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  • sql user defined function

    - by nectar
    for a table valued function in sql why cant we write sql statements inside begin and end tags like- create function dbo.emptable() returns Table as BEGIN --it throws an error return (select id, name, salary from employee) END go while in scalar valued function we can use these tags like create function dbo.countemp() returns int as begin return (select count(*) from employee) end go is there any specific rule where we should use BEGIN & END tags

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  • Comparing arrays with sql

    - by Nissim
    I want to perform a 'SELECT' statement with a byte array (binary) parameter as a condition. I tried to google it, but didn't find anything useful. In general, I keep information of files in the database. one of the properties is the file's hash (binary). I want to give a hash to the SELECT statement, and get all rows with the same hash value.

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  • Slow query execution time

    - by rotor
    select p.id,p.title,p.slug,p.content, (select url from gallery where postid=p.id limit 1) as url, t.name from posts as p inner join termrel as tr on (tr.object = p.id) inner join termtax as tx on (tx.id = tr.termtax_id) inner join terms as t on (t.id = tx.term_id) where tx.taxonomy_id=3 and p.post_status is null order by t.name asc This query took about 0.2407s to execute. How to make it fast?

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  • MySQL grouping by a previously declared alias, what do I wrap it in? ' OR `

    - by cgmojoco
    I have an SQL query that has an alias in the SELECT statement SELECT CONCAT(YEAR(r.Date),_utf8'-',_utf8'Q',QUARTER(r.Date)) AS 'QuarterYear' Later, I want to refer to this in my group by statement. I'm a little confused...should I wrap this with backticks, single quote or just leave it unwrapped int he group by GROUP BY `QuarterYear ` or should I do this?: GROUP BY 'QuarterYear' or just this?: GROUP BY QuarterYear

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  • MySQL Order By Problem, Why is 1000 being seen as Smaller than 2?

    - by Jack
    I have a strange problem, I am trying to order the output of a set of records by a field called displayOrder. Now even though record A has a displayOrder of 2 and record B has a displayOrder of 1000, record B still shows up before record A. Here's my select statement: SELECT * FROM items ORDER BY displayOrder ASC It works fine until I have a record greater than 9, then 10, 11, 12, etc are seen as smaller than 2, 3, 4 because they start with the number 1. Any way to fox this?

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  • Problem with sql like

    - by phenevo
    Hi, I'm writing sql query to my SqlCommand, and some part of them looks like: WHERE Path like N'+(select top 1 path from [Paths] where objectcode=@objectCode and objecttype=@objectType)+%' order by path desc,objecttype desc I get no records , bu when I wrote the same in sql server 2005 i have plenty rows... where path like (select top 1 path from [Paths] where objectcode='eg' and objecttype='0')+'%' order by path desc What's wrong ?? @objectType is 'eg'

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  • removing comma from string array

    - by sarah
    Hi, I want to execute a query like select ID from "xyz_DB"."test" where user in ('a','b') so the corresponding code is like String s="("; for(String user:selUsers){ s+= " ' " + user + " ', "; } s+=")"; Select ID from test where userId in s; The following code is forming the value of s as ('a','b',) i want to remove the comma after the end of array how to do this ?

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  • How to get a profile picture from fb:friends selector

    - by malshan
    Im a Newbie to PHP and FBML(Facebook Markup Language).....so now im coding a Facebook app so I need to get profile picture and friend name when I select a name from FB:Friend Selector Select a Friend <fb:friend-selector uid="exclude_ids" name="pal" idname="friend_sel" /> I use exclude_ids to see all friends in my selector so how to get profile picture? I can get name from this but how to get the profile pic large?

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  • how to number the datas from mysql

    - by udaya
    Hi This is a doubt on mysql select query let me axplain my doubt with a simple example consider this is my query SELECT dbCountry from tableCountry tableCountry has fields dbCuntryId dbCountry and dbState I have the result as dbCountry india america england kenya pakisthan I need the result as 1 india 2 america 3 england 4 kenya 5 pakisthan the numbers 12345 must be generated with the increase in data and itis not a autoincrement id How can i get it is it something like loop

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  • SQL Server > Query > Column Names

    - by pojomx
    Hi, I'm here again- I have something like this Select A.a, A.b, A.a+A.b as c, (A.a+A.b*2)+A.d as d from Table But i want to know, if it is possible, to make it work with something like this: Select A.a,A.b,A.a+A.b as c, (c*2)+A.d as d from Table Thank you

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  • django update object

    - by John
    Hi, How do I run an update and select statement on the same queryset rather than having to do 2 querys, ones to select the object and one to update the object? the sql would be something like update my_table set field_1 = 'some value' where pk_field = some_value Thanks

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  • SQL more elegant combination of boolean checks possible?

    - by Matze
    Call me pedantic but is there a more elegant way to combine all those checks? SELECT * FROM [TABLE1] WHERE [path] = 'RECEIVE' AND [src_ip] NOT LIKE '10.48.20.10' AND [src_ip] NOT LIKE '0.%' AND [src_ip] NOT LIKE '127.%' ORDER BY [date],[time] DESC; To something like this: SELECT * FROM [TABLE1] WHERE [path] = 'RECEIVE' AND [src_ip] NOT LIKE IN ('10.48.20.10','0.%','127.%', .... ) ORDER BY [date],[time] DESC;

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  • Subscript out of bounds on a which statement in R

    - by ahandler
    I have data that looks like this: > head(newdata) zero one real 601 0.01273885 0.9872611 1 602 0.01273885 0.3242234 1 I want to select records where one is greater than .5 When I try this, I get "subscript out of bounds." Why am I getting this error? How do I perform this select? newDataGoodPredict <- newdata[ which(one0.5),] Error in newdata[which(one 0.5), ] : subscript out of bounds

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  • How to save the values of one model in another?

    - by ragupathi
    I have user model and Language model where the language model contains different languages and i want the user to select the languages from that model and it should be stored for the corresponding user. Consider there are five languages A, B, C, D, E then the user has to select from the languages. Suppose user 1 selects A and C whereas user 2 selects B and D then the languages has to be stored for that user. How can i do this? please help me.

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  • MySQL: group by and IF statement

    - by notset
    By default, parent_id = 0. I want to select all records with parent_id = 0 and only the last ones with parent_id 0. I tried this, but it didn't work: SELECT * FROM `articles` IF `parent_id` > 0 THEN GROUP BY `parent_id` HAVING COUNT(`parent_id`) >= 1 END; ORDER BY `time` DESC What could be the solution?

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  • Oracle query with LOWER

    - by Nickolodeon
    Hi. Why this returns 0 rows SELECT GARTUSERID, USER_CODE, UNITID, RANKCODE, RANKID, FIO, LOGINNAME, START_DATE, EXPIR_DATE, NOTE, POSITION, ISCHGPASSWORD, IS_EXPIRDATE, IS_BLOCKED, ROW_ID FROM ACONTROL.GARTUSERS WHERE LOWER(LOGINNAME)=LOWER(:LOGIN) AND ROW_ID=:MD5PSWD and this returns 1 row (as I wanted for the first query)? SELECT GARTUSERID, USER_CODE, UNITID, RANKCODE, RANKID, FIO, LOGINNAME, START_DATE, EXPIR_DATE, NOTE, POSITION, ISCHGPASSWORD, IS_EXPIRDATE, IS_BLOCKED, ROW_ID FROM ACONTROL.GARTUSERS WHERE LOGINNAME=:LOGIN AND ROW_ID=:MD5PSWD

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  • Is it possible to have variable find conditions for both the key and value?

    - by DarrenD
    I'm trying to pass in both the field and the value in a find call: @employee = Employee.find(:all, :conditions => [ '? = ?', params[:key], params[:value].to_i) The output is SELECT * FROM `employees` WHERE ('is_manager' = 1) Which returns no results, however when I try this directly in mysqsl using the same call without the '' around is_manager, it works fine. How do I convert my params[:key] value to a symbol so that the resulting SQL call looks like: SELECT * FROM `employees` WHERE (is_manager = 1) Thanks, D

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  • IS NULL vs = NULL in where clause + MSSQL

    - by Nev_Rahd
    Hello How to check a value IS NULL [or] = @param (where @param is null) Ex: Select column1 from Table1 where column2 IS NULL = works fine If I want to replace comparing value (IS NULL) with @param. How can this be done Select column1 from Table1 where column2 = @param = this works fine until @param got some value in it and if is null never finds a record. How can this achieve?

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  • Mysql: Order Results by number of matching rows in Second Table.

    - by KyleT
    I'm not sure the best way to word this question so bear with me. Table A has following columns: id name description Table B has the following columns: id a_id(foreign key to Table A) ip_address date Basically Table B contains a row for each time a user views a row from Table A. My question is how do I sort Table A results, based on the number of matching rows in Table B. i.e SELECT * FROM TableA ORDER BY (SELECT COUNT(*) FROM TableB where TableB.a_id = TableA.id) Thank you!

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  • Firebird 2.1 + EXISTS = query bug?

    - by Atlas
    Using Delphi 2009 + Firebird 2.1.3. Database is ODS 11.1, default char set is UTF8. My prepared query is as follows: SELECT a.po_id, a.po_no FROM purchase_order a WHERE EXISTS (SELECT 1 FROM sales_order_item z1 JOIN purchase_order_item z2 ON z2.so_item_id = z1.so_item_id AND z2.po_id = a.po_id WHERE z1.so_id = :soid) ORDER BY a.po_no Now when I loop this say 1000 times because I have 1000 x so_id, the CPU usage get at 100% for FBSERVER.EXE Anyone encountered this problem?

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  • Left Join with Entity Framework

    - by sanfra1983
    hi, someone can tell me how to do this query in EF1: select a.idAnimali, a.titolo, a.commenti, a.ordine, a.idcatanimali, table1.nomefoto FROM tabanimali as a LEFT JOIN (SELECT idanimali, nomefoto tabfotoanimali FROM LIMIT 1) AS Table1 On a.idAnimali = table1.idanimali WHERE a.idcatanimali = idcatanimale Thanks

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  • Fetching Cassandra row keys

    - by knorv
    Assume a Cassandra datastore with 20 rows, with row keys named "r1" .. "r20". Questions: How do I fetch the row keys of the first ten rows (r1 to r10)? How do I fetch the row keys of the next ten rows (r11 to r20)? I'm looking for the Cassandra analogy to: SELECT row_key FROM table LIMIT 0, 10; SELECT row_key FROM table LIMIT 10, 10;

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