Search Results

Search found 84599 results on 3384 pages for 'java util set'.

Page 304/3384 | < Previous Page | 300 301 302 303 304 305 306 307 308 309 310 311  | Next Page >

  • JAVA: Build XML document using XPath expressions

    - by snoe
    I know this isn't really what XPath is for but if I have a HashMap of XPath expressions to values how would I go about building an XML document. I've found dom-4j's DocumentHelper.makeElement(branch, xpath) except it is incapable of creating attributes or indexing. Surely a library exists that can do this? Map xMap = new HashMap(); xMap.put("root/entity/@att", "fooattrib"); xMap.put("root/array[0]/ele/@att", "barattrib"); xMap.put("root/array[0]/ele", "barelement"); xMap.put("root/array[1]/ele", "zoobelement"); would result in: <root> <entity att="fooattrib"/> <array><ele att="barattrib">barelement</ele></array> <array><ele>zoobelement</ele></array> </root>

    Read the article

  • Android/Java Append String + int

    - by xger86x
    Hi, i have a question, what is the best way to append ints and Strings to build a new String? In the allocation debug tool i see too much allocations if i use the operator +. But i have tried also with StringBuffer and there are still too much allocations. Anyone can help me? Thanks

    Read the article

  • create a sparse BufferedImage in java

    - by elgcom
    I have to create an image with very large resolution, but the image is relatively "sparse", only some areas in the image need to draw. For example with following code /* this take 5GB memory */ final BufferedImage img = new BufferedImage( 36000, 36000, BufferedImage.TYPE_INT_ARGB); /* draw something */ Graphics g = img.getGraphics(); g.drawImage(....); /* output as PNG */ final File out = new File("out.png"); ImageIO.write(img, "png", out); The PNG image on the end I created is ONLY about 200~300 MB. The question is how can I avoid creating a 5GB BufferedImage at the beginning? I do need an image with large dimension, but with very sparse color information. Is there any Stream for BufferedImage so that it will not take so much memory?

    Read the article

  • Java logger that automatically determines caller's class name

    - by alex
    public static Logger getLogger() { final Throwable t = new Throwable(); final StackTraceElement methodCaller = t.getStackTrace()[1]; final Logger logger = Logger.getLogger(methodCaller.getClassName()); logger.setLevel(ResourceManager.LOGLEVEL); return logger; } This method would return a logger that knows the class it's logging for. Any ideas against it?

    Read the article

  • java applet communication port

    - by udhaya
    Communication ports: Change a given class in an applet in that way, that browser-defined proxy-configuration files can be used for applet communication with serve(upload method). i.e browser communicate via port 8080 or via ssl(443) - applet should also communicate by this port automatically. In the given method port 80 is hardcoded. -- please give some code or program for this..

    Read the article

  • How to disable log4j logging from Java code

    - by Erel Segal Halevi
    I use a legacy library that writes logs using log4j. My default log4j.properties file directs the log to the console, but in some specific functions of my main program, I would like to disable logging altogether (from all classes). I tried this: Logger.getLogger(BasicImplementation.class.getName()).setLevel(Level.OFF); where "BasicImplementation" is one of the main classes that does logging, but it didn't work - the logs are still written to the console. Here is my log4j.properties: log4j.rootLogger=warn, stdout log4j.logger.ac.biu.nlp.nlp.engineml=info, logfile log4j.logger.org.BIU.utils.logging.ExperimentLogger=warn log4j.appender.stdout = org.apache.log4j.ConsoleAppender log4j.appender.stdout.layout = org.apache.log4j.PatternLayout log4j.appender.stdout.layout.ConversionPattern = %-5p %d{HH:mm:ss} [%t]: %m%n log4j.appender.logfile = ac.biu.nlp.nlp.log.BackupOlderFileAppender log4j.appender.logfile.append=false log4j.appender.logfile.layout = org.apache.log4j.PatternLayout log4j.appender.logfile.layout.ConversionPattern = %-5p %d{HH:mm:ss} [%t]: %m%n log4j.appender.logfile.File = logfile.log

    Read the article

  • PreparedStatement question in Java against Oracle.

    - by fardon57
    Hi everyone, I'm working on the modification of some code to use preparedStatement instead of normal Statement, for security and performance reason. Our application is currently storing information into an embedded derby database, but we are going to move soon to Oracle. I've found two things that I need your help guys about Oracle and Prepared Statement : 1- I've found this document saying that Oracle doesn't handle bind parameters into IN clauses, so we cannot supply a query like : Select pokemon from pokemonTable where capacity in (?,?,?,?) Is that true ? Is there any workaround ? ... Why ? 2- We have some fields which are of type TIMESTAMP. So with our actual Statement, the query looks like this : Select raichu from pokemonTable where evolution = TO_TIMESTAMP('2500-12-31 00:00:00.000', 'YYYY-MM-DD HH24:MI:SS.FF') What should be done for a prepared Statement ? Should I put into the array of parameters : 2500-12-31 or TO_TIMESTAMP('2500-12-31 00:00:00.000', 'YYYY-MM-DD HH24:MI:SS.FF') ? Thanks for your help, I hope my questions are clear ! Regards,

    Read the article

  • Download file using java apache commons?

    - by Kyle
    How can I use the library to download a file and print out bytes saved? I tried using import static org.apache.commons.io.FileUtils.copyURLToFile; public static void Download() { URL dl = null; File fl = null; try { fl = new File(System.getProperty("user.home").replace("\\", "/") + "/Desktop/Screenshots.zip"); dl = new URL("http://ds-forums.com/kyle-tests/uploads/Screenshots.zip"); copyURLToFile(dl, fl); } catch (Exception e) { System.out.println(e); } } but I cannot display bytes or a progress bar. Which method should I use?

    Read the article

  • Sending files from server to client in Java

    - by Lee Jacobson
    Hi, I'm trying to find a way to send files of different file types from a server to a client. I have this code on the server to put the file into a byte array: File file = new File(resourceLocation); byte[] b = new byte[(int) file.length()]; FileInputStream fileInputStream; try { fileInputStream = new FileInputStream(file); try { fileInputStream.read(b); } catch (IOException ex) { System.out.println("Error, Can't read from file"); } for (int i = 0; i < b.length; i++) { fileData += (char)b[i]; } } catch (FileNotFoundException e) { System.out.println("Error, File Not Found."); } I then send fileData as a string to the client. This works fine for txt files but when it comes to images I find that although it creates the file fine with the data in, the image won't open. I'm not sure if I'm even going about this the right way. Thanks for the help.

    Read the article

  • java servlet:response.sendRedirect() not giving illegal state exception if called after commit of re

    - by sahil garg
    after commit of response as here redirect statement should give exception but it is not doing so if this redirect statemnet is in if block.but it does give exception in case it is out of if block.i have shown same statement(with marked stars ) at two places below.can u please tell me reason for it. protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub synchronized (noOfRequests) { noOfRequests++; } PrintWriter pw=null; response.setContentType("text/html"); response.setHeader("foo","bar"); //response is commited because of above statement pw=response.getWriter(); pw.print("hello : "+noOfRequests); //if i remove below statement this same statement is present in if block.so statement in if block should also give exception as this one do, but its not doing so.why? ***response.sendRedirect("http://localhost:8625/ServletPrc/login% 20page.html"); if(true) { //same statement as above ***response.sendRedirect("http://localhost:8625/ServletPrc/login%20page.html"); } else{ request.setAttribute("noOfReq", noOfRequests); request.setAttribute("name", new Name().getName()); request.setAttribute("GmailId",this.getServletConfig().getInitParameter("GmailId") ); request.setAttribute("YahooId",this.getServletConfig().getInitParameter("YahooId") ); RequestDispatcher view1=request.getRequestDispatcher("HomePage.jsp"); view1.forward(request, response); } }

    Read the article

  • Java xsd validation of xml without namespace

    - by Darkflare
    Hi, I want to validate an xml file against an xsd schema. The xml files root element does not have any namespace or xsi details. It has no attributes so just . I have tried the following code from http://www.ibm.com/developerworks/xml/library/x-javaxmlvalidapi.html with no luck as I receive cvc-elt.1: Cannot find the declaration of element 'root' SchemaFactory factory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema"); File schemaFile = new File("schema.xsd"); Schema xsdScheme = factory.newSchema(schemaFile); Validator validator = xsdScheme.newValidator(); Source source = new StreamSource(xmlfile); validator.validate(source); The xml validates fine with the namespace headers included etc (added via xmlspy), but I would have thought the xml namespace could be declared without having to manually edit the source file?

    Read the article

  • JAVA Inheritance Generics and Casting.

    - by James Moore
    Hello, I have two classes which both extends Example. public class ClassA extends Example { public ClassA() { super("a", "class"); } .... } public class ClassB extends Example { public ClassB() { super("b", "class"); } .... } public class Example () { public String get(String x, String y) { return "Hello"; } } So thats all very well. So suppose we have another class called ExampleManager. With example manager I want to use a generic type and consequently return that generic type. e.g. public class ExampleManager<T extends Example> { public T getExample() { return new T("example","example"); // So what exactly goes here? } } So where I am returning my generic type how do i get this to actually work correctly and cast Example as either classA or classB? Many Thanks

    Read the article

  • Searching a 2D array for a range of values in java

    - by Paige O
    I have a 2^n size int array and I want to check if an element exists that is greater than 0. If the element exists, I want to divide the array by 4 and check if the coordinates of the found element are in the 1st, 2nd, 3rd or 4th quadrant of the array. For example, logically if the element exists in the first quadrant it would look something like this: If array[][] 0 && the row of that coordinate is in the range 0-(grid.length/2-1) && the column of that coordinate is in the range 0-(grid.length/2-1) then do something. I'm really not sure how to check the row and column index of the found element and store those coordinates to use in my if statement. Help!

    Read the article

  • How to add deploy.jar to classpath?

    - by dma_k
    I am facing the problem: I need to add ${java.home}/lib/deploy.jar JAR file to classpath in the runtime (dynamically from java). The solution with Thread#setContextClassLoader(ClassLoader) (mentioned here) does not work because of this bug (if somebody can explain what is really a problem – you are welcome). The solution with -Xbootclasspath/a:"%JAVA_HOME%/jre/lib/deploy.jar" does not work well for me, because I want to have "pure executable jar" as a deliverable: no wrapping scripts please (more over %JAVA_HOME% may not be defined in user's environment in Windows for example, plus I need to write a script per platform) The solution with merging deploy.jar file into my deliverable works only if I make a build on Windows platform. Unfortunately, when the deliverable is produced on build server running on Linux, I got Linux-dependant JAR, which does not execute on Windows – it fails with the trace below. I have read How the Java Launcher Finds Classes and Java programming dynamics: Java classes and class loading articles but I've got no extra ideas, how to correctly handle this situation. Any advices or solutions are very welcomed. Trace: java.lang.NoClassDefFoundError: Could not initialize class com.sun.deploy.config.Config at com.sun.deploy.net.proxy.UserDefinedProxyConfig.getBrowserProxyInfo(UserDefinedProxyConfig.java:43) at com.sun.deploy.net.proxy.DynamicProxyManager.reset(DynamicProxyManager.java:235) at com.sun.deploy.net.proxy.DeployProxySelector.reset(DeployProxySelector.java:59) ... java.lang.NullPointerException at com.sun.deploy.net.proxy.DynamicProxyManager.getProxyList(DynamicProxyManager.java:63) at com.sun.deploy.net.proxy.DeployProxySelector.select(DeployProxySelector.java:166)

    Read the article

  • Java regex replace multiple file paths in a large String

    - by Joe Goble
    So a Regex pro I am not, and I'm looking for a good way to do this. I have a large string which contains a variable number <img> tags. I need to change the path on all of these images to images/. The large string also contains other stuff not just these img's. <img src='http://server.com/stuff1/img1.jpg' /> <img src='http://server.com/stuff2/img2.png' /> Replacing the server name with a ReplaceAll() I could do, it's the variable path in the middle I'm clueless on how to include. It doesn't necessarily need to be a regex, but looping through the entire string just seems wasteful.

    Read the article

  • Java Refreshing a screen

    - by Goutham
    I have a screen in which one of its components is made invisible depending on a boolean value. If the boolean changes after the screen has been created, how do I refresh the screen to take this into account?

    Read the article

< Previous Page | 300 301 302 303 304 305 306 307 308 309 310 311  | Next Page >