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  • regex php: find everything in div

    - by Fifth-Edition
    I'm trying to find eveything inside a div using regexp. I'm aware that there probably is a smarter way to do this - but I've chosen regexp. so currently my regexp pattern looks like this: $gallery_pattern = '/([\s\S]*)<\/div/'; And it does the trick - somewhat. the problem is if i have two divs after each other - like this. <div class="gallery">text to extract here</div> <div class="gallery">text to extract from here as well</div> I want to extract the information from both divs, but my problem, when testing, is that im not getting the text in between as a result but instead: "text to extract here text to extract from here as well" So . to sum up. It skips the first end of the div. and continues on to the next. The text inside the div can contain "<", "/" and linebreaks. just so you know! Does anyone have a simple solution to this problem? Im still a regexp novice.

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  • Mysql error in php code

    - by Ockonal
    Hello, can't understand mysql error: UPDATE static_pages SET order = " Some new data 222222 "Database error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order = " $query = 'UPDATE someTable SET '.$key.' = "'.$value.'"'; Here is $key = order; $value = 'new data 222222'; There is such keys in table: order, prices, contacts. Each of these updates well except the 'order'. Why?

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  • Strange php problem

    - by M28
    The following code: print_r($_GET); echo '<br />'; echo isset($_GET['logout'])?'yes':'no'; prints: Array ( [logoout] => ) no Why is it printing "no" instend of "yes"?

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  • PHP - fgetcsv - Delimiter being ignored?

    - by KnockKnockWhosThere
    I'm trying to output each line in a csv file, and it seems like the delimiter is being ignored... I'm sure my syntax is wrong somewhere, but can't seem to pinpoint it... The CSV file looks like this: ID,Code,Count TM768889,02001,10 TM768889,02002,10 TM768889,02003,10 TM768889,02004,10 TM768889,02005,10 I'm trying to output: 0 - ID,Code,Count 1 - TM768889,02001,10 2 - TM768889,02002,10 3 - TM768889,02003,10 4 - TM768889,02004,10 5 - TM768889,02005,10 But instead, it's outputting this: 0 - ID 1 - Code 2 - Count TM768889 3 - 02001 4 - 10 TM768889 5 - 02002 6 - 10 TM768889 7 - 02003 8 - 10 TM768889 9 - 02004 10 - 10 TM768889 11 - 02005 12 - 10 Here's my code: $row = 0; if(($handle = fopen($_FILES["Filedata"]["tmp_name"], "r")) !== FALSE) { $string = ''; while(($line = fgetcsv($handle,1000,",")) !== FALSE) { $num = count($line); $row++; for($c=0; $c < $num; $c++) { $string .= $c.' - '.$line[$c].'<br />'; } } fclose($handle); echo $string; }

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  • php mysql array - insert array info into mysql

    - by Michael
    I need to insert mutiple data in the field and then to retrieve it as an array. For example I need to insert "99999" into table item_details , field item_number, and the following data into field bidders associated with item_number : userx usery userz Can you please let me know what sql query should I use to insert the info and what query to retrieve it ? I know that this may be a silly question but I just can't figure it out . thank you in advance, Michael .

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  • penny auctions in PHP

    - by Cudos
    I have a project where I need a penny auction. Rather than doing it from scratch I would like to hear if you know any "ready-to-go" scripts for that? There are alot of them out there but most seems dodgy. I have no problem tweaking/customizing such scripts. I just don't want to start from scratch.

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  • PHP MVC Principles

    - by George
    I'm not using an off-the-shelf framework and don't particularly want to (nor d I want to go into the reasons why...). Anyway, onto my question(s), I hope it make sense.... I'm trying to get my head around what should go in the model and what should go in the controller. Originally I had the impression that a model class should represent an actual object (eg - a car from the cars table of a database) and model properties should mirror the database fields. However I'm now getting the feeling that I've got the wrong idea - should an instance of a model class represent an actual item, or should it contain a number of methods for doing stuff - sometimes to one car or sometimes to multiple cars based on my example earlier. For example I want to get all the cars from a the database and show them in the view. Am I right in think it should be along the lines of this? Controller File function list() { $cars = $this->model->get_all(); $this->view->add($cars); $this->view->render('cars-list'); } Model File function get_all() { // Use a database interaction class that I've written $cars = Database::select(); return $cars; } Now, if the car had a "status" field that was stored as an integer in the database and I wanted to change that to a string, where should that be done? By looping the SQL results array in the get_all() method in the model? Also, where should form validation live? I have written a validation class that works a little like this: $validator = new Validator(); $validator->check('field_name', 'required'); If the check fails, it adds an error message to the array in the Validator. This array of error messages would then get passed to the view. Should the use of my validator class go in model or the controller? Thanks in advance for for any help anyone can offer. If you know of any links to a simple MVC example / open source application that deals with basic CRUD, they would be much appreciated.

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  • php upload image with ftp problem

    - by ntan
    Hi, I am using the code below to upload an image through ftp $sFile=$ftp_dir."/".$image_name; $image=$database_row["image"];//image is store in database $fh = tmpfile(); $fwrite($fh, $image); $uploadFile = ftp_fput($conn_id, $sFile, $fh, FTP_ASCII); fclose($fh); The ftp is creating the file and has a size BUT the file i get is not an image.When try to open on image viewer i get error. Before switch to ftp i had this code $image=$database_row["image"];//image is store in database $file = fopen( "images/".$image_name, "w" ); fwrite( $file, $image); fclose( $file ); and was working fine, but now i have to use ftp. What am i missing.

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  • I need help with creating a data structure in PHP

    - by alex
    What I need to do is have a data structure that shows jobs organised into 14 day periods, but only when an id is the same. I've implemented all sorts of stuff, but they have failed miserably. Ideally, maybe a SQL expert could handle all of this in the query. Here is some of my code. You can assume all library stuff works as expected. $query = 'SELECT date, rig_id, comments FROM dor ORDER BY date DESC'; $dors = Db::query(Database::SELECT, $query)->execute()->as_array(); This will return all jobs, but I need to have them organised by 14 day period with the same rig_id value. $hitches = array(); foreach($dors as $dor) { $rigId = $dor['rig_id']; $date = strtotime($dor['date']); if (empty($hitches)) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } else { $found = false; foreach($hitches as $key => $hitch) { $hitchStartDate = $hitch['startDate']; $dateDifference = abs($hitchStartDate - $date); $isSameHitchTimeFrame = $dateDifference < (Date::DAY * 14); if ($rigId == $hitch['rigId'] AND $isSameHitchTimeFrame) { $found = true; $hitches[$key]['dors'][] = $dor; } } if ($found === false) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } } } This seems to work OK splitting up by rig_id, but not by date. I also think I'm doing it wrong because I need to check the earliest date. Is it possible at all to do any of this in the database query? To recap, here is my problem I have a list of jobs with all have a rig_id (many jobs can have the same) and a date. I need the data to be organised into hitches. That is, the rig_id must be the same per hitch, and they must span a 14 day period, in which the next 14 days with the same rig_id will be a new hitch. Can someone please point me on the right track? Cheers

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  • php - replace array elements with another array's elements?

    - by Simpson88Keys
    Not sure how to go about this... But, I have two arrays, one with updated information, another with outdated information... There are a lot more elements in the second array, but I'm looking to "update" the outdated one with the updated information. Here's what the arrays look like: //Outdated Array ( [0] => Array ( [anum] => 3236468462 [cid] => 4899097762 [mid] => 1104881401 [na_title] => [na_fname] => JOHN [m_initial] => [na_lname] => DOE [na_suffix] => [na_addr1] => 1234 SAMPLE AVENUE [na_addr2] => [na_city] => NORWALK [state] => OH [zip] => [zip_plus_4] => [route] => R002 [dma_code] => 510334 ) ) //Updated Array ( [1] => Array ( [0] => YUD990 [1] => 98 [2] => 1234 Sample Avenue [3] => [4] => Norwalk [5] => OH [6] => 44857-9215 [7] => 3236468462 ) ) To clarify, I want to: (1) Match up the value for [7] from the updated array with the value for [anum] in the outdated array, and then update [na_addr1], [na_addr2], [na_city], [state], [zip], [zip_plus_4] in the outdated array with the values for [2],[3],[4],[5],[6] (I know I'll need to split the updated [6] in order to get it to map corrected to the outdated) Feel like I'm making this very confusing... sorry about that...

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  • Mysql php error insert statement not working

    - by DAFFODIL
    I created database using mysql but now,i am unable to insert data,I am getting this error. Notice: Undefined index: Name in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Address in C:\wamp\www\customer.php on line 12 Notice: Undefined index: City in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Pincode in C:\wamp\www\customer.php on line 12 Notice: Undefined index: State in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Country in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Phone in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Mobile in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Fax in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Email in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Website in C:\wamp\www\customer.php on line 12 Notice: Undefined index: Notes in C:\wamp\www\customer.php on line 12 Error: Table 'form.customer' doesn't exist

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  • Entity-attribute-value model using codeigniter / php

    - by John Stewart
    SO I am trying to create a way to structure my database to be able customize forms. I looked into EAV pattern and here is my db structure: Table form - form_id - form_name - form_added_on - form_modified_at Table: form_fields - field_id - form_id - field_type (TEXT, RADIO etc..) - field_default_value - field_required Table: form_data - data_id - field_id - form_id - field_value so now I can store any custom form into the database and if I want to get the values for an individual form I can simply join it by "form_id" .. the problem: I want to be able to search through all the forms for a specific field value. How can I do that with EAV model? Also, I thought about just storing the custom data as a serialized (JSON) object but then I am not sure how can I query that data. Please note that I am using Codeigniter with MYSQL. So if conversation can use Codeigniter libraries if needed.

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  • how to find the directory already is there or not in php

    - by zahir hussain
    hi i want know find the directory is already there or not... if not i would like to create the directory... my coding is below... $da = getdate(); $dat = $da["year"]."-".$da["mon"]."-".$da["mday"]; $m = md5($url)."xml"; if(is_dir($dat)) { chdir($dat); $fh = fopen($m, 'w'); fwrite($fh, $xml); fclose($fh); echo "yes"; } else { mkdir($dat,0777,true); chdir($dat); $fh = fopen($m, 'w'); fwrite($fh, $xml); fclose($fh); echo "not"; } thanks and advance

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  • How Easy Is It to Hijack Session Vars on GoDaddy (PHP)

    - by yar
    This article states that If your site is run on a shared Web server, be aware that any session variables can easily be viewed by any other users on the same server. On a larger host like GoDaddy, are there really no protections in place against this? Could it really be that easy? If it is that easy, where are the session vars of the other users on my host so I can check them out? Edit: I didn't believe it, but here's my little program which shows that this is true! I wonder if those are really the same as the value stored in the cookies on the users' machine?

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  • PHP - Loop thru recordset and fire event each n rows

    - by Luciano
    I'm looking for the right logic to loop thru a recordset and fire an event each n times. Searching on Google i've found some discussion on similar situations, but it seems that solutions don't fits my needs. Let's say i have a recordset of 22 rows. I want to loop thru each row and launch a function on the 4th, the 8th, the 12th and so on... Using the modulus operator as shown in this answer, if($i % 4 == 0), i get the event fired each 4 rows, but 22 its not a multiple of 4 so the event is fired till the 20th row and then nothing. Maybe i need to make a division counting rows in 'excess'? Since the recordset will be between 50 and 200 rows i think its not necessary run multiple query of 4 rows, am I wrong? Thanks in advance!

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  • Php - Looping For Different CSS

    - by bob
    MySQL $selectSize = "SELECT * FROM products"; $querySize = $db->select($selectSize); while ($product = $db->fetcharray($querySize)) { HTML <ul> <li>Product A</li> <li>Product B</li> <li class='right'>Product C</li> <li>Product D</li> <li>Product E</li> <li class='right'>Product F</li> </ul> Question While getting the product, I want the Product C and Product F or any product after 3 loops will have class='right' to the list style. Let me know Thanks

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  • PHP form validation question?

    - by GeNx
    Is it necessary to validate a name or street address? when I have it coded in the following format. And if so why? $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $name = mysqli_real_escape_string($mysqli, htmlentities($_POST['name']));

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