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  • iOS iPad Master Detail template can't interact with detail view

    - by CraigularB
    I have an iPad app generated from the Master-Detail template in XCode. The iPad Storyboard has under the Detail View Controller a View that holds a ScrollView which holds an ImageView. In the DetailViewController.m file I added the following code to allow the ScrollView to move and zoom the image: -(UIView *)viewForZoomingInScrollView:(UIScrollView *)scrollView { return self.comicImage; } This works great on the iPhone (it's a universal app) but not the iPad; I can scroll and zoom the image on the iPhone no problem, but on the iPad it's like the ScrollView isn't responding to the touches, and I can't figure out how to pass the touches on to the ScrollView. I've already deactivated the popover controller from appearing with a right swipe like this: self.splitViewController.presentsWithGesture = NO; How do I make it so the user can interact with the ScrollView in the DetailViewController?

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  • jquery $.ajax not working in firefox against rails (406 response) (works in chrome & IE)

    - by phil swenson
    I have a rails backend and am testing the following jquery code against it: var content = $("#notification_content").val(); var data = new Object(); data.content = content; $.ajax({ url: "/notifications/detect_type.json", type:"POST", data: data, success: function(result ){updateTypeDropDown(result)}}); This code works fine in Chrome and IE. However in Firefox (using Firebug), I see this: http://localhost:3000/notifications/detect_type.json 406 Not Acceptable here is a chrome request in the log: Processing NotificationsController#detect_type (for 127.0.0.1 at 2010-12-21 17:05:59) [POST] Parameters: {"action"="detect_type", "content"="226 south emerson denver co 80209", "controller"="notifications"} User Columns (2.0ms) SHOW FIELDS FROM users User Load (37.4ms) SELECT * FROM users WHERE (users.id = '1') LIMIT 1 Completed in 58ms (View: 1, DB: 40) | 406 Not Acceptable [http://localhost/notifications/detect_type.json] here is a firefox request in the log: Processing NotificationsController#detect_type (for 127.0.0.1 at 2010-12-21 17:06:41) [POST] Parameters: {"action"="detect_type", "content"="226 south emerson 80209", "controller"="notifications"} User Columns (2.1ms) SHOW FIELDS FROM users User Load (30.4ms) SELECT * FROM users WHERE (users.id = '1') LIMIT 1 Completed in 100ms (View: 1, DB: 33) | 200 OK [http://localhost/notifications/detect_type.json] I'm stumped. Ideas?

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  • back button wont work.. Iphone

    - by lotuseater
    Hi, I have 2 page controls in my app, one for category and when i click details button of that category other page control comes. I have pushed the first view controller and used present modal view controller. Now a need to go back to the home page from the category page control but the view did load and view will appear wont work. That is where i have added my navigation bar programmatically. is there any way i can call them? i am new to iphone programming. Please help me if you can.... Thankyou

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  • How to record when user follows external links without slowing user down

    - by taw
    I want to track when user clicks external links for analytics purposes. The simplest solution is to replace all external links with links to special record-and-redirect controller, but that would slow the user unnecessarily. The second idea would be to override click event and within in $.post a message to record controller, then let the main event handler happen, which will usually be either click (open link in same tab) or middle click (open in new tab) - good either way, and the user won't have to wait for wait for my server to record it, it's fire-and-forget. (I don't care if users without Javascript don't get tracked) Is that a reasonable way to go? Or what else would be the best way to track all external link clicks?

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  • Deserialising Json to derived types in Asp.Net Web API

    - by IoChaos
    I'm calling a method of my WebAPI sending a json that I would like to match (or bind) with a model. In the controller I have a method like: public Result Post([ModelBinder(typeof(CustomModelBinder))]MyClass model); 'MyClass', wich is given as a parameter is an abstract class. I would like that at, depending of the type of json passed, the correct inherited class is instantiated. To achieve it, I'm trying to implement a custom binder. The problem is that (I don't know if it's very basic but I can't find anything) I don't know how to retrieve the raw Json (or better, some kind of serialization) that comes in the request. I see: actionContext.Request.Content But all methods are exposed as async. I don't know who this fits with passing the generate model to the controller method... Thanks a lot!

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  • Where to put a recursive function when following MVC?

    - by Glibly
    Hello, I have a recursive function being used to generate a menu on my site. The function is calling a database for each level of children in the menu, and generating html for them. I've currently put this function in a Model part of the code, however, I feel that generating html in the model goes against the MVC. I didn't put it in a Controller because I didn't want to have database calls or HTML generation there. I didn't put it in a View because I didn't want database calls there either. Is the 'correct' way of tackling this problem to have a Controller call a recursive function in a Model that returns a 2d array representing the menu. Then pass the array to a view which has it's own recursive function for generating html from the array?

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  • How do I (or should I?) access the service layer from a SiteMesh template (views/layouts/main.gsp) in Grails?

    - by knorv
    I need to create a toplist in the page footer on a site that I'm building. The footer is created in the default SiteMesh layout template (views/layouts/main.gsp). In order to create the toplist access to the database is needed, so I've encapsulated all logic needed for the toplist creation in a service class (services/FooService). Please note that while services are usually accessed from the controller layer, in this case the default layout template (views/layouts/main.gsp) is not generated from a controller. Can the layout view (views/layouts/main.gsp) access a service class? How? Is this the correct design decision? If not, what is a better encapsulation and how do I interact with said encapsulation from the layout view (views/layouts/main.gsp)?

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  • Any PHP MVC framework planning to use 5.3 features?

    - by alexandrul
    I would like to get started with PHP, and 5.3 release seems to bring many nice features (namespaces, lambda functions, and many others). I have found some MVC frameworks, and some of them support only PHP 5: PHP Frameworks PHP MVC Frameworks Model–view–controller on Wikipedia but can anyone recommend one of those MVC frameworks that plans to actively use PHP 5.3 features, not just being compatible with PHP 5.3? Update Results so far: Zend Framework 2.0 (in development) Lithium (in development, based on CakePHP) Symfony (in development) FLOW3 (in development, alpha)

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  • iPhone - Landscape Only App

    - by Robert
    Hello all! I am trying to make an app that will only be viewed in Landscape. I have looked up some tutorials (albeit older ones) and have done the following: -set up the info.plist to include a key for uiinterfaceorientation -in the main view controller I have set the frame to be 480 x 320 Now, the first screen loads up ok. Everything is where it should be and whatnot. However, if I click a button that is set to present a modal view controller nothing happens. Everything is linked and coded correctly but nothing happens when I press the button. Am I doing something wrong with trying to force landscape? At it's basic, this question is a how do you effectively make an app that will only be in landscape mode? Thanks for any help.

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  • Rendering Views as String with Spring MVC and Apache Tiles

    - by lynxforest
    I am trying to reuse some of my tiles in a controller which is returning a json response to the client. I would like to return a json response similar to the following format: { 'success': <true or false>, 'response': <the contents of an apache tile> } In my controller I would like to perform logic similar to this pseudocode: boolean valid = validator.validate(modelObj) String response = "" if(valid){ response = successView.render() // im looking for a way to actually accomplish // this, where the successView is the apache tiles view. // I would also need to pass a model map to the view somehow. }else{ response = errorView.render() } writeJsonResponse(httpResponse, /* a Map whose json representation looks like the one I described above. */)

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  • Subprocess with variables & Command from different class

    - by Pastelinux
    source: http://pastebin.com/utL7Ebeq My thinking is that if i run from controller class "main" it will allow me to take the "data" from Class "model", def "filename". It doesn't seem to work. As you can see below what i mean class Controller: def __init__(self): self.model = Model() self.view = View() def main(self): data = self.model.filename() self.view.tcpdump(data) class View: def tcpdump(self, command): subprocess.call(command.split(), shell=False) When i run my code i get this error: subprocess.call(command.split(), shell=False) AttributeError: 'NoneType' object has no attribute 'split' My guess means that its not picking up command (look at source for reference) or that its not getting command with variables. But i know the error when variables are not being picked up so i don't think it is that. My question is, from what i have thus far, how do i from "class view" grab "command" for my subprocesses to run. Thanks~ John Riselvato

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  • How to get the action from the HttpServlet request to dispatch to multiple pages

    - by JFB
    I am using the Page Controller pattern. How could I use the same controller for two different pages by detecting the request action and then dispatching according to the result? Here is my code: account.jsp <form name="input" action="<%=request.getContextPath() %>/edit" method="get"> <input type="submit" value="Modifier" /> </form> Account Servlet public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { System.out.println("received HTTP GET"); String action = request.getParameter("action"); if (action == null) { // the account page dispatch(request, response, "/account"); } else if (action == "/edit") { // the popup edit page dispatch(request, response, "/edit"); } protected void dispatch(HttpServletRequest request, HttpServletResponse response, String page) throws javax.servlet.ServletException, java.io.IOException { RequestDispatcher dispatcher = getServletContext() .getRequestDispatcher(page); dispatcher.forward(request, response); } }

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  • Pushing View from UITableView Problem

    - by golfromeo
    Basically, what I want is to be able to press a record in a table, and have it push to another view. To do this, I created a nib file and a UIViewController subclass (for the "pushed" view). I set the nib file's "File Owner" to be the controller I created. Then, in the view controller of the table that will push that view, I set the didSelectRowIndexAtPath: method to include the following: SearchTableController *vc = [[SearchTableController alloc] initWithNibName:@"SearchTable" bundle:[NSBundle mainBundle]]; [self.navigationController pushViewController:vc animated:YES]; [vc release]; (where "SearchTableController" is the name of the UIViewController subclass and "SearchTable" is the name of the nib file) However, when I run this code and click on the record, nothing happens- the app doesn't crash, but the view doesn't get pushed. The code is getting run, because it works when I NSLog(), but it doesn't seem to be pushing the view. Thanks for any help in advance.

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  • How to add :format options to a named route in Rails?

    - by Alfred Nerstu
    I've got a named route called profile and I would like to be able to access it as json. But when I look at my rake routes output I see that the (.:format) is missing. How do I add it to a named route? user GET /users/:id(.:format) {:action=>"show", :controller=>"users"} profile /:username {:action=>"show", :controller=>"users"} Thanks in advance!

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  • Best practices for multiple asserts on same result in C#

    - by asdseee
    What do you think is cleanest way of doing multiple asserts on a result? In the past I've put them all the same test but this is starting to feel a little dirty, I've just been playing with another idea using setup. [TestFixture] public class GridControllerTests { protected readonly string RequestedViewId = "A1"; protected GridViewModel Result { get; set;} [TestFixtureSetUp] public void Get_UsingStaticSettings_Assign() { var dataRepository = new XmlRepository("test.xml"); var settingsRepository = new StaticViewSettingsRepository(); var controller = new GridController(dataRepository, settingsRepository); this.Result = controller.Get(RequestedViewId); } [Test] public void Get_UsingStaticSettings_NotNull() { Assert.That(this.Result,Is.Not.Null); } [Test] public void Get_UsingStaticSettings_HasData() { Assert.That(this.Result.Data,Is.Not.Null); Assert.That(this.Result.Data.Count,Is.GreaterThan(0)); } [Test] public void Get_UsingStaticSettings_IdMatches() { Assert.That(this.Result.State.ViewId,Is.EqualTo(RequestedViewId)); } [Test] public void Get_UsingStaticSettings_FirstTimePageIsOne() { Assert.That(this.Result.State.CurrentPage, Is.EqualTo(1)); } }

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  • Conditional value for ActiveRecord create method only

    - by Steve Wright
    I have a form where I have an administrator creating new users. The form uses the User model I created (login, password, first_name, etc...). For the last field on the form, I want to have a checkbox that doesn't need to be stored as part of the User record, but it is needed for the controller. This will control whether or not the newly created user will receive a welcome email or not. def create @user = User.new(params[:user]) if @user.save if @user.send_welcome_email UserMailer.welcome_email(@user).deliver end redirect_to(admin_users_url, :notice => "User #{@user.name} was successfully created.") else render :action => "new" end end In my view (haml) I am trying to access it like this: %p Send Welcome Email? = f.check_box :send_welcome_email I tried to make this an attr_accessible: :send_welcome_email but the controller does not recognize it. I get an undefined method 'send_welcome_email' for #&lt;User:0x00000100d080a8&gt; I would like it to look like this: What is the best way to get this working:

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  • image is not getting loaded in view.

    - by anurag
    I have created 2 views named "FirstView" and "SecondView".SecondView's nib file has an UIImage view object as its IBOtlet.Now I am getting an UIImage object from some FirstViewController's method.Now I am setting the SecondViewController's imageView property with that image and then I am pushing my SecondView Controller's object in Navigation Controller.The SecondView gets loaded but that image is not shown in that view. The code is as follows:..... (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingImage:(UIImage *)img editingInfo:(NSDictionary *)editInfo { [[picker parentViewController] dismissModalViewControllerAnimated:YES]; SecondViewController *secondView=[[SecondViewController alloc] initWithNibName:@"SecondViewController" bundle:[NSBundle mainBundle]]; secondView.imageView.image=img; [self.navigationController pushViewController:secondView animated:YES]; }

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  • image is not getting loaded in view.

    - by anurag
    I have created 2 views named "FirstView" and "SecondView".SecondView's nib file has an UIImage view object as its IBOtlet.Now I am getting an UIImage object from some FirstViewController's method.Now I am setting the SecondViewController's imageView property with that image and then I am pushing my SecondView Controller's object in Navigation Controller.The SecondView gets loaded but that image is not shown in that view. The code is as follows:..... - (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingImage:(UIImage *)img editingInfo:(NSDictionary *)editInfo { [[picker parentViewController] dismissModalViewControllerAnimated:YES]; SecondViewController *secondView=[[SecondViewController alloc] initWithNibName:@"SecondViewController" bundle:[NSBundle mainBundle]]; secondView.imageView.image=img; [self.navigationController pushViewController:secondView animated:YES]; }

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  • Property Scope (Iphone)

    - by Hank
    Hello All. I am having trouble accessing a declared property and I think I am missing something fundamental about the nature of properties and perhaps view controllers. Here's what I'm doing so far: declaring a property "myPhone" in a root view controller called RootViewController. grabbing a phone number from a modally presented people picker setting "myPhone" to the value from the people picker (from within shouldContinueAfterSelectingPerson of ABPeoplePickerNavigationController) trying to access "myPhone" from another modally presented view controller "myPhone" continues to NSLog to null despite trying every permutation of self.myPhone, super, RootViewController, etc. to try and access the value I set. What am I missing?

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  • iPhone screen rotates at random !

    - by Baldoph
    I use a tabBar Controller as root controller. It has 4 tabs and each of its ViewControllers has - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation { return YES; } as long as the tabBarController itself. But when I rotate the device (real or simulator), the screen turns at random! If it doesn't turn when I open the application it would have the same behavior until I quit the app. I tried to add the 4 viewControllers one by one in IB to see if one was problematic, but I obtained the same issue. It only always works when there is no tabs at all! Please tell me if you have any ideas. Thanks!

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  • cocoa - referencing a method on the parent

    - by Mike
    I had a method on my main view controller named "calculateThis". This method was run, obviously, as int newValue = [self calculateThis:myVariable]; when I run it from inside the view controller. Then I created a static class and I need to run this method from there. How do I reference this method from that class using just relative references, as super, superview, delegate, etc. I cannot use the class name defined on the delegate because this static class is used in several apps of mine.

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  • How to set UITableView to Grouped?

    - by 4thSpace
    In an iPhone navigation based app, I want to add a second tableview but have its design available in IB. I've added a new empty XIB and dragged a UITableView onto it. I want to setup the layout through IB. I've created a controller for this tableview and set the File's Owner class in IB to this controller. I linked the tableview to File's Owner as well. I set the tableview to grouped in IB. However, that does not translate at runtime. I still have a plain tableview. In fact, none of the Inspector settings work at runtime. What have I missed?

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  • What are the differences between MVP, Presentation Model, MVVM and MVC?

    - by Nicholas
    I have a pretty good idea how each of these patterns work some of the minor differences between them, but are they really all that different from each other? It seems to me that the Presenter, Presentation Model, ViewModel and Controller are essentially the same concept. Why couldn't I classify all of these concepts as controllers? I feel like it might simplify the entire idea a great deal. Can anyone give a clear description of their differences? I want to clarify that I do understand how the patterns work, and have implemented most of them in one technology or another. What I am really looking for is someone's experience with one of these patterns, and why they would not consider their ViewModel a controller for instance.

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  • What is your prefered way to return XML from an ActionMethod in Asp.net MVC?

    - by serbrech
    I am displaying charts that load the data asynchronously because the searches are the work to fetch the data is quite heavy. The data has to be return as XML to make the chart library happy. My ActionMethods return a ContentResult with the type set as text/xml. I build my Xml using Linq to XML and call ToString. This works fine but it's not ideal to test. I have another idea to achieve this which would be to return a view that builds my XML using the XSLT View engine. I am curious and I always try to do the things "the right way". So how are you guys handling such scenarios? Do you implement a different ViewEngine (like xslt) to build your XML or do you Build your XML inside your controller (Or the service that serves your controller)?

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