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  • php regex - can't find the error

    - by peirix
    Just one simple, specific question: I've got the string {var1}12345{var2}, and I want to get the variable names used. if (preg_match("/{([a-zA-Z0-9]*)}/g", $url, $matches)) { print_r($matches); } If I remove the global flag, it works, but I only get the first variable, as expected. Why isn't it working with a global flag? It works when I'm testing it with the Regex Tester

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  • PHP combobox can't save the selected value on Edit Page

    - by bEtTy Barnes
    hello I've got problem with my combobox. It's not saving the selected value in Edit page. Here what I'm working with: private function inputCAR(){ $html = ""; $selectedId = $this->CAR; //$html .= '<option value="Roadmap Accelerator - Core">Roadmap Accelerator - Core</option>'; //$html .= '<option value="Roadmap Accelerator - Optional Core">Roadmap Accelerator - Optional Core</option>'; //$html .= '<option value="Regulatory">Regulatory</option>'; //$html .= '<option value="Mission Critical">Mission Critical</option>'; //$html .= '<option value="Various CARs/Types">Various CARs/types</option>'; $selection = array( "Roadmap Accelerator - Core", "Roadmap Accelerator - Optional Core", "Regulatory", "Mission Critical", "Various CARs/types" ); $html .= '<label for="car">CAR Type</label>'; $html .= HTML::selectStart("car"); foreach($selection as $value){ $text = $value; $html .= HTML::option($value, $text, $selectedId == $value ? true : false); } $html .= HTML::selectEnd(); return $html; } My option function: public static function option($value, $text, $isSelected=false) { $html = '<option value="' . $value . '"'; if($isSelected) { $html .= ' selected="selected"'; } $html .= '>'; $html .= $text; $html .= '</option>'; return $html; } When I first created a record. The selected value from my combobox got saved into the DB then the page refreshed to display. When I went to edit page, to select another value, and clicked save button. On the display page, it's not saving. For example. on Create page I selected Regulatory. then I changed my mind and changed it to Mission Critical on Edit page. On display page it is not changed. I don't know what's wrong or what I'm missing here. Any help is welcome and truly appreciated. Thanks.

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  • [PHP] Kohana-v3 ORM parent relationship

    - by VDVLeon
    Hi all, I just started with the version 3 of the Kohana Framework. I have worked a little with the $_has_many etc. Now I have the table pages. The primary key is pageID. The table has a column called parentPageID. Now I want to make a ORM model who, when accesed like this $page->parent->find() returns the page identified by parentPageID. I have the following already: // Settings protected $_table_name = 'pages'; protected $_primary_key = 'pageID'; protected $_has_one = array( 'parent' => array( 'model' => 'page', 'foreign_key' => 'parentPageID', ), ); But that does not work, it simply returns the first page from the table. Last query says this: SELECT `pages`.* FROM `pages` ORDER BY `pages`.`pageID` ASC LIMIT 1 Does somebody know how to solve this? I know this can: $parent = $page->parent->find($page->parentPageID); but it must be and can be cleaner (I think).

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  • Errors checking and opening a URL using PHP

    - by Jean
    Hello Here is one script with out any errors $url="http://yahoo.com"; $file1 = fopen($url, "r"); $content = file_get_contents($url); $t_beg = explode('<title>',$content); $t_end = explode('</title>',$t_beg[1]); echo $t_end[0]; And here is the same script using a look to check multiple urls and getting errors for ($j=1;$j<=$i;$j++) { if ($x[$j]!=''){ $t_u = "http:".$x[$j]; $file2 = fopen($t_u, "r"); $content2 = file_get_contents($t_u); $t_beg = explode('<title>',$content); $t_end = explode('</title>',$t_beg[1]); echo $t_end[0]; } } The error is Warning: fopen() [function.fopen]: php_network_getaddresses: getaddrinfo failed: No such host is known. in g:/ What exactly is wrong here?

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  • php domDocument variables

    - by geoffs3310
    Hi, I have the following code at the moment: $ip = '195.72.186.157'; $xmlDoc = new DOMDocument(); $xmlDoc->loadXML(file_get_contents('http://www.geoffmeierhans.com/services/geo-locator/locate/?ip='.$ip.'&output=xml')); foreach($xmlDoc->getElementsByTagName('city') as $link) { $links = array('text' => $link->nodeValue); } $city = $links['text']; echo $city; Is there a better way to get the city variable? Since there is only one tag called city a loop isn't really needed but I can't get it to work any other way

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  • problem creating jpg thumb with php

    - by Ross
    Hi, I am having problems creating a thumbnail from an uploaded image, my problem is (i) the quality (ii) the crop http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/large.jpg http://welovethedesign.com.cluster.cwcs.co.uk/phpimages/thumb.jpg If you look the quality is very poor and the crop is taken from the top and is not a resize of the original image although the dimesions mean it is in proportion. The original is 1600px wide by 1100px high. Any help would be appreciated. $thumb = $targetPath."Thumbs/".$fileName; $imgsize = getimagesize($targetFile); $image = imagecreatefromjpeg($targetFile); $width = 200; //New width of image $height = 138; //This maintains proportions $src_w = $imgsize[0]; $src_h = $imgsize[1]; $thumbWidth = 200; $thumbHeight = 138; // Intended dimension of thumb // Beyond this point is simply code. $sourceImage = imagecreatefromjpeg($targetFile); $sourceWidth = imagesx($sourceImage); $sourceHeight = imagesy($sourceImage); $targetImage = imagecreate($thumbWidth,$thumbHeight); imagecopyresized($targetImage,$sourceImage,0,0,0,0,$thumbWidth,$thumbWidth,imagesx($sourceImage),imagesy($sourceImage)); //imagejpeg($targetImage, "$thumbPath/$thumbName"); imagejpeg($targetImage, $thumb); chmod($thumb, 0755);

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  • INSERT INTO error MYSQL/PHP

    - by bat
    I get this error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order (total, addy, cc) VALUES ('798' , '123 sadf' , '12124123')' at line 1 $total = addslashes(($_SESSION['total'])); $addy = addslashes(($_POST['addy'])); $cc = addslashes(($_POST['cc'])); echo "$total"; echo "$addy"; echo "$cc"; mysql_query("INSERT INTO order (total, addy, cc) VALUES ('$total' , '$addy' , '$cc')") or die(mysql_error()); help plz =]

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  • php - arrange array to display in score order

    - by Phil Jackson
    hi, i have wrote a script to produce an array of data but now want to display in order of score. The array outputs as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user1_design [2] => user2_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 6 [2] => 15 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) so in a nutshell I am wanting it to be converted as follows; [display_name] => Array ( [0] => ACT_Web_Designs [1] => user2_design [2] => user1_design ) [proffesion] => Array ( [0] => Web Developer [1] => web developer [2] => Web Developer ) [score] => Array ( [0] => 15 [1] => 15 [2] => 6 ) [img] => Array ( [0] => ./?0000=gif&0001=3fadb8c362ff39f3322909899ff14760&0002=prof_pic [1] => [2] => ) I have been looking at asort() but cant get anything to work. any help would be much appreciated.

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  • php shuffle() returns one item

    - by mike
    Anyone have any idea why shuffle() would only return 1 item? when using: $array2 = shuffle($array1); with the following array($array1): Array ( [0] => 1 [1] => 5 [2] => 6 [3] => 7 [4] => 8 [5] => 10 [6] => 11 [7] => 12 [8] => 13 [9] => 14 ) The output of: print_r($array2); is simply: 1 Any idea as to why it would not only not shuffle the array, but knock off the remaining 9 items in the array? thanks!

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  • drop down box php

    - by DAFFODIL
    I have stored 6 records in mysql db,when i use this code each of the 6 records getting displayed in seprate drop down box,i want them to be displayed in a single drop down box.Where am i going wrong? Any help ii be appreciated. Thnx in advance. http://dpaste.com/hold/180077/

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  • Implode error for PHP

    - by Pete Herbert Penito
    Hi Everyone! I have a form where I've got three checkboxes like this: <td>Wireless <input type="checkbox" name="services[]" value="wireless" /></td> </tr> <tr> <td>Cellular <input type="checkbox" name="services[]" value="cellular" /></td> </tr> <tr> <td>Security <input type="checkbox" name="services[]" value="Security" /></td> <input type="submit" name="submit"> and then I extract($_POST), and have this code $comServices = implode(",", $services); but I get an error: Warning: implode() [function.implode]: Invalid arguments passed in .. does anyone know why Im getting this error?

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  • Are Dynamic Prepared Statements Bad? (with php + mysqli)

    - by John
    I like the flexibility of Dynamic SQL and I like the security + improved performance of Prepared Statements. So what I really want is Dynamic Prepared Statements, which is troublesome to make because bind_param and bind_result accept "fixed" number of arguments. So I made use of an eval() statement to get around this problem. But I get the feeling this is a bad idea. Here's example code of what I mean // array of WHERE conditions $param = array('customer_id'=>1, 'qty'=>'2'); $stmt = $mysqli->stmt_init(); $types = ''; $bindParam = array(); $where = ''; $count = 0; // build the dynamic sql and param bind conditions foreach($param as $key=>$val) { $types .= 'i'; $bindParam[] = '$p'.$count.'=$param["'.$key.'"]'; $where .= "$key = ? AND "; $count++; } // prepare the query -- SELECT * FROM t1 WHERE customer_id = ? AND qty = ? $sql = "SELECT * FROM t1 WHERE ".substr($where, 0, strlen($where)-4); $stmt->prepare($sql); // assemble the bind_param command $command = '$stmt->bind_param($types, '.implode(', ', $bindParam).');'; // evaluate the command -- $stmt->bind_param($types,$p0=$param["customer_id"],$p1=$param["qty"]); eval($command); Is that last eval() statement a bad idea? I tried to avoid code injection by encapsulating values behind the variable name $param. Does anyone have an opinion or other suggestions? Are there issues I need to be aware of?

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  • php forms insert and update

    - by DAFFODIL
    I have a form.The user enter the data ,the data will be stored in the data base. Now,using phpmysql,i need to display the whole data present in db to front end.The user will click a particular thing and make some modifications and if,he press update the data should get into database. Give me a snippet http://dpaste.com/hold/178740/

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  • PHP mySQL - replace some string inside string

    - by apis17
    i want to replace ALL comma , into ,<space> in all address table in my mysql table. For example, +----------------+----------------+ | Name | Address | +----------------+----------------+ | Someone name | A1,Street Name | +----------------+----------------+ Into +----------------+----------------+ | Name | Address | +----------------+----------------+ | Someone name | A1, Street Name| +----------------+----------------+ Thanks in advance.

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  • PHP PDO - Num Rows

    - by Ian
    PDO apparently has no means to count the number of rows returned from a select query (mysqli has the num_rows variable). Is there a way to do this, short of using count($results->fetchAll()) ?

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  • PHP MVC correct usage

    - by Ratt
    What is the correct (recommended method) for passing information to a view in a MVC environment. Currently we use Zend Framework, where we write classes to handle specific things EG a Book class with a save and load method to retrieve info from the DB, which is called from a particular nameAction(). What I would like to know is what is the best way to pass this information to the view, in some cases we do $this-view-book_name = $book-getBookName(); and in other cases we do the following $this-view-book = $book; OR $this-view-books = Book_Manager::getAllBooks(); and then access the object(s) properties in the view. Information on-line suggests we try limit what access a view has to information, i.e pass them only what they need and in some cases people say its ok to pass stuff through as long as nothing is done to that information. Regards

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  • Lightweight CMS in PHP

    - by David
    Hi, I am building a site which will require some very limited content management for a client. There are only a few areas of the site which will require the client to be able to update the content themselves. Would it be better to create a very simple custom admin page for the client to log in and say add a news story etc or would it be best using a fully fledged CMS like Drupal etc which seems overkill to me.

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  • change font in sharedbook api in php

    - by ashish
    I m using Sharedbook api to generate a memory book, although it's working perfect, but font of the memory book is unchangeable ...means i can't change the font family of that book. I tried to change the font then it display error. please suggest me how to change Font of that memory book.. Thank is advance

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  • PHP: SimpleXML and Arrays

    - by acemasta
    When I run this code: foreach($xml->movie as $movie) { if(isset($movie->photos)) { foreach ($movie->photos as $photo) { echo $photo."&nbsp;"; } echo "<hr/>"; } } I get nice output of the actual data, e.g. a row looks like 06397001.jpg 06397002.jpg 06397003.jpg 06397004.jpg 06397005.jpg But when I throw it in an array, it includes all the SimpleXML wrapper tags and the jpgs are not at the root of the array. code: foreach($xml->movie as $movie) { if(isset($movie->photos)) { $photos = array(); foreach ($movie->photos as $photo) { $photos[] = $photo; } } else $photos = ""; var_dump($photos); echo "<hr />"; } e.g. same row looks like array(5) { [0]= object(SimpleXMLElement)#11 (1) { [0]= string(12) "06397001.jpg" } [1]= object(SimpleXMLElement)#12 (1) { [0]= string(12) "06397002.jpg" } [2]= object(SimpleXMLElement)#13 (1) { [0]= string(12) "06397003.jpg" } [3]= object(SimpleXMLElement)#14 (1) { [0]= string(12) "06397004.jpg" } [4]= object(SimpleXMLElement)#15 (1) { [0]= string(12) "06397005.jpg" } } Why is this happening/how can I remove this so I just get an array of the photos at root level like when I echo it? Thanks, sorry for the single line code formatting; was messing up when I tried to paste directly with line breaks.

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  • PHP Date Manipulations

    - by Ajith
    I need to get previous 30 days from a specific date which is available from database(eg: 2010-05-23 12:36:29).I am try it by using date('d', strtotime("-30 days")) Which is getting the currect answer what i looking for but it is not help me to enter date from database.Please help me to solve the issue.

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  • Best way to stop SQL Injection in PHP

    - by Andrew G. Johnson
    So specifically in a mysql database. Take the following code and tell me what to do. // connect to the mysql database $unsafe_variable = $_POST["user-input"]; mysql_query("INSERT INTO table (column) VALUES ('" . $unsafe_variable . "')"); // disconnect from the mysql database

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  • PHP, is_array() generating an "Undefined property: stdClass::$crit " error

    - by Brook Julias
    is_array($src2->crit) is generating an "Undefined property: stdClass::$crit" error. The line throwing the error is: if(is_array($src2->crit) && count($src->crit) > 0){ $src2->crit is initialized here. $src2->crit = array(); $src2->crit[0] = new dataSet(); $src2->crit[0]->tblName = $tbl2; $src2->crit[0]->colName = "ID"; $src2->crit[0]->val = $elm->editID; When testing $src2->crit with this code. print("\$src->crit is a ".$src->crit."<br />"); print_r($src->crit); print("<br />"); This is returned. $src2->crit is a Array Array ( [0] => dataSet Object ( [tblName] => sExam [colName] => ID [val] => 10 ) ) What am I not seeing/understanding correctly? If print("\$src2->crit is a ".$src->crit."<br />") returns that it is an array then why is is_array($src2->$crit) generating an error?

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  • GZIP .htaccess and php session problem

    - by Suresh
    Hi, I am trying to implement GZIP compression for my website. I copied the below code in my .htaccess file: ExpiresActive On ExpiresDefault A604800 Header append Cache-Control "public" <IfModule mod_deflate.c> <FilesMatch "\.(js|css)$"> SetOutputFilter DEFLATE </FilesMatch> </IfModule> what happens is when I type username and password the page reloads but still the login form is displayed but session is set. When I refresh the page using ctrl + R the login form goes and the username is displayed. what will be the problem. wwaiting for ur reply.

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  • Capitalize Words in PHP with custom delimitor

    - by Paulie
    Hey guys, i need a method to capitalize every first letter of a word. This is what i got so far and it is working for almost every string...but it fails on this one "WELLNESS & RENOMME". // method in stringModify Class function capitalizeWords($words, $charList) { $capitalizeNext = true; for ($i = 0, $max = strlen($words); $i < $max; $i++) { if (strpos($charList, $words[$i]) !== false) { $`capitalizeNext` = true; } else if ($capitalizeNext) { $capitalizeNext = false; $words[$i] = strtoupper($words[$i]); } } return $words; } // Calling method $stringModify->capitalizeWords("WELLNESS & RENOMME", " -&"); I hope someone can help me out...i tried for 1,5 hours now and don't have a clue. Thanks in advance for any tips or hints. Greetz Paulie

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