Passing char * into fopen with C.
- by Rhys
Hey there,
I'm writing a program that passes data from a file into an array, but I'm having trouble with fopen (). It seems to work fine when I hardcode the file path into the parameters (eg fopen ("data/1.dat", "r");) but when I pass it as a pointer, it returns NULL.
Note that line 142 will print "data/1.dat" if entered from command line so parse_args () appears to be working.
132 int
133 main(int argc, char **argv)
134 {
135 FILE *in_file;
136 int *nextItem = (int *) malloc (sizeof (int));
137 set_t *dictionary;
138
139 /* Parse Arguments */
140 clo_t *iopts = parse_args(argc, argv);
141
142 printf ("INPUT FILE: %s.\n", iopts->input_file); /* This prints correct path */
143 /* Initialise dictionary */
144 dictionary = set_create (SET_INITAL_SIZE);
145
146 /* Use fscanf to read all data values into new set_t */
147 if ((in_file = fopen (iopts->input_file, "r")) == NULL)
148 {
149 printf ("File not found...\n");
150 return 0;
151 }
Thanks!
Rhys
