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• Rails, ActiveRecord, how to find foreign rows that are NOT there?

  - by randombits

  The title is a bit difficult to put together for this question. Say I have two models, Foo and Bar. Foo has many Bar's. Bar belongs to one Foo. How do I use Foo.find to find all of the Foos that currently have zero Bars? In SQL this would translate into something like: SELECT * from foo where id NOT IN (select foo_id from bar);

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• Selecting from a Large Table SQL 2005

  - by Eugene

  I have a SQL table it has more than 1000000 rows, and I need to select with the query as you can see below: SELECT DISTINCT TOP (200) COUNT(1) AS COUNT, KEYWORD FROM QUERIES WITH(NOLOCK) WHERE KEYWORD LIKE '%Something%' GROUP BY KEYWORD ORDER BY 'COUNT' DESC Could you please tell me how can I optimize it to speed up the execution process? Thank you for useful answers.

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• what does positional and named parameter in a query mean?

  - by ajsie

  here we got a positional parameter: SELECT u FROM ForumUser u WHERE u.id = ?1 and here a named parameter: SELECT u FROM ForumUser u WHERE u.username = :name this is DQL (doctrine query language) but i think the concept is the same. could someone please explain what these mean and do?

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• From Now() to Current_timestamp in Postgresql

  - by xRobot

  In mysql I am able to do this: SELECT * FROM table WHERE auth_user.lastactivity > NOW() - 100 now in postgresql I am using this query: SELECT * FROM table WHERE auth_user.lastactivity > CURRENT_TIMESTAMP - 100 but I get this error: operator does not exist: timestamp with time zone - integer How can I resolve ?

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• mySQL JOIN wont return results with 0 count

  - by MPC

  SELECT categories.*, COUNT(categoryID) AS kritCount FROM categories AS categories LEFT JOIN krits ON categories.id = categoryID WHERE (krits.approved = '1') GROUP BY categories.id So this works great except that it does not return a category that has a 0 count of krits in the category. It will if I remove the WHERE statement but I need the WHERE to only select the krits where the field approved = 1

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• problem with IN clause in SQL

  - by user179056

  Hello, We have observed that there seems to be a maximum number of ids/variables which one can pass in the IN clause of SQL as comma seperated values. To avoid this we are storing all the ids in a table and doing a SELECT within the IN clause. This however means extra database operations to store and retrieve ids. Is there any other way to use IN without SELECT? regards Sameer

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• Postgresql full text search part of words

  - by Grezly

  Is postresql capable of doing a full text search, based on 'half' a word? For example i'm trying to seach foor tree, but i tell postgres to search for 'tr'. I can't find such a solution that is capable of doing this. Currently i'm using this select * from test, to_tsquery('tree') as q where vectors @@ q ; But i like to do something like this: select * from test, to_tsquery('tr%') as q where vectors @@ q ;

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• sql user defined function

  - by nectar

  for a table valued function in sql why cant we write sql statements inside begin and end tags like- create function dbo.emptable() returns Table as BEGIN --it throws an error return (select id, name, salary from employee) END go while in scalar valued function we can use these tags like create function dbo.countemp() returns int as begin return (select count(*) from employee) end go is there any specific rule where we should use BEGIN & END tags

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• Where should i store data table [ViewState/ Session/ Catch]

  - by Hemant Kothiyal

  Hi I have datatable having around 10 thousand rows. I would like to store this data once for aspx page. When use select different options in page data would be further select from already stored datatable. I then tried solution using ViewState, but as soon as data grow beyond 100 rows, performance degrade. Where should i store data please help?

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• jquery file type selector

  - by Adi

  Hi, What is the correct jQuery syntax to only select certain file types? e.g. $("#fragment-1 a[SELECT ONLY ANCHOR TAGS WITH FILE TYPE OF MP3]").hide(); Thanks.

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• generating images by user id php + mysql

  - by jay

  function user_image($id, $increment_views = false) { $id = mysql_real_escape_string($id); $q = mysql_query("SELECT * FROM `images` WHERE `id` = '$id'"); if (mysql_num_rows($q)) { $return = mysql_fetch_assoc($q); $q = mysql_query("SELECT * FROM `sources` WHERE `source_id` = $return[id] AND `source_flagged` = 0"); while ($r = mysql_fetch_assoc($q)) { $return['sources'][] = $r; } if ($increment_views) { $q = mysql_query("UPDATE `images` SET `views` = `views` + 1 WHERE `id` = $return[id]"); } return $return; } else { return false; } }

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• Slow query execution time

  - by rotor

  select p.id,p.title,p.slug,p.content, (select url from gallery where postid=p.id limit 1) as url, t.name from posts as p inner join termrel as tr on (tr.object = p.id) inner join termtax as tx on (tx.id = tr.termtax_id) inner join terms as t on (t.id = tx.term_id) where tx.taxonomy_id=3 and p.post_status is null order by t.name asc This query took about 0.2407s to execute. How to make it fast?

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• MySQL Order By Problem, Why is 1000 being seen as Smaller than 2?

  - by Jack

  I have a strange problem, I am trying to order the output of a set of records by a field called displayOrder. Now even though record A has a displayOrder of 2 and record B has a displayOrder of 1000, record B still shows up before record A. Here's my select statement: SELECT * FROM items ORDER BY displayOrder ASC It works fine until I have a record greater than 9, then 10, 11, 12, etc are seen as smaller than 2, 3, 4 because they start with the number 1. Any way to fox this?

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• Problem with sql like

  - by phenevo

  Hi, I'm writing sql query to my SqlCommand, and some part of them looks like: WHERE Path like N'+(select top 1 path from [Paths] where objectcode=@objectCode and objecttype=@objectType)+%' order by path desc,objecttype desc I get no records , bu when I wrote the same in sql server 2005 i have plenty rows... where path like (select top 1 path from [Paths] where objectcode='eg' and objecttype='0')+'%' order by path desc What's wrong ?? @objectType is 'eg'

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• removing comma from string array

  - by sarah

  Hi, I want to execute a query like select ID from "xyz_DB"."test" where user in ('a','b') so the corresponding code is like String s="("; for(String user:selUsers){ s+= " ' " + user + " ', "; } s+=")"; Select ID from test where userId in s; The following code is forming the value of s as ('a','b',) i want to remove the comma after the end of array how to do this ?

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• How to get a profile picture from fb:friends selector

  - by malshan

  Im a Newbie to PHP and FBML(Facebook Markup Language).....so now im coding a Facebook app so I need to get profile picture and friend name when I select a name from FB:Friend Selector Select a Friend <fb:friend-selector uid="exclude_ids" name="pal" idname="friend_sel" /> I use exclude_ids to see all friends in my selector so how to get profile picture? I can get name from this but how to get the profile pic large?

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• how to run a query from the VBA Editor window in ACCESS?

  - by every_answer_gets_a_point

  i would like to do something like this: DoCmd.OpenQuery "select * from some_table;" how would i do this? please keep in mind i don't want create a new query, save it, and run it, i just want to type the select statement in the vba code and run it.

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• how to number the datas from mysql

  - by udaya

  Hi This is a doubt on mysql select query let me axplain my doubt with a simple example consider this is my query SELECT dbCountry from tableCountry tableCountry has fields dbCuntryId dbCountry and dbState I have the result as dbCountry india america england kenya pakisthan I need the result as 1 india 2 america 3 england 4 kenya 5 pakisthan the numbers 12345 must be generated with the increase in data and itis not a autoincrement id How can i get it is it something like loop

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• SQL Server > Query > Column Names

  - by pojomx

  Hi, I'm here again- I have something like this Select A.a, A.b, A.a+A.b as c, (A.a+A.b*2)+A.d as d from Table But i want to know, if it is possible, to make it work with something like this: Select A.a,A.b,A.a+A.b as c, (c*2)+A.d as d from Table Thank you

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• django update object

  - by John

  Hi, How do I run an update and select statement on the same queryset rather than having to do 2 querys, ones to select the object and one to update the object? the sql would be something like update my_table set field_1 = 'some value' where pk_field = some_value Thanks

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• SQL more elegant combination of boolean checks possible?

  - by Matze

  Call me pedantic but is there a more elegant way to combine all those checks? SELECT * FROM [TABLE1] WHERE [path] = 'RECEIVE' AND [src_ip] NOT LIKE '10.48.20.10' AND [src_ip] NOT LIKE '0.%' AND [src_ip] NOT LIKE '127.%' ORDER BY [date],[time] DESC; To something like this: SELECT * FROM [TABLE1] WHERE [path] = 'RECEIVE' AND [src_ip] NOT LIKE IN ('10.48.20.10','0.%','127.%', .... ) ORDER BY [date],[time] DESC;

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• Left Join with Entity Framework

  - by sanfra1983

  hi, someone can tell me how to do this query in EF1: select a.idAnimali, a.titolo, a.commenti, a.ordine, a.idcatanimali, table1.nomefoto FROM tabanimali as a LEFT JOIN (SELECT idanimali, nomefoto tabfotoanimali FROM LIMIT 1) AS Table1 On a.idAnimali = table1.idanimali WHERE a.idcatanimali = idcatanimale Thanks

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• Oracle query with LOWER

  - by Nickolodeon

  Hi. Why this returns 0 rows SELECT GARTUSERID, USER_CODE, UNITID, RANKCODE, RANKID, FIO, LOGINNAME, START_DATE, EXPIR_DATE, NOTE, POSITION, ISCHGPASSWORD, IS_EXPIRDATE, IS_BLOCKED, ROW_ID FROM ACONTROL.GARTUSERS WHERE LOWER(LOGINNAME)=LOWER(:LOGIN) AND ROW_ID=:MD5PSWD and this returns 1 row (as I wanted for the first query)? SELECT GARTUSERID, USER_CODE, UNITID, RANKCODE, RANKID, FIO, LOGINNAME, START_DATE, EXPIR_DATE, NOTE, POSITION, ISCHGPASSWORD, IS_EXPIRDATE, IS_BLOCKED, ROW_ID FROM ACONTROL.GARTUSERS WHERE LOGINNAME=:LOGIN AND ROW_ID=:MD5PSWD

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• How to save the values of one model in another?

  - by ragupathi

  I have user model and Language model where the language model contains different languages and i want the user to select the languages from that model and it should be stored for the corresponding user. Consider there are five languages A, B, C, D, E then the user has to select from the languages. Suppose user 1 selects A and C whereas user 2 selects B and D then the languages has to be stored for that user. How can i do this? please help me.

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• Mysql: Order Results by number of matching rows in Second Table.

  - by KyleT

  I'm not sure the best way to word this question so bear with me. Table A has following columns: id name description Table B has the following columns: id a_id(foreign key to Table A) ip_address date Basically Table B contains a row for each time a user views a row from Table A. My question is how do I sort Table A results, based on the number of matching rows in Table B. i.e SELECT * FROM TableA ORDER BY (SELECT COUNT(*) FROM TableB where TableB.a_id = TableA.id) Thank you!

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