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  • Need help with transferring data between MySQL db's using PHP

    - by JM4
    In one of the sites I manage, the client has decided to take on ACH/Bank Account administration where it was previously outsourced. As a result, the information submitted in our online form which used to simply store in a single database for processing now must sit in 'limbo' until the funds used for payment have been verified. My original plan is as follows: At the end of an enrollment, all form data is collected and stored in a single MySQL database. Our internal administrator will receive an email notification reminding him enrollments have taken place. He will process the ACH information collected and wait the 3-4 business days needed for payment to clear. Once the payment information has been returned as Good (haven't considered what I will do with the 'bad' yet), the administrator can log into a secure portal which allows him to click a button to 'process' the full information once compared and verified. the process is simplified as: Enrollment complete: data stored in DB 'A' Funds verified and link clicked: data from 'A' is copied to DB 'B' and 'A' is deleted. I have run similar processes with CSV output before and simply used //transfers old data to archive $transfer = mysql_query('INSERT INTO '.$archive.' SELECT * FROM '.$table) or die(mysql_error()); //empties existing table $query = mysql_query('TRUNCATE TABLE '.$table) or die(mysql_error()); but in those cases, ALL data returned was copied and deleted. I only want to copy and delete a single record. Any idea how to accomplish this?

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  • PHP GD Incredibly Strange Problem

    - by ThinkingInBits
    if ($img = imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { die("success"); } if ($img = imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { $image_width = imagesx($img); $image_height = imagesy($img); $target_width = 150; $target_height = 150; if ($image_width > $image_height) { $percentage = ($target_width / $image_width); } else { $percentage = ($target_height / $image_height); } $new_image_width = round($image_width * $percentage); $new_image_height = round($image_height * $percentage); $imgResized = imagecreatetruecolor($new_image_width, $new_image_height); imagecopyresampled($imgResized, $img, 0, 0, 0, 0, $new_image_width, $new_image_height, $image_width, $image_height); imagejpeg($imgResized, $this->path, 100); imagedestroy($img); imagedestroy($imgResized); $this->storeThumbnailLocation(); } else { die ("image was not created or saved"); } The first if statement dies and echos success. If I take out the first if statement, the second one echos "image could not be created or saved" If honestly run out of ideas on this one, the code is identical

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  • override __set in __construct() in php?

    - by user151841
    I have a class based on database values. I'm using __set to automatically sync database values with the class properties. Set checks an array of database fields that it is allowed to update in the database. The field 'id' isn't in the list, so __set will throw an exception if you try to do $objDbRow->id = 5;. However, there is one time when I do want to set the id property of the object, and that's on instantiation. So in __constuct, I have $this->id = $id (where $id is passed to __construct). However, __set seems to be intercepting the setting here, because an exception is being thrown on construction. What's the way to get around this? I suppose I also have a boolean flag, like $instantiated, that __set() would check before it does it's field whitelist checking. But that feels inelegant.

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  • Super fast getimagesize in php

    - by Sir Lojik
    Hi all, im trying to get image size(DIMENSIONS) of hundreds of remote images and getimagesize is way too slow. ive done some reading and found out the quickest way would be to use get_file_contents to read a certain aount of bytes from the images and examining the size within the binary data. Anyone attempted this before? How would i examine different formats. Seen any library for this? please let me know

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  • PHP turn off errors - in one file only

    - by Industrial
    Hi! I am well aware about error_reporting(0); & ini_set('display_errors', "Off"); to make error messages go away. What would be an appropriate way to do this - for a specific file or part of code only? Surpressing errors with @'s seems like a bad idea since it apparently slows the code down... Thanks!

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  • Create a PHP cache system in MySQL database?

    - by Zach Smith
    I'm creating a web service that often scrapes data from remote web pages. After scraping this data, I have a simple multidimensional array of information to use. The scraping process is fairly taxing on my server, and the page load takes a while. I was considering adding a simple cache system using a MySQL database, where I create one row per remote web page with a the array of information pulled from it stored as a JSON encoded string. Is this a good enough system? Or would something like a text file per web page be a better idea?

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  • Php read directory file

    - by kwek-kwek
    I have a script that goes through a directory that has 3 images $imglist=''; $img_folder = "path to my image"; //use the directory class $imgs = dir($img_folder); //read all files from the directory, checks if are images and ads them to a list while ($file = $imgs->read()) { if (eregi("gif", $file) || eregi("jpg", $file) || eregi("png", $file)) $imglist .= "$file "; } closedir($imgs->handle); //put all images into an array $imglist = explode(" ", $imglist); //display image foreach($imglist as $image) { echo '<img src="'.$img_folder.$image.'">'; } but the problem that I am having is it display a 4th img with no image.. yet I only have 3 image in that folder.

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  • How to reformat date in PHP?

    - by Lisa
    I am pulling the dates of various posts from a database. The dates are in the following format: 2009-08-12 Numeric Year - Numeric Month - Numeric Day How can I reformat these dates to something more user friendly like: August 12, 2009 Numeric Month Numeric Date, Numeric Year Assuming that the date gotten from the mysql database is stored in a variable called: $date = $row['date_selected'];

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  • How to create PHP method linking?

    - by Kerry
    I've seen other objects that do this: $obj->method1()->method2(); How do I do that? Is each function just modifying the pointer of an object or returning a pointer? I don't know the proper term for this style -- if anyone could help me with that, it would be great.

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  • update in the php

    - by DAFFODIL
    I wrote a code to insert data .When ,i enter the value in the form and click submit ,the data is getting into database. Now,i should make all those data to edit from from end and,if i click update button,it should be updated in database. Give a snippet for performing this task.

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  • Php pi help... (Loops)

    - by James Rattray
    Is this iteration the best? (Pi^2)/12 = 1 - 1/4 + 1/9 - 1/16 + 1/25 etc. -For converging faster? If not please answer with the iteration -preferably in the form above (an example) -not a splat of algebra ... I'm doing this to find Pi to 1,000,000,000 places online.

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  • REST Authentication in PHP (CodeIgniter)

    - by zidane
    I writing REST API form my web application. Application is written using CodeIgniter framework. Application itself is working fine, but I'm stuck on making REST Authentication. I think that basic Http Authentication will be good enough for some time. Public API is not yet planned. Is there any code example how to achieve REST Authentication so after user is authenticated he can freely call all protected methods.

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  • PHP fails silently when function not defined?

    - by John Isaacks
    I am migrating from PHP4 to PHP5 I have this in my .htaccess: php_flag display_errors on php_value error_reporting 2039 Which used to show all errors. I am still getting some errors but I used to get an error when I called a function that was not defined, but now it stops where it is at and send the client everything up to the error and nothing after. With no error message. Here is what phpinfo is telling me: Directive Local Value Master Value display_errors On Off error_reporting 2039 6143 I would like to be able to see my error messages for trouble shooting purposes. Can someone tell me what I need to do? Thanks!!

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  • PHP Array - some further problems with displaying elements in the array

    - by Homer_J
    Hi again, Thanks in advance for the help. Here is my array based on $rowq: Array ( [0] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [1] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [2] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [3] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [4] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [5] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [6] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [7] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) ) I would like to display elements of the array using (i think) the foreach statement but I can't get it working, ideally, I would like to echo something like this echo "<tr>".$rowq[qnum]." is the questions number and the question text is ".$rowq[qtext].". The page and q values are ".$rowq[page]." and ".$rowq[questions]." respectively."; And that link of text would appear how however many rows the array has in it. Any and all advice appreciated - I'm struggling like heck to get my head around multi-dimensional arrays :( Homer.

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  • PHP SDK Requires two logins...doesn't recognize first

    - by Jay Konieczny
    I am using the following code to authenticate whether users are logged in or not. While users can log in, they have to click the login button twice. Additionally, sometimes even after they click the log-in button twice, my "user info" part of the page (earlier in the page than the content) shows them as logged out while the actual page shows them as logged in. Here is the code. Could someone suggest a better way of handling log-ins? function isLoggedIn($facebook) { if (isset($facebook) and $facebook->getUser() != 0) { // UserID exists, but user may still not be logged in. Let's check: try { $facebook->api('/me', 'GET'); // If this succeeds, then they are logged in. return true; } catch(FacebookApiException $e) { // Some kind of error, so not logged in. if(session_id() === '') session_destroy(); return false; } } else { if(session_id() === '') session_destroy(); return false; } } Thanks!

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  • PHP/MySQL - an array filter for bots

    - by Mike
    Hello, I'm making a hit counter. I have a database and I store the IP and $_SERVER['HTTP_USER_AGENT']; of the visitors. Now I need to add a filter, so I can put away the hits, that are made by bots. I found out, that many bots usually keep some common words in the $_SERVER['HTTP_USER_AGENT']; , so I's like to make and array of words, that would keep the bot from displaying in the results. Here is what I have now: while($row = mysql_fetch_array($yesterday, MYSQL_ASSOC)) { <-- Here I need a code, that would run through an array and check, if it containts the keywords and if it doesn't ... just count++; -- } Also if you know any other way of detecting and removing the bots from the results, I'd be verry thankful. Cheers

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  • php mysql , update query is not working

    - by Michael
    I'm trying to update some info into database but for some reasons it doesn't update. Also I'm not getting error in the server logs. mysql_query("UPDATE `view_item` SET `item_number` = $item_number, `title` = $title, `price` = $price, `shipping` = $shipping, `location` = $location, `start_time` = $start_time, `end_time` = $end_time, `seller_userName` = $seller_userName, `seller_UserNum` = $seller_UserNum, `number_of_bids` = $number_of_bids, `picture_link` = $picture_link WHERE `item_number` = $item_number");

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  • PHP/MySQL Interview - How would you have answered?

    - by martincarlin87
    I was asked this interview question so thought I would post it here to see how other users would answer: Please write some code which connects to a MySQL database (any host/user/pass), retrieves the current date & time from the database, compares it to the current date & time on the local server (i.e. where the application is running), and reports on the difference. The reporting aspect should be a simple HTML page, so that in theory this script can be put on a web server, set to point to a particular database server, and it would tell us whether the two servers’ times are in sync (or close to being in sync). This is what I put: // Connect to database server $dbhost = 'localhost'; $dbuser = 'xxx'; $dbpass = 'xxx'; $dbname = 'xxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die (mysql_error()); // Select database mysql_select_db($dbname) or die(mysql_error()); // Retrieve the current time from the database server $sql = 'SELECT NOW() AS db_server_time'; // Execute the query $result = mysql_query($sql) or die(mysql_error()); // Since query has now completed, get the time of the web server $php_server_time = date("Y-m-d h:m:s"); // Store query results in an array $row = mysql_fetch_array($result); // Retrieve time result from the array $db_server_time = $row['db_server_time']; echo $db_server_time . '<br />'; echo $php_server_time; if ($php_server_time != $db_server_time) { // Server times are not identical echo '<p>Database server and web server are not in sync!</p>'; // Convert the time stamps into seconds since 01/01/1970 $php_seconds = strtotime($php_server_time); $sql_seconds = strtotime($db_server_time); // Subtract smaller number from biggest number to avoid getting a negative result if ($php_seconds > $sql_seconds) { $time_difference = $php_seconds - $sql_seconds; } else { $time_difference = $sql_seconds - $php_seconds; } // convert the time difference in seconds to a formatted string displaying hours, minutes and seconds $nice_time_difference = gmdate("H:i:s", $time_difference); echo '<p>Time difference between the servers is ' . $nice_time_difference; } else { // Timestamps are exactly the same echo '<p>Database server and web server are in sync with each other!</p>'; } Yes, I know that I have used the deprecated mysql_* functions but that aside, how would you have answered, i.e. what changes would you make and why? Are there any factors I have omitted which I should take into consideration? The interesting thing is that my results always seem to be an exact number of minutes apart when executed on my hosting account: 2012-12-06 11:47:07 2012-12-06 11:12:07

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