Search Results

Search found 32007 results on 1281 pages for 'php openid'.

Page 314/1281 | < Previous Page | 310 311 312 313 314 315 316 317 318 319 320 321  | Next Page >

  • PHP Recursive Function

    - by Tempname
    In my database I have a hierarchical flat table that returns data ordered by ParentID, ObjectID asc I am having a bit of an issue getting this recursive function to work properly. I get the first ParentChildChild but after that I get nothing else. Any help with this is greatly appreciated. Here is my testing code: $objectArr = array(); $objectData = DAOFactory::getTemplateObjectsDAO()->queryByTemplateID(1); for($i = 0; $i < count($objectData); $i++) { if(empty($objectData[$i]->parentID)) { echo $objectData[$i]->objectID; $objectArr[$i] = $objectData[$i]; $objectArr[$i]->children = array(); $objectArr[$i]->children = getChildren($objectData[$i]->objectID, $objectData); } } function getChildren($objectID, $data) { $childArr = array(); foreach($data as $object) { if($object->parentID == $objectID) { $childArr = $object; $childArr->children = array(); $childArr->children = getChildren($object->objectID, $data); } } return $childArr; } new dBug($objectData); This is the output that I am getting: Fullsize Link

    Read the article

  • PDF Viewer for my web - PHP

    - by hjaffer2001
    I am searching for pdf viewer for my web(Open Source). Searched for months and months. Is there any open source to view pdf in my web (without adobe). On the other hand, the documents should be secured. I have done a synopsis with the following urls;(but no use) http://embedit.in/ http://www.vuzit.com/ http://www.ajaxdocumentviewer.com/ http://flexpaper.devaldi.com http://www.icepdf.org/ https://docs.google.com/viewer http://www.snowbound.com/ http://www.mygazines.com http://www.issuu.com/business www.box.net http://viewer.zoho.com/ I want both download and print option for my pdf viewer.

    Read the article

  • PHP sql with foreach loop variable problem

    - by anthony
    This is really getting frustrating. I have a text file that I'm reading for a list of part numbers that goes into an array. I'm using the following foreach function to search a database for matching numbers. $file = file('parts_array.txt'); foreach ($file as $newPart) { $sql = "SELECT products_sku FROM products WHERE products_sku='" . $newPart . "'"; $rs = mysql_query($sql); $num_rows = mysql_num_rows($rs); echo $num_rows; echo "<br />"; } The problem is I'm getting 0 rows returned from mysql_num_rows. I can type the sql statement without the variable and it works perfectly. I can even echo out the sql statement from this script, copy and paste the statement from the browser and it works. But, for some reason I'm not getting any records when I'm using the variable. I've used variables in sql statements tons of times, but this really has me stumped.

    Read the article

  • get path of Array (PHP)

    - by Kawah Grafis
    i have an array input like this .. Array ( [0] => Array ( [0] => 42 ) [**42**] => Array ( [0] => 12 [1] => 14 ) [**14**] => Array ( [0] => 317 ) [317] => Array ( [0] => 319 ) [**12**] => Array ( [0] => 306 [1] => 307 ) [307] => Array ( [0] => 311 ) [306] => Array ( [0] => 309 ) ) and i want to get result array like bellow : $paths[]=array(42,12,306,309); $paths[]=array(42,12,307,311); $paths[]=array(42,14,317,319); see array input root in array input = 42 (index of array 0) 42 have child = 12, 14 12 have child = 306, 307 14 have child = 317 306 have child = 309 307 have child = 311 317 have child = 319 like this.. and output array insert into $paths $paths[0]=array(42,12,306,309); $paths[1]=array(42,12,307,311); $paths[2]=array(42,14,317,319);

    Read the article

  • Please explain this php expression "!$variable"

    - by DogBot
    What does an exclamaton mark in front of a variable mean? And how is it being used in this piece of code? EDIT: From the answers so far I suspect that I also should mention that this code is in a function where one of the parameters is $mytype ....would this be a way of checking if $mytype was passed? - Thanks to all of the responders so far. $myclass = null; if ($mytype == null && ($PAGE->pagetype <> 'site-index' && $PAGE->pagetype <>'admin-index')) { return $myclass; } elseif ($mytype == null && ($PAGE->pagetype == 'site-index' || $PAGE->pagetype =='admin-index')) { $myclass = ' active_tree_node'; return $myclass; } elseif (!$mytype == null && ($PAGE->pagetype == 'site-index' || $PAGE->pagetype =='admin-index')) { return $myclass; }`

    Read the article

  • help with converting javascript function to php

    - by Haroldo
    My javascript isnt so great, but i found a brilliant looking function here I'm not sure what to do with this bit: var ranges = [], rstart, rend; full function: function getRanges(array) { var ranges = [], rstart, rend; for (var i = 0; i < array.length; i++) { rstart = array[i]; rend = rstart; while (array[i + 1] - array[i] == 1) { rend = array[i + 1]; // increment the index if the numbers sequential i++; } ranges.push(rstart == rend ? rstart+'' : rstart + '-' + rend); } return ranges; } getRanges([2,3,4,5,10,18,19,20]); // returns ["2-5", "10", "18-20"] getRanges([1,2,3,5,7,9,10,11,12,14 ]); // returns ["1-3", "5", "7", "9-12", "14"] getRanges([1,2,3,4,5,6,7,8,9,10]) // returns ["1-10"]

    Read the article

  • second sorting with php usort

    - by bluedaniel
    So Ive got a pretty big array of data and need to sort them by two criteria. There is variable $data['important'] and $data['basic']. They are simple numbers and I am using uasort to sort $data firstly by important and then by basic. So Important | Basic 10 | 8 9 | 9 9 | 7 7 | 9 The usort function is a simple public function sort_by_important($a, $b) { if ($a[important] > $b[important]) { return -1; } elseif ($b[important] > $a[important]) { return 1; } else { return 0; } } How can I re-sort the array to the second variable and keep the Important ordering? Thanks everyone. EDIT How about adding a third sorting option after this even? So Important Basic Less

    Read the article

  • Prevent PHP sesison hijack, are these good ideas?

    - by matthew Rhodes
    I'm doing a simple shopping cart for a small site. I plan to store cart items as well as logged in user_id in session variables. to make things a little more secure, I thought I'd do this: sha1() the user_id before storing it in the session. Also sha1() and store the http_user_agent var with some salt, and check this along with the user_id. I know there is more one can do, but I thought this at least helps quite a bit right? and is easy for me to implement.

    Read the article

  • Partial PHP code refresh

    - by Tom
    Is it possible to refresh only the part of the page? How? the part: if (checkExpiry($member->expires)==true) { print timeLeft($leftts); } else { print "expired"; } I have table which is showing name, email, time until membership ends and I need to refresh 'time until membership ends' every second.

    Read the article

  • PHP Changing Class Variables Outside of Class

    - by Jamie Bicknell
    Apologies for the wording on this question, I'm having difficulties explaining what I'm after, but hopefully it makes sense. Let's say I have a class, and I wish to pass a variable through one of it's methods, then I have another method which outputs this variable. That's all fine, but what I'm after is that if I update the variable which was originally passed, and do this outside the class methods, it should be reflected in the class. I've created a very basic example: class Test { private $var = ''; function setVar($input) { $this->var = $input; } function getVar() { echo 'Var = ' . $this->var . '<br />'; } } If I run $test = new Test(); $string = 'Howdy'; $test->setVar($string); $test->getVar(); I get Var = Howdy However, this is the flow I would like: $test = new Test(); $test->setVar($string); $string = 'Hello'; $test->getVar(); $string = 'Goodbye'; $test->getVar(); Expected output to be Var = Hello Var = Goodbye I don't know what the correct naming of this would be, and I've tried using references to the original variable but no luck. I've come across this in the past, with the PDO prepared statements, see Example #2 $stmt = $dbh->prepare("INSERT INTO REGISTRY (name, value) VALUES (?, ?)"); $stmt->bindParam(1, $name); $stmt->bindParam(2, $value); // insert one row $name = 'one'; $value = 1; $stmt->execute(); // insert another row with different values $name = 'two'; $value = 2; $stmt->execute(); I know I can change the variable to public and do the following, but it isn't quite the same as how the PDO class handles it, and I'm really looking to mimic that behaviour. $test = new Test(); $test->setVar($string); $test->var = 'Hello'; $test->getVar(); $test->var = 'Goodbye'; $test->getVar(); Any help, ideas, pointers, or advice would be greatly appreciated, thanks.

    Read the article

  • String useless character strip - PHP

    - by Zoltan Repas
    Hi! I've got a huge problem. I made a special ID for the things in our webpage. Let's see an example: H0059 - this is the special ID called registration number. The last two chars are the things' id. I'd like to cut off the useless characters, to get the real ID, what means strip the first char, and all the 0s before any other numbers. (Example: L0745 = 745, V1754 = 1754, L0003 = 3, B0141 = 141, P0040 = 40, V8000 = 8000) Please help me in this. I've tried with strreplace and explode but failed :( Thanks for the help.

    Read the article

  • MySQL order by error in PHP

    - by theflyinghaiwian
    Hi, I'm making a simple cms system for a site I'm making for non-tech users to edit... So far so good but when I try and run this code I keep getting: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''pages' ORDER BY 'pages'.'pageOrder' ASC LIMIT 0 , 30' at line 1 By the error it looks like a problem with the order by section and indeed it works without it... $sql = "SELECT * FROM 'pages' ORDER BY 'pages'.'pageOrder' ASC LIMIT 0 , 30"; $result = mysql_query($sql) or die(mysql_error()); Now I know there is nothing wrong with the code because originally I wrote my own SQL but then after it failed I robbed some from phpmyadmin and it still gives the error but it works in phpmyadmin... I'm really at my wits end with this, help is very much appreciated thank you...

    Read the article

  • Read part of a file in PHP

    - by Johan
    I would like to read the last 1 megabyte of a MP3 file and calculate SHA1 checksum for just that part of the file. The reason that I would want this is that when I'm looking for duplicate MP3's, the header info (song title, album etc.) can differ even though it's the exakt same audio file, so I figured I would be better of to checksum a part of the file at the end instead of the whole one. Is there an efficient way of doing this?

    Read the article

  • php mysql search

    - by mckenzie
    Hello, My code contain SELECT * FROM newchap WHERE company LIKE '%$company%' OR Category LIKE '%$cat%' It works perfectly however, when the field $company contain empty, it return all result in MYSQL. How to prevent it?

    Read the article

  • PHP Upload file enhance security

    - by mandril
    Hey.. my question is how to prevent someone upload a virus or some malicious code with the extension you pretend for example i have a pdf file uploader, anyone can upload a binary with pdf camouflage there are lots of programs to do that.

    Read the article

  • Upload image with Tumblr API in PHP

    - by John
    I'm having trouble uploading a photo from my computer to tumblr using their API. http://www.tumblr.com/docs/en/api photo - Requires either source or data, but not both. If both are specified, source is used. * source - The URL of the photo to copy. This must be a web-accessible URL, not a local file or intranet location. * data - An image file. See File uploads below. * caption (optional, HTML allowed) * click-through-url (optional) I need to use data File uploads can be done in a data parameter where specified above. You may use either of the common encoding methods: multipart/form-data method, like a file upload box in a web form. Maximum size: o 50 MB for videos o 10 MB for photos o 10 MB for audio I would post my code but it's not showing up correctly for me.

    Read the article

  • PHP: Manage roles with math?

    - by Mike
    I once saw an article about how to use a specific type of numbering system to manage roles. A user would be assigned a specific role number and depending on a calculation, the number could stand for multiple roles. Can anybody share this technique with me or share a link? Thanks!

    Read the article

  • sort associative array PHP

    - by jim smith
    Here's my array, how do I sort it by saleref? Array ( [xml] => Array ( [sale] => Array ( [0] => Array ( [saleref] => 12345 [saleline] => 1 [product] => producta [date] => 19/ 3/10 [manifest] => 0 [qty] => 1 [nextday] => [order_status] => ) [1] => Array ( [saleref] => 12344 [saleline] => 1 [product] => productb [date] => 18/ 3/10 [manifest] => 11892 [qty] => 1 [nextday] => [order_status] => )

    Read the article

  • PHP simplexml Entities

    - by FFish
    What's going one here? $string = <<<XML <?xml version="1.0" encoding="UTF-8"?> <album> <img src="002.jpg" caption="w&aacute;ssup?" /> </album> XML; $xml = simplexml_load_string($string); // $xmlobj = simplexml_load_file("xml.xml"); // same thing echo "<pre>"; var_dump($xml); echo "</pre>"; Error: Warning: simplexml_load_string() [function.simplexml-load-string]: Entity: line 5: parser error : Entity 'aacute' not defined

    Read the article

  • PHP CURL works fine from localhost not from server

    - by Joby Joseph
    I have 2 servers, srv1 and srv2. All client sites are stored in srv2 and all authentication details are stored in srv1. Each time a client site is loaded, the site in srv2 sends a curl request to srv1 to validate. I am always getting bool(false) when I print the curl response using var_dump. But if I am requesting for validation from my local wamp installation(localhost) it is perfectly returning the response. According to my understanding srv2 is blocking srv1 ip or something like that. Any help or suggestions will be greatly appreciated. The solution is really urgent as all my clients are stuck with invalid authorization message. Edit: Now when i tested curl in srv2 is working fine i think. Because I am able to fetch other websites without any trouble. But I am not able to fetch data from srv1. I can view a page from srv1 through browser url but not through curl.

    Read the article

< Previous Page | 310 311 312 313 314 315 316 317 318 319 320 321  | Next Page >