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  • Trying to understand the Zend_Auth OpenId

    - by Will Olbrys
    I'm using a slightly modified version of the Zend_Auth_OpenId classes to get openid logins from google apps. The results are very positive, as I seem to be getting successful results from Google. I cannot get successful results passed to Zend_Auth, though. For example, Zend_Auth_Adapter_OpenId on line 241: if (!$consumer->login($id, $this->_returnTo, $this->_root, $this->_extensions, $this->_response)) { return new Zend_Auth_Result( Zend_Auth_Result::FAILURE, $id, array("Authentication failed", $consumer->getError())); } The consumer calls login() which in turn calls the private method _checkId() in Zend_OpenId_Consumer. _checkId() always ends in redirecting to the openid server. How is this ever supposed to return a valid Zend_Auth_Result object? I'm pretty close to giving up and trying to implement another OpenId library, but I'm so close to just making this work. I must be missing something so obvious! Maybe I don't understand how openid works exactly, but if someone could help me understand I would really appreciate it.

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  • Zend_Controller_Router_Route_Chain more routes - more problems

    - by epmspec
    When i use only langRoute and moduleRoute i have not any problems. But when i add pageRoute it is not work properly. I have tried many another ways do it (Regex etc) but none gives the desired result. Can anybody help me? $front = Zend_Controller_Front::getInstance(); $router = $front->getRouter(); //Route_page needs dispatcher and request $dispatcher = $front->getDispatcher(); $request = $front->getRequest(); // Add languag routes $langRoute = new Zend_Controller_Router_Route_Hostname( ':language.domain.com', array( 'language' => 'ru', ), array( 'language' => '^(ru|en)$', ) ); // Add module routes $moduleRoute = new Zend_Controller_Router_Route_Module(array(),$dispatcher,$request); // Add page routes $pageRoute = new Zend_Controller_Router_Route( ':uri\.html', array( 'controller' => 'index', 'module' => 'default', 'action' => 'index', 'uri' => 'index', ), array ('uri' => '[0-9a-z\-]+') ); // Add chain routes $chainedRoute = new Zend_Controller_Router_Route_Chain(); $chainedRoute->chain($pageRoute); $chainedRoute->chain($langRoute)->chain($moduleRoute); $router->addRoute('default', $chainedRoute);

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  • trying to show a variable in my layout

    - by user1400
    hi i have a simple question where is my code wrong ? in index controller and index action i put $this->view->username="user1"; and when i try in my layout i use echo $this->username; i got fllowing error or null value Notice: Trying to get property of non-object in D:\Zend\Apache2\htdocs\test\application\layouts\layout.phtml on line 115 thanks

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  • Zend_Dojo_Form not rendering in layout

    - by Grant Collins
    Hi, I have a quick question about adding Zend_Dojo_Form into Zend_layouts. I have a Zend_Dojo_Form that I want to display in the layout that is used for a particular controller. I can add the form to the layout without any issue however the dojo elements fail to render, as they would do if I added the form to a standard view. Is there any reason why this would be the case? Do I need to do something to the layout so that it will enable the components for this embedded form in the layout. Any other dojo enabled forms that are added in the view using this layout work fine. My form is created in the usual way: class QuickAddJobForm extends Zend_Dojo_Form{ public function init(){ $this->setName('quickaddjobfrm') ->setMethod('post') ->setAction('/addjob/start/); /*We now create the elements*/ $jobTitle = new Zend_Dojo_Form_Element_TextBox('jobtitle', array( 'trim' => true ) ); $jobTitle->setAttrib('style', 'width:200px;') ->addFilter('StripTags') ->removeDecorator('DtDdWrapper') ->removeDecorator('HtmlTag') ->removeDecorator('Label'); .... $this->addElements(array($jobTitle, ....)); In the controller I declare the layout and the form in the init function: public function init(){ $this->_helper->layout->setLayout('add-layout'); $form = new QuickAddJobForm(); $form->setDecorators(array(array('ViewScript', array('viewScript' => 'quickAddJobFormDecorator.phtml')))); $this->_helper->layout()->quickaddjob = $form; In my layout Where I want the form I have: echo $this->layout()->quickaddjob; Why would adding this form in the layout fail to render/add the Dojo elements? All that is currently being displayed are text boxes, rather than some of the other components such as ComboBoxes/FilteringSelects etc... Thanks in advance.

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  • ZF Site in ZF Site? How do I redirect form subdirectory to another subdirecotry?

    - by AD
    The deal is that I have a ZF site for which root directory is /public. How should I go about redirecting to a subdirectory if I want to do next? I want to have another subdirectory under /public/ that would not be linked to a main website in any way except it using save ZF. Lets say I have this: /public/newsite/ which will include a complete modular ZF (just I have it for the main site). That is the root directory for the NEWSITE would be /public/newsite/public. So my question how do I modify my .htaccess rules so it would redirect any requests from /public/newsite/ to /public/newsite/public/? Thank you in advance.

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  • ZF2 - ServiceManager injecting into 84 tables... tedious

    - by Dominic Watson
    I originally made another thread about this a couple of months ago in regards to ZF2 injecting into tables with DI during Beta 1 and figured back then that it wasn't really possible. Now ZF2 has been released as version 2.0.0 and ServiceManager is defaulted to instead of DI I guess I have the same question now I'm refactoring. I've got 84 tables that need the DbAdapter injecting into them and I'm sure there has to be a better way as I'm replicating myself SO much. public function getServiceConfig() { return array( 'factories' => array( 'accountTable' => function ($sm) { $dbAdapter = $sm->get('Zend\Db\Adapter\Adapter'); $table = new Model\DbTable\AccountTable($dbAdapter); return $table; }, 'userTable' => function ($sm) { $dbAdapter = $sm->get('Zend\Db\Adapter\Adapter'); $table = new Model\DbTable\UserTable($dbAdapter); return $table; }, // another 82 tables of the above ) ) } With the EventsManager and ServiceManager I have no idea where I stand in getting my application's instances/resources. Thanks, Dom

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  • Using Zend_Db and multiple tables

    - by Yacoby
    I have a normalized database that stores locations of files on the internet. A file may have multiple locations spread across different sites. I am storing the urls in two parts (Site.UrlStart, FileLocation.UrlEnd). The UrlEnd is the part unique to that file (for the site). Simplified Db structure: I am using Zend_Db as my ORM (If it is that), with classes for the tables inheriting from Zend_Db_Table_Abstract. The issue is that retrieving the location data (e.g. the url) requires the use of multiple tables and as far as I can make out and I would either have to use both table classes (thereby exposing my table structure) or scatter sql all over my application, neither of which sound appealing. The only solution I can see is to create a façade that acts like Zend_Db_Table_Abstract (Maybe inherits from it?) and hides the fact that the data is actually on two tables. My questions are as follows: Am I going in the right direction in creating a façade class (Are there other alternatives)? Should the facade class inherit from Zend_Db_Table_Abstract?

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  • How to handle error on other thread?

    - by markattwood
    Hi, I'm trying to handle errors that have occurred on other threads the .NET CF program is like below: static void Main() { Thread t = new Thread(Start); t.Start(); ... } void Start() { ... Exception here } In my situation, putting try catch in the Start method is impossible. How can I handle it in the global code?

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  • Check if the current date is between two dates + mysql select query

    - by kj7
    I have following table : id dateStart dateEnd active 1 2012-11-12 2012-12-31 0 2 2012-11-12 2012-12-31 0 I want to compare todays date in between dateStart and dateEnd. Following is my query for this : $todaysDate="2012-26-11"; $db = Zend_Registry::get("db"); $result = $db->fetchAll("SELECT * FROM `table` WHERE active=0 AND {$todaysDate} between dateStart and dateEnd"); return $result; But its not working. Any solution. Thanks in advance.

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  • Make a router like zend

    - by Vahan
    I have a url http://*.com/branch/module/view/id/1/cat/2/etc/3. It becomes. array ( 'module'=>'branch', 'controller'=>'module', 'action'=>'view' ); next I need to get the params. Ihave this array. /*function getNextSegments($n,$segments) { return array_slice ( $q = $this->segments, $n + 1 ); } $params = getNextSegments(3); */ array ( 0 => 'id', 1 => '1', 2 => 'cat', 3 => '2', 4 => 'etc', 5 => '3' );//params And i wanna convert it to this one: array ( 'id'=1, 'cat'=2, 'etc'=3, ); How i can do this using php function. I know I can do using for or foreach, but I think php has such function , but i cant find it :(. Thank you. class A { protected function combine($params) { $count = count ( $params ); $returnArray = array (); for($i = 0; $i < $count; $i += 2) { $g = $i % 2; if ($g == 0 or $g > 0) { if (isset ( $params [$i] ) and isset ( $params [$i + 1] )) $returnArray [$params [$i]] = $params [$i + 1]; } } return $returnArray; } } This works normaly. If anybody has better login for this please help. Thank you again.

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  • Have a workaround for the 1,000 file limit in a directory on windows mobile 5?

    - by nateday76
    I need to download more than 1,000 files into a windows mobile 5 directory located on the storage card. If i copy the files onto the storage card via my desktop there is no problem. But when i try to download the files from the handheld device I get a disk full error, even though there is plenty of room due to the 1,000 file limit. Has anyone run into this and found a workaround? I'm going to try zipping all of the files then decompressing on the device but not sure that this will work.

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  • .NET CF 2.0: Stream implements IDisposable ... kind of?

    - by mvanbem
    I've run into something odd in a .NET CF 2.0 project for Pocket PC 2003 (Visual Studio 2005). I was dealing with a System.IO.Stream object and found that the IDE wouldn't auto-complete the Dispose() method. I typed it in manually and received: 'System.IO.Stream.Dispose(bool)' is inaccessible due to its protection level The error is referring to the protected Dispose(bool) method. Dispose() is either private or not present. Question 1: How is this possible? Stream implements IDisposable: public abstract class Stream : MarshalByRefObject, IDisposable ... and IDisposable requires a Dispose() method: public interface IDisposable { void Dispose(); } I know the compiler won't let me get away with that in my code. Question 2: Will I cause problems by working around and disposing my streams directly? IDisposable idisp = someStream; idisp.Dispose(); The implicit cast is accepted by the compiler.

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  • Zend_Registry - Do you need getInstance() ?

    - by Jesse
    Hey I'm wondering when accessing Zend_Registry in an application if you need to include getInstance() and if so, why? for example Zend_Registry::getInstance()-get('db'); vs. Zend_Registry::get('db'); they both seem to work with the later being less verbose. I vaguely understand that Zend_Registry is a singleton, which I think means there can only be one instance of it? so why would you need getInstance()?

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  • Easily reuse views, controller, layout in a command line interface

    - by Alex
    My Zend application is going to get an command line php script that should email reports. There generation depends on Zend_View, Zend_Layout and is currently already working fine in the web interface. How can I reuse this whole MVC functionality in the command line? Should I add a new controller CommandLineController and call this somehow from the commandline? How can I kick of such a Controller manually, without having a HTTP request?

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  • jQuery ajax form and Zend_Form file upload

    - by Sinisa Valentic
    If i submit my ajax form from jQuery, and do print_r($_FILES); i get a list of files uploaded, but if i do something like this $add_form->sound_file->isUploaded(); or $params = $this->_getAllParams(); print_r($params); i don't get my file in zend parametars, and i don't get it uploaded!? Mayb the problem is with he context beng ajax?!

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  • having problems using Zend_Db_Table_Abstract::createRow()

    - by Gootik
    Hey, I have built a model that extends Zend_Db_Table_Abstract and I can't figure out why I can't use createRow(); here is my code: class Model_User extends Zend_Db_Table_Abstract { public function createUser() { $row = $this->createRow(); $row->name = 'test'; $row->save(); } } and in a controller I use: $userModel = new Model_User(); $userModel->createUser(); which when run displays an error An error occurred Application error here is my setup in application.ini resources.db.adapter = "pdo_mysql" resources.db.params.host = "localhost" resources.db.params.username = "root" resources.db.params.password = "pass" resources.db.params.dbname = "app_db" resources.db.isDefaultTableAdapter = true I am sure that my user/pass/dbname is correct. I would appreciate it if you point me in the right direction.

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