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  • How can I spot subtle Lisp syntax mistakes?

    - by Marius Andersen
    I'm a newbie playing around with Lisp (actually, Emacs Lisp). It's a lot of fun, except when I seem to run into the same syntax mistakes again and again. For instance, here's something I've encountered several times. I have some cond form, like (cond ((foo bar) (qux quux)) ((or corge (grault warg)) (fred) (t xyzzy))) and the default clause, which returns xyzzy, is never carried out, because it's actually nested inside the previous clause: (cond ((foo bar) (qux quux)) ((or corge (grault warg)) (fred)) (t xyzzy)) It's difficult for me to see such errors when the difference in indentation is only one space. Does this get easier with time? I also have problems when there's a large distance between the (mal-)indented line and the line it should be indented against. let forms with a lot of complex bindings, for example, or an unless form with a long conditional: (defun test () (unless (foo bar (qux quux) (or corge (grault warg) (fred)))) xyzzy) It turns out xyzzy was never inside the unless form at all: (defun test () (unless (foo bar (qux quux) (or corge (grault warg) (fred))) xyzzy)) I auto-indent habitually and use parenthesis highlighting to avoid counting parentheses. For the most part it works like a breeze, but occasionally, I discover my syntax mistakes only by debugging. What can I do?

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  • Asp.Net Cookie sharing

    - by SH
    This is C#.Net code: How to share Cookie between 2 HttpWebRequest calls? Details: I am posting a form in first request, this form contains some setting variables which are used by the system. lets say there is a input field in the form which sets the size of grid pages to be displayed in other pages. Once i have updated the setings in previous request, i go to send a request to another page which shows off asp.net gridview/grid. The grid might contaian several pages and the page size should be the one which i set in previous request. But when i do this via HttpWebReeust it does not happen. When i do it via browser, loading the setting page in the browser and then going to the grid view page... i see the page size is updated. I want to achieve this via code. Sicne i am scraping this grid. i have to set page size or visit the gird pages one by one via code. Or is it possible to set a cookie on 2nd request which is used to set in first request? It will be great if i go this way. any solution?

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  • Filling a region draws it off canvas

    - by Xanyx
    Hi Using the following code in Delphi 2007: procedure TfrmTest.PaintBox1Paint(Sender: TObject); const Rect_Size = 10; begin PaintBox1.Canvas.Brush.Color := clYellow; PaintBox1.Canvas.FillRect(Rect(0, 0, PaintBox1.width, PaintBox1.height)); PaintBox1.Canvas.Brush.Color := clRed; DrawARect(PaintBox1.Canvas, 0, 0, Rect_Size, Rect_Size); end; procedure TfrmTest.DrawARect(ACanvas: TCanvas; iLeft, iTop, iWidth, iHeight: Integer); var rgnMain: HRGN; begin rgnMain := CreateRectRgn(iLeft, iTop, iLeft + iWidth, iTop + iHeight); try SelectClipRgn(ACanvas.handle, rgnMain); ACanvas.FillRect(ACanvas.ClipRect); SelectClipRgn(ACanvas.handle, 0); finally DeleteObject(rgnMain); end; end; I get this: (Yellow area shows boundaries of PaintBox1). HMMM, NOT ALLOWED TO POST IMAGE Please go to: http://www.freeimagehosting.net/uploads/62cf687d29.jpg (Linked image shows a form with a yellow box [PaintBox1] in the center. However my red rectange [rgnMain] has been drawn at pos 0,0 on the form) My expectation was that the red rectangle would be at the top left of the PaintBox1 canvas, not the form's canvas. Why is it not? Can regions only be used with controls that have a Windows handle? Thanks

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  • saveall not saving associated data

    - by junior29101
    I'm having a problem trying to save (update) some associated data. I've read about a million google returns, but nothing seems to be the solution. I'm at my wit's end and hope some kind soul here can help. I'm using 1.3.0-RC4, my database is in InnoDB. Course has many course_tees CourseTee belongs to course My controller function is pretty simple (I've made it as simple as possible): if(!empty($this-data)) $this-Course-saveAll($this-data); I've tried a lot of different variations of that $this-data['Course'], save($this-data), etc without luck. It saves the Course info, but not the CourseTee stuff. I don't get an error message. Since I don't know how many tees any given course will have, I generate the form inputs dynamically in a loop. $form-input('CourseTee.'.$i.'.teeName', array('error' = false, 'label' = false, 'value'=$data['course_tees'][$i]['teeName'])) The course inputs are simpler: $form-input('Course.hcp'.$j, array('error' = false, 'label' = false, 'class' = 'form_small_w', 'value'=$data['Course']['hcp'.$j])) And this is how my data is formatted: Array ( [Course] = Array ( [id] = 1028476 ... ) [CourseTee] = Array ( [0] = Array ( [key] = 636 [courseid] = 1028476 ... ) [1] = Array ( [key] = 637 [courseid] = 1028476 ... ) ... ) )

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  • Asp.net MVC - Model binding image button

    - by big dave
    I've got a very complex form and i'm using the MVC model binding to capture all the information I've got it set up to capture all the different submissions that can happen as there are about 10 different submit buttons on the form, and there are also 2 image buttons I tried to get a bit clever (or so i thought) with capturing the image button submissions, and have created a child class so that i can capture the x value that's returned public class ImageButtonViewData { public int x { get; set; } public string Value { get; set; } } The parent class looks something like this public class ViewDataObject { public ImageButtonViewData ImageButton { get; set; } public ViewDataObject(){ this.ImageButton = new ImageButton(); } } The html for the image button then looks like <input type="image" id="ViewDataObject_ImageButton" name="ViewDataObject.ImageButton" /> This works fine in all browsers except for Chrome. When i debug it in chrome, the Request.Form object contains the values that i would expect, but after the model binding has occurred, the ImageButton property on the ViewDataObject has been set to null The only difference that i can see between the submission values is that Chrome passes the x as lower case (ViewDataObject.ImageButton.x) and IE passes it as upper case (ViewDataObject.ImageButton.X) but i didn't think that model binding took any notice of casing on property names Does anyone have any ideas ?

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  • Textarea (asp:Textbox TextMode="Multiline") overlapping buttons

    - by Gogster
    Hi all, I'm having this problem with form buttons overlapping an asp:Texbox with TextMode set to multi-line: Here is the code: <asp:Panel ID="pnlGiftStep" Visible="false" runat="server"> <img src="/images/shopping-cart/form-separator.png" alt="separator" /> <div class="form-title">GIFT OPTIONS</div> <div class="row"> <asp:TextBox ID="txtGiftName" Height="31" Width="323" BorderStyle="None" Font-Names="Arial" Font-Size="116.7%" runat="server"></asp:TextBox> <cc1:TextBoxWatermarkExtender ID="wmeGiftName" TargetControlID="txtGiftName" WatermarkText="Gift Name" WatermarkCssClass="watermark" runat="server"></cc1:TextBoxWatermarkExtender> </div> <br class="clear" /> <div class="row"> <asp:TextBox ID="txtGiftMessage" Rows="5" Width="323" BorderStyle="None" Font-Names="Arial" TextMode="MultiLine" Font-Size="116.7%" runat="server"></asp:TextBox> <cc1:TextBoxWatermarkExtender ID="wmeGiftMessage" TargetControlID="txtGiftMessage" WatermarkText="Gift Message" WatermarkCssClass="watermark" runat="server"></cc1:TextBoxWatermarkExtender> </div> <br class="clear" /> <div class="button-row"> <asp:ImageButton ID="imbShippingDetails" ImageUrl="/images/shopping-cart/ship-details-btn.png" OnClick="ReturnToShipping" ValidationGroup="shipping" runat="server" /> <asp:ImageButton ID="imbPayDetails" ImageUrl="/images/shopping-cart/pay-details-btn.png" ValidationGroup="pay" runat="server" /> </div> <br class="clear" /> </asp:Panel> Here is the CSS: .row { float:left; height:40px; } .button-row { float:left; width:323px; text-align:right; } Any ideas how I can stop this? Thanks.

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  • Why does this sql statement keep saying it is a boolean and not a paramter? (php/Mysql)

    - by ggfan
    In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

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  • jQuery: responding to click event of element added to document after page load

    - by morpheous
    I am writing a page which uses a lot of in situ editing and updating using jQuery for AJAX. I have come accross a problem which can best be summarised by the workflow described below: Clicking on 'element1' on the page results in a jQuery AJAX POST Data is received in json format The data received in json format The received data is used to update an existing element 'results' in the page The received data is actual an HTML form I want jQuery to be responsible for POSTing the form when the form button is clicked The problem arises at point 6 above. I have code in my main page which looks like this: $(document).ready(function(){ $('img#inserted_form_btn').click(function(){ $.ajax({'type: 'POST', 'url': 'www.example.com', function($data){ $(data.id).html($data.frm); }), 'dataType': 'json'} }); }); However, the event is not being triggered. I think this is because when the document is first loaded, the img#inserted_form_btn element does not exist on the page (it is inserted into the DOM as the result of an element being clicked on the page (not shown in the code above - to keep the question short) My question therefore is: how can I get jQuery to be able to respond to events occuring in elements that were added to the DOM AFTER the page has loaded?

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  • Django ModelForm Imagefield Upload

    - by Wei Xu
    I am pretty new to Django and I met a problem in handling image upload using ModelForm. My model is as following: class Project(models.Model): name = models.CharField(max_length=100) description = models.CharField(max_length=2000) startDate = models.DateField(auto_now_add=True) photo = models.ImageField(upload_to="projectimg/", null=True, blank=True) And the modelform is as following: class AddProjectForm(ModelForm): class Meta: model = Project widgets = { 'description': Textarea(attrs={'cols': 80, 'rows': 50}), } fields = ['name', 'description', 'photo'] And the View function is: def addProject(request, template_name): if request.method == 'POST': addprojectform = AddProjectForm(request.POST,request.FILES) print addprojectform if addprojectform.is_valid(): newproject = addprojectform.save(commit=False) print newproject print request.FILES newproject.photo = request.FILES['photo'] newproject.save() print newproject.photo else: addprojectform = AddProjectForm() newProposalNum = projectProposal.objects.filter(solved=False).count() return render(request, template_name, {'addprojectform':addprojectform, 'newProposalNum':newProposalNum}) the template is: <form class="bs-example form-horizontal" method="post" action="">{% csrf_token %} <h2>Project Name</h2><br> {{ addprojectform.name }}<br> <h2>Project Description</h2> {{ addprojectform.description }}<br> <h2>Image Upload</h2><br> {{ addprojectform.photo }}<br> <input type="submit" class="btn btn-success" value="Add Project"> </form> Can anyone help me or could you give an example of image uploading? Thank you!

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  • How can I measure the time it takes a file to upload to a PHP script?

    - by Gustav Bertram
    I am trying to measure the time a script takes to upload a file to a PHP script, inside the receiving script. Here's a short example: <form action="#" enctype="multipart/form-data" method="post"> Upload: <input type="file" name="datafile" size="40"> <input type="submit" value="Send"> </form> <?php $upload_time = time() - $_SERVER['REQUEST_TIME']; echo $upload_time . " seconds."; I've submitted 4MB, 25MB, 100MB and 1.4GB files. They took anything from a fraction of a second, to almost a minute, yet the script above always yielded 0 seconds. NOTE: I know that this is a duplicate question, but the accepted answer on the other question did not work for me (at least, initially): Detect how long it takes for a file to upload (PHP) I've tried it using PHP 5.3.3 with Apache 2.2.16 on Ubuntu 10.4. UPDATE: I've discovered that both the Apache header and Ajax solutions work. In fact, the solution on the duplicate question also works. The critical element to making these solutions work is to ensure that the following values in the php.ini are sufficiently high: memory_limit = 1000M upload_max_filesize = 1000M post_max_size = 1000M I am accepting the Apache header solution, since it only uses PHP.

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  • Handling large datasets with PHP/Drupal

    - by jo
    Hi all, I have a report page that deals with ~700k records from a database table. I can display this on a webpage using paging to break up the results. However, my export to PDF/CSV functions rely on processing the entire data set at once and I'm hitting my 256MB memory limit at around 250k rows. I don't feel comfortable increasing the memory limit and I haven't got the ability to use MySQL's save into outfile to just serve a pre-generated CSV. However, I can't really see a way of serving up large data sets with Drupal using something like: $form = array(); $table_headers = array(); $table_rows = array(); $data = db_query("a query to get the whole dataset"); while ($row = db_fetch_object($data)) { $table_rows[] = $row->some attribute; } $form['report'] = array('#value' => theme('table', $table_headers, $table_rows); return $form; Is there a way of getting around what is essentially appending to a giant array of arrays? At the moment I don't see how I can offer any meaningful report pages with Drupal due to this. Thanks

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  • ThickBox - update inside without redirect

    - by Alex Maslakov
    ASP.NET MVC and jQuery ThickBox. I show some content in ThickBox. It includes file upload form The view multi-media.apsx (it's strange, the this editor doesn't allow start the line with "<" in the code) form action="/upload/multi-media" method="post" enctype="multipart/form-data" label for="file"File name: input type="file" name="file" id="file" / input type="submit" value="Upload" / <% if (Model.Count > 0) { foreach (FileInfo mediaFile in Model) { <img width="100px" height="100px" src="<%: ResolveUrl("~/audio.png") %>" border="0" alt="<%: mediaFile.Name %>" / //................ After file upload I redirect to /upload/multi-media action and content shows in normal window, not in ThickBox. [ActionName("multi-media"), HttpPost] public ActionResult MultiMedia(HttpPostedFileBase file) { if (file.ContentLength > 0) { file.SaveAs(GenerateNewFileName(fullFileName)); return View("multi-media", model); } } How can I stay into ThickBox after file upload? I need show content in ThickBox all the time, even after the file upload.

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  • Tab Index on div

    - by Mithun P
    Please see the form HTML code below <form method="post" action="register"> <div class="email"> Email <input type="text" tabindex="1" id="email" value="" name="email"> </div> </div> <div class="agreement"> <div tabindex="2" class="terms_radio"> <div onclick="changeTerm(this);" class="radio" id="terms_radio_wrapper" style="background-position: left 0pt;"> <input type="radio" id="terms" value="1" name="terms"><label for="terms">I have read and understood the ZapAV</label> </div> </div> </div> <div class="form_submit"> <input type="button" tabindex="3" value="Cancel" name="cancel"> <input type="submit" tabindex="4" value="Submit" name="submit"> </div> </form> Here I syled teh agreement check box insuch a way that radio input is completly hidden and background image is applied to the wrapper div, and onclick of the wrapper div will toggle the backgroud image as well as the checked status of teh radio input. I need to set the tabindex index on the 'terms_radio' DIV, simply tabindex="2" attribute on div is not working, Is it possible to bring the dotted border on the label for the radio input up on pressing the TAB when the cursor is at email input field?

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  • jQuery dynamic validation

    - by kpomka
    Hi there Im trying to do a few things with jQuery validation plugin and seems stuck on one place. Here is some code: <script type="text/javascript"> $(document).ready(function(){ $('#myform').validate(); $('#email').rules('add', {required: true, messages: {required: 'email is required'}} ); $('#phone').rules('add', {required: true, messages: {required: 'phone is required'}} ); $('#validate').click(function(){ $('#result').text($('#myform').validate().form()); return false; }); }); </script> <form id="myform"> <div>email:<input type="text" id="email" /></div> <div>phone:<input type="text" id="phone" /></div> <div id="result"></div> <input id="valdate" type="image" src="images/submit.png" /> </form> As a result i keep getting a wrong error message. If i click on submit button 'phone is required' is shown near email input and 'email is required' isnt shown at all. Whats wrong with this code ?

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  • Very Urgent :How to start a new session if a user click on the new tab in IE or mozilla on websphere

    - by ha22109
    Hi, I have one "user search" portlet on the home page of one application running on websphere portal server.Which display the matching user records as per the search criteria filled in the search form.I have requirement to have a "back to search input" link on the results page which onclick should show the filled form on the input jsp. The issue which i am facing is if i open the application in two diff tab of same IE browser and start giving some search criteria and submit and same time search for some other input from other IE tab (in the same browser)and then go back to previous tab and click on "back to search input" link then instead of showing me the first input it will show me the imput which i entered in the next IE tab. I am setting and getting the bean(form bean) through portlet session.but in the two diff tab of same IE it will be the sae user session (and may be the same portlet session..) Please tell me solution for this. The one thing to be notice here is i can access this "user search" application even without doing login also.so it must be taking the default portlet session in this case. what wil happen once i login and then search,will it going to overwrite the portlet session and http session or howz is that?

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  • Disabling Text field with Javascript when value in drop down box is from mysql

    - by SteveJ313
    Hi I have a simple script in HTML, using a dropdown menu. When the value 1 is selected, the user can write in the text field, if value 2 is selected, it disables the text field. However, i changed the values of the dropdown menu, so that one value was from a mysql table(using PHP) and the other remained 'option value='1''. Yet now neither text field is disabled. Below is the code. `<script type="text/javascript"> function findselected() { if (document.form.selmenu.value == <?php echo $id; ?>) { document.form.txtField.disabled=true; // return false; // not sure this line is needed } else { document.form.txtField.disabled=false; // return false; // not sure this line is needed } } ` And the PHP section if(mysql_num_rows($SQL) == 1) { echo "<select name='selmenu' onChange='findselected()'>"; echo "<label>TCA_Subject</label>"; while ($row=mysql_fetch_array($SQL)) { echo "<option value='$id'>$thing</option>"; echo "<option value='2'>Choice 2</option>"; } } echo "<option value=$userid>'Choice 1'</option>"; ?> <option value='2'>Choice 2</option>"; </select> I have tried taking the second option value out of the loop, putting it into html, editing the variable in the javascript function. There is not a fault with the PHP as it is retrieving the right results and displaying it, yet the text field doesnt become disabled. Does anyone know of a possible solution? Thanks

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  • What are various methods for discovering test cases

    - by NativeByte
    All, I am a developer but like to know more about testing process and methods. I believe this helps me write more solid code as it improves the cases I can test using my unit tests before delivering product to the test team. I have recently started looking at Test Driven Development and Exploratory testing approach to software projects. Now it's easier for me to find test cases for the code that I have written. But I am curios to know how to discover test cases when I am not the developer for the functionality under test. Say for e.g. let's have a basic user registration form that we see on various websites. Assuming the person testing it is not the developer of the form, how should one go about testing the input fields on the form, what would be your strategy? How would you discover test cases? I believe this kind of testing benefits from exploratory testing approach, i may be wrong here though. I would appreciate your views on this. Thanks, Byte

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  • How to add or remove a value inside a table cell on selection / de-selection of checkbox of that row, trying to submit the value via Jquery?

    - by Raul
    Here is the table: <%= form_tag '', :id => "costs" do %> <table class="table table-bordered" id="service_cost"> <% @services.each do |service| %> <tbody> <tr> <td><%= check_box_tag :open_service, {}, false, :class => 'checkable' %></td> <td><%= service.phone %></td> <td><%= service.internet %></td> <td></td> <td></td> <td></td> <td></td> <td></td> <td><%= service.house_keeping %> </td> <td>0.0 </td> <td><%= service.laundry %></td> <td><%= text_field_tag "service_cost", service.total, :class => "input-small" %></td> </tr> <% end %> when the form gets submitted, the javascript gets into action: $("#costs").submit(function(){ formData=$("#costs").serializeArray(); processFormData(formData) return false; }); This ensures form submission on selecting the checkbox: $('.checkable').live('change', function() { $(this).parents('form:first').submit(); }); But, what I am looking for is adding or removing a cell value based on checkbox selection/de-selection and submitting it, kindly suggest a way to do it.

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  • Codeigniter PHP - loading a view at an anchor point

    - by James Billings
    I have a form at the bottom of a long page, if a user fills out the form but it doesn't validate the page is reloaded in the typical codeigniter fashion: $this->load->view('template',$data); however because the form is way down at the bottom of the page I need the page to load down there like you do with HTML anchors. Does anyone know how to do this in codeigniter? I can't use the codeigniter redirect(); function because it loses the object and the validation errors are gone. Other frameworks I've used like Yii you can call the redirect function like: $this->redirect(); which solves the problem because you keep the object. I've tried using: $this->index() within the controller which works fine as a redirect but the validation errors are in another method which is where the current page is loaded from: $this->item($labs) but when I use this it get stuck in a loop Any ideas? I've seen this question a lot on the net but no clear answers. I'm researching using codeigniter "flash data" but think it's a bit overkill. cheers.

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  • cfdiv working in FF and Safari but does not show up in IE

    - by JS
    Within a form I have a button that launches a cfwindow, then presents a search screen for the user to make a selection. Once selection is made, the cfwindow closes and the selected content shows in the main page by being bound to a cfdiv. This all works fine in FF but the cfdiv doesn't show at all in IE. In IE, the cfwindow works, the select works, but then no bound page. I have tried setting bindonload and that made no difference (and I need it to be true if there is content that is pulled in via a query when it loads). All I have been able to find so far regarding this issue is setting bindonload to false and putting the cfdiv outside of the form but that's not possible in my current design. Here is a snippet which is inside of a larger form (and all necessary tags are cfimported). <td class="left" style="white-space:nowrap;"> <cfoutput>#n#</cfoutput>.&nbsp;<cfinput type="button" value="Select" name="x#n#Select#i#" onClick="ColdFusion.Window.create('x#n#Select#i#', 'Exercise Lookup', 'xSelect/xSelect.cfm?xNameVar=x#n#S#i#&window=x#n#Select#i#&workout=workout#i#', {x:100,y:100,height:500,width:720,modal:true,closable:true,draggable:true,resizable:true,center:true,initshow:true,minheight:200,minwidth:200 })" /> &nbsp; <cfdiv id="x#n#S#i#" tagName="x#n#S#i#" bind="url:xSelect/x.cfm"></cfdiv> <cfinput type="hidden" name="x#n#s#i#" value="#n#"> </td> Thanks for any help.

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  • jquery select one class from many

    - by simnom
    Hi, I'm trying to achieve the following functionality. Within a form I have multiple fields with the class name .inputField if one of these fields is selected then the div associated with that element should be shown on focus and hidden on blur. However, when I implement the code below on selecting the second element the class is applied to both. Not sure where I'm going wrong?!?!? html markup: <form class="friendlyForm" name="friendlyForm" id="friendlyForm"> <ul> <li> <label for="testField">Test field</label> <input name="testField" value="here" class="inputField" id="testField" /> <div class="helper" style="display: none;">helper text here</div> </li> <li> <label for="testField">Test field2</label> <input name="testField2" value="here" class="inputField" id="testField2" /> <div class="helper" style="display: none;">helper text here</div> </li> </ul> </form> jQuery markup: $('.friendlyForm').find('.inputField').each(function(i) { $(this).blur(); $(this).focus(function() { //Add the focus class and fadeIn the helper div $(this).parent().addClass('focus'); $(this).parent().parent().find('.helper').fadeIn(); }); $(this).blur(function () { //Remove the focus class and fadeOut helper div $(this).parent().removeClass('focus'); $(this).parent().parent().find('.helper').fadeOut(); }); }); Any pointers here would be greatly appreciated. Thanks

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  • PHP checking/refreashing functions

    - by user1284360
    ok i have a main document that displays a chatbox, what i want is for the chatbox to refreash on everyone who is logged in's screen whenever someone posts a new message... ive tried many methods including sleep timers and new functions that call then sleep and get recalled but this just generates an endless line of the same or little diffrent data making the form unusable until error... this is my code <?php // set error reporting level if (version_compare(phpversion(), "5.3.0", ">=") == 1) error_reporting(E_ALL & ~E_NOTICE & ~E_DEPRECATED); else error_reporting(E_ALL & ~E_NOTICE); require_once('inc/login.inc.php'); require_once('inc/chat.inc.php'); // initialization of login system and generation code $oSimpleLoginSystem = new SimpleLoginSystem(); $oSimpleChat = new SimpleChat(); // draw login box echo $oSimpleLoginSystem->getLoginBox(); // draw chat application $sChatResult = '<font color="0x99000"> <a href="Register_form.html">New Account</a><br> login to send a message<br> or register for a new account</font>'; if ($_COOKIE['member_name'] && $_COOKIE['member_pass']) { if ($oSimpleLoginSystem->check_login($_COOKIE['member_name'], $_COOKIE['member_pass'])) { $sChatResult = ""; if($oSimpleLoginSystem->check_privledges($_COOKIE['member_name']) >= 2) { $sChatResult .= "<br>privledge check Working<br>"; } $sChatResult .= "<form action=$_SERVER[PHP_SELF] method='post'> <input type='hidden' name='foo' value='<?= $foo ?>' /> <input type='submit' name='submit' value='Refresh Messages' /> </form>"; $sChatResult .= $oSimpleChat->acceptMessages(); $sChatResult .= "<br><br>"; $sChatResult .= $oSimpleChat->getMessages(); } } echo $sChatResult; ?>

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  • wordpress add post validation

    - by dskanth
    This is embarrassing, but yet i am surprised to see that there is no validation by default while adding a new post in wordpress. When i don't enter a title and even content, and just hit Publish, it says that the post is published, and when i view the front end, there is no new post. How could wordpress skip the simple validation for adding a post? Atleast i expected a server side validation (if not client side). Don't know why the validation is skipped. It is upto wordpress, whether they incorporate it in the new versions. But i want to know how can i add a javascript (or jquery) validation for adding a post in wordpress. I know it must not at all be difficult. But being new to wordpress, i would like to get some hint. From Firebug, i could see the form is rendering like: <form id="post" method="post" action="post.php" name="post"> ... </form> Where shall i put my javascript validation code?

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  • Upload to a PHP Server, using Ajax ( XMLHttp POST)

    - by Krishnanunni
    Right now i'm using the below method to Upload a file to PHP <form enctype="multipart/form-data" action="http://sserver.com/fileupload.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="30000000" /> <input type="hidden" name="filename" value="file_uploaded.gif" /> <input type="hidden" name="username" value="foobar"/> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> I read the $_POST and $_FILE in php to complete upload like this. $target = $_SERVER['DOCUMENT_ROOT']."/test/upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; echo $target; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } My questions is , can i change the above said code (HTML) to an Ajax XMLHttpRequest without changes in PHP.

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  • C#: Passing data to forms UI using BeginInvoke

    - by Bi
    Hi I am a C# newbie and have a class that needs to pass row information to a grid in the windows form. What is the best way to do it? I have put in some example code for better understanding. Thanks. public class GUIController { private My_Main myWindow; public GUIController( My_Main window ) { myWindow = window; } public void UpdateProducts( List<myProduct> newList ) { object[] row = new object[3]; foreach (myProduct product in newList) { row[0] = product.Name; row[1] = product.Status; row[2] = product.Day; //HOW DO I USE BeginInvoke HERE? } } } And the form class below: public class My_Main : Form { //HOW DO I GO ABOUT USING THIS DELEGATE? public delegate void ProductDelegate( string[] row ); public static My_Main theWindow = null; static void Main( ) { Application.EnableVisualStyles(); Application.SetCompatibleTextRenderingDefault(false); theWindow = new My_Main(); Application.Run(theWindow); } private void My_Main_Load( object sender, EventArgs e ) { /// Create GUIController and pass the window object gui = new GUIController( this ); } public void PopulateGrid( string[] row ) { ProductsGrid.Rows.Add(row); ProductsGrid.Update(); } } Thanks!

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