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  • Java Disabled JLabel Reports Mouse Clicked

    - by ikurtz
    colLabels[i].addMouseListener(new MyAdapter()); private class MyAdapter extends MouseAdapter { @Override public void mouseClicked(MouseEvent event) { ColJLabel colJLabel = (ColJLabel)event.getComponent(); System.out.println(colJLabel.ColID); setColumnHeader(false); } } colLabels[i].setEnabled(flag); The situation is this: Mouse clicks are trapped correctly but when i have the JLabel (ColJLabel) control disabled it still reports mouse clicks. How can I make so that mouse clicks are only reported when the control is enabled? Thanks.

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  • Passing mix of T and T[] to a Java varargs method

    - by rfalke
    Suppose you have a Java method void foobar(int id, String ... args) and want to pass both String arrays and Strings into the method. Like this String arr1[]={"adas", "adasda"}; String arr2[]={"adas", "adasda"}; foobar(0, "adsa", "asdas"); foobar(1, arr1); foobar(2, arr1, arr2); foobar(3, arr1, "asdas", arr2); In Python there is "*" for this. Is there some way better than such rather ugly helper method: static String[] concat(Object... args) { List<String> result = new ArrayList<String>(); for (Object arg : args) { if (arg instanceof String) { String s = (String) arg; result.add(s); } else if (arg.getClass().isArray() && arg.getClass().getComponentType().equals(String.class)) { String arr[] = (String[]) arg; for (String s : arr) { result.add(s); } } else { throw new RuntimeException(); } } return result.toArray(new String[result.size()]); } which allows foobar(4, concat(arr1, "asdas", arr2));

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  • Using Java method to display HTML code

    - by javArc
    Hey folks, ok so this is my problem, I need to display HTML code in a jsp, which wouldn't be a problem, except a requirement for this project is that we place all the code in a public class file and have seperate methods for each chunk(header, sidebar footer, etc). Now here's where i'm confused: "Your method should take the PrintWriter as a parameter to print out each line of HTML, and should have a return type of void" What does that mean? How do I pass the PrintWriter into a method? Does this make sense to anyone?

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  • Thread Code...anything wrong with this, must use java 1.4

    - by bmw0128
    I have a servlet automatically firing up when the app server starts, and in its init(), I'm making another thread: init(){ new FooThread() } in FooThread(), i want to periodically check the status of a DB value, then depending on the value, make a web service call. When these two tasks complete, I want the thread to sleep to wait a certain period then repeat. This cycle would just continue forever. FooThread: public class FooThread implements Runnable{ Thread t; FooThread(){ t = new Thread(this, "BBSThread"); logger.info("*** about to start " + t.getName()); t.start(); logger.info("*** started: " + t); } public void run() { try{ while(true){ //do the db check, then conditionally do the web services call logger.info("*** calling sleep() ***"); Thread.sleep(50000); logger.info("*** now awake ***"); } } catch (InterruptedException e) { System.out.println("*** FooThread interrupted"); } } }

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  • In Eclipse, how do I change the default modifiers in the class/type template?

    - by gustafc
    Eclipse's default template for new types (Window Preferences Code Style Code Templates New Java Files) looks like this: ${filecomment} ${package_declaration} ${typecomment} ${type_declaration} Creating a new class, it'll look something like this: package pkg; import blah.blah; public class FileName { // Class is accessible to everyone, and can be inherited } Now, I'm fervent in my belief that access should be as restricted as possible, and inheritance should be forbidden unless explicitly permitted, so I'd like to change the ${type_declaration} to declare all classes as final rather than public: package pkg; import blah.blah; final class FileName { // Class is only accessible in package, and can't be inherited } That seems easier said than done. The only thing I've found googling is a 2004 question on Eclipse's mailing list which was unanswered. So, the question in short: How can I change the default class/type modifiers in Eclipse? I'm using Eclipse Galileo (3.5) if that matters.

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  • Creating a 2d matrix from an array (java)

    - by anna
    I'm supposed to write a method that creates a 2d matrix from an array, for instance: ({1, 2, 3, 4}, 3) should return the matrix {{1, 2, 3}, {4}} public class Matrix { public static int[][]toM(int[] array, int a) { int[][]matrix = new int [(array.length + a- 1)/ a][a]; for (int i = 0; i < array.length; i++){ int value = array[i]; value = value++; for (int row = 0; row < (array.length + a- 1)/a; row++) { for (int col = 0; col < a; col++) { matrix[row][col]= value++; } } } return matrix; } } I'm getting [[4, 5, 6], [7, 8, 9]]?

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  • post increment operator java

    - by srandpersonia
    I can't make heads or tails of the following code from "java puzzlers" by joshua bloch. public class Test22{ public static void main(String args[]){ int j=0; for(int i=0;i<100;i++){ j=j++; } System.out.println(j); //prints 0 int a=0,b=0; a=b++; System.out.println(a); System.out.println(b); //prints 1 } } I can't get the part where j prints 0. According to the author, j=j++ is similar to temp=j; j=j+1; j=temp; But a=b++ makes b 1. So it should've evaluated like this, a=b b=b+1 By following the same logic, shouldn't j=j++ be evaluated as, j=j j=j+1 Where does the temp come into picture here? Any explanations would be much appreciated. << I'm breaking my head over this. ;) Thanks in advance.

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  • Exporting to CSV/Excel in Java

    - by WIOijwww
    I'm trying to export data into a CSV file through Java and I've got some code to do it but it doesn't seem to be outputting the CSV file. Could someone tell me what's wrong? What I would like to do is rather than saving the file somewhere, I would like it to be directly exported to the user. EDIT: Just in case it's not clear, I don't want the file to be saved anywhere but would like it to be outputted automatically to the user i.e. they click export and get the "Run/Save results.csv" window and they open the file. Currently the file is getting saved so I know that the method seems to work, just in the opposite way that I want it to. public static void writeToCSV(List<Map> objectList) { String CSV_SEPARATOR = ","; try { BufferedWriter bw = new BufferedWriter(new OutputStreamWriter( new FileOutputStream("results.csv"), "UTF-8")); for (Map objectDetails : objectList) { StringBuffer oneLine = new StringBuffer(); Iterator it = objectDetails.values().iterator(); while (it.hasNext()) { Object value = it.next(); if(value !=null){ oneLine.append(value.toString()); } if (it.hasNext()) { oneLine.append(CSV_SEPARATOR); } } bw.write(oneLine.toString()); bw.newLine(); } bw.flush(); bw.close(); } catch (UnsupportedEncodingException e) { } catch (FileNotFoundException e) { } catch (IOException e) { } }

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  • UTF-8 support in java application

    - by jacekn
    I'm having trouble with UTF-8. common.jsp <%@ page language="java" contentType="text/html; charset=UTF-8" pageEncoding="UTF-8"%> typical.jsp <%@ include file="common.jsp" %> Page Head <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> Form <form id="screenObject" accept-charset="UTF-8" action="/SiteAdmin/articleHeaderEdit?articleId=15" method="post"> I enter non latin1 characters into a text field and click Save. Validator complains about another field and stops the submission. This never gets to the database, so database ability to handle UTF-8 is not in this picture. The page redisplays with appropriate error but the text that had been entered is all messed up. All non latin1 characters are converted to some gibberish. I'm using Spring 3 MVC, in case that matters... Attempts Adding this to my view resolver didn't help: <property name="contentType" value="text/html;charset=UTF-8" />

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  • Sorting a very large text file in Java

    - by Alice
    Hi, I have a large text file I need to sort in Java. The format is: word [tab] frequency [new line] The algorithm for sorting is: Read some of the file, filtering for purlely alphabetic words. Once you have X number of alphabetic words, call Collections.sort and write the result to a file. Repeat until you have finished reading the file. Start reading two sorted files, comparing line by line for the word with higher frequency, and writing at the same time to a new file as to not load much into your memory Repeat until all files are merged into one large file Right now I've divided the large file into smaller ones (sorted by descending frequency) with 10,000 lines each. I know I need to somehow merge these files back together, but I'm not sure how to go about this. I've created a LinkedList to keep track of all the files created. The algorithm says to compare each line in the two files, except I've tried a case where , say file1 = 8,6,5,3,1 and file2 = 9,8,8,8,8. Then if I compare them line by line I would get file3 = 9,8,8,6,8,5,8,3,8,1 which is incorrectly sorted (they should be in decreasing order). I think I'm misunderstanding some part of the algorithm. If someone could point out what I should do instead, I'd greatly appreciate it. Thanks. edit: Yes this is an assignment. We aren't allowed to increase memory unfortunately :(

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  • Java - Does null variable require space in memory

    - by Yatendra Goel
    class CheckStore { private String displayText; private boolean state; private String meaningfulText; private URL url; public CheckStore(String text, boolean state) { this.displayText = text; this.state = state; } : : } As I am initializing only two variables (displayText and state) in the constructor, Will the rest two variables (meaningfulText and url which will have the value null) will require space in memory to store null value. Q1. I think they will require space. If they will, then how much memory does a null value takes in the memory (like int takes 4 bytes). Q2. How much space a string takes in memory. I guess it will depend on the length of the string. So how much space a string takes of how much length?

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  • Parsing XML with XPath in Java

    - by Mg
    I have a XML with a structure similar to this: <category> <subCategoryList> <category> </category> <category> <!--and so on --> </category> </subCategoryList> </category> I have a Category class that has a subcategory list (List<Category>). I'm trying to parse this XML file with XPath, but I can't get the child categories of a category. How can I do this with XPath? is there a better way to do this? Thanks in advance.

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  • Java Object Array item to String Array

    - by user341264
    Say I have the following: Class myclass { public string stra ="", strb = "" myclass(String a, String b){stra=a;strb=b} } //then in the app I want to do: myclass myclassinst1 = new myclass("blah","xxxx"); myclass myclassinst2 = new myclass("blah2","yyyy"); myclass myclassinst3 = new myclass("blah3","zzzz"); list <myclass> mylist = new ArrayList<myclass>(); mylist.add(myclassinst1 ); mylist.add(myclassinst2 ); mylist.add(myclassinst3 ); //How would I then convert that to a String[] Array of all the stra elements without using a loop. //eg: String[] strarr_a = mylist.toarray(myclass.stra); String[] strarr_b = mylist.toarray(myclass.strb); //instead of having to do String[] strarr_a = new String[mylist.size()]; String[] strarr_b = new String[mylist.size()]; for (int i=0;i<mylist.size();i++) { strarr_a[i] = mylist.get(i).stra; strarr_b[i] = mylist.get(i).strb; }

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  • Vectors or Java arrays for Tetris?

    - by StackedCrooked
    I'm trying to create a Tetris-like game with Clojure and I'm having some trouble deciding the data structure for the playing field. I want to define the playing field as a mutable grid. The individual blocks are also grids, but don't need to be mutable. My first attempt was to define a grid as a vector of vectors. For example an S-block looks like this: :s-block { :grids [ [ [ 0 1 1 ] [ 1 1 0 ] ] [ [ 1 0 ] [ 1 1 ] [ 0 1 ] ] ] } But that turns out to be rather tricky for simple things like iterating and painting (see the code below). For making the grid mutable my initial idea was to make each row a reference. But then I couldn't really figure out how to change the value of a specific cell in a row. One option would have been to create each individual cell a ref instead of each row. But that feels like an unclean approach. I'm considering using Java arrays now. Clojure's aget and aset functions will probably turn out to be much simpler. However before digging myself in a deeper mess I want to ask ideas/insights. How would you recommend implementing a mutable 2d grid? Feel free to share alternative approaches as well. Source code current state: Tetris.clj (rev452)

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  • java.awt.Desktop.open doesn’t work with PDF files?

    - by Jason S
    It looks like I cannot use Desktop.open() on PDF files regardless of location. Here's a small test program: package com.example.bugs; import java.awt.Desktop; import java.io.File; import java.io.IOException; public class DesktopOpenBug { static public void main(String[] args) { try { Desktop desktop = null; // Before more Desktop API is used, first check // whether the API is supported by this particular // virtual machine (VM) on this particular host. if (Desktop.isDesktopSupported()) { desktop = Desktop.getDesktop(); for (String path : args) { File file = new File(path); System.out.println("Opening "+file); desktop.open(file); } } } catch (IOException e) { e.printStackTrace(); } } } If I run DesktopOpenBug with arguments c:\tmp\zz1.txt c:\tmp\zz.xml c:\tmp\ss.pdf (3 files I happen to have lying around) I get this result: (the .txt and .xml files open up fine) Opening c:\tmp\zz1.txt Opening c:\tmp\zz.xml Opening c:\tmp\ss.pdf java.io.IOException: Failed to open file:/c:/tmp/ss.pdf. Error message: The parameter is incorrect. at sun.awt.windows.WDesktopPeer.ShellExecute(Unknown Source) at sun.awt.windows.WDesktopPeer.open(Unknown Source) at java.awt.Desktop.open(Unknown Source) at com.example.bugs.DesktopOpenBug.main(DesktopOpenBug.java:21) What the heck is going on? I'm running WinXP, I can type "c:\tmp\ss.pdf" at the command prompt and it opens up just fine. edit: if this is an example of Sun Java bug #6764271 please help by voting for it. What a pain. :(

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  • list all files from directories and subdirectories in Java

    - by Adnan
    What would be the fastest way to list the names of files from 1000+ directories and sub-directories? EDIT; The current code I use is: import java.io.File; public class DirectoryReader { static int spc_count=-1; static void Process(File aFile) { spc_count++; String spcs = ""; for (int i = 0; i < spc_count; i++) spcs += " "; if(aFile.isFile()) System.out.println(spcs + "[FILE] " + aFile.getName()); else if (aFile.isDirectory()) { System.out.println(spcs + "[DIR] " + aFile.getName()); File[] listOfFiles = aFile.listFiles(); if(listOfFiles!=null) { for (int i = 0; i < listOfFiles.length; i++) Process(listOfFiles[i]); } else { System.out.println(spcs + " [ACCESS DENIED]"); } } spc_count--; } public static void main(String[] args) { String nam = "D:/"; File aFile = new File(nam); Process(aFile); } }

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  • [java] tcp socket communication [send and recieve help]

    - by raven
    hello, I am creating a Chat in java. I have a method (onMouseRelease) inside an object that creates a tcp server and waits for a socket ServerSocket server = new ServerSocket(port); Socket channel = server.accept(); now I want to make a thread that will loop and read data from the socket, so that once the user on the other side sent me a string, I will extract the data from the socket [or is it called packet? sry I am new to this], and update a textbox to add the additional string from the socket [or packet?]. I have no idea how to READ (extract) the information from the scoket [/packet] and then update it into a JTextArea which is called userOutput. And how to Send a string to the other client, so that it will also could read the new data and update its JTextArea. (from what I know, for a 2 sided tcp communication you need one computer to host a server and the other to connect [as a client] and once the connection is set the client can also recieve new information from the socket. Is that true? and please tell me how ) Any help appreciated !! I know this is abit long but I have searched allot and didn't understand [I saw something like printwriter but failed to understand].

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  • Replacing XML in File from "Document" in Java

    - by poeschlorn
    Hi, after processing my first steps in working with XML in java I am now at the point where I want to update some data in my XML/GPX file... Reaplacing it in my "Document" data type works great :) How here comes the question: how can I store the changed "document"-model back to my file? Do I have to do this by using the standart file-functions (via steams and so on) oder is the a more elegant way to do this? ;-) Here's the code I already worked out, maybe that could help. (the method getParsedXML is just puting the conversion from the file into an extra method) Document tmpDoc = getParsedXML(currentGPX); //XML Parsind tests: // Access to tag attribute <tag attribut="bla"> System.out.println(tmpDoc.getElementsByTagName("wpt").item(0).getAttributes().getNamedItem("lat").getTextContent()); // Access to the value of an child element <a><CHILD>ValueOfChild</CHILD></a> System.out.println(tmpDoc.getElementsByTagName("wpt").item(0).getChildNodes().item(5).getTextContent()); // Replacing access to tag attribute tmpDoc.getElementsByTagName("wpt").item(0).getAttributes().getNamedItem("lat").setTextContent("139.921055008"); System.out.println(tmpDoc.getElementsByTagName("wpt").item(0).getAttributes().getNamedItem("lat").getTextContent()); // Replacing access to child element value tmpDoc.getElementsByTagName("wpt").item(0).getChildNodes().item(5).setTextContent("Cala Sant Vicenç - Mallorca 2"); System.out.println(tmpDoc.getElementsByTagName("wpt").item(0).getChildNodes().item(5).getTextContent());

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  • Java: over-typed structures? To have many types in Object[]?

    - by HH
    Term over-type structure = a data structure that accepts different types, can be primitive or user-defined. I think ruby supports many types in structures such as tables. I tried a table with types 'String', 'char' and 'File' in Java but errs. How can I have over-typed structure in Java? How to show types in declaration? What about in initilization? Suppose a structure: INDEX VAR FILETYPE //0 -> file FILE //1 -> lineMap SizeSequence //2 -> type char //3 -> binary boolean //4 -> name String //5 -> path String Code import java.io.*; import java.util.*; public class Object { public static void print(char a) { System.out.println(a); } public static void print(String s) { System.out.println(s); } public static void main(String[] args) { Object[] d = new Object[6]; d[0] = new File("."); d[2] = 'T'; d[4] = "."; print(d[2]); print(d[4]); } } Errors Object.java:18: incompatible types found : java.io.File required: Object d[0] = new File("."); ^ Object.java:19: incompatible types found : char required: Object d[2] = 'T'; ^

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  • Put an array of Objects in nodes of another array of Objects [JAVA]

    - by zengr
    public class hello { public static void main(String[] args) { Object[] newarray = new Object[1]; Object[] obj = new Object[2]; obj[0] = "Number1"; //string value obj[1] = "Number2"; //string value newarray[0] = obj; //this works Object[] tmp_obj = new Object[2]; tmp_obj = newarray[0]; //obviously does not work System.out.println(tmp_obj[0]); //nope System.out.println(tmp_obj[1]); //nope } } So, now if I want to access the values "Number1" and "Number2" which are stored in obj[0] and obj[1]; obj is in newarray[0]. what should I do? Is this a possible? Thanks

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  • Simple Java math operations

    - by user1730056
    I'm making a BMI calculator that doesn't seem to be working. The math operations work if i just do something like w/h, but once i had the brackets, it returns an error. If i change the variables w and h and use a constant number, the operation works. Another problem is that although i'm making result a double, it seems to be rounding to the nearest int. Could someone tell me what I'm doing wrong here? public class ass10 { public static void main(String[] args) { bmi(223,100); } public static bmi(int w, int h){ double result; result = (w/(h*h))*703 System.out.println(result) } }

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  • Java: empty ArrayLists in a foor loop

    - by Patrick
    hi, I'm reusing the same ArrayList in a for loop, and I use for loop results = new ArrayList<Integer>(); experts = new ArrayList<Integer>(); output = new ArrayList<String>(); .... to create new ones. I guess this is wrong, because I'm allocating new memory. Is this correct ? If yes, how can I empty them ? Added: another example I'm creating new variables each time I call this method. Is this good practice ? I mean to create new precision, relevantFound.. etc ? Or should I declare them in my class, outside the method to not allocate more and more memory ? public static void computeMAP(ArrayList results, ArrayList experts) { //compute MAP double precision = 0; int relevantFound = 0; double sumprecision = 0; thanks

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  • Java Socket - how to catch Exception of BufferedReader.readline()

    - by Hasan Tahsin
    I have a Thread (let's say T1) which reads data from socket: public void run() { while (running) { try { BufferedReader reader = new BufferedReader( new InputStreamReader(socket.getInputStream()) ); String input = reader.readLine(); } catch (IOException e) { e.printStackTrace(); } } } Another Thread (lets say T2) try to finish the program in one of its method. Therefore T2 does the following: T1.running = false; socket.close(); Here is this scenario for which i couldn't find a solution: T1 is active and waiting for some input to read i.e. blocking. context switching T2 is active and sets running to false, closes the socket context switching because T1 was blocking and T2 closed the socket, T1 throws an Exception. What i want is to catch this SocketException. i can't put a try/catch(SocketException) in T1.run(). So how can i catch it in T1's running-method? If it's not possible to catch it in T1's running, then how can i catch it elsewhere? PS: "Another question about the Thread Debugging" Normally when i debug the code step by step, i lose the 'active running line' on a context switch. Let's say i'm in line 20 of T1, context switch happens, let's assume the program continues from the 30.line of T2, but the debugger does not go/show to the 30.line of T2, instead the 'active running line' vanishes. So i lose the control over the code. I use Eclipse for Java and Visual Studio for C#. So what is the best way to track the code while debugging on a context switch ?

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  • Java: "cannot find symbol" error of a String[] defined within a while-loop

    - by David
    Here's the relevant code: public static String[] runTeams (String CPUcolor) { boolean z = false ; //String[] a = new String[6] ; boolean CPU = false ; while (z == false) { while (CPU==false) { String[] a = assignTeams () ; printOrder (a) ; for (int i = 1; i<a.length; i++) { if (a[i].equals(CPUcolor)) CPU = true ; } if (CPU==false) { System.out.println ("ERROR YOU NEED TO INCLUDE THE COLOR OF THE CPU IN THE TURN ORDER") ; } } System.out.println ("is this turn order correct? (Y/N)") ; String s = getIns () ; while (!((s.equals ("y")) || (s.equals ("Y")) || (s.equals ("n")) || (s.equals ("N")))) { System.out.println ("try again") ; s = getIns () ; } if (s.equals ("y") || s.equals ("Y") ) z = true ; } return a ; } the error i get is: Risk.java:416: cannot find symbol symbol : variable a location: class Risk return a ; ^ Why did i get this error? It seems that a is clearly defined in the line String[] a = assignTeams () ; and if anything is used by the lineprintOrder (a) ;` it seems to me that if the symbol a really couldn't be found then the compiler should blow up there and not at the return statment. (also the method assignTeams returns an array of Strings.)

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  • Problem with Java Scanner sc.nextLine();

    - by Jonathan B
    Hi, sry about my english :) Im new to Java programming and i have a problem with Scanner. I need to read an Int, show some stuff and then read a string so i use sc.nextInt(); show my stuff showMenu(); and then try to read a string palabra=sc.nextLine(); Some one told me i need to use a sc.nextLine(); after sc.nextInt(); but i dont understand why do you have to do it :( Here is my code: public static void main(String[] args) { // TODO code application logic here Scanner sc = new Scanner(System.in); int respuesta = 1; showMenu(); respuesta = sc.nextInt(); sc.nextLine(); //Why is this line necessary for second scan to work? switch (respuesta){ case 1: System.out.println("=== Palindromo ==="); String palabra = sc.nextLine(); if (esPalindromo(palabra) == true) System.out.println("Es Palindromo"); else System.out.println("No es Palindromo"); break; } } Ty so much for your time and Help :D

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