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  • updating button text and other issues

    - by droidus
    I am trying to update my button. but the problem is that I can't have an ID/name with it, right, when doing this? so what if I have multiple forms on the page, and must identify the button? <input type="submit" value="Upload my File" style="background-color:#00F; font-size:14px; padding:1em;" onclick=" this.value='Please wait...'; this.disabled = true; var theForm = this.form; window.setTimeout(function(){theForm.submit();},3);" /> also, the button doesn't seem to wait 3 seconds when I hit the submit button.

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  • showing error on uploading a big file using php

    - by user1489969
    I have created a php code to display the upload option to upload multiple files as below: <?php $f_id= $_GET["id"]; ?> <title>Upload File</title> <form enctype="multipart/form-data" method="post" action="upload_hal_mult.php?id=<?php echo $f_id;?>" > <input type="hidden" name="MAX_FILE_SIZE" value="10000000"> <input id="infile" type="file" name="infile[]" multiple="true" /> <input type="submit" value="upload" name="file_uploaded" / > <br> <br> </form> So this will call "upload_hal_mult.php" when "upload" button is clicked. And the code for that is as follows: <title>Upload Results</title> <?php define("MAX_SIZE",10000000); $f_id= $_GET["id"]; $dir_name="dir_hal_".$f_id; $u=0; if (!is_dir($dir_name)) mkdir($dir_name); $dir=$dir_name."/"; $file_realname = $_FILES['infile']['name']; for ($i = 0; $i < count($_FILES['infile']['name']); $i++) { $ext = substr(strrchr($_FILES['infile']['name'][$i], "."), 1); $fname = substr($_FILES['infile']['name'][$i],0,strpos($_FILES['infile']['name'][$i], ".")); $fPath = $fname."_(".substr(md5(rand() * time()),0,4).")".".$ext"; echo "files size=".$_FILES["infile"]["size"][$i]."\n"; if($_FILES["infile"]["size"][$i]>MAX_SIZE) echo('File uploaded exceeds maximum upload size.'); if(($_FILES['infile']['error'][i]==0) && move_uploaded_file($_FILES['infile']['tmp_name'][$i], $dir . $fPath)) { $u=$u+1; ?> <!--<script type="text/javascript">setTimeout("window.close();", 1300);</script>--> <?php echo "Upload is successful\n"; } else echo "if stmt failed so error \n"; } if($u!=count($_FILES['infile']['name'])) echo "Error"; else echo "count is correct"; ?> This upload works correctly for files of size<10MB. But for files of size10MB, it's not echoing 'File uploaded exceeds maximum upload size.' as expected. Its also not uploading the file of size10MB. But the $u gets incremented. But none of the statements like "Upload is successful" or "if stmt failed so error" are being echoed as well. However the statement "count is correct" is being displayed, and this shows the $u got incremented somehow even though the echo statements didnt work! Can someone please point out the error I am doing here? I thought its simply a matter of 'if/else' statements but it seems more than that to me. Please help me out if you have any clue. Thanks

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  • Maximizing the current window in javascript

    - by user349134
    Is there a way I can maximize a currently minimized window from Javascript? Here's my situation: I have a series of links that all target the same external window (e.g. "MyNewWindow"). When I click a link, a new window pops up. If I click another link, the page pops up in the same window as expected. If I minimize the "MyNewWindow" popup, I'd like to be able to click another link and have that window maximize. My approach was to put something on the onLoad part of the body so that when the page is refreshed it will automatically "maximize" if it is minimized. Note: Using window.MoveTo() and window.resizeTo() doesnt seem to do the trick (the window stays minimized). Thanks!

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  • js function causing all other functions not to work inside js file

    - by Camran
    In safari 4 and all explorer browsers, whenever I try to call a function inside a javascript file which contains this function below, that first function isn't called. So calling function1 will not work if function2 is inside the same .js file, explanation? Here is the code which makes the problem. Whenever I remove this function, everything works fine and all functions work fine. So this function is causing a problem. function addOption(selectbox, value, text, class, id_nr ) { var optn = document.createElement("OPTION"); optn.text = text; optn.value = value; optn.id = value; if (class==1){ optn.className = "nav_option_main"; } selectbox.options.add(optn); } Any ideas why? Thanks

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  • How to Keep the selected value of the select box after Form POST or GET

    - by Rajasekar
    Im trying to implement the search feature in my website. when the search keyword is entered in the textbox, and the category combo is selected, the form will be Posted and the result will be shown on the same page. what i want is to keep the selected category of the combo by default in the form after posted For eg., If i select the category 'Automobiles' in the combo and click search, after form submit, the combo should show the automobiles as default selected option. Please help me. Any help will be appreciated

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  • Select multi-select form from array

    - by Budove
    Here's the issue. I have a database column called pymnt_meth_pref, which contains a comma separated string of payment methods chosen from a multiselect form. <td>Payment Methods Used:<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Cash">I can pay with cash.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Check">I can pay by check.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Credit Card">I can pay by credit card.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Paypal">I can pay with Paypal.<br /> </td> This array is posted to a variable and turned into a comma separated string if (isset($_POST['pyment_meth_pref'])) $pymntmethpref = implode(", ", $_POST['pyment_meth_pref']); if (isset($_POST['pyment_meth_acc'])) $pymntmethacc = implode(", ", $_POST['pyment_meth_acc']); This is then inserted into the database as a comma separated string. What I would like to do, is take this string and apply the values to the original form when the user goes back to the form as 'pre-selected' checkboxes, indicated that the user has already selected those values previously, and keeping those values in the database if they choose to edit any other information in the form. I'm assuming this would need to be done with javascript but if there is a way to do it with PHP I'd rather do it that way.

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  • JavaScript text slideshow not working?

    - by I Build Websites
    I'm making a Javascript slideshow for my blog yet the array doesn't seem to be working. Can someone please say what I've been doing wrong <SCRIPT type="text/javascript"> var blog = new Array() blog[0]= "<h4>Sunday 17 of June 2012</h4><p title='Blog'>Donec tempus risus eget ligula viverra eget placerat odio tincidunt. Duis nisl sem, scelerisque faucibus congue vitae, accumsan at lectus. Cras vestibulum arcu ut lorem luctus eu pharetra tortor ultricies. Nam iaculis orci mauris. Etiam luctus, mauris sed adipiscing ullamcorper, augue enim volutpat sem, ut sagittis ipsum nibh ac nulla. Nam ultrices, quam eget sollicitudin porta, sapien mauris pulvinar augue, posuere hendrerit erat ligula ut magna. Maecenas laoreet nisi vitae magna consectetur a mollis purus tristique. Pellentesque elementum arcu non urna convallis eleifend. Aliquam eu lorem sed risus tempus tempor. Donec malesuada velit in odio vulputate iaculis. In tristique neque quis velit posuere adipiscing. Nullam dui neque, scelerisque non egestas feugiat, pellentesque vitae mauris.</p><hr>" and so the array continues till function display1() { document.getElementById(blogShow).innerHTML( blog[0]) } function display2() { document.getElementById(blogShow).innerHTML(blog[1]) } function display3() { document.getElementById(blogShow).innerHTML(blog[2]) } function display4() { document.getElementById(blogShow).innerHTML(blog[3]) } function display5() { document.getElementById(blogShow).innerHTML(blog[4]) } </SCRIPT> <div id="blogShow"> <SCRIPT type="text/javascript">display1()</SCRIPT> </div> <div id="blogNav"> <input type="button" onClick="display2()" value="1" class="button"> <input type="button" onClick="display3()" value="2" class="button"> <input type="button" onClick="display4()" value="3" class="button"> <input type="button" onClick="display5()" value="4" class="button"> </div> I know it's all inline and i will clean up after it works

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  • Tool to measure Render time

    - by Noob
    Hi Folks, Is there a tool out there to measure the actual Render time of an element(s) on a page? I don't mean download time of the resources, but the actual time the browser took to render something. I know that this time would vary based on factors on the client machine, but would still be very handy in knowing what the rendering engine takes a while to load. I would imagine this should be a useful utility since web apps are becoming pretty client heavy now. Any thoughts?

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  • background-image in IE

    - by amit
    <div id="banner" style="display: block; background-image: url('images/swirl_home.gif'); background-repeat: no-repeat; background-color: #e7e7e7;"> <div id="Hi"> some text here... </div> <div id="loader"> <img src="images/ajax-loader.gif" /> </div> </div> #banner { background-color: #e7e7e7; min-height: 285px; } the above code renders perfectly in Mozilla and Chrome. Fails entirely in IE 6/7/8. The background image just doesnt show. I can see the text though. What am I doing wrong...?

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  • CSS IE7 Problem

    - by tpae
    Hello, I am trying to make a vertical progress bar, which works fine on almost all browsers except IE7. I don't know what's going on.. link text I've tried almost everything, and I can't figure out what's wrong...

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  • How to use Javascript to create a checked radioButton in IE?

    - by Chris
    I was trying to create a checked radiobutton by using following code in IE7. But it doesn't work. var x = document.createElement(""); var spn=document.createElement("span"); spn.appendChild(x); x.checked=true; document.body.appendChild(spn); I found that I could put x.checked=true after appendChild statement to make it work. I also noticed that when I change "radio" to "checkbox", it can be checked without changing the order of statements. I am really confused by these facts. Am I doing something wrong in the above code?

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  • Displaying images in one line inside a shorter div

    - by nemiss
    How can I set all images in one line and display only the first 200px of them inside the div? Without breaking the layout, or moving images to a next line. online demo <div id="thumbsContainer"> <ul> <li><img src="http://img214.imageshack.us/img214/6030/small3.jpg" alt="" /></li> <li><img src="http://img263.imageshack.us/img263/5600/small1ga.jpg" alt="" /></li> <li><img src="http://img638.imageshack.us/img638/3521/small4j.jpg" alt="" /></li> <li><img src="http://img682.imageshack.us/img682/507/small5.jpg" alt="" /></li> <li><img src=" http://img96.imageshack.us/img96/6118/small2o.jpg" alt="" /></li> </ul> </div> #thumbsContainer { width:200px; overflow:hidden; } ul { list-style:none; } li { float:left; }

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  • search submitbutton in all forms with textareas with jquery

    - by domueni
    Hi there i'm working on a ff-plugin which searchs a webpage for all textareas and places a warning before the submit button. my code looks like this var submitWarning = content.document.createElement("div"); submitWarning.innerHTML = "Fancy Message"; $('textarea', window.content.document).each(function() { var form = $(this, window.content.document).parents('form:first'); $(form, window.content.document).children('input[type=submit]').each(function() { form.insertBefore(submitWarning, this); }); }); if i search all submits with $('input[type=submit]'.each... it works fine but since i added the thing with the textarea and the form:first i got problems (nothing happens) p.s. i use the window.content.document thingy because its a ff-plugin and it won't work nothing without it

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  • How to show/hide certain div when i have multiple div with same class name

    - by Rajasekar
    I had multiple div with class name blueflip i want to toggle this class's div content when the div link_button is clicked. My Code : $(document).ready(function(){ $('.blueflip').hide(); $('.link_button').click(function() { $('.blueflip').toggle(400); return false; }); }); It works fine. But my problem is, my page has multiple link_button and blueflip div's all over the page. when i click any one of link_button all of the blueflip div's are toggling. But i need to toggle the corresponding child blueflip div only Note : The divs are dynamically generated from database. How to achieve that, Plz help. Any suggestion will be highly appreciated

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  • JS - Why is this hidden div not showing in IE?

    - by Dodi300
    Hello. I've made a page which should show a div when the user clicks on a input text box. The div will contain more information about the required input, etc. The page works fine on FireFox and the div shows, but when using IE the div just doesn't show. It seems like I've tried everything and nothing has worked so far. This is the page. Maybe you could look at the source and see what I'm doing wrong? If you need me to upload the source as a text file, I can do that. Thanks for the help!

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  • PageableListView Not rendering my data as required

    - by Robin
    i am working on wicket, where i am supposed to show my data's under <tr> <td>Name</td> <td>Single Player Score</td> <td>Double Player Score</td> <td>Total Score</td> </tr> <tr wicket:id="data"> <td wicket:id="name"></td> <td wicket:id="singlePlayerScore"></td> <td wicket:id="doublePlayerScore"></td> <td wicket:id="totalScore"></td> </tr> My Player model class is as: Player class with attributes singlePlayerScore, doublePlayerScore(), name with getter and setter and also a list data obtained from database. Data from SQLQuery is as; name score gamemode A 200 singlePlayerMode A 100 doublePLayerMode B 400 singlePlayerMode B 300 doublePLayerMode dataList == player.getScoreList(); My PageableListView is as: final PageableListView listView = new PageableListView("data",dataList,10){ @Override protected void populateItem(Item item){ player = (Player)item.getModelObject(); item.add(Label("name",player.getName())); item.add(Label("singlePlayerScore",player.getName())); item.add(Label("doublePlayerScore",player.getName())); item.add(Label("totalScore",String.valueOf(player.getSinglePlayerScore()+player.getDoublePlayerScore()))); } } My Problem is as: What view i get is as: Name single Player Score Double Player Score Total Score A 0 100 100 A 200 0 200 B 0 300 300 B 400 0 400 How do i achieve below view on my webpage? Name single Player Score Double Player Score Total Score A 200 100 300 B 400 300 700 Please help me as to why is this happening? I guess my list has size four that's one reason why as to it is rendering the view? So what can i do to get as require rendering view?

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  • How to create a proxy server?

    - by Rakesh Juyal
    I want to create a proxy server. I googled it and even found some tutorial but those were in PHP. If somebody is having tutorial of proxy server creation in java then please post it here Or simply let me know what approach should i follow to create a proxy server. [ i will be using Tomcat { if that matters for your answer } ] Thanks

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