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  • permutation need help to code

    - by Hunt
    Thank for your reply, first thing i wish to thank you for trying to help me out, and i have post this in few website also no one trying to help at all. For my code, what i wish to do is permutation count. it will count from top to bottom 1,2,3 1,2,3 1,2,3 output to 111 = 1 112 = 1 113 = 1 121 = 1 122 = 1 123 = 1 133 = 1 211 = 1 212 = 1 213 = 1 333 = 1 and continue till all number is count and also store to the array which can check how many count after all code will check the input number and count how many outcome and show the results with how many outcome and each have how many after permutation count. Its hard to do?. Anyway thank you for help.

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  • how to put header authentication into a form using php?

    - by SkyWookie
    Hey guys, for the page I am doing needs a login authentication using Twitter (using tweetphp API). For test purposes I used this code below to do a successful login: if (!isset($_SERVER['PHP_AUTH_USER'])){ header('WWW-Authenticate: Basic realm="Enter your Twitter username and password:"'); header('HTTP/1.0 401 Unauthorized'); echo 'Please enter your Twitter username and password to view your followers.'; exit(); } $username = $_SERVER['PHP_AUTH_USER']; $password = $_SERVER['PHP_AUTH_PW']; The problem now is, I want to integrate it into a form, so far I have the following: <form action="logincheck.php" method="post" class="niceform" > <fieldset> <legend>Twitter Login:</legend> <dl> <dt><label for="email">Twitter Username:</label></dt> <dd><input type="text" name="username" id="username" size="32" maxlength="128" /></dd> </dl> <dl> <dt><label for="password">Password:</label></dt> <dd><input type="password" name="password" id="password" size="32" maxlength="32" /></dd> </dl> </fieldset> <fieldset class="action"> <input type="submit" name="submit" id="submit" value="Submit" /> I am sending it to logincheck.php, this is where I think I get stuck. I am not sure how to compare the form data with Twitter's login data. I was trying a similar if statement as I used in the first code (box that pops up before page loads), but I couldn't wrap my head around it. Thanks again guys!

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  • Jquery hover function doesn't work for a table...

    - by chandru_cp
    I dynamically added rows to a table but it doesn't seem to take hover effects given in jquery... Here is my code, <table id="chkbox" cellpadding="0" cellspacing="2" width="100%" class="table_Style_Border"> <tr> <td style="width:150px" class="grid_header" align="center">RackName</td> <td style="width:150px" class="grid_header" align="center">LibraryName</td> <td style="width:200px" class="grid_header" align="center">LibrarianName</td> <td style="width:200px" class="grid_header" align="center">Location</td> <td style="width:1%" class="grid_header"></td> </tr> <? if(isset($comment)) { echo '<tr><td class=table_label colspan=5>'.$comment.'</td></tr>'; } ?> <?php foreach($rackData as $key => $row) { ?> <?php printf('<tr class="%s">', ($key % 2) ? 'rowcolor' : 'alternaterowcolor'); ?> <td align="left" class="table_label"> <?=$row['rack_name']?> </td> <td align="left" class="table_label"> <?=$row['library_name']?> </td> <td align="center" class="table_label"> <?=$row['librarian']?> </td> <td align="center" class="table_label"> <?=$row['location']?> </td> <td align="center"> <input type="checkbox" name="group" id="group" value="<?=$row['rack_id']?>" onclick="display(this);" > </td> </tr> <? } ?> </table><div align="right" class="pagination"> <?php /*?><?php echo $links;?><?php */?></div> <script type="text/javascript"> $("#chkbox").hover(function() { $(this).addClass("resultshover"); }, function() { $(this).removeClass("resultshover"); }); </script>

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  • Why is this <p> expanding the whole page?

    - by George Edison
    If you visit this page and shrink your browser window, you will see my problem. [If you want to open the page in a new window, just hold down shift when you click the link.] The answers to the question extend beyond the page margin instead of wrapping. I have spent the last half hour working with Chrome's Inspector and Firefox's DOM inspector - all to no avail. I just cannot figure out why it's doing this.

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  • How to design websites for all display sizes

    - by katie bekell
    I like to use a lot of unique graphics on my pages, which often results in making different page sizes depending on available screen width/height. Here are two examples: http://www.uvm.edu/~areid/homesite/ - the image floats at the bottom of my screen but on a larger browser, the image floats near the middle making it look off. It looks best when the bottom of the window aligns with the bottom of the image www.stevenlebel.com - it loads two different pages depending on what monitor size is detected. This seems like a lot of redundant coding. My question is, how can I make sliced/Photoshop images transition well to different screen sizes. Does Photoshop allow you to make DIVS instead of tables? Can i make each of the slices created by Photoshop grow/shrink when the browser window size changes? If anyone has any input on creating websites like this I would be very interested to hear what they have to say. Thanks Katie

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  • Deploying patches and new versions.

    - by 0plus1
    I'm deveoping a big project, I have the dev folder (connected to a specific subdomain) then the "real" folder, the live one. When I'm ready to push patches or whole new versions I'm currently copying the files individually, is there a program that can help me do this task? Keep in mind that some files (the config one and the htacess) must never change in the live version. Thank you

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  • Loading/Displaying large amount of data on webpage.

    - by jb
    I have a webpage which contains a table for displaying a large amount of data (on average from 2,000 to 10,000 rows). This page takes a long time to load/render. Which is understandable. The problem is, while the page is loading the PCs memory usage skyrockets (500mb on my test system is in use by iexplorer) and the whole PC grinds to a halt until it has finished, which can take a minute or two. IE hangs until it is complete, switching to another running program is the same. I need to fix this - and ideally i want to accomplish 2 things: 1) Load individual parts of the page seperately. So the page can render initially without the large data table. A loading div will be placed there until it is ready. 2) Dont use up so much memory or local resources while rendering - so at least they can use a different tab/application at the same time. How would I go about doing both or either of these? I'm an applications programmer by trade so i am still a little fizzy on the things I can do in a web environment. Cheers all.

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  • Echo mysql results in a loop?

    - by Roy D. Porter
    I am using turn.js to make a book. Every div within the 'deathnote' div becomes a new page. <div id="deathnote"> //starts book <div style="background-image:url(images/coverpage.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"></div> //creates new page </div> //ends book What I am doing is trying to get 3 'content' (content being a name and cause of death) divs onto 1 page, and then generate a new page. So here is what i want: <div id="deathnote"> //starts book <div style="background-image:url(images/coverpage.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"></div> //creates new page <div style="background-image:url(images/paper.jpg);"> //creates new page but leaves it open <div> CONTENT </div> <div> CONTENT </div> <div> CONTENT </div> </div> //ends the page </div> //ends book Seems simple enough, however the content is data from a MySQL DB, so i have to echo it in using PHP. Here is what i have so far <div id="deathnote"> <div style="background-image:url(images/coverpage.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <div style="background-image:url(images/paper.jpg);"></div> <?php $pagecount = 0; $db = new mysqli('localhost', 'username', 'passw', 'DB'); if($db->connect_errno > 0){ die('Unable to connect to database [' . $db->connect_error . ']'); } $sql = <<<SQL SELECT * FROM `TABLE` SQL; if(!$result = $db->query($sql)){ die('There was an error running the query [' . $db->error . ']'); } //IGNORE ALL OF THE GARBAGE ABOVE. IT IS SIMPLE CONNECTING SCRIPT THAT I KNOW WORKS //THE METHOD I AM HAVING TROUBLE WITH IS BELOW $pagecount = 0; while($row = $result->fetch_assoc()){ //GETS THE VALUE (and makes sure it isn't nothing echo '<div style="background-image:url(images/paper.jpg);">'; //THIS OPENS A NEW PAGE while ($pagecount !== 3) { //KEEPS COUNT OF HOW MUCH CONTENT DIVS IS ON THE PAGE while($row = $result->fetch_assoc()){ //START A CONTENT DIV echo '<div class="content"><div class="name">' . $row['victim'] . '</div><div class="cod">' . $row['cod'] . '</div></div>'; //END A CONTENT DIV $pagecount++; //UP THE PAGE COUNT } } $pagecount=0; //PUT IT BACK TO 0 echo '</div>'; //END PAGE } $db->close(); ?> <div style="background-image:url(images/backpage.jpg);"></div> //BACK PAGE </div> At the moment i seem to be causing and infinite loop so the page won't load. The problem resides within the while loops. Any help is greatly appreciated. Thanks in advance guys. :)

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  • i want to show a panel just like facebook or for captcha validation

    - by Lokesh
    i have a simple form and when user enters all the information and hits the submit botton than a panel should open just a width of 200px and height of 100px inside the same window. which should have two fields one is captcha image and a text box and a check botton and if captcha code is right than panel should automatically close and redirect to another page just like facebook . all the details of the panel is saved on another php file.

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  • Variable disappears when I log in

    - by John
    Hello, I have profile page where the profile is retrieved via GET. The index file has this: $profile = $_GET['profile']; When I log in on the profile page, the $profile variable disappears. Here is the form action on the login function: <form name="login-form" id="login-form" method="post" action="./index.php"> (The $profile variable is separate of the login username.) How could I make the page retain the $profile variable? Thanks in advance, John

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  • how to add url in onclick function????

    - by rajesh
    i have line new_element.innerHTML =""; which will call the function addWidget as function addWidget(url) { alert(url); var main= document.getElementById('mainwidget'); main.innerHTML = ""; } but its not working whats the problem...

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  • Align 3 images in a div , left-centre-right, uneven margin

    - by Adrian
    I could find a work around for this if I wanted but it seems wrong and am trying to learn to code in a neater way. Basically I have a div with 3 images in it, the div is 700px, and each image is 220px, So thats 660px with two 20px gaps left and right of the centre image, and the outside images going all the way to their end of the div. Is there a quicker way of doing this without setting up seperate ids for each image? .contentpictureblock { float:left; } .contentpictureblock img { margin-right:20px; } <div class="contentpictureblock"> <img src="http://..."> <img src="http://..."> <img src="http://..."> </div> Doing the above^ pushes the third image to the next line, which is understandable. I know I could always make seperate divs for each image, and adjust the margins for each one but Im just wondering is there a quicker one off overflow type command that I could apply to the above? It would mean the right margin would be on all the images but would have no effect on its positioning in the last image. Thanks for the help.

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  • Parsing XML with jQuery

    - by Jamie
    I've used this: $(document).ready(function () { $.ajax({ type: "GET", url: "http://domain.com/languages.php", dataType: "xml", success: xmlParser }); }); function xmlParser(xml) { $('#load').fadeOut(); $(xml).find("result").each(function () { $(".main").append('' + $(this).find("language").text() + ''); $(".lang").fadeIn(1000); }); } I used a local XML file on my computer, it works fine, but when I change the URL to an website, it just keeps loading all the time... How do I get this to work?

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  • Gradient colors in Internet Explorer

    - by Jeremy
    I know that Internet Explorer has some proprietary extensions so that you can do things like create divs with a gradient background. I can't remember the element name or it's usage. Does anyone have some examples or links?

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  • jQuery: Trouble with draggable across cloned elements

    - by Rosarch
    I'm trying to implement: User drags a draggable li to a droppable li. The original li is no longer draggable A new li is cloned from the original li, and is appended to the droppable li. I can't get it to work. function moveToTerm(original_course, helper, term) { var cloned_course = original_course.clone(true); original_course.addClass('already-scheduled'); original_course.draggable('disable'); cloned_course.draggable(); cloned_course.appendTo(term).hide().fadeIn('slow'); } This works fine, except now the cloned_course is not draggable. A droppable li: <li class="term ui-droppable"> <strong>Fall 2010</strong> <li class="course">Computing Cultures</li> <!-- this course was just dropped. I want it to be draggable but it's not --> <li class="course ui-draggable" style="display: list-item;">New Media and Society</li> </li> What am I doing wrong?

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  • Refreshing page after posted vars

    - by Pete Herbert Penito
    So a form is submitted on my site, with form action equal to itself. I want the user to be able to refresh the page without sending the same variables again. I thought unset($_POST); would accomplish this for some reason it doesn't is there another way to accomplish this?

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  • onblur deletes data when submit, why?

    - by Syom
    i have the following script <input style="color: #ccc" type="text" value="something" name="country" onFocus="if (this.value == 'something') { this.value='';this.style.color='black';}" onblur="if (this.value != 'something') { this.value='something'}" /> <input type="submit" value="save" /> it works fine, but when i click on submit button, it also deletes the value "something" so, what can i do, if i want, that when i click on submit button, value doesn't delete? thanks

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  • Form still posts back with return false in JS

    - by jiewmeng
    it seems like #frmToDo still posts backs <form id="frmToDo" name="frmToDo"> ... <a id="btnSubmit" href="javascript:document.frmToDo.submit();">Add</a> google.load("jquery", 1); google.load("jqueryui", 1); google.setOnLoadCallback(function() { ... $("#frmToDo").submit(function() { return false; ... why will this happen? might it be because of href="javascript:document.frmToDo.submit(). how can i submit the form with that link (i didnt use <input type="submit" /> because of styling problems, it seems like buttons are harder to style, esp in different browsers) the AJAX way?

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  • How to load content from external page using jQuery?

    - by Pr0fess0rX
    Hello, Is it possible to load content from an external page (not relative) into div using jquery? I mean here by external page is another web application like for example: http://www.yahoo.com There is the code: $("#externalContent").load("http://www.yahoo.com", function () { alert("loading finish"); }); when I use firebug I got this result: you see here, i highlighted the response code, it's 200 which means OK, but still no content loaded. DOES anyone know the reason?

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  • Codeigniter achor producing dodgy link in email inbox.. what could the problem be?

    - by Psychonetics
    My application is emailing out fine but the email I receive displays incorrectly. Rather than have text and a simple "click here to activate" link it doesn't. it shows this instead: Hi user1, please click the following link to activate your account <a href="http://mysite.com/activation/fzyZuyxVAzZS2koVg5UFjfVjlcLNcrzp">ssss</a> Here is the code from my model that sends email to user when they request activation email. $this->load->library('email'); $this->email->from('[email protected]', 'my site'); $this->email->to($result[0]->email); $this->email->subject('my site - Activate your account'); $this->email->message('Hi ' . $result[0]->first_name . ', please click the following link to activate your account ' . anchor('http://mysite.com/activation/' . $new_activation_code, 'click here to activate')); $this->email->send(); Also the mail always ends up in my spam folder.

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