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  • Incrementing through mysql PHP

    - by Rawdon
    I am looking at try to increment and decrement by three records through a table and present those records. Say if the id '4' is currently active. I want the to be display the ID's and category of 3.2.1 and 5.6.7 from an increment and decrement So far I have: $stmt = $db->query("SELECT id, category FROM test"); $stmt->execute(); while ($results = $stmt->fetch(PDO::FETCH_ASSOC)) { $current = $results['id']; $category = $results['category']; $next = array(array('slide_no' => $current, 'category' => $category)); } print_r($next); Now with this, I am getting back every row in the table. I'm now getting confused on how I could increment and decrement the records by 3 and make sure that the category will also increment correctly. Thank you very much.

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  • PHP: question about passing parameters in URL's

    - by user248959
    Hi, i have this two lines: var_dump($parametros_post_signin); $this->redirect('prueba/aux?email='.$parametros_post_signin['signin']); the first one prints this: array 'signin' => array 'email_address' => string '' (length=0) 'password' => string '' (length=0) the second one takes to another action where i have this code: var_dump($request->getParameter('email')); that prints this: string 'password' (length=8) I expected it to print something like this: string '' (length=0) What should i do to the get value of the 'email_address' field ? Regards Javi

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  • Problem with unlink() in php!

    - by Holicreature
    I'm creating a temp image always named 1.png under specific folder and once i read the image_contents and process, i use unlink() to delete that specific image from that folder. But sometimes the image file is not deleted and the same image is file is read and processed. That script is working otherwise fine... There is no permission related issues , as the files are deleted sometimes... Will there be any issue when the script is repeatedly called and the image with the name is already present and not deleted etc.. ??? Please suggest me what would be the problem extension_loaded('ffmpeg'); $max_width = 120; $max_height = 72; $path ="/home/fff99/public_html/temp/"; ..... ..... $nname = "/home/friend99/public_html/temp/".$imgname; $fileo = fopen($nname,"rb"); if($fileo) { $imgData = addslashes(file_get_contents($nname)); .... ... .. } unlink('$nname');

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  • Accessing array elements in PHP

    - by Elliot B.
    I have an array $aMethods whose print_r output is this: Array ( [0] => Array ( [pattern] => [return_media] => 1 [return_name] => ) ) I'm trying to access 'return_media' with this code: $iReturnMedia = $aMethods[0]->return_media; echo $iReturnMedia; Also, when I tried this: $iReturnMedia = $aMethods[0]['return_media']; I get an error stating: Cannot use string offset as an array in... But it's not working, $iReturnMedia comes back as blank. Could someone tell me what I'm doing wrong here?

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  • PHP & MySQL query value question.

    - by space
    How can I use the first query's id value $row['id'] again after I run a second query inside the while loop statement? To show you what I mean here is a sample code below of what I'm trying to do. I hope I explained it right. Here is the code. $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id = 4"); if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); } while($row = mysqli_fetch_assoc($dbc)) { echo '<div>User: ' . $row['id'] . '</div>'; echo '<div>Link To User' . $row['id'] . '</div>'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc2 = mysqli_query($mysqli,"SELECT COUNT(cid) as num FROM comments WHERE comments_id = $row[id]"); if (!$dbc2) { // There was an error...do something about it here... print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc2)){ $num = $row['num']; } } echo '<div>User ' . $row['id'] . ' Comments# ' . $num . '</div>'; }

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  • split a string into a key => value array in php

    - by andy-score
    +2-1+18*+7-21+3*-4-5+6x29 The above string is an example of the kind of string I'm trying to split into either a key = value array or something similar. The numbers represent the id of a class and -,+ and x represent the state of the class (minimised, expanded or hidden), the * represents a column break. I can split this into the columns easily using explode which gives and array with 3 $key = $value associations. eg. $column_layout = array( [0] => '+2-1+18' , [1] => '+7-21+3' , [2] => '-4-5+6x29' ) I then need to split this into the various classes from there, keeping the status and id together. eg. $column1 = array( '+' => 2 , '-' => 1 , '+' => 18 ) ... or $column1 = array( array( '+' , 2 ) , array( '-' , 1 ) , array( '+' , 18 ) ) ... I can't quite get my head round this and what the best way to do it is, so any help would be much appreciated.

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  • php associative array name?

    - by daniel Crabbe
    hello! Just trying to get the name of an assoc array; $test = array('selected' =>$selected, 'sectionList'=>$sectionList, 'categoryList'=>$categoryList); <? foreach($test as $list) { ?> <h3><?=$list?>, <?=$list[id]?>, <?=$list['name']?>, <?=$list['value']?></h3> <? } ?> but either get 'Array' or nothing?! I can see the name when i print_r($test); Do you think this is possible? Thanks in advance, D.

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  • Delete an (exact) element from an array in php

    - by Holian
    Hi Masters! For example i have an array like this: $test= array("0" => "412", "1" => "2"); I would like to delete the element if its = 2 $delete=2; for($j=0;$j<$dbj;$j++) { if (in_array($delete, $test)) { unset($test[$j]); } } print_r($test); But with this, unfortunatelly the array will empty... How can i delete an exact element from the array? Thank you

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  • PHP: Classes to use functions from each other?

    - by Martti Laine
    Hello I've been into this problem for a while already, and have asked some questions about it here Stackoverflow. I've got some advice, but I just can't understand it. Could someone provide me an example of classes working smoothly together. I have 3 (maybe more) classes: mysql user alerts As I said, could someone provide an example, so these classes could use functions from each other class, e.g. user could use mysql's functions. I'm asking for an simple example, for learning-purposes. And please, no google-suggestions or links to other questions. I've tried to search this for a while already. No success, though. Martti Laine

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  • My cookies won't stay (PHP).

    - by RemiX
    I'm building an autologin system using cookies, but one fundamental part of the functionality of the cookies fails: they are non-persistent over different sessions - or even pages! In my login script, I set the cookies like this: setcookie('userID', $userID, time()+86400); // (edited after replies) $userID has a value. Then I print the $_COOKIE variable and it says array(['base_usid'] = 1); So that's good, but when I click the home page and print the $_COOKIE variable there, it says NULL. Does anyone see the problem?

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  • PHP Forms checkbox calculation

    - by Sef
    Hello, I am trying to perform some calculations with a form but every time i try to work with checkboxes it goes wrong. The checkboxes are beign set on value 1 in the form itselff and are being checked if there checked or not. $verdieping = isset($_POST["verdieping"]) ? $_POST["verdieping"] : 0; $telefoon = isset($_POST["telefoon"]) ? $_POST["telefoon"] : 0; $netwerk = isset($_POST["netwerk"]) ? $_POST["netwerk"] : 0; When i try to do calculations every works expect for the options with the checkboxes. When both checkboxes (telefoon & netwerk) are selected the value should be 30. If only one is selected the value should be 20. But no mather what i have tried to write down it always give problem, and it always uses 20, never the value 30. How do i solve this problem? Or suppose i am writing the syntax all wrong to lay conditions to a calculation? Any input appreciated. $standnaam = $_SESSION["standnaam"]; $oppervlakte = $_SESSION["oppervlakte"]; $verdieping = $_SESSION["verdieping"]; $telefoon = $_SESSION["telefoon"]; $netwerk = $_SESSION["netwerk"]; if ($oppervlakte <= 10) $tarief = 100; if ($oppervlakte > 10 && $oppervlakte <= 20) $tarief = 90; if ($oppervlakte > 20) $tarief = 80; if($verdieping == 1) { $prijsVerdieping = $oppervlakte * 120; } else { $prijsVerdieping = 0; } if(($telefoon == 1) && ($netwerk == 1)) { $prijsCom = 30; // never get this value, it always uses 20 } if(($telefoon == 1) || ($netwerk == 1)) { $prijsCom = 20; } $prijsOpp = $tarief * $oppervlakte; // works $totalePrijs = $prijsOpp + $prijsVerdieping + $prijsCom; //prijsCom value is always wrong Regards.

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  • Empty files generated from running `mysqldump` using PHP

    - by alex
    I keep getting empty files generated from running $command = 'mysqldump --opt -h localhost -u username -p \'password\' dbname > \'backup 2009-04-15 09-57-13.sql\''; command($command); Anyone know what might be causing this? My password has strange characters in it, but works fine with connecting to the db. I've ran exec($command, $return) and outputted the $return array and it is finding the command. I've also ran it with mysqldump > file.sql and the file contains Usage: mysqldump [OPTIONS] database [tables] OR mysqldump [OPTIONS] --databases [OPTIONS] DB1 [DB2 DB3...] OR mysqldump [OPTIONS] --all-databases [OPTIONS] For more options, use mysqldump --help So it would seem like the command is working.

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  • php for-loop issue

    - by rajesh1984
    Heya, I have a loop which generates a table code for a specific number of times. What I'm having problems with is to echo a variable inside the loop. The loop runs 10 times, and there are 10 text messages sent to the page, so my problem is how do I get each of the looped tables to echo one of the text messages each time?

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  • How to assign variable dynamically to php list function

    - by ravisoni
    What I am doing that I want to generate a list based on how many items are in an array, so I have counted the items and loop over them, create a number based var and construct a string $var which contains $a1,$a2.... and assigns the $var to list list($var) and tried to access $a1 but it gives me the error "Undefined variable: a1" Is there any other way to do it? Here is my code: $arr = array('1','2','3'); $listsize = count($arr); $var=''; for($i=1;$i<=$listsize;$i++){ $var.='$a'.$i; if($i!=$listsize){ $var.=','; } } list($var) = $arr; echo $a1;

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  • What pattern is this? php

    - by user151841
    I have several classes that are basically interfaces to database rows. Since the class assumes that a row already exists ( __construct expects a field value ), there is a public static function that allows creation of the row and returns an instance of the class. Here's an example ( without the actual database inserts ): class selfStarter { public $type; public function __construct( $type ) { $this->type = $type; } public static function create( $type ) { if ( ! empty($type) ) { $starter = & new selfStarter($type); return $starter; } } } $obj1 = selfStarter::create( "apple" ); $obj2 = & new selfStarter( "banana" ); What is this pattern called?

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  • Saving PHP Table as CSV

    - by user2403705
    I have been looking everywhere for a way to do this. There are a lot of people that have asked the questions but when I try myself i cant seem to get it to work. Often I get the format correct but it inputs the information into a new page instead of saving it. I did manage to get one to work for google chrome but when i ran it in internet explorer it didnt work. I have a table being created from a MYSQL query and i would like the table to be able to be saved as a CSV. Could anyone help me out?

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  • php - How do I count occurences of items in an array

    - by Steven
    take this array: Array ( [#twitterwhites] => 0 [#lufc] => 0 [#FOOTBALL] => 0 [#Liverpool] => 0 [#liverpool] => 0 [#ESPN] => 0 [#LUFC] => 0 [#cafc] => 0 [#cafc] => 0 [#ocra] => 0 [#nra] => 0 [#2nd] => 0 [#secondamendment] => 0 [#SCR] => 0 [#TC500] => 0 [#cpfc] => 0 [#MOT] => 0 ) I want to return a result like this: #liverpool = 2 #cafc = 2 #LUFC = 1 ETC ETC How do I do it?

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  • give preference to print array values in php

    - by Bharanikumar
    Hi , I have country table, i fetch all values and moved into array , these value i like to populate into combo/dropdown list , here i want to do some magic things, that is , for my site most of the users coming from uk,us,Australia,Romain and few, So i like to populate by my preference , is there any array will do this magic work, else is it possible mysql query , So final question is , Populate country name into combo based on my prefernce , Thanks

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  • Memcached for PHP 5.3

    - by Industrial
    Hi everyone, I have looked everywhere for some clues on how to run the Memcached extension in my WAMP windows development environment (thats right, the memcached with an D in the end, not memcache). I already use memcache (without the D), but it would be handy to take part of memcached's more extended multiple-server features. How can I get this up and running? Thanks

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  • PHP variable question

    - by Kyle Parisi
    This works: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); $customerBox = mysql_query("MY SQL STATEMENT AGAIN"); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } This does not: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } Why? I guess I don't understand how variables work yet.

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  • Simple PHP GET question

    - by Jake
    I know how to detect if a particular GET method is in the url: $username = $_GET['username']; if ($username) { // whatever } But how can I detect something like this: http://www.mysite.com?username=me&action=editpost How can I detect the "&action" above?

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