or not. After searching on internet I have found two ways to do it. IF operator which works for VB.NET 2008 and higher version and IIF operator which is there since VB 6.0. So let’s check same above example with both of this operators. So let’s create a console application which has following code. Module Module1 Sub Main() Dim value As Boolean = False Dim output As String = String.Empty ''Output using if else statement If value = True Then output = "True" Else output = "False" Console.WriteLine("Output Using If Loop") Console.WriteLine(output) output = If(value = True, "True", "False") Console.WriteLine("Output using If operator") Console.WriteLine(output) output = IIf(value = True, "True", "False") Console.WriteLine("Output using IIF Operator") Console.WriteLine(output) Console.ReadKey() End If End SubEnd Module As you can see in the above code I have written all three-way to condition check using If.Else statement and If operator and IIf operator. You can see that both IIF and If operator has three parameter first parameter is the condition which you need to check and then another parameter is true part of you need to put thing which you need as output when condition is ‘true’. Same way third parameter is for the false part where you need to put things which you need as output when condition as ‘false’. Now let’s run that application and following is the output as expected. That’s it. You can see all three ways are producing same output. Hope you like it. Stay tuned for more..Till then Happy Programming.

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  • Dynamic Unpivot : SSIS Nugget

    - by jamiet
    A question on the SSIS forum earlier today asked: I need to dynamically unpivot some set of columns in my source file. Every month there is one new column and its set of Values. I want to unpivot it without editing my SSIS packages that is deployed Let’s be clear about what we mean by Unpivot. It is a normalisation technique that basically converts columns into rows. By way of example it converts something like this: AccountCode Jan Feb Mar AC1 100.00 150.00 125.00 AC2 45.00 75.50 90.00 into something like this: AccountCode Month Amount AC1 Jan 100.00 AC1 Feb 150.00 AC1 Mar 125.00 AC2 Jan 45.00 AC2 Feb 75.50 AC2 Mar 90.00 The Unpivot transformation in SSIS is perfectly capable of carrying out the operation defined in this example however in the case outlined in the aforementioned forum thread the problem was a little bit different. I interpreted it to mean that the number of columns could change and in that scenario the Unpivot transformation (and indeed the SSIS dataflow in general) is rendered useless because it expects that the number of columns will not change from what is specified at design-time. There is a workaround however. Assuming all of the columns that CAN exist will appear at the end of the rows, we can (1) import all of the columns in the file as just a single column, (2) use a script component to loop over all the values in that “column” and (3) output each one as a column all of its own. Let’s go over that in a bit more detail.   I’ve prepared a data file that shows some data that we want to unpivot which shows some customers and their mythical shopping lists (it has column names in the first row): We use a Flat File Connection Manager to specify the format of our data file to SSIS: and a Flat File Source Adapter to put it into the dataflow (no need a for a screenshot of that one – its very basic). Notice that the values that we want to unpivot all exist in a column called [Groceries]. Now onto the script component where the real work goes on, although the code is pretty simple: Here I show a screenshot of this executing along with some data viewers. As you can see we have successfully pulled out all of the values into a row all of their own thus accomplishing the Dynamic Unpivot that the forum poster was after. If you want to run the demo for yourself then I have uploaded the demo package and source file up to my SkyDrive: http://cid-550f681dad532637.skydrive.live.com/self.aspx/Public/BlogShare/20100529/Dynamic%20Unpivot.zip Simply extract the two files into a folder, make sure the Connection Manager is pointing to the file, and execute! Hope this is useful. @Jamiet Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

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  • Oracle UCM GET_SEARCH_RESULTS service with full text search

    - by Lyudmil Pelov
    Newly I was working on portlet which should be able to do full text search through the UCM documents and I was experimenting with the Ridc and also with the CIS API's. There are some ticks you may take care of, for example using quotes is a very spacial case and most of situations UCM will throw an exception if you not use them well. So during my tests I was able to develop one solution which works very well for me doing full text search and here is it: final IdcClientManager idcManager = new IdcClientManager(); final IdcClient idcClient = idcManager.createClient("idc://127.0.0.1:4444"); final IdcContext idcContext = new IdcContext("sysadmin"); final DataBinder binder = idcClient.createBinder(); // populate the binder with the parameters binder.putLocal ("IdcService", "GET_SEARCH_RESULTS"); binder.putLocal ("QueryText", "dDocFullText <substring> <qsch>"+yourSearchWordOrWords+"</qsch>");  binder.putLocal ("SearchEngineName", "databasefulltext"); binder.putLocal ("ResultCount", "20"); // execute the request ServiceResponse response = idcClient.sendRequest (idcContext, binder); // get the binder DataBinder serverBinder = response.getResponseAsBinder (); DataResultSet resultSet = serverBinder.getResultSet ("SearchResults"); // loop over the results for (DataObject dataObject : resultSet.getRows ()) { System.out.println ("Title is: " + dataObject.get ("dDocTitle")); System.out.println ("Author is: " + dataObject.get ("dDocAuthor")); }Nothing special so far except the line which declares the full text search. To be able to proceed with the full text search you have to use dDocFullText attribute inside the search query. The tag <substring> is the same as 'like'. Also you have to put your searching string or words in quotes which could be a problem sometime, so I used the tag <qsch>. Using this tag you can have quotes now inside you searching string without to break the code and get parsing exceptions.To be able to test the example, you do have to enable full text search inside UCM. To do this follow the steps for example from this blog here and then re-index the documents in UCM.There is also one very nice article about how to define UCM queries if want to replace the full text search with something more specific, you can read this article from Kyle's Blog here.

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