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  • PHP SimpleXML, how to set attributes ?

    - by Jahmaica
    Hi, if you've got something like, <hello id="1" name="myName1"> <anotherTag title="Hello"> </anotherTag> </hello> <hello id="2" name="myName2"> <anotherTag title="Hi"> </anotherTag> </hello> How to change the attributes of, for example, hello id 2, to name="William" ? Or the title hi to hello ? Thanks a lot for your atention, H'

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  • PHP: Parsing of a given form input variable

    - by Jaime Cross
    How would I go about parsing incoming form data where the name changes based on section of site like: <input type="radio" name="Motorola section" value="Ask a question"> where 'Motorola section may be that, or Verizon section, or Blackberry section, etc. I do not have any control over changing the existing forms unfortunately, so must find a way to work with what is there. Basically, I need to be able to grab both the name="" data as well as its coresponding value="" data to be able to populate the email that gets sent properly.

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  • problem in using while loop in php&mysql

    - by Mac Taylor
    hey guys im using a while loop to show my latest forum topics now i need to count some fields either I'm trying to do it in one query and here is my code : $result = $db->sql_query("SELECT t.*,p.*, SUM(t.topic_approved='1') AS Amount_Of_Topics, SUM(t.topic_views) AS Amount_Of_Topic_Views, SUM(t.topic_replies) AS Amount_Of_Topic_Replies, SUM(p.post_approved ='1') AS Amount_Of_Posts FROM bb3topics t left join bb3posts p ON t.topic_id=p.topic_id ORDER BY t.topic_last_post_id DESC LIMIT 10 " ); while( $row = $db->sql_fetchrow($result) ) { problem : this code shows only one forum topic and not the rest , but if i remove sum() part from it , then it shows the rest is there anything wrong with my query code ?!

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  • How to reformat date in PHP?

    - by Lisa
    I am pulling the dates of various posts from a database. The dates are in the following format: 2009-08-12 Numeric Year - Numeric Month - Numeric Day How can I reformat these dates to something more user friendly like: August 12, 2009 Numeric Month Numeric Date, Numeric Year Assuming that the date gotten from the mysql database is stored in a variable called: $date = $row['date_selected'];

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  • PHP fails silently when function not defined?

    - by John Isaacks
    I am migrating from PHP4 to PHP5 I have this in my .htaccess: php_flag display_errors on php_value error_reporting 2039 Which used to show all errors. I am still getting some errors but I used to get an error when I called a function that was not defined, but now it stops where it is at and send the client everything up to the error and nothing after. With no error message. Here is what phpinfo is telling me: Directive Local Value Master Value display_errors On Off error_reporting 2039 6143 I would like to be able to see my error messages for trouble shooting purposes. Can someone tell me what I need to do? Thanks!!

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  • override __set in __construct() in php?

    - by user151841
    I have a class based on database values. I'm using __set to automatically sync database values with the class properties. Set checks an array of database fields that it is allowed to update in the database. The field 'id' isn't in the list, so __set will throw an exception if you try to do $objDbRow->id = 5;. However, there is one time when I do want to set the id property of the object, and that's on instantiation. So in __constuct, I have $this->id = $id (where $id is passed to __construct). However, __set seems to be intercepting the setting here, because an exception is being thrown on construction. What's the way to get around this? I suppose I also have a boolean flag, like $instantiated, that __set() would check before it does it's field whitelist checking. But that feels inelegant.

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  • PHP Session Array Value keeps showing as "Array"

    - by Nerathas
    Hello, When sending data from a form to a second page, the value of the session is always with the name "Array" insteed of the expected number. The data should get displayed in a table, but insteed of example 1, 2, 3 , 4 i get : Array, Array, Array. (A 2-Dimensional Table is used) Is the following code below a proper way to "call" upon the stored values on the 2nd page from the array ? $test1 = $_SESSION["table"][0]; $test2 = $_SESSION["table"][1]; $test3 = $_SESSION["table"][2]; $test4 = $_SESSION["table"][3]; $test5 = $_SESSION["table"][4]; What exactly is this, and how can i fix this? Is it some sort of override that needs to happen? Best Regards.

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  • Fetch multiple rows from SQL in PHP foreach item in array

    - by TrySpace
    I try to request an array of IDs, to return each row with that ID, and push each into an Array $finalArray But only the first result from the Query will output, and at the second foreach, it skips the while loop. I have this working in another script, so I don't understand where it's going wrong. The $arrayItems is an array containing: "home, info" $finalArray = array(); foreach ($arrayItems as $UID_get) { $Query = "SELECT * FROM items WHERE (uid = '" . cleanQuery($UID_get) . "' ) ORDER BY uid"; if($Result = $mysqli->query($Query)) { print_r($UID_get); echo "<BR><-><BR>"; while ($Row = $Result->fetch_assoc()) { array_push($finalArray , $Row); print_r($finalArray ); echo "<BR><><BR>"; } } else { echo '{ "returned" : "FAIL" }'; //. mysqli_connect_errno() . ' ' . mysqli_connect_error() . "<BR>"; } } (the cleanQuery is to escape and stripslashes) What I'm trying to get is an array of multiple rows (after i json_encoded it, like: {"finalArray" : { "home": {"id":"1","created":"0000-00-00 00:00:00","css":"{ \"background-color\" : \"red\" }"} }, { "info": {"id":"2","created":"0000-00-00 00:00:00","css":"{ \"background-color\" : \"blue\" }"} } } But that's after I get both, or more results from the db. the print_r($UID_get); does print info, but then nothing.. So, why am I not getting the second row from info? I am essentially re-querying foreach $arrayItem right?

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  • Rotating images with PHP reduces quality especially over about 10-20 actions

    - by Dylan Cross
    I am using this code below to rotate my jpeg images, the problem is that after around 10-20 times of rotating the image the image is dramatically lower quality, especially blue skies and such, my question is how can I keep these images the same high quality image? There must be a way. I mean, i keep the original image on the server for each image uploaded, and I don't do anything to that, so if need be it, I guess I could always come up with some way of using that over whenever possible.. But would rather not have to. $source = imagecreatefromjpeg($filename); $rotate = imagerotate($source, 90, 0); imagejpeg($rotate, $filename ,100);

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  • Add multiple IF tags in php

    - by Andy
    Hi , I would like to add this condition : {if $profile.sex == 1 || $profile.sex == 4} {/if} To this code : case 'friendlist': if ( app_Features::isAvailable( 14 ) ) { $_output = '<div class="memhome_link">'; $_output.= '<a href="'.SK_Navigation::href( 'profile_friend_list' ).'" '.$class.'>'.$lang_section->text( 'href_my_friendlist').'</a>'; $_output.= ' ('.app_FriendNetwork::countFriends( SK_HttpUser::profile_id() ).')'; $_output.= '</div>'; } break; Can anybody give me any help , please ? Thanks for all the help .

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  • PHP IF statement not taking variable into account!

    - by Jess
    I have a tabled view in a while loop, where a user can view information on books. For example, book ISBN, book name, read status... Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this: $readstatus = $_GET['readstatus']; if ($readstatus == 'complete') { echo '<tr class="completed">'; } else if ($readstatus != 'complete') { echo '<tr class="reading">'; } I'm obviously doing something wrong here, but all I need is the CSS class of the table row to change if the value of 'readstatus' = 'complete', if not, then output the default CSS table row color ('reading') Should I be putting $result as the variable or something? I have this coming just before my nested IF statement: $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); while($row = mysql_fetch_array($result)) { ?>

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  • PHP Array - some further problems with displaying elements in the array

    - by Homer_J
    Hi again, Thanks in advance for the help. Here is my array based on $rowq: Array ( [0] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [1] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [2] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [3] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [4] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [5] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [6] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [7] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) ) I would like to display elements of the array using (i think) the foreach statement but I can't get it working, ideally, I would like to echo something like this echo "<tr>".$rowq[qnum]." is the questions number and the question text is ".$rowq[qtext].". The page and q values are ".$rowq[page]." and ".$rowq[questions]." respectively."; And that link of text would appear how however many rows the array has in it. Any and all advice appreciated - I'm struggling like heck to get my head around multi-dimensional arrays :( Homer.

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  • case insensitive highlighting in php

    - by fusion
    i'm using this function to highlight the results from mysql query: function highlightWords($string, $word) { $string = str_replace($word, "<span class='highlight'>".$word."</span>", $string); /*** return the highlighted string ***/ return $string; } .... $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); the problem is, if i type in 'good', it will only show my search results with a lower-case 'g'ood and not 'Good'. how do i rectify this?

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  • Super fast getimagesize in php

    - by Sir Lojik
    Hi all, im trying to get image size(DIMENSIONS) of hundreds of remote images and getimagesize is way too slow. ive done some reading and found out the quickest way would be to use get_file_contents to read a certain aount of bytes from the images and examining the size within the binary data. Anyone attempted this before? How would i examine different formats. Seen any library for this? please let me know

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  • php mysql , update query is not working

    - by Michael
    I'm trying to update some info into database but for some reasons it doesn't update. Also I'm not getting error in the server logs. mysql_query("UPDATE `view_item` SET `item_number` = $item_number, `title` = $title, `price` = $price, `shipping` = $shipping, `location` = $location, `start_time` = $start_time, `end_time` = $end_time, `seller_userName` = $seller_userName, `seller_UserNum` = $seller_UserNum, `number_of_bids` = $number_of_bids, `picture_link` = $picture_link WHERE `item_number` = $item_number");

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  • How to create PHP method linking?

    - by Kerry
    I've seen other objects that do this: $obj->method1()->method2(); How do I do that? Is each function just modifying the pointer of an object or returning a pointer? I don't know the proper term for this style -- if anyone could help me with that, it would be great.

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  • Make HTTP/1.1 request with PHP

    - by ejunker
    My code is using file_get_contents() to make GET requests to an API endpoint. It looks like it is using HTTP/1.0 and my sysadmin says I need to use HTTP/1.1. How can I make an HTTP/1.1 request? Do I need to use curl or is there a better/easier way?

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  • read XML tag id from php

    - by Sakthivel
    Hi friends i am have the following XML file <?xml version="1.0" encoding="iso-8859-1"?> <Message Id="Language">German</Message> <Message Id="LangEnglish">German</Message> <Message Id="TopMakeHomepage"> Mache 4W Consulting Webseite zu deiner Starseite! </Message> <Message Id="TopLinkEmpSec"> 4W Mitarbeiter </Message> <Message Id="TopLinkFeedback"> Feedback </Message> <Message Id="TopLinkSiteMap"> Site Map </Message> <Message Id="TopLinkContactUs"> Kontakt </Message> <Message Id="TopSetLangEn"> ins Englische </Message> <Message Id="TopSetLangDe"> ins Deutsche </Message> <Message Id="TopSetLangEs"> ins Spanische </Message> <Message Id="MenuLinks"> !~|4W Starseite|Company|Über uns|Kontakt|4W anschließen|Services|Kunden Software Entwicklung|Altsystem Neugestalltung &amp; Umwandlung|Altsystem Dokumentation|Daten Umwandlung &amp; Migration|Erstellen von Datenbeschreibungsverzeichnis|System- &amp; Anwendungs Support|Projekt Management &amp; Planunng|Personal Erweiterung|Projekt Ausgliederung|Mitarbeiter Ausbildung|Technologie|Intersystems Caché|M / MUMPS|Zusätzliche Technologien|Methodologie|Feedback|~! </Message> </MsgFile> in this XML file i need to fetch the contents using the tagid . Please help me to find out this . Thanks in advance

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  • Simple PHP query question: LIKE

    - by pg
    When I replace $ordering = "apples, bananas, cranberries, grapes"; with $ordering = "apples, bananas, grapes"; I no longer want cranberries to be returned by my query, which I've written out like this: $query = "SELECT * from dbname where FruitName LIKE '$ordering'"; Of Course this doesn't work, because I used LIKE wrong. I've read through various manuals that describe how to use LIKE and it doesn't quite make sense to me. If I change the end of the db to "LIKE "apples"" that works for limiting it to just apples. Do I have to explode the ordering on the ", " or is there a way to do this in the query?

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