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  • Replace single character in windows filenames

    - by Matt Rogish
    I have a Win2k3 server that has a whole bunch of filenames that need renamed. Basically, I just need all - (dashes) replaced with _ (underscores), no matter where they are in the string. Assume that there are no duplicates. I can do this on my mac with a little script but the files are too large and crazy to transfer to my mac, rename, then go back to the server. Would love to do this in a command shell and not have to download a renamer or any add'l software. Thanks!

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  • how to setup a ssh acount with no terminal but port forwarding?

    - by admalledd
    I am trying to set up a new user account I can give to friends so they can SSH into my forward computer, and only allow forwarding of certain ports. I do not want my friends to have a shell, or be able to change what ports to where they are allowed to forward. example session: joe(friend) connects using PuTTY (that I have pre-set, he isn't good with computers) to example.com(my Internet facing computer) forwarding ports 8080,1990,25565 to him(with what ever end ports he wants, preferably they stay the same numbers) example ssh command to do similar (but he can still change the ports on my computer!) ssh -N [email protected] -p443 -L8080:192.168.1.2:8080 -L1990:127.0.0.1:1990 -L25565:127.0.0.1:25565 then, same story with other friend smith(same ports, same user even) except he is using linux, so cant use putty. is it possible to also leave default SSH functinality for all other users but this one? I found this when I was searching google, but alas, I did not quite understand what was being suggested, and I don't think they covered restricting port forwarding

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  • How do I install the vi text editor ONLY on my Cygwin installation?

    - by gath
    I have managed to install the Cygwin on my Windows Vista machine. I installed using the default settings. When I try to do vi in the Bash shell, Bash tells me command not found. I believe I need to install the Cygwin editors package which include the vi editor. The nightmare is every time I run the Cygwin setup and select ONLY the editors package and specifically the Vim and select install, Cygwin setup tries to install all other packages, very frustrating!! Is there an easier way of installing just a single package using the Cygwin setup utility?

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  • Windows Software to Save Arbitrary Application State

    - by ashes999
    VM software does a great job of saving state when you "turn it off," allowing instant and immediate return to that previous state. Is there some application for Windows that allows me to do the same thing, for any arbitrary software? It would allow me to save/restore state, possibly via a shell command or button that it appends to every window. Edit: For clarity, there are two types of apps: those that save their own states, and those that save others' states. Those that save their own state are like Chrome, which on load, reloads the windows you had open last time. That's not what I'm asking about; I'm asking for an app that can save the state of other apps, kind of like VM software does; but for any app. (A trivial test would be load notepad++, type a bunch of stuff, and save-state; on reset-state, you should be able to multi-level undo a lot of what you wrote, as if you never shut down the application.)

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  • How do I securely share my server?

    - by Blue
    I have a large dedicated server running Debian and I want to share it with about 6 friends of mine. I know I can simply just use adduser to create user accounts for them, but I want to know if they can, even as a regular user without root permissions, do anything malicious. I know by default they have read permissions for other users in the /home, and can solve that with chmod, but I just want to make sure that there's nothing else they can do. And also, is there any kind of script or program that makes it easier to create and manage shell users on a server?

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  • Sapi How to get text inside elements?

    - by code_wizard
    My sapi grammar file looks like <RULE NAME="SOUNDLOG" TOPLEVEL="ACTIVE"> <O> Please </O> <O> Enter</O> <P> Name </P> <P> <RULEREF REFID="VID_InputType" /> </P> </RULE> <RULE ID="VID_InputType"> <L PROPID="VID_InputType"> <P >John</P> <P>Jill</P> <P>Gary</P> </L> How do I get the name when it is recognized by sapi recognizer?

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  • can not access dlink 604 set up interface

    - by user36089
    Hello everyone I used dlink-di604 enthernet board as router to share web access. My ISP provides the service base on Ethernet rathern than base on Ethernet pppoe mode. It is manually setup ipv4, subnet mask , DNS, Gateway etc Log in using web user name&password. I use http://192.168.0.2 try to access dlink di604 setup inferface, but failed I call command ipconfig /all Dos shell displayed: Ethernet adapter Local Connection: Physical Address: 00-3c-56-79-19-49 IPv4 address:10.7.8.225 subnet mask: 255.255.255.0 default gate way: 10.7.8.1 DNS servers 10.10.10.10 What is the correct way to access dlink 604 setup interface and set to share web access? Welcome any comment Thanks interdev

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  • Enter response once prompt returns?

    - by mjb
    It's neither a secure idea nor one I'd recommend elsewhere, but I have a situation when occasionally it takes a while for my Ansible ad-hoc command to respond. I'd love to pipe or args or whatever is needed to push the required text into the prompt so I can walk away and know it will finish. Ex: $ ansible all -m shell -a "reboot" --ask-pass Password: blah blah blah it worked I'd love to send an argument or << or something to get the password in. Is that possible?

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  • Can't get ZSH working on CentOS

    - by waveslider
    I've been using zsh for a couple of years now on Ubuntu and really like it a lot. I've installed it on our production server as well, which is running CentOS 5.2 However, I just installed it via yum on a new VM I created to use as a development box, to replicate our production box as closely as possible. Although yum shows that it is definitely installed (/bin/zsh) and that it is set as my shell, it does not appear to be working. Instead of creating the .zshrc and .profile files in my home directory, it created a .tcshrc file. Also, I did not receive the default configuration menu that is always displayed once you begin using ZSH, and none of the features (like advanced tab comple

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  • Cannot use `su` or `sudo` after set up key-based access to SSH

    - by OrangeTux
    I'm following this tuturial to setup key-based access to the SSH I created a user. I add copy the key to the client via ssh-copy-id <username>@<host> Becasuse ssh <username>@<host> still prompts for a password I run ssh-add on the local machine. The terminal doens't prompt for a password, I can login without using a password. But I cannot run su anymore. Every input for the password results in Authentication failure. I tried it again. But before coping the key, I added to the sudoer file. Copied key, ssh-add. But now I cannot login to my SSH shell att all? How can I setup a key-based SSH access with the possibiluty to use su or sudo?

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  • Backup all plesk MySQL Databases to individual files

    - by Michael
    Hy, Because I'm new to shell scripting I need a hand. I currently backup all mydatabases to a single file, thing that makes the restore preaty hard. The second problem that my MySQL password dosen't work because of a Plesk bug and i get the password from "/etc/psa/.psa.shadow". Here is the code that I use to backup all my databases to a single file. mysqldump -uadmin -p`cat /etc/psa/.psa.shadow` --all-databases | bzip2 -c > /root/21.10.2013.sql.bz2 I found some scripts on the web that backup each database to individual files but I don't know how to make them work for my situation. Here is a example script: for db in $(mysql -e 'show databases' -s --skip-column-names); do mysqldump $db | gzip > "/backups/mysqldump-$(hostname)-$db-$(date +%Y-%m-%d-%H.%M.%S).gz"; done Can someone help me make the script above work for my situation? Requirements: Backup each database to individual file using plesk password location.

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  • How to detect identical part(s) inside string?

    - by Horace Ho
    I try to break down the http://stackoverflow.com/questions/2711961/decoding-algorithm-wanted question into smaller questions. This is Part I. Question: two strings: s1 and s2 part of s1 is identical to part of s2 space is separator how to extract the identical part(s)? example 1: s1 = "12 November 2010 - 1 visitor" s2 = "6 July 2010 - 100 visitors" the identical parts are "2010", "-", "1" and "visitor" example 2: s1 = "Welcome, John!" s2 = "Welcome, Peter!" the identical parts are "Welcome," and "!" Python and Ruby preferred. Thanks

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  • Executing a command as apache

    - by Lord Loh.
    This script keeps outputting a 1. and I cannot understand why. <?php passthru("nohup sudo rndc reload sd.example.com",$op); print_r($op); ?> I have also tried the above code without the nohup. I have the following line in my sudoers file apache ALL = NOPASSWD: /usr/sbin/rndc reload sd.example.com Just to test, temporally, I allowed apache a shell, logged in as apache by sudo su apache and successfully managed to execute sudo rndc reload sd.example.com. I do not see any error message in my log files wither. What could I be possibly doing wrong? None of the similar threads have pointed me to anything that solved my problem or debug it.

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  • Could someone give me their two cents on this optimization strategy

    - by jimstandard
    Background: I am writing a matching script in python that will match records of a transaction in one database to names of customers in another database. The complexity is that names are not unique and can be represented multiple different ways from transaction to transaction. Rather than doing multiple queries on the database (which is pretty slow) would it be faster to get all of the records where the last name (which in this case we will say never changes) is "Smith" and then have all of those records loaded into memory as you go though each looking for matches for a specific "John Smith" using various data points. Would this be faster, is it feasible in python, and if so does anyone have any recommendations for how to do it?

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  • Embed Powershell prompt in Windows 7 desktop

    - by EricRRichards
    On Linux (last time I did this was with Compiz on Ubuntu 11), I like to have a transparent console window anchored to the desktop, so I can get to a shell just by clicking out of whatever I'm doing and don't have to play with with moving/resizing windows. I'd like to do something similar on Windows 7/Server 2008. I could probably write up a quick little app in .Net that would run fullscreen and have a powershell terminal embedded in it, but, if somebody has already created something sufficient, or there is some other hackery to do this, I don't want to reinvent the wheel. Another possibility could be a Quake-style pulldown console, similar to Guake (guake.org).

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  • DD-WRT with both https and sshd running in port 443

    - by Bruno
    I have a buffalo router with dd-wrt v24 SP2. After setting up the basic stuff, I enabled the https access to the admin page. Several days later, while setting up remote ssh, I changed the default port from 22 to 443. And now..well :) You got the picture :) I can ssh the router but I have no web access to it's admin page. Before rushing to a cold-hearted configuration reset, is there any way to change the ssh port from a shell? Or make dd-wrt accessible thru basic http?

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  • Mongo Client RedHat EL5 UT8 Support

    - by Michael Irey
    # mongo MongoDB shell version: 1.6.4 Fri Mar 16 11:55:46 *** warning: spider monkey build without utf8 support. consider rebuilding with utf8 support connecting to: test Mongo Server seems to handle the utf8 characters fine, as well as my php-mongo-client driver. But when I try to query a record that has a utf8 character from the mongo command line client I get: > db.Users.find({age:33}); error:non ascii character detected Fri Mar 16 11:55:43 mongo got signal 11 (Segmentation fault), stack trace: Fri Mar 16 11:55:43 0x440b50 0x3664c302d0 0x3f47e7b6e0 0x3f47e83bbd 0x3f47e254f3 0x3f47e25660 0x3f47e256ee 0x3f47e25792 0x3f47e2876e 0x4b031d 0x443b72 0x445476 0x3664c1d994 0x43fd39 mongo(_Z12quitAbruptlyi+0x3b0) [0x440b50] /lib64/libc.so.6 [0x3664c302d0] /usr/lib64/libjs.so.1 [0x3f47e7b6e0] /usr/lib64/libjs.so.1(js_CompileTokenStream+0x3d) [0x3f47e83bbd] /usr/lib64/libjs.so.1 [0x3f47e254f3] /usr/lib64/libjs.so.1(JS_CompileUCScriptForPrincipals+0x60) [0x3f47e25660] /usr/lib64/libjs.so.1(JS_EvaluateUCScriptForPrincipals+0x3e) [0x3f47e256ee] /usr/lib64/libjs.so.1(JS_EvaluateUCScript+0x22) [0x3f47e25792] /usr/lib64/libjs.so.1(JS_EvaluateScript+0x6e) [0x3f47e2876e] mongo(_ZN5mongo7SMScope4execERKSsS2_bbbi+0xed) [0x4b031d] mongo(_Z5_mainiPPc+0x14a2) [0x443b72] mongo(main+0x26) [0x445476] /lib64/libc.so.6(__libc_start_main+0xf4) [0x3664c1d994] mongo(__gxx_personality_v0+0x269) [0x43fd39] Any ideas or suggestions would be welcome

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  • How do I reference members of a single object passed to the View?

    - by Juxtaposed
    I'm new to MVC2 in ASP.NET/C#, so please forgive me if I misunderstand something. I have code similar to this in my Controller: var singleInstance = new Person("John"); ViewData["myInstance"] = singleInstance; return View(); So in my view, Index.aspx, I want to be able to reference members in that object. For example, Person has a member called Name, which is set in the constructor. In the view I want to get Person.Name from what is stored in the ViewData object. Ex.: <%= ViewData["myInstance"].name %> That doesn't work. The only real workaround I've found is to do something like this: <% var thePerson = ViewData["myInstance"]; print (or whatever the method is) thePerson.Name; %> Any help would be much appreciated... This was so much easier in PHP/Zend Framework... sigh

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  • SSH disconnects active session after 20 minutes

    - by Paramaeleon
    I’ve just set up a new Linux box (OpenSuSE 12.3 on VmWare). Now I stated that my SSH shell sessions are disconnected exactly after 20 minutes, clearly with activity. (Putty: “Network error: Software caused connection abort”) I already set Putty to send keep alives every 64 sec. In sshd_config, I set ClientAliveInterval 50 ClientAliveCountMax 2 and did a deamon reload. Didn’t help. About two minutes after the link breakdown, ssh reports to /var/log/messages: … … sshd[…]: Timeout, client not responding. … … sshd[…]: pam_unix(sshd:session): session closed for user root I don’t encounter this behaviour when connecting to other virtual machines, so I guess the problem isn’t in the network. Any help is appreciated.

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  • Looking for a way execute a task on all files in a directory (recursively) on Windows

    - by stzzz1
    I have a huge number of mp4 video files that needs to have a volume boost. I need a way to execute a ffmpeg audio filter on all files in a specified base directory (and in subdirectories as well). My problem is that I'm working on a Windows computer and I have no knowledge of its shell syntax. I would like to do the equivalent of what this bash script does : TARGET_FILES=$(find /path/to/dir -type f -name *.mp4) for f in $TARGET_FILES do ffmpeg -i $f -af 'volume=4.0' output.$f done I spent quite some time this afternoon looking for a solution but the recursive nature of what I need (that is so simple with find!) isn't too clear. Any help would be greatly appreciated!

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  • How to configure in crontab with condition statement for checks

    - by chz
    We like to monitor the NAS storage mounted on a linux box. We only like to be notified via mail when the usage exceeds a certain number say 80. We have only seen in linux books where most of them are calling shell scripts at certain times. How do we write inside crontab to only mail us if it exceeds 80 ? Usual eg 2 2 * * * /home/someUser/script.sh 2&1 | mail [email protected] Looking for solution like below 2 2 * * * if [ someNumber "80" ] ; then /home/someUser/script.sh | mail [email protected] Sincerely

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  • Apache 2 Symbolic link not allowed or link target not accessible

    - by astropanic
    My apache server runs as user foo. I have some Rails applications in /home/foo/app1 /home/foo/app2. Each of them has an vhost <VirtualHost *:80> ServerName app1.foobar.com ServerAlias www.app1.foobar.com DocumentRoot /var/www/html/app1/current/public RailsEnv production <Directory /var/www/html/app1/current/public> AllowOverride all Options -MultiViews </Directory> </VirtualHost> I have a symlink in /var/www/html/app1 : current -> /home/foo/app1/tmp_20102611 All file permissons are set correctly (user foo group foo), I can go through the filesystem from shell. SELINUX is disabled Distro is CentOs 5.5 Which the above symlink I get an 403 and an error entry in error_log Symbolic link not allowed or link target not accessible:/var/www/html/app1/current When I symlink my app in the subdir of /var/www/html instead of /home/foo it works. How I can avoid this error still placing my app in my /home/foo directory ?

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  • Javascript Closure question.

    - by Tony
    Why the following code prints "0-100"? (function () { for ( var i = 100; i >= 0; i -= 5) { (function() { var pos = i; setTimeout(function() { console.log(" pos = " + pos); }, (pos + 1)*10); })(); } })(); I declare pos = i , which should be in a descending order. This code originated from John Resig' fadeIn() function in his book Pro javascript techniques.

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  • Roll standalone JBoss app under Tomcat

    - by Seva Alekseyev
    I've got a Linux box where there’s Tomcat running, with some JSP applications in it. Now, I’ve received a third party app from a developer shop to be eventually deployed. It came as an archive called "jboss7.tar" which, it seems, contained a whole standalone Web server. Once I’ve followed their instructions and run the designated shell script, it would start a server that would listen on port 8081, and app pages are being served up. Still, this strikes me as an inelegant setup. Why run two Web servers side by side, both of them Java-enabled? Also, the manual startup of the standalone app, I don't like that either. The real question is – can I take the user-provided portions from the said archive and somehow plug it under the existing Tomcat instance? It looks like the user code is packaged into files with .war extension, I can see them under /var/jboss7/standalone/deployments.

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  • how to google a symbol keyword like "$?"

    - by ZhengZhiren
    i saw a trick in a book: in a linux shell, we can use &? to get the return value of a command. For example,we run a command,if it exit normally, the return value is 0. And then we type $?,we will get 0 in the screen. i want to google this kind of usage, so i have to type these two symbol $? in the search blank.But the search engine just return nothing to me... i have looked at the google help page, but still can't find a solution. so my question is: how can i search with this kind of keyword. or if you can give me some advise of the usage of $? or sort of thing, that will be also appreciated.

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