Search Results

Search found 37316 results on 1493 pages for 'model view controller'.

Page 311/1493 | < Previous Page | 307 308 309 310 311 312 313 314 315 316 317 318  | Next Page >

  • with "viewDidLoad" my viewController take much time to appear!

    - by dingua
    hi, when i load my viewController i used "viewDidLoad"method to init my view ,but this take much time to make the view appeared .So i had the idea to use "viewDidAppear" method to accelerate the appearance of my view but the load of the informations about my view are now loaded to the memory every time that i push my view (which is normal) or i pop to it(and there is my problem) Have you an idea?

    Read the article

  • invoke a method on the click of backbutton

    - by praseed
    hi friends... Does anyone know how can i invoke a method on the click of the backbarButton of a viewcontroller... wat i have are two table view controllers..one list view and another detail view.... the detail view is pushed in to the navigation controller when an item is clicked in the list view. when the Back bar button is clicked i want to invoke a function... Pls any help will be appreciated..

    Read the article

  • A question is related to state maintainance

    - by user217572
    my question is like that My 5 th view is Acontroller and it has 1 UIButton.when i click on this UIButton my Bcontroller's view opens.this operation wrks perfectly. but i'm actually doing state maintainanace.when i reach to 5 th view of Acontroller.after that i press home button and then when i again click on application as per my state maintainance code 5 th view of Acontroller opens .but when i click on it's UIButton Bcontroller's view not open.why A code of UIButton is as below [self.navigationController pushViewController:bcontroller animated:YES]; bcontroller is nothing but object of Bcontroller

    Read the article

  • what's the right way to cause a subview to redraw when the device orientation changes?

    - by RobertL
    I have a view controller with a view and one subview. When the device orientation changes the view auto-redraws but the subview doesn't. If I explicitly do [subview setNeedsDisplay] it redraws but I don't have a logical place to put that call in my code. And, since I don't have to explicitly tell the view to redraw, it seems counter-intuitive to tell the subview to redraw. Is there a way to make the subview auto-redraw when the view redraws?

    Read the article

  • Stack Info button above UIView in Utility App

    - by bgw
    I've started creating a iPhone Utility app (main view and flip view). I want to draw some graphics in the Main view, so I dragged a UIView object onto it. This works, but I find that if I resize the UIView to fill the Main view, it covers the Info button that invokes the Flip view. Is there any way to get the Info button to appear on top of the UIView? In IB? In code?

    Read the article

  • How to change the default "double click" action of a web service in a class library (VS2010)?

    - by JL
    I have a web service defined as follows, residing in a class library: [WebService(Namespace = "http://comp.com/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] // To allow this Web Service to be called from script, using ASP.NET AJAX, uncomment the following line. // [System.Web.Script.Services.ScriptService] public class SendingItems_new : System.Web.Services.WebService When I double click it, instead of going to code view, it shows the design view. I NEVER use design view, so how can I get it to open up code view instead, its very annoying having to flick from design view each time. Thank you

    Read the article

  • Configuring JPA Primary key sequence generators

    - by pachunoori.vinay.kumar(at)oracle.com
    This article describes the JPA feature of generating and assigning the unique sequence numbers to JPA entity .This article provides information on jpa sequence generator annotations and its usage. UseCase Description Adding a new Employee to the organization using Employee form should assign unique employee Id. Following description provides the detailed steps to implement the generation of unique employee numbers using JPA generators feature Steps to configure JPA Generators 1.Generate Employee Entity using "Entities from Table Wizard". View image2.Create a Database Connection and select the table "Employee" for which entity will be generated and Finish the wizards with default selections. View image 3.Select the offline database sources-Schema-create a Sequence object or you can copy to offline db from online database connection. View image 4.Open the persistence.xml in application navigator and select the Entity "Employee" in structure view and select the tab "Generators" in flat editor. 5.In the Sequence Generator section,enter name of sequence "InvSeq" and select the sequence from drop down list created in step3. View image 6.Expand the Employees in structure view and select EmployeeId and select the "Primary Key Generation" tab.7.In the Generated value section,select the "Use Generated value" check box ,select the strategy as "Sequence" and select the Generator as "InvSeq" defined step 4. View image   Following annotations gets added for the JPA generator configured in JDeveloper for an entity To use a specific named sequence object (whether it is generated by schema generation or already exists in the database) you must define a sequence generator using a @SequenceGenerator annotation. Provide a unique label as the name for the sequence generator and refer the name in the @GeneratedValue annotation along with generation strategy  For  example,see the below Employee Entity sample code configured for sequence generation. EMPLOYEE_ID is the primary key and is configured for auto generation of sequence numbers. EMPLOYEE_SEQ is the sequence object exist in database.This sequence is configured for generating the sequence numbers and assign the value as primary key to Employee_id column in Employee table. @SequenceGenerator(name="InvSeq", sequenceName = "EMPLOYEE_SEQ")   @Entity public class Employee implements Serializable {    @Id    @Column(name="EMPLOYEE_ID", nullable = false)    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator="InvSeq")   private Long employeeId; }   @SequenceGenerator @GeneratedValue @SequenceGenerator - will define the sequence generator based on a  database sequence object Usage: @SequenceGenerator(name="SequenceGenerator", sequenceName = "EMPLOYEE_SEQ") @GeneratedValue - Will define the generation strategy and refers the sequence generator  Usage:     @GeneratedValue(strategy = GenerationType.SEQUENCE, generator="name of the Sequence generator defined in @SequenceGenerator")

    Read the article

  • Getting Started With Sinatra

    - by Liam McLennan
    Sinatra is a Ruby DSL for building web applications. It is distinguished from its peers by its minimalism. Here is hello world in Sinatra: require 'rubygems' require 'sinatra' get '/hi' do "Hello World!" end A haml view is rendered by: def '/' haml :name_of_your_view end Haml is also new to me. It is a ruby-based view engine that uses significant white space to avoid having to close tags. A hello world web page in haml might look like: %html %head %title Hello World %body %div Hello World You see how the structure is communicated using indentation instead of opening and closing tags. It makes views more concise and easier to read. Based on my syntax highlighter for Gherkin I have started to build a sinatra web application that publishes syntax highlighted gherkin feature files. I have found that there is a need to have features online so that customers can access them, and so that they can be linked to project management tools like Jira, Mingle, trac etc. The first thing I want my application to be able to do is display a list of the features that it knows about. This will happen when a user requests the root of the application. Here is my sinatra handler: get '/' do feature_service = Finding::FeatureService.new(Finding::FeatureFileFinder.new, Finding::FeatureReader.new) @features = feature_service.features(settings.feature_path, settings.feature_extensions) haml :index end The handler and the view are in the same scope so the @features variable will be available in the view. This is the same way that rails passes data between actions and views. The view to render the result is: %h2 Features %ul - @features.each do |feature| %li %a{:href => "/feature/#{feature.name}"}= feature.name Clearly this is not a complete web page. I am using a layout to provide the basic html page structure. This view renders an <li> for each feature, with a link to /feature/#{feature.name}. Here is what the page looks like: When the user clicks on one of the links I want to display the contents of that feature file. The required handler is: get '/feature/:feature' do @feature_name = params[:feature] feature_service = Finding::FeatureService.new(Finding::FeatureFileFinder.new, Finding::FeatureReader.new) # TODO replace with feature_service.feature(name) @feature = feature_service.features(settings.feature_path, settings.feature_extensions).find do |feature| feature.name == @feature_name end haml :feature end and the view: %h2= @feature.name %pre{:class => "brush: gherkin"}= @feature.description %div= partial :_back_to_index %script{:type => "text/javascript", :src => "/scripts/shCore.js"} %script{:type => "text/javascript", :src => "/scripts/shBrushGherkin.js"} %script{:type => "text/javascript" } SyntaxHighlighter.all(); Now when I click on the Search link I get a nicely formatted feature file: If you would like see the full source it is available on bitbucket.

    Read the article

  • Error about 'invalid JSON' with couchDB view but the json's fine...

    - by Chris Huang-Leaver
    I am trying to setup the following view on CouchDB { "_id":"_design/id", "_rev":"1-9be2e55e05ac368da3047841f301203d", "language":"javascript", "views":{ "by_id":{ "map" : "function(doc) { emit(doc.id, doc)}" },"from_user_id":{ "map" : "function(doc) { if (doc.from_user_id) {emit(doc.from_user_id, doc)}}"}, "from_user":{ "map" : "function(doc) { if (doc.from_user) {emit(doc.from_user, doc)}}"}, "to_user_id":{ "map" : "function(doc) {if (doc.to_user_id){ emit(doc.to_user_id, doc)}}"}, "to_user":{ "map" : "function(doc) {if (doc.to_user){ emit(doc.to_user, doc)}}" }, "max_id":{ "map" : "function(doc) { if (doc.id) {emit(doc._id, eval(doc.id))}}", "reduce" :"function(key,value) { a = value[0]; for (i=1; i <value.length; ++i){a = Math.max(a,value[i])} return a}" } } } when I try to 'PUT' this using curl: curl -X PUT -d keys.json $CDB/_design/id {"error":"bad_request","reason":"invalid UTF-8 JSON"} I know it's not invalid JSON, because I tested it using the 'json' library built into Python 2.6, it loads fine. JS screw ups give me the error 'must evaluate to a function' What else might be wrong with it?

    Read the article

  • How to display the image in the web view using html code?

    - by Madan Mohan
    Hi Guys, I am getting the data form Parser, In that I am getting a set of urls. Using these urls can I make image url by appending any data values getting from the parser. http://musicbrainz.org/ws/1/artist/f27ec8db-af05-4f36-916e-3d57f91ecf5e?type=xml&inc=url-rels+artist-rels using these url i get data and set of urls.They are not providing image url or thumbnail. So, Is it possible to get or form an image url from parser (http://musicbrainz.org/ws/1/artist/f27ec8db-af05-4f36-916e-3d57f91ecf5e?type=xml&inc=url-rels+artist-rels) and display in the web view. Please help me from this problem. Thank You, Madan Mohan.

    Read the article

  • How to add a pulldown button in a view's toolbar?

    - by madgnome
    I need to add a pulldown button to a view's toolbar in an Eclipse plugin. Actually buttons in the toolbar are added like that : <extension point="org.eclipse.ui.viewActions"> <viewContribution id="..." targetId="$MyViewId$"> <action id="..." toolbarPath="action1" class="Class extending Action and implementing IViewActionDelegate"> </action> </viewContribution> </extension>

    Read the article

  • How set panel Default Button that is inside a details view in asp.net?

    - by Avinash
    <asp:panel ID="Panel1" runat="server"> <asp:DetailsView ID="DetailsView1" .... <asp:templatefield ShowHeader="False"> <insertitemtemplate> <asp:Button ID="btnAdd" runat="server" CausesValidation="True" CommandName="Insert" Text="Insert"></asp:Button> ... <asp:DetailsView> </asp:panel> and i write the code for setting the panels default button in details view's DataBound event Button btnAdd = new Button(); btnAdd = DetailsView1.Rows[indexNumber].FindControl("btnAdd") as Button; Panel1.DefaultButton = btnAdd.UniqueID; but I get the error : The DefaultButton of 'Panel1' must be the ID of a control of type IButtonControl.

    Read the article

  • How can I set a highlighted image on a table view cell?

    - by nevan
    I've followed the code in Apple's AdvancedTableViewCells and built a table view with a background image for cells. Now I want to change it so that instead of the blue highlight colour, it shows a darker version of my image. What are the steps I need to follow to do this? I'm using a UITableViewCell subclass with a custom NIB. My background image is implemented as the cell.backgroundView. The steps I've take so far are: Change the selectionStyle of the cell to "None" Set the Highlight colour on my UILabel subviews to a light colour Create a darker version of my background as a separate image Override setSelected: animated: I'm wondering about the next steps.

    Read the article

  • How can I get a view of favorite user documents by user in Couchdb map/reduce?

    - by Jeremy Raymond
    My Couchdb database as a main document type that looks something like: { "_id" : "doc1", "type" : "main_doc", "title" : "the first doc" ... } There is another type of document that stores user information. I want users to be able to tag documents as favorites. Different users can save the same or different documents as favorites. My idea was to introduce a favorite document to track this something like: { "_id" : "fav1", "type" : "favorite", "user_id" : "user1", "doc_id" : "doc1" } It's easy enough to create a view with user_id as the key to get a list of their favorite doc IDs. E.g: function(doc) { if (doc.type == "favorite") { emit(doc.user_id, doc.doc_id); } } However I want to list of favorites to display the user_id, doc_id and title from the document. So output something like: { "key" : "user1", "value" : ["doc1", "the first doc"] }

    Read the article

  • How can a user view profile info of other users?

    - by Arvind Singh
    I have stored profile info using this code ProfileBase userprofile = HttpContext.Current.Profile; userprofile.SetPropertyValue("FirstName", TextBoxFirstName.Text); userprofile.SetPropertyValue("LastName", TextBoxLastName.Text); userprofile.SetPropertyValue("AboutMe", TextBoxAboutMe.Text); userprofile.SetPropertyValue("ContactNo", TextBoxContactNo.Text); and in web.config <profile enabled="true" defaultProvider="AspNetSqlProfileProvider"> <properties> <add name="FirstName" type="String" /> <add name="LastName" type="String" /> <add name="AboutMe" type="String" /> <add name="ContactNo" type="String" /> </properties> </profile> The profile info is stored and every user is able to view his own profile info using something like this TextBoxFirstName.Text = HttpContext.Current.Profile.GetPropertyValue("FirstName").ToString(); How to fetch profile info of other user say a user types the username of other user in a text box and clicks a button?

    Read the article

  • MVC 3 Remote Validation jQuery error on submit

    - by Richard Reddy
    I seem to have a weird issue with remote validation on my project. I am doing a simple validation check on an email field to ensure that it is unique. I've noticed that unless I put the cursor into the textbox and then remove it to trigger the validation at least once before submitting my form I will get a javascript error. e[h] is not a function jquery.min.js line 3 If I try to resubmit the form after the above error is returned everything works as expected. It's almost like the form tried to submit before waiting for the validation to return or something. Am I required to silently fire off a remote validation request on submit before submitting my form? Below is a snapshot of the code I'm using: (I've also tried GET instead of POST but I get the same result). As mentioned above, the code works fine but the form returns a jquery error unless the validation is triggered at least once. Model: public class RegisterModel { [Required] [Remote("DoesUserNameExist", "Account", HttpMethod = "POST", ErrorMessage = "User name taken.")] [Display(Name = "User name")] public string UserName { get; set; } [Required] [Display(Name = "Firstname")] public string Firstname { get; set; } [Display(Name = "Surname")] public string Surname { get; set; } [Required] [Remote("DoesEmailExist", "Account", HttpMethod = "POST", ErrorMessage = "Email taken.", AdditionalFields = "UserName")] [Display(Name = "Email address")] public string Email { get; set; } [StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = 8)] [DataType(DataType.Password)] [Display(Name = "Password")] public string Password { get; set; } [StringLength(100, ErrorMessage = "The {0} must be at least {2} characters long.", MinimumLength = 8)] [DataType(DataType.Password)] [Display(Name = "Confirm password")] public string ConfirmPassword { get; set; } [Display(Name = "Approved?")] public bool IsApproved { get; set; } } public class UserRoleModel { [Display(Name = "Assign Roles")] public IEnumerable<RoleViewModel> AllRoles { get; set; } public RegisterModel RegisterUser { get; set; } } Controller: // POST: /Account/DoesEmailExist // passing in username so that I can ignore the same email address for the same user on edit page [HttpPost] public JsonResult DoesEmailExist([Bind(Prefix = "RegisterUser.Email")]string Email, [Bind(Prefix = "RegisterUser.UserName")]string UserName) { var user = Membership.GetUserNameByEmail(Email); if (!String.IsNullOrEmpty(UserName)) { if (user == UserName) return Json(true); } return Json(user == null); } View: <script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js" type="text/javascript"></script> <script src="//ajax.googleapis.com/ajax/libs/jqueryui/1.8.17/jquery-ui.min.js" type="text/javascript"></script> <script type="text/javascript" src="/Content/web/js/jquery.unobtrusive-ajax.min.js"></script> <script type="text/javascript" src="/Content/web/js/jquery.validate.min.js"></script> <script type="text/javascript" src="/Content/web/js/jquery.validate.unobtrusive.min.js"></script> ...... @using (Html.BeginForm()) { @Html.AntiForgeryToken() <div class="titleh"> <h3>Edit a user account</h3> </div> <div class="body"> @Html.HiddenFor(model => model.RegisterUser.UserName) @Html.Partial("_CreateOrEdit", Model) <div class="st-form-line"> <span class="st-labeltext">@Html.LabelFor(model => model.RegisterUser.IsApproved)</span> @Html.RadioButtonFor(model => model.RegisterUser.IsApproved, true, new { @class = "uniform" }) Active @Html.RadioButtonFor(model => model.RegisterUser.IsApproved, false, new { @class = "uniform" }) Disabled <div class="clear"></div> </div> <div class="button-box"> <input type="submit" name="submit" value="Save" class="st-button"/> @Html.ActionLink("Back to List", "Index", null, new { @class = "st-clear" }) </div> </div> } CreateEdit Partial View @model Project.Domain.Entities.UserRoleModel <div class="st-form-line"> <span class="st-labeltext">@Html.LabelFor(m => m.RegisterUser.Firstname)</span> @Html.TextBoxFor(m => m.RegisterUser.Firstname, new { @class = "st-forminput", @style = "width:300px" }) @Html.ValidationMessageFor(m => m.RegisterUser.Firstname) <div class="clear"></div> </div> <div class="st-form-line"> <span class="st-labeltext">@Html.LabelFor(m => m.RegisterUser.Surname)</span> @Html.TextBoxFor(m => m.RegisterUser.Surname, new { @class = "st-forminput", @style = "width:300px" }) @Html.ValidationMessageFor(m => m.RegisterUser.Surname) <div class="clear"></div> </div> <div class="st-form-line"> <span class="st-labeltext">@Html.LabelFor(m => m.RegisterUser.Email)</span> @Html.TextBoxFor(m => m.RegisterUser.Email, new { @class = "st-forminput", @style = "width:300px" }) @Html.ValidationMessageFor(m => m.RegisterUser.Email) <div class="clear"></div> </div> Thanks, Rich

    Read the article

  • PHP MVC Framework Structure

    - by bigstylee
    I am sorry about the amount of code here. I have tried to show enough for understanding while avoiding confusion (I hope). I have included a second copy of the code at Pastebin. (The code does execute without error/notice/warning.) I am currently creating a Content Management System while trying to implement the idea of Model View Controller. I have only recently come across the concept of MVC (within the last week) and trying to implement this into my current project. One of the features of the CMS is dynamic/customisable menu areas and each feature will be represented by a controller. Therefore there will be multiple versions of the Controller Class, each with specific extended functionality. I have looked at a number of tutorials and read some open source solutions to the MVC Framework. I am now trying to create a lightweight solution for my specific requirements. I am not interested in backwards compatibility, I am using PHP 5.3. An advantage of the Base class is not having to use global and can directly access any loaded class using $this->Obj['ClassName']->property/function();. Hoping to get some feedback using the basic structure outlined (with performance in mind). Specifically; a) Have I understood/implemented the concept of MVC correctly? b) Have I understood/implemented Object Orientated techniques with PHP 5 correctly? c) Should the class propertise of Base be static? d) Improvements? Thank you very much in advance! <?php /* A "Super Class" that creates/stores all object instances */ class Base { public static $Obj = array(); // Not sure this is the correct use of the "static" keyword? public static $var; static public function load_class($directory, $class) { echo count(self::$Obj)."\n"; // This does show the array is getting updated and not creating a new array :) if (!isset(self::$Obj[$class]) && !is_object(self::$Obj[$class])) //dont want to load it twice { /* Locate and include the class file based upon name ($class) */ return self::$Obj[$class] = new $class(); } return TRUE; } } /* Loads general configuration objects into the "Super Class" */ class Libraries extends Base { public function __construct(){ $this->load_class('library', 'Database'); $this->load_class('library', 'Session'); self::$var = 'Hello World!'; //testing visibility /* Other general funciton classes */ } } class Database extends Base { /* Connects to the the database and executes all queries */ public function query(){} } class Session extends Base { /* Implements Sessions in database (read/write) */ } /* General functionality of controllers */ abstract class Controller extends Base { protected function load_model($class, $method) { /* Locate and include the model file */ $this->load_class('model', $class); call_user_func(array(self::$Obj[$class], $method)); } protected function load_view($name) { /* Locate and include the view file */ #include('views/'.$name.'.php'); } } abstract class View extends Base { /* ... */ } abstract class Model extends Base { /* ... */ } class News extends Controller { public function index() { /* Displays the 5 most recent News articles and displays with Content Area */ $this->load_model('NewsModel', 'index'); $this->load_view('news', 'index'); echo $this->var; } public function menu() { /* Displays the News Title of the 5 most recent News articles and displays within the Menu Area */ $this->load_model('news/index'); $this->load_view('news/index'); } } class ChatBox extends Controller { /* ... */ } /* Lots of different features extending the controller/view/model class depending upon request and layout */ class NewsModel extends Model { public function index() { echo $this->var; self::$Obj['Database']->query(/*SELECT 5 most recent news articles*/); } public function menu() { /* ... */ } } $Libraries = new Libraries; $controller = 'News'; // Would be determined from Query String $method = 'index'; // Would be determined from Query String $Content = $Libraries->load_class('controller', $controller); //create the controller for the specific page if (in_array($method, get_class_methods($Content))) { call_user_func(array($Content, $method)); } else { die('Bad Request'. $method); } $Content::$var = 'Goodbye World'; echo $Libraries::$var . ' - ' . $Content::$var; ?> /* Ouput */ 0 1 2 3 Goodbye World! - Goodbye World

    Read the article

  • How do i create a view that can filter unique titles from a checkbox?

    - by buws
    I'm currently creating a view in Drupal that contains a number of fields. What I want to do is to create an exposed filter that is able to filter duplicate titles. The filter would be a checkbox. This is an example of the list NAME TIME RACE DISTANCE John Doe 2.07.54 Boston Marathon 42km Jane Boss 2.15.21 Boston Marathon 42km John Doe 2.02.22 Boston Marathon 42km Jane Boss 2.15.44 Boston Marathon 42km What I want to have is an exposed filter that only shows one unique NAME and sorts it by its best time. The resulting list would look as follows: NAME TIME RACE DISTANCE Jane Boss 2.15.21 Boston Marathon 42km John Doe 2.02.22 Boston Marathon 42km Any help is appreciated!

    Read the article

  • iphone: custom UITableViewCell taller than the default cell view.

    - by Luc
    Hello, I'm creating an application that consists of a ListView with 5 rows: - 1st one containing a graph - 2nd to 5th rows containing some data with the same formatting. I have created 2 classes: GraphCustomViewCell and DataCustomViewCell. Depending upon the position of the cell I load the correct CustomCell with: NSArray *topLevelObjects = [[NSBundle mainBundle] loadNibNamed:@"GraphCustomViewCell" owner:nil options:nil]; for(id currentObject in topLevelObjects) { if([currentObject isKindOfClass:[GraphCustomViewCell class]]) { cell = (GraphCustomViewCell *)currentObject; break; } } That works fine except that the first row, the one corresponding to the graph, is bigger (in height) that the 4 other rows, and as a results it hides the 3 first other rows. Is there any option in the table view that enables the custom cell to expand the default cells ? I'd like that the 5 rows (graph + 4 data rows) to fit the entire screen (480 - tabbar's height). Thanks a lot for your help. Regards, Luc

    Read the article

  • How do I make a view that groups nodes by taxonomy term?

    - by Andrew Weir
    Hello, I'm trying to bend views and drupal to my will. So far I've produced a view to display the titles of my nodes. Each node will be assigned exactly one taxonomy term from the set {X, Y and Z}. So for example, Node A has a title "Car drives into field, thousands don't care". Node A has a taxonomy term "Pointless". I'd like to group all the node titles by their taxonomy term. So.. Pointless - Car drives into field, thousands don't care - .... Next Taxonomy Term - ..... - ...... - ... You get the idea. Is it doable and how do I do it? I can't find the group by option in views. cheers SO.

    Read the article

  • How to op-en file and view in a rich text box using vb.net?

    - by Aaron Warnke
    Hi I am trying to open and view a files text in a rich text box. Here is what I have please let me know what I am doing wrong? Private Sub loadButton_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles loadButton.Click ' Displays an OpenFileDialog so the user can select a Cursor. Dim openFileDialog1 As New OpenFileDialog() openFileDialog1.Filter = "Cursor Files|*.txt" openFileDialog1.Title = "Select a Cursor File" If openFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then ' Assign the cursor in the Stream to the Form's Cursor property. Me.mainRTBox = New Text(openFileDialog1.OpenFile()) End If End Sub

    Read the article

  • What problems do you find with this view on domain-driven design?

    - by Bozho
    I just wrote a long (and messy) blogpost about my view on domain-driven design at present day, with frameworks like spring and hibernate massively in use. I'd ask you to spot any problems with my views on the matter - why this won't work, why it isn't giving the benefits of DDD, why it is not a good idea in general. The blogpost is here (I don't think I need to copy-paste it on SO - if you think I should, tell me). I know the question is subjective, but it is aimed at gathering the most predominant opinions. (I'm tagging Java, since the frameworks discussed are Java frameworks)

    Read the article

  • The best way to display data in a table view?

    - by LawVS
    Hey guys, I'm trying to display nutritional information in a table view but am struggling about the best way to show the info. I don't want to create unique views for each page as that would take up a lot of space. My ideal avenue would be like a website having links to data pages instead of individual views for each page. How would I best implement that? For example, I would want the first page to be a list of restaurants, then as you press the restaurant it would list the different types of food...the next page would be a list of those foods and then the final page would be the nutrition info itself. Thanks

    Read the article

< Previous Page | 307 308 309 310 311 312 313 314 315 316 317 318  | Next Page >