Search Results

Search found 33936 results on 1358 pages for 'html practice'.

Page 317/1358 | < Previous Page | 313 314 315 316 317 318 319 320 321 322 323 324  | Next Page >

  • jQuery: Trouble with draggable across cloned elements

    - by Rosarch
    I'm trying to implement: User drags a draggable li to a droppable li. The original li is no longer draggable A new li is cloned from the original li, and is appended to the droppable li. I can't get it to work. function moveToTerm(original_course, helper, term) { var cloned_course = original_course.clone(true); original_course.addClass('already-scheduled'); original_course.draggable('disable'); cloned_course.draggable(); cloned_course.appendTo(term).hide().fadeIn('slow'); } This works fine, except now the cloned_course is not draggable. A droppable li: <li class="term ui-droppable"> <strong>Fall 2010</strong> <li class="course">Computing Cultures</li> <!-- this course was just dropped. I want it to be draggable but it's not --> <li class="course ui-draggable" style="display: list-item;">New Media and Society</li> </li> What am I doing wrong?

    Read the article

  • How to design websites for all display sizes

    - by katie bekell
    I like to use a lot of unique graphics on my pages, which often results in making different page sizes depending on available screen width/height. Here are two examples: http://www.uvm.edu/~areid/homesite/ - the image floats at the bottom of my screen but on a larger browser, the image floats near the middle making it look off. It looks best when the bottom of the window aligns with the bottom of the image www.stevenlebel.com - it loads two different pages depending on what monitor size is detected. This seems like a lot of redundant coding. My question is, how can I make sliced/Photoshop images transition well to different screen sizes. Does Photoshop allow you to make DIVS instead of tables? Can i make each of the slices created by Photoshop grow/shrink when the browser window size changes? If anyone has any input on creating websites like this I would be very interested to hear what they have to say. Thanks Katie

    Read the article

  • Dynamic width of DIV (offsetWidth issue).

    - by Tom
    Hi all, I face issue with retrieving (via javascript) width of the div which content is changed (just before reading the widht via offsetWidth) in dynamic way (via changing innerHTML or using createTextNode). Here is some sample code: var con = document.getElementById('avContent'); //content div within page var temp = document.createElement('div');<br /> var text1 = document.createTextNode('CCCCC');<br /> temp.appendChild(text1);<br /> con.appendChild(temp);<br /> var length1 = temp.offsetWidth;<br /> var text2 = document.createTextNode('CCCCC33333333vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv');<br /> temp.removeChild(text1);<br /> temp.appendChild(text2);<br /> con.removeChild(temp);<br /> con.appendChild(temp); var length2 = temp.offsetWidth;<br /> The length1 and length2 do have the same width.. (the same result I get while using innerHTML instead of createTextNode). Looks like it's the same issue like described in following discussion: http://www.webdeveloper.com/forum/showthread.php?t=187716 Does anybody have answer (work around)? Thanks much for help in advance.

    Read the article

  • Variable disappears when I log in

    - by John
    Hello, I have profile page where the profile is retrieved via GET. The index file has this: $profile = $_GET['profile']; When I log in on the profile page, the $profile variable disappears. Here is the form action on the login function: <form name="login-form" id="login-form" method="post" action="./index.php"> (The $profile variable is separate of the login username.) How could I make the page retain the $profile variable? Thanks in advance, John

    Read the article

  • Background not filling in completely

    - by Cody.Stewart
    For some reason the background on my website is not loading fully. Randomly, not all the time, the website will load with white rectangles around the content of the website. Check out this screenshot to get a better picture, or visit www.thinkitpostit.com to see if it randomly happens for you. Thanks in advance!

    Read the article

  • Align 3 images in a div , left-centre-right, uneven margin

    - by Adrian
    I could find a work around for this if I wanted but it seems wrong and am trying to learn to code in a neater way. Basically I have a div with 3 images in it, the div is 700px, and each image is 220px, So thats 660px with two 20px gaps left and right of the centre image, and the outside images going all the way to their end of the div. Is there a quicker way of doing this without setting up seperate ids for each image? .contentpictureblock { float:left; } .contentpictureblock img { margin-right:20px; } <div class="contentpictureblock"> <img src="http://..."> <img src="http://..."> <img src="http://..."> </div> Doing the above^ pushes the third image to the next line, which is understandable. I know I could always make seperate divs for each image, and adjust the margins for each one but Im just wondering is there a quicker one off overflow type command that I could apply to the above? It would mean the right margin would be on all the images but would have no effect on its positioning in the last image. Thanks for the help.

    Read the article

  • get element position

    - by hopes
    how can i know that a specific is on another specific after dragging the first and drop it I am using this code in the head of my document to enable drag and drop of my divs var dragapproved=false var z,x,y function move(){ if (event.button==1&&dragapproved){ z.style.pixelLeft=temp1+event.clientX-x z.style.pixelTop=temp2+event.clientY-y return false } } function drags() { if (!document.all) return if (event.srcElement.className=="drag") { dragapproved=true z=event.srcElement temp1=z.style.pixelLeft temp2=z.style.pixelTop x=event.clientX y=event.clientY document.onmousemove=move } } document.onmousedown=drags document.onmouseup=new Function('dragapproved=false')

    Read the article

  • Parsing XML with jQuery

    - by Jamie
    I've used this: $(document).ready(function () { $.ajax({ type: "GET", url: "http://domain.com/languages.php", dataType: "xml", success: xmlParser }); }); function xmlParser(xml) { $('#load').fadeOut(); $(xml).find("result").each(function () { $(".main").append('' + $(this).find("language").text() + ''); $(".lang").fadeIn(1000); }); } I used a local XML file on my computer, it works fine, but when I change the URL to an website, it just keeps loading all the time... How do I get this to work?

    Read the article

  • Why is this <p> expanding the whole page?

    - by George Edison
    If you visit this page and shrink your browser window, you will see my problem. [If you want to open the page in a new window, just hold down shift when you click the link.] The answers to the question extend beyond the page margin instead of wrapping. I have spent the last half hour working with Chrome's Inspector and Firefox's DOM inspector - all to no avail. I just cannot figure out why it's doing this.

    Read the article

  • Echo mysql results in a loop?

    - by Roy D. Porter
    I am using turn.js to make a book. Every div within the 'deathnote' div becomes a new page. <div id="deathnote"> //starts book <div style="background-image:url(images/coverpage.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"></div> //creates new page </div> //ends book What I am doing is trying to get 3 'content' (content being a name and cause of death) divs onto 1 page, and then generate a new page. So here is what i want: <div id="deathnote"> //starts book <div style="background-image:url(images/coverpage.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"> //creates new page but leaves it open <div> CONTENT </div> <div> CONTENT </div> <div> CONTENT </div> </div> //ends the page </div> //ends book Seems simple enough, however the content is data from a MySQL DB, so i have to echo it in using PHP. Here is what i have so far <div id="deathnote"> <div style="background-image:url(images/coverpage.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <?php $pagecount = 0; $db = new mysqli('localhost', 'username', 'passw', 'DB'); if($db->connect_errno > 0){ die('Unable to connect to database [' . $db->connect_error . ']'); } $sql = <<<SQL SELECT * FROM `TABLE` SQL; if(!$result = $db->query($sql)){ die('There was an error running the query [' . $db->error . ']'); } //IGNORE ALL OF THE GARBAGE ABOVE. IT IS SIMPLE CONNECTING SCRIPT THAT I KNOW WORKS //THE METHOD I AM HAVING TROUBLE WITH IS BELOW $pagecount = 0; while($row = $result->fetch_assoc()){ //GETS THE VALUE (and makes sure it isn't nothing echo '<div style="background-image:url(images/paper.jpg);">'; //THIS OPENS A NEW PAGE while ($pagecount !== 3) { //KEEPS COUNT OF HOW MUCH CONTENT DIVS IS ON THE PAGE while($row = $result->fetch_assoc()){ //START A CONTENT DIV echo '<div class="content"><div class="name">' . $row['victim'] . '</div><div class="cod">' . $row['cod'] . '</div></div>'; //END A CONTENT DIV $pagecount++; //UP THE PAGE COUNT } } $pagecount=0; //PUT IT BACK TO 0 echo '</div>'; //END PAGE } $db->close(); ?> <div style="background-image:url(images/backpage.jpg);"></div> //BACK PAGE </div> At the moment i seem to be causing and infinite loop so the page won't load. The problem resides within the while loops. Any help is greatly appreciated. Thanks in advance guys. :)

    Read the article

  • permutation need help to code

    - by Hunt
    Thank for your reply, first thing i wish to thank you for trying to help me out, and i have post this in few website also no one trying to help at all. For my code, what i wish to do is permutation count. it will count from top to bottom 1,2,3 1,2,3 1,2,3 output to 111 = 1 112 = 1 113 = 1 121 = 1 122 = 1 123 = 1 133 = 1 211 = 1 212 = 1 213 = 1 333 = 1 and continue till all number is count and also store to the array which can check how many count after all code will check the input number and count how many outcome and show the results with how many outcome and each have how many after permutation count. Its hard to do?. Anyway thank you for help.

    Read the article

  • SPAN vs DIV (inline-block)

    - by blackjid
    Hi, Is there any reason to use a <div style="display:inline-block"> instead of a <span> to layout a webpage? Can I put content nested inside the span? What is valid and what isn't? Thanks! It's ok to use this to make a 3x2 table like layout? <div> <span> content1(divs,p, spans, etc) </span> <span> content2(divs,p, spans, etc) </span> <span> content3(divs,p, spans, etc) </span> </div> <div> <span> content4(divs,p, spans, etc) </span> <span> content5(divs,p, spans, etc) </span> <span> content6(divs,p, spans, etc) </span> </div>

    Read the article

  • Submit button on nested form submits the outer form in IE7

    - by Mike Christensen
    I have the following code on my Home.aspx page: <form id="frmJump" method="post" action="Views/ViewsHome.aspx"> <input name="JumpProject" /><input type="submit" value="Go" /> </form> However, when I click the "Go" button, the page posts back to Home.aspx rather than going to ViewsHome.aspx. I even tried adding some script to force the form to submit: <input name="JumpProject" onkeypress="if(event.keyCode == 13) { this.form.submit(); return false; }" /> But still even if I press ENTER, the Home.aspx page is reloaded. The only thing I can see that might be borking things is this form is actually a child form of the main POSTBACK form that ASP.NET injects into the page. I'm sure there's something stupid I'm missing and this post will get 800 downvotes instantly banishing me back into the n00b realm, but perhaps I haven't gotten enough sleep lately and I'm missing something stupid. This is on IE7 and an ASP.NET 4.0 backend. I also have jQuery libraries loaded on the page incase jQuery can improve this somehow. Thanks!

    Read the article

  • Jquery hover function doesn't work for a table...

    - by chandru_cp
    I dynamically added rows to a table but it doesn't seem to take hover effects given in jquery... Here is my code, <table id="chkbox" cellpadding="0" cellspacing="2" width="100%" class="table_Style_Border"> <tr> <td style="width:150px" class="grid_header" align="center">RackName</td> <td style="width:150px" class="grid_header" align="center">LibraryName</td> <td style="width:200px" class="grid_header" align="center">LibrarianName</td> <td style="width:200px" class="grid_header" align="center">Location</td> <td style="width:1%" class="grid_header"></td> </tr> <? if(isset($comment)) { echo '<tr><td class=table_label colspan=5>'.$comment.'</td></tr>'; } ?> <?php foreach($rackData as $key => $row) { ?> <?php printf('<tr class="%s">', ($key % 2) ? 'rowcolor' : 'alternaterowcolor'); ?> <td align="left" class="table_label"> <?=$row['rack_name']?> </td> <td align="left" class="table_label"> <?=$row['library_name']?> </td> <td align="center" class="table_label"> <?=$row['librarian']?> </td> <td align="center" class="table_label"> <?=$row['location']?> </td> <td align="center"> <input type="checkbox" name="group" id="group" value="<?=$row['rack_id']?>" onclick="display(this);" > </td> </tr> <? } ?> </table><div align="right" class="pagination"> <?php /*?><?php echo $links;?><?php */?></div> <script type="text/javascript"> $("#chkbox").hover(function() { $(this).addClass("resultshover"); }, function() { $(this).removeClass("resultshover"); }); </script>

    Read the article

  • i want to show a panel just like facebook or for captcha validation

    - by Lokesh
    i have a simple form and when user enters all the information and hits the submit botton than a panel should open just a width of 200px and height of 100px inside the same window. which should have two fields one is captcha image and a text box and a check botton and if captcha code is right than panel should automatically close and redirect to another page just like facebook . all the details of the panel is saved on another php file.

    Read the article

  • Clever "add tag" javascript help needed

    - by Camran
    I have this function for adding options to a Select list: function addOption(selectbox, value, text, cl ) { var optn = document.createElement("OPTION"); optn.text = text; optn.value = value; if (cl==1){ optn.className = "nav_option_main"; } selectbox.options.add(optn); } I have just discovered the "optgroup" tag, but I don't know how to implement it to the drop list. The function above is called on another selectboxes "OnChange" event, to fill sub-select-box with the desired options. I don't think it should be too difficult to add the "optgroup" tag into this, or is it? Thanks and if you need more input let me know...

    Read the article

  • how to add url in onclick function????

    - by rajesh
    i have line new_element.innerHTML =""; which will call the function addWidget as function addWidget(url) { alert(url); var main= document.getElementById('mainwidget'); main.innerHTML = ""; } but its not working whats the problem...

    Read the article

< Previous Page | 313 314 315 316 317 318 319 320 321 322 323 324  | Next Page >