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  • State

    Imagine that you need to develop application for shipping Orders. Your Orders could be in few states: New Order, Registered, Granted, Shipped, Invoiced, Cancelled. And there are some rules which allow your Order to migrate to another state. How to encapsulate states and rules logic? - STATE

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  • WS-Eventing for WCF (Indigo)

    This article describes the design, implementation and usage of the WS-Eventing for distributed applications driven by new MS communication model WCF (Windows Communication Foundation)

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  • Creating simple c++.net wrapper. Step-by-step

    - by sfx
    I've a c++ project. I admit that I'm a complete ZERO in c++. But still I need to write a c++.net wrapper so I could work with an unmanaged c++ library using it. So what I have: 1) unmanaged project's header files. 2) unmanaged project's libraries (.dll's and .lib's) 3) an empty C++.NET project which I plan to use as a wrapper for my c# application How can I start? I don't even know how to set a reference to an unmanaged library. S.O.S.

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  • WebService DIME Bridge

    The DIME Bridge transferring a web service response (any serializable object) in the binary format across the Internet. It's a full transparent loosely coupled solution between the web service and its consumer - just injecting the bridge in their config files.

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  • Utilizing multiple python projects

    - by Marcin Cylke
    Hi I have a python app, that I'm developing. There is a need to use another library, that resides in different directory. The file layout looks like this: dir X has two project dirs: current-project xLibrary I'd like to use xLibrary in currentProject. I've been trying writting code as if all the sources resided in the same directory and calling my projects main script with: PYTHONPATH=.:../xLibrary ./current-project.py but this does not work. I'd like to use its code base without installing the library globaly or copying it to my project's directory. Is it possible? Or if not, how should I deal with this problem.

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  • Maven + Java package declaration

    - by Vasan
    We have a Maven project (packaged as JAR) with Java files. A new Java source file was recently added to this project. The path in which the Java file was added, does not match its package declaration. As expected, Eclipse shows an error in the class for the mismatch. However, Maven builds the project just fine. In the generated JAR file, the .class file is present in the path indicated by the package declaration. We tried moving the Java source file to other incorrect folders (i.e. different from the package declaration), but every time Maven builds the project fine. So, does Maven ignore the actual directory in which the .java file is present? Does it only consider package declaration?

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  • How to remove .zip file in c on windows? (error: Directory not empty)

    - by ExtremeBlue
    include include include include "win32-dirent.h" include include include define MAXFILEPATH 1024 bool IsDirectory(char* path) { WIN32_FIND_DATA w32fd; HANDLE hFindFile; hFindFile = FindFirstFile((PTCHAR)path, &w32fd); if(hFindFile == INVALID_HANDLE_VALUE) { return false; } return w32fd.dwFileAttributes & (FILE_ATTRIBUTE_DIRECTORY); } int RD(const char* folderName) { DIR *dir; struct dirent *ent; dir = opendir(folderName); if(dir != NULL) { while((ent = readdir(dir)) != NULL) { if(strcmp(ent->d_name , ".") == 0 || strcmp(ent->d_name, "..") == 0) { continue; } char fileName[MAXFILEPATH]; sprintf(fileName,"%s%c%s", folderName, '\\', ent->d_name); if(IsDirectory(fileName)) { RD(fileName); } else { unlink(fileName); } } closedir(dir); //chmod(folderName, S_IWRITE | S_IREAD); if(_rmdir(folderName) != 0)perror(folderName); } else { printf("%s <%s>\n","Could Not Open Directory.", folderName); return -1; } return 0; } int main(int argc, char* argv[]) { if(argc < 2) { printf("usage: ./a.out \n"); return 1; } //RD(argv[1]); //_mkdir("12"); //_mkdir("12\\34"); //_rmdir("12\\34"); //_rmdir("12"); char buf[0xff]; sprintf(buf, "unzip -x -q -d 1234 1234.zip"); system(buf); RD("1234"); //unlink("D:\\dev\\c\\project\\removeFolder\\Debug\\1234\\56\\5.txt"); //unlink("D:\\dev\\c\\project\\removeFolder\\Debug\\1234\\56\\6.txt"); //unlink("D:\\dev\\c\\project\\removeFolder\\Debug\\1234\\1_23.zip"); //unlink("D:\\dev\\c\\project\\removeFolder\\Debug\\1234\\4.txt"); //_rmdir("D:\\dev\\c\\project\\removeFolder\\Debug\\1234\\56"); //_rmdir("D:\\dev\\c\\project\\removeFolder\\Debug\\1234"); return 0; } Archive: 1234.zip inflating: 1234/4.txt inflating: 1234/56/5.txt inflating: 1234/56/6.txt inflating: 1234/1_23.zip

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