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• Wheel rotation, to change velocity of vehicle

  - by Lewis

  I update the velocity of my vehicle like so: [v setVelocity: ((2 * 3.14 * 100 * (wheel.getRotationValue / 360) / 30)) * gameSpeed]; // update on 60 fps this gets velocity on all frames divide by 60 for 1 frame. This is done in my update method in my world class. Now wheel.getRotationValue returns the rotation value which is worked out like this: - (void)ccTouchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { UITouch *touch = [touches anyObject]; CGPoint location = [touch locationInView:[touch view]]; location = [[CCDirector sharedDirector] convertToGL:location]; if (CGRectContainsPoint(wheel.boundingBox, location)) { CGPoint firstLocation = [touch previousLocationInView:[touch view]]; CGPoint location = [touch locationInView:[touch view]]; CGPoint touchingPoint = [[CCDirector sharedDirector] convertToGL:location]; CGPoint firstTouchingPoint = [[CCDirector sharedDirector] convertToGL:firstLocation]; CGPoint firstVector = ccpSub(firstTouchingPoint, wheel.position); CGFloat firstRotateAngle = -ccpToAngle(firstVector); CGFloat previousTouch = CC_RADIANS_TO_DEGREES(firstRotateAngle); CGPoint vector = ccpSub(touchingPoint, wheel.position); CGFloat rotateAngle = -ccpToAngle(vector); CGFloat currentTouch = CC_RADIANS_TO_DEGREES(rotateAngle); float limit = 0.5; rotationValue += (currentTouch - previousTouch) * limit; } touching = YES; } Say I steer the vehicle to the far right of the screen, and want to move it to the far left, It wont start moving to the left of the screen until the rotationValue is past 0 degrees again (the wheel is in its center posistion) and is dragged past this value. Is there anyway to change the code I have above, so that movement on the wheel is recognised instantly and updates the velocity of v instantly too?

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• Easy way to access cookies in Chrome

  - by macek

  To view specific cookies in Chrome, currently I have to: Go to preferences Click Under the Hood tab Click Content Settings... button Click Cookies tab (if it's not already active) Click Show cookies and other site data... button If I want to narrow this down to a specific domain, I have to type it in, too. Compare this to Firefox: View Page Info Click Security tab Click View Cookies The domain for the page I'm currently on is already used as a filter, too. My question: Is there an easier way in Chrome? I've done some searching for an extension but have come up with nothing.

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• What is the best way to render a 2d game map?

  - by Deukalion

  I know efficiency is key in game programming and I've had some experiences with rendering a "map" earlier but probably not in the best of ways. For a 2D TopDown game: (simply render the textures/tiles of the world, nothing else) Say, you have a map of 1000x1000 (tiles or whatever). If the tile isn't in the view of the camera, it shouldn't be rendered - it's that simple. No need to render a tile that won't be seen. But since you have 1000x1000 objects in your map, or perhaps less you probably don't want to loop through all 1000*1000 tiles just to see if they're suppose to be rendered or not. Question: What is the best way to implement this efficiency? So that it "quickly/quicker" can determine what tiles are suppose to be rendered? Also, I'm not building my game around tiles rendered with a SpriteBatch so there's no rectangles, the shapes can be different sizes and have multiple points, say a curved object of 10 points and a texture inside that shape; Question: How do you determine if this kind of objects is "inside" the View of the camera? It's easy with a 48x48 rectangle, just see if it X+Width or Y+Height is in the view of the camera. Different with multiple points. Simply put, how to manage the code and the data efficiently to not having to run through/loop through a million of objects at the same time.

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• How to determine the end of list has been reached?

  - by Sweta Dwivedi

  I'm trying to animate my object according to a set of recorded values from kinect skeleton stream by saving the (x,y,z) stream from the skeletal data into a list and then set my objects x and y position from the x,y of the list. However, once the list end has been reached it starts to animate again from the start. I don't want that - I just want the model position to keep going in the positive X direction. Is there any way I can check if end of the list has been reached and to just update the model position in x direction? Or is there any other way to continue moving my sprite once the points in the list are over... i dont want it to start animating all the way again.. protected override void Update(GameTime gameTime) { //position += spriteSpeed * (float)gameTime.ElapsedGameTime.TotalSeconds; //// TODO: Add your update logic here using (StreamReader r = new StreamReader(f)) { string line; Viewport view = graphics.GraphicsDevice.Viewport; int maxWidth = view.Width; int maxHeight = view.Height; while((line = r.ReadLine()) != null) { string[] temp = line.Split(','); int x = (int) Math.Floor(((float.Parse(temp[0]) * 0.5f) + 0.5f) * maxWidth); int y = (int) Math.Floor(((float.Parse(temp[1]) * -0.5f) + 0.5f) * maxHeight); motion_2.Add(new Point(x, y)); } } position.X = motion_2[i].X; position.Y = motion_2[i].Y; i++; a_butterfly_up.Update(gameTime); a_butterfly_side.Update(gameTime); G_vidPlayer.Play(mossV); base.Update(gameTime); }

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• C#4: Why does this static field always get initialized over-eagerly?

  - by TheSilverBullet

  I am looking at this excellent article from Jon Skeet at this location: http://csharpindepth.com/Articles/General/Beforefieldinit.aspx While executing the demo code, Jon Skeet says that we can expect three different kinds of behaviours. To quote that article: The runtime could decide to run the type initializer on loading the assembly to start with... Or perhaps it will run it when the static method is first run... Or even wait until the field is first accessed... When I try this out (on framework 4), I always get the first result. That is, the static method is initialized before the assembly is loaded. I have tried running this multiple times and get the same result. (I tried both the debug and release versions) Why is this so? Am I missing something?

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• XNA, how to draw two cubes standing in line parallelly?

  - by user3535716

  I just got a problem with drawing two 3D cubes standing in line. In my code, I made a cube class, and in the game1 class, I built two cubes, A on the right side, B on the left side. I also setup an FPS camera in the 3D world. The problem is if I draw cube B first(Blue), and move the camera to the left side to cube B, A(Red) is still standing in front of B, which is apparently wrong. I guess some pics can make much sense. Then, I move the camera to the other side, the situation is like: This is wrong.... From this view, the red cube, A should be behind the blue one, B.... Could somebody give me help please? This is the draw in the Cube class Matrix center = Matrix.CreateTranslation( new Vector3(-0.5f, -0.5f, -0.5f)); Matrix scale = Matrix.CreateScale(0.5f); Matrix translate = Matrix.CreateTranslation(location); effect.World = center * scale * translate; effect.View = camera.View; effect.Projection = camera.Projection; foreach (EffectPass pass in effect.CurrentTechnique.Passes) { pass.Apply(); device.SetVertexBuffer(cubeBuffer); RasterizerState rs = new RasterizerState(); rs.CullMode = CullMode.None; rs.FillMode = FillMode.Solid; device.RasterizerState = rs; device.DrawPrimitives( PrimitiveType.TriangleList, 0, cubeBuffer.VertexCount / 3); } This is the Draw method in game1 A.Draw(camera, effect); B.Draw(camera, effect); **

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• Windows XP self-installing virus [closed]

  - by Oliver

  Do you remember. Some years ago, there was a huge virus attacking Windows XP in its first version. Once you had installed Windows XP, and on your first internet access, the virus installed itself on your computer, closing your internet connection and making the computer reboot after some seconds. I wonder... How can a virus install itslef this way from nowhere ? Without any user action. You install Windows XP... the computer just connects itself to the internet (assuming Microsoft don't connect to bad sites on its first connection)... and you have a virus. There is something magic I don't understand here. Can someone explain me how that virus could attack Windows that way, without any user action on a fresh installed system...

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• Use MvcContrib Grid to Display a Grid of Data in ASP.NET MVC

  The past six articles in this series have looked at how to display a grid of data in an ASP.NET MVC application and how to implement features like sorting, paging, and filtering. In each of these past six tutorials we were responsible for generating the rendered markup for the grid. Our Views included the <table> tags, the <th> elements for the header row, and a foreach loop that emitted a series of <td> elements for each row to display in the grid. While this approach certainly works, it does lead to a bit of repetition and inflates the size of our Views. The ASP.NET MVC framework includes an HtmlHelper class that adds support for rendering HTML elements in a View. An instance of this class is available through the Html object, and is often used in a View to create action links (Html.ActionLink), textboxes (Html.TextBoxFor), and other HTML content. Such content could certainly be created by writing the markup by hand in the View; however, the HtmlHelper makes things easier by offering methods that emit common markup patterns. You can even create your own custom HTML Helpers by adding extension methods to the HtmlHelper class. MvcContrib is a popular, open source project that adds various functionality to the ASP.NET MVC framework. This includes a very versatile Grid HTML Helper that provides a strongly-typed way to construct a grid in your Views. Using MvcContrib's Grid HTML Helper you can ditch the <table>, <tr>, and <td> markup, and instead use syntax like Html.Grid(...). This article looks at using the MvcContrib Grid to display a grid of data in an ASP.NET MVC application. A future installment will show how to configure the MvcContrib Grid to support both sorting and paging. Read on to learn more! Read More >

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• Easy way to access cookies in Chrome

  - by macek

  To view specific cookies in Chrome, currently I have to: Go to preferences Click Under the Hood tab Click Content Settings... button Click Cookies tab (if it's not already active) Click Show cookies and other site data... button If I want to narrow this down to a specific domain, I have to type it in, too. Compare this to Firefox: View Page Info Click Security tab Click View Cookies The domain for the page I'm currently on is already used as a filter, too. My question: Is there an easier way in Chrome? I've done some searching for an extension but have come up with nothing. Any help is appreciated :)

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• Rotating wheel with touch adding velocity

  - by Lewis

  I have a wheel control in a game which is setup like so: - (void)ccTouchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { UITouch *touch = [touches anyObject]; CGPoint location = [touch locationInView:[touch view]]; location = [[CCDirector sharedDirector] convertToGL:location]; if (CGRectContainsPoint(wheel.boundingBox, location)) { CGPoint firstLocation = [touch previousLocationInView:[touch view]]; CGPoint location = [touch locationInView:[touch view]]; CGPoint touchingPoint = [[CCDirector sharedDirector] convertToGL:location]; CGPoint firstTouchingPoint = [[CCDirector sharedDirector] convertToGL:firstLocation]; CGPoint firstVector = ccpSub(firstTouchingPoint, wheel.position); CGFloat firstRotateAngle = -ccpToAngle(firstVector); CGFloat previousTouch = CC_RADIANS_TO_DEGREES(firstRotateAngle); CGPoint vector = ccpSub(touchingPoint, wheel.position); CGFloat rotateAngle = -ccpToAngle(vector); CGFloat currentTouch = CC_RADIANS_TO_DEGREES(rotateAngle); wheelRotation += (currentTouch - previousTouch) * 0.6; //limit speed 0.6 } } I update the rotation of a the wheel in the update method by doing: wheel.rotation = wheelRotation; Now once the user lets go of the wheel I want it to rotate back to where it was before but not without taking into account the velocity of the swipe the user has done. This is the bit I really can't get my head around. So if the swipe generates a lot of velocity then the wheel will carry on moving slightly in that direction until the overall force which pulls the wheel back to the starting position kicks in. Any ideas/code snippets?

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• Issue with a point coordinates, which creates an unwanted triangle

  - by Paul

  I would like to connect the points from the red path, to the y-axis in blue. I figured out that the problem with my triangles came from the first point (V0) : it is not located where it should be. In the console, it says its location is at 0,0, but in the emulator, it is not. The code : for(int i = 1; i < 2; i++) { CCLOG(@"_polyVertices[i-1].x : %f, _polyVertices[i-1].y : %f", _polyVertices[i-1].x, _polyVertices[i-1].y); CCLOG(@"_polyVertices[i].x : %f, _polyVertices[i].y : %f", _polyVertices[i].x, _polyVertices[i].y); ccDrawLine(_polyVertices[i-1], _polyVertices[i]); } The output : _polyVertices[i-1].x : 0.000000, _polyVertices[i-1].y : 0.000000 _polyVertices[i].x : 50.000000, _polyVertices[i].y : 0.000000 And the result : (the layer goes up, i could not take the screenshot before the layer started to go up, but the first red point starts at y=0) : Then it creates an unwanted triangle when the code continues : Would you have any idea about this? (So to force the first blue point to start at 0,0, and not at 50,0 as it seems to be now) Here is the code : - (void)generatePath{ float x = 50; //first red point float y = 0; for(int i = 0; i < kMaxKeyPoints+1; i++) { if (i<3){ _hillKeyPoints[i] = CGPointMake(x, y); x = 150 + (random() % (int) 30); y += -40; } else if(i<20){ //going right _hillKeyPoints[i] = CGPointMake(x, y); x += (random() % (int) 30); y += -40; } else if(i<25){ //stabilize _hillKeyPoints[i] = CGPointMake(x, y); x = 150 + (random() % (int) 30); y += -40; } else if(i<30){ //going left _hillKeyPoints[i] = CGPointMake(x, y); //x -= (random() % (int) 10); x = 150 + (random() % (int) 30); y += -40; } else { //back to normal _hillKeyPoints[i] = CGPointMake(x, y); x = 150 + (random() % (int) 30); y += -40; } } } -(void)generatePolygons{ static int prevFromKeyPointI = -1; static int prevToKeyPointI = -1; // key points interval for drawing while (_hillKeyPoints[_fromKeyPointI].y > -_offsetY+winSizeTop) { _fromKeyPointI++; } while (_hillKeyPoints[_toKeyPointI].y > -_offsetY-winSizeBottom) { _toKeyPointI++; } if (prevFromKeyPointI != _fromKeyPointI || prevToKeyPointI != _toKeyPointI) { _nPolyVertices = 0; float x1 = 0; int keyPoints = _fromKeyPointI; for (int i=_fromKeyPointI; i<_toKeyPointI; i++){ //V0: at (0,0) _polyVertices[_nPolyVertices] = CGPointMake(x1, y1); //first blue point _polyTexCoords[_nPolyVertices++] = CGPointMake(x1, y1); //V1: to the first "point" _polyVertices[_nPolyVertices] = CGPointMake(_hillKeyPoints[keyPoints].x, _hillKeyPoints[keyPoints].y); _polyTexCoords[_nPolyVertices++] = CGPointMake(_hillKeyPoints[keyPoints].x, _hillKeyPoints[keyPoints].y); keyPoints++; //from point at index 0 to 1 //V2, same y as point n°2: _polyVertices[_nPolyVertices] = CGPointMake(0, _hillKeyPoints[keyPoints].y); _polyTexCoords[_nPolyVertices++] = CGPointMake(0, _hillKeyPoints[keyPoints].y); //V1 again _polyVertices[_nPolyVertices] = _polyVertices[_nPolyVertices-2]; _polyTexCoords[_nPolyVertices++] = _polyVertices[_nPolyVertices-2]; //V2 again _polyVertices[_nPolyVertices] = _polyVertices[_nPolyVertices-2]; _polyTexCoords[_nPolyVertices++] = _polyVertices[_nPolyVertices-2]; //CCLOG(@"_nPolyVertices V2 again : %i", _nPolyVertices); //V3 = same x,y as point at index 1 _polyVertices[_nPolyVertices] = CGPointMake(_hillKeyPoints[keyPoints].x, _hillKeyPoints[keyPoints].y); _polyTexCoords[_nPolyVertices] = CGPointMake(_hillKeyPoints[keyPoints].x, _hillKeyPoints[keyPoints].y); y1 = _polyVertices[_nPolyVertices].y; _nPolyVertices++; } prevFromKeyPointI = _fromKeyPointI; prevToKeyPointI = _toKeyPointI; } } - (void) draw { //RED glColor4f(1, 1, 1, 1); for(int i = MAX(_fromKeyPointI, 1); i <= _toKeyPointI; ++i) { glColor4f(1.0, 0, 0, 1.0); ccDrawLine(_hillKeyPoints[i-1], _hillKeyPoints[i]); } //BLUE glColor4f(0, 0, 1, 1); for(int i = 1; i < 2; i++) { CCLOG(@"_polyVertices[i-1].x : %f, _polyVertices[i-1].y : %f", _polyVertices[i-1].x, _polyVertices[i-1].y); CCLOG(@"_polyVertices[i].x : %f, _polyVertices[i].y : %f", _polyVertices[i].x, _polyVertices[i].y); ccDrawLine(_polyVertices[i-1], _polyVertices[i]); } } Thanks

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• (Abstract) Game engine design

  - by lukeluke

  I am writing a simple 2D game (for mobile platforms) for the first time. From an abstract point of view, i have the main player controlled by the human, the enemies, elments that will interact with the main player, other living elements that will be controlled by a simple AI (both enemies and non-enemies). The human player will be totally controlled by the player, the other actors will be controlled by AI. So i have a class CActor and a class CActorLogic to start with. I would define a CActor subclass CHero (the main player controlled with some input device). This class will probably implement some type of listener, in order to capture input events. The other players controlled by the AI will be probably a specific subclass of CActor (a subclass per-type, obviously). This seems to be reasonable. The CActor class should have a reference to a method of CActorLogic, that we will call something like CActorLogic::Advance() or similar. Actors should have a visual representation. I would introduce a CActorRepresentation class, with a method like Render() that will draw the actor (that is, the right frame of the right animation). Where to change the animation? Well, the actor logic method Advance() should take care of checking collisions and other things. I would like to discuss the design of a game engine (actors, entities, objects, messages, input handling, visualization of object states (that is, rendering, sound output and so on)) but not from a low level point of view, but from an high level point of view, like i have described above. My question is: is there any book/on line resource that will help me organize things (using an object oriented approach)? Thanks

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• Isometric Camera trouble - can't rotate or move correctly

  - by Deukalion

  I'm trying to create a 3D editor, but I've been having some trouble with the Camera and understanding each component. I've created 2 camera that works OK, but now I'm trying to implement an Isometric Camera in XNA without success on the rotation and movement of the camera. All I get working is Zoom. (Cube with x=3f, y=3f, z=1f in center) And this is the constructor for my IsometricCamera (inherits from ICamera, with methods for Rotation, Movement and Zoom, and Properties for World/View/Projection matrices) public IsometricCamera3D(GraphicsDevice device, float startClip = -1000f, float endClip = 1000f) { matrix_projection = Matrix.CreateOrthographic(device.Viewport.Width, device.Viewport.Height, startClip, endClip); rotation = Vector3.Zero; matrix_view = Matrix.CreateScale(zoom) * Matrix.CreateRotationY(MathHelper.ToRadians(45 + 180)) * Matrix.CreateRotationX(MathHelper.ToRadians(30)) * Matrix.CreateRotationZ(MathHelper.ToRadians(120)) * Matrix.CreateTranslation(rotation.X, rotation.Y, rotation.Z); } Problem is when I rotate it, all that happens is that the Cube gets more or less shiny and nothing happens. What is wrong and how should I create my View matrix to move it / rotate it correctly? Rotate, Move and Zoom looks like: MethodName(Vector3 rotation/movement), Zoom(float value); and just increases the value, then calls an update to recreate the View Matrix according to the code in the constructor. Currently, in my editor I use MiddleButton + Mouse Movement to rotate the camera, but it's not working as the other camera. But in my default camera I use World Matrix to move, but I guess that's not the best way to go which is why I'm trying this.

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• Introduction to Oracle ADF

  - by Arda Eralp

  The Oracle Application Development Framework (Oracle ADF) is an end-to-end application framework that builds on Java Platform, Enterprise Edition (Java EE) standards and open-source technologies. You can use Oracle ADF to implement enterprise solutions that search, display, create, modify, and validate data using web, wireless, desktop, or web services interfaces. Because of its declarative nature, Oracle ADF simplifies and accelerates development by allowing users to focus on the logic of application creation rather than coding details. Used in tandem, Oracle JDeveloper 11g and Oracle ADF give you an environment that covers the full development lifecycle from design to deployment, with drag-and-drop data binding, visual UI design, and team development features built in. In line with community best practices, applications you build using the Fusion web technology stack achieve a clean separation of business logic, page navigation, and user interface by adhering to a model-view-controller architecture. MVC architecture: The model layer represents the data values related to the current page The view layer contains the UI pages used to view or modify that data The controller layer processes user input and determines page navigation The business service layer handles data access and encapsulates business logic Each ADF module fits in the Fusion web application architecture. The core module in the framework is ADF Model, a data binding facility. The ADF Model layer enables a unified approach to bind any user interface to any business service, without the need to write code. The other modules that make up a Fusion web application technology stack are: ADF Business Components, which simplifies building business services. ADF Faces rich client, which offers a rich library of AJAX-enabled UI components for web applications built with JavaServer Faces (JSF). ADF Controller, which integrates JSF with ADF Model. The ADF Controller extends the standard JSF controller by providing additional functionality, such as reusable task flows that pass control not only between JSF pages, but also between other activities, for instance method calls or other task flows.

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• What is an Enterprise Resource Planning (ERP) System?

  In order to understand what an Enterprise Resource Planning System is let us look at a classic American kids snack, the Rice Krispy Treat if we conceptually view the treat as a company’s internal applications as a whole.  Furthermore we can view a company’s departmentalized software applications as the theoretical Rice Krispies in the treat. In addition, the Rice Krispies consist of a combination of ingredients that be broken down into data, user interfaces and business logic. Next, we have the margarine or butter that is used to help the marshmallows bind with the Rice Krispies; this role in our conceptual view is taken by a data source typically as a relational database management system. Finally we have the melted marshmallows which act as the ERP software that connects all of the individual departmental software applications in to one unified system that allows all user one unified system to interact with all of the individual dispersed systems. An example of this would be if a customer places an order with a telephone operator and once the orders is processed an employee in the shipping department can see the order ready for fulfillment on his order screen. The ERP acts a go between for various independent departmental systems so that they can integrate with one another.

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• Hello NHibernate! Quickstart with NHibernate (Part 1)

  - by BobPalmer

  When I first learned NHibernate, I could best describe the experience as less of a learning curve and more like a learning cliff.  A large part of that was the availability of tutorials.  In this first of a series of articles, I will be taking a crack at providing people new to NHibernate the information they need to quickly ramp up with NHibernate. For the first article, I've decided to address the gap of just giving folks enough code to get started.  No UI, no fluff - just enough to connect to a database and do some basic CRUD operations.  In future articles, I will discuss a repository pattern for NHibernate, parent-child relationships, and other more advanced topics. You can find the entire article via this Google Docs link: http://docs.google.com/Doc?docid=0AUP-rKyyUMKhZGczejdxeHZfOGMydHNqdGc0&hl=en Enjoy! -Bob

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• Java Virtual Developer Day Session Videos Available

  - by Tori Wieldt

  How are Lambdas handled on a bytecode level? How does replacing assembly code with Java code improve performance? Can we send flat files/comma separated/XML files to process in Batch? In a Java EE app, can I inject an EJB bean inside a REST POJO using @EJB annotation? Where I can find JavaFX UI controls? At OTN's Virtual Developer Day, Java experts answered these questions and more. Session are now available for you to view on demand (registration required). This is limited time offer: the sessions will be up to view for free for the next two weeks.  You can view sessions from these tracks: Java SE 8 Track Learn about the features scheduled for Java SE 8, including Lambda expressions, extension methods for interfaces and a new Date and Time API. Learn how to create basic apps with JavaFX.  Java EE Track Take a close look at the new functionality in Java EE 7. Get presentations and demos on JSON, WebSockets, Batch, Concurrency, JAX-RS 2, JMS 2,  Java Embedded Track Provides an introductions to the Raspberry Pi, the Keil board, ARM architecture, and how to make it all work with Java Embedded. You know Java, now really know Java. Check out the OTN Virtual Developer Day sessions!

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• How to handle multiple domains correctly? [closed]

  - by Eric Itzhak

  Possible Duplicate: Could I buy a domain name to increase traffic to my site like this? I have a website with multiple keyword based domains ( 2 actully) Now both domains are common google searches for the topic. What i'm intrested is to handle the domains as such that google can recognize the seconed domain with the same page rank as the primary domain, so it will also appear on the first page. My question is how do i do it correctly so i will help SEO? meaning i want the 2nd domain to be on the first page, because the primary is on the first page for it's keyword. do i simple put a redirect in the index.php file? Or to do a 301 redirect? or change the .htaccess file? Or create a domain pointer in the Control panel?

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• How can I force a preferred sound output device to be used?

  - by Dave M G

  In my sound settings interface, there are two devices for sound output: Both refer to the same physical device, which is a network sound device. Both work, but only with the second one, Simultaneous output to Kenwook Audio Device Digital Stereo (IEC958) on mythbuntu@mythbuntu, does the output volume respond to being changed. The first one always plays at the same level, and ignores volume settings. Every time I boot, the first one is selected. How can I make it so the second one is the default and the first one is disabled or at least never selected?

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• Why is my model's scale changing after rotating it?

  - by justnS

  I have just started a simple flight simulator and have implemented Roll and pitch. In the beginning, testing went very well; however, after about 15-20 seconds of constantly moving the thumbsticks in a random or circular motion, my model's scale begins to grow. At first I thought the model was moving closer to the camera, but i set break points when it was happening and can confirm the translation of my orientation matrix remains 0,0,0. Is this a result of Gimbal Lock? Does anyone see an obvious error in my code below? public override void Draw( Matrix view, Matrix projection ) { Matrix[] transforms = new Matrix[Model.Bones.Count]; Model.CopyAbsoluteBoneTransformsTo( transforms ); Matrix translateMatrix = Matrix.Identity * Matrix.CreateFromAxisAngle( _orientation.Right, MathHelper.ToRadians( pitch ) ) * Matrix.CreateFromAxisAngle( _orientation.Down, MathHelper.ToRadians( roll ) ); _orientation *= translateMatrix; foreach ( ModelMesh mesh in Model.Meshes ) { foreach ( BasicEffect effect in mesh.Effects ) { effect.World = _orientation * transforms[mesh.ParentBone.Index]; effect.View = view; effect.Projection = projection; effect.EnableDefaultLighting(); } mesh.Draw(); } } public void Update( GamePadState gpState ) { roll = 5 * gpState.ThumbSticks.Left.X; pitch = 5 * gpState.ThumbSticks.Left.Y; }

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• Payroll Customers Must Apply Mandatory Patches to Maintain Your Supportability

  - by DanaD

  The HRMS Suite of products has minimum required Rollup Patch (RUP) levels as well as additional mandatory patches that our customers must apply to ensure they are in compliance for support.  Without these patches, customers risk not being able to apply any fixes for issues they encounter as these RUPs and mandatory patches are the minimum patch level expected by Oracle Support and Oracle Development.  Core Payroll and International Payroll customers must apply the yearly Rollup Patch within 12 months of its issue. Legislative Payroll customers have additional requirements for the Rollup Patch, as the RUP generally is a pre-requisite for the next Year End/Fourth Quarter/Year Begin payroll processing supported by Oracle. These minimum RUP patches and other mandatory patches for your product or legislation are created with the following goals in mind: Compliance: Manage the people in your organization within the requirements of a specific country. Supportability: Ensure you are on a common code base so that if problems are identified, patches can be readily provided to you. Reliability: Reliable code with multiple customer downloads and comprehensive testing. For the listing of Mandatory Rollup Patches for Oracle Payroll please view: Doc ID 295406.1: Mandatory Family Pack/Rollup Patch (RUP) Levels for Oracle Payroll. For the listing of Mandatory Patches for the HRMS Suite please view: Doc ID 1160507.1: Oracle E-Business Suite HCM Information Center – Consolidated HRMS Mandatory Patch List. For information on the latest Rollup Patches (RUPs) for the HRMS Suite please view: Doc ID 135266.1: Oracle HRMS Product Family – Release 11i & 12 Information.

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• Debugging an IP Camera

  - by Kevin Boyd

  Further to my previous question on ServerFault here, I finally can view the stream on RTSP however I still cannot view the camera stream in a web browser. The IP camera uses an activeX control in Internet Explorer. And although I can configure the camera settings from IE, I cannot view the stream it shows connecting for a few sec and shows disconnecting. I have forwarded the HTTP, RTSP and Stream ports of the IP camera. the public port is 7071 and private port is 7070. When I try to see the connections in TCPView it shows that the ActiveX control in IE is trying to connect to port 7070 which is quite unusual since it should connect to 7071 Also the state shows SYN_SENT for sometime and then disconnects. I have really no clue what's going on and why?

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• Using an old penalized domain for a new website

  - by MiladSafaei

  I had a website with 2 domains like these: firstdomain.com and first-domain.com. The main domain was first-domain.com and the other one was 301 redirected to first one. The main domain got a Google Penguin penalty some months ago. I uploaded the site on an new domain and removed Google index of old domain by using the remove URL tool in Webmaster Tools. Now, I want to use firstdomain.com (which was redirected to the penalized domain) for a new and fresh website with new and perfect content. Is it probable that history of this domain affects the new website and harms its ranking?

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• Setting coding priorities

  - by dotnetdev

  Hi, In the dev shops I've worked in, nobody has ever mentioned "coding priorities". I read this in a book or site somewhere, and sets the expectation of what priority should be first in the code. In places where this is not specified, what should the first priority be? It may sound simple to say "do what the business need requires", but that could be at the expense of performance/maintainability. Many people say maintainability first, regardless, some say fulfill the need regardless. I am a young developer, so I am probably missing the point somewhere. Of course, programming is engineering and tough because you can never have the perfect solution. Thanks

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• GRUB is not Booting Correctly

  - by msknapp

  I have a PC with three hard disks. Windows 7 is installed on the first, Ubuntu 14.04 is installed on the third. After I re-booted, it went straight to Windows 7. So I tried explicitly telling my PC to boot using the third hard disk, but that just takes me to the grub rescue prompt. I followed Scott Severence's instructions here to try and recover. Essentially, I updated grub, reinstalled grub, and then updated it again. After re-booting, absolutely nothing had changed. So instead I tried using the boot-repair tool. In the past it had failed for me, saying that I had programs running and it could not unmount drives, when I was running nothing. I never figured out how to solve that problem, but it went away when I bought another hard drive and used that for my Ubuntu installation, I don't know why. In any case, I ran the boot-repair tool and this time it said it was successful. First time for everything right? I re-booted, only to be taken straight to the grub rescue prompt. So I changed my BIOS settings to use the third hard disk for boot start up. That is the same hard drive where I have Ubuntu and grub installed, and the same one that the grub-repair tool told me to use. It still took me straight to the grub rescue prompt. So I went from not being able to boot Ubuntu, to not being able to boot either OS installed on my system. Thanks boot-repair! Boot repair gave me this URL for future troubleshooting: http://paste.ubuntu.com/8131669 When I try to boot from the third hard disk, this is my console: Loading Operating System ... error: attempt to read or write outside of disk 'hd0'. Entering rescue mode... grub rescue> grub rescue> set cmdpath=(hd0) prefix=(hd0,gpt2)/boot/grub root=hd0,gpt2 grub rescue> ls (hd0) (hd0,gpt3) (hd0,gpt2) (hd0,gpt1) (hd1) (hd2) (hd2,gpt2) (hd2,gpt1) (hd3) Those values look correct to me. I have also experimented with changing some of those values, but 'insmod normal' always throws the same error. Somebody please tell me how to fix this. I have tried everything, reinstalling grub, and running boot-repair. =========================== Update: I think the problem might be that the ubuntu installer did not partition my hard disk correctly. I booted from live USB and then launched gparted and looked at how it partitioned things. This is what gparted says: Partition, File System, Size, Used, Unused, Flags /dev/sda1 (!), unknown, 1.00 MiB, ---, ---, bios_grub /dev/sda2, ext4, 2.71 TiB, 47.30 GiB, 2.67 TiB, /dev/sda3, linux-swap, 16.00 GiB, 0.00 B, 16.00 GiB, So that first line looks problematic. It is supposed to be the /boot partition. However, it was given only 1 MiB? I am assuming that MiB is actually supposed to mean megabyte, no idea why that 'i' is there. It also says the file system is unknown. I read the answer by andrew here, and he says he had to do a custom install, explicitly configuring the boot partition. So I think that maybe Ubuntu's installer has a bug in it, where it does not set up the boot partition correctly if you are not installing on the first hard disk in your computer. I am going to try reinstalling with a custom partition scheme. I read elsewhere (askubuntu won't let me post another link) that I don't even need a /boot partition any more. So instead of following Andrew's instructions ver batim, I'm first going to try having just two partitions: one for /, and another for my 16GB swap space. Both as primary partitions. The first will be formatted as ext4. If that doesn't work, I may try again using /boot. ======================== So I did my custom install with no /boot partition, and it did not work. When I rebooted, I had an error message saying that some address did not exist. So for the hundredth time, I booted from the live USB, and ran boot-repair. Now I get this message GPT detected. Please create a BIOS-Boot partition (>1MB, unformatted filesystem, bios_grub flag). This can be performed via tools such as Gparted. Then try again. I feel like I'm running in circles and nobody will help me.

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